About how many kwh does the solana parabolic trough solar array generate in a month?

Answer: Velocity can best be described as, the speed in a given direction.

Explanation: To find the answer, we need to know more about the Velocity of a body.

Thus, we can conclude that, the option C is best describing velocity.

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The speed in a certain direction is the best way to define velocity.

We need to learn more about a body's velocity in order to locate the solution.

As a result, we can say that choice C best captures velocity.

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Answer:

St. Elmo's Fire - well known to old time sailors

A. The height above the ground reached by the mass is 2.3 m.

P.E = mgh

where;

h = P.E/mg

h = (342)/(15.2 x 9.8)

h = 2.3 m

Thus, the height above the ground reached by the mass is 2.3 m.

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Answer:

Gravity

Explanation:

The more massive the object is, the higher the gravity

Hence, a massive star, like our sun, has enough gravity to pull on planets and keeping them in orbit

The second step would be to divide the mass of the compound by the molar mass of the compound.

In converting the mass of a compound to the number of moles of the same compound, one needs to divide the mass by the molar mass of the compound.

Mathematically, this is expressed as:

Number of moles of a compound = mass of the compound/molar mass of the compound.

Thus, the first step would be to calculate the molar mass of the compound from the molar weight of the atoms of elements that constitute the compound.

The second step would then be to divide the mass by the calculated molar mass in order to obtain the number of moles.

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The Earth’s average orbital speed expressed in kilometers per hours is 107225.5 Km/hr and the mass of the sun is 2.58 x [tex]10^{24}[/tex] Kg

Linear speed is the product of angular speed and the maximum displacement of the particle. That is,

V = Wr

Where

Given that the earth orbits the sun at an average circular radius of about 149.60 million kilometers every 365.26 Earth days.

a) To determine the Earth’s average orbital speed, we will make use of the below formula to calculate angular speed

W = 2[tex]\pi[/tex]/T

W = (2 x 3.143) / (365.26 x 24)

W = 6.283 / 876624

W = 7.2 x [tex]10^{-4}[/tex] Rad/hr

The Earth’s average orbital speed V = Wr

V = 7.2 x  [tex]10^{-4}[/tex] x 149.6 x [tex]10^{6}[/tex]

V = 107225.5 kilometers per hours.

b) Based on the information given in this question, to calculate the approximate mass of the Sun, we will use Kepler's 3rd law

M = (4[tex]\pi ^{2}[/tex][tex]r^{3}[/tex]) / G[tex]T^{2}[/tex]

M = (4 x 9.8696 x 3.35 x [tex]10^{24}[/tex]) / (6.67 x [tex]10^{-11}[/tex] x 7.68 x [tex]10^{11}[/tex])

M = 1.32 x [tex]10^{26}[/tex] / 51.226

M = 2.58 x [tex]10^{24}[/tex] Kg

Therefore, the Earth’s average orbital speed expressed in kilometers per hours is 107225.5 Km/hr and the mass of the sun is 2.58 x [tex]10^{24}[/tex] Kg

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(a) The forces acting on the truck is not balanced.

(b) The resultant force acting on the truck is 40 N towards the right direction.

(c) As the resultant force increases, the speed of the truck increases.

net vertical force = 500 N - 500 N = 0

net horizontal force = 100 N - 60 N = 40 N

The forces acting on the truck is not balanced.

The resultant force acting on the truck is 40 N towards the right direction.

Thus, as the resultant force increases, the speed of the truck increases.

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If the density of water does not vary and the vents range in depth from about 1500 m to 3200 m below the surface, then the gauge pressure at a 2452-m deep vent is 224.268 atm.

Calculation:

Step-1:

It is given that the vents range in depth from about 1500 m to 3200 m below the surface. If we are assuming that the density of water does not vary. Then it is required to calculate the gauge pressure at a 2452-m deep vent.

The gauge pressure at a particular depth of ocean water is calculated as:

[tex]$$P=\rho g h$$[/tex]

Here [tex]\rho[/tex] is the density of water, P is the required pressure, h is the depth of water, and g is the gravitational acceleration.

Step-2:

Now we are substituting the values to calculate the pressure at the depth of 2452-m.

[tex]$$\\\begin{aligned}\\P&=\rho gh\\&=1030 (\text{ kg/m}^3)\times 9.8 (\text{ m/s}^2)\times 2452 \text{ m}\\&=24.75\times 10^6 \text{ Pa}\times\frac{1 \text{ atm}}{10.1325 \times10^4 \text{ Pa}}\\&=224.268 \text{ atm}\\\end{aligned}\\$$[/tex]

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The diameter of the largest orbit just before the protons exit the cyclotron is 39 cm.

The number of orbits completed by the proton during this 1.0 ms is 14000 revolutions.

The kinetic energy for the protons can be computed by using the formula:

mv² = 2 K.E

v = sqrt( 2*KE / M)

the kinetic energy of the medical isotopes = 6.5 MeV

substituting the values,

v = sqrt( 2* 6.5* 1.6* 10^-13 / 1.67* 10^-27 )

v = 3.53 × 10⁷ m/s

The radius of the orbit can be estimated by using the formula:

mv² / R = qvB

r = q*v / mv²

r = ( 1.67* 10^-27 * 3.53 × 10⁷ ) / ( 1.9* 1.6* 10^-19 )

r = 0.19415 m

Since diameter (D) = 2r,

D= 2(0.19415  m)

D= 0.39 m

D≅ 39 cm

The time period to complete a revolution around the spiral trajectory is:

T = 2πr / v

T = 2*3.14* 0.1941 / 3.53*10^7

T = 0.7 × 10⁻⁷ s

Finally, the number of orbits that the proton does to complete the revolution in 1 ms is:

n = t / T

n = 10^-3 / (0.7*10^-7)

n = 14285.71

n ≅ 14000 revolutions

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Your question is incomplete, but most probably full question was:

A medical cyclotron used in the production of medical isotopes accelerates protons to 6.5 MeV. The magnetic field in the cyclotron is 1.9 T.

(a) What is the diameter of the largest orbit, just before the protons exit the cyclotron? Express your answer with the appropriate units. d = 57 cm Previous

(b) A proton exits the cyclotron 1.0 ms after starting its spiral trajectory in the center of the cyclotron. How many orbits does the proton complete during this 1.0 ms?

Answer:

It is because of the blood pressure balances with our atmospheric pressure

Answer:

[tex]250000 \frac{n}{m {}^{2} } [/tex]

Explanation:

pressure is the force applied perpendicular to the surface area of an object per unit area.

for the question,

Force (F) = 5000N

[tex]Area = 200cm {}^{2} = 0.02m {}^{2} \\ Pressure = \frac{force}{area} \\ Pressure = \frac{5000}{0.02} \\ Pressure = 250000 \frac{n}{m {}^{2} } [/tex]

A person riding a Ferris wheel moves through positions at

(1) the top,

(2) the bottom, and

(3) mid-height. If the wheel rotates at a constant rate, rank these three positions according to

(a)the magnitude of the person’s centripetal acceleration, is same in all cases.

(b) the magnitude of the net centripetal force on the person, is same in all three cases.

(c) the magnitude of the normal force on the person from the bottom,

2<3<1

(d) the weight the person feels, greatest first is at the bottom.

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From the calculation, the mass of the dummies head is 1647.44 Kg

We know that the momentum after collision is equal to the momentum before collision.

Mass of the headrest = 2005.6 kg

Initial velocity of the head rest = 4.524 m/s

Final velocity of the head rest =  4.487 m/s

Mass of the dummy = m

Initial velocity of the dummy = -1.005 m/s

Final velocity of the dummy = 9.965 m/s

Then;

(m *  -1.005) + (2005.6 * 4.524 ) = (2005.6 *   4.487) + (m * 9.965)

-1.005m + 9073.33 = 8999.13 + 9.965m

9073.33 - 8999.13  = 9.965m + 1.005m

18072.46 = 10.97m

m = 18072.46/ 10.97

m = 1647.44 Kg

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[tex] \large{ \boxed{ \tt{447.3 \: m}}}[/tex]

-Please see the attached picture for full solution!:)

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Answer:

2.45s

Explanation:

is explanation needed too?

Answer:

See below

Explanation:

Power = amps * volts  = .27 * 12 = 3.24 watts

V= IR

R = V/I = 12/.27 = 44.44 ohms

The power required to force the current of 4.13 A to flow through the conductor is 1927.43 watts

This is defined as the rate in which energy is consumed. Electrical power is expressed mathematically as:

Power (P) = square current (I²)× resistancet (R)

P = I²R

P = I²R

P = 4.13² × 113

P = 1927.43 watts

Thus, the power required is 1927.43 watts

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Volume of the box observed at the given speed is 7.89 m³

Given:

Length of side of box = 1.5 m

horizontal speed = 0.90 c

To Find:

Volume of box

Solution: The amount of space occupied by a three-dimensional figure as measured in cubic units (as inches, quarts, or centimeters)

The edge length of the cube according to the stationary observer is calculated as

a' = a x √ 1 - v^2/c^2

a' = 1.5 x √ 1 - (0.9c)^2/c^2

a' = 1.5 x 0.19

a' = 0.285 m

The volume of the cube is calculated as follows;

V = A x a'

V = (a)^2 x a'

V = (1.5)^2 x 0.285

V = 7.89 m³

Thus, the volume of the box observed at the given speed is 7.89 m³

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From position 1 to position 2, the kinetic energy is increasing.

The kinetic energy of a pendulum undergoing simple harmonic motion decreases as the displacement of the pendulum increases and increases as the displacement of the pendulum decreases.

From position 1 to position 2, the kinetic energy is increasing while the potential energy is decreasing.

Thus, from position 1 to position 2, the kinetic energy is increasing.

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The magnitude of acceleration of a block m₂ is 0.05 m/s² and the tension in the cord is 0.01 N.

Given:

mass of block 1, m₁ = 40 gm = 40×10⁻³ kg

mass of block 2, m₂ = 20 gm = 20×10⁻³ kg

Applied force, F = 0.03 N

Calculation:

Consider the free-body diagram of the system as shown below. Using Newton's second law of motion we get:

F = ma

where F is the applied force

            m is the total mass of the system

            a is the acceleration of block 2 (as it is pulled by horizontal force)

From the above equation we get:

0.03 N = (m₁+m₂) a

⇒ a = (0.03 N) / (m₁+m₂)

⇒ a = (0.03 N) / (40×10⁻³ kg + 20×10⁻³ kg)

⇒ a = 0.5 m/s²

Now, from the free-body diagram of block 2 as shown in figure 3, we get:

Balancing the forces along the horizontal:

∑Fₓ = 0

∴ T = m₂ a

where T is tension in the string

           a is the acceleration of block 2

Applying values in the above equation we get:

T = (20×10⁻³ kg) × (0.5 m/s²)

  = 0.01 N

Therefore, the acceleration of block 2 due to the applied horizontal force is 0.5 m/s² and the tension in the cord is 0.01 N.

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Answer:

Kinematics is the study of the motion of mechanical points, bodies and systems without consideration of their associated physical properties and the forces acting on them. The study is often referred to as the geometry of motion, and it models these motions mathematically using algebra

Answer:

the branch of mechanics concerned with the motion of objects without reference to the forces which cause the motion is kinematics

B. The heat loss by the heat engine is 8,330 J.

The heat loss by the heat engine is calculated as follows;

H = E - W

where;

H = 10,750 J - 2,420 J

H = 8,330 J

Thus, the heat loss by the heat engine is 8,330 J.

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Answer: 1280 J

[tex]KE=\frac{1}{2}mv^{2} \\\\KE= \frac{1}{2} (10 kg)(16 m/s)^2\\=1280 J[/tex]

I have to be honest with you . . . It's not possible to determine the answer with only the information given in the question.

Kinetic energy = (1/2) (mass) (speed squared).

Josie's Kinetic energy as she crosses the finish line is

(1/2) (her mass) (her speed as she crosses the finish line)².

That's (5 kg) x (her speed as she crosses the finish line)² .

But read the question again.

WE DON'T know her speed as she crosses the finish line.

The question only tells us her average speed for the whole race.

We can be confident that her Average Kinetic Energy was

(5 kg) (16 m/s)²  =  1,280 Joules.

But we can't tell what her kinetic energy was as she crossed the finish line, beause we don't know what her speed was at that instant.

A. The acceleration during the slide is 6.86 m/s²

B. The time taken to slide until he stops is 1.2 s

F = μN

F = 0.7 × 798.7

F = 559.09 N

a = F / m

a = 559.09 / 81.5

a = 6.86 m/s²

a = (v – u) / t

t = (v – u) / a

t = (0 – 8.23) / -6.86

t = 1.2 s

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Answer:75 percent

Explanation:so in order tro fin d thge efficiency i used the forumla ,efficency=useful output energy/input energyx100%,in order to use this formula i needed the output,which i found by subtracting the input energy with wasted energy,that gave me the output,and after founding the output,i put that into the formula,

output energy=input energy - wasted energy

output energy=6000j-1500j

output energy=4500

put that into the formula

efficiency =output energy/input enrgy x100%

efficiency=4500/6000 multiplied by 100%

efficiency=0.75x100%

efficiency=75%

Taking into account the definition of calorimetry,  the final temperature of the silver and water is 11.84 °C.

Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.

Sensible heat is defined as the amount of heat that a body absorbs or releases without any changes in its physical state (phase change).

So, the equation that allows to calculate heat exchanges is:

Q = c× m× ΔT

where:

In this case, you know:

Replacing in the expression to calculate heat exchanges:

For silver: Qsilver= 240 [tex]\frac{J}{kgC}[/tex]× 0.5 kg× (Final temperature of silver - 250 C)

For water: Qwater= 4180 [tex]\frac{J}{kgC}[/tex] × 1 kg× (Final temperature of water - 5 C)

If two isolated bodies or systems exchange energy in the form of heat, the quantity received by one of them is equal to the quantity transferred by the other body. That is, the total energy exchanged remains constant, it is conserved.

Then, the heat that the silver gives up will be equal to the heat that the water receives. Therefore:

- Qsilver = + Qwater

And the final temperature of the silver is equal to the temperature of the water (Final temperature of silver= Final temperature of water= Final temperature). Then:

- 240 [tex]\frac{J}{kgC}[/tex]× 0.5 kg× (Final temperature - 250 C)= 4180 [tex]\frac{J}{kgC}[/tex] × 1 kg× (Final temperature - 5 C)

Solving:

- 120 [tex]\frac{J}{C}[/tex]× (Final temperature - 250 C)= 4180 [tex]\frac{J}{C}[/tex]× (Final temperature - 5 C)

120 [tex]\frac{J}{C}[/tex]× (250 C - Final temperature) = 4180 [tex]\frac{J}{C}[/tex]× (Final temperature - 5 C)

120 [tex]\frac{J}{C}[/tex]×250 C - 120 [tex]\frac{J}{C}[/tex]×Final temperature = 4180 [tex]\frac{J}{C}[/tex]×Final temperature - 4180 [tex]\frac{J}{C}[/tex]×5 C

30,000 J - 120 [tex]\frac{J}{C}[/tex]×Final temperature = 4180 [tex]\frac{J}{C}[/tex]×Final temperature - 20,900 J

50,900 J= 4300 [tex]\frac{J}{C}[/tex]×Final temperature

50,900 J÷ 4300 [tex]\frac{J}{C}[/tex]= Final temperature

11.84 °C= Final temperature

Finally,  the final temperature of the silver and water is 11.84 °C.

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Answer:

easy

Explanation:

it when the sunlight hits a rain droplets ,some of the light is reflected .The electromagnetic spectrum is made of light with many different wavelengths and each is reflected at a different angle . Thus spectrum is seperated producing a rainbow

The sound that Tina produces while singing is loud and high-pitched.

How is a sound produced?

Vibrations that travel through the air or another medium and can be heard by an observer are called sounds. Sound is produced by the following cycle:

Therefore, when Tina sings larger vibrations are created, and the tension within her vocal cords increases producing a very high-pitched loud sound.

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The average acceleration in the first 10 seconds of the journey is 2 m/s²; option B.

Acceleration is the rate of change of velocity with time.

From the graph;

Acceleration in first  seconds = 20 - 0/5 = 4 m/s²

Acceleration in second 5 seconds = 0

Average acceleration = 4 + 0/2

Average acceleration = 2 m/s²

In conclusion, average acceleration is the average of the final and initial acceleration.

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Two-electron or metallic conducting electrodes that are connected by an electrolyte solution that conducts ions.

An electrochemical measurement method is potentiometry. The phrase was first used in relation to possible electrochemical measurement chain determinations. Potentiometer is a tool that measures an electrochemical cell's potential without drawing current or changing the makeup of the cell.

Potentiometric measurement is done to detect the difference in potential between a working (an indicator) electrode and a counter (a reference), using a potentiometer. The working/indicator electrode is called the cathode (right half-cell) and the counter/reference electrode is called an anode(half of a left cell).

A basic galvanic cell may just have one electrolyte isolated from it by a semi-permeable membrane, but a more complex one has two independent half-cells linked together by a salt bridge. An inert electrolyte like potassium sulfate is included in the salt bridge, and its ions will diffuse into each of the individual half-cells to balance the charges that are building up at the electrodes.

I understand the question you are looking for is this:

Potentiometric measurements are based on galvanic electrochemical cells. These types of cells consist of:

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