for r = 300.0 kω and c = 600.0 μf, what is the time constant? give the magnitude with the correct mks units. the time constnat is _____ units.

Answer:

The final temperature is [tex]29.6^oC[/tex].

Explanation:

When the two masses come in contact, one releases heat and the other absorbs it. The former can be modelled with the equation [tex]HeatLost = (Mass1 (kg))(c1)(T1-T)[/tex], and the latter by [tex]HeatGained=(Mass2(kg))(c2)(T-T2)[/tex]

m1=0.15 kg

m2=0.06 kg

T1 = 70 degrees Celsius = 343 K

T2 =  20 degrees Celsius = 293 K

T= Final temperature

c1 = Specific heat capacity of copper

c2 = Specific heat capacity of water

Because there is no heat lost into the surroundings, the heat removed from one substance is the same as the heat gained in the other. Therefore:

[tex](Mass1)(c1)(T1-T)=(Mass2)(c2)(T-T2)[/tex]

[tex](0.150)(400)(343-T)=(0.06)(4184)(T-293)[/tex]

[tex](60)(343-T)=(251.04)(T-293)[/tex]

[tex]20580-60T=251.04T-73554.72[/tex]

[tex]-311.04T=-94134.72[/tex]

[tex]T=302.6 K[/tex]

[tex]T=29.6^oC[/tex]

Hope this helps! (My apologies if the answer is wrong, it has been a while since I've done this)

Answer:

the rock will probably sink in water because density of rock heavier than the density of water.

Density of water=1g/cm

density of rock=1.73g/cm

1g/cm< 1.73g/cm

Answer:

a whole new glacier will start because the other one is melting

The speed of the airplane, v is 144.2 m/s

The height, H of the roof above the head of the man is 66.4 m.

The speed of the airplane is determined using the Pythagoras theorem.

The speed of the airplane, v is calculated as follows:

v = √(80² + 120²0

v = 144.2 m/s

The height, H of the roof above the head of the man is calculated as follows:

tan 38° = H/85

H = tan 38° * 85 m

H = 66.4 m

In conclusion, the tangent ratio is used to find the height of the roof above the head of the man.

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Answer:

5.1 The DNA double helix is the most recognizable nucleic acid structure, but these are ribozymes.

It starts fusing hydrogen in a shell around a helium core

Eventually, a star will run out of hydrogen fuel in its core, nuclear fusion will stop, and the star will enter a new stage of its lifetime.

Faster hydrogen burning means the star will grow larger and more luminous to allow the extra energy created to escape but since the temperature of the core remains constant the star's surface temperature will drop.

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It takes four times the work and four times the stopping distance.

Given:

original speed of car = x

brakes applied so final speed = 0

moving speed of another car = 2x

To Find:

work done to stop the car

Solution: Work is done whenever a force moves something over a distance. You can calculate the energy transferred, or work done, by multiplying the force by the distance moved in the direction of the force.

Work done is given by

W = KE(final) - KE(initial)

W = 1/2m(v)^2 - 1/2m(u)^2

W = 1/2m(0 - (x)^2)

W = 1/2m(4x^2)

W = 4(1/2mx^2)

W = 4W

So, work done will be 4 times initial work

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In the NEC Code, 210.8 indicates article 210, section 8 and is denoted as option A.

This is referred to the standards which are required for the safe installation of electric wires and equipment in USA.

This comprises of several articles covering different topics and sections which gives it a more elaborate meaning and understanding.

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The X and Y components are as follows;

1. X = 35 * cos 57 = 19. 1m/s; Y = 35 * sin 57 = 29.4 m/s

2. X = 12 * -cos 34  = -10 m/s; Y = 12 * -sin 34 = -6.7 m/s

3. X = 8 * -cos 90  = 0 m/s; Y = 12 -sin 90 = -8 m/s

4. X = 20 * cos 75 = 5. 2m/s; Y = 20 * (-sin 75) =  -19.3 m/s

The horizontal and vertical components of the velocities are given as follows:

1. 35 m/s at  57° from x-axis

X = 35 * cos 57 = 19. 1m/s

Y = 35 * sin 57 = 29.4 m/s

2. 12m/s at 34° S of W

X = 12 * -cos 34  = -10 m/s

Y = 12 * -sin 34 = -6.7 m/s

3. 8 m/s at South

X = 8 * -cos 90  = 0 m/s

Y = 12 -sin 90 = -8 m/s

4. 20 m/s at  275° from x-axis

X = 20 * cos 75 = 5. 2m/s

Y = 20 * (-sin 75) =  -19.3 m/s

In conclusion, the X and Y components are found by taking cosines and sine of the angles.

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The work done in moving the chair from x = 2.4 to x = 4.1 ft using a force of F = 13 lbs is 29.98 J

This is simply defined as the product of force and distance moved in the direction of the force. Mathematically, it can be expressed as

Workdone (Wd) = force (F) × distance (d)

Wd = Fd

1 lb = 4.45 N

Therefore,

13 lbs = 13 × 4.45

13 lbs = 57.85 N

1 ft = 0.3048 m

Therefore,

1.7 ft = 1.7 × 0.3048

1.7 ft = 0.51816 m

Wd = Fd

Wd = 57.85 × 0.51816

Workdone = 29.98 J

Thus, the workdone in moving the chair is 29.98 J

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Power require in Watts is 50 watts

Given:

Force = 30 N

Distance = 100m

Time for which force applied = 1 min = 60 sec

To Find:

Power

Solution: A watt is a unit of power. It is the amount of energy an item needs to function; the rate at which energy is consumed. One watt is equivalent to electricity flowing at a rate of one joule (unit of energy) per second

P = W/t

where W is work done by force and t is the time for which force is applied

W = F x d

W = 30 x 100 = 3000

P = 3000/60 = 50 watts

So Power require in Watts is 50 watts

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Answer:

A speed is a scalar quantity because it only has magnitude.

Answer:

what is electronic configuration

The solution is (v, u) = (- 585.709, 593,034). Please notice that the value of v only means that the direction of the real vector is antiparallel to the supposed one.

According to the definition of vector sum and vectors in rectangular form, we must solve the following vector equation:

(0, 0) = 205 · (cos 23°, - sin 23°) + v · (- cos 75°, sin 75°) + u · (- cos 55°, - sin 55°)

(0, 0) = (188.703, 80.100) + v · (- 0.259, 0.966) + u · (- 0.574, 0.819)

(- 188.703, - 80.100) =  v · (- 0.259, 0.966) + u · (- 0.574, 0.819)

Then, we must solve the following system of linear equations:

- 0.259 · v - 0.574 · u = - 188.703

0.966 · v + 0.819 · u = - 80.100

The solution is (v, u) = (- 585.709, 593,034). Please notice that the value of v only means that the direction of the real vector is antiparallel to the supposed one.

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Answer:

KE = 1/2 M v^2

KE = 60/2 * 25^2 = 18750 Joules         initial Kinetic Energy

W = Fs * d        distance thru which friction acts

d = W / Fs = 18750 J / 50 N = 375 m

The work done by the force is 140 J.

Calculation:

It is given that, an 80-N crate is pushed a distance of 5.0 m upward along a smooth incline that makes an angle of [tex]30^\circ[/tex] with the horizontal. The force pushing the crate is parallel to the slope and the acceleration is 1.5 [tex]\text{ m/s}^2[/tex].

It is required to find the work done by the force.

The free-body diagram is shown below,

Here, W=80 N, a=-1.5 [tex]\text{ m/s}^2[/tex]

We can write the net force equation as,

[tex]\begin{gathered}F-W \sin 30^{\circ}=m a \\F-m g \sin 30^{\circ}=\left(\frac{W}{g}\right) a\end{gathered}[/tex]

Here W is the weight of the object, m is the mass of the body, and F is the applied force.

Thus,

[tex]\begin{aligned}F-(80 \mathrm{~N}) \sin 30^{\circ} &=\left(\frac{80 \mathrm{~N}}{9.8 \mathrm{~m} / \mathrm{s}^{2}}\right)\left(-1.5 \mathrm{~m} / \mathrm{s}^{2}\right) \\F &=27.755 \mathrm{~N}\end{aligned}[/tex]

It is known that the work done by the force is calculated as the multiplication of the applied force and the displacement.

Thus the work one is,

[tex]\begin{aligned}W &=(27.755 \mathrm{~N})(5 \mathrm{~m}) \\& \approx 140 \mathrm{~J}\end{aligned}[/tex]

Thus the last option is the correct one.

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Answer: d) income only includes salary

Explanation:

i just took a test for economics and personal finance and got it correct

The statement that "Income only includes salary " is not true.

Income is the money that an individual or organization receives in return for their services or goods. 

Depending on the context—such as taxation, financial accounting, or economic analysis—income may have a variety of definitions.

For the majority of people, their total earnings include their wages and salaries, investment returns, pension payments, and other receipts. 

For businesses, income refers to the money made from selling goods and services as well as any interest or dividends paid on the company's cash holdings and reserves.

So, the amount of money, property, and other value transfers received over a predetermined period in return for goods or services is often referred to as "income."

That's why income does not include only salary.

Hence Statement (D) about the income is not true.

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Answer:

As the plane moves toward the listener, the apparent frequency of the plane would be [tex]4250\; {\rm Hz}[/tex] ([tex]2250\; {\rm Hz}[/tex] higher than the frequency at the source.)

As the plane moves away from the listener, the apparent frequency of the plane would be approximately [tex]1308\; {\rm Hz}[/tex] (approximately [tex]692\; {\rm Hz}[/tex] lower than the frequency at the source.)

Assumption: the speed of sound in the air is [tex]340\; {\rm m\cdot s^{-1}}[/tex].

Explanation:

Crests of this sound wave travel toward the listener at a constant [tex]v = 340\; {\rm m\cdot s^{-1}}[/tex]. Since there is a pause of [tex]t = 1 / f = (1/2000)\; {\rm s}[/tex] between every two consecutive crests of this sound wave, the distance between each pair of consecutive crests would be:

[tex]\begin{aligned}\lambda &= \frac{v}{f} \\ &= \frac{340\; {\rm m \cdot s^{-1}}}{2000\; {\rm s^{-1}}} \\ &= 0.17\; {\rm m} \end{aligned}[/tex].

Hence, if the aircraft wasn't moving, the first crest would have a head start of [tex]\lambda = 0.17\; {\rm m}[/tex] relative to the second one. This head start would ensure that the first crest arrive [tex]t = \lambda / v = 0.17\; {\rm m} / (340\; {\rm m \cdot s^{-1}}) = (1/2000)\; {\rm s}[/tex] earlier than the second crest.  

However, at a speed of [tex]v_{\text{s}} = 180\; {\rm m\cdot s^{-1}}[/tex], the aircraft would have travelled an additional [tex]v_\text{s}\, t = 180\; {\rm m\cdot s^{-1}} \times (1/2000)\; {\rm s} = 0.09\; {\rm m}[/tex] within that [tex]t = (1 / 2000)\; {\rm s}[/tex].

In other words, if the aircraft was moving towards the listener, the period of the sound would appear to the listener to be approximately [tex]0.000235\; {\rm s}[/tex]. in contrast, if the aircraft was moving away from the listener, the period of the sound would appear to the listener as approximately [tex]0.000765\; {\rm s}[/tex].

Therefore:

Answer:

[tex]\huge\boxed{\sf v = 448\ m/s}[/tex]

Explanation:

Frequency = f = 16 Hz

Wavelength = λ = 28 m

Speed = v = ?

v = fλ

Put the givens.

v = (16)(28)

v = 448 m/s

[tex]\rule[225]{225}{2}[/tex]

The ray will not emerge into the air medium from glass medium.

To find the answer, we need to know about the critical angle.

Thus, we can conclude that the light will not emerge into air medium.

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OPTION (C) IS CORRECT

ANSWER - UNIFORM MOTION

If there is no change in the velocity of the object then it is known to be in UNIFORM MOTION.

EXPLORE MORE:-

EXAMPLE - A CAR COVERS A DISTANCE OF 15 KM WE'D EVERY 2 HOURS

FOR AN UNIFORM MOTION, ACCELERATION IS ZERO , AS THERE IS NO CHANGE IN VELOCITY....

-THANKS.!!

The velocity of the object s calculated as 22.1 m/s.

Given that we can write that;

v^2 = u^2 + 2gh

Now u = 0 m/s because the object was dropped from a height

v^2 = 2gh

v = √2 * 9.8 * 25

v = 22.1 m/s

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Nuclear decay results in the change in the mass number of a nucleus. In precise it is alpha decay.

The process through which an unstable atomic nucleus loses energy through radiation is known as radioactive decay, also known as nuclear decay, radioactivity, radioactive disintegration, or nuclear disintegration.

How is mass number of nucleus is changed by alpha decay?

When a nucleus emits an alpha particle, these changes happen:

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When the north-pole end of a bar magnet is held near a stationary positively charged piece of plastic, it remains unaffected.

What is a bar magnet?

A bar magnet is made of ferromagnetic substance that produces

magnetic field.

What are the properties of a bar magnet?

Since plastic is not a ferromagnetic material or any other material like gold and silver ,they remain unaffected in the presence of magnetic field.

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   After impact velocity = 14.968 ft/s

Weight and mass of Bullet and wooden block:

Bullet: w = 1oz = 1/16 lb m = 0.001941 lb

wooden block : W = 5lb M = 0.15528 lb

velocity of block and bullet immediately after impact:

Σmv1 + ΣImp = mv2

Resolving vertical component

( m× v₀cos30⁰) + 0 = ( m+M) v'

v' = ( m× v₀cos30⁰)/ (m+M)

v' = 14.968 ft/s

Horizontal and vertical component of the impulse exerted by block on the bullet:

   Here we will apply the principle of impulse and momentum.

 Horizontal component:

          -mv₀ cos30⁰ + RxΔt  =0

                                 RxΔt = mv₀sin30⁰

                                          = 0.001941 × 1400sin30⁰

                                   RxΔt = 1.3587 lb.s

         Vertical component:

                           -mv₀cos30⁰  + RyΔt =  -mv'

                                     RyΔt = m( v₀cos30⁰-v')

                                     RyΔt = 0.001941(1400cos30⁰ - 14.968)

                                              = 2.32 lb.s

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Astronomers explain the energetic jets that come out of quasars and active galactic nuclei(AGN) in opposite directions in a way that the supermassive black holes' chaotic accretion discs "spit out" jets in directions perpendicular to the disc.

Quasar : A supermassive black hole with a mass between millions and tens of billions of solar masses that is fueled by an extraordinarily bright active galactic nucleus (AGN) and encircled by a gaseous accretion disc is known as a quasar.

An active galactic nucleus (AGN) is a compact area at the Centre of a galaxy that exhibits features that indicate the luminosity is not coming from stars and is substantially brighter than usual over at least some of the electromagnetic spectrum.

Hence, astronomers propose that the chaotic accretion discs of supermassive black holes "spit out" jets in directions perpendicular to the disc, explaining the intense jets that emerge from quasars and active galactic nuclei in different directions.

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Answer: Plane-polarized light is incident on a single polarizing disk with the direction of E0 parallel to the direction of the transmission axis. Through angle [tex]\alpha=cos^-1(\sqrt{\frac{1}{n} })[/tex] should the disk be rotated so that the intensity in the transmitted beam is reduced by a factor of n .

Explanation: To find the correct answer, we need more clarifications about the Malu's law.

                                 [tex]I=I_0cos^2\alpha[/tex]

where, [tex]I_0[/tex] is the maximum intensity of transmitted light.

                                            [tex]I=I_0cos^2\alpha[/tex]

                                 [tex]\alpha =cos^-1\sqrt{(\frac{I}{I_0}} )=cos^-1\sqrt{\frac{I}{nI} } \\\alpha =cos^-1\sqrt{\frac{1}{n} }[/tex]

Thus, we can conclude that, the value of angle alpha, so that the intensity in the transmitted beam is reduced by a factor of n will be,

                                 [tex]\alpha=cos^-1(\sqrt{\frac{1}{n} })[/tex] .

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you can use the graph to estimate the value of x when y is required to start a doubles match with the sun and the sky very well from her childhood and a kind young women who lives with her wearing a black and a veil and shows to be in that position or they have a bad past or bad life that they want to take revenge on every one by murder goes on by them in the streets of St and St Mary's Church and its followers are known as Sikhs and the other children claim she

Answer:

Under the reasonable assumption that the brick has more mass than the feather, the brick experiences a greater force of air friction.

Explanation:

Objects at terminal velocity, only under the influence of gravity, have maximized their speed and have an acceleration of zero.  Thus, neither object is accelerating.

Recall Newton's second law: [tex]\sum {\vec {F}}=m \vec {a}[/tex]

Since acceleration for each object is zero, the sum of the force acting on each of those objects must also be zero.

Since the only forces acting on the objects are gravity and the force of air friction, in order to zero out, the force of air friction must be equal in magnitude and opposite in direction to the force of gravity.

Recall that near the surface of the earth, [tex]F_{gravity}=mg[/tex], so the Force of Gravity acting on an object is directly proportional to the object's mass.  (A similar argument could be made even if this were not taking place on the surface of the earth, so long as the objects were the same distance from the object providing gravitational influence).

If the masses of the objects are different, the object with the greater mass will experience a larger force of gravity, and hence a larger force of air friction at terminal velocity.  

Under the reasonable assumption that the brick has more mass than the feather, the brick experiences a greater force of air friction.

Dead space is the name of the air in the conducting zone that is not available for gas exchange.

What is conducting zone?

The conducting zone consists of all of the structures that provide passageways for air to travel into and out of the lungs.

The volume of air that is inhaled that does not take part in the gas exchange is dead space. Because it either remains in the conducting airways or reaches alveoli that are not perfused or poorly perfused.

Dead space volume is air in the conducting airways that does not participate in gas exchange between the alveoli and blood.

Hence,

Dead space is the name of the air in the conducting zone that is not available for gas exchange.

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