Help Me need help please it is due today please help ASAP

Answer:

2 games.

Step-by-step explanation:

2.5 + 1.8 = 4

4 divided by 2 = 2

Total 32 games home and away games have been played.

The average of a group of variables is referred to as the mean in mathematics and statistics. There are several methods for calculating the mean, including simple arithmetic means (adding the numbers together and dividing the result by the number of observations), geometric means, and harmonic means.

From the bar chart :

We can obtain the total number of goals scored :

Home goals (quarter 1 to quarter 4) :

= (9 + 6 + 8 + 7)

= 30

Away goals (quarter 1 to quarter 4) :

= (2 + 7 + 4 + 5)

= 18

Using the relation :

Mean goals scored = total goals scored / number of games played

Home games :

Mean goals = 2.5

Number of home games played = total goals scored / mean goals

= 30 / 2.5

= 22

Away games :

Mean goals = 1.8

Number of away games played = 18 / 1.8

= 10

Therefore, number of home and away games played in total = 22 + 10 = 32 games

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Answer:

x=9

Step-by-step explanation:

because its isosceles, and as stated PQ = QR

so...

2x+1=3x-8

solve for x

x=9

Hope you are having a good day!

Answer:

The value of X in isosceles triangle is 9

Answer:

d = 60h + 35

Step-by-step explanation:

60 = Slope

35 = Y-intercept

You would just input whatever amount of time you need to the variable h in order to find the value of d.

Answer:

17 m

Step-by-step explanation:

As shown in the figure,  [tex]A_0-B_0[/tex] is the ground level, [tex]A_1-B_1[/tex] is the old level of water which was at 20 m below ground level, [tex]A_2-B_2[/tex] is the new level of water which is 5m above of old level. The height of wall of the well, 1.20 m, and the the pelly at 80 cm =0.80 m, has been shown too.

The minimum length of the rope is equal to the distance between the pully and the new water level, indicated by the length [tex]L_0[/tex] in the figure.

So, [tex]L_0= 20-5+1.20+0.80= 17m[/tex]

Hence, Raghu must use a rope having the minimum length 17 m to draw water from the well.

Answer:

0.55

Step-by-step explanation:

Complete Question

An open rectangular box with length of 6 feet, width of 4 feet and height of 2.5 feet is to be painted on all exterior sides, including the bottom, with a special waterproof coating. Each gallon of this special coating covers 12 square feet of surface area and costs $36.00. The box is then to be filled with water that weighs approximately 62 pounds per cubic foot.

A. Find the cost of painting this open box.

B. Find the weight of the water in the filled box

Answer:

A

[tex]x = \$ 294[/tex]

B

[tex]z =  3720 \  pounds[/tex]

Step-by-step explanation:

From the question we are told that  

  The length is  [tex]l  =  6 \ ft[/tex]

    The width is  [tex]b =  4 \ ft[/tex]

   The height is [tex]h  =  2.5 \  ft[/tex]

Generally the total surface area of the open, rectangular box is mathematically represented as

       [tex] T_ A = 2lb + 2lh + 2bh[/tex]

=>   [tex] T_ A = 2(6 * 4) + 2(6 * 2.5) + 2(4 * 2.5)[/tex]  

=>   [tex] T_ A = 98 \ ft^2 [/tex]

From the question we are told that

     $36.00 worth of paint  covers  [tex]12 ft^2[/tex]

So  $x worth of paint covers  [tex]98 \ ft^2[/tex]

=>  [tex]x = \frac{98 * 36}{12}[/tex]

=>   [tex]x = \$ 294[/tex]

Generally the volume of the open, rectangular box is mathematically represented as

     [tex]V  =  l *  b  *  h[/tex]

=>   [tex]V  =  6 *  4  *  2.5[/tex]

=>   [tex]V  =  60 \ ft^3 [/tex]

From the question we are told that  

[tex]1 ft^3[/tex]  weigh 62 pounds

[tex] 60 \ ft^3[/tex] weigh z pounds

=>  [tex]z = \frac{60 * 62}{1}[/tex]

=> [tex]z =  3720 \  pounds[/tex]

Answer:

y=4x+1

Step-by-step explanation:

I’m guessing the equation needed to be in the y=Mx+b form. If so, m is your slope and b is your y-intercept.

Answer:

y - 1 = 4 ( x - 0 )

Step-by-step explanation:

point slope form

Answer:

Supplementary and Linear Pair

Step-by-step explanation:

The angles 1 and 2 form 180 degrees. That is the definition of a Supplementary Angle and Linear Pair.

9514 1404 393

Answer:

  C.  y = 50x + 3.5

Step-by-step explanation:

100 miles in 2 hours is 100/2 = 50 miles per hour. Multiplying that rate by x hours gives the miles traveled in addition to the 3.5 miles so far. The appropriate equation for miles traveled is ...

  y = 50x +3.5 . . . matches choice C

Answer:

Step-by-step explanation:

Answer: Required ratio= 3:1.

larger bed has 3 square feet of area of every 1 square feet on smaller bed.

Step-by-step explanation:

Given: Felipe has a flower bed with area [tex]\dfrac{25}4[/tex] square feet.

He expands the flower bed to have area [tex]\dfrac{75}4[/tex] square feet.

Now, area on larger flower bed  for every square foot of the smaller flower bed = (area of larger bed) ÷ (area of smaller bed)

[tex]= \dfrac{75}{4}\div\dfrac{25}{4}=\dfrac{75}{4}\times\dfrac{4}{25}=\dfrac{3}{1}[/tex]

So, larger bed has 3 square feet of area of every 1 square feet on smaller bed.

Required ratio= 3:1.

Answer:

Both castles will have the same height at 3.33 minutes

Step-by-step explanation:

This problem will be solved with linear modeling, that is, expressing both people's sand castle's height as a function of time.

Justin built a sandcastle 180 cm tall, and its height is losing at 8 cm/min by the effect of wind. Thus, the height of Justin's sandcastle is:

[tex]H_J=180-8t[/tex]

Where t is the time expressed in minutes.

Taylor's sandcastle is initially 160 cm tall. The wind blows away sand at 8 cm/min but she adds sand at 6 cm/min, thus the real loss of sand is 8 cm/min - 6 cm/min= 2 cm/min. Thus, the height of Taylor's sandcastle is:

[tex]H_T=160-2t[/tex]

To find when both castles have the same height, we set:

[tex]180-8t=160-2t[/tex]

Simplifying:

6t=20

Solving:

t=20/6=3.33\ minutes

Both castles will have the same height at 3.33 minutes

Answer:

The correct answer is C. controlling interstate and foreign trade

Based on the Constitution, all of the above are Reserved powers except, C.  controlling Interstate and foreign trade

Reserved powers are those that are reserved for state governments and some of them are:

Regulating interstate and foreign trade is the responsibility of the federal government as it does so on behalf of all states in a joint manner.

In conclusion, regulating foreign and interstate trade is not a reserved power.

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Answer:

Domain is [tex]\{2,8,30,46\}[/tex]

Range is [tex]\{-1,9,16\}[/tex]

Step-by-step explanation:

The relation refers to the collection of ordered pairs, which contains an element from one set to another set.

Domain of a relation [tex]y=f(x)[/tex] is all the values [tex]x[/tex] that go into a function, and the range is a set of all the values [tex]f(x)[/tex] that are obtained for the given domain.

The given relation is [tex]\{(2,-1),(8,16),(30,9),(46,16)\}[/tex]

Here, domain is [tex]\{2,8,30,46\}[/tex]

Range is [tex]\{-1,9,16\}[/tex]

Answer:17

Step-by-step explanation:my teacher explained how 20 is wrong

Answer:

It is 17 percent.

Step-by-step explanation:

Confirming the other answer is right and just saying it's right for other people who might not trust em. :D

Answer:

7.50$

Step-by-step explanation:

3+3+1.5=7.50$.

Answer:

Carla's suitcase was a better purchase.

Step-by-step explanation:

The complete question is:

Carla and Daniel bought identical suitcases at different stores. Carla's suitcase originally cost $75 and was discounted 19% Daniel's suitcase original cost $85 and was on sale for 20% off the original price. Which suitcase was the cheaper?

Solution:

        Discount% for Carla = 19%

        The amount paid by Carla is,

        [tex]\text{Amount}=CP\times [1-d\%]=75\times [1-0.19]=60.75[/tex]

        So, the amount paid by Carla was, $60.75.

        Discount% for Jeana = 20%

        The amount paid by Jeana is,

        [tex]\text{Amount}=CP\times [1-d\%]=85\times [1-0.20]=68[/tex]

        So, the amount paid by Jeana was, $68.

Carla's suitcase was a better purchase.

Answer:

∠AEB = 62°

∠CED = 62°

∠CDE = 36°

Step-by-step explanation:

The measure of ∠m = ∠CDE of the triangle and ∠CDE = 36°

A triangle is a plane figure or polygon with three sides and three angles.

A Triangle has three vertices and the sum of the interior angles add up to 180°

Let the Triangle be ΔABC , such that

∠A + ∠B + ∠C = 180°

The area of the triangle = ( 1/2 ) x Length x Base

For a right angle triangle

From the Pythagoras Theorem , The hypotenuse² = base² + height²

Given data ,

Let the first triangle be represented as ΔABE

Let the second triangle be represented as ΔCDE

The measure of angle ∠EAB = 62°

The measure of angle ∠ABE = 56°

The sum of the interior angles of a triangle = 180°

So , the measure of angle ∠AEB = 180° - ( 62° + 56° )

The measure of angle ∠AEB = 180° - 118°

The measure of angle ∠AEB = 62°

And , by vertically opposite angles

The measure of angle ∠AEB  = measure of angle ∠CED

And , the measure of ∠CDE = 180° - ( 82° + 62° )

The measure of ∠D = 180° - 144°

The measure of ∠D = 36°

Therefore , the measure of ∠m = 36°

Hence , the measure of angle ∠D is 36°

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Answer:

a) Two thorough rinses gives;

1/25 × 1/2 × 2/17 strong bleach/L = 1/425 strong bleach/L

b) The water should be divided into two quantities of 10 liters each

Step-by-step explanation:

The given parameters are;

The initial volume of strong bleach solution in the nappies = 1/2 Liters

The volume of water first used to rinse = 12 liters

The volume of water used in the second rinse = 8 liters

Therefore, we have;

The total volume of the water and the concentrated bleach in the first rinse = 1/2 + 12 = 12.5 Liters

The new concentration of the bleach in the first rinse water = (1/2 strong bleach)/12.5 L = (1/2 strong bleach)/25/2 L = 1/2×2/25 = 1/25 strong bleach/L

The volume of the first rinse introduced in the second rinse = 1/2 Liters

The concentration of the bleach introduced in the second rinse = The new concentration of the bleach in the first rinse water = 1/25 strong bleach/L

The volume of water added in the second rinse = 8 liters

The total volume of the water and the bleach in the second rinse = (8 + 1/2) liters = 8.5 liters

The concentration of bleach in the second rinse = (The concentration of the bleach introduced in the second rinse × (Volume of bleach solution introduced in the second rinse))/(The total volume of the water and the bleach in the second rinse)

The concentration of bleach in the second rinse = (1/25 strong bleach/L × 1/2 L)/(8.5 Liters)

The concentration of bleach in the second rinse = (1/25 strong bleach/L × 1/2 L)/(17/2 Liters) = 1/25 × 1/2 × 2/17 strong bleach/L = 1/425 strong bleach/L

b) The the quantity of water in the first rinse = x

The amount of water in the second rinse = 20 - x

The concentration of bleach in the first rinse = 1/2/(x + 1/2) = 1/(2·x + 1)

The concentration introduced in the second rinse = 1/2 × 1/(2·x + 1) = 1/(4·x + 2)

The total volume of water and bleach introduced in the second rinse = (20 - x + 1/2) = 20.5 - x

The concentration of bleach in the second rinse = 1/(4·x + 2)/(20.5 - x)

The minimum value for the concentration can be found from taking the derivative of the function for the concentration and equation to zero as follows;

[tex]\dfrac{\mathrm{d} \dfrac{1}{\left ( 4\cdot x + 2 \right )\cdot \left ( 20.5 - x \right )}}{\mathrm{d} x} = \dfrac{2\cdot \left ( x - 10 \right )}{\left ( 2\cdot x + 1 \right )^{2}\cdot \left ( 20.5 - x \right )^{2}} = 0[/tex]

2·(x - 10) = 0

x = 0/2 + 10 = 10

x = 10

The the quantity of water in the first rinse = x = 10 liters

The the quantity of water in the first rinse = 10 liters

The amount of water in the second rinse = 20 - x = 20 - x = 20 - 10 = 10 liters

The amount of water in the second rinse = 10 liters

The water should be divided into two quantities of 10 liters each

Therefore, the water should be divided into two quantities of 10 liters each to give a final bleach solution concentration of 1/(4·x + 2)/(20.5 - x) = 1/(4×10 + 2)/(20.5 - 10) = 1/42 × 1/10.5 = 1/441 concentration/liter.

Answer: a) Two thorough rinses gives;

1/25 × 1/2 × 2/17 strong bleach/L = 1/425 strong bleach/L

b) The water should be divided into two quantities of 10 liters each

Answer:

C.

Step-by-step explanation:

Answer:

[tex]\mathbf{ P =D(x)= 70 -\dfrac{ x}{20}}[/tex]

Step-by-step explanation:

From the information given :

The objective is to find the demand function which is expressed in p, the price in dollars charged for each ticket, as a function of x, and the number of average attendance is:

Suppose the admission price P = D(x) = 30 and number of average attendant = x = 800 people

Then:

ΔP = -1

Δx = 20

[tex]\left \{ \dfrac{\Delta x}{\Delta P }= -20 }}\ \right.[/tex]

According to point line form :

[tex]\dfrac{\Delta x}{\Delta P }= -20[/tex] where the point is (30, 800)

∴

x - 800 = -20 (P - 30)

x - 800 = -20P + 600

collect like terms

x + 20P = 800+ 600

x + 20P = 1400

x = 1400 - 20P

[tex]\mathsf{ P = 70 -\dfrac{ 1}{20}x}[/tex]

Thus, price in dollars for each ticket P = D(x) is:

[tex]\mathbf{ P =D(x)= 70 -\dfrac{ x}{20}}[/tex]

Answer:

The domain of the graph is (-infinity, infinity)

The range of the graph is [0, infinity)

Please mark as helpful if this is helpful!

Thanks

Answer:

No.

Step-by-step explanation:

A graph must pass the Vertical Line Test in order to be a function. Since this graph doesn't pass the test, it is not a function.

However, this graph is a conic, specifically a hyperbola.

Answer:

Definition. A pronoun (I, me, he, she, herself, you, it, that, they, each, few, many, who, whoever, whose, someone, everybody, etc.) is a word that takes the place of a noun. In the sentence Joe saw Jill, and he waved at her, the pronouns he and her take the place of Joe and Jill, respectively.

Answer:

7.302997e+301

Step-by-step explanation:

Answer:

calculator cannot  hold that much digits

Step-by-step explanation:

Answer:

1

Step-by-step explanation:

27 divided by 26.

Answer:

360"

Step-by-step explanation:

Firstly, you need to be able to convert your feet to inches. Remember, one foot is equal to twelve inches. You multiply six inches by five feet and later multiply by twelve to convert to inches.