Find each difference and show work please !!

The height of the actual house is 26'.26" .

A ratio indicates how many times one number contains another.

Therefore, the heights will form a similar length. Therefore, the corresponding length have the same ratios.

Therefore,

height of Kelly / x = height of Kelly shadows / height of house shadow

Hence,

where

x = actual height of the house

5.4 / x = 8.7 / 42.3

cross multiply

42.3 × 5.4 = 8.7x

Therefore,

228.42 = 8.7x

divide both sides by 8.7

228.42 / 8.7 = 8.7x / 8.7

x = 26.2551724138

Therefore, the height of the actual house is 26'.26"

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The time that the first train would get to Oakengats is 08:15.

The time of arrival of the first train can be gotten from the table.

The first entry has a blank space. This would have been the time of arrival for the train.

After the blank space, the next time is when the fits train got to this destination. That is at 08:15

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Answer:

Step-by-step explanation:

let x = the number of votes of the first person

winner  = x + 4000

x+ x+4000 = 6000

2x=2000

x=1000

first person = x = 1000

winner  = x+4000 = 5000

The winner got 5000 votes

They are parallel because they have the same slope of 2.

The segments are given as;

AB => 6x - 3y = 9

CD => 4x - 2y = 8

We start by making y the subject of both equations

AB => 6x - 3y = 9

-3y = -6x + 9

Divide through by -3

y = 2x - 3

CD => 4x - 2y = 8

-2y = -4x + 8

Divide through by -2

y = 2x - 2

A linear equation is represented as:

y = mx + b

Where m represents the slope of the line.

By comparing the three equations, we have:

m1 = 2

m2 = 2

Parallel lines have equal slopes.

This means that the lines AB and CD are parallel lines

Hence, they are parallel because they have the same slope of 2.

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Answer: They are parallel because they have the same slope of 2.

Step-by-step explanation:vvvvvvvvvvvvvvvvvvvvv

Answer:

2

Step-by-step explanation:

There are only 2 numbers in the final answer (6.0), so you just need 2 significant figures.

Congruency property relates to two or more triangles with similar dimensions, and internal angles. So that the required statements to complete the proof are:

1. definition of a straight angle.

2. subtraction property of equality

3. corresponding sides of similar triangles are proportional

4. transitive property of equality.

The intersection of two or more lines forms a number of angles which depends on the number of lines involved. These angles formed may have similar or different properties.

When two or more triangles have similar lengths of sides and measure internal angles, it can be said that they are congruent. Thus they have some common properties.

Therefore, the appropriate statements to answer the given question are stated below:

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Answer:

Step-by-step explanation:

sin(90-a)=cos

cos = angle adjacent

theta=BC/CA

Considering the mean of a discrete distribution, you are expected to earn $0.13 by the end of the game.

The expected value of a discrete distribution is given by the sum of each outcome multiplied by it's respective probability.

Since 71% of your rolls are successful and 29% of your rolls are unsuccessful, the distribution of your earnings is:

Hence the expected value is:

E(X) = 1 x 0.71 - 2 x 0.29 = 0.71 - 0.58 = 0.13

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3 is the square root of nine.

The square root of a number is the factor that we can multiply by itself to get that number. The symbol for square root is \sqrt{ } ​square root of, end square root . Finding the square root of a number is the opposite of squaring a number.

To find the fraction square root, first, find the square root of the numerator and then find the square root of denominator. After finding the square root values, simplify the fraction. For example, √(4/16), can be written as √4/√16.

(3)^2 = 9

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Answer: a, c, e

Step-by-step explanation:

a) True. If x=0, f(0)=c.

b) False. Considering the quadratic formula, we know the solutions are not always x=c.

c) True. This is a standard fact.

d) False. If the discriminant is not positive, there are less than two x-intercepts.

e) True. If you plug into the formula [tex]x=-\frac{b}{2a}[/tex], if b=0, then obviously the x-coordinate of the vertex is also 0.

The volume of the box without the lid is 500 cubic inches.

The capacity of an object is measured by its volume. For instance, a cup's capacity is stated to be 100 ml if it can hold 100 ml of water in its brim.

Another way to think of volume is as the amount of space a three-dimensional object takes up.

Calculation for the volume of the box-

The volume of a box without a lid is given by the formula v = 4x(10-x)².

Where,

'x' is a length in inches, and

'v' is the volume in cubic inches.

The volume when x = 5 inches.

Substitute the value of 'x' in the formula of volume;

v = 4×5(10-5)²

  = 20×5²

v  = 500

Therefore, the volume of a box without a lid is 500 cubic inches.

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The value value of x is at the 40th percentile of the distribution is 0.65.

The standard normal distribution is a normal distribution with a mean of zero and standard deviation of 1. The standard normal distribution is centered at zero and the degree to which a given measurement deviates from the mean is given by the standard deviation

Given:- μ[tex]_X[/tex]=0,σ[tex]_X[/tex]=1

We can standardize the random variable: Z=(X−μx)/σx,

Then the equation is P(X≤ x )=Φ(x−μx/σx)=Φ(x−0/1)=0.4

Inverse function

Ф[tex]\\^{-1}[/tex](0.4) = [tex]\frac{x-0}{1}[/tex]

From the table we get,

Ф[tex]^{-1}[/tex] = 0.65

Thus

[tex]\frac{x-40}{10}[/tex] = 0.65

x -0 = 0.65

x = 6.5

Thus the value value of x is at the 40th percentile of the distribution is 0.65

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The values of x and y that are solutions to the simultaneous equations are; x = -11 and y = -4

We are given the simultaneous equations;

4x - 6y = -20   -----(eq 1)

-2x + 4y = 6     -----(eq 2)

Multiply equation 2 by 2 and eq 1 by 1 to get;

-4x + 8y = 12     -----(eq 3)

Add eq 3 to eq 1 to get;

2y = -8

y = -4

Thus;

4x - 6(-4) = -20

4x + 24 = - 20

4x = -20 - 24

4x = -44

x = -44/4

x = -11

Thus, the values of x and y that are solutions to the simultaneous equations are; x = -11 and y = -4

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Answer:

Step-by-step explanation:

43

I dont exactly know if this is correct sorry if its wrong

Answer:

81

Step-by-step explanation:

A perfect square is multiplying a number with the same number in question. 81 is a perfect square because either 9 or -9 will go into it perfectly, like a square's length and height.

[tex]9^{2} = 81[/tex]

Answer: 81

Step-by-step explanation:

81 can be perfectly square rooted into 9. [tex]\sqrt{81}=9[/tex]

The attached graph represents the scatter plot of the table of values

The table of values is given as:

Variable A 1 4 2 3 5 1 3 7 6 6 2 9 7 5 8

Variable B 6 6 1 6 7 4 4 7 5 3 5 25 21 4 4

Rewrite the table as:

x 1 4 2 3 5 1 3 7 6 6 2 9 7 5 8

y 6 6 1 6 7 4 4 7 5 3 5 25 21 4 4

Next, we plot the values on a graph

See attachment for the scatter plot

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Answer:

The area of the square is 121mm

Step-by-step explanation:

To solve this we need two basic formulas:

P = 4s

A = [tex]s^{2}[/tex]

P = perimeter

s = the length of the side

Since the shape is a square all the sides are the same length. To get the value of 's' we need to isolate:

P = 4s

44 = 4s

44 / 4 = 4s / 4

11 = s

Now plug in the answer for 's' to get the area:

A = [tex]s^{2}[/tex]

A = [tex]11^{2}[/tex]

A = 121

Hope this helps.

Answer:

x=27.80

Step-by-step explanation:

we know that cosA=base/hypotaneous

so,

[tex]cos44 = \frac{20}{x} \\ x = \frac{20}{cos(44)} \\ = \frac{20}{0.7193...} \\ = 27.80 [/tex]

Answer:

A.  12 grams Zn

B.  280 g of copper.

Step-by-step explanation:

100 grams of brass

20 grams of zinc

100 grams of brass has 20 grams of Zn.

20/100 = 0.200  Zn   20% Zn  and 80% copper.

A.  (60 g brass)*(0.2) = 12 grams Zn

B.  (350 g brass)*(0.80) = 280 g of copper.

If [tex]$D_{o,\frac{1}{2}} \frac{1}{2} (x, y)[/tex] exists a dilation of △ ABC, the facts regarding the image

△A'B'C' exist AB exists parallel to A'B'.

Any point in the coordinate plane exists directed by a point (x, y), where the x value exists the position of the point with respect to the x-axis, and the y value exists the position of the point with respect to the y-axis.

A dilation exists a transformation [tex]$D_{o,k} \frac{1}{2} (x, y)[/tex], with center O and a scale factor of k that exists not zero, that maps O to itself and any other point P to P'. The center O exists as a fixed point, P' exists as the image of P, and points O, P, and P' exist on the exact line.

In a dilation of [tex]$D_{o,\frac{1}{2}} \frac{1}{2} (x, y)[/tex], the scale factor, 1/2 exists mapping the original figure to the image in such a manner that the distances from O to the vertices of the image exist half the distances from O to the original figure.

Also, the size of the image exists half the size of the original figure.

If [tex]$D_{o,\frac{1}{2}} \frac{1}{2} (x, y)[/tex] exists a dilation of △ ABC, the facts regarding the image △A'B'C' exist AB is parallel to A'B'.

[tex]$D_{o,k} \frac{1}{2} (x, y) = (\frac{1}{2} x, \frac{1}{2}y)[/tex]

The distance from A' to the origin exists half the distance from A to the origin.

Therefore, the correct answer is option A). △ A'B'C' exist AB is parallel to A'B'.

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Step-by-step explanation:

12 = 2 × 2 × 3

18 = 2 × 3 × 3

56 = 2 ×2 × 2 × 7

Now

Common factor = 2

Remaining factor = 2 × 3 × 2 × 3 × 7

LCM = RF × CF

= 504

hence the lCM of 12 , 18 and 56 is 504...

[tex]...[/tex]

Answer:

answer is the third choice : 104

Step-by-step explanation:

Inscribed Angle Theorem

If an angle is inscribed in a circle, then the measure of the angle equals one half the measure of its intercepted arc.

so the intercepted arc is TWICE the measure of an angle inscribed in a circle

1. A central angle is an angle with endpoints located on a circle's circumference and vertex located at the circle's center. A central angle in a circle determines an arc.

2. An inscribed angle is an angle formed by three points on the circle's circumference.

Angle at the Center Theorem: An inscribed angle is half of the central angle (if they determine the same arc).

In your case angles:

1. ∠QSR is insribed (determines the arc QR);

2. ∠QTR is central (determines the arc QR).

Then by Angle at the Center Theorem, m∠QTR=2m∠QSR=2·52°=104°. Arc QR has the same measure as central angle QSR.

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Answer:

Step-by-step explanation:

true

Answer:

[tex]a_{18}=-70[/tex]

Step-by-step explanation:

[tex]a_n=a_1+(n-1)d[/tex]

[tex]a_1=2, d = -4[/tex]

[tex]a_{18}=-2+(18-1)*(-4)=-2-68=-70[/tex]

See below for the solution to each question

From the graph, we can see that:

V(x) have a positive value from x > 0 to x < 5.5

When x = 0 and ≥ 5.5, the values of V(x) are either 0 or negative

Hence, the reasonable domain of V(x) is 0 < x < 5.5

From the graph, the maximum value of V(x) is at

V(2) = 182

Hence, the approximate value of x that gives the maximum volume is 2

This is the interval where V(x) increase as x increase

From the graph, V(x) increase from x > 0 to x = 2

Hence, the approximate values of x where the volume increases are 0 < x ≤ 2

The other function is

B(x) = 140

So, the point of intersection represent where the volume is 140

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[tex]\textbf{ Heya !}[/tex]

Your Answer Is:-

[tex]\sf{9x\div6}[/tex]

because,

               it has a coefficient of 9 (a number that comes before a variable)

`hope that was helpful to u ~

The three stages that have to do with fluency, progression and automaticity are found in the Number Sense and Operations .

This is the part of mathematics that is known to teach the student basic ways to carry out number operations in mathematics. This has to do with representation of numbers as well as solving for the existing relationships in these numbers.

Having a sense of numbers is a very important ability skill that has to be developed early is students to enable them progress in the subject.

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Normal income: 25 $

Last week's income: 25 + 20: 45 $

% = Last week's/normal = 45/25 ×100 =180 %

Probability that the lock code consists of all even digits is [tex]1344[/tex] if we choose the [tex]4[/tex] digit lock is randomly from numbers [tex]1,2,3,4,5,6,7,8,9[/tex]

How can we find the probability that the lock code consists of all even digits?

Total numbers are [tex]1,2,3,4,5,6,7,8,9[/tex]

And we choose [tex]4[/tex] digit code

So probability of choosing [tex]4[/tex] numbers from [tex]9[/tex] numbers without reapitation is

[tex]9p_{4} =\frac{9!}{(9-4)!} \\=\frac{9*8*7*6*5!}{5!} \\=3024[/tex]

For All numbers are even , probability the last digit of number is even.

So we have [tex]4[/tex]  even number and if we fix one on last digit and can change other [tex]3[/tex] then the probability is

[tex]4*8P_{3} =4*\frac{8!}{(8-3)!} \\=4*\frac{8*7*6*5!}{5!} \\=1344[/tex]

So the total probability of code lock having all even number is [tex]1344[/tex]

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