Estimate the constant rate of withdrawal (in m3 /s) from a 1375 ha reservoir in a month of 30 days during which the reservoir level dropped by 0.75 m in spite of an average inflow into the reservoir of 0.5 Mm3 /day. During the month, the average seepage loss from the reservoir was 2.5 cm, total precipitation on the reservoir was 18.5 cm and the total evaporation was 9.5 cm

Answers

Answer 1

Answer:

Explanation:

1 ha = 10⁴ m²

1375 ha = 1375 x 10⁴ m² = 13.75 x 10⁶ m²

In flow in a month = .5 x 10⁶ x 30 m³ = 15 x 10⁶ m³

Net inflow after all loss = 18.5 - 9.5 - 2.5 cm = 6.5 cm = .065 m

Net inflow in volume = 13.75 x 10⁶ x .065 m³= .89375 x 10⁶ m³

Let Q be the withdrawal in m³

Q - 15 x 10⁶ - .89375 x 10⁶ = 13.75 x 10⁶ x .75 = 10.3125 x 10⁶

Q = 26.20 x 10⁶ m³

rate of withdrawal per second

= 26.20 x 10⁶ / 30 x 24 x 60 x 60

= 26.20 x 10⁶ / 2.592 x 10⁶

= 10.11 m³ / s

Answer 2

The rate of withdrawal is 10.11 cubic meter per second

Given-

Total reservoir is 1375 hectare. which is equal to [tex]1375\times 10^4[/tex] meter square.

The average seepage loss from the reservoir is 2.85 cm or 0.0285 m.

Total precipitation on the reservoir is 18.5 cm or 0.185 m.

Total evaporation is 9.5 cm or 0.085 m.

The average inflow into the reservoir is [tex]0.5\times10^6[/tex] cubic meter per day.

The total inflow in a month can be calculate is

[tex]=0.5\times 30=1500\times10^4[/tex]

Net inflow is equal to the total precipitation on the reservoir subtract by all the losses.It can be represent as,

[tex]Q_{net}=0.185 - 0.095 - 0.025[/tex]

[tex]Q_{net}=0.065[/tex]

Total volume inflow is equal to the product of net inflow and total reservoir,

[tex]V_{net} =1375\times 10^4\times Q_{net}[/tex]

[tex]V_{net} =1375\times 10^4\times 0.065[/tex]

[tex]V_{net} =89.375[/tex]

The constant rate of withdrawal in cubic meter can be calculated by adding the net inflow in a month, total volume inflow and the reservoir.

[tex]Q=1375\times 10^4\times 0.75+89.375\times 10^4+1500\times10^4[/tex]

[tex]Q=2620\times10^4[/tex]

For per second withdrawal,

[tex]Q=\dfrac{2620\times10^4}{30\times24\times60\times60}[/tex]

[tex]Q=10.11[/tex]

Hence, the rate of withdrawal is 10.11 cubic meter per second.

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Related Questions

Greatest to least order

Answers

Answer:

Explanation:

FBEDAC

A cylinder is filled with a liquid of density d upto a height h. If the beaker is at rest ,then the mean pressure on the wall is?​

Answers

Answer:

h over 2 dg

Explanation:

brainliest!!!!!!!

How is a charged object created?

Charges are created when an object touches water.
Charges are created when the object is exposed to light.
Charges are transferred from one object to another.
Charges are transferred from the air to the object.

Answers

Answer:

Charges are transferred from one object to another.

Explanation:

The charges from one object to another are sharing there energy.


A bicyclist accelerates from rest to a speed of
5.0 meters per second in 10 seconds. During the
same 10 seconds, a car accelerates from a speed
of 22 meters per second to a speed of 27 meters
per second. Compared to the acceleration of the
bicycle, the acceleration of the car is

Answers

Answer:

They have the same acceleration of 0.5m/s2 (please note m/s2 is the unit for acceleration and 2 is the power of s)

Explanation:

acceleration= velocity ÷ time

and the time is said to be 10seconds

velocity of car will be the new velocity- the initial velocity = 27-22= 5

acceleration= 5÷10

acceleration= 0.5

hope this helped

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What is the measure of minor arc AB?

Answers

the answer is b, you are correct. here’s why.

a is angle p which is 286

b is correct because it looks like it would fit based on what 286 looks like

c is too small

d is way too small

hope this helps brainlist would be much appreciated:)

10. A change in
indicates the acceleration of an object
O A the time of travel
OB the distance from a given point
O c displacement
OD velocity

Answers

Answer:

d velocity will be the one according to me

If your mass is 63.7kg and standing 7.5m away from a boulder with a mass of 9750.6kg what is the gravitational force?

Answers

The gravitational force is determined as 7.37 x 10⁻⁷ N.

What the gravitational force?

The gravitational force is determined by applying Newton's law of universal gravitation.

Mathematically, the formula for the Newton's law of universal gravitation is given as;

Fg = ( Gm₁m₂ ) / ( r² )

where;

G is universal gravitation constantm₁ is your massm₂ is the mass of the boulderr is the distance between you and the boulder

Fg = ( 6.67 x 10⁻¹¹ x 63.7 x 9750.6 ) / ( 7.5² )

Fg = 7.37 x 10⁻⁷ N

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What force acts in the opposite direction to
an object moving through the air?

Answers

Air resitances also know as drag is a force that is caused by air the force acts in oppsite directions to an object moving through the air ..

HOPE THIS HELP YOU ..

The electric field 30cm from a van de Graaff generator is measured to be 28,300N/C. What is the charge of the van de Graaf?

Answers

Answer:

14

Explanation:

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What does a mass extinction look like in the fossil record?
O A. A layer of rock contains only fossils of living things that no longer
exist on Earth.
B. A layer of rock contains only fossils of species that presently exist
on Earth.
O C. A younger layer of rock contains a much greater variety of fossils
than a slightly older layer of rock does.
D. An older layer of rock contains a much greater variety of fossils
than a slightly younger layer of rock does.

Answers

Answer:

the answer is D

Explanation:

Mass extinctions were first identified by the obvious traces they left in the fossil record. ... Such dramatic changes in adjacent rock layers make it clear that mass extinctions were geologically rapid and suggest that they were caused by catastrophic events (e.g., a period of intense volcanic activity).

Mass extinction events wiped out many species at the same time resulting in older rock layers having more fossil variety than younger rock layers.

What are mass extinction events?

Mass extinction events are events which resulted in the mass death of many species of organisms.

Mass extinction events are presumed to have occurred in the past as seen from gaps in the fossils records.

Mass extinction events are thought to have occurred through intense volcanic activity in a particular area.

A mass extinction event in the fossil record will show an older layer of rock containing a much greater variety of fossils than a slightly younger layer of rock does.

Therefore, mass extinction events wiped out many species at the same time.

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1: Give one word answer.

The bouncing back of the light rays after hitting a smooth surface _____

Answers

Answer:

RThe answer is Reflection....

Using a simply pulley/rope system, a crewman on an Arctic expedition is trying to lower a 6.17-kg crate to the bottom of a steep ravine of height 23.8 meters. The 55.6-kg crewman is walking along holding the rope, being careful to lower the crate at a constant speed of 1.50 m/s. Unfortunately, when the crate reaches a point 13.2 meters above the ground, the crewman steps on a slick patch of ice and slips. The crate immediately accelerates toward the ground, dragging the hapless crewman across the ice and toward the edge of the cliff.

If we assume the ice is perfectly slick (that is, no friction between the crewman and the ice once he slips and falls down), at what speed will the crate hit the ground? Assume also that the rope is long enough to allow the crate to hit the ground before the crewman slides over the side of the cliff. At what speed will the crewman hit the bottom of the ravine?

Answers

Answer:

a. Vc = 5.06 m/s

b. Vp =  22.18 m/s

Explanation:

The acceleration of the pulley-mass system is as follows:

a = [tex]\frac{mg}{m + M}[/tex]

Solving for acceleration, we get:  

a = [tex]\frac{6.17 *9.8}{6.17 + 55.6}[/tex]

a = 0.97

So, for the part a:

Calculate the velocity of the crewman by using the following equation:

Vc = [tex]\sqrt{Vi^{2} + 2ay}[/tex]

Substituting the values into the equation, we get:

Vc = [tex]\sqrt{1.50^{2} + 2*0.97*13.2}[/tex]

Vc = 5.06 m/s

Now, for part b:

Calculate the final velocity of the pulley by using the following expression:

Vp = [tex]\sqrt{Vi^{2} +2gy }[/tex]

Just plugging in the values.

Vp = [tex]\sqrt{5.06^{2} +2*9.8*23.8 }[/tex]

Vp =  22.18 m/s

 

Question 2 of 25
Which three statements are true about the wave shown?
A. The wave is a longitudinal wave.
B. The wave could be an electromagnetic wave.
C. The wave could be a sound wave.
D. The wave is a mechanical wave.

Answers

Answer:

ACD

Explanation:

according to it's description above

The wave is a mechanical wave and can also be sound wave also the wave is a longitudinal wave. The correct option is A, C, and D.

What is mechanical wave?

A mechanical wave is one whose energy cannot be transmitted via a vacuum. To transfer their energy from one place to another, mechanical waves need a medium.

A mechanical wave is something like a sound wave. A vacuum can not be traversed by sound waves.

Waves like mechanical waves require a medium to travel through. Non-mechanical waves are those that can travel through any medium.

Mechanical waves include, but are not limited to, sound waves, water waves, and seismic waves.

The three claims are accurate as follows: The wave is a longitudinal wave and can also be a mechanical wave or a sound wave.

Thus, the correct option is A, C, and D.

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Your question seems incomplete, the missing image is:

Magnus has reached the finals of a strength competition. In the first round, he has to pull a city bus as far as he can. One end of a rope is attached to the bus and the other is tied around Magnus's waist. If a force gauge placed halfway down the rope reads out a constant 2100 Newtons while Magnus pulls the bus a distance of 1.30 meters, how much work does the tension force do on Magnus

Answers

Answer:

Workdone = -2730 J

Explanation:

Formula for workdone is;

W = Force × Displacement

Now, according to Newton's 3rd law of motion, to every action, there is an equal and opposite reaction.

In the question given, we are told that a force gauge placed halfway down the rope reads out a constant 2100 Newtons while Magnus pulls the bus. This means that the force exerted by the rope on Magnus acts in an opposite direction to that which Magnus does to the rope.

Therefore, the force will be in the negative direction.

So;

Workdone = -2100 N × 1.3 m

Workdone = -2730 J

What are two things that happen to the sugars that are made by the plant during photosynthesis?
I

Answers

Answer:

The sugars produced by photosynthesis can be stored, transported throughout the tree, and converted into energy which is used to power all cellular processes. Respiration occurs when glucose (sugar produced during photosynthesis) combines with oxygen to produce useable cellular energy.

Explanation:

I think this is correct lol.

You throw a small rock straight up from the edge of a highway bridge that crosses a river. The rock passes you on its way down, 5.00 s after it was thrown. What is the speed of the rock just before it reaches the water 22.0 m below the point where the rock left your hand? Ignore air resistance.

Answers

Answer:

Explanation:

for vertical movement , time to reach the top = time to reach the hand = 2.5 s

v = u - gt

At the top , v = 0 , time t = 2.5 s

0 = u - g x 2.5

u = 2.5 x 9.8 = 24.5 m /s

velocity of throw = 24.5 m /s

So , when it passes the hand on its way down , it will have velocity equal to 24.5 m /s and it will accelerate downwards . Let its velocity down by 22 m be v

v² = u² + 2 g s

= 24.5² + 2 x 9.8 x 22

= 600.25 + 431.2

= 1031.45

v = 32.11 m /s .

If a car's speed triples, how does the momentum and kinetic energy of the

car change? Answer in form (momentum change, kinetic energy change)

Answers

Answer: When the car speed triples, momentum also triples but Kinetic energy increases 9 times or by 9 fold.

Explanation:

The momentum of a car (an object) is

p= mv

where

m is =the mass of the object( in this case car)

v is its= velocity

While the kinetic energy is is given by the formulae

K=1/2mv²

To determine how momentum and kinetic energy of the  car changes when the speed of the object triples, We have that the new velocity,

v¹= 3v

So that  the momentum  change becomes

p¹=mv¹=m (3v)= 3mv

mv=p

therefore p¹= 3p

we can see that the momentum also triples.

And the kinetic energy change  becomes

K¹=1/2m(v¹)²= 1/2m (3v)²

= 1/2m9v²= 1/2 x m x 9 x v²=9 x1/2mv²

1/2mv²=K

K¹= Kinetic energy = 9k

but Kinetic energy increases 9 times

An object's mass has a greater influence on its kinetic energy than does its velocity. True or False?

Answers

Answer: I think false

Explanation:The velocity at which an object is sent moving and the mass of the object both play a hand in the level of kinetic energy that object produces. Mass and kinetic energy have a positive relationship, which means that as mass increases, kinetic energy increases, if all other factors are held constant.

To increase the gravitational force between the two objects above, I could
Your answer:
A. increase the mass of the objects and decrease the distance between the objects.

B. increase BOTH the distance and the mass between the two objects

C. decrease the mass of the objects and increase the distance between the objects.

D. decrease BOTH the mass and distance between the two objects.

Answers

Answer:

Option A

Explanation:

a 2kg bowling bowl is at a top of the hill with a speed of 9.8 m/s with a height of 40m. what is its potential energy

Answers

To calculate potential energy, use the formula

[tex]ep \: = mgh[/tex]

Where m is mass in kg, g is gravitational field strength in m s^-2 and h is height in metres.

So in this case, calculate

2kg × 9.8m/s × 40m

and you should find your answer.

Honeybees accumulate charge as they fly, and they transfer charge to the flowers they visit. Honeybees are able to sense electric fields; tests show that they can detect a change in field as small as 0.77 N/C. Honeybees seem to use this sense to determine the charges on flowers in order to detect whether or not a flower has been recently visited, so they can plan their foraging accordingly. As a check on this idea, let's do a quick calculation using typical numbers for charges on flowers.If a bee is at a distance of 24 cm, can it detect the difference between flowers that have a +30 pC charge and a +40 pC charge?

Answers

Answer:

difference between the field  = 1.56 N/C

as; 1.56 N/C is greater than 0.77 N/C;

Hence, Honeybees can detected the difference

Explanation:

Given the data in the question;

distance r = 24 cm = 0.24 m

charge 1 Q1 = +30 pC = 30×10⁻¹² C

charge 2 Q2 = +40 pC = 40×10⁻¹² C

Now, electric field due to +30 pC charge

E1 = kQ1/r²

where coulomb constant k is 9 × 10⁹ N.m²/C²

so we substitute

E1 = [( 9 × 10⁹ ) × (30×10⁻¹²)] / (0.24)²

E1 = 0.27 / 0.0576

E1 = 4.69 N/C

electric field due to +40 pC charge

E2 = kQ1/r²

E2 = [( 9 × 10⁹ ) × (40×10⁻¹²)] / (0.24)²

E2 = [( 9 × 10⁹ ) × (40×10⁻¹²)] / (0.24)²

E2 = 0.36 / 0.0576

E2 = 6.25 N/C

Now,

E2 = E1 =  6.25 N/C - 4.69 N/C = 1.56 N/C

difference between the field  = 1.56 N/C

as; 1.56 N/C is greater than 0.77 N/C;

Hence, Honeybees can detected the difference

a man is trying to pull a box a distance of 3 m with a force of 20 N that makes a 35º with the horizontal.

Answers

Answer:

34.4Joules

Explanation:

Complete question

a man is trying to pull a box a distance of 3 m with a force of 20 N that makes a 35º with the horizontal. Find the workdone

Work done = Fdsin theta

Force F = 20N

distance d = 3m

theta = 35 degrees

Substitute

Workdone = 20(3)sin 35

Workdone = 60sin35

Workdone = 34.4Joules

Hence the workdone by the man is 34.4Joules

Part of understanding the physical effects on Mars, we must understand
first that our laws of Physics on Earth must apply in the same manner that it
is on Mars. Discuss the Three Laws of Motion as set forth by Isaac Newton.
Following this, write out the mathematical description of these laws. Provide
three examples to con rm your results, and include free body diagrams

Answers

Answer:

so easy add the subtract then multiplay the add

Explanation:


How can you tell whether an object is neutral
or charged? What would you have to do to test
that object?

Answers

Answer:

The number of electrons that surround the nucleus will determine whether or not it is electrically charged or electrically neutral

Explanation:

There is a parallel plate capacitor. Both plates are 4x2 cm and are 10 cm apart. The top plate has surface charge density of 10C/m^2 and the bottom plate has a surface charge density of -10C/m^2. Find the total charge on each plate. Find the electric field at the point exactly midway between the plates. Find the electric potential between the two plates. If an electron was in the middle the two plates, find the force on it.

Answers

Answer:

1) The total charge of the top plate is 0.008 C

b) The total charge of the bottom plate is -0.008 C

2) The electric field at the point exactly midway between the plates is 0

3) The electric field between plates is approximately 1.1294 × 10¹² N/C

4) The force on an electron in the middle of the two plates is approximately 1.807 × 10⁻⁷ N

Explanation:

The given parameters of the parallel plate capacitor are;

The dimensions of the plates = 4 × 2 cm

The distance between the plates = 10 cm

The surface charge density of the top plate, σ₁ = 10 C/m²

The surface charge density of the bottom plate, σ₂ = -10 C/m²

The surface area, A = 0.04 m × 0.02 m = 0.0008 m²

1) The total charge of the top plate, Q = σ₁ × A = 0.0008 m² × 10 C/m² = 0.008 C

b) The total charge of the bottom plate, Q = σ₂ × A = 0.0008 m² × -10 C/m² = -0.008 C

2) The electrical field at the point exactly midway between the plates is given as follows;

[tex]V_{tot} = V_{q1} + V_{q2}[/tex]

[tex]V_q = \dfrac{k \cdot q}{r}[/tex]

Therefore, we have;

The distance to the midpoint between the two plates = 10 cm/2 = 5 cm = 0.05 m

[tex]V_{tot} = \dfrac{k \cdot q}{0.05} + \dfrac{k \cdot (-q)}{0.05} = \dfrac{k \cdot q}{0.05} - \dfrac{k \cdot q}{0.05} = 0[/tex]

The electric field at the point exactly midway between the plates, [tex]V_{tot}[/tex] = 0

3) The electric field, 'E', between plates is given as follows;

[tex]E =\dfrac{\sigma }{\epsilon_0 } = \dfrac{10 \ C/m^2}{8.854 \times 10^{-12} \ C^2/(N\cdot m^2)} \approx 1.1294 \times 10^{12}\ N/C[/tex]

E ≈ 1.1294 × 10¹² N/C

The electric field between plates, E ≈ 1.1294 × 10¹² N/C

4) The force on an electron in the middle of the two plates

The charge on an electron, e = -1.6 × 10⁻¹⁹ C

The force on an electron in the middle of the two plates, [tex]F_e[/tex] = E × e

∴ [tex]F_e[/tex] = 1.1294 × 10¹² N/C ×  -1.6 × 10⁻¹⁹ C ≈ 1.807 × 10⁻⁷ N

The force on an electron in the middle of the two plates, [tex]F_e[/tex] ≈ 1.807 × 10⁻⁷ N

Do you ever have a sensation of loneliness?

Answers

Answer:

nope

Explanation:

sige bigyan kitang Happy pills

In which direction does Earth’s gravitational force act?
a. opposite the direction of motion
b. downward toward the center of Earth
c. upward away from the center of Earth
d. in the direction of motion

Answers

B downward
Earth's gravitational force acts in what direction? Earth's gravity acts downward toward the center of Earth. Gravity causes objects to accelerate downward, whereas air resistance acts in the direction opposite to the motion and reduces acceleration.

While talking to a friend, a construction worker momentarily set her cell phone down on one end of an iron rail of length 7.50 m. At that moment, a second worker dropped a wrench so that it hit the other end of the rail. The person on the phone detected two pulses of sound, one that traveled through the air and a longitudinal wave that traveled through the rail. (Assume the speed of sound in iron is 5,950 m/s and the speed of sound in air is 343 m/s).
A) Which pulse reaches the cell phone first?
B) Find the separation in time (in s) between the arrivals of the two pulses.

Answers

Answer:

A)

The impulse that reaches the cell phone first is the Longitudinal wave

B)  0.0206  seconds

Explanation:

length of Iron rail = 7.5 m

speed of sound in Iron = 5950 m/s

speed of sound in Air = 343 m/s

A) Determine which pulse reaches the cell phone first

The impulse that reaches the cell phone first is the Longitudinal wave

 Time for longitudinal pulse to be detected =  7.5 / 5950 = 0.00126 s

  Time for pulse through air to be detected = 7.5 / 343 = 0.02186  s

B) separation in time between the arrivals of the two pulses

   ΔT = 0.02186 - 0.00126  = 0.0206  seconds

The cylinder with piston locked in place is immersed in a mixture of ice and water and allowed to come to thermal equilibrium withthe mixture. The piston is then moved inward very slowly, that thegas is always in thermal equilibrium with the ice-water mixture,what happens to the following(increase, decrease, same)?

a. volume of gas
b. temperature of gas
c. internal energy of gas,
d. pressure of gas

Answers

Answer:

a. volume of gas:  (decreases)

b. temperature of gas:  (same)

c. internal energy of gas: (same)

d. pressure of gas: (increases)

Explanation:

We have a gas (let's suppose that is ideal) in a piston with a fixed volume V.

Then we put in a reservoir at 0°C (the mixture of water and ice)

remember that the state equation for an ideal gas is:

P*V = n*R*T

and:

U = c*n*R*T

where:

P = pressure

V = volume

n = number of mols

R = constant

c = constant

T = temperature.

Now, we have equilibrium at T = 0°C, then we can assume that T is also a constant.

Then in the equation:

P*V = n*R*T

all the terms in the left side are constants.

P*V = constant

And knowing that:

U = c*n*R*T

then:

n*R*T = U/c

We can replace it in the other equation to get:

P*V = U/c = constant.

Now, the piston is (slowly) moving inwards, then:

a) Volume of the gas: as the piston moves inwards, the volume where the gas can be is smaller, then the volume of the gas decreases.

b) temperature of the gas: we know that the gas is a thermal equilibrium with the mixture (this happens because we are in a slow process) then the temperature of the gas does not change.

c) Internal energy of the gas:

we have:

P*V = n*R*T = constant

and:

P*V = U/c = constant.

Then:

U = c*Constant

This means that the internal energy does not change.

d) Pressure of the gas:

Here we can use the relation:

P*V = constant

then:

P = (constant)/V

Now, if V decreases, the denominator in that equation will be smaller. We know that if we decrease the value of the denominator, the value of the quotient increases.

And the quotient is equal to P.

Then if the volume decreases, we will see that the pressure increases.

YALL PLEASE HELP I BARELY HAVE TIME
Which of the following is not a property of light?
Light travels in a straight line.
Light travels through empty space.
Light moves in a compressional wave.
All options are true

Answers

Answer:

All of then are true

I need brainliest so I can rank up

Explanation:

Answer:

I think all options are true is the right answer

Explanation:

Mark me the brainliest plzzz

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