How many moles of sodium acetate must be added to 500.0 mL of 0.250 M acetic acid solution to produce a solution with a pH of 4.94? (The pKa of acetic acid is 4.74)A) 0.011 molesB) 0.021 molesC) 0.13 molD) 0.20 molE) 0.21 mol

Answers

Answer 1

To produce a solution with a pH of 4.94, a certain amount of sodium acetate should be added to a 500.0 mL 0.250 M acetic acid solution. The correct amount is (A) 0.011 moles.

First, we need to use the Henderson-Hasselbalch equation to find the ratio of[tex]\frac{{[\text{{acetate}}]}}{{[\text{{acetic acid}}]}}[/tex]required to produce a solution with pH 4.94.

[tex]pH = pKa + log \left( \frac{{[Acetate]}}{{[Acetic Acid]}} \right)[/tex]

4.94 = 4.74 + log([acetate]/[acetic acid])

[tex]0.2 = \log \left( \frac{{[\text{{acetate}}]}}{{[\text{{acetic acid}}]}} \right)[/tex]

[tex]\frac{{[\text{{acetate}}]}}{{[\text{{acetic acid}}]}} = 10^{0.2} = 1.585[/tex]

We want to add enough sodium acetate to produce a 0.250 M solution, so we can set up the following equation:

[tex]0.250 \, \text{M} = \frac{{[\text{acetate}] + [\text{acetic acid}]}}{{0.5 \, \text{L}}}[/tex]

Since [acetate]/[acetic acid] = 1.585, we can substitute and simplify:

[tex]0.250 \, \text{M} = \frac{{[\text{acetic acid}] \cdot (1 + 1.585)}}{{0.5 \, \text{L}}}[/tex]

[acetic acid] = 0.105 M

To find the amount of acetic acid required, we can use the following equation:

moles = M x V (where V is in liters)

moles acetic acid = 0.105 M x 0.500 L = 0.0525 moles

Since sodium acetate is a 1:1 electrolyte, we need to add the same amount of moles of sodium acetate as acetic acid:

moles sodium acetate = 0.0525 moles

Therefore, the answer is A) 0.011 moles.

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BRAINLIEST IF YOU GET IT!! 5 STARS & A THANK YOU!!
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Answers

Answer:

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It on googIe
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