17
Post Test: Transformations and Congruence
Select the correct answer from each drop-down menu.
Consider Undefined control sequence \triangle HJI.
H
सौ
Triangle HJIis
triangle HJI, the triangles
#
triangle EFG. Since triangle EFGuses
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Answer:

ASA

Step-by-step explanation:

From the graph given, the equilibrium price and quantities are given respectively as;

The total consumer spending(TCS) is achieved by finding the product of the price and the quantities at the equilibrium point.

Hence,
TCS = 5 * 6

= 60

A) The producer surplus is the area of the triangle shaded yellow in the attached image.

Recall that he area of triangle is:

1/2 b *  h

b = 4

h = 6

Hence Area of the RA-Triangle (Producer Surplus) =

1/2 * 4 * 6

= 12

B) The Consumer surplus is the area of the triangle shaded Green in the attached image.

Recall that the area of triangle is:

1/2 b *  h

b = 4

h = 6

Hence Area of the RA-Triangle (Consumer Surplus) =

1/2 * 4 * 6

= 12

If the suppliers charged $6, then the quantity demanded would drop to 4 units of  funnel cakes. It is demonstrated graphically. Recall that the law of demand and supply indicates that when prices goes up, demand comes down and vice versa.

Graph II illustrates what would happen if a large number of guests entered the fair. It would result to a right-ward shift in the demand curve.

Yes, there is an increase in the consumer surplus. Now there are more consumers hence the total amount they are willing to pay as an aggregate sum has increased from what was.

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Answer:

x intercepts: (1,0), (-3,0)

the roots are 1 and -3

Step-by-step explanation:

Using the Quadratic Formula:

x=−b±sqrt(b2−4ac)/2a

Substitute:

x= -8±sqrt(8^2-4(4)(-12))/2(4)

x=-8±sqrt((64- -192))/8

x=-8±sqrt(256)/8

Solve two equations (±)

x=-8±16/8

x=8/8  and x=-24/8

x=1 and x=-3

Answer:

x = -3

x = 1

Step-by-step explanation:

Hello!

We can solve the quadratic by Factoring the Equation and using the Zero Product Property.

We want to find two numbers that multiply out to -3, but add up to 2. The numbers that work are -1 and 3. We can expand 2x to -x and 3x and factor by grouping.

Set each factor to 0 and solve for x in both.

Therefore, the x-interecpts are -3 and 1.

The answers to the questions are:

1. x = 4

2.  x = 1.5

3. x = 1.875

4. x = 1

1. 4x + 3 = 19

4x = 19 - 3

4x = 16

divide by 4

x = 4

(4/3)x + 5 = 17

= 1.33x + 5 = 7

Take like terms

1.33x = 7-5

1.33x = 2

divide through by 1.33x to get 2

x = 2/1.33

x = 1.5

4x(6 - 2) - 10 = 20

Multiply and open the bracket

24x - 8x - 10 = 20

Take like terms

16x = 20+10

16x = 30

x = 30/16

= 1.875

4.3x + 0.7 = 5

4.3x = 5 - 0.7

4.3x = 4.3

x = 1

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B0 AND B1 are the parameters which describes the intercept and slope of the lines.

According to statement

we have to find the parameters which describes the intercept and slopes.

Simple linear regression is a  model that estimates the relationship between one independent variable and one dependent variable using a straight line. Both variables should be quantitative.

So, B0 AND B1 are the parameters which describes the intercept and slope of the lines.

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Answer:

The answer to your question is P=56

Step-by-step explanation:

P=7a=7·8=56

I hope this helps and have a good day!

By applying the definition of product between two square matrices, we find that [tex]\vec A \,\cdot \,\vec A = \left[\begin{array}{cc}1&2\\3&6\end{array}\right] \cdot \left[\begin{array}{cc}1&2\\3&6\end{array}\right][/tex] is equal to the matrix [tex]\vec A \,\cdot \,\vec A = \left[\begin{array}{cc}7&14\\21&42\end{array}\right][/tex]. (Correct choice: D)

In this question we must use the definition of product between two square matrices to determine the resulting construction:

[tex]\vec A \,\cdot \,\vec A = \left[\begin{array}{cc}1&2\\3&6\end{array}\right] \cdot \left[\begin{array}{cc}1&2\\3&6\end{array}\right][/tex]

[tex]\vec A \,\cdot \,\vec A = \left[\begin{array}{cc}7&14\\21&42\end{array}\right][/tex]

By applying the definition of product between two square matrices, we find that [tex]\vec A \,\cdot \,\vec A = \left[\begin{array}{cc}1&2\\3&6\end{array}\right] \cdot \left[\begin{array}{cc}1&2\\3&6\end{array}\right][/tex] is equal to the matrix [tex]\vec A \,\cdot \,\vec A = \left[\begin{array}{cc}7&14\\21&42\end{array}\right][/tex].

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Answer:

0,5*0,5=0,25

Step-by-step explanation:

assuming a die of 6 faces

25

0,5 for < 4; 0,5 for < 3

Answer:

a) 25830

b)9975

Step-by-step explanation:

a) 287

x 90

25830

b) 105

x 95

9975

Answer:1+1

Step-by-step explanation:

The correct option that depicts the centroid of the triangle is; C. Point A is the center of the circle that passes that passes through the points E, F and G and is the center of the circle that passes through the points X, Y and Z.

The center of inscribed circle into the triangle is the point where the angle bisectors of the triangle meet.

The center of the circumscribed circle over the triangle is the point where the perpendicular bisectors of the sides meet.

Line segments ZE, FY and GX are both angle bisectors and perpendicular bisectors of the sides. Thus, the point of intersection of line segments ZE, FY and GX is the center of inscribed circle into the triangle and the center of the circumscribed circle over the triangle.

Inscribed circle passes through the points X, Y and Z. Circumscribed circle passes through the points E, F and G. So, point A is the center of the circle that passes that passes through the points E, F and G and is the center of the circle that passes through the points X, Y and Z.

Thus, the correct option is option C. Point A is the center of the circle that passes that passes through the points E, F and G and is the center of the circle that passes through the points X, Y and Z.

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The congruency proof that can be used to show that ∠P≅∠R is as given in the steps below.

From the figure as seen online, we can see that;

The figure shows the same triangles PQS and RQS as in the beginning of the task. Angles SPQ and SRQ are highlighted in red.

Thus, the 2 column proof to show that ∠P≅∠R is;

Statement 1; ∠SPQ≅∠SRQ

Reason 1; Given

Statement 2; SQ bisects ∠PSR

Reason 2; Given

Statement 3; ∠PSQ≅∠QSR

Reason 3; Definition of angle bisector

Statement 4; SQ ≅ SQ

Reason 4; Reflexive Property of Congruence

Statement 5; △PQS≅△RQS

Reason 5; Angle - Angle Side (AAS) Congruency Postulate

Statement 6; PS ≅ SR

Reason 6; CPCTC (Corresponding parts of congruent triangles are congruent)

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The simplification of the polynomial expression will give 3x² - 20x + 8.

The polynomial expression is given as:

(5x² + 13x4) (17x² + 7x - 19) + (5x-7)(3x + 1)

= 5x² + 13x - 4 - 17x² - 7x + 19 + 15x² + 5x - 21x - 7

Then collect like terms

= 5x² + 15x² - 17x² + (13x - 7x + 5x - 21x) - 4 - 7 + 19

= 3x² - 20x + 8.

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Answer: 144 [tex]cm^{2}[/tex]

Step-by-step explanation:

The rectangle's length is twice as long as it's width as the square is folded in half. Let's say that the width's length is x, we get the equation

x + 2x + x + 2x = 36

6x = 36

x = 6 cm

The length of the rectangle is the length of the square which is 2x = 2 * 6 = 12 cm

So the area of the square is 12 * 12 = 144 [tex]cm^{2}[/tex]

Answer:

Below.

Step-by-step explanation:

12.  That is a semicircle

The central angle is 180 degrees.

The lifetime of the batteries in a package is 14.31 hours which exceeds that value for only 5% of all packages.

Give sample mean of 13 hours and standard deviation of 1 hour and sample size is 9.

We have to apply t test in this because the value of n which is sample size is less than 30.

We have been given the p value of the required mean so we have to find the t value for this with degree of freedom (9-1)=8

t value=2.306.

We know that

t=X bar-μ/s/[tex]\sqrt{n}[/tex]

s/[tex]\sqrt{n}[/tex]=1/[tex]\sqrt{3}[/tex]=0.57

Put all the values in the above formula to calculate required mean.

2.306=X bar-13/0.57

X bar=1.31442+13

=14.31442

after rounding off we get

X bar=14.31

Hence the lifetime of the batteries is 14.31 for which  the percentage exceeds 5%.

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The Area of given figure is 341.6 square.

According to the statement

we have to find the total area of given figure.

Here a= 10 and h= 11

So, we use the formula is A = a(a + √((a)^2 + 4(h)^2))

where the a represent the base of given solid or sides of the equilateral triangle

And h represent the slant height of the solid.

So, Substitute the values in above formula then

A = 10(10 + √((10)^2 + 4(11)^2))

A = 10(10 + √((100 + 4(121))

A = 10(10 + √(100 + 484)

A = 10(10 + √(584)

A = 10(10 + 24.16)

A = 10(34.16)

A= 341.6

So, The Area of given figure is 341.6 square.

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Answer:

r=8.74038744 m
and surface area=1303.76211 m2

Step-by-step explanation:

Answer:

[tex]\frac{9\pi }{4}[/tex] inches

Step-by-step explanation:

I suppose they are asking you for the length of the red part.

18[tex]\pi \\[/tex] * [tex]\frac{45}{360}[/tex] = [tex]\frac{9\pi }{4}[/tex] inches

Answer:

L = 7.07 in

Step-by-step explanation:

L = arc lenght

[tex]L=\frac{\pi (45)(9)}{180} =2.25\pi =7.07in.[/tex]

Hope this helps

Answer:

[tex](1*10^{15} )(5*10^{14})[/tex] or 1.5×10^14

Step-by-step explanation:

The answer is [tex](1*10^{15} )(5*10^{14})[/tex] or 1.5×10^14.

Hope this helps!

Evaluating the given expressions and inequalities, we have;

[tex]11) \: \frac{x}{4} \cdot \left(2 + y - x \right) = 4[/tex]

12) (8•a - 5•b) - 2•(a + b) = 4

[tex] 13) \: \frac{p \cdot (p + {a}^{2} )}{6} = 55 [/tex]

[tex] 14) \: 3\cdot m - \frac{2\cdot m}{2} +\frac{n}{3} = 12 [/tex]

[tex] 16) \: x \geq 11\frac{2}{3} [/tex]

17) k > 9

18) v > 9

20) m ≤ 16

The given expressions are;

[tex]11) \: \frac{x}{4} \cdot \left(2 + y - x \right)[/tex]

Where x = 4, and y = 6, we have;

[tex]\frac{x}{4} \cdot \left(2 + y - x \right) = \frac{4}{4} \cdot \left(2 + 6 - 4 \right) = 4[/tex]

Therefore;

[tex]\frac{x}{4} \cdot \left(2 + y - x \right) = 4[/tex]

12) (8•a - 5•b) - 2•(a + b)

Where a = 3 and b = 2, we have;

(8•a - 5•b) - 2•(a + b) = (8×3 - 5×2) - 2•(3 + 2) = 4

Therefore;

[tex]13) \: \mathbf{\frac{p \cdot (p + {a}^{2} )}{6}} [/tex]

Where a = 7, and p = 6, we have;

[tex] \frac{p \cdot (p + {a}^{2} )}{6} = \mathbf{ \frac{6 \times (6 + {7}^{2} )}{6}} = 55 [/tex]

Therefore;

[tex] \frac{p \cdot (p + {a}^{2} )}{6} = 55 [/tex]

[tex]14) \: \mathbf{3\cdot m - \frac{2\cdot m}{2} +\frac{n}{3} } [/tex]

Where m = 5, and n = 6, we have;

[tex] 3\cdot m - \frac{2\cdot m}{2} +\frac{n}{3} = \mathbf{3\times 5 - \frac{2\times 5}{2} +\frac{6}{3} }= 12 [/tex]

Therefore;

[tex] 3\cdot m - \frac{2\cdot m}{2} +\frac{n}{3} = 12 [/tex]

[tex]16) \: \mathbf{1 \frac{1}{6} }\leq \frac{x}{10} [/tex]

Which gives;

[tex] \frac{7}{6} \times 10 \leq x [/tex]

[tex] \mathbf{ \frac{35}{3} }\leq x [/tex]

[tex] x \geq 11\frac{2}{3} [/tex]

17) 20 < k + 11

Therefore;

k > 20 - 11 = 9

18) 6•v > 54

v > 54 ÷ 6 = 9

Therefore;

[tex]20) \: 8 \geq \mathbf{ \frac{m}{2}} [/tex]

Therefore;

2 × 8 = 16 ≥ m

Which gives;

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Answer:

y = 6x + 8

Step-by-step explanation:

y = mx + b

20 = 6(2) + b

b = 8

y = 6x + 8

6 is the growth factor in the function f(x) = (1/3)(6ˣ).

The rate at which a quantity multiplies itself over the independent factor, to increase the value of the function exponentially is known as its growth factor.

In the question, we are given a function f(x) = (1/3)(6ˣ) and are asked to identify the growth factor of the function.

We know that the rate at which a quantity multiplies itself over the independent factor, to increase the value of the function exponentially is known as its growth factor.

In the given function, f(x) = (1/3)(6ˣ), (1/3) remains unaffected with the change in the independent factor x, but 6 is exponentially increasing with x.

Thus, 6 is the growth factor in the function f(x) = (1/3)(6ˣ).

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The equation of the parallel line is y = -5x - 1

The equation is given as:

5x + y = 4

Make y the subject

y = -5x + 4

The slope of the above equation is

m = -5

Parallel lines have equal slope.

This means that the slope of the new line is 5

The equation is then calculated as:

y = m(x - x1) + y1

So, we have:

y = -5(x + 1) + 4

Expand

y = -5x - 5 + 4

Evaluate

y = -5x - 1

Hence, the equation of the parallel line is y = -5x - 1

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The graph is a decreasing exponential graph.

Part A: The given graph is decreasing the exponential graph since the graph is decreasing rapidly as the value of x is increasing and the value of y is decreasing rapidly.

Part B: The graph shown here is maybe the case of any electric appliance which is of cheap quality. The time when it is brought then its performance and its life is awesome after that its life is decreasing rapidly.

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Complete question:

Describe a relationship that can be modeled by the function represented by the graph, and explain how the function models the relationship. Identify and interpret the key features of the function in the context of the situation you described in part A.

The value of x is 4.

Given that diagonals of a rectangle measure x+5 feet and 2x+1 feet as shown in the attached figure.

The diagonal of a rectangle is a line or straight line that connects the opposite corners or vertices of the rectangle.

In the given figure ABCD is a rectangle.

OA=2x+1 and OD=x+5             [Given]

AC and BD are diagonals of a rectangle.

As we know that the diagonals of a rectangle are always equal.

So, AC = BD

We can also write it as,

2×OA=2×OD

2×(2x+1) =2×(x+5)

Apply the distributive property a(b+c)=ab+ac, we get

4x+2=2x+10

Subtract 2x from both sides, we get

4x+2-2x=2x+10-2x

2x+2=10

Subtract 2 from both sides, we get

2x+2-2=10-2

2x=8

Divide both sides by 2, we get

2x/x=8/2

x=4

Hence, the value of x=4 when diagonals of a rectangle measure x+5 feet and 2x+1 feet.

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Answer:

[tex]|x-85| \leq 5[/tex]

Step-by-step explanation:

|x-85| represents the 'distance' of the test score than 85, and this distance must be less than or equal to 5.

Answer:

11.4 feet

Step-by-step explanation:

1/1.9 = h/w  (h= height, w=width)

Solving for w, gives you the formula

w = (1.9)h

This means the width is 1.9 times the height.

Use the formula to find the width where the height is 6 feet.

h = 6

w = (1.9)(6) = 11.4

The width is 11.4 feet.

This Bay store can also be described as a big box retailer store.

Big Box Retailer

A big box retailer is a physically enormous retail store that is typically a component of a chain of stores (also known as a hyper store, supercenter, superstore, or megastore). By extension, the phrase, big box retailer can also refer to the business that runs the store.

The Bay Store as a Big Box

There are numerous retail chains that only operate in Canada, aside from the large American big box retailer stores like Walmart Canada and the formerly-existent Target Canada. These include places like Hudson's Bay by Home Outfitters, Loblaws by Real Canadian Superstore, Rona, Winners by HomeSense, Canadian Tire by Mark's & Sport Chek, Shoppers Drug Mart, Chapters by Indigo Books and Music, Sobeys, and several others.

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Consider the lengths of consecutive 1-2 blocks.

block 1 - 1, 2 - length 2

block 2 - 1, 2, 2 - length 3

block 3 - 1, 2, 2, 2 - length 4

block 4 - 1, 2, 2, 2, 2 - length 5

and so on.

Recall the formula for the sum of consecutive positive integers,

[tex]\displaystyle \sum_{i=1}^j i = 1 + 2 + 3 + \cdots + j = \frac{j(j+1)}2 \implies \sum_{i=2}^j = \frac{j(j+1) - 2}2[/tex]

Now,

[tex]1234 = \dfrac{j(j+1)-2}2 \implies 2470 = j(j+1) \implies j\approx49.2016[/tex]

which means that the 1234th term in the sequence occurs somewhere about 1/5 of the way through the 49th 1-2 block.

In the first 48 blocks, the sequence contains 48 copies of 1 and 1 + 2 + 3 + ... + 47 copies of 2, hence they make up a total of

[tex]\displaystyle \sum_{i=1}^48 1 + \sum_{i=1}^{48} i = 48+\frac{48(48+1)}2 = 1224[/tex]

numbers, and their sum is

[tex]\displaystyle \sum_{i=1}^{48} 1 + \sum_{i=1}^{48} 2i = 48 + 48(48+1) = 48\times50 = 2400[/tex]

This leaves us with the contribution of the first 10 terms in the 49th block, which consist of one 1 and nine 2s with a sum of [tex]1+9\times2=19[/tex].

So, the sum of the first 1234 terms in the sequence is 2419.