Answer:
the cost of Roy's ride is $23.05
Step-by-step explanation:
According to the Question,
Let, Cost of per minute charge is 'x' & Cost Of Per Kilometre charge is y .
Given, A ride-share company has a fee of the fixed cost of a ride is $2.55 .And, The Total cost of the Ride depends on both the time spent on travelling(in minutes), and the distance travelled(in kilometres) .⇒ Judy's ride costs $16.75 . but the actual cost after deducting the fixed charge is 16.75-2.55 = $14.20, took 8 minutes & The distance travelled was 10 km. Thus, the equation for the journey is 8x+10y=14.20 ⇒ Equ. 1
⇒ Pat's ride costs $30.35 . but the actual cost after deducting the fixed charge is 30.35-2.55 = $27.80, took 20 minutes & The distance travelled was 18 km. Thus, the equation for the journey is 20x+18y=27.80 ⇒ Equ. 2
Now, on Solving Equation 1 & 2, We get
x=0.4(Cost of per minute charge) & y=1.1(Cost Of Per Kilometre charge)
Now, Roy's ride took 10 minutes & The distance travelled was 15 km . Thus, the cost of Roy's Ride is 10x+15y ⇔ 10×0.4 + 15×1.1 ⇔ $20.5
Hence, the total cost of Roy's ride is 20.5 + 2.55(fixed cost) = $23.05
Help I’m stuck!!!! Solve the equation below for x. Enter your answer as a fraction in lowes
terms, using the slash mark (/) as the fraction bar. 4/21 + 2/9
X=
Answer:
26/63
Step-by-step explanation:
Try to make the denominators equal so that you can add them:
4(3)/21(3)= 12/63
2(7)/9(7)= 14/63
And now you add, which will give you:
12/63 + 14/63= 26/63
Can someone answer this plz
Answer:
[tex]A^{I}[/tex]= (7, -1)
Step-by-step explanation:
Rotation is a method of rigid transformation in which a point is moved about a reference point through a stated angle. The rotation could be clockwise or counterclockwise so as to produce the image of the initial object.
In the polar coordinate given, the coordinate of A is given as;
A = (3, 3)
On rotating point A about point C counterclockwise for [tex]270^{o}[/tex], an image [tex]A^{I}[/tex] would be produced.
But [tex]A^{I}[/tex] would have a coordinate;
[tex]A^{I}[/tex]= (7, -1)
The image of A produced is [tex]A^{I}[/tex] (7, -1).
Davis's Snacks will make 8,412 ounces of corn chips next year. The company plans to put the chips into 4-ounce bags. How many bags will the company be able to fill next year?
Answer:
2103 bags
Step-by-step explanation:
8412/4=2103
Instructions: Using the image, find the distance between the points given on the graph.
How many miles did it cruise?
Answer:
A. 120
Step-by-step explanation:
600÷60=10
10×12=120
Hope this helps! :)
Question 2 Multiple Choice Worth 5 points)
(02.04 LC)
Determine the equation of the line shown in the graph
Answer choices
X= 5
y = 0
x = 0
y = 5
Answer:
A
Step-by-step explanation:
The line is parallel to y axis, so the equation is x = 5
Can someone please answer these 2 questions
Answer:
part 1: $532.95. Part 2: 16
Step-by-step explanation:
Part 1: 15 * 15.35 = 230.25
30 * 10.09 = 302.70
230.25 + 302.70 = $532.95
Part 2: R = letters in the word desk
there are 4 letters in the word Desk
[tex]2^{R}[/tex] = [tex]2^{4}[/tex] = 2 * 2 * 2 * 2 = 4 * 4 = 16 subsets
Answer the questions for BRAINLIEST (EASY)
A.
B.
C.
Answer:
A=x-3
B=X-14
C=X-10
a trader sold an article at 10% profit if he had sold it at 10% loss,it would yield RS 140 less than the previous selling price.find the cost price of the article.
Answer:
CP = ₹ 700
Step-by-step explanation:
Let the cost price be 'x'
SP = [tex](\frac{100+Profit}{100})*CP[/tex]
[tex]= \frac{100+10}{100}*x\\\\=\frac{110}{100}*x\\\\= \frac{11}{10}x[/tex]
If it had been sold are 10% loss, then
SP = [tex](\frac{100-loss}{100})*CP[/tex]
[tex]=\frac{100-10}{100}*x\\\\=\frac{90}{100}*x\\\\=\frac{9}{10}x[/tex]
Difference in both the selling price = 140
[tex]\frac{11}{10}x-\frac{9}{10}x=140\\\\\\\frac{2}{10}x=140\\\\\frac{1}{5}x=140\\\\ x = 140*5\\x = 700[/tex]
In the diagram below, ΔABC≅ΔSTR. Complete the statement ∠A≅
A. ∠C
B. ∠S
C. ∠T
D. ∠R
Answer:
b
Step-by-step explanation:
Answer: B <S
Step-by-step explanation:
Leona has a large bag of apples. There are 180 apples in the bag. She uses 14of the apples to make some juice. She uses 20% of the apples to make some pies. How many apples are left?
Answer:
132.8 are left enjoy
The perpendicular room is 4m long, 3m wide and 2.5m high. They tiled and painted the interior walls of the room. How many square meters of tiles should be used? Answer only
Answer:
12m²
Step-by-step explanation:
are the files to be used only for the floor, or also for the walls ? ceiling ?
if it is only for the floor, then the height of the room is irrelevant.
perpendicular clearly stands here for rectangular.
so, the good of the room is a rectangle of 4m length and 3m width.
the area of a rectangle is length×width.
area = 4×3 = 12m²
so, 12m² of tiles will be needed (in reality there would be at least 10% to 20% added for bad tiles, wrong cuts, ...).
if walls need to be included, then you will have to add the areas of 4 more rectangles of length×height.
which would be 2 times 3×2.5 = 7.5m² and 2 times 4×2.5 = 10m².
so, the total area incl. walls would be
12 + 7.5 + 7.5 + 10 + 10 = 47m²
if the ceiling has to be included too, then you need to add the area of another rectangle of the same size as the floor.
so, that total would then be
47 + 12 = 59m².
Complete the proof that
Answer:
The two column proof is presented as follows;
Statement [tex]{}[/tex] Reason
ΔSCW ≅ ΔTUW [tex]{}[/tex] Given
[tex]\overline {SV}[/tex] ≅ [tex]\overline {TU}[/tex] [tex]{}[/tex] CPCTC
[tex]\overline {SW}[/tex] ≅ [tex]\overline {TW}[/tex] [tex]{}[/tex] CPCTC
[tex]\overline {WV}[/tex] ≅ [tex]\overline {UW}[/tex] [tex]{}[/tex] CPCTC
∠SVW ≅ ∠TUW [tex]{}[/tex] CPCTC
SU = SW + UV [tex]{}[/tex] Additive property of Length
TU = TW + VW [tex]{}[/tex] Additive property of Length
SU = TW + VW [tex]{}[/tex] Substitution
SU = TV [tex]{}[/tex] [tex]{}[/tex] Transitive property
ΔSTV ≅ ΔTSU [tex]{}[/tex] SAS
∠TSV ≅ ∠STU [tex]{}[/tex] CPCTC
Step-by-step explanation:
The two column proof is presented as follows;
Statement [tex]{}[/tex] Reason
ΔSCW ≅ ΔTUW [tex]{}[/tex] Given
[tex]\overline {SV}[/tex] ≅ [tex]\overline {TU}[/tex] [tex]{}[/tex] Congruent Parts of Congruent Triangles are Congruent
[tex]\overline {SW}[/tex] ≅ [tex]\overline {TW}[/tex] [tex]{}[/tex] Congruent Parts of Congruent Triangles are Congruent
[tex]\overline {UV}[/tex] ≅ [tex]\overline {VW}[/tex] [tex]{}[/tex] Congruent Parts of Congruent Triangles are Congruent
∠SVW ≅ ∠TUW [tex]{}[/tex]Congruent Parts of Congruent Triangles are Congruent
SU = SW + UV [tex]{}[/tex] Additive property of Length
TU = TW + VW [tex]{}[/tex] Additive property of Length
SU = TW + VW [tex]{}[/tex] Substitution
SU = TV [tex]{}[/tex] Transitive property
ΔSTV ≅ ΔTSU [tex]{}[/tex] Side-Angle-Side rule of congruency
∠TSV ≅ ∠STU [tex]{}[/tex] Congruent Parts of Congruent Triangles are Congruent
Pls I beg someone to finish ALL of this :(. I’ve stayed up all night to do this but I couldn’t figure all of them out. Pls pls pls!!! ill mark you brainliest n I can give you a thank you such as 5 Stars in return. Please take your time and I hope you all have a amazing day!
Answer:
Question 1: 75 minutes
Question 2: 4:07
Question 3: 30 minutes
Question 4: 8:35
Step-by-step explanation:
An hour is sixty minutes; that's the key to solving these questions.
The time basketball was played is 75 minutes or 1 hour 15 minutes
The time I get home is at 4:07
The cook was cooked for 30 minutes.
The cheerleading was over at 8:35.
What is unit conversion?It is the conversion of one unit to another unit with its standard conversion.
We have,
Trey and Na Asia played basketball from 10:30 - 11:45.
From 10 to 11 we have 60 minutes.
= 60 minutes - 30 minutes [10:30] + 45 minutes [ 11:45]
= 105 minutes - 30 minutes
= 75 minutes
The time basketball was played.
= 75 minutes
= 1 hour 15 minutes
I left school at 3:15 on the bus. I got home 52 minutes later.
1 hour = 52 minutes
= 3:15 + 52 minutes
= 3 + 15 minutes + 52 minutes
= 3 + 67 minutes
= 3 + 1 hour + 7 minutes
= 4:07
The time I get home is at 4:07
Antavious makes Macaroni and cheese. He begins making it at 6:35 and finished at 7:05.
= 6:35 to 7:05
From 6 to 7 we have 60 minutes.
So,
= 60 minutes - 35 minutes [6:35] + 5 minutes [7:05]
= 65 minutes - 35 minutes
= 30 minutes
The cook was cooked for 30 minutes.
Makhiya and Madison went to cheerleading at 7:15. It was over 1 hour and 20 minutes later.
= 7:15 + 1 hour + 20 minutes
= 7 + 15 minutes + 1 hour + 20 minutes
= 8 + 35 minutes
= 8:35
The cheerleading was over at 8:35.
Thus,
The time basketball was played is 75 minutes or 1 hour 15 minutes
The time I get home is at 4:07
The cook was cooked for 30 minutes.
The cheerleading was over at 8:35.
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solve for the missing sidebof the triangle shown in the figure
Answer:
∠B = 74°
a ≈ 14.5 inches
c ≈ 11.4 inches
Step-by-step explanation:
The given parameters of triangle ΔABC are;
∠A = 62.2°, ∠C = 43.8° and side [tex]\overline{AB}[/tex] = b = 15.8 in
By sine rule, we have;
[tex]\dfrac{a}{sin(\angle A)} = \dfrac{b}{sin(\angle B)} = \dfrac{c}{sin(\angle C)}[/tex]
[tex]a = {sin(\angle A)} \times \dfrac{b}{sin(\angle B)}[/tex]
By angle sum property, we have;
∠B = 180° - (∠A + ∠C)
∴ ∠B = 180° - (62.2° + 43.8°) = 74°
∠B = 74°
[tex]\therefore {a} = {sin(62.2^{\circ})} \times \dfrac{15.8}{sin(74^{\circ})} \approx 14.5[/tex]
a ≈ 14.5 in.
[tex]c = {sin(\angle C)} \times \dfrac{b}{sin(\angle B)}[/tex]
[tex]\therefore {c} = {sin(43.8^{\circ})} \times \dfrac{15.8}{sin(74^{\circ})} \approx 11.4[/tex]
c ≈ 11.4 in.
What is the mode
of 2, 8, 16, 4,
12, 9, 2?
The mode is the highest frequency data among the given data set is 2.
What is the mode?The value that appears most frequently in a data set is called the mode. One mode, several modes, or none at all may be present in a set of data.
Mode is the highest frequency of any number among data
For example 2,3,5,5,6,5,9,8,5,1
Here mode will be 5 because it has a frequency of 4 remaining all have a lower frequency than 5.
Given the data set is
2, 8, 16, 4, 12, 9, 2
2 has frequency = 2
And remaining all have a frequency as 1
Since 2 has the highest frequency so it will be mode.
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3n^5 ÷ 6n^3, using properties of exponents
Answer:
Step-by-step explanation:
[tex]\frac{a^{m}}{a^{n}}=a^{m-n}\\\\\frac{3n^{5}}{6n^{3}}=\frac{3}{6}*n^{5-3}\\\\=\frac{1}{2}n^{2}[/tex]
Answer:
[tex]\frac{n^{2} }{2}[/tex]
Step-by-step explanation:
Rewrite the division as a fraction.
[tex]\frac{3n^{5} }{6n^{3} }[/tex]
Cancel the common factor of 3 and 6.
[tex]\frac{3(n^{5}) }{6n^{3} }[/tex]
[tex]\frac{n^{5} }{2n^{3} }[/tex]
Cancel the common factor
[tex]\frac{n^{2} }{2}[/tex]
Hope this helps!
If you need more help with questions like these please reach out to me!
Write and solve a real-world problem that involves finding the volume of a rectangular or triangular prism
Answer:
l
Step-by-step explanation:
Question 24 of 25 The graph of F(x) shown below resembles the graph of G(X) = x2, but it has been changed somewhat. Which of the following could be the equation of F(x)? G(X) = x2 Fx) = ?
Answer:
!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!;;;;!!!!!!!!!!!
The required equation of graph f(x) is y = -x²-3.
What is parabola?A parabola is a U-shaped plane curve where any point is at an equal distance from a fixed point (known as the focus) and from a fixed straight line which is known as the directrix.
here, we have,
Given that,
The graph of f(x), resembles the graph of G(x) =x^2 .
We have to find,
Which of the following could be the equation of f(x).
According to the question,
Function, G(X) = x^2 ,
The graph in the given question figure. It is a parabola with vertex at (0,0).
By the graph predict that Sign of x^2 is positive, that is why the parabola opens up.
General equation of parabola is given by,
y = a(x-h)^2 + k
Where, a = 1, and vertex (h, k) is (0,0).
The graph of F(x) unknown function opens down ,
Sign of x^2 as negative. and the vertex is at (0,-3)
To find the equation of function f(x),
Putting the values of a and vertex coordinates,
y = a(x-h)^2 + k
The equation of parabola become:
y = -x²-3.
(solving we get)
Hence, The required equation of f(x) is y = -x²-3.
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If triangle LMN ~ triangle PON, what is MN?
Answer:
pretty sure its 40cm
Step-by-step explanation:
hope this helps :)
Answer:
36cm
Step-by-step explanation:
Tan(14/12)=angle of ONP
Tan(42/X)=angle of LNM
singe those angels are the same;
Tan(14/12)=Tan(42/X)
14/12=42/X
14*X=42*12
X=(42*12)/14
X=36
if 6.2a=0.0143 then what is a?
6.2a = 0.0143
=> a = 0.0143/6.2
=> a = 0.0023......
Please help i dont remember how to do this
the girls heights in inches are as follows:62,70,60,63,66,what is their average height?
Answer:
Average height = 64.2 inches
Step-by-step explanation:
[tex]Average = \frac{sum \ of \ the \ values }{number \ of\ value}[/tex]
[tex]=\frac{62 + 70 + 60 + 63 + 66}{5}\\\\=\frac{321}{5}\\\\=64.2 \ inches[/tex]
The average of the given heights is 64.2 inches
What is an average?
An average of a list of data is the expression of the central value of a set of data. It is defined as the ratio of summation of all the data to the number of units present in the list.
According to the given problem,
Given data = { 62, 70, 60, 63, 66 }
Sum of the given heights = ( 62 + 70 + 60 + 63 + 66 )
= 321
Average = [tex]\frac{321}{5}[/tex]
= 64.2 inches
Hence, we can conclude, the average of the given data is 64.2 inches.
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Please solve with explanation.
Answer:
Area = 160 cm²
Perimeter = 55.31 cm
Step-by-step explanation:
Applying,
Area of the figure = area of the rectangle- area of the triangle
A = lw+bh/2............... Equation 1
From the question,
Given: l = 16 cm, w = 12 cm, h = 8cm, b = 8 cm
Substitute these values into equation 1
A = (16×12)-(8×8/2)
A = 192-32
A = 160 cm²
Perimeter P = /BC/+/CD/+/DE/+/EF/+/FG/+/GA/
Applying pythagoras theorem to get /FG/
FG² = GE²+EF²
FG² = 8²+8²
FG² = 64+64
FG² = 128
FG = √128
FG = 11.31 cm
Therefore,
P = 16+12+4+8+11.31+4
P = 55.31 cm
The variable 100 POINTS!!!!
What is the value of 2 + (-2/3) ^2 ÷1/3 ?
16
3 1/3
-2
0
Answer:
second option is correct
Please help me out this is hard .
Answer:
24.6
Step-by-step explanation:
take 72 degree as reference angle
using tan rule
tan 72 = opposite / adjacent
3.07 = x/8
3.07 * 8 = x
24.56 = x
24.6 = x
The length of the rectangle, in feet, is represented by (5x + 4). Find the perimeter of the rectangle.
Solve the following inequality for qq. Write your answer in simplest form. -6q+7≤8q-3
Answer:
q ≥ 5/7
General Formulas and Concepts:
Pre-Algebra
Order of Operations: BPEMDAS
Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to RightEquality Properties
Multiplication Property of Equality Division Property of Equality Addition Property of Equality Subtraction Property of EqualityAlgebra I
Terms/CoefficientsStep-by-step explanation:
Step 1: Define
Identify
-6q + 7 ≤ 8q - 3
Step 2: Solve for q
[Subtraction Property of Equality] Subtract 8q on both sides: -14q + 7 ≤ -3[Subtraction Property of Equality] Subtract 7 on both sides: -14q ≤ -10[Division Property of Equality] Divide -14 on both sides: q ≥ 5/7Here we see that any number q greater than or equal to 5/7 would work as a solution to the inequality.
Answer:
q ≥ [tex]\frac{5}{7}[/tex]
Step-by-step explanation:
Given
- 6q + 7 ≤ 8q - 3 ( add 6q to both sides )
7 ≤ 14q - 3 ( add 3 to both sides )
10 ≤ 14q ( divide both sides by 2 )
5 ≤ 7q ( divide both sides by 7 )
[tex]\frac{5}{7}[/tex] ≤ q , then
q ≥ [tex]\frac{5}{7}[/tex]
Write the equation of the line that passes through points A(6,1) and B(9,4)? simple answers
Given:
Two points are A(6,1) and B(9,4).
To find:
The equation of the line that passes through the given points.
Solution:
If a line passes through two points [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex], then the equation of the line is:
[tex]y-y_1=\dfrac{y_2-y_1}{x_2-x_1}(x-x_1)[/tex]
It is given that the line passes through the two points A(6,1) and B(9,4). So, the equation of the line is:
[tex]y-1=\dfrac{4-1}{9-6}(x-6)[/tex]
[tex]y-1=\dfrac{3}{3}(x-6)[/tex]
[tex]y-1=1(x-6)[/tex]
[tex]y-1=x-6[/tex]
Adding 1 on both sides, we get
[tex]y-1+1=x-6+1[/tex]
[tex]y=x-5[/tex]
Therefore, the equation of the line is [tex]y=x-5[/tex].
what is the domain of the function represented by the graph
Answer:
Domain: all real numbers
Step-by-step explanation:
The domain is the values that x can take
X can be any real number
Domain: all real numbers