Is triangle FHK similar to triangle GHJ? If so, which postulate or theorem proves these two triangles are similar?

Answer: 72 square units

Step-by-step explanation:

[tex]A=Bh=6(12)=72[/tex]

Answer:

72 SQUARE UNITS

Step-by-step explanation:

Answer:

m∠1 = 51°

m∠2 = 16°        

Step-by-step explanation:

First ,check the attached photo.

=================

In the right triangle ABC :

m∠1 = 90 - 39

       = 51°

……………………

In the right triangle ABD :

m∠2 = 90 - 74

       = 16°

Answer:

• ∠ 1 = 51°

• ∠ 2 = 16°

Step-by-step explanation:

•  ∠ 1, the 39° angle, and the right angle marked in red are angles of a triangle.

∴  ∠ 1 + 90° + 39° = 180°             [Angles in a triangle add up to 180°]

⇒ ∠ 1 = 180° - 90° - 39°

⇒ ∠ 1 = 51°

• The small triangle on the top-left of the image consists of ∠ 2, a right-angle (marked in red) and a 74° angle.

∴  ∠ 2 + 90° + 74° = 180°            [Angles in a triangle add up to 180°]

⇒ ∠ 2 = 180° - 90° - 74°

⇒ ∠ 2 = 16°

The percentage change in volume from cylinder A to cylinder B; D: 100%

Formula for Volume of a Cylinder is;

V = πr²h

Thus, volume of Cylinder A is;

V_a = π * 7² * 5

V_a = 245π

Thus, percentage change in volume is;

[245π/(490π - 490π)] * 100%

Percentage change in volume = 100%

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Answer:

100% increase

Step-by-step explanation:

I got it right on the test.

Answer:

(-1,-2)

Step-by-step explanation:

See attached graph.

In the quadrilateral ABCD, in which angle A = 60° and angle B = 50°. The measure of angles C and D are,

∠C = 200° and ∠D = 50°

In the quadrilateral ABCD, it is given that,

A = 60° and angle B = 50°

Now, since AC is the angle bisector of angles A and C, we have,

∠DAC = ∠BAC ......... (1)

And ∠ACD = ∠ACB ............ (2)

Also, AC divides the quadrilateral ABCD into two triangles, ΔABC and ΔACD.

In ΔABC, ∠BAC = 30° [from (2)] and ∠ABC = 50°

Using angle sum property of a triangle, we have,

∠BAC + ∠ABC + ∠ACB = 180°

⇒ 30° + 50° + ∠ACB = 180°

80° + ∠ACB = 180°

∠ACB = 180° - 80°

∠ACB = 100°

From (1), ∠ACD = ∠ACB = 100°

∠C = ∠ACD + ∠ACB

⇒ ∠C = 100° + 100°

∠C = 200°

Now, according to the angle sum property of a quadrilateral,

∠A + ∠B + ∠C + ∠D = 360°

Substituting the values of ∠A, ∠B, and ∠C, we get,

60° + 50° + 200° + ∠D = 360°

310° + ∠D = 360°

∠D = 360° - 310°

∠D = 50°

Hence, in quadrilateral ABCD, ∠C = 200° and ∠D = 50°

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Using an exponential function, it is found that there will be 32,768 bacteria after 3 hours.

An exponential function is modeled by:

[tex]y = ab^x[/tex]

In which:

For this problem, the parameters are:

a = 8, b = 4.

3 hours is 6 periods of 30 minutes, hence the amount is:

[tex]y = 8 \times 4^6 = 32768[/tex]

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Answer:

there are 6 people that need to sit down so let's see how we can fill those seeds we will start while finding seats for Alice and bob they can't sit next to each other so will remove one of the seeds them both in the remaining 5 then at a seat between them to ensure that they are not next to each other they are 5 ways to choose seat and 4 ways from those that we make giving 20 ways to seats

Step-by-step explanation:

once a lies and verb are ct we can arrange the remaining people in 4 is equal to 24 west in each other four seats for the total of 20 into 24 4 80 ways to seat everyone

Answer:

b.  -x + y = 0

Step-by-step explanation:

Direct variation:

Direct variation means "y varies directly as x”:

[tex]y \propto x \implies y=kx[/tex]

where k is the (non-zero) constant of variation.

To determine which of the given equations represents a direct variation, isolate y for each and compare with the direct variation equation.

Equation a

[tex]y=\dfrac{4}{3}x-2[/tex]

This is not a direct variation equation as there is an addition of -2.

Equation b

[tex]-x+y=0[/tex]

[tex]\implies y=x[/tex]

This is a direct variation equation where the constant of variation is 1.

Equation c

[tex]xy=8[/tex]

[tex]\implies y=\dfrac{8}{x}[/tex]

This is not a direct variation equation as y is inversely proportional to x.

Equation d

[tex]y=14[/tex]

This equation does not include the variable x, and so is therefore not a direct variation equation.

If y varies inversely with x then the line must be linear and increasing

And the y intercept must be 0 in y=mx+c

#1

c=-2

#2

Yes

#3

No

#4

Parallel to x axis no direct variation

10u + t is the expressions shows the value of the reversal of digits in a two digit number, t = the tens digit and u = the ones digit. This can be obtained by multiplying 10 with the tens digit and adding unit digit.

Given that, in a two digit number,

t = the tens digit

u = the ones digit

The expression for the digit will be ,

10×t + u = 10t + u

The value of its reversal,

u = the tens digit

t = the ones digit

10×u + t = 10u + t is the required expression

For example,

37 = 10×3 + 7 = 30 + 7 and its reverse 73 = 10×7 + 3 = 70 + 3

Hence 10u + t is the expressions shows the value of the reversal of digits in a two digit number, t = the tens digit and u = the ones digit.

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Answer:

d=(x^2-x^1)+(y^2-y^1)^2

Answer:

[tex]\mathfrak{Distance \: between \: two \:points}[/tex]

The distance between two points [tex]A(x_1,y_1)[/tex] and [tex]B(x_2,y_2)[/tex] is given by the formula,

[tex]AB= \sqrt{(x_2-x_1)^2+(y_2-y_1)^2 }[/tex]

Proof: Let X'OX and YOY' be the x-axis and y-axis respectively. Then, O is the origin.

Let[tex]A(x_1,y_1) [/tex] and [tex]B(x_2,y_2)[/tex]

be the given points.

Draw AL perpendicular to OX, BM perpendicular to OX and AN perpendicular to BM

Now,[tex]OL=x_1,OM=x_2,AL=y_1 \: and \: BM=y_2[/tex]

[tex] \therefore{AN=LM=(OM-OL)=(x_2-x_1)}[/tex]

[tex] \: \: \: BN=(BM-NM)=(BM-AL)=(y_2-y_1)[/tex]

In right angled triangle [tex] \triangle \: ANB[/tex],by Pythagorean theorem,

We have,

[tex] \: \: \: AB^2=AN^2+BN^2[/tex]

[tex]or,AB^2=(x_2-x_1)^2+(y_2-y_1)^2[/tex]

[tex] \therefore \: AB= \sqrt{(x_2-x_1)^2+(y_2-y_1)^2} [/tex]

Thus ,the distance between the points A(x_1,y_1) and B(x_2,y_2) is given by,

[tex] \implies \boxed{AB= \sqrt{(x_2-x_1)^2+(y_2-y_1)^2} }[/tex]

Answer:

π & 4-π

Step-by-step explanation:

Answer:

a) is the correct answer

Based on the interquartile range, the true statement about the box plots is: D. Number of calories in the packs of trail mix have a greater variation than the number of calories in the packs of crackers.

The interquartile range is the range of the box, which is the difference between the upper and lower quartile. Interquartile range is a measure of variation. The larger the value, the more the variation of the data.

Interquartile range for cracker = 85 - 75 = 10

Interquartile range for trail mix = 105 - 90 = 15

This means that the variation for trail mix is greater.

Therefore, the statement that is true is: D. Number of calories in the packs of trail mix have a greater variation than the number of calories in the packs of crackers.

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Answer:d

Step-by-step explanation:

=========================================================

Explanation:

You could use the AC method to factor this, but the quadratic formula is the most efficient route in my opinion. This will avoid any guess-and-check.

Compare the original equation to the form [tex]a\text{x}^2 + b\text{x} + c = 0[/tex]

We have a = 9, b = 6, and c = -8

Those values lead to...

[tex]\text{x} = \frac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\\text{x} = \frac{-6\pm\sqrt{(6)^2-4(9)(-8)}}{2(9)}\\\\\text{x} = \frac{-6\pm\sqrt{324}}{18}\\\\\text{x} = \frac{-6\pm18}{18}\\\\\text{x} = \frac{-6+18}{18} \ \text{ or } \ \text{x} = \frac{-6-18}{18}\\\\\text{x} = \frac{12}{18} \ \text{ or } \ \text{x} = \frac{-24}{18}\\\\\boldsymbol{\text{x} = \frac{2}{3} \ \text{ or } \ \text{x} = -\frac{4}{3}}\\\\[/tex]

Side notes:

Answer:

$92,250 per town

Step-by-step explanation:

See attached image.

The two towns may be connected with a straight line, the road, that can be made into the hypotenuse of a right triangle.  The twio sides are calculated from the coordinates and shown in the image.  Then use the phythagorean theorem to calculate the hypotenuse.  The towns are 12.3 km apart.  The total road cost would be:

 ($150,000/km)(12.3 km) = $1,845,000, or $92,250 per town.

The volume of the cylinder having diameter 12 cm and height of 4 cm is 452 [tex]cm^{3}[/tex].

Given diameter of cylinder be 12 cm and height of cylinder be 4cm.

We are required to find the volume of cylinder.

Volume is the quantity of substance a container can hold in its capacity.

Diameter=12 cm

Radius=6 cm (Radius is always equal to half of diameter)

Volume of cylinder=π[tex]r^{2} h[/tex]

We have to just put the values of r, h and π in the formula to get the volume of the cylinder.

Volume=π[tex](6)^{2} 4[/tex]

=3.14*4*36

=452.57 [tex]cm^{3}[/tex]

After rounding off we will get 452 [tex]cm^{3}[/tex].

Hence the volume of cylinder is 452 [tex]cm^{3}[/tex].

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Question is incomplete as it should include height of cylinder be 4cm.

The expression of the equation 4(x - 8) + y = 9(x - 2) in slope intercept form is; y = 5x + 14

We want to express 4(x - 8) + y = 9(x - 2) in slope intercept form of y = mx + b.

Let us expand the equation to get;

4x - 32 + y = 9x - 18

Isolate y to get;

y = 9x - 4x - 18 + 32

y = 5x + 14

Thus;

Slope = 5

y - intercept = 14

x - intercept = -2.8

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Answer:

[tex]y=2x+4[/tex]

Step-by-step explanation:

[tex](y-2)= 2(x-(-1))[/tex]

[tex](y-2)=2(x+1)[/tex]

[tex]y-2=2x+2[/tex]

[tex]y=2x+4[/tex]

Answer:

  A.  The volumes are the same, based on Cavalieri's principle.

Step-by-step explanation:

Cavalieri's principle tells us the volumes of solids will be identical if their cross sectional areas are identical at every height.

A right cylinder and an oblique cylinder of the same height and radius will both have circular cross sections of the given radius at any height. Since the radius is the same, the area of the circle is the same. Hence the requirements of Cavalieri's principle are met, and the cylinders have the same volume.

Using proportions, it is found that the seismic activity density for this state is of 0.0059 earthquakes per square mile.

A proportion is a fraction of a total amount, and the measures are related using a rule of three. Due to this, relations between variables, either direct or inverse proportional, can be built to find the desired measures in the problem.

In this problem, the density is the proportion given by the number of earthquakes divided by the area, hence:

424/71,300 = 0.0059 earthquakes per square mile.

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Answer:  Using proportions, it is found that the seismic activity density for this state is of 0.0059 earthquakes per square mile.

Step-by-step explanation:

Answer:

AB = 17, x = 6

Step-by-step explanation:

3x - 1 = 34 / 2

3x - 1 = 17

3x = 18

x = 6

AB = 17

x = 6

The exact value of the trigonometric relation sin(θ/2) is √[(1 + √(17)/5)) / 2]

Given data:

The trigonometric relation is :

sin(θ) = (2√2) / 5 and π/2 < θ< π

Using the half-angle identity for sine:

sin(θ/2) = ± √[(1 - cos(θ)) / 2]

To determine the sign, look at the quadrant in which theta lies. Since π/2 < θ< π, θis in the second quadrant, where the sine function is positive. Therefore, we take the positive sign.

Now, let's calculate the cosine of θ. Using the Pythagorean identity for sine and cosine, we have:

sin²(θ) + cos²(θ) = 1

(2√2/5)² + cos²(θ) = 1

8/25 + cos²(θ) = 1

cos²(θ) = 1 - 8/25

cos²(θ) = 17/25

Taking the square root:

cos(θ) = ± √(17)/5

Since theta is in the second quadrant, take the negative sign:

cos(θ) = -√(17)/5

Now, substituting the values into the half-angle identity, we get:

sin(θ/2) = ± √[(1 - cos(θ)) / 2]

sin(θ/2) = ± √[(1 - (-√(17)/5))) / 2]

sin(θ/2) = ± √[(1 + √(17)/5)) / 2]

Since θ is in the second quadrant, where the sine function is positive, take the positive sign:

sin(θ/2) = √[(1 + √(17)/5)) / 2]

Therefore, the exact value of sin(θ/2) is √[(1 + √(17)/5)) / 2].

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The amount of medication that stays in the bloodstream is the same at 3.04 hours for the two medications

The functions are given as:

[tex]f(x)=-1.25\cdot \ln{\left(\dfrac{1}{x}\right)}[/tex]

[tex]g(x)=-1.8\cdot\ln\left(\dfrac{2.1}{x}\right)[/tex]

Next, we represent both functions on a graph.

From the attached graph, we can see that both functions intersect at (11.34, 3.04)

This means that the amount of medication that stays in the bloodstream is the same at 3.04 hours for the two medications

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Complete question

A pharmaceutical scientist studying two medications wonders how long different amounts of each medicine stay in someone's bloodstream. The amount of time (in hours) one medication stays in the bloodstream can be modeled by [tex]f(x)=-1.25\cdot \ln{\left(\dfrac{1}{x}\right)}[/tex] where x is the initial amount of the medicine (in milligrams). The corresponding function for the other medication is [tex]g(x)=-1.8\cdot\ln\left(\dfrac{2.1}{x}\right)[/tex]. Here are the graphs of

Answer:

It gives the initial amount + It gives the solution

Step-by-step explanation:

It gives the initial amount + It gives the solution

We know from the graph given and the data provided that the function can automatically be proven true.

It cannot describe the amount of time as the data says X is how much of the medicine is given, not the time.

It can't be the equal ratio because, for example, 1 milligram of medicine doesn't equal 1h of time in the body.

All you need to do for this is educational guessing, reasoning, and the process of elimination. Hope this helped! have a great day :7)

Answer:

x = 2 ;   x = -8

Step-by-step explanation:

 [tex]\sf \ log_4 \ x +log_4 \ (x +6) = 2\\\\ log_4 \ (x)*(x +6) = 2\\\\[/tex]

    log₄  ( x² + 6x) = 2

                        4² = x² + 6x

         x² + 6x - 16 = 0

   x² - 2x + 8x - 16 = 0  

   x(x - 2) + 8(x - 2) = 0

       (x - 2) (x + 8)   = 0

x - 2 = 0  or x + 8 = 0

    x  = 2  or      x  = - 8

The primary goal of a data scientist is to create new questions using data.

In the data ecosystem, a data scientist is one who creates new questions using data.

Unlike a data scientist, a data analyst uses existing data questions to find answers through insightful analysis of data.

Data designers design databases and database-specific constructs, and the procedures for storing, retrieving, and deleting persistent objects.

Data engineers build data systems to collect, manage, and convert data into information for both data scientists and analysts.

Thus, the primary goal of a data scientist is to create new questions using data.

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a) scientist

b) engineer

c) designer

d) analyst

In the above question, (image attached) The option that shows the segments that are parallel, if any, if ∠EDA≅∠HCB is option A: None of these.

Note that by examining the the image if ∠EDA≅∠HCB, the two lines can never intersect even if they go a longer distance.

The reason why is that there are no parallel lines on it and as such, they cannot intercept.

Hence, In the above question, (image attached) The option that shows the segments that are parallel, if any, if ∠EDA≅∠HCB is option A: None of these.

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The quotient of 24x2y + 8xy2 + 8xy and -4xy is -6x - 2y - 2

The statement is given as:

Divide 24x2y + 8xy2 + 8xy by -4xy

The quotient is represented as:

Quotient = (24x^2y + 8xy^2 + 8xy)/(-4xy)

Factor out -4xy

Quotient = (-4xy)(-6x - 2y - 2)/(-4xy)

Evaluate the quotient

Quotient = -6x - 2y - 2

Hence, the quotient of 24x2y + 8xy2 + 8xy and -4xy is -6x - 2y - 2

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The circle E, circle F and circle G are the circles which are congruent (similar) to the circle A has a radius of 6.

Let us discuss about the structure of each circles.

The circle D has the secant with the length 12. The secant means the straight line joining two points on the circle. So, we can't conclude that the secant will always be the diameter. Hence, it has different shape compared to circle A.

The circle E has the radius with length 6. The radius is same as the radius of the circle A. So, it is similar to the circle A.

The circle D has the secant with the length 6. Similar to the condition of circle D, it is not congruent to circle A.

The circle F has the diameter with length 12. Which means, the radius of this circle is with length 6. Hence, it is similar to the circle A.

The circle G has the diameter with length 12. Which means, the radius of this circle is with length 6. Hence, it is similar to the circle A.

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Answer:

Circles E and F are congruent to circle A

The expression which expresses the number of square feet of wallpaper needed is 12[tex]x^{2}[/tex]-21.

Given that the length of family room is 3x, breadth be 3x , height be x and the length and breadth of door be 7 feet and 3 feet.

We are required to find the expression which shows the square feet of wallpaper needed for the walls of the family room.

Because the wallpaper is not usually used on the floor and the ceiling and on doors so we will deduct the area of ceiling , floor and door from the surface area of whole room or we will just find the area of four walls one by one and then deduct the area of door from it.

Area of four walls only=2(lh+bh)

=2(3x*x+3x*x)

=2(3[tex]x^{2}[/tex]+3[tex]x^{2}[/tex])

=2*6[tex]x^{2}[/tex]

=12[tex]x^{2}[/tex]

Area of door=length*breadth

=3*7

=21 [tex]feet^{2}[/tex]

Required area=12[tex]x^{2}[/tex]-21.

Hence the expression which expresses the number of square feet of wallpaper needed is 12[tex]x^{2}[/tex]-21.

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