.
For the following data set, find Q1, Q2, Q3 and the interquartile range.

15, 12, 23, 15, 7, 8, 21, 10, 12, 14, 16, 24, 19
1.
Interquartile Range
2.
Q3
3.
Q2
4.
Q1
a.
15
b.
9
c.
20
d.
11

Neglecting the fractional points and taking the whole number values for volume, the probability of getting equivalence point at 100 ml is 1/10. The probability of getting less than 100 ml is 1/2.

The probability is the measurement of the chance of an event to happen. It is determined based on the total possibilities and criteria.

Given that the experiment trials got the values from 95 to 104. From 95 to 104, there are 10 numbers. Thus, the volume of the acid can be any of these 10.

Thus, total possibility = 10.

probability of getting 100 = 1/10

There are 5 volumes which are  less than 100 here,  [95, 99]. Thus, the probability = 5/10 = 1/2.

There are 5 values between 98 and 102 including these two values.

Hence, probability of getting these range  = 5/10 = 1/2.

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Option A) In the graph for each value of x there is exactly one value of y

So the function is  a One to One function.

A function is a procedure or a relation that links each element of a non-empty set A, at least one element of another non-empty set B, to another element of the first non-empty set A. In mathematics, a relation f between two sets, A and B, is referred to as the function's domain and co-domain. For all values of a and b, f = (a,b)|

A function f is said to be injective if it maps different items in its domain to other elements; for example, f = f implies x1 = x2. Alternatively, every element of the function's codomain is at most one of its domain's elements.

If some function output value corresponds to more than one input value, the function is said to be many-to-one (sometimes written as "many-one"). If the domain of f contains two different values a and b such that f(a)=f, the function f is many-to-one in symbols (b).

In the graph for each value of x there is exactly one value of y

So the function is  a One to One function.

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The distance from the top of the tree of height 30 tall to the end of the shadow is 50.

Distance is the length between two point.

To calculate the distance from the top of the tree to the end of the shadow, we use the formula below.

Note: The tree and the shadow form a right angle.

Formula:

Where:

From the question,

Given:

Susbtitute these values into equation 1

Hence, the distance from the top of the tree to the end of the shadow is 50.

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On solving the provided question, we can say that F= The lifting force is 27135 0.003357*250*180*180 = F=27135, surface area

The total area that all of a 3D object's faces cover is the surface area. The surface area of a cube is its surface area, for instance, if we are trying to determine how much paint is needed to paint it. Always expressed in square units.

The entire surface of a three-dimensional shape is referred to as its surface area. A cuboid with six rectangular faces has a surface area equal to the sum of the areas of each face. Alternatively, you can label the cuboid's length, width, and height (l, w, and h), then calculate its surface area (SA) using the formula: SA=2lw+2lh+2hw.

F= k*a*v^2

a= 250

v=190

30300=k*250*{190^2}

k= 0.03357

F= 0.003357*250*180*180

F=27135

The lifting force is 27135

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Therefore , R(N) = 100 + 400 (N+1)(2N+1) + 800 x N2 N3 and area are the formulas for R(N) for the function f(x) = (5x)2 on [1, 5] and the function f(x) = (5x)2 in terms of N. R(N) = 767(approx) (approx).

Each x value in the domain has one but only one y value range, according to the rule of a function. Definition. If there is only one and only one value of x variable such that f(x) = y, then the function is one-to-one.

Here,

In the given question, we have to find a formula for R(N) for the function f(x) =(5x)^2 on [1, 5] in terms of N.

The given function is f(x)=(5x)^2 on [1, 5].

Ax = (5-1)/N

Ax = 4/N

X = 1+iAx

X = 1+i4/N

f(x) = 25X^2

f(x) = 25(1+i4/N)^2

f(x) = 25(1+i8/N+16/N^2 i^{2})

R(N) = 1ƒ(X) Ax

Now putting the value of f(x) and Ax

R(N)==1 [25 (1+ &i + 16i2)]

R(N) = 1001 (1 +Ni + 16i2)

N100 (1+i+12)N

100 (N += i +122)+16 N(N+1)(2N+1)(+1)(2N+1)

R(N)=100 (N + √2/ N(N+1) x 100

R(N) =2/6× N + 100 × 5 × N(N+1) + 100 x 2

[tex]\lim_{n \to \infty}[/tex] R(N) = 100 + 400 + 800/3

[tex]\lim_{n \to \infty}[/tex] R(N) = 766.67

[tex]\lim_{n \to \infty}[/tex] R(N) = 767(approx)

Therefore , the solution of the given problem of function comes out to be [tex]\lim_{n \to \infty}[/tex] R(N) = 767(approx).

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Answer:

Step-by-step explanation:

You want the angles associated with different arc lengths and radii.

The length of an arc is given by the formula ...

  s = rθ . . . . . θ is the angle in radians, r is the radius

Solving for θ gives ...

  θ = s/r

For s=17 in, r=4 in, ...

  θ = (17 in)/(4 in) = 4.25 . . . . radians

For s=12 ft, r=5 ft, ...

  θ = (12 ft)/(5 ft) = 2.4 . . . . radians

For s=8.5 mm, r = 13.6 mm, ...

  θ = (8.5 mm)/(13.6 mm) = 0.625 . . . . radians

well, we know that 37.5% have finished it, that leaves unaccounted for 100% - 37.5% = 62.5%.

now, of those 62.5% fellows only 40% have finished only half of it, how many are those?

well, what's 62.5% of 32?   what's 40% of that much?

[tex]\begin{array}{|c|ll} \cline{1-1} \textit{\textit{\LARGE a}\% of \textit{\LARGE b}}\\ \cline{1-1} \\ \left( \cfrac{\textit{\LARGE a}}{100} \right)\cdot \textit{\LARGE b} \\\\ \cline{1-1} \end{array}~\hspace{5em}\stackrel{\textit{62.5\% of 32}}{\left( \cfrac{62.5}{100} \right)32}\implies 20 ~\hfill \stackrel{\textit{40\% of 20}}{\left( \cfrac{40}{100} \right)20}\implies \text{\LARGE 8}[/tex]

Answer:

-15y

Step-by-step explanation:

The square root of any squared number is always the number itself.

So in this case, it is -15y

Brainliest please. It'll help a lot.

Answer:

---------------------------------

Simplify the expression:

We know the square root is never negative and since y is positive, we get:

Answer:

  (b)  No solution

Step-by-step explanation:

You want the solution to 0.5(-2+ 4d) - 2d = -13.

Eliminating the parentheses using the distributive property, we have ...

  -1 +2d -2d = -13

Collecting terms gives ...

  -1 = -13 . . . . . false

No value of d will make this true. There is No Solution.

A 90% confidence interval for the population mean is; CI = (163.355, 166.655)

The formula to find the confidence level here is;

CI = x' ± z(s/√n)

Where;

CI is confidence  level

z-score at confidence level

x' is sample mean

s is standard deviation

n is sample size

We are given;

Sample mean; x' = 165

Sample size; n = 20

standard deviation; s = 4.5

z at CL of 90% = 1.645

Thus;

CI = 165 ± 1.645(4.5/√20)

CI = 165 ± 1.655

CI = (163.355, 166.655)

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The cookies that each person bake will be:

A = 4 1/2 dozen cookies

B = 6 3/4 dozen cookies

C = 15 3/4 dozen cookies.

A fraction simply means a piece of a whole. In this situation, the number is represented as a quotient such that the numerator and denominator are split.

Person A baked 4 1/2 Dozens of cookies for a bake sale. Person B Baked 1 1/2 as many as Person A. This will be:

= 1 1/2 × 4 1/2

= 6 3/4

Person C Baked 2 1/3 as many as Person B. This will be:

= 2 1/3 × 6 3/4

= 7/3 × 27/4

= 15 3/4

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Answer: A y-intercept is a point where the graph of a function or relation intersects the y-axis of the coordinate system.

Slope - A number that describes both direction and steepness of the line.

Step-by-step explanation: If a line intersects the y-axis at point 5 then its y-intercept will be c= 5. As we denote y-intercept with c.

The slope is denoted by m.

The tax rate of an Item that costs $450 Before tax. and the sales tax is $31.50 is 7%

The tax rate is the percentage of an income or an amount of money that has to be paid as tax.

To find the tax rate of $31.50 from $450

The formula is

Amount taxed/Principal amount x 100

= $31.50/$450 x100

=$3150/450

=7%

Hence, the tax rate is 7%

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Answer:

Step-by-step explanation:

An radical expression usually involves a radicand which is the number or expression inside the radical symbol √ and an index which is the number outside the radical symbol indicating the root, the radicand raised to the power of the reciprocal of the index.

But in the case of expression "U-2/5" it's not a radical expression as is. It's a fractional expression with variable U and a constant -2/5.

It can be written as √(U-2)/5 or U- √(2/5) if you want to express it as an radical expression.

Answer:

x = -11, 2/3

Step-by-step explanation:

-3x^2-11x+2=0

-(3x^2+11x-2) = 0

3x^2 + 11x - 2 = 0

3x^2 + 33x - 22x - 2 = 0  ==> 33-22=11 and 33/11=3 and -22/11=-2

3x(x + 11) - 2(x + 11) = 0  ==> factor

(3x - 2)(x + 11) = 0

3x - 2 = 0                x + 11 = 0

3x = 2                x + 11 - 11 = 0 - 11

{ x = 2/3                         x = -11 } ==> x = -11, 2/3

It's a good idea to utilize the 13 cm measurement that Martha used for her scale illustration. This is because it would be simpler to measure the flag's stripes. The American flag has 13 stripes, thus each one is 1 centimeter wide.

Flags can be as big as 20 feet by 38 feet, although most are between 3 feet by 5 feet and 5 feet by 8 feet in size. The standard size for an American flag flown outside a home is 3 x 5.

A flag's rectangular design assures that even a moderate breeze would cause it to move, making it readily apparent to everyone else. Additionally, the shape is efficient in terms of production costs, according to a number of flag designers.

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Answer:

-3w2-11w-3

Step-by-step explanation:

take w2 and w as variables. you can substitute it as w2=y and w=X then expand brackets

2y-8x-8-5y-3x+5

note that the signed changed at the second part because it was expanded with the minus sign which is basically like -1, so it changes the signs

then you collect like terms:

2y-5y-8x-3x-8+5= -3y-11x-3

now put substitute back w2=y and w=X

-3w2-11w-3

if it won't be a problem solving with w2 and w, then you skip the substitution part and solve the same

a) The portion of the garden is made up of beef steak tomatoes is 8.

b) he Equation for beef steak tomatoes is 4/5 x (portion of tomatoes).

The fractional bar is a horizontal bar that divides the numerator and denominator of every fraction into these two halves.

Given:

Portion of Garden have Tomatoes = 2/3

and, 4/5 of the tomato plants are beefsteak tomatoes.

a) The total section in model is 15.

so, Tomatoes in the garden = 2/3 x 15

                                               = 10

and, the portion of the garden is made up of beef steak tomatoes

= 10 x 4/5

= 8 portion.

b) The Equation for beef steak tomatoes

= 4/5 x (portion of tomatoes)

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Two equations that have the same solution as the given equation are;

2.3p – 10.1 =  6.49p – 4

230p – 1010 = 650p – 400 – p

Both sides of an equation will remain equal, when both sides are

multiplied by the same amount.

The given equation: 2.3·p - 10.1 = 6.5·p - 4 - 0.01·p

Simplifying the above equation by collecting like terms gives;

2.3·p - 10.1 = 6.5·p - 0.01·p - 4 = 6.49·p - 4

2.3·p - 10.1 = 6.49·p - 4

Multiplying both sides of the original equation by 100 gives

100 × (2.3·p - 10.1) = 100 × (6.5·p - 4 - 0.01·p)

230·p - 1010 = 650·p - 400 - p

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Answer:

[tex]y1 = 4 \\ x1 = 3[/tex]

[tex]y - y1 = m(x - x1)[/tex]

[tex]y - 4 = 0(x - 3)[/tex]

[tex]y - 4 = 0[/tex]

[tex]y = 4[/tex]

The rates of change in attendance in week 1-4 is 33, week 4-6 is -11, week 6-10 is -37 people per week

The rate of change in attendance with respect to time is calculated by taking the difference in attendance between two weeks and dividing by the number of weeks between those weeks. This is done to find the average rate of change in attendance per week. The formula used is:

[tex]Rate =\frac{Attendance at week 2 - Attendance at week 1}{week 2 - week 1}[/tex]

Weeks 1-4:

The rate of change in attendance with respect to time is 33 people per week. This can be calculated by taking the difference in attendance between weeks 1 and 4 (230-131) and dividing by the number of weeks between those weeks (4-1 = 3).

[tex]rate =\frac{230-131}{4-1}\\[/tex]

hence rate is 33 people per week

Weeks 4-6:

The difference in attendance between weeks 4 and 6 (230 - 208)

The number of weeks between those weeks (6-4 = 2).

[tex]rate =\frac{208-230}{6-4}[/tex]

Hence rate is -11 people per week

Weeks 6-10:

The difference in attendance between weeks 6 and 10 (60-208)

The number of weeks between those weeks (10-6 = 4).

[tex]rate=\frac{60-208}{10-6}[/tex]

Hence rate is -37 people per week

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Answer: $305

Step-by-step explanation:

1) 12.50 multiplied by 10= 125

2) 12% of 1500 is 180

3) 125+180=305

Answer: 130

Step-by-step explanation:

The original price of the sweater is $303.

A discount is the reduction of either the monetary amount or a percentage of the normal selling price of a product or service.

Given that, June is buying a sweater using a coupon offering a 30% discount on items over $99.

The discounted price is $91

Let the original price of the sweater be x.

So, 30% of x=91

30/100 ×x=91

0.3x=91

x=91/0.3

x=$303

Therefore, the original price of the sweater is $303.

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One possible equation is (6b+2)+40 = 90

That equation solves to b = 8

======================================================

Explanation:

The angles (6b+2) and 40 degrees combine to form a right angle, aka 90 degree angle. This is because the upper angle is 90 degrees, so the remaining portion is 180-90 = 90.

So (6b+2)+40 = 90 is one possible equation.

Let's solve for b.

(6b+2)+40 = 90

6b+42 = 90

6b = 90-42

6b = 48

b = 48/6

b = 8

---------------

A slight alternative.

The angles (6b+2), 40, and the 90 degree angle form a straight line.

The three angles add to 180

(6b+2)+(40)+(90) = 180 is another possible equation

6b+132 = 180

6b = 180-132

6b = 48

b = 48/6

b = 8

The total displacement made by her to go from home to the school is given by the sum of the distances of P to Q, Q to R and then R to S.

The total displacement is obtained as the distance that she walks to go to the school from her home.

The check-points that she passes to go to the school are given as follows:

Hence the total displacement is given by the sum of each of these distances.

These distances are calculated using the formula for the distance between two points, given as follows:

[tex]D = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

In which [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex] are the coordinates of each point.

The problem is incomplete, hence the answer is given in general terms.

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Answer:

Step-by-step explanation:

(49/72)-(13/14)

-125/504

Answer:

0

8

0

9

0

9

9

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