Amory turns the light on in her house. Looking at the lights, she begins to wonder how the charges are moving through the bulb. Which statement best describes how the charges move through the bulb ?

Answer:

Distillation can be used to separate and collect a liquid from a solution. Distillation can also be used to soften water as the water evaporates as it is heated and the ions are left behind. Hard water can be softened by adding sodium carbonate (washing soda) or by passing the water through an ion-exchange column.

Explanation:

Answer:

otherwise you will be bord and have nothing to do

Explanation:

Given the data from the question, the final temperature is 200 K, while pressure remains constant.

To obtain the correct answer to the question, we shall consider two conditions:

We shall determine the new pressure by using the combined gas equation (P₁V₁ / T₁ = P₂V₂ / T₂) as illustrated below:

P₁V₁ / T₁ = P₂V₂ / T₂

Since temperature is constant, we have:

P₁V₁ = P₂V₂

3 × 1 = P₂ × 2

3 = P₂ × 2

Divide both side by 2

P₂ = 3 / 2

P₂ = 1.5 atm

We shall determine the new temperature by using the combined gas equation (P₁V₁ / T₁ = P₂V₂ / T₂) as illustrated below:

P₁V₁ / T₁ = P₂V₂ / T₂

Since pressure is constant, we have:

V₁ / T₁ = V₂ / T₂

3 / 300 = 2 / T₂

1 / 100 = 2 / T₂

Cross multiply

T₂ = 100 × 2

T₂ = 200 K

SUMMARY

From the calculations made above, we can conclude that the correct answer is:

The final temperature is 200 K, while pressure remains constant.

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Answer:

b

Explanation:

Hi!

[tex]\\ \sf\rightarrow pH=-log[H^+][/tex]

[tex]\\ \sf\rightarrow -log[H^+]=6.1[/tex]

[tex]\\ \sf\rightarrow log[H^+]=-6.1[/tex]

[tex]\\ \sf\rightarrow [H^+]=10^{-6.1}[/tex]

[tex]\\ \sf\rightarrow [H^+]=7.94M[/tex]

That is correct! It is a positive ion!

Answer:

Pure gold belongs to ELEMENT because it purely consists of one single element, which is Aurum (Au.)

Explanation:

When pure gold is mixed with other elements to make jewelry, it becomes a mixture.

Answer:

I will find the answer for you

Explanation:

Just a minute

Answer:

answer in the picture above

Answer:

Explanation:

alculate the (H3O+) for a solution whose pH is 6.79

Note: blank 1 should have three significant figures

The answer is: Blank 1 X 10^Blank 2

The pH of a solution is the negative logarithm of H₃O⁺ ion concentration.The concentration of H₃O⁺ ions in a solution with a pH of 6.79 is 1.6 × 10⁻⁷M.

pH of a solution is the measure of its acidity or basicity. Mathematically it is the negative logarithm of its  H₃O⁺ ion concentration. A solution with a pH of 7 is neutral.

The solution with a pH below 7 is acidic and above 7 is basic. Thus, the higher H+ ion concentration, then the pH will be lower and more acidic the solution.

It is given that the pH of the solution is 6.79. The concentration of  H₃O⁺ ions in the solution is calculated is calculated as follows:

pH   = -log ( H₃O⁺)

6.79 = -log( H₃O⁺

[ H₃O⁺] = antilog (-6.79)

             =  1.6 × 10⁻⁷M

Hence, the  hydronium ion H₃O⁺ ion concentration of the solution of pH 6.79 is  1.6 × 10⁻⁷M.

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Since 220 mL of oxygen gas was collected over water, the pressure exerted by only the oxygen gas is 720.8 mmHg

The total pressure of a gas collected over water is given by P = P' + p where

Making P' subject of the formula, we have

P' = P - p

Since the total pressure of oxygen plus water vapor is P = 745.8 mmHg, substituting the values of the variables into the equation, we have

P' = P - p

P' = 745.8 mmHg - 25 mmHg

P' = 720.8 mmHg

So, Since 220 mL of oxygen gas was collected over water, the pressure exerted by only the oxygen gas is 720.8 mmHg

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Answer:

A. Combined magnetic field

Answer:

A.combined magnetic field

Explanation:

CARRY ON LEARNING#

Based on the calculations, the final pressure of this gas sample at 370°C is equal to 2.66 atm..

Given the following data:

Initial temperature = 180°C.

Final temperature = 370°C.

Initial pressure = 900 torr.

Conversion:

760 torr = 1 atm.

900 torr = 1.29 atm.

In order to calculate the final pressure of an ideal gas at constant volume, we would apply Gay Lussac's law.

Mathematically, Gay Lussac's law is given by this formula;

[tex]P\;\alpha \;T\\\\P=kT[/tex]

Where:

Substituting the given parameters into the formula, we have;

[tex]\frac{P_1}{T_1} =\frac{P_2}{T_2} \\\\\frac{1.29}{180} =\frac{P_2}{370} \\\\0.0072 =\frac{P_2}{370}\\\\P_2 = 0.0072 \times 370[/tex]

Final pressure = 2.66 atm.

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I agree with idea of Kevin because bakong soda dissociates faster in hot water than cold water.

Baking soda is a chemical that can undergo a decomposition reaction when heated. At 80 degrees Celsius, sodium bicarbonate starts to break down into sodium carbonate (Na2CO3), water (H2O) and carbon dioxide (CO2) which is ready for reaction with other chemical.

So we can conclude that Kevin idea is correct because bakong soda dissociates faster in hot water than cold water.

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The pH of the buffer prepared by adding 275 mL of .676M of HCl to 500 mL of .525M sodium acetate is 6.45.

The pH of a buffer solution can be calculated by initially calculating the millimoles of both the conjugate base and acid.

From, Henderson Hasselbalch equation,

pH = pKa + log conjugate base/acid

pka of HCl = -6.3

-6.3 + log 262.5/185.9

6.3 + 0.15

pH = 6.45

Therefore, the pH of the buffer prepared by adding 275 mL of .676M of HCl to 500 mL of .525M sodium acetate is 6.45.

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Now

[tex]\\ \rm\rightarrowtail Q=mc\delta T[/tex]

[tex]\\ \rm\rightarrowtail Q=20(40)(0.13)[/tex]

[tex]\\ \rm\rightarrowtail Q=800(0.13)[/tex]

[tex]\\ \rm\rightarrowtail Q=104J[/tex]

Answer:

The charge on the compound

Explanation:

The charge on the compound signifies that the compound is not in its neutral state.

Therefore, the oxidation state would be equal to the charge on the compound.

Answer:

The charge on the compound

Explanation:

The charge on the compound signifies that the compound is not in its neutral state.

Therefore, the oxidation state would be equal to the charge on the compound.

The name of the covalent compound NH3 O2 is dihydroxylamine.

According to the task content;

On this note, the compound possesses 2 oxygen atoms, 3 Hydrogen atoms and 1 Nitrogen atom. Hence, the name of the covalent compound is Dihydroxylamine.

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Answer:

About 7.9 L.

Explanation:

We can utilize the ideal gas law. Recall that:

[tex]\displaystyle PV = nRT[/tex]

Because the amount of carbon dioxide does not change, we can rearrange to formula to:
[tex]\displaystyle \frac{PV}{T}= nR[/tex]

Because the right-hand side stays constant, we have that:
[tex]\displaystyle \frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2} = nR[/tex]

Hence substitute initial values and known final values:
[tex]\displaystyle \begin{aligned} \frac{(793\text{ mm Hg})(4.65 \text{ L})}{(22 \text{ $^\circ$C})} & = \frac{(743 \text{ mm Hg})V_2}{(35\text{ $^\circ$C})} \\ \\ V_2 & = 7.9\text{ L}\end{aligned}[/tex]

Therefore, the final volume is about 7.9 L.

Answer:

follow hypothesis bud

Explanation:

yep

In the double displacement reaction between BaCl₂ and Na₃PO₄, 52.4 g of BaCl₂ are required to produce 50.5 g of Ba₃(PO₄)₂.

Stoichiometry refers to the relationship between the quantities of reactants and products before, during, and following chemical reactions.

BaCl₂(aq) + Na₃PO₄(aq) → Ba₃(PO₄)₂(s) + NaCl(aq)

We will use the trial and error method. We will:

3 BaCl₂(aq) + 2 Na₃PO₄(aq) → Ba₃(PO₄)₂(s) + 6 NaCl(aq)

The mass ratio of BaCl₂ to Ba₃(PO₄)₂ is 624.69:601.93.

50.5 g Ba₃(PO₄)₂ × 624.69 g BaCl₂/601.93 g Ba₃(PO₄)₂ = 52.4 g BaCl₂

In the double displacement reaction between BaCl₂ and Na₃PO₄, 52.4 g of BaCl₂ are required to produce 50.5 g of Ba₃(PO₄)₂.

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The amount of heat absorbed in kilojoules when 3.5 moles of water react is 1635.08 KJ

6CO₂ + 6H₂O → C₆H₁₂O₆ + 6O₂  ΔH = 2803 KJ

From the balanced equation for above,

6 moles of water reacted to absorb 2803 KJ of heat

From the balanced equation for above,

6 moles of water reacted to absorb 2803 KJ of heat

Therefore,

3.5 moles of water will react to absorb = (3.5 × 2803) / 6 = 1635.08 KJ of heat

Thus, 1635.08 KJ of heat were absorbed by the reaction.

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The mass, in grams, of lead that will be produced from the illustrated reaction would be 71.47 grams

From the balanced equation of the reaction:

Pb(NO3)2 + 2NaCl ---> PbCl2 + 2NaNo3

Mole ratio of Pb(NO3)2 and NaCl = 1:2

Mole of 15.3 g NaCl = 15.3/58.4

 = 0.257 moles

Mole of 60.8 g PbCl(NO3)2 = 60.8/331.2

  = 0.184 moles

Thus, NaCl is limiting.

Mole ratio of NaCl to PbCl2 = 1:1

Mas of 0.257 moles PbCl2 = 0.257 x 278.1

 = 71.47 grams

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Copper will turn green and calcium will turn orange.  this is as a result of the atomic transitions visible in line spectra

Transition elements are substances with partially filled d orbitals, sometimes referred to as transition metals. According to IUPAC, a transition element is an element with a partially filled d subshell or one with the capacity to create stable cations that has an unfilled d orbital.

As a result of their transitional behavior between s-block or p-block elements, the d-block elements are referred to as transition elements. Their characteristics are intermediate between those of the covalently-bonded, highly reactive s-block metallic elements and those of the p-block elements.

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Answer:

An alloy is a mixture of two or more metals which is produced with a specific proportion between metals. So, if the proportion is changed the physical characteristic would be changed as well. For example, brass musical instruments are made of brass which is a mixture (an alloy) of zinc and copper in a specific proportion. If you change a proportion, you will change the physical characteristic of brass musical instruments, and a sound they produce will be different.

Explanation:

Answer:

Combination reactions

Explanation:

Hope this helps:)

A. The number of molecules in 0.750 mole of KNO₃ is 4.515×10²³ molecules

B. The mass (in milligrams) of 2.39×10²⁰ molecules of Ag₂SO₄ is 124 mg

C. The number of molecules in 3.429 g of NaHCO₂ is 3.04×10²² molecules

1 mole of substance = 6.02×10²³ molecules

1 mole of KNO₃ = 6.02×10²³ molecules

Therefore,

0.750 mole of KNO₃ = 0.75 × 6.02×10²³

0.750 mole of KNO₃ = 4.515×10²³ molecules

6.02×10²³ molecules = 312 g of Ag₂SO₄

Therefore,

2.39×10²⁰ molecules = (2.39×10²⁰ × 312) / 6.02×10²³

2.39×10²⁰ molecules = 0.124 g

Multiply by 1000 to express in mg

2.39×10²⁰ molecules = 0.124 g × 1000

2.39×10²⁰ molecules = 124 mg of Ag₂SO₄

68 g of NaHCO₂ = 6.02×10²³ molecules

Therefore,

3.429 g of NaHCO₂ = (3.429 × 6.02×10²³) / 68

3.429 g of NaHCO₂ = 3.04×10²² molecules

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