Identify the rule that correctly describes each
sequence.
12, 8, 4, 0, -4, ...
Each term is 4 more than the previous term.
Each term is 4 less than the previous term.
Each term is 1/2 the previous term.
Each term is 2/3 the previous term.
6, 12, 24, 48, 96, ...
Each term is 6 more than the previous term.
Each term is 12 more than the previous term.
Each term is 1/2 the previous term.
Each term is 2 times the previous term.
COMPLETE
COMPLETE
here’s the answers

Answer:

x=  12

Step-by-step explana

2x = 20 +  4

2x=  24

x= 2 4/2

x= 12

Answer:

2 is the base

Step-by-step explanation:

2^3

2 is the base and 3 is the exponent

Answer:

x = 30

Step-by-step explanation:

I'm going to assume the equation you needed help with was:

[tex]\frac{1}{2}(x+6) = 18[/tex]

If not, let me know and I'll redo it.

[tex]\frac{1}{2} x+3 = 18\\\frac{1}{2} x = 15\\x = 30[/tex]

Answer:

5h+6=16

Step-by-step explanation:

He gets 6 dollars and for every hour he walks he gets 5 dollars so he must of walked dogs for 2 hours and plug it in you get your equation.

Answer:

5(2)+6=16

Step-by-step explanation:

That should be it! Contact me if you need to know why.

Given:

A figure of a triangle.

To find:

The measure of angle A.

Solution:

Label the points in the figure as shown below.

In the below figure,

[tex]\angle ACB\cong \angle DCE[/tex]            (Vertically opposite angles)

[tex]m\angle ACB=m\angle DCE[/tex]              (Congregant angles)

[tex]m\angle ACB=8x+4[/tex]

Using exterior angle theorem in triangle ABC, we get

[tex]m\angle A+m\angle C=\text{Exterior }m\angle B[/tex]

[tex]m\angle BAC+m\angle ACB=130^\circ[/tex]

[tex](3x-6)+(8x+4)=130^\circ[/tex]

[tex]11x-2=130^\circ[/tex]

Isolate the variable term x.

[tex]11x=130^\circ+2[/tex]

[tex]11x=132^\circ[/tex]

[tex]x=\dfrac{132^\circ}{11}[/tex]

[tex]x=12^\circ[/tex]

Now, the measure of angle A is:

[tex]m\angle A=3x-6[/tex]

[tex]m\angle A=3(12^\circ)-6[/tex]

[tex]m\angle A=36^\circ-6[/tex]

[tex]m\angle A=30^\circ[/tex]

Therefore, the correct option is B.

Answer:

cos2x=sinx

<=> 1-2sin^{2}x =sinx

solve and we have x=3pie/2, x=pie/6,x= 5pie/6

Step-by-step explanation:

Answer:

3x+2

Step-by-step explanation:

khan told me that my explanation

Answer:

She kicked it up

Step-by-step explanation:

How is this math?

I believe your answer is B.) She kicked it up. Think about it, if she kicks it straight up, it goes up ten feet, and then it comes back down (Revered direction) to her.

Answer:

[tex]-\frac{17}{15}[/tex]

Step-by-step explanation:

By definition, [tex]\cot \theta=\frac{1}{\tan \theta}[/tex] and [tex]\sec \theta=\frac{1}{\cos \theta}[/tex]. Since since [tex]\cot \theta[/tex] is negative, [tex]\tan \theta[/tex] must also be negative, and since [tex]\sin \theta[/tex] is positive, we must be in Quadrant II.

In a right triangle, the sine of an angle is equal to its opposite side divided by the hypotenuse. The cosine of an angle in a right triangle is equal to its adjacent side divided by the hypotenuse. Therefore, we can draw a right triangle in Quadrant II, where the opposite side to angle theta is 8 and the hypotenuse of the triangle is 17.

To find the remaining leg, use to the Pythagorean Theorem, where [tex]a^2+b^2=c^2[/tex], where [tex]c[/tex] is the hypotenuse, or longest side, of the right triangle and [tex]a[/tex] and [tex]b[/tex] are the two legs of the right triangle.

Solving, we get:

[tex]8^2+b^2=17^2,\\b^2=17^2-8^2,\\b^2=\sqrt{17^2-8^2}=\sqrt{225}=15[/tex]

Since all values of cosine theta are negative in Quadrant II, all values of secant theta must also be negative in Quadrant II.

Thus, we have:

[tex]\sec\theta=\frac{1}{\cos \theta}=-\frac{1}{\frac{15}{17}}=\boxed{-\frac{17}{15}}[/tex]

Answer:

Fifty - one billion two hundred one thousand seventy eight

- Let me know if you have any questions regarding my answer :)

Answer:

[tex]\huge\boxed{\boxed{\underline{\textsf{\textbf{Answer}}}}}[/tex]

[tex]\boxed{51,000,201,078}[/tex]

⟹ Fifty one billion two hundred and one thousand seventy eight.

⁺˚*･༓☾✧.* ☽༓･*˚⁺‧

ʰᵒᵖᵉ ⁱᵗ ʰᵉˡᵖˢ

꧁❣ ʀᴀɪɴʙᴏᴡˢᵃˡᵗ2²2² ࿐

Answer:

m = - 2

Step-by-step explanation:

First coordinate : ( -2 , 9 )

Second coordinate : ( 1 , 3 )

Formulae : m=(y2-y1)/(x2-x1)

Substituting,

m = ( 3 - 9 ) / ( 1 + 2 )

m = - 6 / 3

m = - 2

If this helps you, please mark brainliest!

Answer:

Step-by-step explanation:

Answer:

D

Step-by-step explanation:

The starting term is a1.

That's the very first term.

a1 = - 10

The second term = -17 which means that you added - 7 to - 10.

So d must be - 7

The formula must be

an = a1 + (n - 1)*d

an = -10 + (n - 1)(-7)

You might wonder why it is n - 1. The reason is because the first term is already added on the right side. The -1 means that we have already included the first term.

We should try the formula out to see what it does. Let's find a4

a4 = -10 + (4 -1)*-7

a4 = -10 + 3(-7)

a4 = -10 - 21

a4 = - 31 which is what the question suggests.

Area of triangle = 1/2 bh

60 = 1/2 (15) h

8 = h

Quadrilateral area = h x (b1 + b2)/2 = 8 x (15+9)/2 = 96 sq units

96 -60 = triangle BAD area = 36 sq units

The length of side BC in the triangle BCD is 8.

An area is the amount of space occupied by a two dimensional shape or figure.

From the diagram:

Area of triangle BCD = (1/2) * base * height = (1/2) * CD * BC

60 = (1/2) * 15 * BC

BC = 8

The length of side BC in the triangle BCD is 8.

Find out more on area at: https://brainly.com/question/25292087

Answer:

easy

Step-by-step explanation:

9514 1404 393

Answer:

  x -3y = 4

Step-by-step explanation:

A plot of the points reveals the longer diagonal to be BD. (Also, point C is on that line.)

We can write the standard form equation of the line through (x1, y1) and (x2, y2) as ...

  (y2 -y1)x -(x2 -x1)y = (y2 -y1)x1 -(x2 -x1)y1

For points (-2, -2) and (16, 4), this equation is ...

  (4 -(-2))x -(16 -(-2))y = (4 -(-2))(-2) -(16 -(-2))(-2)

  6x -18y = -12 +36

Dividing by the greatest common factor (6), we have the standard-form equation ...

  x -3y = 4

Answer:

B

Step-by-step explanation:

- y = 7 , that is y = - 7

Is a horizontal line parallel to the x- axis and passing through all points with a y- coordinate of - 7

Answer:

[tex]{ \tt{line : x = 2y + 5}} \\ { \tt{circle : {x}^{2} + {y}^{2} = 5}} \\ substitute \: line \: in \: circle \\ { \tt{ {(2y + 5)}^{2} + {y}^{2} = 5 }} \\ { \tt{4 {y}^{2} + 20y + 25 + {y}^{2} = 5}} \\ { \tt{5 {y}^{2} + 20y + 20 = 0 }} \\ { \tt{ {y}^{2} + 4y + 4 = 0 }} \\ y = - 2 \\ x = 2( - 2) + 5 = 1 \\ { \tt{centre = ( - 1, \: 2)}} \\ { \tt{radius = 5 \: units}} \\ hence \: proved[/tex]

Answer:

radius 5

centre -1,2

Step-by-step explanation:

Answer:

(5,20)

Step-by-step explanation:

Looking at the pair, we can see that the value of y is simply the value of x multiplied by 4

so we have to multiply the value of x by 4 to get the value for y

So any of the options we can see this proportional relationship is correct

Looking at the options, we can see the third option. (5,20)

20/5 is 4 which makes the option correct

Step-by-step explanation:

In the second step while opening the bracket, instead of 'a', there should be - 4a.

Answer:

From Step 2 every step is wrong

Step-by-step explanation:

Ste p 1 : 3a - 5b = 12 - 4(b + a)

Step 2 : 3a - 5b = 12 - 4b - 4a      [ Last term instead - 4a she\he wrote + a ]

Step 3 : 7a  - 5b = 12 - 4b

Step 4 : 7a = 12 + b

[tex]Step 5 : a = \frac{12 + b}{7}[/tex]

Answer:

-5

Step-by-step explanation:

For a given x value a function can have only one y value.

-5 cannot have both 15 and 20 as the y value

Answer:

C

Step-by-step explanation:

the domain is for which values of x is that function defined (is that a valid function).

the range is what values that function can produce based on all the different x-values as input.

so, checking option A

that means all x values are negative.

that means all values inside the square root are negative.

the resulting function values are a discussion class of numbers and not part of the interval of (0, infinity).

so, it cannot be A.

checking option B

the domain range includes the value 6 for x.

but that would make this function for x=6 an invalid expression of 1/0

so, it cannot be B.

checking option C

the value range for x (domain) is x>6 (and excluding x=6).

and the result range is all positive numbers including 0.

there is no violation of any function principle.

the answer is C.

checking option D

similar to C, but the result range is defined as all numbers, negative and positive.

but for the domain the function can never produce negative numbers.

so, it is not D.

Answer:

126cm²

Step-by-step explanation:

first divide the figure into two( rectangle and a triangle)

area of a rectangle=length x width

16cmx7xcm

112xcm²

area of a triangle=1/2base x height

1/2x7cmx(20-16)cm

1/2x7cmx(4)cm

14cm²

total area of the figure=area of rectangle+area of triangle

=112cm²+14cm²

=126cm²

hope this is helpful

Step-by-step explanation:

the answer is in the above image

Answer:

Step-by-step explanation:

VOLUME...

1) π*r^2*h

π*(2.5)^2 *h

(π)*(2.5)^2* 6

= 117.8

2) π*r^2*h + 1/2 *[(4/3) · π · r3]

(π)*(3)^2* 3 + 1/2 *[(4/3) · π · 3^3]

         84.8+ 56.5 = 141.41

3) (1/3) π*r^2*h

(1/3) π*3^2*h

3^2 + h^2 = 36

h = sqrt(27) = 5.1

(1/3) π*3^2*5.1

= 48.06

~~~~~~~~~~~~~~~~~~~~~~~~~~~

Height of 1/2 of glass #2

84.8+ 56.5 = 141.41

thus 1/2 of #2 = 70.5

70.5 - 56.6 = 14 (all of 1/2 sphere filled plus 14 into cylinder)

14/[(π)*(3)^2* 3]= .16 of the cylinder... 3*(0.16) =   .48

total height = 3.48

Answer:

1/9th

Step-by-Step Explanation:

The area is measured in units squared, then you have to square 1/3 which is 19th.

Answer:

1/9

Step-by-step explanation: i think so

Answer:

p = -29/2

Step-by-step explanation:

2p + 38 = 9

Subtract 38 from each side

2p + 38-38 = 9-38

2p = -29

divide by 2

2p/2 = -29/2

p = -29/2

Answer:

p=-14.5

Step-by-step explanation:

2p + 38 = 9

      -38    -38

2p = -29

[tex]\sqrt{2}[/tex]    [tex]\sqrt{2}[/tex]

p = -14.5