Can 8 7 and 15 form a triangle?

In the given problem, we are given a parallelogram ABCD with the conditions that ∠GEC is congruent to ∠HFA and AE is congruent to FC. We need to prove that triangle GEC is congruent to triangle HFA.

To prove that triangle GEC is congruent to triangle HFA, we can use the Side-Angle-Side (SAS) congruence criterion.

Given that AE ≅ FC and ∠GEC ≅ ∠HFA, we have two sides and the included angle that are congruent.

Now, since ABCD is a parallelogram, opposite sides are parallel and congruent. Therefore, AD ≅ BC and AB ≅ DC.

By using the corresponding parts of congruent triangles, we can conclude that EG ≅ HF (opposite sides of a parallelogram) and EC ≅ FA (opposite sides of a parallelogram).

Now, we have all three sides of triangle GEC congruent to the corresponding sides of triangle HFA, satisfying the SAS congruence criterion.

Therefore, by the SAS congruence criterion, we can conclude that triangle GEC is congruent to triangle HFA.

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Colin has more chocolate milk by 1 cm³ more.

The volume of a pyramid can be calculated using the formula:

Volume = (1/3) x base area x height

John's container:

Volume = (1/3) x (8 cm x 8 cm) x 6 cm

Volume = 256 cm³

Colin's container:

Volume = (1/3) x (10 cm x 5 cm) x 8 cm

Volume = 133.33 cm³ (rounded to two decimal places)

Comparing the volumes, we can see that John's container has 256 cm³ of chocolate milk, while Colin's container has 133.33 cm³ of chocolate milk.

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The value of Variable x is,

⇒ x = 7

And, Measure of ∠VST is,

∠VST = 26 degree

We have to given that;

In the rectangle below,

RV = 3x-3, and SU = 36,

We know that;

Diagonal are bisect each other.

Hence, We get;

1/2 (SU) = RV

Substitute given values, we get;

1/2 (36) = 3x - 3

18 = 3x - 3

18 + 3 = 3x

21 = 3x

x = 21/3

x = 7

And, We have;

m ∠RVU = 128°

By figure, we get;

⇒ ∠VST = ∠STV = y

Hence, We can formulate;

⇒ ∠VST + ∠STV + ∠RVU = 180

Substitute all the values,

y + y + 128 = 180

2y = 180 - 128

2y = 52

y = 26

Hence, We get;

∠VST = 26 degree

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The area of the composite figure is equal to 100.3 square units.

In this problem we find the representation of a composite figure, formed by a rectangle and two semicircles, whose area formulas are, respectively:

Rectangle

A = w · h

Where:

Semicircle

A = 0.5π · r²

Where r is the radius of the semicircle.

If we know w = 12, h = 6 and r = 3, then the area of the composite figure is:

A = π · 3² + 12 · 6

A = 9π + 72

A = 100.3

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(a) The probability that all 4 of your answers are incorrect is 0.4823.

The probability of getting one question wrong is 5/6, so the probability of getting all four questions incorrect is (5/6)^4 = 0.4823 (rounded to four decimals).

(b) The probability that all 4 of your answers are correct is 0.0008.

The probability of getting one question correct is 1/6, so the probability of getting all four questions correct is (1/6)^4 = 0.0008 (rounded to four decimals).

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Answer:

This relationship is not a function.

The given function is f(x) = −3x^4 + 5x^2 − 2, and the point is (1,0). To find out if the point is a local maximum or minimum, we need to take the second derivative of the function and evaluate it at the given point. The second derivative of the function is f''(x) = −72x^2 + 20, and evaluating it at x = 1 gives f''(1) = −52. Since the second derivative is negative, the function has a local maximum at x = 1. Therefore, the point (1,0) is a local maximum of the function.

To find out whether a point is a local maximum or minimum of a function, we need to use the second derivative test. This involves taking the second derivative of the function and evaluating it at the given point. If the second derivative is positive, the function has a local minimum at that point. If the second derivative is negative, the function has a local maximum at that point. If the second derivative is zero, the test is inconclusive, and we need to use another method to determine if the point is a local maximum or minimum.

The given function f(x) = −3x^4 + 5x^2 − 2 has a local maximum at the point (1,0), as the second derivative f''(x) = −72x^2 + 20 is negative when evaluated at x = 1. Therefore, the point (1,0) represents the highest point on the graph of the function in the immediate vicinity of the point.

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To find the LSQ quadratic polynomial for the given data set, we need to start with creating the design matrix and observation vector. The design matrix X is constructed using the x values of the data set and is given by:
X = [1 -2 4; 1 0 0; 1 -2 4; 1 1 1]

Here, each row corresponds to one data point, with the first column representing the constant term, the second column representing the linear term, and the third column representing the quadratic term.
The observation vector y is constructed using the corresponding y values of the data set and is given by:
y = [1; 1; 1; 3]
Now, to find the LSQ quadratic polynomial, we need to solve the linear system X'Xp = X'y, where p is the parameter vector containing the coefficients of the quadratic polynomial.
Solving this system, we get:
p = [-11/4; 1/2; 9/4]
Therefore, the best fit quadratic polynomial for the given data set is:
y(x) = 20 - 11/4x + 1/2x^2 + 9/4x^2
Note that the constant term 20 is not obtained from the linear system and is instead taken directly from the polynomial form.

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The value of the integral is 8π/11.

To evaluate the integral [tex]\int_2^0\int_8y^2 \sqrt{(y/(11x^2))} x dy dx[/tex] using polar coordinates, we first need to express the integrand in terms of polar coordinates.

Converting the Cartesian coordinates (x, y) to polar coordinates (r, θ), we have:

x = r cos(θ)

y = r sin(θ)

Also, we have:

[tex]\sqrt{(y/(11x^2))[/tex]

= [tex]\sqrt {(r sin(\theta)/(11r^2 cos^2(\theta)))[/tex]

= [tex]\sqrt{(sin(\theta)/(11r cos(\theta)))[/tex]

So, the integral becomes:

[tex]\int_2^0 \int_8-y^2 \sqrt(y/(11x^2)) x dy dx[/tex]

= [tex]\int_0^{(\pi/2)} \int_0^{(8 sin(\theta))} \sqrt(sin(\theta)/(11r cos(\theta))) r dr d\theta[/tex]

Integrating with respect to r first, we have:

[tex]\int_0^{(\pi/2)} \int_0^{(8 sin(\theta))} \sqrt(sin(\theta)/(11r cos(\theta))) r dr d\theta[/tex]

= [tex]\int_0^{(\pi/2)} [1/2 \sqrt(sin(\theta)/11 cos(\theta)) r^2][/tex]evaluated from r = 0 to r = 8 sin(θ) dθ

= [tex]\int_0^{(\pi/2)} 1/2 \sqrt(sin(\theta)/11 cos(\theta)) (8 sin(\theta))^2 d\theta[/tex]

= [tex]\int_0^{(\pi/2)} 32/11 sin^2(\theta) d\theta[/tex]

Using the identity sin²(θ) = (1 - cos(2θ))/2, we can rewrite this as:

[tex]\int_0^{(\pi/2)} 32/11 (1/2 - 1/2 cos(2\theta)) d\theta[/tex]

= [16/11 θ - 8/11 sin(2θ)] evaluated from θ = 0 to θ = π/2

= 8π/11

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The value of y1 for the given differential equation using Euler's Method is y1 = 1.9.

First-order ordinary differential equations can have approximate solutions using Euler's method, a numerical approach. It functions by dividing the answer down into manageable steps and estimating the subsequent value at each step using the derivative. Euler's approach, though relatively straightforward, can be helpful for solving differential equations when there are no closed-form solutions or when finding analytical solutions is challenging.

To use Euler's Method to compute y1 for the given differential equation [tex]dy/dx + 3y = x^2 - 3xy + y^2[/tex], with the initial condition y(0) = 2 and step size h = Δx = 0.05, follow these steps:

Step 1: Rewrite the differential equation in the form dy/dx = f(x, y).
[tex]dy/dx = x^2 - 3xy + y^2 - 3y[/tex]

Step 2: Define the initial condition and step size.
x0 = 0, y0 = 2, and h = 0.05

Step 3: Calculate the next value of y using Euler's Method formula:
y1 = y0 + h * f(x0, y0)

Step 4: Substitute the values into the formula:
[tex]y1 = 2 + 0.05 * (0^2 - 3 * 0 * 2 + 2^2 - 3 * 2)[/tex]
y1 = 2 + 0.05 * (0 - 0 + 4 - 6)
y1 = 2 + 0.05 * (-2)
y1 = 2 - 0.1

Step 5: Compute the result:
y1 = 1.9

So, the value of y1 for the given differential equation using Euler's Method is y1 = 1.9.

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The solution to the system of equations  are A)  x = 4 and y = -2, and

B)  x = 1.25 and y = 11/6.

A) To solve the system of equations:

3x + 2y = 8

y = 2x - 10

We can use the substitution method or the elimination method. Let's use the substitution method:

Substitute the expression for y from equation 2 into equation 1:

3x + 2(2x - 10) = 8

Simplify and solve for x:

3x + 4x - 20 = 8

7x - 20 = 8

7x = 8 + 20

7x = 28

x = 28 / 7

x = 4

Now substitute the value of x back into equation 2 to solve for y:

y = 2(4) - 10

y = 8 - 10

y = -2

So, the solution to the system of equations is x = 4 and y = -2.

B) To solve the system of equations:

2x + 3y = 8

-3y + 3x = -3

We can use the elimination method:

Multiply equation 2 by -1 to eliminate the y term:

-1(-3y + 3x) = -1(-3)

3y - 3x = 3

Now add equation 1 and the modified equation 2:

2x + 3y + 3y - 3x = 8 + 3

-3x + 3x + 6y = 11

6y = 11

y = 11 / 6

Substitute the value of y back into equation 1 to solve for x:

2x + 3(11/6) = 8

2x + 33/6 = 8

2x + 5.5 = 8

2x = 8 - 5.5

2x = 2.5

x = 2.5 / 2

x = 1.25

So, the solution to the system of equations is x = 1.25 and y = 11/6.

Hence, The solutions are, A)  x = 4 and y = -2, and B)  x = 1.25 and y = 11/6.

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(a) Linearly separable data sets are those that can be separated by a straight line. In this case, the data set has two classes that cannot be perfectly separated by a straight line. Therefore, the data set is not linearly separable. (b) A quadratic feature X3 can be used to transform the data set to a higher-dimensional space where it becomes linearly separable. In this case, X3 = X1^2 - X2^2 + 2X1X2 makes the data linearly separable. (c) The equation X3 = Bo can be rearranged to solve for X2, which gives X2 = (Bo - X1^2)/2X1. This equation represents a hyperbola in the original feature space, and the regions above and below the hyperbola are classified as class 1 and class 2, respectively.

In conclusion, the given data set is not linearly separable, but a quadratic feature X3 can be used to make it linearly separable. The maximum margin classifier based on only X3 can be used to classify the data set, and the decision boundary in the original feature space is a hyperbola. The regions above and below the hyperbola are classified as class 1 and class 2, respectively.

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The profit function P(x) is given by:

P(x) = R(x) - C(x)

Substituting the given expressions for R(x) and C(x), we get:

P(x) = (-2x^2 + 469x) - (9x + 13650)

Simplifying this expression, we get:

P(x) = -2x^2 + 460x - 13650

To find the smallest break-even point, we need to find the quantity x for which the profit is zero. That is, we need to solve the equation:

P(x) = 0

Substituting the expression for P(x), we get:

-2x^2 + 460x - 13650 = 0

Dividing both sides by -2, we get:

x^2 - 230x + 6825 = 0

We can use the quadratic formula to solve for x:

x = [230 ± sqrt(230^2 - 4(1)(6825))] / 2(1)

x = [230 ± sqrt(52900)] / 2

x = [230 ± 230] / 2

x = 115 or x = 59.348

Since x represents the number of bins of cat food produced, we must choose the integer value for x. Therefore, the smallest break-even point occurs at x = 115.

Note that we could also have found the break-even point by setting the revenue equal to the cost and solving for x:

R(x) = C(x)

-2x^2 + 469x = 9x + 13650

2x^2 - 460x + 13650 = 0

Dividing both sides by 2, we get the same quadratic equation for x as before, which has solutions x = 115 and x = 59.348. However, we know that x must be a positive integer, so we choose x = 115 as the smallest break-even point.

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The interval of convergence of the series is [-1, 1], and the endpoints x = -1 and x = 1 converge as well.

For the interval of convergence of the series

∑n= [tex]1[infinity]n^3x^(2n)/(2^n[/tex]), we can use the ratio test:

[tex]|a_{n+1}/a_n| = |(n+1)^3 x^(2n+2))/(2^(n+1))| / |(n^3 x^(2n))/(2^n)|[/tex]

Simplifying this expression, we get:

[tex]|a_{n+1}/a_n| = [(n+1)^3/2] * |x|^2[/tex]

Taking the limit as n approaches infinity:

lim (n→∞) [tex]|a_{n+1}/a_n|[/tex] = lim (n→∞) [tex][(n+1)^3/2] * |x|^2[/tex]

Since the limit of (n+1)^3/2 is infinity, this series converges if and only if |x|^2 < 1, which means that the interval of convergence is [-1, 1].

However, we also need to check the endpoints x = -1 and x = 1 to see if the series converges at these points.

When x = 1, the series becomes:

∑n=1[infinity]n^3/(2^n)

We can apply the ratio test again to this series:

[tex]|a_{n+1}/a_n| = (n+1)^3/n^3 * 1/2[/tex]

Taking the limit as n approaches infinity:

lim (n→∞) [tex]|a_{n+1}/a_n|[/tex] = lim (n→∞) [tex](n+1)^3/n^3 * 1/2[/tex] = 1/2

Since the limit is less than 1, the series converges when x = 1.

When x = -1, the series becomes:

∑n= [tex]1[infinity](-1)^n n^3/(2^n)[/tex]

This is an alternating series, so we can apply the alternating series test:

The terms of the series are decreasing in absolute value, and

lim (n→∞)[tex]n^3/(2^n)[/tex] = 0

Therefore, the series converges when x = -1.

Thus, the interval of convergence of the series is [-1, 1], and the endpoints x = -1 and x = 1 converge as well.

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The volume of the solid, obtained by revolving the region bounded by xy = 1, y = 0, x = 1, and x = 2, using the washer method, is: a) π/2 cubic units when revolved about the axis x = -1 and b) 7π/6 cubic units when revolved about the x-axis.

What is washer method?

The washer method is a technique used to calculate the volume of a solid of revolution. It involves integrating the cross-sectional area of the solid, which is obtained by subtracting the inner area from the outer area of a "washer" or "annulus" shape.

a) To find the volume when revolved about the axis x = -1, we consider the slices perpendicular to the x-axis. Each slice will have a radius equal to the distance from the axis of revolution to the curve, which is x + 1. The differential thickness of the slice is dx.

Thus, the volume of each washer-shaped slice is π(radius_outer² - radius_inner²)dx. Integrating this expression from x = 1 to x = 2, we get the volume as π/2 cubic units.

b) When revolved about the x-axis, we consider the slices perpendicular to the y-axis. The radius of each slice is y, and the differential thickness is dy. The limits of integration are y = 1 and y = 2. Using the washer method and integrating π(radius_outer² - radius_inner²)dy, we find the volume to be 7π/6 cubic units.

Therefore, the volume of the solid when revolved about the axis x = -1 is π/2 cubic units, and when revolved about the x-axis is 7π/6 cubic units.

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The equation of the elastic curve for portion ab of the beam is y = w/24 * e^(-x/4 * l) * (4l^2 - x^2)

The elastic curve equation for a simply supported beam with a uniformly distributed load is y = (w/(24 * EI)) * (x^2) * (3l - x), where w is the load per unit length, E is the modulus of elasticity, I is the moment of inertia, x is the distance from the left end of the beam, and l is the length of the beam.

In this case, we are given a load w, and a beam of length l. The elastic curve equation is given as y = w/24 * e^(-x/4 * l) * (4l^2 - x^2), which is a variation of the standard equation. The e^(-x/4 * l) term represents the deflection due to the load, while the (4l^2 - x^2) term represents the curvature of the beam.

To derive this equation, we first find the deflection due to the load by integrating the load equation over the length of the beam. This gives us the expression for deflection as a function of x.

We then use the moment-curvature relationship to find the curvature of the beam as a function of x. Finally, we combine these two expressions to get the elastic curve equation for the beam.

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If the level of significance is decreased, the interval for the population proportion becomes narrower.

The level of significance, denoted by α, is the probability of rejecting the null hypothesis when it is true. When the level of significance is decreased, it means that we are requiring stronger evidence to reject the null hypothesis. This leads to a narrower confidence interval.

In a confidence interval for a population proportion, the range between the lower and upper bounds represents the range of plausible values for the true population proportion. As the level of significance is decreased, the critical value associated with it becomes larger, resulting in a smaller margin of error and a narrower confidence interval.

Therefore, as the level of significance decreases, the interval for the population proportion becomes narrower, providing a more precise estimate of the true population proportion.

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We restrict the domain of x to a specific range where the inverse function is well-defined.

This range is chosen to be (-π/2, π/2), which corresponds to the principal branch of the arctangent function.

We have,

To restrict the domain of the tangent function (tan x) and define the function arctangent (tan⁻¹x or atan x), we limit the values of x to a specific range.

Now,

The tangent function (tan x) is defined for all real numbers except for certain values where the function becomes undefined, such as when x is equal to (2n + 1) x π/2, where n is an integer.

To define the function arctangent (tan⁻¹x or atan x), we restrict the domain of x to a specific range where the inverse function is well-defined. Typically, this range is chosen to be (-π/2, π/2), which corresponds to the principal branch of the arctangent function.

Thus,

To define the arctangent function (tan⁻¹x), we only consider values of x that lie between -π/2 and π/2, excluding the endpoints.

This ensures that the function has a single-valued and well-defined inverse.

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No, your friend is incorrect.

Th measure of angle 4 is 129 degrees

We need to know that the sum of the interior angles of a triangle is equal to 180 degrees.

Then, we have that;

m<1 + m<2 + (180 - m< 4) = 180

substitute the values, we have;

7x + 7 + 5x + 14 + (168 -13x) = 180

expand the bracket, we have;

7x + 7 + 5x + 14 + 168 - 13x = 180

collect the like terms, we get;

7x + 5x - 13x = 180 - 189

12x - 13x = -9

subtract the like terms, we have;

-x = -9

Make 'x' the subject of formula, we have;

x = 9 degrees

m<4 = 129 degrees

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The maximum number of full scoops that can be placed into the trough without overflowing the interior of the trough is 9 full scoops.

The volume of the trough and the volume of one feed scoop, and then divide the volume of the trough by the volume of one feed scoop to get the maximum number of scoops that can fit inside.

The volume of the trough.

We can split the trough into two parts:

A rectangular prism and a truncated pyramid.

The rectangular prism has a base of 1 foot by 2 feet and a height of 1 foot, so its volume is:

[tex]V_{rectangular}[/tex] prism = base area × height

= (1 ft × 2 ft) × 1 ft

= 2 cubic feet

The truncated pyramid has a top base of 1 foot, a bottom base of 2 feet, and a height of 1 foot.

To find its volume, we can use the formula:

[tex]V_{truncated}[/tex] pyramid = (1/3) × height × (top area + bottom area + square root of (top area × bottom area))

The top area is the area of a circle with a diameter of 1 foot, and the bottom area is the area of a trapezoid with base dimensions of 1 foot and 2 feet and a base angle of 60 degrees.

Using the formulas for the area of a circle and the area of a trapezoid, we get:

top area = (1/2) × pi × (1/2 ft)²

= 0.1963 cubic feet

bottom area = (1/2) × (1 ft + 2 ft) × 1 ft × sin(60 degrees)

= 0.866 cubic feet

Plugging in these values, we get:

[tex]V_{truncated[/tex] pyramid = [tex](1/3) \times 1 ft \times (0.1963 + 0.866 + \sqrt{(0.1963 \times 0.866))[/tex]

= 0.543 cubic feet

The total volume of the trough is therefore:

[tex]V_{trough[/tex]= [tex]V_{rectangular prism[/tex] + [tex]V_{truncated pyramid[/tex]

= 2 + 0.543

= 2.543 cubic feet

Next, let's find the volume of one feed scoop.

A hemisphere with a diameter of 1 foot has a volume of:

[tex]V_{hemisphere[/tex] = (1/2) × (4/3) × pi × (1/2 ft)³

= 0.2618 cubic feet

The volume of the trough by the volume of one feed scoop to get the maximum number of scoops that can fit inside:

max number of scoops = [tex]V_{trough[/tex] / [tex]V_{hemisphere[/tex]

= 2.543 / 0.2618

≈ 9.71

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If y varies inversely is y = 9, x is equal to -32.

If y varies inversely as x, it means that their product remains constant. Mathematically, this can be expressed as y = k/x, where k is the constant of variation.

To find the value of k, we can substitute the given values of y and x into the equation.

Given that y = -18 when x = 16, we can write:

-18 = k/16

To solve for k, we can multiply both sides of the equation by 16:

16 × -18 = k

k = -288

Now that we have the value of k, we can use it to find x when y = 9. We can set up the equation as:

9 = -288/x

To solve for x, we can multiply both sides of the equation by x:

9x = -288

Dividing both sides by 9:

x = -288/9

Simplifying:

x = -32

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The particular solution is: Xp(t) = (t/4 - 19/16; -t/2 + 7/8). The correct option is b.

The given system of linear differential equations can be written as:

X'(t) = AX + B(t),

where X'(t) is the derivative of X(t), A is the matrix (2 3; 2 1), and B(t) is the column vector (t; 1). To find the particular solution, we can apply the method of undetermined coefficients. We assume a particular solution of the form Xp(t) = (at + b; ct + d), where a, b, c, and d are constants to be determined.

Taking the derivative of Xp(t), we get Xp'(t) = (a; c). Now, we substitute Xp(t) and Xp'(t) into the given equation:

(a; c) = (2 3; 2 1) (at + b; ct + d) + (t; 1).

Multiplying the matrix and vector, we get:

(a; c) = (2(at + b) + 3(ct + d); 2(at + b) + 1(ct + d)) + (t; 1).

Equating the components, we get the following system of linear equations:

a = 2a + 2b + 3c + 3d + 1,
c = 2a + 2b + c + d + 0.

Solving this system, we find a = t/4 - 19/16, b = -t/2 + 7/8. Therefore, the particular solution Xp(t) is:

Xp(t) = (t/4 - 19/16; -t/2 + 7/8),

which corresponds to option b.

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Answer:

There are 35 different combinations.

Step-by-step explanation:

To find the possible number of combinations, multiply the number of main courses by the number of desserts:

5*7 =35

There are 35 different combinations.

The value of y is 14

A triangle is a polygon with three sides having three vertices. There are different types of triangle. We have , isosceles triangle, scalene triangles, right triangle e.t.c

Isosceles triangle is a type of triangle in which two sides and the corresponding angles are equal.

The sum of angle In a triangle is 180°. i.e A+B+C = 180°

Therefore;

4y-15+4y-15 +7y = 180°

8y -30+7y = 180°

15y = 180+30

15y = 210

divide both sides by 15

y = 210/15

y = 70/5

y = 14

Therefore the value of x is 14

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To find the required linear model using least-squares regression, we first calculate the slope and y-intercept of the line that best fits the given data.

(a) We can use the formula for the slope and y-intercept of a least-squares regression line:

slope = r * (std_dev_y / std_dev_x)

y_intercept = mean_y - slope * mean_x

where r is the correlation coefficient between the two variables, std_dev_y and std_dev_x are the standard deviations of the dependent and independent variables, respectively, and mean_y and mean_x are the means of the dependent and independent variables, respectively.

Using the given data, we can calculate:

n = 5

sum_x = 10055

sum_y = 20884

sum_xy = 41938251

sum_x2 = 20125

sum_y2 = 46511306

mean_x = sum_x / n = 2011

mean_y = sum_y / n = 4177

std_dev_x = sqrt((sum_x2 / n) - mean_x^2) = 1.5811

std_dev_y = sqrt((sum_y2 / n) - mean_y^2) = 164.6483

r = (sum_xy - n * mean_x * mean_y) / (std_dev_x * std_dev_y * (n - 1)) = 0.9941

slope = r * (std_dev_y / std_dev_x) = 102.9552

y_intercept = mean_y - slope * mean_x = -199456.2988

Therefore, the linear model for these data is:

y = 102.9552x - 199456.2988

(b) To estimate the number of federal credit unions in the year 2017, we plug in x = 7 (corresponding to the year 2017) into the linear model and round to the nearest integer:

y = 102.9552(7) - 199456.2988 = 4605.0896

Rounding to the nearest integer, the estimated number of federal credit unions in the year 2017 is 4605.

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The two points on the curve where the tangent is horizontal are:

(0, -9) and (-3/2, 0).

To find where the tangent is horizontal, we need to find where the slope (dy/dx) equals zero.
Using the chain rule, we have:

dy/dx = (dy/dt)/(dx/dt)
     = (6t)/(2t^2-3)

Setting this equal to zero and solving for t, we get:
6t = 0
t = 0
or
2t^2 - 3 = 0
t = ±√(3/2)

Now we need to find the corresponding points on the curve.

When t = 0, x = 0 and y = -9. So the point (0, -9) is one point on the curve where the tangent is horizontal.

When t = √(3/2), x = -3/2 and y = 0. So the point (-3/2, 0) is another point on the curve where the tangent is horizontal.

Therefore, the two points on the curve where the tangent is horizontal are (0, -9) and (-3/2, 0).

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The problem statement is:You are shopping for baseballs and tennis balls at a sports store.

Each baseball costs $3 and each tennis ball costs $2. You want to buy not fewer than 45 baseballs and tennis balls altogether, and you have a $100 budget.a- Write a system of inequalities representing the number of balls you could buy.Solution: Let the number of baseballs be "b" and the number of tennis balls be "t".

Then the total number of balls can be represented as "b + t".Given that, you want to buy not fewer than 45 baseballs and tennis balls altogether. So,b + t ≥ 45Similarly, the total cost of baseballs and tennis balls is less than or equal to $100.

The cost of b baseballs is $3b and the cost of t tennis balls is [tex]$2t. So,3b + 2t ≤ 100[/tex]Thus, the system of inequalities representing the number of balls you could buy is:[tex]b + t ≥ 45 3b + 2t ≤ 100b ≥ 0, t ≥ 0b[/tex]- Can you buy 20 baseballs and 30 tennis balls?

Justify your answer - show your work. Solution: Let's check if (b, t) = (20, 30) satisfies the system of inequalities. b + t ≥ [tex]45   ⇒   20 + 30 ≥ 45   ⇒   50 ≥ 45 (True) 3b + 2t ≤ 100  ⇒   3(20) + 2(30) ≤ 100  ⇒   60 + 60 ≤ 100[/tex] (False)So, you cannot buy 20 baseballs and 30 tennis balls as it does not satisfy the system of inequalities.

Answer: Therefore, you can't buy 20 baseballs and 30 tennis balls.

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Based on the scatterplot, the correct relationship between the GPA and IQ score of the students is positive and roughly linear.

For student A, the IQ score is approximately 110 and the GPA is approximately 2.

The correct reason for considering points A, B, and C as unusual is that students A and B have two lowest GPAs but moderate IQs, while student C has the lowest GPA but moderate IQ.

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The shopper wants to make sure that she has enough cash to purchase a $110 clarinet, and she asks a clerk for the total amount, including sales tax. The clerk responds by stating that the total amount, including sales tax, is $121.

Solution  The formula for calculating the sales tax percentage is as follows:

Sales tax percentage = (Sales tax / Total amount) x 100

The sales tax percentage can be calculated using the given values in the question:

Sales tax = Total amount - Price of item (clarinet)

$121 - $110 = $11

Total amount = $121Therefore, the sales tax percentage can be calculated as follows:

Sales tax percentage = (Sales tax / Total amount) x 100

= ($11 / $121) x 100

= 9.09 %

Therefore, the sales tax percentage on the clarinet is 9.09%.

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The completed table is

boxes sold money collected

1 $30

2 $60

3 $90

4 $120

5 $150

6 $180

7 $210

8 $240

To complete the table, we need to calculate the amount of money collected for each number of boxes sold. Since each box contains 20 bars and each bar sells for $1.50, we can use this information to determine the money collected.

Let's go through each row of the table:

For the first row, where Noah sells 1 box, we can calculate the money collected by multiplying the number of boxes (1) by the number of bars per box (20) and then multiplying it by the price per bar ($1.50).

Money collected = 1 box × 20 bars/box × $1.50/bar = $30.

For the second row, where Noah sells 2 boxes, we can use the same formula:

Money collected = 2 boxes × 20 bars/box × $1.50/bar = $60.

Continuing this pattern, for the third row, where Noah sells 3 boxes:

Money collected = 3 boxes × 20 bars/box × $1.50/bar = $90.

For the fourth row, where Noah sells 4 boxes:

Money collected = 4 boxes × 20 bars/box × $1.50/bar = $120.

Moving on to the fifth row, where Noah sells 5 boxes:

Money collected = 5 boxes × 20 bars/box × $1.50/bar = $150.

For the sixth row, where Noah sells 6 boxes:

Money collected = 6 boxes × 20 bars/box × $1.50/bar = $180.

For the seventh row, where Noah sells 7 boxes:

Money collected = 7 boxes × 20 bars/box × $1.50/bar = $210.

Finally, for the last row, where Noah sells 8 boxes:

Money collected = 8 boxes × 20 bars/box × $1.50/bar = $240.

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Noah is helping his band sell boxes of chocolate to fund a field trip. Each box contains 20 bars and each bar sells for $1.50.

Complete the table for values of m.

boxes sold money collected

1

2

3

4

5

6

7

8