The magnitude of the weight of the disk is greater than the magnitude of the tension force of the string. ((c) [tex]F_{T} < F_{g}[/tex])
How to analysis a rigid body on dynamical conditionA rigid body is a system whose geometry cannot be neglected and in which deformations due to external forces applied on the system are negligible.
In this question we need to establish a free body diagram with all critical forces and motion conditions. There are two external forces: (i) tension ([tex]F_{T}[/tex]), (ii) weight ([tex]F_{g}[/tex]), both in newtons.
The disk falls due to gravity and rotates around the string in a case of rolling, which combines rotation and translation. By Newton's laws of motion we have the following expression:
[tex]\sum F = -F_{g}+F_{T} = -m\cdot R\cdot \alpha[/tex] (1)
Where:
[tex]m[/tex] - Mass of the disk, in kilograms.[tex]\alpha[/tex] - Angular acceleration, in radians per square second.By algebra we derive the following relationship between the two forces:
[tex]-F_{g} = -F_{T}-m\cdot R\cdot \alpha[/tex]
[tex]F_{g} > F_{T}[/tex]
Therefore, the magnitude of the weight of the disk is greater than the magnitude of the tension force of the string. ((c) [tex]F_{T} < F_{g}[/tex]) [tex]\blacksquare[/tex]
Remark
The statement is incomplete and poorly formatted. Correct and complete form is shown below:
A thin uniform disk of mass m and radius r has a string wrapped around its edge and attached to the ceiling. The bottom of the disk is at height 3R above the floor, as shown above. The disk is released from rest. The rotational inertia of a disk around its center is [tex]I = \frac{1}{2}\cdot M\cdot R^{2}[/tex].
When released from rest, the disk falls and the string unwinds. The force that the string exerts on the disk is [tex]F_{T}[/tex], and the gravitational force exerted on the disk is [tex]F_{g}[/tex]. Which of the following expression correctly relates [tex]F_{T}[/tex] and [tex]F_{g}[/tex] as the disk falls?
(a) [tex]F_{T} > F_{g}[/tex], (b) [tex]F_{T} = F_{g}[/tex], (c) [tex]F_{T} < F_{g}[/tex]
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Based on the figure, a decrease in _________ could cause the economy to move from point a to point b
A decrease in production of goods could cause the economy to move from point a to point b.
What cause shifts in economy?Shifts in the production are due to many factors that change the output of an economy such as advances in technology, changes in resources, more education or training and changes in the labor force.
So we can conclude that a decrease in production of goods could cause the economy to move from good to poor.
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A fish swimming at a constant speed of 0.5 m/s suddenly notices a shark
appear behind it. Five seconds later, the fish is swimming in the same
direction at a speed of 3.5 m/s. Calculate the fish's acceleration?
PLEASE HELP <33
Sound can't travel through a
Question 4 options:
A. liquid.
B. vacuum.
C. solid.
D. gas.
Answer:
Vacuum
Explanation:
Sound waves can travel through any medium, such as a solid, a liquid, or a gas. However, sound doesn’t travel through a vacuum, which is why sounds can't be heard in outer space.
PF
Jessie hits a foul ball
straight up in the air
during a softball game.
Assuming all energy is
conserved, at what height
did the 3 kg ball travel if it
had a velocity of 11 m/s?
Answer:
GPE=(3*11^2)/2
(3*121)/2
363/2
GPE=181.5J
Explanation:
Which letter explains why no machine is 100 percent efficient.
A.Mechanical energy is transformed into thermal energy by friction.
B.Mechanical energy is transformed into electrical energy by a spark.
C.Thermal energy is transformed into mechanical energy by friction.
Answer:
A
Explanation:
Think about rubbing your hands together- the friciton produces heat
The magnetic flux through a coil of wire containing two loops changes at a constant rate from -58 wb to 38 wb in 0. 34 s. What is the emf induced in the coil?
Since the magnetic flux through a coil of wire containing two loops changes at a constant rate from -58 wb to 38 wb in 0. 34 s, the emf induced in the coil is -5.65 V
Induced emf in coilThe induced emf in the coil is given by ε = -NΔΦ/Δt where
ΔΦ = change in magnetic flux Φ₂ - Φ₁ where Φ₁ = initial magnetic flux = -58 Wb and Φ₂ = final magnetic flux = 38 Wb and and Δt = change in time = t₂ - t₁ where t₁ = initial time = 0 s and t₂ = final time = 34 sand N = number of loops of coil = 2Since ε = -NΔΦ/Δt
ε = -N(Φ₂ - Φ₁)/(t₂ - t₁)
Substituting the values of the variables into the equation, we have
ε = -N(Φ₂ - Φ₁)/(t₂ - t₁)
ε = -2(38 Wb - (-58 Wb))/(34 s - 0 s)
ε = -2(38 Wb + 58 Wb)/(34 s - 0 s)
ε = -2(96 Wb)/34 s
ε = -192 Wb/34 s
ε = -5.65 Wb/s
ε = -5.65 V
So, the emf induced in the coil is -5.65 V
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The electrical action generated by a non-electrical source, measured in volts. The emf induced in the coil is -564.7 V.
What is EMF?The electrical action generated by a non-electrical source, measured in volts, is referred to as emf or electromotive force. Devices, such as batteries or generators, generate an emf by converting various sources of energy into electrical energy.
The emf induced in a coil is given by
[tex]\varepsilon = \dfrac{-N \times \triangle \phi}{ \triangle t}[/tex]
where
ΔΦ is the change in magnetic flux, Δt is the change in time, and N is the number of loops.
Given that the initial magnetic flux is -58 Wb while the final magnetic flux is 38 Wb. Also, the change in time is 0.34 seconds and the number of loops is 2. Therefore, the emf induced can be written as,
[tex]\varepsilon = \dfrac{-N \times \triangle \phi}{ \triangle t}[/tex]
[tex]\varepsilon = \dfrac{-(2) \times [38-(-58)]}{0.34}\\\\\varepsilon = -564.7\rm\ V[/tex]
Hence, the emf induced in the coil is -564.7 V.
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The particles in a balloon push out on the sides of the balloon. What is the reaction force?
A. The balloon wall pushes the enclosed air particles inwards.
B. The string of the balloon on the particles in the environment.
C. There are no forces involved in a balloon filled with air.
If a satelite with a mass of 9 x 10^2 kg is placed in an orbit around a planet with a mass of 6 x 10^20 kg, at a speed of 17000 m/s, find the distance from the center of the planet to the satelite.
Hi there!
We can begin by deriving an equation for the orbital radius.
For an object orbiting the earth, it is experiencing a centripetal force due to the force of gravitation.
Recall Newton's Law of Universal Gravitation:
[tex]F_g = \frac{Gm_1m_2}{r^2}[/tex]
G = Gravitational Constant (6.67 × 10⁻¹¹ Nm²/kg²)
m = masses (kg)
r = radius (m)
This is equivalent to the satellite's centripetal force experienced:
[tex]F_c = \frac{m_sv^2}{r}[/tex]
[tex]m_s[/tex] = mass of satellite (kg)
v = velocity (m/s)
r = radius (m)
Set the two equal, and rearrange for the orbital radius of the satellite.
[tex]\frac{Gm_sm_p}{r^2} = \frac{m_sv^2}{r}\\\\\frac{Gm_p}{r} = v^2\\\\r = \frac{Gm_p}{v^2}[/tex]
Notice that the orbital radius of the satellite does NOT depend on the satellite's mass. (we canceled it out).
Now, plug in the given values.
[tex]r = \frac{(6.67\times 10^{-11})(6\times 10^{20})}{17000^2} = \boxed{138.478 m}[/tex]
What is the direction of the normal contact force of the road on the wheels?
Tick one box.
Down
Left
Right
Up
The direction of the normal contact force of the road on the wheels is : ( B ) Left
Contact force
The contact force of the road on the wheels will act in a direction opposite to the movement of the wheel on the road. therefore as the wheel moves forward ( right ), the contact force will move backwards ( left ) of the direction of motion.
Hence we can conclude that the direction of the normal contact force of the road on the wheels is : ( B ) Left
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How does the maximum value of the current depend on the frequency of the ac voltage source?.
The maximum value of the current depend on the frequency of the ac voltage source because it increases as the frequency increases.
What is peak current of AC source?
The peak current of an ac source is the amplitude current flowing in the ac circuit.
The magnitude of the peak current is calculated as follows;
I₀ = i/(sin ωt)
I₀ = i/(sin 2πft)
where;
I₀ is the peak currenti is the ac currentω is angular speedf is the frequencyt is timemaximum value ac currenti = I₀ x sin 2πft
From the equation above, as the frequency of the of the ac voltage source increases, the value of the ac current (i) increases.
Thus, the maximum value of the current depend on the frequency of the ac voltage source because it increases as the frequency increases.
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Control rods are used to slow down the reaction in the reactor core when the core becomes too hot. Please select the best answer from the choices provided T F.
The best answer is true. Yes, control rods are used to slow down the reaction in the reactor core when the core becomes too hot.
What is a nuclear reactor?A nuclear reactor, often known as an atomic pile, is a device that initiates and controls nuclear chain reactions or nuclear fusion processes.
Nuclear reactors are used in nuclear power plants to generate energy as well as in nuclear marine propulsion.
Control rods are employed in nuclear reactors because the processes that occur in a nuclear reactor are very exothermic.
As a result, when these control rods are infused into a nuclear reactor, they absorb neutrons and aid in the management of the chain reaction. As a result, the rate of the chain reaction is brought under control.
As a result, we may infer that the statement control rods are employed to slow down the reaction in the reactor core when it gets too hot is correct.
Hence the best answer is true. Yes, control rods are used to slow down the reaction in the reactor core when the core becomes too hot.
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do you think your real?
Answer: Yes I am alive.
How can gravitational tugs from orbiting planets affect the motion of a star?.
Answer:
Gravitational tugs from orbiting planets don't affect the motion of a star. The star, being much larger than the planet, has a much smaller orbit. But it does move slightly. Explain how alien astronomers could deduce the existence of planets in our solar system by observing the Sun's motion.
Money functions primarily as a medium of
a unit of
and a store of value.
.
Answer:
buying and selling goods and services. and exchange account
Explanation:
:)
Answer:
when money is used to intermediate the exchange of goods and services
What is the average velocity of the fly between 0 and 15 seconds
Answer:
where is the displacement
[tex]v = \frac{s}{t} [/tex]
The average velocity of the fly between 0 and 15 seconds will be 10 m/sec.Velocity is the time-based component.
What is average velocity?
The average velocity is the ratio of the total distance traveled to the total time taken by the body. Its unit is m/sec.
From the given graph it is obsderved that the displacement from 0 to 15 seconds will be 150 m.
[tex]\rm V = \frac{D_2-d_1 }{t_2-t_1} \\\\ V = \frac{150}{15-0} \\\\ V= 10 \ m/sec[/tex]
Hence the average velocity of the fly between 0 and 15 seconds will be 10 m/sec.
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One square megameter is equal to 1. 0×106 square kilometers. How many square megameters are in 4,000,000 square kilometers?
Answer:
One has 1E6 km^2 / MM
4E6 km^2 / (1E6 km^2/MM) = 4 MM or 4 megameter
In 4000,000 square kilometers, there are 4 square megameters if the one square megameter is equal to 1. 0×106 square kilometers.
What is unit conversion?It is defined as the conversion from one quantity unit to another quantity unit followed by the process of division, and multiplication by a conversion factor.
We have:
One square megameter = [tex]1\times10^6[/tex]
Let's suppose the x square megameters in the 4,000,000 square kilometers
Then x can be found as follows:
[tex]\rm x = \frac{4,000,000}{1\times10^6}[/tex]
x = 4 square megamters
Thus, in 4000,000 square kilometers, there are 4 square megameters if the one square megameter is equal to 1. 0×106 square kilometers.
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Select the correct answer.
Which of the following social events are often centered around sporting events?
A. Tailgate Parties
B. Parades
C. Pep Rallies
D. All of the above
the red lines on this
national weather
service weather map
connect areas of equal
air pressure. what do
meteorologists call
these lines?
a. isobars
b. cold fronts
c. air masses
d. isotherms
The study of electrons as it relates to their use in electric devices
Answer:
An electron is a component of the broader term, electricity. Generally electricity refers to the control, manipulation, and use of the movement of electrons to perform some kind of work (motion/rotation, light, heat, etc…).
Explanation:
Or
put this
The study of electrons as it relates to their use in electric devices is electricity.
But I will go with the first one
A fighter plane is descending at 30 m/s. The pilot ejects, and the ejector seat accelerates him upwards at 120 m/s2 for 2 seconds. What is his velocity at the end of the 2 seconds?
Answer:
210m/s upwards
Explanation:
u= -30m /s
a= 120m/s^2
t=2s
v=u+at
=(-30)+(120x2)
=240-30
=210m/s
Distinguish between pressure and force in the case of wang yourself on a common bathroom scale
Answer: hey here's your answer...
Explanation: We can think of a force as a push on a surface, such as the force due to gravity you exert when standing on a bathroom scale. Pressure involves the distribution of force. The scale measures force, not pressure, so your weight reading is the same no matter how you distribute your weight on the scale.
Hope this helps...
Have a nice day-
its about dirve its about power
Answer:
We stay hugely we devour
Explanation:
It's the rock
Which has a greater energy, long wavelength red light or short wavelength uv light?.
please solve this as fast as you can
B
The combustion of the fuel in the helicopter is chemical energy. The vertical change in height is the result of kinetic energy. Because the helicopter is hovering in the air, it has gravitational potential.
Answer:
this would be B friend :)
Explanation:
how far does a 1.2g bullet with kinetic energy of 1.2 j go in 2 seconds ?
Answer:
To calculate the energy in joules, simply enter the mass of ammunition (in grams) that you use, and the fps that you've read from your Chrono unit.
A car of 15 kg is traveling on a circular track. If the radius of the track is
7. 8 m and the period is 8. 5 seconds, what's the centripetal force on
the car? (Round to the nearest hundredth)
The magnitude of the centripetal force on the car is 69.6 N.
What is centripetal force?This is a force acting on a body in circular path and it is directed to the center around which the body is moving.
To calculate the centripetal force on the car, we use the formula below.
Formula:
F = m(4π²/t²)........ equation 1Where:
F = Magnitude of the centripetal force on the car, m = mass of the cart = timeFrom the question,
Given:
m = 15 kgt = 8.5π = 3.14Substitute these values into equation 1
F = 15(4×3.14²/8.5²)F = 69.6 NHence, the magnitude of the centripetal force on the car is 69.6 N.
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A very long straight wire carries a current i in the z direction
Answer:
what are you calculating put the full question so I can help you out: )
Explanation:
its quite confusing just a little lol
On the electromagnetic spectrum, what type of light is higher energy: X-rays or radio waves?
Answer:
Radio
Explanation:
X-rays is 10 x 10^-10
radio is 10⁴
A group of graduate students, bored during a cloudy night at the observatory, begin to make bets about the time different stars will take to evolve. If they have a cluster of stars which were all born at roughly the same time, and want to know which star will become a red giant first, which of the following stars should they bet on?
A) a star of about the same mass as our Sun
B) a star that would type O on the main sequence star
C) a star of about 1/2 the mass of our Sun
D) a star of about 8% the mass of our Sun
E) you can't fool me, all stars reach the red giant stage in roughly the same number of years
The stars which they should bet on is D) a star of about 8% the mass of our Sun.
What is a Star?
This refers to the astronomical object which is very far away in the galaxy and and of which the closest star to the Earth is in fact the Sun.
With this in mind, we can see that the students are making bets about the time different stars will take to evolve and want to know which star will become a red giant first so they should bet on a star of about 8% the mass of our Sun.
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A block initially at rest on a horizontal, frictionless surface is accelerated by a constant horizontal force of 5. 0 newtons. If 15 joules of work is done on the block by this force while accelerating it, the kinetic energy of the block increases by.
By the work-energy theorem, the block's kinetic energy is increased by 15 J. The only force performing work on the block is the constant 5.0-N push.