2Ca3(PO4)2+6SiO2+10C-> 6CaSiO3+P4+10CO
Refer to the information above. If you use .57 mol of Ca3(PO4)2 and an excess of silicon dioxide and carbon, how many moles of phosphorus will be produced?

Hydrocarbons (typically petroleum products), which separate in water and have a Specific Gravity of less than one, represent a significant hazard to firefighters. Why?

Any member of the class of organic chemical compounds known as hydrocarbons only includes the atoms carbon (C) and hydrogen (H). The hydrogen atoms bond to the carbon atoms in a variety of ways to create the compound's structural framework.

Although there could be thousands of different hydrocarbon molecules in a given crude oil, these descriptions only focus on the type of hydrocarbon that predominates in the combination. Typically, each sort of molecule can be found in all naturally occurring crude oils.

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A chemical engineer has determined by measurements that there are 7.0 moles of carbon in a sample of nickel tetracarbonyl. 7 moles of oxygen are in the sample.

Stoichiometry helps us use the balanced chemical equation to measure quantitative relationships and it is to calculate the amounts of products and reactants that are given in a reaction.

The balanced chemical equation is the equation in which the number of atoms on the reactant side is equal to the number of atoms on the product side in an equation.

According to Stoichiometry

[tex]7\ \text{mol C} \times \frac{1\ \text{mol O}}{1\ \text{mol C}}[/tex]

= 7 mol O

Thus from the above conclusion we can say that A chemical engineer has determined by measurements that there are 7.0 moles of carbon in a sample of nickel tetracarbonyl. 7 moles of oxygen are in the sample.

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Disclaimer: The question was given incomplete on the portal. Here is the complete question.

Question: This is the chemical formula for Nickel Tetracarbonyl (a powerfully poisonous liquid used in Nickel Refining).

Ni(CO)₄

A chemical engineer has determined by measurements that there are 7.0 moles of carbon in a sample of nickel tetracarbonyl. How many moles of oxygen are in the sample ?

Mass of water produced is equal to 7.2 grams.

The reactants are reacting according to the following equation:

HBr + NaOH = NaBr + H2O

1 mole of HBr requires 1 mole of NaOH to be totally transformed into NaBr and water.

Now, let us calculate the amounts of HBr and NaOH in mols:

m(HBr) = 67.2g

m(NaOH) = 16g

M(HBr) = 80.9g/mol

M(NaOH) = 40g/mol

Following the simple relation

n(moles) = m(grams)/M(g/mol)

n(HBr) = 67.2g/(80.9g/mol)

n(NaOH) = 16g/(40g/mol)

n(H2O) = n(NaOH) = 0.40 mol, which is:

m(H2O) = n(H2O) x M(H2O)

0.40mol∗18g/mol=7.2g

Finally, the mass of water produced is equal to 7.2 grams.

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Answer:

FeCO₃,  Fe(IO₃)₂,  Pb(CO₃)₂,  Pb(IO₃)₄

Explanation:

Cations (positively charged ions) can only form ionic bonds with anions (negatively charged ions). However, you can't just simply put one cation and one anion together to form a compound. Each compound needs to been neutral, or have an overall charge of 0. When cations and anions do not have charges that perfectly cancel, you need to modify the amount of each ion in the compound.

1.) FeCO₃

-----> Fe²⁺ and CO₃²⁻

-----> +2 + (-2) = 0

2.) Fe(IO₃)₂

-----> Fe²⁺ and IO₃⁻

-----> +2 + (-1) + (-1) = 0

3.) Pb(CO₃)₂

-----> Pb⁴⁺ and CO₃²⁻

-----> +4 + (-2) + (-2) = 0

4.) Pb(IO₃)₄

-----> Pb⁴⁺ and IO₃⁻

-----> +4 + (-1) + (-1) + (-1) + (-1) = 0

[tex]\rm FeCO_3, Fe(IO_3)_2, Pb(CO_3)_2, Pb(IO_3)_4[/tex] are the empirical formula for at least four ionic compounds that could be formed from the given ions.

Ions, which are atoms or molecules with one or more lost or acquired electrons and an electric charge, are bonded together to create ionic compounds, a particular class of chemical complex. A metal cation (a positively charged ion) and a non-metal anion (a negatively charged ion) typically make up these compounds. Ionic bonding is a process that leads to the synthesis of ionic compounds. A non-metal atom becomes a negatively charged anion when it gets one or more electrons, while a metal atom becomes a positively charged cation when it loses one or more electrons.

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He can use 3.52/22-n = 24/100 equation to find n, where n is the number of gallons of water.

Calculation of amount of ammonia in 22 gallon of 16% ammonia solution.

amount of ammonia  = 16%×22 gallon = 3.53 gallon

The amount of ammonia remains the same after evaporation of water but the total amount of solution is reduced because solution contain ammonia as well as water . So, if water is evaporate then solution reduced.

Amount of water remains = 22 - n

Desired concentration, 24% = 24/100

Therefore the final equation becomes,  

3.52/22-n = 24/100

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Answer:

» Chlorine (Cl) is the oxidizing agent because it gains an electron.

Explanation:

Oxidization is the process of losing electrons during an ionic reaction.

In the reaction above, aqueous chlorine captures the electrons of bromide ion hence becoming oxidized. In this sense, since aqueous chlorine is the one gaining electrons, it oxidizes bromide to bromine

[tex]{ \rm{Cl _{2(aq)}+ 2Br {}^{ - } _{(aq)} \dashrightarrow 2Cl {}^{ - } _{(aq)} + Br _{2( aq)}}}[/tex]

Answer:

c

Explanation:

edge 2022

1. The half life of the element, given the data from the question is 1600 years

2. The time taken for 312 g of the sample to decay to 9.75 grams is 8000 years

Half-life is the time taken for half a material to decay.

To determine the half life of the given element, do the following:

We'll begin by determining the number of half-lives that has elapsed. This can be obtained as follow:

2ⁿ = N₀ / N

2ⁿ = 312 / 9.75

2ⁿ = 32

2ⁿ = 2⁵

n = 5

Finally, we shall determine the time. This can be obtained as follow:

t = n × t½

t = 5 × 1600

t = 8000 years

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Derivatization means adding fluorescent labels or combining the analyte with chiral reagents or other chemicals to increase detectability.

Some analytes must be derivatized to increase their column retention or detectability.

Retention time can be referred to as the amount of time a solute spends in the stationary and mobile phases of a column.

Detectability is the ability of an analyte to get detected in the mobile phase of chromatography.

The refractometer, fluorescence detector, and UV detector are the three most popular liquid chromatography detectors. These detectors increase the detectability.

For derivatization, the fluorescence detector are used.

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The equation of the reaction is [tex]Na_2SO_4 (aq) + CaCl_2 (s) --- > CaSO_4 (aq) +2 NaCl (s)[/tex]

They are reactions involving chemical reactants leading to the formation of chemical products.

The chemical formula for sodium sulfate is [tex]Na_2SO_4[/tex]

The chemical formula for calcium chloride is [tex]CaCl_2[/tex]

The two react to produce calcium sulfate  ([tex]CaSO_4[/tex]) and sodium chloride (NaCl) according to the following equation:

[tex]Na_2SO_4 (aq) + CaCl_2 (s) --- > CaSO_4 (aq) +2 NaCl (s)[/tex]

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Answer:

Explanation:

244 days

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The half life of the Zn-65 sample if it decays from 65 g to 2.9 g in 3 years is 1.53 years. This can be obtained using the first order kinetic of nuclear decay.

Nuclear decay is the process by which unstable isotopes of an atom decays by the emission of alpha or beta particles to form stable nuclei. Nuclear decay is a first order reaction and the decay constant k can be written as:

k = 1/t log [no]/[nt]

Where, no and nt be the initial and final amount of the sample.

Given that the initial mass of Zn was 65 g and after 3 years it is 2.90 gram. Thus, decay constant is calculated as :

k = 1/3 yrs log (65/2.9)

  = 0.45 yr⁻¹.

Now, the half life of Zn-65 can be calculated as:

t1/2 = 0.693/ k

      = 0.693/0.45  yr⁻¹

      = 1.53 yrs.

Therefore, the half life of Zn-65 will be 1.53 years.

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The missing part of the equation is found to be 4/2He. Option A

The term nuclear equations have to do with the type of equation in which one type of nucleus is transformed into another sometimes by the bombardment or loss of a particle.

Now the full equation ought to be written as 7/3Li + 1/1H -----> 4/2He + 4/2He. This is because the total mass on the left is 8 and the total charge on the left is 4.

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The average atomic mass of sulfur = 32.33 u

The average atomic mass of sulfur is determined as follows:

Average atomic mass = (31.977 × 0.818) + (32.97 × 0.008) + (33.97 × 0.174)

Average atomic mass = 32.33

In conclusion, the average atomic mass of sulfur is determined from the sum of the isotopic masses and their relative abundance.

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Answer:

carbon atoms tend to make four bonds, each carbon atom will have the number of hydrogen atoms that are required for four bonds. This compound contains 16 hydrogen atoms for a molecular formula of C 8 H 16.

Explanation:

Answer: silver nitrate

Explanation:

it is the only soluble salt listed.

The oxidation number for S in the compound SO3 is +6 (option D). Details about oxidation number can be found below.

Oxidation number of an element is the hypothetical charge of an atom within a molecule.

The oxidation number of elements in a compound adds up to the overall charge of that compound.

According to this question, O has an oxidation number of -2 in SO3, the oxidation number of S can be calculated as follows:

x - 2(3) = 0

x - 6 = 0

x = 6

Therefore, the oxidation number for S in the compound SO3 is +6.

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The answer is D: 6+

Worked for me on EDGE 2023

the empirical formula for a compound is Mo2Br5Cl3.

The empirical components of a compound are the best entire quantity ratio of atoms of every detail within the compound. it's miles decided using statistics from experiments and therefore empirical. as an example, the molecular formula of glucose is C 6H 12O 6 however the empirical formulation is CH 2O.

An Empirical formula is the chemical components of a compound that offers the proportions (ratios) of the elements present in the compound however no longer the real numbers or arrangement of atoms. This will be the lowest complete range ratio of the elements within the compound.

The empirical method of a compound gives the only ratio of the range of various atoms gift, while the molecular formula gives the actual range of each distinctive atom found in a molecule. If the components is simplified then it is an empirical components.

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Answer:

Mn₁O₂

Explanation:

To find the empirical formula, you need to (1) determine how many grams of each element are within the compound, then (2) convert grams to moles (via the atomic masses of each element), and then (3) determine the mole-to-mole ratio of each element.

(Step 1)

Because the percents add to equal 100%, we can say that each percent is the mass of each element.

63% Mn ----> 63 grams Mn

37% O ----> 37 grams O

(Step 2)

We need to convert each mass to moles using the atomic masses. The atomic masses are a ratio comparing the mass of each element per every 1 mole.

Atomic Mass (Mn): 54.983 g/mol

Atomic Mass (O): 15.998 g/mol

63 grams Mn                 1 mole
----------------------  x  -------------------------  =  1.15 moles Mn
                                 54.983 grams

37 grams O                1 mole
--------------------  x  ------------------------  =  2.31 moles O
                               15.998 grams

(Step 3)

You can find the mole-to-mole ratio of each element in the compound by dividing the calculated mole values by the smallest mole value. In this case, since 1.15 moles was the smallest value calculated, it should be the divisor. The resulting amounts are the subscripts within the empirical formula.

1.15 moles Mn / 1.15 moles  =  1 moles Mn

2.31 moles O / 1.15 moles  =  2 moles O

Ratio of MnO = 1:2

This make the empirical formula: Mn₁O₂

There is nearly 1000 times more uranium diffused in our oceans as compared to mine on land.

The world ocean contain more than 4 billion metric tons of dissolved uranium . Uranium is removed from ocean by diffusion across the sediment-water interface of organic-rich sediments.

Uranium ore is deposits are economically recovered within earth crust. The uranium elements is common elements present in earth crust as it found 40 times more as compare to silver and 500 times more as compare to gold. It can found in everywhere in the rock , soil, river, and ocean.

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The molecular formula of the compound is C15H12O3.

The molecular formula of the compound is determined from the mole ratio of the elements in the compound.

Carbon = 0.75 × 240/12 = 15

Hydrogen = 0.0505 × 240/1 = 12

Oxygen = 0.1995 × 240/16 = 3

Therefore, the molecular formula of the compound is C15H12O3

In conclusion, the molecular formula of the compound is determined from the mole ratio of the elements and their percentage composition.

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Their fossilized shells formed these limestone rocks, which, like Gubbio's mountains, were once at the bottom of the ocean. Now exposed, they represent over a million years of a geological time period known as the Cretaceous.

Walter Alvarez found that forming a distinct boundary between the limestone of the two periods was a thin layer of red clay. Immediately below this clay boundary, the Cretaceous limestone was heavily populated with a wide mix of the fossils of tiny marine creatures called foraminifera, or “foram” for short.

On the Atlantic Coast, outside the town of Zumaia, Dutch geologist Jan Smit was studying the forams from a different ancient sea. Their fossilized shells formed these limestone rocks, which, like Gubbio's mountains, were once at the bottom of the ocean.

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Answer:

speed=distance/time taken

=300km/3hr

=100km/hr

So it is true.

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The two basic geologic processes which contributed to the formation of folded mountain ranges like in Glacier National Park include:

This is a geologic process which involve materials in the earth being washed away and transported to other parts by water, wind etc.

In the case of Glacier National Park, ice erodes the mountain thereby resulting in the folding of the sedimentary rocks.

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Based on the type of experiment that is being conducted:

This is the term that is used to refer to the variable that is used to arrive at conclusions about the dependent variable.

The experiment is trying to tell us that the temperature of a material is the function of the heat applied to it and the type of material.

This is the term that is used to refer to the variable of interest. It is what is being tested in the experiment.

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Answer:

Explanation:  The reaction between hydrazine and hydrogen peroxide yields nitrogen and water. The balanced chemical reaction is:

N2H4 + 2H2O2  N2 + 4H2O

which means that the mole ratio between hydrazine and hydrogen peroxide is 1:2 and the mole ratio between hydrazine and water is 1:4.

2.7 is the chlorine dosage for this well, expressed in parts per million.

Unlike municipal water, well water does not go through a water treatment facility. That implies that it could be contaminated with poisons like lead, coliform bacteria, volatile chemical compounds, and others. chlorination in well water is done to fulfill the role that chlorine plays in municipal sources' water disinfection processes.

It is advised to start with a chlorine concentration of 50 to 100 parts per million (ppm).

Bacterial pollutants are eliminated from well water, well casings, holding tanks, and the entire water delivery system via shock chlorination. To shock chlorinate, a well driller with a license is trained.

Algae have been linked to green water, and they may thrive in both surface water and groundwater wells even in the absence of sunshine. Algae can color the water in both the pre-and post-decomposition stages with a variety of hues, including green, brown, and reddish.

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Answer:

C. Parasympathetic

Explanation:

The products will be [tex]ZnCl_2(s) + H_2(g)[/tex]

Zn is higher than hydrogen in the reactivity series. Thus, it will be able to displace hydrogen from the acid.

The equation of the reaction becomes: [tex]Zn(s) + HCl(aq) -- > ZnCl_2 (s) + H_2 (g)[/tex]

Hydrogen gas is released as a result. In fact, it is one of the ways of preparing hydrogen gas in the laboratory.

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The order of the students from the most reliable to the least reliable is C. Student 4, Student 1, Student 2, Student 3.

the student with the most reliable data is the one that has the least variation in their data in the various trials.

this student is therefore student 4.

the next student would be student 1 and student 2 would be the third most reliable.

student 3 has large variations in their trials which makes their data the least reliable.

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Part of the investigation must be measuring the pressure inside the lighter fuel tank.

The pressure of gas measures how compact the gas molecules are. We know that the more compacted the gas molecules are, the more likely the gas will exist in the liquid state.

Hence, part of the investigation must be measuring the pressure inside the lighter  fuel tank.

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