10 points!
Which measuring tool should be used to measure the length of a marble track?

graduated cylinder

spring scale

metric ruler

stopwatch

Approximately 5.878 x 1012 miles or 9.461 x 1015 meters, a light-year is the maximum distance light can travel in a single year..

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The required longitude of the certain ship when the time of the day is 12 noon at the Prime Meridian is 5 p.m is 75° West.

The sun is highest in London, but will not pass the ship for another 5 hours.

Given that,

The time of day for a certain ship is 12 noon at the Prime Meridian is 5 p.m.

The ship must be five hours west of Greenwich since the sun goes from east to west.

Each hour of sun motion is 15° of longitude. The ship is located at (5 x 15°) = 75° West longitude.

Thus, the ship's longitude is 75° West.

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The object would have returned to its initial starting point if it had travelled round a circle.

The distance travelled by the object is determined from the product of speed of the object and the time of motion of the object.

D = vt

where;

The distance travelled by the object is calculated as follows;

D = ( 4 cm / s ) x ( 6.28 s )

D = 25.1 cm

Thus, at the given time and speed the object would have travelled round the circle. That is the object would have made one complete revolution.

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Two spherical objects have masses of 8000 KG and 1500 KG their centers are separated by a distance of 1.5 M, the gravitational attraction between them is 3.56 × 10⁻⁴N.

The gravitational force, also known as gravity, pulls objects with mass in the same direction. We frequently think about the Earth's gravitational pull. This force is firmly holding your body in place. But every mass-bearing object attracts other mass-bearing objects toward it through gravity.

Using the formula of gravitational attraction

F = G× M₁M₂/d²

where G = 6.67 × 10⁻¹¹ Nm²Kg⁻²

M₁ = 8000Kg

M₂ = 1500 Kg

F =  6.67 × 10⁻¹¹ × 8000 × 1500 / (1.5)²

F = 3.56 × 10⁻⁴ N

The gravitational force of attraction between them is 3.56 × 10⁻⁴ N.

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The total distance that the truck travels is 11.7 km

Part (a)

The algebraic sum of the various distances results in the total distance covered by the trucks.

DT = d1 + d2 + d3

So, total distance that the truck travels = 1.4 + 7.7 + 2.6 = 11.7 km

Part (b) Question is missing :

(b) What are the magnitude (in km) and direction of the truck's displacement? (Enter a number.)

magnitude   #?   km

direction? east, west or neither.

The quickest route taken by the object to get from one spot to another is called displacement.

As the truck travels in three directions, from east to west to east, it begins out from the east. Think of the east as being good and the west as being negative. As a result, the displacement can be calculated as shown below.

D =d1 - d2 + d3 = 1.4 - 7.7 + 2.6 = 1.4 - 5.1 = -3.7 km

Here, the negative sign shows that the truck has displaced in the west direction.

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The original speed of the bullet was 300.6 m/s.

A measure of the amount of matter contained in or constituting a physical body. In classical mechanics, the mass of an object is related to the force required to accelerate it and hence is related to its inertia, and is essential to Newton's laws of motion.

Given:

mV bi​ +MV wi​ =mV b​ +M Vwf​

where m= mass of bullet =10 g=10^−2 ∣kg

M= mass of wood block =5 kg

V bI​ = initial mass of bullet

Vwi​ = initial mass of wood block and V bf​ =V wf​  

=0.06 m/s 10 −2 Vbi+0(10 −2 +5)0.6 V

bi​ = 10 −2 5.01×0.6​ V

bi​ =300.6 m/s

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The Barbie would be moving with speed 27.69 ft/s at the bottom of the path.

Speed is distance travelled by the object per unit time. Due to having no direction and only having magnitude, speed is a scalar quantity With SI unit meter/second.

Mass of the Barbie = 0.23 kg.

Initial height of the Barbie: h= 11 ft 11 inches = ( 11 + 11/12) feet = 11.92 feet.

Acceleration due to gravity: g = 32.17 ft/s²

Hence, the speed of the Barbie at the bottom of the path = √(2gh)

= √( 2 × 32.17 ×11.92) ft/s

= 27.69 ft/s.

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The distance between the Naval Navigator and the sunken cargo was found to be 2175 m by using sonar with 120kHz frequency and a wavelength of 3mm.

Sonar is largely used by NOAA scientists to create nautical charts, find underwater navigational hazards, find and map things on the bottom like shipwrecks, and map the actual seafloor. Sonar comes in active and passive varieties.

Speed of sound in water  =1450m/s

Time lag between transmission and reception of Sonar waves =3 s

sound waves travel a distance is twice the distance between the navigator and cargo (2S) in this time lag.

Time taken for the sound to reach the submarine  = 1/2 ×3 = 1.5s

Distance between the Navigator and the sunken cargo, S=1450×1.5s =2175m.

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1.7×10^2 m

The student was 1.7×10^2 m far from the speaker.

The distance that sound waves travel is mostly influenced by the temperature and pressure of the ocean, even though sound travels through water at a far faster rate than it does through air.

The change in pressure that a sound wave causes when it is measured at a particular location is related to the amplitude of the wave. If the amplitude grows, the sound is heard as louder, and if it drops, it is heard as quieter.

The pace at which a wave moves has nothing to do with its amplitude. Waves A and B move forward at the same speed. Only changes in the characteristics of the medium a wave travels through can change its speed.

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To calculate the distance between the loudspeaker and the student, we can use the speed of sound in air, which is approximately 340 meters per second (m/s) at standard temperature and pressure (STP).

The formula to calculate distance is:

distance = speed x time

where distance is the distance between the loudspeaker and the student, speed is the speed of sound in air, and time is the delay that was observed between the time the sound wave left the loudspeaker and the time it reached the student.

distance = 340 m/s x 0.50 s

distance = 170 m

So, the distance between the loudspeaker and the student is 170 meters.

This answer corresponds to (2) 91.7 x 102m.

It's worth mentioning that sound speed can be affected by temperature, humidity, and atmospheric pressure which can cause slight variations from the standard 340 m/s at STP.

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According to the above statement, 15800 N of tension is required to draw a cable at 3.0 m/s² of acceleration.

A force known as tension is connected here to tugging of an item like the a rope, cord, or chain. It resembles elastic potential energy a lot. When a thing is pulled out and brought under tension, as soon as that force is removed, it will naturally recover to its relaxed length.

F = ma

  = 2000 kg × 3.0 m/s²

  = 6000 N.

The body's weight and the load are added to create the tension force.

Thus T = w + ma

T = 9800 N + 6000 N

  = 15800 N.

As a result, 15800 N of tension is required to draw a wire at 3.0 m/s² of acceleration.

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The complete question is-

A 2000 kg elevator is accelerated upward at a rate of 3.0 m/s2. What is the tension in the cable pulling the elevator upward when it experiences this acceleration?

Answer: D

Explanation:

The wind will begin to blow the sediments of the arch away, causing the arched structure to become thinner over time. Therefore, the best answer is option D.

If the lever is frictionless, to raise the rock a distance of 0.13 m, then the boy has to move the lever to 0.72 m.

An external force that acts upon an object results in a motion of the object, then it is called a work done upon the object by that force.

Given that the external force on a lever is 225 N and on a rock is 1250 N. The distance of motion by the rock is 0.13 m.

Hence the work done by the lever will be equivalent to the work done by the rock to move a particular distance.

Work (Lever) = Work (Rock)

F(lever) x D (lever) = F (rock) x D (rock)

225x D(lever)= 1250 x0.13

D(lever) is 0.72 m

Hence we can conclude that the distance of the motion by the lever is 0.72 m.

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A jets engine is a device that produces a strong pushing force known as thrust out of liquid fuel that is high in energy.

A rotary engine called a gas turbine converts the flow of combustion into energy.Axial or centrifugal compressors (or both) can be used to boost air pressure and temperature before it enters the combustion chamber. Ambient air is pulled into the engine intake.

By raising internal engine pressure, jet or rocket engines generate thrust.This higher pressure inside the jet and rocket engine causes the forward force to be greater than the backward force.

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51.6 seconds long does it take a plane, traveling at a constant speed of 130 m/s, to fly once around a circle whose radius is 2650 m.

The time it takes for an object to travel once around a circle of radius r at a constant speed v can be found using the equation:

T = 2 x π x r ÷ v

where T is the time in seconds, pi is approximately 3.14, r is the radius of the circle in meters, and v is the speed of the object in meters per second.

Given a constant speed of 130 m/s and a radius of 2650 m, the time it would take for a plane to fly once around the circle would be:

T = 2 x π x 2650 m / 130 m/s

T = 51.6 sec

So, it would take approximately 51.6 seconds for a plane traveling at a constant speed of 130 m/s to fly once around a circle whose radius is 2650 m.

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The total kinetic energy gained by the object when accelerating a 20-n object from rest across a horizontal frictionless table is 10.0 J.

To determine the total kinetic energy gained by the object, we can use the work-energy principle, which states that the work done on an object is equal to the change in kinetic energy of the object.

Work done = change in kinetic energy

W = Kf - Ki

where

W = work done (10.0 J)

Kf = final kinetic energy

Ki = initial kinetic energy (0 J, since the object is at rest)

Given the information provided, we know that a total of 10.0 J of work is done in accelerating the 20-n object from rest.

So,

Kf = W + Ki

Kf = 10.0 J + 0 J

Kf = 10.0 J

Therefore, the total kinetic energy gained by the object is 10.0 J

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Answer: The length of the pendulum is approximately 2.495 meters.

Explanation:

The period of a simple pendulum is the time it takes for the pendulum to swing back and forth through one full oscillation. The period of a simple pendulum is related to the length of the pendulum and the acceleration due to gravity (g) by the formula:

Period = 2 * pi * sqrt(length / g)

In this case, you are given that the period of the pendulum is 3 seconds and the value of g is 9.98 ms-2. You can use these values to solve for the length of the pendulum using the formula above.

Substituting in the values given, you get:

3 = 2 * pi * sqrt(length / 9.98)

Solving for length, you get:

length = (3 / (2 * pi))^2 * 9.98

= 0.5^2 * 9.98

= 0.25 * 9.98

= 2.495

Therefore, the length of the pendulum is approximately 2.495 meters.

Because of the Doppler effect, a light- or sound-emitting object moving toward you has a lower amplitude compared to a stationary object.

The Doppler effect is generally defined as the shift in wave frequency (whether it be sound or light) caused by relative motion between the wave source and the observer. Every time a source wave moves in reference to the observer, this effect can be seen.

The Doppler effect allows astronomers to determine the frequency of light waves as an object moves in relation to the observer. As it approaches you, the frequency decreases and the item exhibits a blueshift. A redshift indicates that an item is travelling away from us.

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According to reports, the biggest meteorite with lunar origin weighs 19 g. If the meteorite placed on a scale whose spring constant is 83 N/m, 0.22 m is the compression of the spring.

We can use Hooke's Law to calculate the compression of the spring caused by the meteorite. Hooke's Law states that the force exerted on a spring is directly proportional to the spring's compression or extension.

= F

= k * x

where F is the force (in newtons), k is the spring constant (in N/m), and x is the compression (in meters).

Given the mass of the meteorite is 19 g and the spring constant is 83 N/m, the force exerted on the spring can be calculated as

= F

= (mass of the meteorite) * g

= (19 g) * (9.8 m/s^2)

The compression of the spring can be found by rearranging Hooke's Law and substituting in the force and spring constant

x = F/k

x = (19 * 9.8) / 83

x = 0.22 m

The compression of the spring caused by the meteorite is 0.22 m.

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Arc bursts, electrical burns, and electric shock are the three basic categories of electrical risks (the effect of blasts).

Live wire contact can result in electric shock and burns.

fires caused by poor wiring.

circuits that are overloaded

Leave electrical components unprotected.

due to a lack of PPE, electrocution or burns.

explosive and flammable materials causing explosions and fires.

exposure to electricity wires above.

A reaction to an electric current running through the body is shock.

Burns are brought on by arc flashes and blasts of strong light.

Old wiring, wires, and switches can cause fires, as can malfunctioning outlets.

When explosive substance in the air is ignited by electricity, an explosion occurs.

The primary concerns connected to them are: contact with exposed live parts causing electric shock and burns (for example, exposed leads or other electrical equipment coming into contact with metal surfaces like metal flooring or roofs); and failures that could result in fires.

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Answer:

To derive the formula for the pressure at a distance r from the rotation axis, you can use the principle of hydrostatic equilibrium. This states that the pressure at a point in a fluid is equal in all directions and the net force on a fluid element is equal to zero.

Consider a small cylindrical element of fluid at a distance r from the rotation axis, as shown in the diagram below. The dimensions of the element are dr in the radial direction, 2πr in the circumferential direction, and h in the vertical direction. The weight of the element is equal to the product of its volume, density, and the acceleration due to gravity: W = (2πr)(dr)(h)(ρ)(g). The pressure at the top and bottom faces of the element is P + dP, where P is the pressure at the point and dP is a small change in pressure. The forces acting on the element are the weight of the element, the pressure force at the top face, and the pressure force at the bottom face.

[asy]

unitsize(2cm);

pair P1, P2, P3, P4;

P1 = (0,0);

P2 = (1,0);

P3 = (1,1);

P4 = (0,1);

draw((-0.5,0)--(1.5,0));

draw((0,-0.5)--(0,1.5));

draw(P1--P2--P3--P4--cycle);

draw((0.5,0)--(0.5,1));

draw((0.25,0)--(0.25,1));

draw((0.75,0)--(0.75,1));

label("$r$", (0.5,1.5), red);

label("$

The coefficient of kinetic friction between the block and the surface is 0.11.

The coefficient of kinetic friction can be found using the equation:

friction = force of friction = coefficient of kinetic friction * normal force

The normal force is equal to the weight of the object, which can be calculated as weight = mass * acceleration due to gravity

The force of friction can be calculated using the equation:

friction = force of friction = coefficient of kinetic friction * weight

The coefficient of kinetic friction can be found by rearranging the equation and substituting the known values:

coefficient of kinetic friction = friction / weight

= (1.10 m/s2) / (1.41 kg * 9.8 m/s2)

= 0.11

So, the coefficient of kinetic friction between the block and the surface is 0.11.

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We know that momentum is defined as the product of mass and velocity, hence p = 0.025 kg x 0.1 m/s or p = 0.0025 kg m/s. Therefore, the bullet's momentum is equal to 0.0025 kg/s.

The ability of a gun to cause such substantial damage is due to the momentum that the gun imparts to the projectile. An object's momentum is equal to its mass times its velocity. Making a thing more large or moving more quickly can increase its momentum and, thus, its capacity for destruction. The force acting on both is therefore the same, but the rifles have smaller recoils since their mass is higher than that of the bullet, which results in a reduced recoil compared to the bullet's speed.

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According to the given information the velocity is .0148 m/s2 and the kinetic energy is 3.78 J.

The movement that an item or particle experiences with regard to time is expressed vectorially as velocity. One metre per second (m/s) is the accepted unit of flow speed (also known as speed).

The metric speed unit is the meter per minute (m/s). A different way to express velocity magnitude is in centimeters per second (cm/s).

vilocity = 5/(5.8×5.8)

            = 0.148

kinetic energy = 1/2mv^2

                        = 1/2 × (0343 × 0.148×0.148)

                        = 3.78 J

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2.78 m/s to the west velocity must a 2. 25 kg croquet mallet have in order to have the same momentum as 1. 25 kg ball that has a momentum 6. 25 kg•m/s to the west.

Given,

Mass = 2.25kg

Momentum = 6.25 kg•m/s

To find,

Velocity

Formula used,

Momentum = Mass x velocity

Calculation,

6.25 kg•m/s = 2.25 kg x velocity

Velocity = 6.25/2.25

Velocity = 2.78 m/s

The conservation of momentum principle asserts that the quantity of momentum inside a problem domain remains constant; momentum is not generated nor destroyed, but only modified by the action of forces as defined by Newton's equations of motion.

Newton's third law says that for every force exerted by object A on object B, object B exerts an equal but opposite force in magnitude and direction. Newton utilised this concept to create the law of conservation of momentum.

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The speed a satellite fall towards Earth compares to the speed it is moving forward If the speed drops, it will fall toward the earth.

We can say that satellite speed has a significant impact on satellite motion because if a satellite's speed is reduced by half, it will fall towards the earth because it is drawn in by the earth's gravitational pull. However, if a satellite's speed is doubled, it will travel into space because the earth's gravitational pull will no longer hold it in orbit.

When a satellite is moving quickly, the force of gravity may not be able to hold it in orbit. If it moves slowly, it won't make enough progress to resist gravity's pull and collide with the object it is orbiting.

Rockets are used to put the majority of satellites into orbit. When the pull of Earth's gravity and the satellite's speed are equal, the satellite circled the planet. Without this equilibrium, the satellite would either fall back to Earth or shoot off into space in a straight path.

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When we do, we make sure to measure our mass in kilograms. We determine that F is equal to 124.26 newtons by entering these numbers into our calculator.

That is the average magnitude of the force applied to the tennis ball.

The equation that Newton was referring to is shown by a serve. You can calculate the total force that was applied by the tennis racket to the ball by multiplying the weight of the racket by the speed at which the player swings their racquet.

An average 120-mph serve slows to 82 mph before the bounce, 65 mph after the bounce, and 55 mph at the opponent's racket, according to tennis instructor and analyst John Yandell.

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The new electrostatic force between the charges, given that q₁ is reduced to 1/2q₁ and q₂ is tripped is 3/2Fₑ (Option C)

First, we shall determine the initial electrostatic force between the charges. Details below:

F = Kq₁q₂ / r²

Fₑ = Kq₁q₂ / r²

Finall, we shall determine the new electrostatic force. The is illustrated below:

F = Kq₁q₂ / r²

F = (K × 1/2q₁ × 3q₂) / r²

F = 3/2Kq₁q₂ / r²

But,

Fₑ = Kq₁q₂ / r²

Thus

F = 3/2Fₑ

Thus, we can conclude that the new electrostatic force is 3/2Fₑ (Option C)

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The velocity of the object when it first reaches a height of 8.10 meters is 18.05 m/s.

To find the speed of the stone when it is 8.26 m higher, we can use the equation for vertical motion under constant acceleration. The equation is:

v^2 = u^2 + 2as

Where:

v = final velocity (m/s)

u = initial velocity (m/s)

a = acceleration due to gravity (9.8 m/s^2, downward)

s = distance traveled (m)

In this case, the initial velocity is 18.1 m/s, the distance traveled is 8.26 m upward, and the acceleration due to gravity is 9.8 m/s^2 downward. We can substitute these values into the equation and solve for the final velocity.

v^2 = 18.1^2 + 2 * 9.8 * 8.26

v^2 = 327.61

v = sqrt(327.61)

v = 18.05 m/s

Air resistance is the term for the frictional force that slows an object's velocity as it moves through the air. Although air resistance considerably affects trajectory motion, it is not taken into account in beginning physics due to the complexity of the calculations.

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The motion of the stars around Polaris (NCP) is due to rotation (daily motion) of Earth.

Polaris is a star in Ursa Minor's northern circumpolar constellation. It is known as Ursae Minoris and is also known as the North Star or Pole Star. With an apparent brightness of roughly 1.98, it is the brightest star in the constellation and may be seen with the bare eyes at night. The star's location is less than one degree from the north celestial pole, making it the current northern pole star. The star's constant location in the Northern Sky makes it ideal for navigation.

Its distance is considered as part of the cosmic distance ladder since it is the nearest Cepheid variable. The updated Hipparcos stellar parallax distance to Polaris is approximately 433 light-years (133 parsecs), whereas the successor mission Gaia distance is around 448 light-years  (137 parsecs). Other techniques of calculation produce significantly disparate results.

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Answer: The answer is Cu+ P4 = Cu3P2

Which after balancing would be, 6Cu + P4 = 2Cu3p2

Explanation: Copper (Cu) is a metal and Phosphorous (P) is a non-metal. Metals and Non-metals combine to form ionic compounds where there is a transfer of ions from metal to non-metal.

Phosphorous has 5 valence electrons in its outer shell and Copper has 2 valence electrons. Following the octet rule, which means that the outer shell should have 8 electrons to be complete we see that combining these two metals on combining have electrons insufficient so we combine till we reach the octet structure. In this case, it happens when there are three copper and two phosphorous. We see that there are no more valence electrons. So it forms Copper II Phosphide, where the two indicates the charge of Copper.

Then we move on to balance both the sides of the equation, upon placing one number after the other to make the numerical value of elements equivalent to the other. Which gives us the answer.