Find the number of moles of oxygen atoms in 3.00 mol of copper(II) sulphate pentahydrate.

The pH value of 500 mL of an aqueous solution of 0.005 mole HCl is 2

We'll begin our calculations by obtaining the molarity of the solution. Details below:

Molarity = mole / volume

Molarity = 0.005 / 0.50

Molarity = 0.01 M

Next, we shall obtain the concentration of the hydrogen ion, H⁺ in the solution. Details below:

HCl(aq) <=> H⁺(aq) + Cl¯(aq)

From the balanced equation above,

1 mole of HCl contains 1 mole of H⁺

Therefore,

0.01 M HCl will also contain 0.01 M H⁺

Thus, the concentration of the hydrogen ion, H⁺ in the solution is 0.01 M

Finally, we shall determine the pH of the solution. Details below:

pH = -Log H⁺

pH = -Log 0.01

pH = 2

Thus, we can conclude that the pH of the solution is 2

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Answer:

A glove is like the earth because...

A globe is like the earth in that it is a three-dimensional representation of the earth's features, such as countries, oceans, and landmasses.

A globe is also like the earth in that it can rotate on its axis, which allows the viewer to see different parts of the earth depending on the angle of rotation.

A globe is not like the earth because...

A globe is not like the earth in that it is typically much smaller than the earth.

A globe is also not like the earth in that it does not depict the earth's relief features, such as mountains and valleys, in their true proportion to the rest of the earth's surface.

A globe is like the earth in that it is a scaled-down, spherical model of the earth's surface, representing physical features accurately. However, a globe is not like the earth because it is much smaller and does not rotate or revolve.

The globe and the earth are similar in two main ways. First, a globe is a scaled-down model of the earth, showing an accurate representation of the earth's surface. This includes physical features such as continents, oceans, and countries, which are mapped out precisely. Second, a globe is spherical, just like the earth.

However, there are differences between a globe and the earth. One key difference is the scale: the earth is far larger than any globe. The most obvious point of difference is the size: while a globe is small enough to be held in your hands or placed on a desk, the earth has a diameter of approximately 7,917.5 miles. Also, the globe is a static object, it does not rotate on its axis or revolve around the sun like the earth does.

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Answer:

623 kgm^-3

Explanation:

Density = Mass/Volume

Mass = 1209 kg

Volume = 1.94 m^3

Density = 1209 / 1.94 kgm^-3

             = 623.1958763 kgm^-3

             = 623 kgm^-3 (3sf)

The functional group of molecules as follows :

Molecule 1. is aldehyde and ketone, Molecule 2 is acid and thio, Molecule 3 is acid and amide, Molecule 4 is alcohol and ether, Molecule 5 is Alcohol and acid. The image attached below show the functional group and molecules are labeled.

The polar compounds are those compound having different positive and negative charge, therefore the bonding with atoms such as nitrogen, oxygen, or sulfur.

A buffer is a solution the can control the pH change along with the addition of an acidic or basic substance. It is able to neutralize small amounts of added acid or base, So it maintains the pH of the solution. This is important to maintain pH ranges.

Thus, Molecule 1. is aldehyde and ketone, Molecule 2 is acid and thio, Molecule 3 is acid and amide, Molecule 4 is alcohol and ether, Molecule 5 is Alcohol and acid.

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The depression in freezing point of the electrolyte is 1.6 K. The weight of the solute added is 29.5 g. Then the molar mass of the compound is obtained to be 342.93 g/mol.

Addition of a non-volatile solute into a solvent decreases the freezing point of the solution. The depression in freezing point is calculated as follows:

ΔT =  W₂ 1000 Kf / (M W₁)

where W₂ be the mass of solute and W₁ is that of solvent, Kf is called molal depression constant. M be the molar mass of the solute.

Given ΔT = 1.6 K

W₂  = 29.5 g

W₁ = 100 g

Kf of water = 1.86 K/m

Then M = W₂ 1000 Kf / ( ΔT W₁)

M = 29.5 g× 1000 × 1.86 / (1.6 K × 100 g) = 342.9 g/mol

Thus, the molar mass of the solute is 342.9 g/mol.

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In an endothermic reaction,  potential energy of products  is greater than that of the reactants. Reactants in endothermic reaction are absorbing enough heat energy to overcome this barrier potential. Hence, option  d is correct.

An endothermic reaction is the one in which heat energy is absorbed by the reactants from the surroundings. In endothermic reactions, the enthalpy change is positive.

The minimum energy that the reactants have to acquire for effective collision and reaction is called the activation energy. By absorbing heat energy reactants becomes  more energetic and overcome this activation potential.

Therefore, in an endothermic reaction, the activation potential of products will be higher than that of the reactants . Hence, option d is correct.

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Answer:

18.015

Explanation:

Using the periodic table of the elements to find atomic weights, we find that hydrogen has an atomic weight of 1, and oxygen's is 16. In order to calculate the molecular weight of one water molecule, we add the contributions from each atom; that is, 2(1) + 1(16) = 18 grams/mole.

The hybridization of C in HCN is sp because, carbon is triple bonded to the nitrogen. Hybridization of N in HCN is also sp. Hybridization of nitrogen in NH₄ is sp³.

When tow atoms combines to form a molecules, the energy of individual atomic orbitals redistribute to form  hybrid orbitals of  equivalent energy. The type of hybridization s based on the on the involvement of s, p or d orbitals of the atom.

In HCN, carbon is triple bonded to nitrogen. Here, both s and p orbital contribution is 50%. Hence, both C and N in HCN in sp hybridized.

In NH₄, the nitrogen is sigma bonded to each hydrogen and the hybridization of N is sp³ here since, 3 p orbitals of nitrogen and one s orbital are involved.

In CH₃-,  C is sp² hybridized and in CH₃⁺ , C is sp³ hybridized. The C in C(CH₃)₄ is also sp³ hybridized where carbon involves sigma bonds with the methyl groups.

N in NH₃ is sp³ hybridized. Oxygen in water is sp² hybridized. When water abstracts one more proton forming H₃O⁺ , oxygen forms sp³ hybridized orbitals.

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Cathode: 2 Ag+ (aq) + 2 e- → 2 Ag (s). Anode: 2 H+ (aq) → H2 (g) + 2 e-.

What is cathode ?

A cathode is an electrode in an electrical circuit from which electrons flow out. It is usually made of metal and is negatively charged. Cathodes are commonly used in electronic devices such as batteries, lamps, and vacuum tubes. In a battery,

the cathode is the terminal which provides a negative charge and is usually connected to the negative terminal of the battery. In a vacuum tube, the cathode is the source of electrons which flow through the tube to the anode, which is the positive terminal.

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The volume of the metal block can be calculated using the density and mass of the block is 30.0 cm³

A metal block is a solid piece of metal that is typically used for machining and other industrial applications. It is usually made from aluminum, steel, or other metals, and can be machined into a variety of shapes and sizes depending on the application. Metal blocks are also used for casting, forging, and other manufacturing processes. Metal blocks may also be used for decorative purposes, such as sculpture or engraving. They are also used in jewelry making and engraving, as well as in medical and dental applications.

The volume of the metal block can be calculated using the density and mass of the block:
Volume = Mass/Density = 223.1 g/7.41 g/cm³ = 30.0 cm³
Since the metal block was submerged in the water, the volume of the block will be added to the volume of water in the beaker. Therefore, the original water level in the beaker can be calculated using the following equation:
Original Water Level = 150 mL + (30.0 cm³/1000 cm³/mL) = 180.0 mL

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The limiting reactant would be calcium and the amount of product that can be made would be 7.14 grams.

Calcium reacts with oxygen to form calcium oxide according to the following balanced equation:

[tex]2Ca + O_2 --- > 2CaO[/tex]

In other words, the mole ratio of Ca to O is 2:1.

Mole of 35.1 g Ca = 35.1/40 = 0.1275

Mole of 37.1 g O = 37.1/16 = 2.3188

This means that oxygen is in excess while Ca is the limiting reagent.

The mole ratio of Ca to CaO is 1:1, thus the equivalent amount of CaO that will be produced will also be 0.1275 moles.

Mass of 0.1275 moles CaO = 0.1275 x 56 = 7.14 grams

In other words, the limiting reactant of the reaction is calcium while the amount of the product that can be made is 7.14 grams.

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To solve this we must be knowing each and every concept related to tautomerization. Therefore, out of keto and enol form, keto form is mot stable.

Tautomers are two structural isomers that are readily inconvertible and vary in the relative locations of their atoms while being in dynamic equilibrium. Tautomers essentially function as structural isomers.

Tautomerization is the term used to describe the tautomerization phenomena. Tautomerization includes the exchange of protons and electrons between molecules. Out of keto and enol form, keto form is mot stable.

Therefore, out of keto and enol form, keto form is mot stable.

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The new volume of the gas will be 1.85L.

According to Boyle's Law, as pressure lowers, gas volume grows. According to Charles' Law, when the temperature rises, the volume of the gas also rises. Avogadro's Law also states that as the amount of gas increases, so does the volume of the gas.

Given, initial volume of gas V1 = 2L

initial temp T1 = 273K

initial pressure P1 = 101.3 kPa

final temperature, T2 = 500K

Final pressure, P2 = 200 kPa

let final or new volume be V,

now for a constant moles of gas,

by using ideal gas equation,

P1×V1/T1 = P2×V/T2

101.3×2/273 = 200×V/500

202.6/273 = 2V/5

V = 0.742×5/2

V = 1.85 L

The new volume of the gas will be 1.85L.

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There is a golden rule of solubility, non polar solute dissolve in non polar solvent and polar solute dissolve in polar solvent. Therefore, the correct option is option B.

Solution is a homogeneous mixture of two or more than two substances. A solution is a homogeneous mixture of solute and solvent molecules. Solvent is a substance that is in large amount in solution. solute is the substance which is in small amount in a solution.

There are two types of mixture that is homogeneous and heterogeneous. Solution is a homogeneous solution. The nature of solvent tells about whether the solvent is in liquid, solid or gas form.

Let amount of 30% to mix, be X

Then amount of 18% to mix = 300 - X

0.3X + 0.18(300 - X) = 0.21(300)

0.3X+ 0.18(300) - 0.18X= 0.21(300)

0.3X - 0.18X =0 .21(300) -0 .18(300)

0.12X =0 .03(300)

X=75L

Therefore, the correct option is option B.

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A bond between 2 atoms as being covalent an electronegativity difference of greater than 1.7 between the atoms.

Bond is a debt instrument, which is issued by governments and corporations. These bonds are used to raise capital for various projects and investments. Bonds are a form of loan and investors are usually paid a fixed interest rate for lending their money. Bonds are typically issued for a fixed period of time, usually for a period of 5-30 years, and have a fixed maturity date. Investors receive interest payments at regular intervals and receive the principal amount of the bond at the end of the period.

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Answer:

To determine the volume of the solution in milliliters, we need to know the mass of CuNO3 and the concentration of the solution.

Given that 3.38g of CuNO3 is dissolved in water to make a 0.220 M solution, we can use the following formula to calculate the volume of the solution:

Volume = (Mass of CuNO3) / (Concentration of solution)

Plugging in the given values, we have:

Volume = (3.38 g) / (0.220 M)

Converting the mass to grams and the concentration to moles/liter, we have:

Volume = (3.38 g) / (0.220 mol/L)

Calculating, we find that the volume of the solution is approximately 15.36 liters.

To convert the volume to milliliters, we can multiply the volume in liters by 1000. In this case, the volume in milliliters is 15,360 ml.

Therefore, the volume of the solution in milliliters is approximately 15,360 ml.

Explanation:

Answer:

The ion-electron method involves breaking the reactants into their component ions and transferring electrons between the ions to balance the charge and the atoms. In a basic solution, the S²⁰⁸² ion will gain two electrons to form SO₂. The I¹⁻ ion will lose one electron to form I³⁻. The balanced redox equation using the ion-electron method is:

S²⁰⁸² + 2e⁻ + 2OH⁻ → SO₂ + H₂O

I¹⁻ + e⁻ → I³⁻

The overall balanced equation is:

2S²⁰⁸² + 2OH⁻ + I¹⁻ → 2I³⁻ + SO₂ + H₂O

Answer:

Explanation:

Given pinene has a (temperature, vapor pressure) relation (K, torr) = {(373, 135), (429, 760)}, you want the heat of vaporization in kJ/mol and the vapor pressure at room temperature (23 °C).

The Clausius–Clapeyron equation can be used to find the heat of vaporization:

  [tex]\ln{P}=-\dfrac{\Delta H_{\text{vap}}}{R}\left(\dfrac{1}{T}\right)+C[/tex]

Solving for ∆H, we find ...

  [tex]\Delta H_{\text{vap}}=-\dfrac{R\cdot\ln{\dfrac{P_1}{P_2}}}{\dfrac{1}{T_1}-\dfrac{1}{T_2}}\\\\\\\Delta H_{\text{vap}}=-\dfrac{8.314\cdot\ln{\dfrac{760}{135}}}{\dfrac{1}{429}-\dfrac{1}{373}}\approx 41052.8[/tex]

The heat of vaporization of pinene is about 41 kJ/mol.

Rearranging the above equation to give P1, we have ...

  [tex]\ln{\dfrac{P_1}{P_2}}=-\dfrac{\Delta H_\text{vap}}{R}\left(\dfrac{1}{T_1}-\dfrac{1}{T_2}\right) \\\\\\P_1=P_2\cdot e^{-\frac{\Delta H_\text{vap}}{R}\left(T_1^{-1}-T_2^{-1})}[/tex]

Using the same P2 and T2 as above, we find the vapor pressure at room temperature (296.15 K) to be ...

  P1 ≈ 4.349 . . . . . torr

The vapor pressure of pinene at room temperature is about 4 torr.

Answer: A balanced chemical reaction is A balanced chemical equation where the number of atoms of each type in the response is the same on both reactants and product sides.

Explanation: Burning, and cooking are 2 examples.

(2)(½^(15/3)) = 0.0625 (5 half-lives) 102.4 grams order

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Sublevels are indicated by letters s, p, d, and f.

How do write Electronic configuration?

Electron configurations have a standard notation that tells you the principle energy levels and sublevels that electrons occupy. here is Sulphur:

The atomic number of Sulphur is 16.

the electronic configuration of Sulphur is 1s2 2s2 2p6 3s2 3p4.

The 4s sublevel has lower energy than the 3d sublevel,

so, it fills next.

One orbital can house a maximum of two electrons, and there are four different types of orbitals (s, p, d, and f). More electrons can be held in the p, d, and f orbitals since they contain various sublevels. According to its location on the periodic table, each element's electron configuration is distinct.

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Answer:

oxygen-16 is a stable isotope of oxygen, having 8 neutrons and 8 protons in its nucleus. It has a mass of 15. u

Answer:

polymer mear least receptive to dye

,

Answer:

Electrons

Explanation:

"An electron is a negatively charged particle that orbits the nucleus of an atom."

"Electrons are negatively charged particles arranged in orbits around the nucleus of an atom"

The molecular weight of [tex](NH_4)_2SO_4[/tex] would be 132 g/mol.

The molecular weight, otherwise known as the molar mass of substances is the sum of the molar weights of individual atoms that make up the substance.

[tex](NH_4)_2SO_4[/tex] is made up of 2 atoms of N, 8 atoms of H, 1 atom of S, and 4 atoms of O.

Thus, the molecular weight of [tex](NH_4)_2SO_4[/tex] = (14x2) + (1x8) + 32 + (16x4)

                                                                     = 132 g/mol

In other words, the molecular weight of [tex](NH_4)_2SO_4[/tex] is 132 g/mol.

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The value of enthalpy(ΔHº) for the final reaction (2C(s) + H₂(g) → C₂H₂(g) ) is  -1932.8KJ.

A system's enthalpy is its heat capacity. A reaction's enthalpy change is roughly equivalent to how much energy is lost or gained throughout the reaction. If the enthalpy of the system decreases over the reaction, the reaction is preferred.

C(s) + O₂(g) → CO₂(g) ΔHº = -94.6 kJ --- (1)

H₂(g) + O₂(g) → H₂O(l) ΔHº = -286.0 kJ ---(2)

2C₂H₂(g) + 5O₂(g) → 4CO₂(g) + 2H₂O (l)  ΔHº = -2598.8 kJ ---(3)

The value of ΔHº for the final reaction,

2C(s) + H₂(g) → C₂H₂(g)

ΔH₄° = 2× ΔH₂º +  ΔH₃º - ΔH₁º
ΔH₄° = 2× -286.0 + ( -2598.8) - (- 94.6)

ΔH₄° = 2× -286.0 -2598.8 + 94.6

ΔH₄° = 666 - 2598.8

ΔH₄° = -1932.8KJ.

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The relationship between the calculated concentration of a material and the actual concentration of particles is known as the Van't Hoff factor.

I is the difference between a typical or theoretical colligative quality and an observable one.

The van 't Hoff factor is the difference between the concentration of a material determined by its mass and the concentration of particles actually formed when the substance is dissolved. The van 't Hoff factor is virtually 1 for the majority of non-electrolytes dissolved in water.

For dissociation, association, and the non-electrolyte solute, the Van't Hoff factor value is more than one, less than one, and equal to one respectively.

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