If a 5-kg object experiences a 10-N force for a duration of 0. 10-second then what is the impulse exerted by the force on the object? What is the momentum change of the object? What is the change in velocity for the object?

Answers

Answer 1

Answer:

orce = rate of change of momentum which is m a if the mass is constant

10 Newtons = change of momentum/0.10 second

so change of momentum = 1 kg m/s

by the way the change in speed would be 1/5 = .2 m/s

Explanation:

Answer 2

If a 5-kg object experiences a 10-N force for a duration of 0. 10-second then the impulse exerted by the force on the object would be 1 Ns, and the change in the momentum would be  1 Ns.

What is momentum?

It can be defined as the product of the mass and the speed of the particle, it represents the combined effect of mass and the speed of any particle, and the momentum of any particle is expressed in Kg m/s unit.

As given in the problem If a 5-kg object experiences a 10-N force for a duration of 0. 10-second then we have to find out what the impulse exerted by the force on the object.

P = force × time

  = 10 × 0.1

  = 1  Ns

Thus, If a 5-kg object experiences a 10-N force for a duration of 0. 10-second then the impulse exerted by the force on the object would be 1 Ns, and the change in the momentum would be  1 Ns.

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Related Questions

11. Which of the following is a type of energy
that is not involved in the human body's
everyday processes?
A. mechanical energy
B. nuclear energy
C. thermal energy
D. chemical energy

Answers

Answer:

nuclear

Explanation:

A: a type of mechanical energy is kinetic, which comes from velocity/movement

C: people produce heat

D: converting food energy into usable energy within the body

A 0. 5 kg mass on a 1-m-long string swings in a circle on a horizontal, frictionless table at a steady speed of 2 m/s. How much work does the tension in the string do on the mass during one revolution?

Answers

The tension does no (zero) work

F· S = W

Since the tension is perpendicular to the direction of motion, and there is no change in S the work done is zero.

Why does the spectroscopic parallax method only work for main sequence stars?.

Answers

Answer:

Only main sequence stars have a well-defined relationship between spectral type and luminosity.

Explanation:

Low-mass stars have much longer lifetimes than high-mass stars.

Two wave pulses move toward each other along a rope. two small triangular crests moving toward each other. which diagram shows the resulting wave when they cross at point x? a straight line. a triangular crest. a rectangular crest. a triangular trough.

Answers

The triangular crest. shows the resulting wave when they cross at a point x. The meeting point of two waves is known as wave interference ia x.

What is wave pulse?

A wave pulse is a short, non-periodic wave that is formed by a single energy input rather than a continuous or repeated energy input.

Wave interference is the result of multiple waves interacting. There are two types of interference: constructive and destructive.

The relative displacement of the waves is the difference between the two. Wave beats are frequently caused by wave interference.

Hence the triangular crest. shows the resulting wave when they cross at a point x.

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Answer:

B

Explanation:

Got it right on edge

4. Which best explains the function of the alveoli in the respiratory system?
Page 135
A. The alveoli help to keep the lungs healthy by providing a way for all the cells
in the lungs to obtain nutrients from the bloodstream
B. The alveoli help to keep the lungs inflated when you breathe out and make it
possible to absorb oxygen
C. The alveoli provide a large surface area for absorbing oxygen from the air and
releasing carbon dioxide wastes from the bloodstream
D. The alveoli provide a large surface area for absorbing oxygen from the air
when you breathe in and look like a bunch of grapes
a

Answers

Answer:

C

Explanation:

Alveoli are tiny functioning structures that compose your lungs. They help with respiration. They have a large total surface area, which is very useful for respiration. The more surface area there is, the more transactions can happen. Which means that breathing will be easier/faster when you have more alveoli. (Please rate this answer if you have time!)

WILL GIVE BRAINLEST!!! What is the magnification of a virtual image if the image is 10.0 cm from a mirror and the object is 20.0 cm from the mirror?

a. -2.0
b. 0.50
c. 2.0
d. -0.50

Answers

option D

hope it helps...!!!

Answer:

B.

Explanation:

You have to divide.
10.0/20.0 = 0.50

I apologize if it is incorrect-

I hope it helps! Have a great day!

Anygays-

A hot tungsten filament emit electromagnetic radiation within

Answers

A hot tungsten filament emit electromagnetic radiation within the bulb because the tungsten is present within the bulb.

What temperature does a tungsten filament glow at?

Due to its high melting point, tungsten can be heated to 3000°C where it glows white hot providing very good brightness due to the presence of argon.

So we can conclude that a hot tungsten filament emit electromagnetic radiation within the bulb.

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Electromagnetic radiation is made up of electromagnetic field waves. A hot tungsten filament emits electromagnetic radiation in the presence of Argon.

What is electromagnetic radiation?

Electromagnetic radiation is made up of electromagnetic field waves that travel through space carrying electromagnetic radiant energy. Radio waves, microwaves, infrared, light, ultraviolet, X-rays, and gamma rays are all examples of electromagnetic waves.

When tungsten is heated to a temperature of around 3000 °C, the tungsten starts to emit lights. Tungsten when used in a bulb as a filament then because of its high melting point when electricity is passed through it, it starts to shine white-hot and provides extremely good brightness due to the presence of argon.

Hence, A hot tungsten filament emits electromagnetic radiation in the presence of Argon.

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28. (a) A pendulum that has a period of 3.00000 s and that is located where the acceleration due to gravity is 9.79m/s2 is moved to a location where it the acceleration due to gravity is 9.82m/s2. What is its new period? (b) Explain why so many digits are needed in the value for the period, based on the relation between the period and the acceleration due to gravity.

The answer is "(a) 2.99541 s(b) Since the period is related to the square root of the acceleration of gravity, when the acceleration changes by 1% the period changes by (0.01)2=0.01% so it is necessary to have at least 4 digits after the decimal to see the changes." But please include the steps to each solution.

Answers

Answer:

See below ↓

Explanation:

Assuming the motion of a simple pendulum, the time period is given by

⇒ T = 2π√(L/g)⇒ T₁/T₂ = √(g₂/g₁)

The values we have

T₁ = 3 sg₁ = 9.79 m/s²g₂ = 9.82 m/s²

Solving

T₂ = T₁/√(g₂/g₁)T₂ = 3/√(9.82/9.79)T₂ = 3.004593 seconds

This many digits are needed because the acceleration is changed by a very small percentage (roughly 2 decimal places)So on taking the square root of the ratio of the gravity due to acceleration (2 values), 4 decimal places will be present at the very least


A compression spring with a spring constant of 200 N/m catches a ball that's falling with
kinetic energy of 0.5 J. How far will the spring compress to stop the ball?
Pls help It would be great if someone can show the steps too thank u

Answers

Answer:

distance of compression: 0.07071 m

Explanation:

[tex]\sf energy = \dfrac{1}{2} kx^2[/tex]

[tex]\rightarrow \sf 0.5= \dfrac{1}{2} (200)x^2[/tex]

[tex]\rightarrow \sf 0.5= (100)x^2[/tex]

[tex]\rightarrow \sf 5\ *\ 10^{-3}= x^2[/tex]

[tex]\rightarrow \sf x = \sqrt{5\ *\ 10^{-3}}[/tex]

[tex]\rightarrow \sf x =0.07071 \ m[/tex]

Explain diffraction at a single slit (light)

Answers

Answer:

At some point on say, the receiving screen, light emanating from the left side of the slit will be out of phase (a difference of 1/2 wavelengths) from   light coming from the center of the slit.

Thus for every point that is left of the center of the slit, there will be a point on the right side of the slit that is out of phase,

There will be no light on the screen at that particular point and thus there will be a dark fringe there.

That is the basic explanation for the appearance of dark and bright fringes on the receiving screen.

Part B
At your sink, turn on your faucet slowly, until you have achieved a steady drip, drip, drip of lukewarm water. Make sure you can visually see and count the drips. Align the center of the bar of soap with the dripping water and set it down. Make sure the soap is in a sturdy location and does not move during the experiment. The soap represents a rock, and the dripping faucet represents precipitation.

While the soap is being weathered, calculate the number of drips that hit it in a minute. Do this by using your stopwatch to count the number of drips that occur in 10 seconds, and then multiply that number by 6 (because there are 60 seconds in a minute, 6 × 10 = 60). What is the number of drips hitting your bar of soap per minute?

Answers

The experiment was conducted in my toilet wash hand sink with a bar soap 30 centimeter away from the faucet, the number of drips record per minute is 120 drips

Control Experimentation

Data

Number of Drips Recorded = 20 drips per 10 secondsIn one minute(60 seconds), the number of drips recorded will be

Calculation for the number of drips per minute

= 20*6

= 120 drips

What is Control Experiment

Control  experiment are carried out to minimize the effects of variables other than the independent variable

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A 10. 0 cm object is 5. 0 cm from a concave mirror that has a focal length of 12 cm. What is the distance between the image and the mirror? 3. 5 cm –3. 5 cm 8. 6 cm –8. 6 cm.

Answers

The distance between the image and the mirror is -8.6 cm

What is concave mirror?

A concave mirror has a reflective surface that is curved inward and away from the light source. Concave mirrors reflect light inward to one focal point.

Unlike convex mirrors, the image formed by a concave mirror shows different image types depending on the distance between the object and the mirror.

Let's use the mirror equation to solve the problem:

[tex]\dfrac{1}{f}=\dfrac{1}{d_o}+\dfrac{1}{d_i}[/tex]

where f is the focal length of the mirror,  the distance of the object from the mirror, and  the distance of the image from the mirror.

For a concave mirror, for the sign convention f is considered to be positive. So we can solve the equation for  by using the numbers given in the text of the problem:

[tex]\dfrac{1}{12}=\dfrac{1}{5}+\dfrac{1}{d_i}[/tex]

[tex]\dfrac{1}{d_i}=-\dfrac{7}{60}[/tex]

[tex]d_i=-8.6\ cm[/tex]

Where the negative sign means that the image is virtual, so it is located behind the mirror, at 8.6 cm from the center of the mirror.

Hence the distance between the image and the mirror is -8.6 cm

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After hearing about an accident on his normal route, mr. gujral checks for alternate routes to get to work. what type of circuit does this traffic situation model? a series circuit because there is more than one path a series circuit because there is only one path a parallel circuit because there is more than one path a parallel circuit because there is only one path

Answers

The type of circuit does this traffic situation model will be a parallel circuit because there is more than one path.

What is a parallel circuit?

A parallel circuit has branches that split the current such that just a portion of it passes through each branch.

The voltage or potential difference between each branch of a parallel circuit is the same, but the currents might differ.

A parallel circuit is having more than one path in order to reach it on time he has to take a different path.

Hence the type of circuit does this traffic situation model will be a parallel circuit because there is more than one path.

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Answer:

C) a parallel circuit because there is more than one path

Explanation:

C) a parallel circuit because there is more than one path

What do we call objects that form like a star (from a contracting gas cloud), but do not have enough mass to ignite hydrogen fusion in their centers

Answers

A brown dwarf is a starlike body that do do not have enough mass to ignite hydrogen fusion in their centers.

What is a brown dwarf?

Brown dwarf refer to a body of substellar that is not huge or big enough to undergo nuclear fusion of o hydrogen into helium in their cores. This formed when there is contraction of gases in the intercellar spaces. The have a mass between 13 to 80 times that of Jupiter.

Therefore, brown dwarf is a starlike body that do don't not have enough mass to ignite hydrogen fusion in their centers.

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Consider the following processes: The temperature of two identical gases are increased from the same initial temperature to the same final temperature. Reversible processes are used. For gas A the process is carried out at constant volume while for gas B it is carried out at constant pressure. The change in entropy:_________.
i. is greater for B
ii. is the same for A and B
iii. is greater for A only if the initial temperature is high
iv. is greater for A
v. is greater for A only if the initial temperature is low

Answers

The entropy at constant pressure is always greater than that at constant volume and the change in entropy for the two processes is greater for gas B.

Second law of thermodynamics

According to the second law of thermodynamics, entropy in the isolated system always stays the same or increases.

Since gas does work in isobaric (constant pressure) change processes, the entropy at constant pressure will be greater than that at constant volume.

Thus, for gas A the process is carried out at constant volume while for gas B that is carried out at constant pressure. The change in entropy is greater for gas B.

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A skateboarder initially has 5 kJ of kinetic energy. As she freewheels along a flat section of path, she does 400 J of work against friction and air resistance. Calculate her final kinetic energy.​

Answers

The final kinetic energy of the skateboarder after she freewheels and did work against friction on the flat section of the path is 4,600 J.

Conservation of energy

The final kinetic energy of the stakeboarder is determined by applying the principle of conservation of energy as shown below;

ΔK.E = -W

K.Ef - K.Ei = -W

where;

K.Ef is the final kinetic energyK.Ei is the initial kinetic energyW is work done

K.Ef = K.Ei - W

K.Ef = 5,000 J - 400 J

K.Ef = 4,600 J

Thus, the final kinetic energy of the skateboarder is 4,600 J.

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A direct current of 3.0 A flows through a circuit consisting of a battery and a 6.0 A resistor. Calculate the potential difference across the resistor. a​

Answers

Question :-

A Direct Current of 3.0 A flows through a Circuit consisting of a Battery and a 6.0 Ohm's Resistor. Calculate the Potential Difference across the Resistor .

Answer :-

Potential Difference is 18 Volt's .

Explanation :-

As per the provided information in the given question, we have been given that the Current of the Device is 3.0 Ampere . The Resistance is given as 6.0 Ohm's . And, we have been asked to calculate the Potential Difference .

As we know ,

V = I R

Where ,

V denotes to Potential DifferenceI denotes to CurrentR denotes to Resistance

Therefore , by Substituting the given values in the above Formula :-

[tex] \sf {\dag \: \: \: Potential \: Difference \: = \: Current \: \times \: Resistance} [/tex]

[tex] \sf {\Longrightarrow \: \: \: \sf Potential \: Difference \: = \: 3.0 \: \times \: 6.0} [/tex]

[tex] \sf {\Longrightarrow \: \: \: \sf Potential \: Difference \: = \: 3 \: \times \: 6} [/tex]

[tex] \bf {\Longrightarrow \: \: \: \bf {Potential \: Difference \: = \: 18 \: }} [/tex]

Hence :-

Potential Difference = 18 Volt's .

[tex] \underline {\rule {210pt}{4pt}} [/tex]

Additional Information :-

[tex] \Longrightarrow \: \: \: \sf {Voltage \: = \: Current \: \times \: Resistance} [/tex]

[tex]\Longrightarrow \: \: \: \sf {Current \: = \: \dfrac {Voltage}{Resistance} } [/tex]

[tex]\Longrightarrow \: \: \: \sf {Resistance \: = \: \dfrac {Voltage}{Current} } [/tex]

[tex] \underline {\rule {210pt}{4pt}} [/tex]

Note :-

Kindly Scroll the Screen from Right to Left for Better View .

A distant star gives off a visible range of light whose color depends on its temperature. Which model of light does this example support? O A. The interference model B. The particle model O C. The diffraction model OD. The wave model​

Answers

The statement 'a distant star gives off a visible range of light whose color depends on its temperature' is supported by the wave model​.

What is wavelength?

The wavelength can be defined as the periodic distance of a given wave that repeats in a constant way.

The emissivity of particles is a function of both wavelength and temperature of a given material/object. Visible wavelengths range from 700 nm to 400 nm (violet color).

Star temperature largely determines its color, blue stars are warmer than yellow and red stars, and red stars are cooler than yellow stars.

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The kinetic energy of a javelin is 81 J, and its speed is 9.0 m/s. What is its mass?

A. 0.5 kg

В. 1.0 kg

C. 2.0 kg

D 9.0 kg

help asap

Answers

Explanation:

[tex]kinetic \: energy = \frac{1}{2} m {v}^{2} [/tex]

[tex]81 = \frac{1}{2}m {(9)}^{2} [/tex]

[tex] \frac{81 \times 2}{81} = m[/tex]

[tex]m = 2kg[/tex]

Calculate the temperature for which the minimum escape energy is 15 times the average kinetic energy of an oxygen molecule. Answer in units of K.

Answers

The temperature for which the minimum escape energy is 15 times the average kinetic energy of an oxygen molecule is 10,684.4 K.

Conservation of energy

The temperature for which the minimum escape energy is 15 times the average kinetic energy of an oxygen molecule is determined by applying principle of conservation of energy as shown below;

E = K + U

E = K - GmM/R

0 = K - GmM/R

K = mgR

When the minimum escape energy is 15 times average kinetic energy;

15K = mgR

[tex]15 \times \frac{3}{2} kT = mgR[/tex]

where;

m is mass of oxygen per atom = (0.032 kg)/(6.02 x 10²³) = 5.316 x 10⁻²⁶ kg/atomg is acceleration due gravity = 9.8 m/s²R is radius of Earth = 6.371 x 10⁶ m.k is Boltzmanns’ constant =   1.38066 x 10⁻²³ J/K.

[tex]T = \frac{2mgR}{15 \times 3k} \\\\T = \frac{(2)(5.316 \times 10^{-26})(9.8)(6.371 \times 10^6)}{45(1.38066 \times 10^{-23})} \\\\T = 10,684.4 \ K[/tex]

Thus, the temperature for which the minimum escape energy is 15 times the average kinetic energy of an oxygen molecule is 10,684.4 K.

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(WILL MARK BRAINLIST) Pure substances can be made of atoms that are attracted to each other or atoms that are not attracted to each other. Which type of pure substance can create elaborate structures? (1 point)

Atoms that are attracted to each other because the bonds that form between them can support the creation of the structure.

Atoms that are attracted to each other because they will mix together to form a mixture with a different structure.

Atoms that are not attracted to each other because they will form bonds with each other and create a larger structure.

Atoms that are not attracted to each other because they will stay still and end up laying on top of each other. ​​​​​​

Answers

QUESTION;

→ Pure substances can be made of atoms that are attracted to each other or atoms that are not attracted to each other. Which type of pure substance can create elaborate structures?

SOLUTION;

Option c) Atoms that are not attracted to each other because they will form bonds with each other and create a larger structure.

a car starts from the rest and accelerates at 9.54m/s for 6.5 seconds. what is the distance covered by the car​

Answers

Answer:

= 201.53 meters

Explanation:

A car started from rest and accelerated at 9.54 m/s^2 for 6.5 seconds. How much distance was covered by the car?

Use the formula  d = [tex]\frac{at^{2} }{2} ,[/tex]

where d is the distance, t is the time and "a" is the acceleration.
[tex]d=\frac{9*54*6*5^{2} }{2} = 201.53 m[/tex]

Explain the terms boiling and boiling point.
How is the volume of water affected when it boils at 100°C.?


Don't spam.. ​

Answers

The particular temperature at which vaporisation occurs is known as the boiling point of liquid. Volume of water increases when it boils at 100° C. 1 cm3 of water at 100 ° C becomes 1760 cm3 of steam at 100 ° C.

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A small car with mass of 0.800 kg travels at a constant speed
on the inside of a track that is a vertical circle with radius 5.00
m. If the normal force exerted by the track on the car when it
is at the bottom of the track is 25 N,
a) What is the normal force on the car when it is at the (i)
top, (ii) rightmost and (iii) leftmost point of the track?
b) What is the speed of the car as it travels around the
vertical circle?

Answers

Answer:

The equation of equilibrium at the top of the vertical circle is:

\Sigma F = - N - m\cdot g = - m \cdot \frac{v^{2}}{R}

The speed experimented by the car is:

\frac{N}{m}+g=\frac{v^{2}}{R}

v = \sqrt{R\cdot (\frac{N}{m}+g) }

v = \sqrt{(5\,m)\cdot (\frac{6\,N}{0.8\,kg} +9.807\,\frac{kg}{m^{2}} )}

v\approx 9.302\,\frac{m}{s}

The equation of equilibrium at the bottom of the vertical circle is:

\Sigma F = N - m\cdot g = m \cdot \frac{v^{2}}{R}

The normal force on the car when it is at the bottom of the track is:

N=m\cdot (\frac{v^{2}}{R}+g )

N = (0.8\,kg)\cdot \left(\frac{(9.302\,\frac{m}{s} )^{2}}{5\,m}+ 9.807\,\frac{m}{s^{2}} \right)

N=21.690\,N

Jessie hits a foul ball
straight up in the air
during a softball game.
Assuming all energy is
conserved, at what height
did the 3 kg ball travel if it
had a velocity of 11 m/s?

Answers

Answer:

GPE=(3*11^2)/2

(3*121)/2

363/2

GPE=181.5J

Explanation:

A mass m on a frictionless plane, inclined at an angle θ with respect to the horizontal, is connected by a cord that runs parallel to the inclined plane and is wrapped around a flywheel of radius r and moment of inertia

[tex]i=\frac{3mr^{2}}{4}[/tex]

what is the acceleration of the mass down
the plane?

Answers

The acceleration of the mass down the plane is determined as (4mg sinθ)/(3mr²).

Conservation of angular momentum

The acceleration of the mass down the plane is determined by applying the principle of conservation of angular momentum.

Fr = Iα

where;

F is weight of the object parallel to the planer is the radius of the flywheelI is moment of inertiaα is angular acceleration

(mg sinθ)r = Iα

(mg sinθ)r = I(ar)

(mg sinθ) = I(a)

[tex]a = \frac{mg \times sin(\theta)}{I} \\\\a = \frac{mg \times sin(\theta)}{3mr^2/4} \\\\a = \frac{4mg \times sin(\theta)}{3mr^2}[/tex]

Thus, the acceleration of the mass down the plane is determined as (4mg sinθ)/(3mr²).

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(please answer) It is better to jump on a smooth, flat surface than on thick carpeting.

Question 5 options:
True
False

Answers

I believe the answer to your question would be True

I think it would have to be true.

If you travel for three hours at a speed of 30 km/h, how far will you go?

Answers

Distance = (speed) x (time)  <== This is important.  You should memorize it.

Distance = (30 km/hr) x (3 hr)

Distance = (30 x 3) (km/hr x hr)

Distance = 90 km

One billiard ball strikes another billiard ball, and they move away from each other
at a 90° angle. The momentums involved include (blank) of the velocity before and after the collision.
(A) only the direction
(C) the magnitude and direction
(B) only the magnitude
(D) the square of the magnitude

Answers

Answer:

C) The magnitude and direction

Explanation:

Velocity is a vector quantity, meaning that it has both magnitude and direction.

For the momentum, we look at both the direction of the ball (negative, positive) and the magnitude of the velocity (5 m/s, 10 m/s) when figuring out what to use for "v" in p = mv.

What type of charge is acquired when a rubber is rubbed with a fur

Answers

Answer:

The triboelectic charging process (a.k.a., charging by friction) results in a transfer of electrons between the two objects that are rubbed together. Rubber has a much greater attraction for electrons than animal fur.

Explanation:

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