Find m (angle) 1 . Then classify the triangle by its angles.


M (angle) 1 =

The situation involving coins that is modeled by the system of equations x + y = 24, 0.25x + 0.05y = 4.60 is given as follows:

You have a combination of 24 quarters and cents, and the total you have is of $4.60. How many coins of each type you have.

To obtain the meaning of each of the variables x and y, we look at the second equation, given as follows:

0.25x + 0.05y = 4.60.

This means that:

The result of this sum means that the total amount of money that you have is of $4.60.

The first equation is given as follows:

x + y = 24.

Which means that the total number of coins that you have is of 24.

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The number of different North Dakota license plates that can be issued is 17,576,000 plates.

For the first digit, there are 10 possibilities (0 to 9). For the second and third digits, there are also 10 possibilities each. For the first letter, there are 26 possibilities. For the second and third letters, there are also 26 possibilities each.

The total number of different license plates that can be issued is therefore:

= 10 x 10 x 10 x 26 x 26 x 26

= 1, 000 x 17, 576

= 17, 576, 000 different plates

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So, it rained 15/8 inch the day before yesterday.

The total amount of rain that fell in the last three days is 1 inch. We know that 2/8 of an inch fell today, and 3/8 of an inch fell yesterday. We can add these amounts together to find out how much more it rained the day before yesterday.

To add 2/8 and 3/8, we need to convert the fractions to have a common denominator, which is 8.

2/8 = 2/8 * 1 = 2/8

3/8 = 3/8 * 1 = 3/8

Now we can add the fractions:

2/8 + 3/8 = (2+3)/8 = 5/8

Since we know that the total amount of rain that fell in the last three days is 1 inch, we can subtract the amount that fell today and yesterday from the total amount to find out how much more it rained the day before yesterday:

1 inch - (5/8 inch) = 15/8 inch

Therefore, it rained 15/8 inch the day before yesterday.

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a) The number of traders who sell only one fruit is given as follows: 88.

b) The number of traders who sell only two fruits is given as follows: 9.

The amounts are obtained using Venn sets in the context of this problem.

The sets are given as follows:

10 sell all three fruits, hence:

A ∩ B ∩ C = 10.

15 vendors sell apples and mangoes, hence:

(A ∩ C) + (A ∩ B ∩ C) = 15

(A ∩ C) = 5.

14 vendors sell apples and oranges, hence:

(A ∩ B) + (A ∩ B ∩ C) = 14

(A ∩ B) = 4.

Hence the number who sell two of them is of:

(A ∩ B) + (A ∩ C)  = 4 + 5 = 9.

50 vendors sell mangoes, hence:

C + (A ∩ C) + (A ∩ B ∩ C) = 50

C = 35.

46 vendors sell oranges, hence:

B + (A ∩ B) + (A ∩ B ∩ C) = 46

B = 32.

40 vendors sell apples, hence:

A + (A ∩ B) + (A ∩ C) + (A ∩ B ∩ C) = 40.

A + 9 + 10 = 40

A = 21.

Hence the number of vendors who sell only one fruit is given as follows:

A + B + C = 21 + 32 + 35 = 88.

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Sample Parameter: The population's weight and the average weight of the cereal box The grain on the line's average weight is the parameter.

The value that consistently appears in a given set is known as the mode in statistics. The mode or modal value is the value or number that appears most frequently in a data set and has a high frequency. Along with mean and median, there are three other ways to measure central tendency. The mode can be calculated quite easily. After sorting the numbers in a set according to their order—lowest to highest or highest to lowest—count how many times each number appears in the group.

given

Example: 50th box of cereal

All cereal boxes are lined up in the population

Example Parameter: The cereal box's average weight

Population metric: The cereal on the line's average weight

Sample Parameter: The population's weight and the average weight of the cereal box The grain on the line's average weight is the parameter.

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Eight 1/2s are in 4. This can be visualized with pattern blocks, as four triangles (each triangle is 1/2) would be needed to make up a square (4).

Visualization is the process of creating graphical representations of data and information. It can take the form of charts, graphs, diagrams, maps, and other visual representations of data and patterns. Visualization can be used to explore, analyze, and communicate data in an effective and meaningful way, helping to make complex data more accessible and easier to understand. Visualization can also help to uncover trends and relationships that might otherwise be difficult to detect.

b. Three 2/3s are in 2. This can be visualized with pattern blocks, as three hexagons (each hexagon is 2/3) would be needed to make up a rectangle (2).
c. Six 1/6s are in 1. This can be visualized with pattern blocks, as six rhombuses (each rhombus is 1/6) would be needed to make up a hexagon (1).

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The place value of 3 in 10,000s place is the product of 10 with the place value of 3 in thousands place.

Every digit in a number has it's own place value. Place value is the position of a digit in a number.

For example, in the number 3456, 6 is in the ones place, 5 is in the tens place, 4 is in the hundreds place and 3 is in the thousands place.

Given the number 33,291.

Place value of 1 = 1

Place value of 9 = 90

Place value of 2 = 200

Place value of 3 in thousands place = 3000

Place value of 3 in ten thousands place = 30,000 = 3000 × 10

That is, place value of 3 in 10,000s place is the product of ten with the place value of 3 in thousands place.

Hence the place value of 3 in thousands place multiplied to 10 gives the place value of 3 in 10,000s place.

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Answer: -2/3x is the slope and the beginning amount is 5 so the equation would be -2/3x+5.

Step-by-step explanation:

Once you find the slope using the formula rise/run you will get 2/3 but since the slope is going downwards it would be -2/3 which gives you the mx. Now to find the beginning amount look where the line intersects the graph which will give you the equation.

Answer:

B) 81 and 20°

Step-by-step explanation:

In any triangle, the sum of the measures of the three angles is 180°. Therefore, if two angles in a triangle have measures of 79° and 81°, the third angle must have a measure of 180 - 79 - 81 = 20°. Therefore, the answer is B) 81 and 20°.

Answer:

B

Step-by-step explanation:

Answer:

x = 1

Step-by-step explanation:

Immediately, we will simplify like terms on the left side of the equation. This will give us:

[tex]\sqrt{2x-x-1}[/tex]  = 0

Simplifying gives us:

[tex]\sqrt{x-1}[/tex] = 0

Now, an important thing to note, is that for the square root of a number to be 0, the number has to be 0. Therefore, x - 1 must equal 0. So, x = 1. Checking our work gives us:

[tex]\sqrt{2x - x - 1}[/tex] = 0

[tex]\\\sqrt{2 - 1 - 1}[/tex] = 0

[tex]\sqrt{0}[/tex] = 0

It all checks out.

Hope this helped!

Answer:

x + 18

Step-by-step explanation:

The variable is going to be the amount of money Jason has before his grandmother gives him money.

That variable is x.

Then, his grandmother gives him $18. The $18 would be added to the amount of money that Jason already has.

The expressions would be x + 18.

By solving, we see that the product of the polynomials 4 - a and a3 + 7a - 18 is a3 + 3a2 + 46a + 72.

The location on the y-axis where the slope of the line passes is known as the intersection point in mathematics. a point on a line or curve where the y-axis crosses. The equation for the straight line is given as Y = mx+c, where m denotes the slope and c the y-intercept. In the intercept form of the equation, the line's slope (m) and y-intercept (b) are highlighted. The slope and y-intercept of an equation with the intercept form (y=mx+b) are m and b, respectively. There are several equations that can be rewritten to look like slope intercepts. The slope and y-intercept are both modified to 1 if y=x is rewritten as y=1x+0, for example.

given

(4 - a) * ( a3 + 7a - 18 )

= 4a3 + 28a - 72 - a4 + 7a2 + 18 a

= a3 + 3a2 + 46a + 72

By solving, we see that the product of the polynomials 4 - a and a3 + 7a - 18 is a3 + 3a2 + 46a + 72.

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The number of green and black marbles will be 15 and 20 black marbles respectively.

Probability simply means the chance that a particular thing or event will happen. It is the occurence of likely events. It is simply the area of mathematics that deals with the numerical estimates of the chance that an event will occur or that a particular statement is true.

We have the following information:

5 red marbles

6 blue marbles

3 green marbles

4 black marbles

2 yellow marbles

Total marble = 20 marbles

The number of green marbles:

= 3/20 × 100

= 15

The black marbles will be:

= 4/20 × 100

= 20

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Answer:

y = 3x - 2

Step-by-step explanation:

Answer:

The answer is a because the sign should be facing right but not be greater than or equal to.

So, Todd picked 1 apple.

We can use the information given to set up the following equations:

Let x be the number of apples Jack picked, and y be the number of apples Marta picked.

We know that x + y = 16 (Jack and Marta pick a total of 16 apples)

Let y be the number of apples Marta picked, and z be the number of apples Rand picked.

We know that y + z = 15 (Marta and Rand pick a total of 15 apples)

Let z be the number of apples Rand picked, and w be the number of apples Todd picked.

We know that z + w = 13 (Rand and Todd pick a total of 13 apples)

We know that the total number of apples picked is 45, therefore x + y + z + w = 45

We can use the equation x + y = 16 to express x in terms of y:

x = 16 - y

We can substitute this into the other equations

(16 - y) + y = 16

y + z = 15

z + w = 13

We can sum all the equations:

(16 - y) + y + y + z + z + w = 45

16 + 2y + 2z + w = 45

From the equation y + z = 15, we can substitute y = 15 - z

16 + 2(15 - z) + 2z + w = 45

16 + 30 - 2z + 2z + w = 45

46 + w = 45

w = 1

Therefore Todd picked 1 apple.

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The smallest whole number that can be divisible by both 176 and 342 is 30096.

To find out the least whole number that is divisible by two numbers, we have to find out the LCM. LCM is the least common multiple. This is done by factorization. We have to factorize both numbers. Prime factorization means we have to write the number as a product of prime numbers.

                   176 =  2×2×2×2×11= 2⁴× 11

                   342 = 2×3×3×19 = 2 × 3² × 19

According to the prime factorization method, we have to multiply the highest powers.

So  LCM = 2⁴×  3²× 11 ×19

               = 30096

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Using Punnett square we know that 25%of the possible gene combinations result in albino coloring.

The genotypes of a specific cross or breeding experiment are predicted using the Punnett square, a square diagram.

It bears Reginald C. Punnett's name, who developed the method in 1905.

Biologists use the figure to calculate the likelihood that a child will have a specific genotype.

So, there is only one gene combination that could result in albinism.

4 different gene pairings are possible.

The proportion of gene combinations that might result in albinism.

Coloring is, therefore:

Percentage = 1/4 * 100 = 25%

Therefore, using Punnett square we know that 25%of the possible gene combinations result in albino coloring.

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Correct question:

Genetics In deer, the gene N is for normal coloring and the gene a is for albino. Any gene combination with an N results in normal coloring. The Punnett square shows the possible gene combinations of an offspring and the resulting colors when both parents have the gene combination Na.

What percent of the possible gene combinations result in albino coloring?

Vanessa needs to buy 2*(22/7)sqrt(1547/22) + 2 inches of ribbon.

What is the area of circle?

The area of a circle is given by the formula: A = πr^2, where A is the area of the circle, π is a constant (approximately equal to 3.14) and r is the radius of the circle.

Given the area of the circular region is 154 square inches. We can use the formula to find the radius: 154 = πr^2

By substituting π = 22/7 we get:

154 = (22/7)r^2

Solving for r, we get:

r = sqrt(154*7/22)

The circumference of the circle is given by the formula C = 2πr, where C is the circumference and r is the radius.

By substituting the value of r we got before, we get:

C = 2πr = 2*(22/7)sqrt(1547/22)

To be sure she has enough ribbon, Vanessa decides to buy 2 inches more of the ribbon than the original circle's circumference. So she needs to buy:

C + 2 = 2*(22/7)sqrt(1547/22) + 2 inches

Hence, Vanessa needs to buy 2*(22/7)sqrt(1547/22) + 2 inches of ribbon.

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The general solution to the given differential equation is y = c₁e⁻t + c₂te⁻t + t².

The given differential equation can be written as y'' - y' - 2y = -2t + 4t², which is a second-order linear differential equation with constant coefficients. To solve this equation, the first step is to solve the associated homogeneous equation, which is y'' - y' - 2y = 0. This homogeneous equation can be solved by using the characteristic equation, r² - r - 2 = 0, which has two roots, r = 2 and r = -1.

The general solution of the homogeneous equation is then y = c₁e²t + c₂e⁻t. To find the particular solution of the non-homogeneous equation, the method of undetermined coefficients is used. Since the non-homogeneous term is 4t², the particular solution of the non-homogeneous equation is yp = t².

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Answer:

g(- 6) = 11

Step-by-step explanation:

substitute x = - 6 into g(x) , that is

g(- 6) = - (- 6) + 5 = 6 + 5 = 11

Answer:

11

Step-by-step explanation:

g(x) = -x + 5

Let x = -6

g(-6) = -(-6) + 5

         =6+5

         =11

There are 10 integers that satisfy 0 < a < 100.

What are integers?

Zero, a positive natural number, or a negative integer denoted by a minus sign are all examples of integers. The inverse additives of the equivalent positive numbers are the negative numbers.

Here, we have

Given: When working modulo m, the notation a⁻¹ is used to denote the residue b for which ab = 1 (mod m), if any exists.

We have to find integers that satisfy 0 < a < 100.

a(a − 1)⁻¹ ≡  4a⁻¹ (mod 20)

a ≡ 4a⁻¹(a − 1)(mod 20)

a² ≡ 4(a-1)(mod 20)

a² - 4a + 4 ≡ 0(mod 20)

(a - 2)² ≡ 0(mod 20)

a = 2 + 10n | for n = (0, 1, 2, 3.....9)

Hence, there are 10 integers that satisfy 0 < a < 100.

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The true statement is 6 less than 10

From the question, we have the following parameters that can be used in our computation:

(-2) (-3) less greater than equal than 8- (-2)

We start by evaluating each expression

So, we have the following representation

(-2) (-3) = 6

8- (-2) = 10

Substitute the known values in the above equation, so, we have the following representation

6 less greater than equal than 10

6 is less than 10

So, we have

6 less than 10

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The dual formula is a formula which we get when we replace the symbol ∨ by ∧ , ∧ by ∨ , T by F  or F by T.

Basically , we can say that it is obtained by replacing tautology by contradiction.

There are certain rules which are to be followed while applying dual formula which are,

S1 is a tautology if and only if S2 is a contradiction.

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Linear equations are equations that can be written in the form ax + b = c, where a, b, and c are real numbers and a ≠ 0.

The equation can be solved for the variable x by subtracting b from both sides and then dividing both sides by a. This will give the solution for x, which is x = (c - b) / a.

For example, consider the equation 2x + 4 = 10. This is a linear equation since it can be written in the form ax + b = c, where a = 2, b = 4, and c = 10. To solve for x, subtract b from both sides to get 2x = 6, and then divide both sides by a to get x = 3. Therefore, the solution to the equation is x = 3.

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Answer: B

Step-by-step explanation:

Correlation tells us the relationship of 2 variables. Looking at the graph, the data appears to going down, as we read graphs from left to right. We can automatically eliminate C and D, since we have determined going down. We know it's also not A because if the correlation is constant, then all the dots would be lined up, and not scattered around. Since the dots are going down, this tells us that it is a negative correlation. Hence, B is the answer.

Answer:

B. negative correlation

Step-by-step explanation:

Answer: 3x+4=34

Step-by-step explanation: let the number be x

A.T.Q

the number is 3 times i.e 3x

4 increase=3x+4.

and it says the equation is equal to 34.

3x+4=34

The dimensions of the original sandbox was 2 ft X 2 ft..

Let, The original has a length of Xft and a width of Xft

The area of original sandbox is X^2 ft^2

As per given statement,

The new sandbox would have a length of (X+4)ft and a width of (X+5)ft

So, the area of new sand box would be: (X+4)(X+5) ft^2

Given, the area of new sandbox will be 38 square feet greater than the area of the original sandbox.

so,

X^2+38 = (X+4)(X+5)

or, X^2+38 = X^2 + 9X + 20

Eliminating X^2 from both side

0r, 9X+ 20 = 38

0r, 9X = 18

0r, X = 18/9 = 2

So, we assumes that the original has a length of Xft and a width of Xft

then the dimensions of the original sandbox was 2 ft by 2 ft.

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The unknown angles in the parallel lines are as follows;

x = 28

y = 23

When parallel lines are cut by a transversal line, angle relationships are formed such as linear angles, vertically opposite angles, interior angles, corresponding angles, alternate interior angles, alternate exterior angles etc.

using vertical angles and same side interior angles,

5y - 4 + 3y = 180 (same side interior angles are supplementary)

8y - 4 = 180

8y = 180 + 4

8y = 184

divide both sides by 8

y = 184 / 8

y = 23

Hence,

3y  = 2x + 13(corresponding angles)

corresponding angles are congruent.

Hence,

3(23) = 2x + 13

69 - 13 = 2x

2x = 56

x = 56 / 2

x = 28

Therefore,

x = 28

y = 23

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Therefore ,A language being infinitive is consequently required but not sufficient for undecidability, according to the solution to the provided problem of infinite.

The ideas of zero and infinity are related, although evidently, zero is not the same as infinity. Instead, if N/Z set  exists, and N is any positive number, the quotient grows indefinitely as Z approaches 0. Therefore, it is obvious that N / 0 is limit- less.

Here,

Regular languages are all finite languages. Some of the infinite languages are common. Only infinite languages have an undecidability limit.

There must be specific language strings that cause the TM to fail for the language to be undecidable. In fact, such strings must exist indefinitely (otherwise, the poorly behaved ones could be handled by special-case logic).

Thus, undecidability requires an is infinite language but does not prove it.

Therefore ,A language being infinitive is consequently required but not sufficient for undecidability, according to the solution to the provided problem of infinite.

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