HELP I NEED TO PASS!!!!!

A. g(x) = 2x-1
B. g(x) = 2x + 1
C. g(x) = 2x –1
D. g(x) = 2x+1

Answer: x^2+12=x+4

Step-by-step explanation:

Answer:

We can conclude that her walking speed is 2.1 miles per hour.

Step-by-step explanation:

We have the relation:

Speed = distance/time.

Here we know:

She walked for 44 miles.

And she ran along the same route, so she ran for 44 miles.

The total time of travel is 22 hours, so if she ran for a time T, and she walked for a time T', we must have:

T + T' = 22 hours.

If we define: S = speed runing

                     S' = speed walking

Then we know that:

"and she ran 33 miles per hour faster than she walked."

Then:

S = S' + 33mi/h

Then we have four equations:

S'*T' = 44 mi

S*T = 44 mi

S = S' + 33mi/h

T + T' = 22 h

We want to find the value of S', the speed walking.

To solve this we should start by isolating one of the variables in one of the equations.

We can see that S is already isoalted in the third equation, so we can replace that in the other equations where we have the variable S, so now we will get:

S'*T' = 44mi

(S' + 33mi/H)*T = 44mi

T + T' = 22h

Now let's isolate another variable in one of the equations, for example we can isolate T in the third equation to get:

T = 22h - T'

if we replace that in the other equations we get:

S'*T' = 44mi

(S' + 33mi/h)*(  22h - T') = 44 mi

Now we can isolate T' in the first equation to get:

T' = 44mi/S'

And replace that in the other equation so we get:

(S' + 33mi/h)*(  22h -44mi/S' ) = 44 mi

Now we can solve this for S'

22h*S' + (33mi/h)*22h + S'*(-44mi/S')  + 33mi/h*(-44mi/S') = 44mi

22h*S' + 726mi - 44mi - (1,452 mi^2/h)/S' = 44mi

If we multiply both sides by S' we get:

22h*S'^2 + (726mi - 44mi)*S' - (1,425 mi^2/h) = 44mi*S'

We can simplify this to get:

22h*S'^2 + (726mi - 44mi - 44mi)*S' - (1,425 mi^2/h) = 0

22h*S'^2 + (628mi)*S' - ( 1,425 mi^2/h) = 0

This is just a quadratic equation, the solutions for S' are given by the Bhaskara's equation:

[tex]S' = \frac{-628mi \pm \sqrt{(628mi)^2 - 4*(22h)*(1,425 mi^2/h)} }{2*22h} \\S' = \frac{-628mi \pm 721 mi }{44h}[/tex]

Then the two solutions are:

S' = (-628mi - 721mi)/44h = -30.66 mi/h

But this is a negative speed, so this has no real meaning, and we can discard this solution.

The other solution is:

S' = (-628mi + 721mi)/44h = 2.1 mi/h

We can conclude that her walking speed is 2.1 miles per hour.

Answer:

1.333333333333

Step-by-step explanation:

Answer:

£70.00

Step-by-step explanation:

You basically want to find what she spent in total, then subtract the amount she spent on ingredients.

50 glasses of lemonade at £2.10 each would be £105. (50*2.1)

Subtract the cost of ingredients, which is £35, with the total she made, £105, to get £70 (105-35)

Answer:

Step-by-step explanation:

I don't know what the answer is if I am not given choices, but here is one possibility.

2(x^2 - 12x - 7)

You could factor what is inside the brackets.

2(x - 12.557) (x + 0.557)

Answer:

Step-by-step explanation:

since it is in the form of quadration equation , we can use quadratic formula . In quadratic equation we get the two values of x . one will be positive and another will be negative.

Answer:

4:15 p.m.

Step-by-step explanation:

There's something missing in this:

Once it started, the movie lasted for 1 hour and minutes. What time was it when the movie ended?

What is the minutes because thats missing.

Also can I get Brainliest please

Answer:10.25-r= hourly rate

Step-by-step explanation:

Answer:

X=-2,-1,0,1,2,3,4,5,6,

Step-by-step explanation:

IF 8 IS LARGER THAN -3 YOU COULD GET THE FOLLOWING ANSWER

Answer:

x>5

Step-by-step explanation:

move -8 to the right side, change the sign and solve:

x > - 3 + 8

x > 5

Answer:

frist answer is

6080

second answer is 72 square yard

Answer:

Step-by-step explanation:

Intervals are always x values. When x = 5, y = 4 (look at the graph to se this); when x = 6, y = 2. The rate of change is the same thing as the slope. We can't get an exact slope here because this isn't a straight line, but we can find the average rate of change. We use the slope formula to do this: with the coordinates (5, 4) and (6, 2):

[tex]m=\frac{2-4}{6-5}=\frac{-2}{1}=-2[/tex]. Third choice down is the one you want.

Answer:

5 units

Step-by-step explanation:

Center of the circle = (-3, 2)

Point on the circle = (1, 5)

Radius of the circle will be equal to the distance between the points (-3, 2) & (1, 5)

[tex] \therefore \: radius \: of \: the \: circle \\ = \sqrt{ {( - 3 - 1)}^{2} + {(2 - 5)}^{2} } \\ = \sqrt{ {( - 4)}^{2} + {( - 3)}^{2} } \\ = \sqrt{16 + 9} \\ = \sqrt{25} \\ \therefore \: radius \: of \: the \: circle = 5 \: units[/tex]

Step-by-step explanation:

a=16

r=3

48/16=3

144/16=3

6th term

=ar^(n-1)

= 16(3)^(6-1)

=3888

Answer:

2/8 because each 1/4 0f the 8 slices is equal to 2/8 by multipliction or you can say 1/4 of 8

Answer:

2/8

Step-by-step explanation:

1/4

times everything by 2 as 8 / 4 = 2

2/8

Answer:

Step-by-step explanation:

Let Terri spent the 'x' hours in the river,

Per hour rental charged by Timmy's Tubes = [tex]\frac{\text{Rental charged}}{\text{Hours spent}}[/tex]

                                                                        = [tex]\frac{18.75}{2.5}[/tex]

                                                                        = $7.5

Charges for 'x' hours = $7.5x

Therefore, function that defines the rental of Timmy's tube will be,

f(x) = 7.5x

Another company Fred's float charges a base fee $2 plus $6.25 per hours.

For 'x' hours Fred's float will charge = 6.25x + 2

And the function that defines the charges will be,

g(x) = 6.25x + 2

1). If x = 1.5 hours,

Rental charged by Timmy's tube,

f(1.5) = 7.5(1.5)

        = $11.25

Rental charged by Fred's float,

g(1.5) = 6.25(1.5) + 2

         = $11.375

2). If Terri has $12 to spend,

For f(x) = 12,

12 = 7.5x

x = 1.6 hours

For g(x) = 12

12 = 6.25x + 2

10 = 6.25x

x = 1.6 hours

Therefore, both the companies charge the same for 1.6 hors.

Terri can opt any company to spend $12.

Work Shown:

area of the triangle on the left = base*height/2 = 0.75*2/2 = 0.75

area of the triangle on the right = base*height/2 = 0.5*4/2 = 1

total area = 0.75+1 = 1.75 square feet

Answer:

8 3 -2 -7

Step-by-step explanation:

becoz the y values are the ranges of the function

Answer:

{y: y = –7, –2, 3, 8}

Answer:

HI=15

Step-by-step explanation:

HI=sqrt(17^2-8^2)=sqrt(225)=15

P=8+15+17=40

S=8*15/2=60

Answer:

Step-by-step explanation:

for side HI

hypotenuse = 17

other two sides are 8 and HI . Hi has to be find so let it be x.

using pythagoras theorem

a^2 + b^2 = c^2

x^2 + 8^2 = 17^2

x^2 + 64 = 289

x^2 = 289 - 64

x^2 = 225

x = [tex]\sqrt{225[/tex]

x = 15

for angle G

take angle G as reference angle

using sin rule

sin G = opposite / hypotenuse

sin G = 15 / 17

sin G = 0.882

G = [tex]sin^{-1} (0.882)[/tex]

G = 61.884°

G = 61.88°

for angle I

angle G + angle H + angle I = 180 degree (being sum of interior angles of a triangle)

61.88° + 90° + angle I = 180°

151.88° + angle I =180°

angle I = 180°- 151.88°

angle I = 28.12°

Answer:

0.9

Step-by-step explanation:

To find the mean temperature, we have to add all of the numbers together and divide that by the amount of numbers there are.

6 + 5 + 3 + -4 + 3 + -3 + 2 + -1 + -2 + 0 = 9

There are 10 numbers.

Our mean, or average, would be 9 / 10 = 0.9

Answer:

volume quantity is hjaj

Answer:

Left 2 units

Step-by-step explanation:

Without knowing what f(x), it is impossible to answer this question. I'll answer assuming a parent function of [tex]f(x)=x^2[/tex].

In the function [tex]y=(x-c)^2[/tex], [tex]c[/tex] represents the phase shift from parent function [tex]f(x)=x^2[/tex]. If [tex]c[/tex] is positive (e.g. [tex](x-3)^2[/tex]), then the function shifts to the right however many units [tex]c[/tex] is. If [tex]c[/tex] is negative (e.g. [tex](x+5)^2[/tex]), the function shifts to the left however many units the absolute value of [tex]c[/tex] is.

In the function [tex]g(x)=(x+2)^2[/tex], let's find out the value of [tex]c[/tex]:

Format: [tex]y=(x-c)^2[/tex]

[tex]g(x)=(x+2)^2=(x-(-2))^2[/tex]

Therefore, [tex]c=-2[/tex].

Since [tex]c[/tex] is negative, the function must shift to the left. To find out how many units it shifts to the left, take the absolute value of [tex]c[/tex]:

[tex]|-2|=\boxed{2\text{ units to the left}}[/tex].

Thus, the graph of [tex]g(x)=(x+2)^2[/tex] is a translation of the graph [tex]f(x)=x^2[/tex] by 2 units to the left.

*Note: Once again, this answer is assuming [tex]f(x)=x^2[/tex] as it is not clarified in the question. If [tex]f(x)\neq x^2[/tex] and is already shifted, you will need to account for shift. If you believe this is the case, feel free to let me know in the comments.

yes

Substitute x and y into the

equation  we have

0+4 .(-5)=-20

<=>-20=-20

satisfy the condition

Answer:

c. y = ¼x - 2

Step-by-step explanation:

Find the slope (m) and y-intercept (b) then substitute the values into y = mx + b (slope-intercept form)

Slope = change in y/change in x

Using two points on the graph, (0, -2) and (4, -1):

Slope (m) = (-1 - (-2))/(4 - 0) = 1/4

m = ¼

y-intercept = the point where the line intercepts the y-axis = -2

b = -2

✔️To write the equation, substitute m = ¼ and b = -2 into y = mx + b:

y = ¼x - 2

Answer:

The answer is A.

Step-by-step explanation:

Rectangles is a quadrilateral shape that has four sides, two pairs of parallel lines, and all the corners MUST be right angles for it to be a rectangle. :)

I hope this helps :DD

Answer: 0.876, 9.123

Step-by-step explanation:

The function is [tex]y=-x^2+10-8[/tex]

It meets the ground level when [tex]y[/tex] is 0

[tex]\Rightarrow -x^2+10x-8=0\\\Rightarrow x^2-10x+8=0\\\\\Rightarrow x=\dfrac{10\pm \sqrt{(-10)^2-4(1)(8)}}{2}\\\\\Rightarrow x=\dfrac{10\pm \sqrt{68}}{2}\\\\\Rightarrow x=5\pm \sqrt{17}\\\Rightarrow x=0.876,\ 9.123[/tex]

Thus, it touches the ground at two points given above

Answer:

(A - B)' = {2, 4, 5, 6, 7, 8, 9}

(A n B) = {2, 4}

Step-by-step explanation:

Given the set :

U = { 1 , 2 , 3 , 4 , 5 ,6 , 7 , 8 , 9 }

A={1 , 2 , 3 , 4 } , B= {2 , 4 , 6 , 8 }

(A - B) = elements of A which are not in B

(A - B) = {1, 3}

(A - B)' = the complement of A - B ; element in the universal set which are not in A - B

(A - B)' = {2, 4, 5, 6, 7, 8, 9}

(A n B) = elements in both set A and set B

(A n B) = {2, 4}