Answers
[tex]\underline \bold{ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: }[/tex]
[tex] \huge\underline{\sf{\red{Problem:}}}[/tex]
7.) Detemine the value of [tex] \sf{ {3a}^{2} -b.}[/tex]
[tex] \huge\underline{\sf{\red{Given:}}}[/tex]
[tex]\quad\quad\quad\quad\sf{a = 2}[/tex]
[tex]\quad\quad\quad\quad\sf{b = - 1}[/tex]
[tex]\quad\quad\quad\quad\sf{c = - 3}[/tex]
[tex] \huge\underline{\sf{\red{Solution:}}}[/tex]
[tex]\quad\quad\quad\quad\sf{⟶{3a}^{2} - b}[/tex]
[tex]\quad \quad \quad \quad \sf{⟶{(3)( 2)}^{2} -( - 1)}[/tex]
[tex]\quad \quad \quad \quad \sf{⟶3(4)-( - 1)}[/tex]
[tex]\quad \quad \quad \quad \sf{⟶12-( - 1)}[/tex]
[tex]\quad \quad \quad \quad \sf{⟶12 + 1 }[/tex]
[tex]\quad \quad \quad \quad ⟶ \boxed{ \sf{ 13}}[/tex]
[tex]\huge\underline{\sf{\red{Answer:}}}[/tex]
[tex]\huge\quad \quad \underline{ \boxed{ \sf{ \red{\:13}}}}[/tex]
8.) Find the value of [tex] \sf{ {a}^{3} {b}^{3} - abc.}[/tex]
[tex] \huge\underline{\sf{\red{Solution:}}}[/tex]
[tex]\quad\quad\quad\quad\sf{⟶ {a}^{3} {b}^{3} - abc}[/tex]
[tex]\quad\quad\quad\quad\sf{⟶{(2)}^{3} {( - 1)}^{3} - (2)( - 1)( - 3)}[/tex]
[tex]\quad\quad\quad\quad\sf{⟶{(8)}{( - 1)} - ( - 2)( - 3)}[/tex]
[tex]\quad\quad\quad\quad\sf{⟶{( - 8)} - ( 6)}[/tex]
[tex]\quad\quad\quad\quad ⟶\boxed{\sf{ - 14}}[/tex]
[tex]\huge\underline{\sf{\red{Answer:}}}[/tex]
[tex]\huge\quad \quad \underline{ \boxed{ \sf{ \red{-14}}}}[/tex]
[tex]\underline \bold{ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: }[/tex]
#CarryOnLearning
[tex]\sf{\red{✍︎ C.Rose❀}}[/tex]
Related Questions
pls answer this. its easy but for me nah
Answers
Answer:
1. acute
2. Right
3. maybe acute
4. obtuse
5. acute
6. obtuse
7. straight
8. obtuse
9. acute
10. obtuse
11. acute
12. acute
13. obtuse
14. obtuse
What is another word for zeros?
Answers
Answer:
nothing
Step-by-step explanation:
Zero is a number without a value so nothing could be another word for it
Choose the function that is a "parent function". O f(x) = x=3 o f(x) = (x - 3)2 O o f(x)= X O f() = x-31
Answers
Answer:
option D is the correct answer I think so
Using √6241=79, Find the value of √62.41
Answers
Answer:
[tex] \blue{7.9} [/tex]
Step-by-step explanation:
[tex] \sqrt{6241} = 79 [/tex]
[tex] \sqrt{62.41} = [/tex]
[tex] = \sqrt{\dfrac{6241}{100} [/tex]
[tex] = \dfrac{79}{10}[/tex]
[tex] = \blue{7.9} [/tex]
En el subnivel basica superior de la unidad manuela cañizares el numero de estudiantes que se alimentan de forma inadecuada ( grasa saturada ) el triple del numero de estudiantes que consumen alimentos saludables menos 8. Si existen 392 estudiantes entre los que consumen alimentos sludables y los que no se alimentan de forma adecuada palntea una ecuacion y determina ¿cuantos estudiantes se alimentan de manera saludable y cuantos estudiantes se alimentan inadecuadamente?
Answers
Answer:
La cantidad de estudiantes que se alimentan de manera saludable es 100 y la cantidad de estudiantes que se alimentan inadecuadamente es 292.
Step-by-step explanation:
Existen 392 estudiantes entre los que consumen alimentos saludables y los que no se alimentan de forma adecuada. Esto es:
Estudiantes que se alimentan adecuadamente + Estudiantes que no se alimentan adecuadamente= 392
El numero de estudiantes que se alimentan de forma inadecuada es el triple del número de estudiantes que consumen alimentos saludables menos 8. El triple de un número se calcula multiplicando el número por 3. Entonces, siendo x la cantidad de estudiantes que se alimentan adecuadamente, la cantidad de estudiantes que no se alimentan adecuadamente se puede calcular como: 3*x - 8
Por lo que:
x + 3*x - 8= 392
Resolviendo:
x + 3*x= 392 + 8
4*x= 400
x= 400÷4
x= 100
Entonces: 3*x - 8= 3*100 -8= 300 - 8= 292
La cantidad de estudiantes que se alimentan de manera saludable es 100 y la cantidad de estudiantes que se alimentan inadecuadamente es 292.
If b=3-2s and A= -2s^2+2s+3 find an expression that equals 2b+2A in standard form
Answers
I think this might be the answer you’re looking for so best of wishes and good luck!!
HELP! ASAP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! Ty ty ty ty tysmmmmm! I hope you have a amazing day!.
Answers
Answer:
(1)1 hour 15 minutes
(2)4:07
(3) 30 minutes
(4) 8:35
Step-by-step explanation:
1.We are given that
Trey and Na'Asia played basketball from 10:30-11:45
We have to find the time they play basketball.
11:45-10:30
11-10=1 hour
45-30=15 minutes
They played basketball for duration=1 hour 15 minutes
(2)
School left at 3:15
I got home 52 minutes later.
Then, I got home at =3:15+52 minutes
15 minutes+52 minutes=67 minutes
67 minutes=1 hour 7 minutes
Therefore, I got home at 4:07.
(3)
He begins making Macaroni and chees at 6:35
He finished at 7:05.
He cook his food for time =25+5=30 minutes
(4)
Mahkiya and Madison went to Cheerleading at 7:15
It was over 1 hour and 20 minutes later .
Therefore, time=7:15+1 hour 20 minutes
=(7+1) : (15+20) minutes
=8:35
Hence, it was over at 8:35.
If the bearing of B from A is 302, what is the bearing of a from B ?
Answers
Answer:
The bearing of A from B is 122°
If f(x) = 4x − 6 and g(x) = 6x − 4, what is f · g?
Answers
Answer:
f · g = 24x² - 52x + 24
General Formulas and Concepts:
Pre-Algebra
Order of Operations: BPEMDAS
Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to RightAlgebra I
Terms/CoefficientsExpand by FOILFunctionsFunction NotationStep-by-step explanation:
Step 1: Define
Identify
f(x) = 4x - 6
g(x) = 6x - 4
Step 2: Find f · g
Substitute in function values: f · g = (4x - 6)(6x - 4)Expand [FOIL]: f · g = 24x² - 16x - 36x + 24[Subtraction] Combine like terms: f · g = 24x² - 52x + 24Find the value of x
3x+2=23
Answers
Answer:
x = 7
Step-by-step explanation:
23 - 2 = 21
21 / 3 = 7
x = 7
Answer:
x = 7
Step-by-step explanation:
3x + 2 = 23
3x = 23 - 2
3x = 21
x = 21/3
x = 7
I hope you understand...
This is Right answer...
The pyramid ABCDE has a square base. the pyramid is 20cm high and each sloping edge measures 30cm. calculate the length of the sides the base
Answers
Answer:
44.8 cm
Step-by-step explanation:
Vertical height (h) = EM = 20 cm
Slant height (l) = 30 cm
This two heights form a right angle at the interception at the base. Thus, we have a right angle triangle.
The length of the sides of the base = 2 × the base of the right triangle
✔️Use Pythagorean theorem to find the base of the right triangle formed. Thus: c² = a² + b²
a = base of the triangle
b = h = 20 cm
c = l = 30 cm
Plug in the values
30² = a² + 20²
a² = 30² - 20²
a² = 500
a = √500
a = 22.4 cm
✔️length of the sides of the base = 2 × the base of the right triangle
= 2 × a
= 2 × 22.4
= 44.8 cm
the quotient of 55 and x
Answers
Answer:
the should be one more piece of information..
Step-by-step explanation:
may be your answer is
55/x
If you place a 20 ft ladder 4ft from the base of the wall. How high up will it reach? Round answer to the nearest tenth
Answers
Answer:
h = 19.6 ft
Step-by-step explanation:
Given that,
A 20 ft ladder 4ft from the base of the wall.
The height of the ladder, H = 20 ft
The base distance, b = 4 ft
We need to find the height of the reach. Let it is P.
Using Pythagoras theorem,
[tex]H^2=b^2+P^2\\\\P=\sqrt{H^2-b^2}\\\\P=\sqrt{20^2-4^2}\\\\=19.59\ ft[/tex]
or
P = 19.6 ft
So, the height is 19.6 ft.
Evaluate 2(x+ 1 - 3 when x = 6 O Ο Α. 11 OB. 5 O C. 8 ( D. 10
whoever answers this first will get 25 points
Answers
[tex]\implies {\blue {\boxed {\boxed {\purple {\sf {A. \:11}}}}}}[/tex]
[tex]\sf \bf {\boxed {\mathbb {STEP-BY-STEP\:\:EXPLANATION:}}}[/tex]
[tex]2 \: ( \: x + 1 \: ) - 3[/tex]
Plugging in the value "[tex]x\:=\:6[/tex]" in the above expression, we have
[tex] = 2 \: ( \: 6 + 1 \: ) - 3[/tex]
[tex] = 2 \: ( \: 7 \: ) - 3[/tex]
[tex] = 14 - 3[/tex]
[tex] = 11[/tex]
Note:-[tex]\sf\red{PEMDAS\: rule.}[/tex]
P = Parentheses
E = Exponents
M = Multiplication
D = Division
A = Addition
S = Subtraction
[tex]\large\mathfrak{{\pmb{\underline{\orange{Mystique35 }}{\orange{❦}}}}}[/tex]
18. Given that g(x) = -(x^2)/4, what is the value of g(+8) ?
F. -16
G. 4
H. -1
J. 4
K. 16
Answers
Answer:
F. -16
General Formulas and Concepts:
Pre-Algebra
Order of Operations: BPEMDAS
Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to RightAlgebra I
FunctionsFunction NotationStep-by-step explanation:
Step 1: Define
Identify
[tex]\displaystyle g(x) = -\frac{x^2}{4}[/tex]
Step 2: Evaluate
Substitute in x [Function g(x)]: [tex]\displaystyle g(-8) = -\frac{(-8)^2}{4}[/tex]Exponents: [tex]\displaystyle g(-8) = -\frac{64}{4}[/tex]Divide: [tex]\displaystyle g(-8) = -16[/tex]Solve −1/4x=7 please
Answers
Answer:
x = -28
Step-by-step explanation:
−1/4x=7
Multiply each side by -4 to isolate the variable
-4 * −1/4x= -4*7
−1/4x=7
pls help I was sick from school and have some much more work to do have a good day yall
Answers
Answer:
3 hours :)
Step-by-step explanation:
5 km x 3 = 15km
also i hope you can catch up on ur work :)
PLEASE HELP AT YOUR EARLIEST CONVINECE CORRECT ANSWER GET BRAINLIEST AND 50 POINTS PLEASE HELP
The data set below shows the weights of some puppies, in pounds, at a kennel:
10, 11, 12, 12, 13, 13, 14, 15, 15
Which histogram represents the data set?
A histogram is shown with title Puppy Weight. On the horizontal axis, the title is Pounds. The title on the vertical axis is Puppies. The range on the horizontal axis is 10 to 11, 12 to 13, and 14 to 15. The values on the vertical axis are from 0 to 6 at intervals of 1. The bar for the first range goes to 2, the bar for the second range goes to 4, the bar for the third range goes to 3.
A histogram is shown with title Puppy Weight. On the horizontal axis, the title is Pounds. The title on the vertical axis is Puppies. The range on the horizontal axis is 10 to 11, 12 to 13, and 14 to 15. The values on the vertical axis are from 0 to 6 at intervals of 1. The bar for the first range goes to 3, the bar for the second range goes to 4, the bar for the third range goes to 2.
A histogram is shown with title Puppy Weight. On the horizontal axis, the title is Pounds. The title on the vertical axis is Puppies. The range on the horizontal axis is 10 to 11, 12 to 13, and 14 to 15. The values on the vertical axis are from 0 to 6 at intervals of 1. The bar for the first range goes to 2, the bar for the second range goes to 3, the bar for the third range goes to 4.
A histogram is shown with title Puppy Weight. On the horizontal axis, the title is Pounds. The title on the vertical axis is Puppies. The range on the horizontal axis is 10 to 11, 12 to 13, and 14 to 15. The values on the vertical axis are from 0 to 6 at intervals of 1. The bar for the first range goes to 4, the bar for the second range goes to 2, the bar for the third range goes to 3.
I ATTACHED A PICTURE OF THE GRAPH ANSWER CHOICES FOR BETTER UNDERSTANDING
Thank you have a wonderful day :) (dont stress over this just try your hardest)
Answers
Answer:
the last graph
Step-by-step explanation:
Answer:
Putting an answer so you can give the other person brainly.
Step-by-step explanation:
Also is it really D) ???
Cause I thought it was A)
Members at a gym pay $9 per class plus a one-time $120 membership fee. Non-members pay $15 per class. How many classes would a member have to take to save money compared to taking classes as a non-member?
Pls help I have only a few for mins and I need step by step equation :) pls pls pls
Answers
Answer:
the answer is 45 dollars
Step-by-step explanation:
its because:
Answer:
25 dollors hope this helps
Step-by-step explanation:
factorise fully the following expression (x2-3x-10)
Answers
Answer:
(x - 5)(x + 2)
Step-by-step explanation:
by first considering the angles on line abc show that ac is parallel to df
Answers
Answer:
so you have to use interior and exterior angles to solve
the perimeter of one rectangle is 120cm. another rectangle with twice the length amd and one third the width has a perimeter of 170 cm. what are the dimensions of the two rectangles?
Answers
Answer:
Dimensions of 1st rectangle,
length = 39 cm, width = 21 cm.
Dimensions of the 2nd rectangle,
length = 78 cm, width = 7 cm.
Step-by-step explanation:
Let the dimensions of the 1st rectangle be,
Length = x, width = y
so the dimensions of the 2nd rectangle becomes,
Length = 2x, width = y/3
perimeter of the first rectangle,
2(x+y)=120 --------- (i)
perimeter of the 2nd rectangle,
2(2x+y/3)=170 ---------(ii)
if we solve equation (i) and (ii), we'll get,
x = 39
y = 21
for the other rectangle, 2x = 78, y/3 = 7.
Answered by GAUTHMATH
I’m begging you too pls pls pls pls help! I’d appreciate it so much. This is independent work and I have no clue of what this means so pls comment as fast as u can because according to my teacher this was supposed to be due yesterday and I’m just doing it today. Pls help thank you so so so much! Pls don’t waste time thanks again!
Answers
Answer:
1. 160 min
2. 84 min
3. 5:12 p.m.
4. 6:40 p.m.
5 a 4:44 p.m.
b 7:14 p.m.
Need help will give thanks and brainliest
Answers
Answer:
6in x 4in = 24in
and for the second one
6in x 2in= 12in
Mrs. Johnson has 159 chickens that she puts in shelters at night to keep safe. She places 12 chickens in a shelter and continues putting this number of chickens in each shelter until she comes to the last one. How many chickens will Mrs. Johnson put in the last shelter?
Answers
Answer:
3 chickens will Mrs. Johnson put in the last shelter
Step-by-step explanation:
According to the question,
Given,Mrs. Johnson has 159 chickens that she puts in shelters at night to keep safe. She places 12 chickens in a shelter .
thus,If she put 12 chickens in each 13 shelters ( 12×13=156 chickens) adjusted in shelters .
Then, the remaining 159-156 = 3 chicken will Mrs. Johnson put in the last shelter .
Tasha is planning an expansion of a square flower garden in a city park. If both the length and the width of the original garden are each increased by *3m*, the new total area of the garden will be *49* squared meters. Find the length of each side of the original garden.
Answers
Answer:
4 m
Step-by-step explanation:
Since the flower garden is square :
Both length and width are equal :
Let :
Original side length = x
Increased length = x + 3
Area of square = s² (s = side length)
New area = 49 m²
That is ;
(x + 3)² = 49
Original length, x can be calculated thus ;
Take square root of both sides
x + 3 = √49
x + 3 = 7
x = 7 - 3
x = 4
Hence, original length of each side = 4 m
Why does the congruency of all angles not prove the congruency of two triangles?
Answers
Draw an equilateral triangle with side lengths 5 inches each. Each interior angle is 60 degrees (this is true of any equilateral triangle).
Now draw an equilateral triangle of 10 inches each. The angles will be the same as before. We can see that the triangles are not congruent. Congruent triangles must have the same side lengths, but clearly the second one is larger than the first.
This is an example of why knowing solely the congruency of the angles is not enough to prove the triangles congruent or not. We would need to know something about the sides (whether they are congruent or not) to be able to determine overall triangle congruency.
Answer:
Because even though the angles may be the same, the lengths can be different. In an isosceles triangles, this may be the case.
Step-by-step explanation:
The equation a + b + c = 180 describes the sum of the angles in a triangle.
Use this formula to find the values of a, b and c when b = 2a and c = 3a
Answers
Answer:
a=30 b=60 c=90
Step-by-step explanation:
you replace b with 2a and c with 3a and you get
a+2a+3a=180
6a=180
a=30
from here you replace a with 30 and find b and c
b=2a=2*30=60
c=3a=3*30=90
What would be a sound, simple, straightforward way to describe IQR (Interquartile range)
Answers
Answer:
IQR: is the length of the middle 50% of that interval of space
Step-by-step explanation:
In order to find IQR, subtract the third interquartile range - the first interquartile range
Which expression is equivalent to (-7) (-7) (-7)