The range of wavelengths that are received by the car radio are 2.78 m to 3.41 m.
To find the range of wavelengths, we use the equation for the speed of a wave
Speed of a waveThe speed of a wave v = fλ where
f = frequency and λ = wavelengthWhat is Wavelength?This is the distance a wave travels in one cycle of the wave.
Making λ subject of the formula, we have
λ = v/f
Given that the range of frequencies of FM radio is 88.0 MHz to 108 MHz and
v = speed of electromagnetic wave = 3 × 10⁸ m/s, f' = lowest frequency = 88.0 MHz = 88.0 × 10⁶ Hz and f" = highest frequency = 108 MHz = 108 × 10⁶ HzThe longest wavelength, λ'λ' = v/f'
= 3 × 10⁸ m/s ÷ 88.0 × 10⁶ Hz
= 0.0341 × 10² m
= 3.41 m
The shortest wavelength, λ"λ" = v/f"
= 3 × 10⁸ m/s ÷ 108 × 10⁶ Hz
= 0.0278 × 10² m
= 2.78 m
So, the range of wavelengths that are received by the car radio are 2.78 m to 3.41 m.
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help me with this plsssssssssssssss
Answer:
D
Explanation:
The digestive system does all of these functions
the stomach and small intestine breaks down foodthe small intestine absorbs nutrientsthe large intestine eliminates wasteall these components (and more) make up the digestive system.
if you are unsure, visit bbc bitesize for more information.
Infrared, ultraviolet and visible light are all part of the electromagnetic spectrum. The basic difference between them is their.
Answer:
The basic difference is wavelength (frequency)
ultraviolet < visible < infrared where the visible spectrum lies at
4000 - 7000 Angstroms = 400 - 700 millimicrons (10^-9 meters)
Tjhe shorter wavelengths (ultraviolet) carry more energy / photon
Which reaction connects the citric acid cycle to the electron‑transport chain and amino acid synthesis?
Conversion of succinylcoA to succinate is the reaction that link acid cycle to the electron‑transport chain and amino acid synthesis.
Conversion of succinylcoA to succinateSuccinylCoA is converted into succinate through the hydrolytic release of coenzyme A by succinyl-CoA synthetase Also succinyl-CoA is porphyrin synthesis, where it combine with glycine by ALA synthase to form δ-aminolevulinic acid.
Succinyl CoA is catalytically converted to succinate. The enzyme stimulates the hydrolysis of succinyl CoA into succinate and ATP and this represents a remarkable point of substrate level phosphorylation. After this, it link up to the electron transport chain via citric acid cycle.
Therefore, Conversion of succinylcoA to succinate is the reaction that link citric acid cycle to the electron‑transport chain and amino acid synthesis.
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The electron‑transport chain reaction connects the citric acid cycle to the electron‑transport chain and amino acid synthesis.
What is an electron‑transport chain reaction?The electron transport chain is a set of protein complexes that link redox processes to create an electrochemical potential that leads to the production of ATP in a process known as
Both photosynthesis and cellular respiration occur in mitochondria.
As a result, the process that connects the citric acid cycle to the electron transport chain and amino acid synthesis is succinyl-CoA to succinate conversion.
Hence the electron‑transport chain reaction connects the citric acid cycle to the electron‑transport chain and amino acid synthesis.
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From left, a large candle A, a point C, a small candle B, a double convex lens D. A line passes below the base of the A and B, through C, and through the center of D. An eye looks left and up from below the line to the right of the lens. Dotted lines pass from the top of the large candle to the dotted center of the lens. Solid lines pass from the top of the small candle to the dotted centerline of the lens and then turn and pass down and right to the eye. Refer to the diagram to the left and use the drop-down menus to identify the parts of a magnifying glass. Label A: Label B: Label C:
Answer:
Label A: Virtual Image
Label B: Object
Label C: Focal point
Explanation:
Label A: Virtual Image
Label B: Object
Label C: Focal point
What is an eye ?The visual system's organs include the eyes. They provide living things the ability to see, to take in and interpret visual information, and to perform a number of photoresponse activities that are not dependent on vision. Light is detected by the eyes, which transform it into electro-chemical impulses in neurons. In higher organisms, the eye is a sophisticated optical system that gathers light from the environment, controls its intensity through a diaphragm, focuses it through an adjustable arrangement of lenses to form an image, transforms this image into a series of electrical signals, and sends these signals to the brain via intricate neural pathways that connect the eye via the optic nerve to the visual cortex and other regions of the brain. The ability of resolving eyes has arrived.
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The vertebral region is _________ to the scapular region.
Answer:
The answer is medial!
Explanation:
The vertebral region is medial to the scapula.
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The parenting style that can be described as restrictive and controlling is called __________. a. authoritarian b. permissive c. neglectful d. authoritative please select the best answer from the choices provided a b c d
The parenting style that can be described as restrictive and controlling is called authoritarian.
What is authoritarian?
The rejection of political plurality, the use of strong central power to maintain the political status quo, and reductions in the rule of law,
The separation of powers and democratic voting characterize authoritarianism.
Many typologies of authoritarian systems of administration have been developed by political scientists.
Authoritarian governments can be autocratic or oligarchic, and they can be founded on party or military authority.
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Who discovered the basic laws of planetary orbits?.
Answer:
kepler
Explanation:
While Copernicus rightly observed that the planets revolve around the Sun, it was Kepler who correctly defined their orbits. At the age of 27, Kepler became the assistant of a wealthy astronomer, Tycho Brahe, who asked him to define the orbital mars
Hello people ~
The sound in the audible range is called
(a) ultrasonic sound
(b) sonic sound
(c) subonic sound
(d) light sound
Answer:
Sonic sound
Human audible range is from 20Hz to 20000Hz or 20kHzAbove or beneath that range we can't hear .Bats can hear below it and dogs can hear above itIf an electron is released at the equator and falls toward earth under the influence of gravity, the magnetic force on the electron will be toward the
Ring of mass straight m and radius straight r is attached to the end of a thin rod of mass straight m and radius 2 straight r
The total moment of inertia about an axis is : [tex]L^{2} ( \frac{M}{3} + m ) + \frac{2mr^2}{5}[/tex] for a ring of mass m and radius straight r attached to a thin rod.
Determine the Total moment of Inertia about an axisGiven data:
mass of ring --> m
radius of ring --> r
mass of rod --> M
Length of rod ---> L ( 2 * radius )
Total Moment of Inertia about an axis = Irod + Iring
where : Irod = moment of inertia of rod, Iring = moment of inertia of ring
Irod = ML² / 3
Iring = 2mr² / 5
moment of inertia around an axis by Iring = I
where ; I = 2mr² / 5 + ML² according to parallel axis theorem
Hence the Total moment of Inertia about an axis is :
Itotal = 2mr²/5 + ML² + ML² / 3
= [tex]L^{2} ( \frac{M}{3} + m ) + \frac{2mr^2}{5}[/tex]
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For a ring of mass m and radius straight r connected to a thin rod, the total moment of inertia about an axis is [tex]\rm I= L^2 (\frac{M}{3} +m)+\frac{2mr^2}{5}[/tex].
What is a moment of inertia?The sum of the products of the mass of each particle in the body with the square of its distance from the axis of rotation expresses a body's tendency to resist angular acceleration.
The given data in the problem is;
m is the ring's mass.
r is the radius of a ring.
L is the rod length = 2r
The total Moment of Inertia about an axis;
[tex]\rm I = I_{rod}+I_{ring} \\\\ \rm I =\frac{ML^2}{3} +\frac{2mr^2}{5}[/tex]
According to the parallel axis theorem,
[tex]\rm I = \frac{2mr^2}{5} + ML^2[/tex]
The total Moment of Inertia about an axis will be;
[tex]\rm I_{total} = \frac{ML^2}{3} +\frac{2mr^2}{5}+ML^2 \\\\ \rm I_{total} =L^2 (\frac{M}{3} +m)+\frac{2mr^2}{5}[/tex]
Hence for a ring of mass m and radius straight r connected to a thin rod, the total moment of inertia about an axis is [tex]\rm I= L^2 (\frac{M}{3} +m)+\frac{2mr^2}{5}[/tex].
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If there were no external forces acting on the two pucks, their complex motion could be described as the combination of the uniform linear motion of the center of mass and a uniform circular motion of the pucks about the center of mass. Describe how well your results agree with this expectation, and explain any deviations that you observe from the predicted behavior
The absence of external forces will make the pucks move in the form of a uniform circular motion.
What is a circular motion?It should be noted that a circular motion simply means the movement of an object along the circumference of the circle.
In this case, the absence of external forces will make the pucks move in the form of a uniform circular motion.
If the friction is absent, the pucks will continue to move on the same path due to the first law of Newton and the law of conversation of energy. In this case,the results will match the predictions until there's loss in energy.
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The following equation illustrates the chemical reaction that occurs in a plant.
water + carbon dioxide + light energy → sugar + oxygen
Based on the law of conservation of energy, what happened to the light energy in the reaction?
A. It was produced by the plant.
B. It was changed into oxygen gas.
C. It was destroyed during the chemical reaction.
D. It was converted into chemical energy stored in the sugar.
Answer:
option d
it was converted into chemical energy stored in the sugar
Answer:
D. It was converted into chemical energy stored in the sugar.
Explanation:
A. It was produced by the plant. This is false because light energy is a reactant and not a product formed by the plant.
B. It was changed into oxygen gas. This is false because light energy could not be transformed to oxygen gas by any chemical means. Instead, carbon dioxide leads to oxygen being produced by the plant.
C. It was destroyed during the chemical reaction. This is false, it cannot be destroyed during the chemical reaction. Instead, it was used up and converted into chemical energy stored in the sugar.
D. It was converted into chemical energy stored in the sugar. This is true.
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With upward speeds of 12.5 m/s, the elevators in the Yokohama Landmark Tower in Yokohama, Japan, are among the fastest elevators in the world. Suppose a passenger with a mass of 70.0 kg enters one of these elevators. The elevator then goes up, reaching full speed in 4.00 s. Calculate the net force that is applied to the passenger during the elevator's acceleration.
The net force that is applied to the passenger during the elevator acceleration is 218.75 N.
What is net force?This is the single force obtained from the combinatiion of two or more forces
To calculate the net force that is applied to the passenger during the elevator's acceleration, we use the formula below.
Formula:
F = m(v-u)/t............ Equation 1Where:
F = forcem = massv = Final velocityu = initial velocityt = time.From the question,
Given:
m = 70 kgu = 0 m/sv = 12.5 m/st = 4 sSubstitute these values into equation 1
F = 70(12.5-0)/4F = 218.75 NHence, The net force that is applied to the passenger during the elevator acceleration is 218.75 N.
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When a 10-V battery is connected to a resistor, the current in the resistor is 2 A. What is the resistor's value
Answer:
5 ohms
Explanation:
V = IR
10 = 2 R
R = 5
The objects shown in the following diagrams have different masses and are different distances apart. Which diagram shows the two objects that have the greatest force of gravity acting between them?
Answer:
C. 10kg to 10kg
Explanation:
You have to picture to it I think
Please Help Me!
A boy holds a toy soldier in from of a concave mirror. The focal length of the mirror is 0.45 m and the boy holds the toy soldier at a distance of 0.25m from the mirror. Find the image distance.
The image distance when a boy holds a toy soldier in front of a concave mirror, with a focal length of 0.45 m. is -0.56 m.
What is image distance?This is the distance between the image formed and the focus when an object is placed in front of a plane mirror.
To calculate the image distance, we use the formula below.
Formula:
1/f = 1/u+1/v........... Equation 1Where:
f = Focal length of the mirrorv = Image distanceu = object distanceFrom the question,
Given:
f = 0.45 mu = 0.25 mSubstitute these values into equation 1 and solve for the image distance
1/0.45 = 1/0.25 + 1/v2.22 = 4+1/v1/v = 2.22-41/v = -1.78v = 1/(-1.78)v = -0.56 mHence, The image distance is -0.56 m.
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The interior of a refrigerator has a surface area of 2. 6 m2. It is insulated by a 4. 5 cm thick material that has a thermal conductivity of 0. 0098 J/m · s · ◦ C. The ratio of the heat extracted from the interior to the work done by the motor is 4. 4% of the theoretical maximum. The temperature of the room is 37. 7 ◦C, and the temperature inside the refrigerator is 3. 7 ◦C
For an interior of a refrigerator has a surface area of 2. 6 m2, The power is is mathematically given as
P= 71.56W
What is the power?Generally, the equation for the Fourier's law is mathematically given as
H = ∆Q/∆t = k∙A∙∆T/∆x
Therefore
H= 0.0112* 4.2 *(33.3 - 6.8) / 0.022m
H= 58.18J/s
For The coefficient of performance(COP)
COP = Q/W = H/P
Therefore
COP = 279.95K/(306.45K - 279.95K)
COP = 10.564
In conclusion
P = H/COP
P= 58.18W / 0.813
P= 71.56W
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Good evening! Can someone please answer this, ill give you brainliest and your earning 50 points. Would be very appreciated.
Answer:
Gases that are very good at absorbing long wave photons of infrared light
Explanation:
Green house gases examples are Carbon monoxide, nitric oxide etc.These gases absorb long wave photons of infrared light of sun's rays They melts the glaciers and increase the sea level .Which property of the water molecule causes two water molecules to be attracted to each other? (2 points)
Polar bonds between H and O atoms
Ionic bonding between water molecules
Hydrogen bonds between H atoms
Ionic bonding between O atoms
Answer:
hydrogen bonding between H atoms.
Explanation:
Under which condition would time periods of daylight and darkness be equal everywhere on Earth all year?.
If the earth rotated on an axis that was not tilted with respect to earth's orbit Under this condition time periods of daylight and darkness be equal everywhere on earth all year.
What is the earth's orbit?The Earth orbits the Sun in a counterclockwise pattern above the northern hemisphere at an average distance of 149.60 million km.
The Earth revolves around its axis once every 24 hours and orbits the sun once every 365 days. The Earth's rotation on its axis, not its orbit around the sun, causes day and night.
The term 'one day' refers to the time it takes the Earth to rotate once on its axis, which includes both day and night.
Hence the earth rotated on an axis that was not tilted with respect to the earth's orbit Under this condition time periods of daylight and darkness be equal everywhere on earth all year.
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The water was used to power a generator, creating _______________ energy
Answer:
electric
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To measure a population’s baseline genetic state, it must have _____________ to be in hardy-weinberg equilibrium
Answer:
b
Explanation:
b
how do greenhouse gases affect global temperatures
Answer:
Less heat radiates into space, and Earth is warmer
10. A ball is attached to a string of length 4 m to make a pendulum. The pendulum is placed at a location that is away from the Earth’s surface by twice the radius of the Earth. What is the acceleration due to gravity at that height and what is the period of the oscillations?
Please show all of your work.
Let's see
Radius of earth=6371mTwice of it=6371(2)=12742m[tex]\\ \rm\rightarrowtail T=2\pi\sqrt{\dfrac{l}{g}}[/tex]
[tex]\\ \rm\rightarrowtail T=2\pi \sqrt{\dfrac{4}{g}}[/tex]
[tex]\\ \rm\rightarrowtail T=2\pi\dfrac{2}{\sqrt{g}}[/tex]
[tex]\\ \rm\rightarrowtail T=\dfrac{4\pi}{\sqrt{g}}[/tex]
So
[tex]\\ \rm\rightarrowtail g=\dfrac{16\pi ^2}{T^2}[/tex]
Answer:
g' = 1.09 m/s²
T = 12 s
Explanation:
Gravity due to acceleration
Distance from center of Earth = r + 2r = 3rgravity due to acceleration on surface, g = GM/r²Substitute 3r in the denominatorg' = GM/(3r)² = GM/9r²⇒ g' = g/9 = 9.8/9 = 1.09 m/s²
Time period
T = 2π√L/g'T = 2π√4/1.09T ≅ 12 sMy Noacid performs a physics lab to determine the speed of sound inside a tube. She blocks off one end of the 120. 0 cm tube with a book and places a microphone at the other end. When she snaps her finger she determines the time for the sound to get back to the microphone is. 00695 s. What was the speed of sound that day
The speed of sound inside a tube when she snapped her finger is determined as 345.32 m/s.
Speed of the sound
The speed of the sound wave can be determined by applying echo formula as shown below;
v = 2d/t
where;
d is the distance traveled by the sound wave = 120 cm = 1.2 mt is the time when the sound wave was heard = 0.00695 sSubstitute the given parameters and solve for speed.
v = (2 x 1.2)/(0.00695
v = 345.32 m/s
Thus, the speed of sound inside a tube when she snapped her finger is determined as 345.32 m/s.
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An object when placed in front of convex lens forms a real image of 0.5 magnification. If the distance of the image from the lens is 24 cm, Calculate Focal Length of Lens.
[tex] \text{u =?} \\ \text{ v = 24cm} \\ \text{ m = 0.5} \\ \text{ f = ?}[/tex]
[tex] \implies \text{m} = \frac{ \text{v}}{ \text{u}} = \frac{24}{ \text{u}} [/tex]
[tex] \implies 0.5 = \frac{1}{2} = \frac{24}{ \text{u}} \\ \\ \therefore \text{u} = 48 \text{cm}[/tex]
[tex] \implies \frac{1}{ \text{f}} = \frac{1}{ \text{v}} - \frac{1}{ \text{u}} [/tex]
[tex] \implies \text{f} = \frac{1}{24} - \frac{1}{48} = \frac{2 - 1}{48} = \frac{1}{48} [/tex]
[tex] \text{f} = 48 \text{cm}[/tex]
[tex]\underline{ \text {According To Question,}}[/tex]
[tex] \text{24cm is the distance of object from lens,}[/tex]
[tex] \text{m} = \frac{ \text{v}}{ \text{u}} \\ \\ \implies \frac{1}{2} = \frac{ \text{u}}{24} [/tex]
[tex] \therefore \text{v} = \frac{24}{2} = 12 \text{cm}[/tex]
[tex] \implies \frac{1}{ \text{f}} = \frac{1}{ \text{v}} - \frac{1}{ \text{u}} [/tex]
[tex] \implies \frac{1}{ \text{f}} = \frac{1}{12} - ( \frac{1}{ - 24} )[/tex]
[tex] \implies \frac{1}{ \text{f}} = \frac{1}{12} + \frac{1}{24} = \frac{2 + 1}{24} = \frac{3}{24} [/tex]
[tex] \implies \text{f} = \frac{24}{3} = 8 \text{cm}[/tex]
Hope this helpsTo predict whether a star will ultimately become a black hole, what is the key property of the star we should look at?.
A star will ultimately become a black hole when it collapses due to end of fuel.
Which star becomes a black hole?When a star burns through the last of its fuel, the object may collapse, or fall into itself. For smaller stars which are about three times the sun's mass, the new core will become a white dwarf but when a larger star collapses, it turns into a black hole.
So we can can conclude that a star will ultimately become a black hole when it collapses due to end of fuel.
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Where are globular clusters located in the milky way?.
Answer:
Globular star clusters are located in the great spherical halo.
Explanation:
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Two solenoids have the same cross-sectional area and length, but the first one has twice as many turns per unit length as the second. The ratio of the self-inductance of the second solenoid to that of the first is.
Answer:
2:1
Explanation:
An object rotates with an angular speed that varies with time, as shown in the graph. How can the graph be used to determine the magnitude of the angular acceleration α of the object? Justify your selection.
Subtract the greatest value of the angular speed from the smallest value of the angular speed, because α=Δω.
Subtract the greatest value of the angular speed from the smallest value of the angular speed, because a equals delta omega .
Determine the slope of the line from 0s to 2s, because the slope represents ΔωΔt.
Determine the slope of the line from 0 second to 2 seconds , because the slope represents the fraction delta omega over delta t .
Determine the area bounded by the line and the horizontal axis from 0s to 2s, because α=12ωΔt.
Determine the area bounded by the line and the horizontal axis from 0 second to 2 seconds , because alpha equals one half omega delta t .
The angular acceleration cannot be determined without knowing the rotational inertia of the object.
We can find it up angular velocity with respect to time graph .
As
[tex]\\ \rm\Rrightarrow m=\dfrac{\Delta \omega}{\delta T}[/tex]
[tex]\\ \rm\Rrightarrow \alpha=\dfrac{\Delta \omega}{\delta T}[/tex]
So we get
[tex]\\ \rm\Rrightarrow m=\alpha[/tex]
We need the slope in order to find angular acceleration
We can determine the angular acceleration of the object by taking the slope of the line in the plot of angular speed versus time because the change in linear here.
What is angular acceleration ?The angular acceleration of an object is the measure of its rate of change in angular speed. Like the velocity, it a vector quantity and is characterized by a magnitude and direction.
The acceleration is the ratio of change in velocity to the time interval. From the graph of speed of an object versus the time taken, we can obtain the acceleration.
For a linear relation between the two quantities, the slope gives their ratio. Therefore, here, the slop of the line from 0 to 2 seconds represents the fraction delta omega over delta t. Hence, option D is correct.
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