A car used 1/81 of a gallon of gas to drive 1/4 of a mile. At this rate, how many miles can the car travel using 1 gallon of gas? ??????????

The probability of selecting two orange marbles with replacement is 36/169.

Data;

Since after each draw, the orange marble is replaced.

The total number of marbles in the bag is

6+3+4 = 13

And the number of orange marbles is 6.

For the first selection, the probability of selecting one orange is

[tex]P = \frac{6}{13}[/tex]

After drawn and replaced, the probability of selecting another marble is

[tex]P = \frac{6}{13}[/tex]

And the probability of selecting two orange marbles with replacement is

[tex]P = \frac{6}{13} * \frac{6}{13} = \frac{36}{169}[/tex]

The probability of selecting two orange marbles with replacement is 36/169.

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The two angles form a straight line and need to equal 180 degrees

180 - 61 = 119

The missing angle is 119 degrees

The final statement is: The rate of interest is 7% and simple interest is $12.60

Simple interest is an interest charge that borrowers pay lenders for a loan. It is calculated using the principal only and does not include compounding interest. Simple interest relates not just to certain loans. It's also the type of interest that banks pay customers on their savings accounts.

Given here: Principal =$180 And amount after one year=$192.60

Therefore simple interest= 192.60-180

                                          =12.60

∴12.60=180×r×1/100

 r=7%

Hence, The rate of interest is 7% and simple interest is $12.60

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Answer:

x = 16

Step-by-step explanation:

Given:

Therefore, total marks = 15 × 6 = 90

To find the value of x, add up the individual marks:

12 + 16 + 14 + 13 + 19 + x = 74 + x

Now equate this to the total number of marks found previously:

74 + x = 90

Solve for x:

⇒ 74 + x - 74 = 90 - 74

⇒ x = 16

Therefore, the value of x is 16.

Answer:

0.125 = ⅛

Step-by-step explanation:

Both are equal.......

Answer:

C

Step-by-step explanation:

Givens

You are given 2 tangent lines.

You are also given a 4 sided figure.

All 4 sided figures have 360 degrees

A radius meets a tangent at 90 degrees

Formula

<BDA + <DCA + <BCA + <BDC = 360

Solution

90 + 90 +40 + <BDC = 360               Combine

220 + <BDC = 360                             Subtract 220 from both sides

220- 220 +BDC =360 - 220

<BDC = 140

Answer: C

Answer:

6 carnations

Step-by-step explanation:

0.5x +15 = 3x

x = 6

Answer:  (x + 4)(x + 4)

                x² + 8x + 16

                x² + 4x + 4x + 16                

Step-by-step explanation:

See the image below.

Answer:

Adult Ticket = $13.00, Children Ticket = $4.00

Step-by-step explanation:
13*4=52, 4*9=36, 52+36=88

13*7=91, 4*5=20, 91+20=111

Answer:

150 cm^2

Step-by-step explanation:

A cube has 6 surfaces

Each surface square = 5 by 5

So.....

5 x 5 (or 25) times 6

25 x 6 = 150

Hope this helps!

The z-statistic is 1. 68, so the null hypothesis cannot be rejected.

The expected value of the amount of average snowfall for over 30 years is 86.7 inches with a standard deviation of 40.4 inches.

To verify if this particular trend continues, we must check the significance value of the amount snowfall for the past four years.

Given that the snowfall for past years are as follows: 115.7 inches, 62.9 inches, 168.5 inches, and 135.7 inches.

Thus the mean of the sample would be: (115.7 + 62.9 + 168.5 + 135.7)/4 = 120.7 inches.

To compute for the z-score,

we have z-score = (x – μ) / (σ / √n)

where x is the computed/measured value,

μ is the expected mean, σ is the standard deviation,

and n is the number of samples.

Using the information we have,

z-score (z) = (120.7 - 86.7) / (40.4/ √4) = 1.68

In order to reject the null hyptohesis our probability value must be less than the significance level of 5%. For our case, since z = 1.68, P-value = 0.093 > 0.05.

Hence The z-statistic is 1. 68, so the null hypothesis cannot be rejected.

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Answer:

B. The z-statistic is 1.68, so the null hypothesis cannot be rejected.

Step-by-step explanation:

edg 22, got 100 on unit test

Hey there!
Linear functions have a continuous change.

Let's check these tables and see if we can tell linear functions from non-linear functions.

The first one is

- we add 1 each time

- we subtract 3 each time

[tex]\rule{200}{2}[/tex]

Let's try the next one:

- we add 1 each time

- we add 5 each time

[tex]\rule{200}{2}[/tex]

Let's try the third one:

        - we add 3, then 2, then 1..

So this table doesn't represent a linear function.

Let's check the fourth one:

- we add 1 each time

- we add 1 each time

Thus, Option C is the right option.

Hope everything is clear.

Let me know if you have any questions!

Always remember: Knowledge is power!

Answer:

true

Step-by-step explanation:

Using the z-distribution, as we are working with a proportion, it is found that the buyers need a sample of 1505.

A confidence interval of proportions is given by:

[tex]\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

In which:

The margin of error is given by:

[tex]M = z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

In this problem, we have a 98% confidence level, hence[tex]\alpha = 0.98[/tex], z is the value of Z that has a p-value of [tex]\frac{1+0.98}{2} = 0.99[/tex], so the critical value is z = 2.327.

There is no estimate of the percentage, hence [tex]\pi = 0.5[/tex], and the margin of error is of M = 0.03, hence we solve for n to find the desired sample size.

[tex]M = z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

[tex]0.03 = 2.327\sqrt{\frac{0.5(0.5)}{n}}[/tex]

[tex]0.03\sqrt{n} = 2.327(0.5)[/tex]

[tex]\sqrt{n} = \frac{2.327(0.5)}{0.03}[/tex]

[tex](\sqrt{n})^2 = \left(\frac{2.327(0.5)}{0.03}\right)^2[/tex]

[tex]n = 1504.2[/tex]

Rounding up, the buyers need a sample of 1505.

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Answer:

m = 4

Step-by-step explanation:

(80, 40) and (90, 80)

40/10= 4

Answer:

4

Step-by-step explanation:

choose two points

I chose (80,40) and (90,80)

(80-40)÷(90-80)

40/10

4

Answer:

30,976

Step-by-step explanation:

=}.

[tex](11 {}^{3} \times 4 { }^{2} \binom{}{11 {}^{2} } ) {}^{2} [/tex]

=}.

[tex](11 \times 4 {}^{2} ) {}^{2} [/tex]

=}.

[tex]121 \times (4 {}^{2} ) {}^{2} [/tex]

=}.

[tex]121 \times 256[/tex]

=}. 30,976

Answer:

Answer given above

Step-by-step explanation:

11^2 * 4^4

Answer:

498. 498/6 = 83.

Step-by-step explanation:

Answer:

Step-by-step explanation:

5x^2 - 125 factors into 5 (x^2 - 25)

x^2 - 25 factors into  (x + 5)(x - 5)

So the answer to this part is 5(x + 5)(x - 5)

x^2 -  10x + 25 factors into

(x - 5)(x - 5)

So the HCF is (x - 5)

Answer:

x= ½, y= 7

Step-by-step explanation:

[tex]\textcolor{steelblue}{\text{\textcircled{1} Label the equations}}[/tex]

6x -y= -4 -----(1)

2x +2y= 15 -----(2)

[tex]\textcolor{steelblue}{\text{\textcircled{2} Make y the subject of formula}}[/tex]

We could also make x the subject of formula in one equation, however the equation can be easily rearranged so that the coefficient of y is 1. This can be done by moving the y term to the right hand side of the equation, and the rest to the left. Note that each time you bring a term or constant over to the other side of the equation, its sign changes (e.g. positive to negative).

From (1):

6x +4= y

y= 6x +4 -----(3)

Label the equation as equation (3) so we can refer to it easily later.

[tex]\textcolor{steelblue}{\text{\textcircled{3} Substitute (3) into (2)}}[/tex]

Now that we have an equation of y that is written in terms of x, we can replace all the y in equation (2) so that the whole equation is only in terms of x.

Subst. (3) into (2):

2x +2(6x +4)= 15

Expand:

2x +12x +8= 15

Simplify:

14x +8= 15

14x= 15 -8

14x= 7

x= 7 ÷14

x= ½

[tex]\textcolor{steelblue}{\text{\textcircled{4} Find y}}[/tex]

Substitute x= ½ into (3):

y= 6(½) +4

y= 3 +4

y= 7

Answer:

96

Step-by-step explanation:

L=6

W=2

H=8

LxWxH=8x6x2=96

8x6=48

48x2=96

Answer:

76

Step-by-step explanation:

the answer is 76 because I took the test

Answer:

the annswer is 4155 because its in formal information

Step-by-step explanation:

the annswer is 4155 because its in formal information

Answer:

  (d)  as a triangle, a rectangle, and a semicircle

Step-by-step explanation:

The description of the shape tells you how to decompose it. The shape is described as a semicircle, a rectangle, and a triangle. The appropriate decomposition is ...

  as a triangle, a rectangle, and a semicircle

Answer:

d

Step-by-step explanation:

Answer:

Area of a rectangle

A = lw

perimeter = turn of the figure

P = 6 + 3 + 4 + 4 + 3 + 6 + 3 + 4 + 3 = 36

the triangle has 2 équal sides => isosceles

and 1 angle is 60° so the triangle is equilateral

Answer: Volume: 65.4 Weight: 46.4

Step-by-step explanation:

Density describes mass per unit volume. The weight of each of the considered chocolate truffle is 46.47 grams approx.

Density is like rate. It tells you how much of a thing is available for each unit other thing which contains the first thing.

Density = (Total amount available)/(total space which contains that amount)

We're given that:

Volume of each chocolate truffle = volume of sphere with radius 2.5 cm

=  [tex]\dfrac{4}{3} \pi (2.5)^3 \approx 65.45 \: \rm cm^3[/tex]

One cubic cm has 0.71 grams weight,

so one truffle, which has 65.45 cubic cm of chocolate, will weigh approx[tex]0.71 \times 65.45 \approx 46.47 \: \rm g[/tex]

Thus, the weight of each of the considered chocolate truffle is 46.47 grams approx.

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The figure below is composed of eight circles, seven small circles and one large circle containing them all. Neighboring circles only share one point, and two regions between the smaller circles have been shaded. Each small circle has a radius of 5 cm.

‎[tex] \qquad\quad\hookrightarrow{\sf { 1000(e-1)}}[/tex]

[tex] \begin{aligned}&\longrightarrow \int_{0} ^{1000} {e}^{ - |x| }dx = \sum_{k = 0}^{999} \int_{k}^{k + 1}e ^{x - |x| }dx \\ \\ &\longrightarrow\int_{0} ^{1000} {e}^{ - |x| }dx = \sum_{k = 0}^{999} \int_{k}^{k + 1}e^{x - k}dx \\\\&\longrightarrow\int_{0} ^{1000} {e}^{ - |x| }dx = \sum_{k = 0}^{999}e^{x - k \big |_{k}^ {k + 1}} \\ \\& \longrightarrow\int_{0} ^{1000} {e}^{ - |x| }dx = \sum_{k = 0}^ {999}(e - 1)\\\\&\longrightarrow\int_{0} ^{1000} {e}^{ - |x| }dx = 1000(e - 1)\end{aligned}[/tex]