A girl climbs a 12 meter ladder, walks across a 15 meter plank then climbs down another 12 meter ladder as shown in the diagram below. What was the magnitude of the girls displacement

Answers

Answer 1

Hence, the magnitude of the displacement for each girl is 400 m. This is equal to the actual length of the path skated by girl.

What is magnitude of the girls displacement?When the motion is in a fixed direction, the displacement's magnitude equals its distance (one direction ). The size of the displacement without respect to direction is what we refer to as the magnitude (i.e., just a number with a unit). For instance, during a lecture, the professor could pace back and forth repeatedly, covering perhaps 150 metres in total, and still only finish up two metres to the right of her starting place. Magnitude is simply "distance or quantity" in the context of physics. In terms of motion, it shows the absolute or relative size, direction, or movement of an object. It is used to describe something's size or scope. Magnitude in physics typically refers to a size or quantity.

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Related Questions

A 0.15 kg baseball is traveling at 40 meters per second (about 90 miles per hour) if the ball comes to a complete stop when it hits the catchers mitt, what is the change in velocity?

Answers

Answer:

Please find attached pdf

Explanation:

What was the average speed in km/h of a car that travels 788 km in 7.1 h?

Answers

Answer:

Well the answer is 111 (rounded) km/h

Explanation:

788/7.1 is 110.9... so if you round it it would equal 111.

What is the equivalent resistance of this network?

Answers

The equivalent resistance of the circuit network is determined as 1.6 ohms.

What is the equivalent resistance of the network?

The equivalent resistance of the circuit network is calculated as follows;

To determine the equivalent resistance of the circuit, we will decompose the circuit into series and parallel components.

The equivalent resistance at J₄ is calculated as follows;

The two 4 ohms are in series;

J₄ = 4Ω + 4 Ω = 8 Ω

The equivalent resistance at J₁ is calculated as follows;

The 4 ohms and 0 ohm are in series;

J₁ = 0 Ω + 4 Ω = 4 Ω

The equivalent resistance at J₂ and J₃ is calculated by applying the formula for parallel resistors;

1/Re = 1/J₁  + 1/J₄ + 1/J₂,₃

1/Re = 1/4 + 1/8 + 1/4

1/Re = 5/8

Re = 8/5

Re = 1.6 ohms

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a girl whose mass is 40kg walk up a flight of 20steps each 15mm hight in 10seconds.find power developed by the girl showing the solution

Answers

Answer: Approximately 11.76 joules per second

=========================================================

Work Shown:

Mass = 40 kg

Force pulling down = (mass)*(gravity) = 40*9.8 = 392 newtons

Roughly 392 newtons of force are pulling down on her.  

To climb the steps, she must apply 392 newtons of force upward.  

---------------

Displacement = 20*(15 mm) = 300 mm = 0.3 m

Work = Force*Displacement

Work = 392*0.3

Work = 117.6 joules of energy

---------------

Power = (Work)/(Time)

Power = (117.6 joules)/(10 seconds)

Power = (117.6/10) joules per second

Power = 11.76 joules per second, which is approximate

The low-frequency speaker of a stereo set has a surface area of and produces 1W of acoustical power. What is the intensity at the speaker

Answers

Answer:

      I =  [tex]\frac{1}{4\pi \ r^2}[/tex]

we see the intensity decreases with the inverse of the distance squared

Explanation:

Intensity is defined as power per unit area,

           I = P / A

in this case we have that the sound is emitted in a spherical form therefore the area is

           A = 4 pi r2

therefore the intensity is

          I =  [tex]\frac{1}{4\pi \ r^2}[/tex]

as we see the intensity decreases with the inverse of the distance squared

A transformer used on a 220V line deliver 1.5A at 1800V. what current is drawn from the line assuming the ideal Transformers

Answers

The current drawn from the line, assuming an ideal transformer, is approximately 12.27A.

In an ideal transformer, the power remains the same before and after transformation. Therefore, we can use the power equation to determine the current drawn from the line.

The power equation for a transformer is given by:

P1 = P2

where P1 is the input power, P2 is the output power.

Given that the input voltage (V1) is 220V, the input current (I1) is unknown, the output voltage (V2) is 1800V, and the output current (I2) is 1.5A, we can rewrite the equation as:

V1 * I1 = V2 * I2

Substituting the known values:

220V * I1 = 1800V * 1.5A

Simplifying:

I1 = (1800V * 1.5A) / 220V

I1 ≈ 12.27A

Therefore, the current drawn from the line, assuming an ideal transformer, is approximately 12.27A.

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One species of eucalyptus tree, Eucalyptus regnans, grow to heights similar to those attained by California redwoods. Suppose a bird sitting on top of one specimen of eucalyptus tree drops a nut that is 1.7 ounces. If the speed of the falling nut at the moment it is 50.3 m above the ground is 42.7 m/s, how tall is the tree

Answers

Answer:

The tree is 143.325 meters tall

Explanation:

The given parameters of the eucalyptus tree are;

The mass of the eucalyptus tree nut = 1.7 ounces

The speed of the nut at 50.3 m above the ground, v = 42.7 m/s

The equation for free fall is given as follows;

v² = 2·g·h

Where;

v = The velocity after falling through a height, h

g = The acceleration due to gravity = 9.8 m/s²

h = The height through which the seed has already fallen

Therefore, we have;

h = v²/(2·g) = (42.7 m/s)²/(2 × 9.8 m/s²) = 93.025 m

The height through which the seed has already fallen, h = 93.025 m

The height of the tree = h + The height of the seed above ground at the moment it was falling at 42.7 m/s

The height of the tree = 93.025 m + 50.3 m = 143.325 m

The height of the tree = 143.325 m.

The height of the eucalyptus tree is approximately 111.9 meters.

To determine the height of the tree, we can use the equations of motion. The initial velocity of the nut, u, is 0 m/s (since it is dropped), the acceleration due to gravity, a, is approximately 9.8 m/s², and the final velocity, v, is 42.7 m/s. We need to find the height, h. Using the equation v² = u² + 2a(h - u), we can rearrange it to solve for h: h = (v² - u²) / (2a) Plugging in the values, we get: h = (42.7² - 0²) / (2 * 9.8) = 111.9 meters Therefore, the height of the eucalyptus tree is approximately 111.9 meters.

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can you ans please ?????????????????????????????????????????

Answers

Answer:

ans a

Explanation:

as the circuit should not be completed until switch is closed

How does altitude from the surface of earth affect the time period of a simple pendulum

Answers

Answer:

because the strength of Earth's gravitational field is not uniform everywhere, a given pendulum swings faster, and thus has a shorter period, at low altitudes and at Earth's poles than it does at high altitudes and at the Equator.

Two students on ice skates stand one behind the other. Student 2 pushes student 1 in the back; student 1 has less mass than student 2; student 1 has a great acceleration than student 2. which law of motion is this (Newton's laws)

Answers

Answer:

law in acting

Explanation:

Q4. (a) An acre-foot is the volume of water that would cover 1 acre of flat land to a depth of 1
foot. How many gallons are in 1 acre-foot?

Answers

Answer:

326,000

Explanation:

One acre-foot equals about 326,000 gallons, or enough water to cover an acre of land, about the size of a football field, one foot deep. An average California household uses between one-half and one acre-foot of water per year for indoor and outdoor use.

Semiconductors can simplistically be thought of as an intermediate state between insulators and conductors. In a semiconductor, charges are normally bound in place (like in an insulator), but when injected with enough energy, the charges can move freely (like in a conductor). Given what we have observed about the behavior of conductors and insulators in this exploration, what would happen if we replaced the glass rod with a semiconductor material

Answers

Answer:

The semiconductor rod will conduct electricity

Explanation:

Glass rod does not conduct electricity. Glass is one of the best insulators of electricity. But when a glass rod is replace with a semi conductor, then the semi conductor rod starts conducting electricity as the electrons are free to move.

Semi conductors are special materials in which the energy band lies in between the conductor and the non conductor. The conductivity of a semi conductor increases with the increasing temperature.

In an semi conductor the electrons are free to move and as they starts moving they conduct electricity. Thus a semi conductor rod replacing a glass rod conducts electricity.

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Answers

Answer:

b

Explanation:

this because if force (f) are resultant cos then the point is proportional to the direction of c at greatest possible forces

two small identical conducting spheres have charges of 2.0x10-9C and - 0.5x109 C respectively when they are placed 4cm apart, what is the force between them? If they are brought into contact and then separated by 4cm, what is the force between them? ​

Answers

Answer:

6

Explanation:

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Stacy collected the data shown in the table.
Number of Washers Total Mass Total Force
0.6 kg 5.9 N
2
1.2 kg 11.8 N
3
1.8 kg 17.6N
4
2.5 kg 24.5 N
5
3.2 kg 31.4 N
What's the general relationship between mass and gravitational force?

Answers

Answer:

1.8 Kg 17.6N

Explanation:

I don't know the explanation hahaha

Answer:

The gravitational force on an object increases as the object’s mass increases.

Explanation:

This is the answer on Edmentum. :)

A flower as an object in front of a convex mirror. A smaller upright flower closer to the mirror. A smaller upright flower close to the mirror on the other side of the mirror. An inverted smaller flower on the on the other side of the mirror just past the focal point. An inverted flower the same size as the object right below it.
Which flower would most likely represent the image formed by the mirror? Justify your answer.

Answers

Answer:

There are 13 a

Explanation:

That's the answer how many a r there

Answer:

the convex mirror will produce image 3. the image is virtual and is now behind the mirror and it becomes smaller but remains upright.

Explanation:

Plzz answer correctly

Answers

“X”. Is the answer. Tell me if you got it correct

The blood pressure at your heart is approximately 100 mm Hg. As blood is pumped from the left ventricle of your heart, it flows through the aorta, a single large vessel with a diameter of about 2.5 cm. The speed of blood flow in the aorta is about 60 cm/s. Any change in pressure as blood flows in the aorta is due to the change in height: the vessel is large enough that viscous drag is not a major factor into successively smaller and smaller blood vessels until it reaches the capillaries. Blood flows in the capillaries at the much lower speed of approximately 0.7 mm/s. The diameter of capillaries and other small blood vessels is so small that viscous drag is a major factor..Because the flow speed in your capillaries is much less than in the aorta, the total cross-section area of the capillaries considered together must be much larger than that of the aorta. Given the flow speeds noted, the total area of the capillaries considered together is equivalent to the cross-section area of a single vessel of approximately what diameter?

a. 25 cm
b. 50 cm
c. 75 cm
d. 100 cm

Answers

Answer:

The correct option is c. 75 for this question

Explanation:

The correct option is c. 75 for this question:

Let's see how.

Continuity Equation is given as:

AcVc = AaVa

Where,

Aa = Area of Aorta

Ac = Area of the capillary

Va = Fluid speed in Aorta

Vc = Fluid speed in Capillary

So,

Assuming the fluid is the ideal one/

[tex]\pi[/tex]/4 [tex]Dc^{2}[/tex] Vc= [tex]\pi[/tex]/4 [tex]Da^{2}[/tex] Va

[tex]Dc^{2}[/tex] Vc= [tex]Da^{2}[/tex] Va

Dc = Da x [tex]\sqrt{\frac{Va}{Vc} }[/tex]

Dc = 2.5 cm x [tex]\sqrt{\frac{60 cm}{0.07 cm } }[/tex]

Dc = 73.192 cm

Dc = 75 approximately

Hence, the diameter of the capillary = 75 cm approximately  

A motorcyclist is making an electric vest that, when connected to the motorcycle's 12 V battery, will warm her on cold rides. She is using 0.25-mm-diameter copper wire, and she wants a current of 4.2 A in the wire. Part A What length wire must she use

Answers

Answer:

L = 8.35 m

Explanation:

The lenght of a wire L can be calculated using the following expression:

L = R A/ρ  (1)

Where:

R: resistance of the wire

A: Cross section area of the wire

ρ: resistivity of the copper wire.

With this expression we realize that we do not have the area of the cross section, and the resistance of the wire either.

To calculate the area we can use the following expression:

A = πr²    (2)

If the diameter is 0.25 mm, then the radius is half, 0.125 mm. Converting this in meter it will have to be:

0.125 /1000 = 0.000125 m

Replacing we have:

A = π(0.000125)²

A = 4.91x10⁻⁸ m²

The reported resistivity of a copper wire is 1.68x10⁻⁸ Ω.m, so we just need to determine the resistance, which can be found using Ohm's law:

R = V/I  (3)

Replacing (3) into (1) we have:

L = (V * A) / (I * ρ) (4)

So finally, the length of the copper wire will be:

L = (12 * 4.91x10⁻⁸) / (4.2 * 1.68x10⁻⁸)

L = 8.35 m

Hope this helps

I love you


Please answer my question :-)

Answers

Answer:

A- Astronomical body

C- Galaxy

D- Comet

B- Moon

Hope this helps you! Have a great day!

Answer:

1. A

2. C

3. D

4. B

Explanation:

how is work and energy inter-related?? (in simple words)​

Answers

Answer:

The work and energy is inter- related because if we are energetic then only we are able to work.

People who are weak and not energetic cannot work continuously.

Explanation:

hope this helps you....

A steel cylinder of length 10 cm, mass 160 g and density 8 g/em. The radius of the cylinder is​

Answers

Answer:

0.8cm

Explanation:

Volume = mass/density = 160/8 = 20cm³

Volume = πr²h

r² = v/πh = 20/10π =0.64

r = √0.64 = 0.8

f body with a mass of 6kg. (Ans: When we throw a stone with 12 N force to produce an acceleration of m/s², what is the mass of 6 kg? (Ans: 1.5kg) Calculate the acceleration produced when a force of 48 N is What They m​

Answers

a. When the force = 12 N, mass = 6 kg, the acceleration is a = 2 m/s²

b. When the force = 48 N, mass = 6 kg, the acceleration is a = 8 m/s².

What is the acceleration of the body?

The acceleration of the body is calculated by applying Newton's second law of motion as follows;

F = ma

where;

F is the force applied to the objectm is the mass of the objecta is the acceleration of the object

a = F / m

when the force = 12 N, mass = 6 kg, the acceleration is calculated as;

a = 12 N / 6 kg

a = 2 m/s²

when the force = 48 N, mass = 6 kg, the acceleration is calculated as;

a = 48 N / 6 kg

a = 8 m/s²

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Which of the following helps prevent and cope with heat-related conditions?

Drinking water


Wear proper clothing


Rest frequently


all of the above

Answers

drinking water is ur answer.

An action which would help in preventing and coping with heat-related conditions is: A. Drinking water.

What is heat?

Heat can be defined as a form of energy that is transferred from a physical object (body) to another, as a result of a difference in temperature. Also, heat is a condition of weather that is generally characterized by a high degree of temperature.

This ultimately implies that, heat is most likely to cause dehydration and high body temperature.

In order to prevent and cope with heat-related conditions, you should ensure that you drink water at regular intervals for hydration.

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A car starts from rest at a stop sign. It accelerates at 2.0 m/s2 for 6.2 seconds, coasts for 2.5 s , and then slows down at a rate of 1.5m/s2 for the next stop sign. How far apart are the stop signs

Answers

Answer:

the distance between the stop signs is 120.7 m.

Explanation:

The car moved in three stages;

(1) It accelerates from rest at 2.0 m/s² for 6.2 seconds

(2) it moved at a constant speed for 2.5 s

(3) it finally decelerate at the rate of 1.5m/s²

(1) The distance moved by the car during the first stage;

s₁ = ut + ¹/₂at²

s₁ = 0 + ¹/₂ (2)(6.2)²

s₁ = 38.44 m

(2) The distance moved by the car during the second stage;

calculate the constant speed of the car,

v = u + at

v = 0 + 2 x 6.2

v = 12.4 m/s

The distance moved by the  car as it coasts for 2.5s: s₂ = vt

s₂ = 12.4 x 2.5

s₂ = 31 m

(3) The distance moved by the car during the third stage;

When the car stops, the final velocity is zero.

v² = u² + 2as₃

a = -1.5 m/s², since the car slowed down or decelerated.

0 = 12.4² + (2 x - 1.5)s₃

0 = 153.76 - 3s₃

3s₃ = 153.76

s₃ = 153.76 / 3

s₃ = 51.253 m

The total distance moved by the car from the start to stop = s₁ + s₂ + s₃

d = 38.44 m + 31 m + 51.253 m

d = 120.7 m

Therefore, the distance between the stop signs is 120.7 m.

If a shopping cart is pushed by a person exerting 50 J of work on it, what is the energy transfer to the shopping cart if it has a mass of 2 kg?

A. 52 J
B. 50 J
C. 25 J

Answers

Answer:

B

Explanation:

The "seeing" ability, or resolution, of radiation is determined by its wave length

The mass of an electrons is 9.10939 * 10^-31 kg and Planck's constant is 6.62607 * 10^-34 Js

If the size of an atom is an the order of 0.08 nm, how fast must an electron travel to have a wavelength small enough to "see" an atom? Answer in the units of m/s

Answers

ANSWER: 0.08nm !
Have a good night/day

In the human arm, the forearm and hand pivot about the elbow joint. Consider a simplified model in which the biceps muscle is attached to the forearm 3.80 cm from the elbow joint. Assume that the person's hand and forearm together weigh 15.0 N and that their center of gravity is 15.0 cm from the elbow (not quite halfway to the hand). The forearm is held horizontally at a right angle to the upper arm, with the biceps muscle exerting its force perpendicular to the forearm.
A. Find the force exerted by the biceps when the hand is empty.
B. Now the person holds a 80.0-N weight in his hand, with the forearm still horizontal. Assume that the center of gravity of this weight is 33.0 cm from the elbow. Find the force now exerted by the biceps.
C. Explain why the biceps muscle needs to be very strong.
D. Under the conditions of part B, find the magnitude of the force that the elbow joint exerts on the forearm.
E. Under the conditions of part B, find the direction of the force that the elbow joint exerts on the forearm.
F. While holding the 80.0-N weight, the person raises his forearm until it is at an angle of 53.0∘ above the horizontal. If the biceps muscle continues to exert its force perpendicular to the forearm, what is this force when the forearm is in this position?
G. Has the force increased or decreased from its value in part B? Explain why this is so, and test your answer by actually doing this with your own arm.

Answers

Answer:

Answer is explained in the explanation section below.

Explanation:

Part A)

From conserve moment of force, we have:

F1d1 = F2d2

F1 x (3.80 x [tex]10^{-2}[/tex] m) = 15N x (15 x [tex]10^{-2}[/tex] m)

F1 = [tex]\frac{15 . 15 . 10^{-2} }{3.80 . 10^{-2} }[/tex]

F1 = 59.2 N

Force exerted by the biceps when the hand is empty.

Part B)

The 80 N weight acts at 33 cm and 15 N at 15 cm, then the center of mass is:

x = [tex]\frac{m1x1 + m2x2}{m1+m2}[/tex]

x = [tex]\frac{\frac{80}{9.8} (33 .10^{-2}) + \frac{15}{9.8}(15.10^{-2} }{\frac{80}{9.8} + \frac{15}{9.8} }[/tex]

x = 30.16 x [tex]10^{-2}[/tex] m

Total Weight is:

F = 80N + 15N = 95N

From the conserve moment of force, we have:

F ( 3.8 x [tex]10^{-2}[/tex] ) = 95N (30.16 x [tex]10^{-2}[/tex])

F = 754 N

Part C:

From the above two examples solved, the force exerted by the biceps is higher than downward force, due to this muscle need to be very strong.

Part D)

The force exerted by elbow on the forearm is:

The force exerted by the elbow and biceps are in upward direction and total weight is in downward direction. So, the balancing force in vertical direction is:

F2 + 754N = 95N

F2 = 95N -754N

F2 = -659N

Negative sign shows the force is in downward direction.

Part E)

The bicep muscle acts perpendicular to the forearm, so it is lever arm stays the same. but those of the other two forces decreases as the arm is raised. There tension in the biceps muscle decreases.

Part F)

Angle = 53 degrees.

So,

Force = FcosФ

Force = 754 cos 53

Force = 453.76 N

Part G)

The value of force has gone downwards. It has decreased from that of part B.

Work is a measurement of the transfer of which of the following?
A. Impulse
B. Power
C. Energy

Answers

Answer:Enegry

Explanation:Energy transfer is used to do work

A Van de Graaff generator is one of the original particle accelerators and can be used to accelerate charged particles like protons or electrons. You may have seen it used to make human hair stand on end or produce large sparks. One application of the Van de Graaff generator is to create x-rays by bombarding a hard metal target with the beam. Consider a beam of protons at 1.10 keV and a current of 4.65 mA produced by the generator.
(a) What is the speed of the protons?
(b) How many protons are produced each second?

Answers

Solution :

Given that :

The energy of the protons, K.E. = 1.10 keV

                                                    [tex]$= 1.10 \times 10^3 \ eV $[/tex]

The current produced by the generator is I = 5 mA

                                                                        [tex]$= 5 \times 10^{-3} \ A$[/tex]

Now [tex]$1 \ eV = 1.6 \times 10^{-19 }\ J$[/tex]

Mass of the proton, m = [tex]$1.67 \times 10^_{-27} $[/tex] kg

Charge of the proton, [tex]$q_p = 1.6 \times 10^{-19} \ C$[/tex]

a). Therefore using the formula for K.E. we can find out the velocity of the proton.

[tex]$K.E. =\frac{1}{2}mv^2$[/tex]

[tex]$v=\sqrt{\frac{2K.E.}{m}}$[/tex]

[tex]$v=\sqrt{\frac{2\times 10^3 \times 1.6 \times 10^{-19}}{1.67 \times 10^{-27}}}$[/tex]

  [tex]$= 4.38 \times 10^5 \ m/s$[/tex]

b). We know that the current is :

 [tex]$I=\frac{\Delta Q}{\Delta t}$[/tex]

Therefore, the total charge in one second is given by :

[tex]$\Delta Q = I \times \Delta t$[/tex]

     [tex]$= 5 \times 10^{-3} \times 1$[/tex]

    [tex]$= 5 \times 10^{-3}\ C$[/tex]

So, the number of protons in this charge is given by :

[tex]$n = \frac{\Delta Q}{q_p}$[/tex]

  [tex]$=\frac{5 \times 10^{-3} }{1.6 \times 10^{-19}}$[/tex]

  [tex]$= 3.13 \times 10^{16}$[/tex] protons

Other Questions
reread ""pied beauty."" what is gerard manley hopkins praising? why is he praising it? For a sample of 41 New England cities, a sociologist studies the crime rate in each city (crimes per 100,000 residents) as a function of its poverty rate (in %) and its median income (in $1,000s). He finds that SSE = 4,182,663 and SST = 7,732,451. a. Calculate the standard error of the estimate. true/false. complexities often reduce span of supervision in a process layout 43. keynesian economists stress the importance of aggregate ________ and generally believe that the economy ________ to reach full-employment equilibrium on its own. design a logic circuit to determine if a binary number between 0 and 15 is a prime number (only divisible by 1 and itself) Lab 08: Reflection and Refraction of Light You will need to run a simulation to do the lab. Answer the following questions as you work through the lab. Write your answers in blue. (Note that we may miss your response if it does not stand out ) Re-load the file in word or PDF format in Canvas before the due date. Overview Light bends when it enters from one medium to another. This bending of light is called Refraction of light. The relationship between the angle of incidence (medium 1) and the angle of refraction (in the medium 2) is given by Snells Law: n_1 sin_1=n_2 sin_2 Eq. 8.1 Where n_1 is the index of refraction, _1 angle of incidence in medium 1; n_2 is the index of refraction, _2 is the angle of refraction in medium 2. The angles, are measured with respect to the normal to the surface between the two mediums. When light travels from an optically light medium to an optically dense medium, i.e. n_1 n2, the refracted light bends away from the normal. For a certain angle of incidence (called the critical angle, _c) the refracted ray will be 90 from the normal. If the angle of incidence is any larger, the ray is totally reflected in medium 1 and no light comes out of medium 2. This is called Total Internal Reflection. For this part of the lab, you will find the critical angle for different sets of boundaries. Select "More Tools" tab . Check the "normal" and "angle" box to view and measure the angles. 1. Set the Medium 1 = Glass (n1 = 1.5); Medium 2 = Air (n2 = 1.0). 2. Start with _1=0. Gradually increase _1 until the refracted ray, _2=90. This incident angle is the critical angle, _c . If you keep on increasing _1, there will only be reflected light. In this way, you can figure out the critical angle for different mediums at the boundaries listed in the table below. Table 8.5: Critical angle of different sets of boundaries Medium 1 (n1) Medium 2 (n2) Critical Angle (c) Water Air Glass Air Glass Water Mystery Medium A Air Mystery Medium A Glass 3. Conclusion Question: (i) Based on your observation in the table, what is the condition for total internal reflection? (ii) Is there a total internal reflection if both mediums have same index of refraction (e.g. n_1=n_2 )? 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