I NEED HELP IMMEDIATLY! 100 POINTS AND BRAINLY!!!!!!!

Solve for ccc.
Give an exact answer.
0.2(10-5c)=5c-160.2(10−5c)=5c−160, point, 2, left parenthesis, 10, minus, 5, c, right parenthesis, equals, 5, c, minus, 16
c =c=c, equals

Answer:

n=1

Step-by-step explanation:

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Answer:

looking at the straight line, it touches the axis at (-2,0) and (6,0)

Step-by-step explanation:

Answer:

m = 5[tex]\sqrt{5}[/tex]

Step-by-step explanation:

To find the measure  of m we use the following Euclidian theorem:

m^2 = 5*(5+20)

m^2 = 125 find the root for both sides

m = 5[tex]\sqrt{5}[/tex]

Answer: I am pretty sure it's 18 feet.

Step-by-step explanation:

Answer:

  1 1/2 inches

Step-by-step explanation:

To find how much more a second number is than a first number, the first is subtracted from fhe second. Here, we want to know how much more the second week total is than the first, so we subtract the first week's total from the second week's total.

__

We find the second week's total by adding up the values associated with the different days in the second week.

  second week's total = 1 7/8 +2 3/4 = (1 +2) +(7/8 +6/8) = 3 13/8 = 4 5/8

Then the difference is ...

  second week's total - first week's total

  = 4 5/8 -3 1/8 = (4 -3) +(5/8 -1/8) = 1 4/8 = 1 1/2

It rained 1 1/2 inches more this week than last week.

Step-by-step explanation:

let, the tulips be 'x'

According to the question,

heather=4x

& sarah=x

but heather planted 64 so,

4x=64

or, x=64/4

x=16

hence, sarah planted 16 tulips

Heather planted 4x Sarah's tulips. On the off chance that Heather has 64 tulips, Sarah has 16 tulips (64/4 = 16).

Let's utilize algebra to illuminate this issue. Let s speak to the number of tulips Sarah planted.

Concurring to the data given, Heather planted 4 times as numerous tulips as Sarah, so we will compose this as:

Heather's tulips = 4 * Sarah's tulips

64 = 4s

Presently, ready to fathom for s:

s = 64 / 4

s = 16

Sarah planted 16 tulips.

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[tex]======================================[/tex]

In order to solve this equation, we should first subtract 3 from both sides:

[tex]\pmb{2x=12-3}[/tex]

Which equals

[tex]\pmb{2x=9}[/tex]

Divide both sides by 2

[tex]\pmb{x=\displaystyle\frac{9}{2} }[/tex]

[tex]======================================[/tex]

Hope everything is clear; if you need any more explanation/clarification, kindly let me know, and I will comment and/or edit my answer :)

Answer:

If you are trying to find slope this is how you solve it.

Step-by-step explanation:

2x+3=12

-2x       -2x

3=-2x+12

÷3  ÷3   ÷3

y=-2/3x+4

So if you are trying to find the slope it is -2/3x and the y intercept is 4.

Answer: $7401.22

Step-by-step explanation: it’s right just trust me

Answer:

A=lw+l(w

2)2+h2+w(l

2)2+h2=30·20+30·(20

2)2+282+20·(30

2)2+282≈2127.25933

Your answer is 2127.259

I think it will help you

If "s" represents the slant height in the rectangular pyramid with dimensions l = 30, w = 20, and h = 28, then the length of "s" is approximately 29.75 units.

To find the length of "s" in the rectangular pyramid, we first need to understand the terminology used to describe the different dimensions of a pyramid.

In a rectangular pyramid, "l" usually represents the length of the base, "w" represents the width of the base, and "h" represents the height of the pyramid (the perpendicular distance from the base to the apex or top vertex of the pyramid).

However, there is no standard notation for the length of the slant height (s) in a rectangular pyramid. In this context, the term "s" could represent either the slant height or some other unknown dimension of the pyramid.

If "s" represents the slant height of the pyramid, we can use the Pythagorean theorem to find its value. The slant height, "s," is the hypotenuse of a right triangle formed by one of the triangular faces of the pyramid and the height and half the width of the base.

Using the given dimensions:

l = 30 (length of the base)

w = 20 (width of the base)

h = 28 (height of the pyramid)

Let's find the value of "s" using the Pythagorean theorem:

[tex]s^2 = h^2 + (w/2)^2\\s^2 = 28^2 + (20/2)^2\\s^2 = 28^2 + 10^2\\s^2 = 784 + 100\\s^2 = 884\\[/tex]

Now, take the square root of both sides to find the value of "s":

s ≈ √884

s ≈ 29.75 (rounded to two decimal places)

So, if "s" represents the slant height in the rectangular pyramid with dimensions l = 30, w = 20, and h = 28, then the length of "s" is approximately 29.75 units.

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Yes :- true

as in the diagram 6 units in between the 20° and 90° and third angle will be 180-110 = 70°

Triangle with angle 90 and 20 degree possible as it Satisfies the angle sum property.

The total of a triangle's three internal angles is 180 degrees, as stated by the angle sum feature of a triangle. A closed shape with both inner and exterior angles, a triangle is created by three line segments.

Given:

angles= 20 and 90 degree

Using Angle Sum property

20 + 90 + <3 =180

<3 = 180 - 110

<3 =70

Hence, the Triangle with angle 90 and 20 degree possible as it Satisfies the angle sum property.

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Right now, Scott is 5.
His Aunt Mary is 4*5 = 20

We can solve this algebraically if your teacher requires to.
In x years, Scott will be half as old as his Aunt right now (which is 20).

5+x= 20/2
5+x=10
x=5

In 5 years Scott will be half as old as his aunt was.

Answer:

19

Step-by-step explanation:

(Assuming that each cube is 1 unit), the volume is 5 + 6 + 8 which equals 19

Answer:

Bridget flew 4100 miles.

Step-by-step explanation:

L + K + B = 7800

1500+2200+B=7800

3700 + B = 7800

Subtract 3700.

B = 4100

Bridget flew 4100 miles.

The required point that could have been one of the points that Tom graphed is (-3,-7) lies in Quadrant III. The correct answer would be an option (A).

A quadrant is defined as an area contained by the x and y axes, which there are four quadrants in a graph.

A point that could have been one of the points that Tom graphed is (-3,-7). This is because it lies in Quadrant III of the coordinate grid. In Quadrant III, the x-coordinate is negative and the y-coordinate is negative.

Point A has a negative x-coordinate and a negative y-coordinate, so it satisfies the requirement of being in Quadrant III.

Hence, the correct answer would be option (A).

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Answer:

The common denominator of 5/8 and 5/4 is 8.

4×2 is 8 and 5/8 already has a denominator of 8

The common denominator of two fractions 5/8 and 5/4 is 8.

A number system is defined as a system of writing to express numbers.

To find a common denominator for 5/8 and 5/4, we need to find the least common multiple (LCM) of the denominators 8 and 4.

The multiples of 8 are: 8, 16, 24, 32, 40, 48, ...

The multiples of 4 are: 4, 8, 12, 16, 20, 24, 28, 32, 36, 40, 44, 48, ...

We can see that the least common multiple of 8 and 4 is 8, since 8 is the smallest number that appears in both lists.

To convert 5/8 to an equivalent fraction with denominator 8, we can multiply both the numerator and the denominator by 1, which is equivalent to multiplying by 8/8

Hence, the common denominator of two fractions 5/8 and 5/4 is 8.

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Answer:

see explanation

Step-by-step explanation:

look at the photo

Answer:

N = 9  & P = 4

Step-by-step explanation:

N* N = 81

N * N = 9*9

N = 9

N * P = 36

Substitute N = 9,

9* p = 36

    P = 36 ÷ 9

  P = 4

Answer:

Height of the triangle = 12 feet

Base of the triangle = 19 feet

Step-by-step explanation:

Let the height of the triangle be x feet

-> Base of the triangle = (x + 7) feet

[tex]A(\triangle)= 114\: ft^2[/tex]

[tex]\because A(\triangle)=\frac{1}{2}(base)(height) [/tex]

[tex]\implies 114=\frac{1}{2}(x+7)(x) [/tex]

[tex]\implies 114\times 2= x^2+7x[/tex]

[tex]\implies 228= x^2+7x[/tex]

[tex]\implies x^2+7x-228=0[/tex]

[tex]\implies x^2+19x-12x-228=0[/tex]

[tex]\implies x(x+19)-12(x+19)=0[/tex]

[tex]\implies (x+19)(x-12)=0[/tex]

[tex]\implies (x+19)=0,\:\:(x-12)=0[/tex]

[tex]\implies x =-19,\:\:x=12[/tex]

x represents the height of the triangle.

-> x can not take negative value.

[tex]\implies x\neq -19[/tex]

[tex]\implies x = 12[/tex]

[tex]\implies x +7= 12+7=19[/tex]

Thus,

Height of the triangle = 12 feet

Base of the triangle = 19 feet

[tex]\text{Area of equilateral triangle ABC}\\ \\=\dfrac{\sqrt 3}{4} BC^2\\\\=\dfrac{\sqrt 3}4 \cdot 12^2\\\\=\dfrac{144\sqrt 3}{4}\\\\=36\sqrt 3[/tex]

We are given the equation of circle (x - 7)² + (y - 3)² = 64² , but let's recall the standard equation of circle i.e (x - h)² + (y - k)² = r², where (h, k) is the centre of the circle and r being the radius ;

So, consider the equation of circle ;

[tex]{:\implies \quad \sf (x-7)^{2}+(y-4)^{2}=(64)^{2}}[/tex]

On comparing this equation with the standard equation of Circle, we will get, centre and radius as follows

Answer:

a∥b, Converse of the Alternate Interior Angles Theorem

Answer:

D.)25 children and 75 adults

Equation 1: a + c = 100

Equation 2: 3a + 2c = 275

Step-by-step explanation:

A team t-shirt costs $3 per adult and $2 per child.

Let the number of children be = c

Let the number of adults be = a

A team t-shirt costs $3 per adult that is 3a and $2 per child that is 2c, also given is that the total money collected is $275, so equation becomes:

On a certain day, the total number of adults (a) and children (c) who bought shirts was 100, equation becomes:

Now to know the number of children and adult, we can check by plugging in the values from options provided.

25 children and 75 adults  = 25(2)+75(3)=50+225 =275

Answer:

4

Step-by-step explanation:

Find the least common multiple of those two denominators, which would be 2 and 4.

Then do LCM of 2 and 4 and that should be 4.

Step-by-step explanation:

the area is the sum of the top square of 9×9 and the bottom parallelogram.

we know the length of the parallelogram is still also the square side length : 9ft.

but we don't need to bother about the lengths of the inclined sides, as the area of a parallelogram is

baseline × height

and the height we can see on the right hand side, as the height of the total shape is 14ft. given that the square side length is 9ft, that leaves us with 14-9 = 5ft as the height of the parallelogram.

so, the area of the square is

9×9 = 81 ft²

the area of the parallelogram is

9×5 = 45 ft²

the total area is then

81 + 45 = 126 ft²

Step-by-step explanation:

Given point are: P(at², 2at)

Q(a/t², 2a/t)

S(0, 0)

Now, the distance between A(x₁y₁) and B(X₂, y₂)

then AB = √{(x₂ - x₁)² + (y₂ - y₁)²} units

(i) The distance between S and P:

(x₁, y₁) = (0, 0) ⇛x₁= 0, y₁ = 0

(x₂, y₂ ) = (at², 2at) ⇛x₂ = at², y₂ = 2at

SP = √{at² - 0)² + (2at - 0)²}

= √{(at²)² + (2at)²}

= √{a²t²*² + 4a²t²}

= √{a²t⁴ + 4a²t²}

= √{a²t²(t²+4)}

SP = at√(t² + 4)→→→Eqn(1)

(ii) The distance between S and Q :

(x₁, y₁) = (0, 0) ⇛x₁= 0, y₁ = 0

(x₂, y₂ ) = (a/t², 2a/t) ⇛x₂ = a/t², y₂ = 2a/t

SQ = √[{(a/t²) - 0} + {(2a/t) - 0}

= √{(a/t²)² + (2a/t)²}

= √{(a²/t²*²) + (4a²/t²)}

= √{(a²/t⁴) + (4a²/t²)}

= √{(a² + 4a²t²)/t⁴}

= √[{a²(1 + 4t²)}/t⁴]

SQ = (a/t²)√(1 + 4t²) →→→ Eqn(2)

Now,

(1/SP) + (1/SQ) = [1/{at√(t² + 4)}] + [1/{(a/t²)√(1 + 4t²)}]

= (1/at)[1/{√(t² + 4)}] + (t²/a)[1/{(√1 + 4t²)}]

= (1/a)[[1/{t√(t² + 4)}] + [t²/{√(1 + 4t²)}]]

(1/SP) + (1/SQ) = 1/a is not independent of 't'

If suppose S = (a, 0) then

SP = √{(at² - a)² + (2at - 0)²}

= √{a²(t² - 1)² + (2at)²}

= a√{(t² - 1)² + 4t²}

= a√{(t² + 1)²}

SP = a(t² + 1)

1/SP = 1/{a(t² + 1)} →→→Eqn(1)

And

SQ = √[{(a/t²) - a}² + {(2a/t) - 0}²]

= √[a²{(1/t²) - 1}² + a²(2/t)²]

= a√[{(1 - t²)²/t⁴} + (4/t²)]

= a√[{(1 - t²)² + 4t²}/t⁴]

( a/t²)√(1 + t²)²

SQ = (a/t²)(1 + t²)

1/SQ = 1/{(a/t²)(1 + t²)} = t²/{a(1 + t²)} →→→Eqn(2)

Therefore, (1/SP) + (1/SQ)

= 1/{a(t² + 1)} + t²/{a(1 + t²)}

= (1 + t²)/a(1 + t²)

= 1/a

1/a is independent of 't'.

[tex]\text{R.H.S}\\\\=4\sin 45^{\circ} \cos 15^{\circ} \\\\=4\sin 45^{\circ} \cos (45^{\circ}-30^{\circ})\\ \\=4 \sin 45^{\circ} \left(\cos 45^{\circ} \cos 30^{\circ} +\sin 45^{\circ} \sin 30^{\circ} \right)\\\\=4 \left(\sin 45^{\circ} \cos 45^{\circ} \cos 30^{\circ} +\sin^2 45^{\circ} \sin 30^{\circ} \right)\\[/tex]

[tex]=4\left[\dfrac 1{\sqrt 2} \cdot \dfrac 1{\sqrt 2} \cdot \dfrac{\sqrt 3}2 +\left( \dfrac 1{\sqrt 2} \right)^2 \cdot \dfrac 12 \right]\\ \\=4\left(\dfrac{\sqrt 3}4 +\dfrac 14\right)\\\\=4\cdot \dfrac 14 \left(1+\sqrt 3\right)\\\\=1+\sqrt 3\\\\=\text{L.H.S}[/tex]