Find the 11th term of the following geometric sequence 2,6,18,54,…

Find The 11th Term Of The Following Geometric Sequence 2,6,18,54,

Answers

Answer 1

Answer:

118,098

Step-by-step explanation:

Notice that each term is multiplied by 3, 2 x 3 is 6, 6 x 3 is 18... and so on.

so 54*3 = 162 and keep multiplying your answer by three until you have 11 times


Related Questions

How many different triangles can you make if you are
given these three measurements for angles?

Answers

Answer:

1

Step-by-step explanation:

If you're given 3 side lengths and 3 measurements of the angles , there's only one triangle that you may draw. You also can draw distinctive  triangles given 3 aspect lengths or  aspect lengths and the blanketed distinctive measure.

Answer:

1

Step-by-step explanation:

if you are given 3 measurements you are kind of stuck making that one triangle, no matter which way you shape it you have to have those three angles so you can't make more than that one triangle

simplify 35x-35
over 14x-49

Answers

Answer:  Distributive property  a(b+c) = ab + ac

-5(7)x + 7(7) = -35x + 49 (D)

More help please! IF YOU DON'T KNOW THE ANSWER THEN DO NOT ANSWER!

Answers

Answer:

8/3 < 8/2

D

Step-by-step explanation:

8/3 = 2.67

8/2 = 4

So, when fractions have equivalent (same) numerators, the one with the lesser denominator is the greater fraction.

There is more left if 8 is divided by 2 than when it is divided by 3

[Answer]8/3 < 8/2

[Answer] D

PLEASE RATE!! I hope this helps!!

If you have any questions comment below

help me please I will mark as brainlist ​

Answers

Answer:

[tex] \frac{ \alpha + \beta + \gamma }{ - d} [/tex]

Step-by-step explanation:

If we simplify that fraction, we get

[tex] \frac{ \alpha + \beta + \gamma }{ \alpha \beta \gamma } [/tex]

Keep that in mind.

If y, a ,b are zeroes of the cubic polynomial, then that means

[tex](x - \alpha )(x - \beta )(x - \gamma )[/tex]

make up the polynomial.

Notice that leading xoeffeicent will be 1, so the roots will multiply to

[tex] - d[/tex]

so

[tex] \alpha \beta \gamma = - d[/tex]

which gives us

[tex] \frac{ \alpha + \beta + \gamma }{ - d} [/tex]

Proof:

Consider the function

[tex](x - 2)(x - 3)(x - 5)[/tex]

The roots are 2, 3, 5.

D is -30 so we get

Using the value,

[tex] \frac{2 + 3 + 5}{ 30} = \frac{1}{3} [/tex]

If we use the orginal equation, we get

[tex] \frac{1}{6} + \frac{1}{10} + \frac{1}{15} = \frac{10}{30} = \frac{1}{3} [/tex]

Answer:

Hey,mate

Notice that leading xoeffeicent will be 1, so the roots will multiply to

The roots are 2, 3, 5.

[tex]\sqrt{2} \sqrt{3} \sqrt{5}[/tex]

D is -30

Mr. Wilson bought a bag of birdseed and put half of it in his bird feeder. He split the other half equally among his 4 pet birds. How much of the bag did each pet bird get?

Answers

Answer:

each pet bird got 1/8 of the bag of birdseed

Step-by-step explanation:

the easiest way to do this is to divide the bag into eighths. if you divide the bag into eighths, 4/8 of the bag, being half, goes into the bird feeder. the other 4/8 of the bag is divided among Mr. Wilson's four pet birds, leaving each bird to get 1/4 of the bag when split evenly.

hope this helps

4/9 x 5/6 simplest form

Answers

5/6 x 4/9 = 10/27 as a fraction form. The work for 5/6 times 4/9 as a fraction provides more insight of how to find what is 5/6 times 4/9 in fraction form and the different variations of such problems.

Convert km into cm
10 points available

Answers

1 kilometre = 100000 centimetres
1 kilometre = 100000 centimetre

solve pls brainliest

Answers

Answer:

63

Step-by-step explanation:

Multiply each side by 9

4y=252

Divide by 4

y=63

Answer:

y= 63

Step-by-step explanation:

The half-life of a radioactive substance is the time it takes for a quantity of the substance to decay to half of the initial amount. The half-life of the radioactive gas radon is approximately 2.8 days. The initial amount of radon used in an experiment is 74 grams. If N represents the number of grams of radon remaining t days after the start of the experiment,

Answers

Answer:

  N = 74(1/2)^(t/2.8)

Step-by-step explanation:

The exponential function expressing a half-life relation can be written ...

  amount = (initial amount) × (1/2)^(t/(half-life))

For the numbers given in this problem, this is ...

  N = 74(1/2)^(t/2.8)

__

Some folks like to express these relations in the form ...

  N  = 74e^(-kt)

In this form, the value of k is ...

  k = ln(2)/(half-life) ≈ 0.693147/2.8 ≈ 0.24755

  N = 74e^(-0.24755t)

The leg lengths of a right triangle are 14 in and 26 in. What is the length of the missing side?

Answers

Answer:

29.5

Step-by-step explanation:

14sq + 26sq = 872

sq root of 872 is 29.5

ABCD is an irregular quadrilateral. The sum of all the interior angles is 360 degrees. What is the measure of angle D?

A. 60°
B. 120°
C. 180°
D. Need more information
please hurry! first CORRECT answer gets brainliest! :)

Answers

Answer:

D. Need more information

Step-by-step explanation:

The given information is not sufficient to determine each angle measure since the quadrilateral is irregular.

It would be good to see the picture at least.

Possible options are A or B but we can't confirm without additional detals, option C can't be a correct choice as 180° represents a straight line.

A square with side length s has an area of 324 square centimeters. This equation shows the area of the square ^{s^2}is 324

Answers

Answer:

the side s is 18

Step-by-step explanation:

s=?

Area of square(A)=324

Now,

A=s²

324=s²

√(324)=s

s=18

Which of the following is an expression
A. 7x = 4
B. 7 = x = 4
C. 7 - x
D. 7n - 3 = 32

Answers

Answer:

c 7-x

Step-by-step explanation:

The enrollment at Allenton High School is expected to decrease by 5% each year.
There are currently 720 students at the high school. The following function can be used to approximate the
number of students who will be enrolled at Allenton High School in tyears from now.
ald) = 720(1 – 0.05)
A. In how many years will the high school have approximately 450 students?
Round your solution to the nearest hundredth of a year. Show your work.

Answers

Answer:

around 8 or 9 years

Step-by-step explanation:

what is the slope of line AB

Answers

Answer:

2,3

Step-by-step explanation:

you count up 2,then count over three

the half life of a radioactive substance is the time it takes for a quantity of the substance to decay to half of the initial amount . The half-life of the radioactive gas radon is approximately 3.8 days. The initial amount of radon used in an experiment is 75 grams. if N represents the number of grams of radon remaining t days after the start of the experiment,
a. Write an equation that gives N in terms of t.
b. How much gas radon approximately remains after 3.8 days?
c. approximately when will the amount of radon remaining be 10 grams?

Answers

Using an exponential function, it is found that:

a) [tex]N(t) = 75(0.5)^{\frac{t}{3.8}}[/tex]

b) 37.5 grams of the gas remains after 3.8 days.

c) The amount remaining will be of 10 grams after approximately 11 days.

What is an exponential function?

A decaying exponential function is modeled by:

[tex]A(t) = A(0)(1 - r)^t[/tex]

In which:

A(0) is the initial value.r is the decay rate, as a decimal.

Item a:

We start with 75 grams, and then work with a half-life of 3.8 days, hence the amount after t daus is given by:

[tex]N(t) = 75(0.5)^{\frac{t}{3.8}}[/tex]

Item b:

This is N when t = 3.8, hence:

[tex]N(t) = 75(0.5)^{\frac{3.8}{3.8}} = 37.5[/tex]

37.5 grams of the gas remains after 3.8 days.

Item c:

This is t for which N(t) = 10, hence:

[tex]N(t) = 75(0.5)^{\frac{t}{3.8}}[/tex]

[tex]10 = 75(0.5)^{\frac{t}{3.8}}[/tex]

[tex](0.5)^{\frac{t}{3.8}} = \frac{10}{75}[/tex]

[tex]\log{(0.5)^{\frac{t}{3.8}}} = \log{\frac{10}{75}}[/tex]

[tex]\frac{t}{3.8}\log{0.5} = \log{\frac{10}{75}}[/tex]

[tex]t = 3.8\frac{\log{\frac{10}{75}}}{\log{0.5}}[/tex]

[tex]t \approx 11[/tex]

The amount remaining will be of 10 grams after approximately 11 days.

More can be learned about exponential functions at https://brainly.com/question/25537936

Help if you understand thanks

Answers

Step-by-step explanation:

Table A represents an arithmetic sequence with a common difference d=+7.5

so for x=4, it's y³+7.5=25+7.5=32.5

for x=5, it's y⁴+7.5=32.5+7.5=40

Table B represents a geometric sequence with a common ratio r=4, so you're essentially multiplying by 4.

for x=4, y⁴=y³×4=160×4=640

for x=5, y⁵=y⁴×4=640×4=2560

solve- cbb to work it out

Answers

Answers:

➝ Hypotenuse of triangle ( a ) = 21.63 mm

➝ Hypotenuse of triangle ( b ) = 150 mm

➝ Hypotenuse of triangle ( c ) = 111.80 mm

[tex] \quad\rule{300pt}{1.5pt}\quad[/tex]

Solution:

We have to find the length of hypotenuse in the given 3 triangles, which can be done by using Pythagoras theorem.

Pythagoras theorem states that :

" In a right angled triangle, the square of hypotenuse side is equal to the sum of square of other two sides "

[tex] \qquad \bull \:{\pmb{\mathfrak{ h^2 = b^2 + p^2}}}[/tex]

And we have to convert the answer to the units indicated in red i.e, in mm.

Since 1cm = 10 mm, we will convert the given values of length of side in mm before putting the values in the formula

For triangle ( a )

[tex] :\implies\qquad \sf{ h^2 = b^2 + p^2}[/tex]

[tex] :\implies\qquad \sf{ h =\sqrt{b^2 + p^2}}[/tex]

[tex] :\implies\qquad \sf{h=\sqrt{ (12)^2 + (18)^2 }}[/tex]

[tex] :\implies\qquad \sf{ h= \sqrt{144 + 324}}[/tex]

[tex] :\implies\qquad \sf{ h = \sqrt{468}}[/tex]

[tex] :\implies\qquad\underline{\underline{\pmb{ \sf{ h = 21.63 mm}}}}[/tex]

For triangle ( b )

[tex] :\implies\qquad \sf{ h^2 = b^2 + p^2}[/tex]

[tex] :\implies\qquad \sf{h =\sqrt{b^2 + p^2} }[/tex]

[tex] :\implies\qquad \sf{ h = \sqrt{(90)^2+(120)^2}}[/tex]

[tex] :\implies\qquad \sf{ h=\sqrt{8100+14400}}[/tex]

[tex] :\implies\qquad \sf{ h =\sqrt{22500}}[/tex]

[tex] :\implies\qquad\underline{\underline{\pmb{ \sf{h = 150mm}}} }[/tex]

For triangle ( c )

[tex] :\implies\qquad \sf{h^2 = b^2 + p^2 }[/tex]

[tex] :\implies\qquad \sf{ h=\sqrt{b^2 + p^2}}[/tex]

[tex] :\implies\qquad \sf{ h =\sqrt{(100)^2)+(50)^2}}[/tex]

[tex] :\implies\qquad \sf{ h=\sqrt{10000+2500}}[/tex]

[tex] :\implies\qquad \sf{ h =\sqrt{12500}}[/tex]

[tex] :\implies\qquad \underline{\underline{\pmb{\sf{h = 111.80mm}}} }[/tex]

Answers:

Hypotenuse of triangle ( a ) = 21.63 mm

Hypotenuse of triangle ( b ) = 150 mm

Hypotenuse of triangle ( c ) = 111.80 mm

Explanation :

find the length of hypotenuse in the given 3 triangles, which can be done by using Pythagoras theorem.

[tex]h^2 = b^2 + p^2[/tex]

And we have to convert the answer to the units indicated in red i.e, in mm.

Since 1cm = 10 mm, we will convert the given values of length of side in mm before putting the values in the formula

[tex]For \: \: triangle ( a )

\qquad \sf{ h^2 = b^2 + p^2}[/tex]

[tex]\qquad \sf{ h =\sqrt{b^2 + p^2}}[/tex][tex]\qquad \sf{h=\sqrt{ (12)^2 + (18)^2 }}[/tex][tex]\qquad\sf{h=\sqrt{ (12)^2 + (18)^2 }} \\ \\ \qquad \sf{ h= \sqrt{144 + 324}} \\ \\ \qquad \sf{ h = \sqrt{468}}

\\ \\\qquad\underline{\underline{\pmb{ \sf{ h = 21.63 mm}}}} \\ \\ For \: \: triangle ( b ) \qquad \sf{ h^2 = b^2 + p^2} \\ \\ \qquad \sf{h =\sqrt{b^2 + p^2} } \\ \\ \qquad \sf{ h = \sqrt{(90)^2+(120)^2}} \\ \\ \qquad \sf{ h=\sqrt{8100+14400}} \\ \\

\qquad \sf{ h =\sqrt{22500}} \\ \\\qquad\underline{\underline{\pmb{ \sf{h = 150mm}}} } \\ \\ For \: \: triangle ( c ) \qquad \sf{h^2 = b^2 + p^2 } \\ \\ \qquad \sf{ h=\sqrt{b^2 + p^2}} \\ \\\qquad\sf{ h=\sqrt{(100)^2)+(50)^2}} \\ \\\qquad\sf{ h=\sqrt{10000+2500}} \\ \\ \qquad \sf{ h =\sqrt{12500}} \\ \\

\qquad\underline{\underline{\pmb{\sf{h = 111.80mm}}} } [/tex]

Can someone help me pls

Answers

Answer:

The angle of KLM is 50°

Step-by-step explanation:

Used protractor

Answer:

∠ KLM ≈ 33.7°

Step-by-step explanation:

using Pythagoras' identity in right triangle JKM

KM²  = JK² + JM² = 7² + 4.5² = 49 + 20.25 = 69.25 ( take square root of both sides )

KM = [tex]\sqrt{69.25}[/tex] ≈ 8.322 cm

using the sine ratio in right triangle KLM

sin KLM = [tex]\frac{opposite}{hypotenuse}[/tex] = [tex]\frac{KM}{LM}[/tex] = [tex]\frac{8.322}{15}[/tex] , then

∠ KLM = [tex]sin^{-1}[/tex] ( [tex]\frac{8.322}{15}[/tex] ) ≈ 33.7° ( to 3 significant figures )

A lifeguard fills a pool with water at a constant rate. After 1/2 hour, 1/3 of the pool is filled.

At this rate, what fraction of the pool is filled per hour?

A. 1/6 of the pool
B. 1/3 of the pool
C. 1/2 of the pool
D. 2/3 of the pool

Answers

Answer:

D

Step-by-step explanation:

1/2 hour -> 1/3 pool

multiply this by 2

1 hour -> 2/3 pool

so D 2/3 pool

The fraction of the pool that would be filled per hour at the given rate is: D. 2/3 of the pool.

What is a Constant Rate?

A constant rate can be described as a quantity that changes steadlity over time.

The rate that the pool gets filled is given as:

1/2 hr = 1/3 of the water that would be filled in the pool

1 hr would be: 1/3 × 2 = 2/3

Therefore, the fraction of the pool that would be filled per hour at the given rate is: D. 2/3 of the pool.

Learn more about rate on:

https://brainly.com/question/25184007

It is now 11:15 A.M. What time will it be in three quarters of an hour?

A) noon

B) 11:45 A.M.

C) 11:45 P.M.

D) midnigh

Answers

Answer:

Ur mom

Step-by-step explanation:

Ur mom JK here's the answer 11:45 A.M. because 15 + 15 + 15 = 45 15 is a quarter so yeah Bois is 11:45 A.M Good luck

It’s a 4 digit number. The tens are double the ones. The thousands are double the tens. The sum of the digit is 19

URGENT

Answers

the tens are double the ones: c= 2d
the thousands are double the tens:
a = 2c = 4d
the sum of the digits is 19:: a+b+c+ d = 19

Substitute for a and c to get:
4d + b + 2d + d = 19
b + 7d = 19
d=2;b=5;0=4;a=8
Ans:8542

An equilateral triangle has an area of 50 units 2. What is the length of each side?

Answers

Answer:

Length of each side of equilateral Traingle is 10.75 units

Step-by-step explanation:

Given that area of an equilateral traingle 50 square units.

Let the length of side of equilateral traingle be 'x' units. To calculate length of each side we will use the formula of area of equilateral traingle:

[tex] \: \: { \underline { \boxed{\pmb { \sf{ \purple {Area_{(equilateral \: traingle)} = \dfrac{\sqrt 3}{4} \times (Side)^2}} }}}} \\ [/tex]

By substituting the values in above formula:

[tex]~[/tex]

[tex] : \implies \sf \: \: 50 = \dfrac{ \sqrt{3} }{4} \times {(x)}^{2} \\ \\ \\ : \implies \sf \: \: {(x)}^{2} = \dfrac{50 \times 4}{ \sqrt{3} } \\ \\ \\ : \implies \sf \: \: {(x)}^{2} = \dfrac{200}{ \sqrt{3} } \\ \\ \\ : \implies \sf \: \: x = \sqrt{ \dfrac{200}{ \sqrt{3} } } \\ \\ \\ : \implies \: \: { \boxed{\pmb{ \frak{ x = 10.75 \: units }}}}\\ \\ \\ [/tex]

Hence, Length of each side of equilateral Traingle is 10.75 units

Indicate whether the two functions are equal. If the two functions are not equal, then give an element of the domain on which the two functions have different values

Answers

The function f(x) = x² and g(x) = |x|² are the same since they both give a positive value.

How to interpret the function?

From the complete information, it should be noted that the function f(x) = x² and g(x) = |x|² are the same since they both give a positive value.

Also, f(x) = x³ and g(x) = |x|³ are not equal. This is because both functions are not equal for x < 0. This can be illustrated when x = -1. In this case, f(x) = -1 and g(x) = 1.

Learn more about functions on:

https://brainly.com/question/22340031

The function f(x) = x² and g(x) = |x|² are the same since they both give a positive value.

What is the equality of the two functions?

Two functions are equal if they have the same domain and codomain and their values are the same for all elements of the domain.

The function f(x) = x² and g(x) = |x|² are the same since they both give a positive value.

Also, f(x) = x³ and g(x) = |x|³ are not equal.

This is because both functions are not equal for x < 0.

This can be illustrated when x = -1. In this case, f(x) = -1 and g(x) = 1.

Hence, the function f(x) = x² and g(x) = |x|² are the same since they both give a positive value.

Learn more about functions on:

brainly.com/question/22340031

#SPJ4

Find the side labeled x.

Answers

Answer:

4√3

Step-by-step explanation:

Hello!

This is a 30° 60° 90° because it has a 90° angle, a 30° angle, and the missing angle is 60° (sum of angles in a triangle is 180°). This triangle has special properties.

In a 30°-60°-90° triangle, the leg opposite 30° is always half the hypotenuse.

This means that the hypotenuse would be 2 times 4, or 8.

The leg opposite to 60° in a right triangle of this sort is the length of a leg multiplied by √3.

So the measure of x is 4√3.

An image is attached for your reference.

The value of side labeled x using Trigonometric ratio is  [tex]{4}{\sqrt 3}[/tex].unit.

Given:

Angle = 30

Perpendicular or opposite side= 4

Using Trigonometric ratio

tan 30 = Opposite side / Adjacent side

Substituting Opposite side= 4 and Adjacent side = 4 in above ratio

So, tan 30 = 4 / x

As, the value of tan 30 = [tex]\dfrac{1}{\sqrt 3}[/tex] then

tan 30 = 4 / x

[tex]\dfrac{1}{\sqrt 3}[/tex]  = [tex]\dfrac{4}{x}[/tex]

solving for x

x = [tex]{4}{\sqrt 3}[/tex]

Thus, the value of x is [tex]{4}{\sqrt 3}[/tex].

Learn more about Trigonometric ratio here:

https://brainly.com/question/29156330

#SPJ6

The ratio of the measures of the three angles in a triangle is 15:8:13. Find the measure of the three angles.

Answers

Answer: 75, 40, 65

Step-by-step explanation:

Let the angles measure 15x, 8x, and 13x.

Since the sum of the angles of a triangle is 180 degrees,

15x+8x+13x=180, meaning that x=5.

So, the angles are 15(5)=75 degrees, 8(5)=40 degrees, and 13(5)=65 degrees.

A water sprinkler sends water out in a circular pattern. How large is the watered area if the radius of the watering pattern is23ft ​ft?

Answers

Answer:

Step-by-step explanation:

Simply put, it is similar to finding the area of a circle.

Therefore, a=pi*r^2

a=pi*23^2

a=529pi

a=1661.9 ft^2

line d has a slope of 7/3. line e is perpendicular to line d. what is the slope of line e?

Answers

hello!

Perpendicular lines have slopes that are opposite reciprocals.

This means we take a number, flop it over, and change its sign.

Here we have the number:-

[tex]\boxed{\frac{7}{3}}[/tex]

Flop it over:-

[tex]\boxed{\frac{3}{7} }\longleftarrow\sf{the~numerator~and~denominator~switch~places}[/tex]

Change its sign:-

[tex]\boxed{-\frac{3}{7}}[/tex]

Hence, the slope of line e is:-

[tex]\bigstar{\boxed{\pmb{Slope=-\frac{3}{7}}}}[/tex]

note:-

Hope everything is clear; if you need any explanation/clarification, kindly let me know, and I will comment and/or edit my answer :)

A ________ is a set of points that extends infinitely in both directions.

Answers

Answer:

line

Step-by-step explanation:

A line is a set of points that extends infinitely in both directions.

the measures of the angles in a triangle are in a ratio 1:5:6. find the measures of the angles

Answers

Answer:

The required angles are 15, 75 and 90

Step-by-step explanation:

1x + 5x+ 6x = 180
or 12x = 180
180 ÷ 12 = 15
hence,
15, 75, 90.

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