Math a challenging subject, sigh...

Answer:

[tex]a = 18x[/tex]

Step-by-step explanation:

Given

[tex]\frac{1}{2}(a + d) = 10x[/tex]

[tex]\frac{1}{2}(b + c) = 8x[/tex]

[tex]\frac{1}{3}(b + c+d) = 6x[/tex]

Required

The value of (a)

We have:

[tex]\frac{1}{2}(a + d) = 10x[/tex] --- multiply by 2

[tex]\frac{1}{2}(b + c) = 8x[/tex] --- multiply by 2

[tex]\frac{1}{3}(b + c+d) = 6x[/tex] --- multiply by 3

So, we have:

[tex]\frac{1}{2}(a + d) = 10x[/tex]

[tex]a + d = 20x[/tex]

[tex]\frac{1}{2}(b + c) = 8x[/tex]

[tex]b + c = 16x[/tex]

[tex]\frac{1}{3}(b + c+d) = 6x[/tex]

[tex]b + c + d= 18x[/tex]

Substitute [tex]b + c = 16x[/tex] in [tex]b + c + d= 18x[/tex]

[tex]16x + d = 18x[/tex]

Solve for d

[tex]d = 18x - 16x[/tex]

[tex]d = 2x[/tex]

Substitute [tex]d = 2x[/tex] in [tex]a + d = 20x[/tex]

[tex]a + 2x = 20x[/tex]

Solve for (a)

[tex]a = 20x - 2x[/tex]

[tex]a = 18x[/tex]

1 hour is 60 minutes

6 hours x 60 = 360 total minutes

Divide total time by number of lessons:

360/8 = 45

Each lesson was 45 minutes

Answer:

[tex]MK\approx 87.7[/tex]

Step-by-step explanation:

By definition, similar polygons have corresponding sides in a constant proportion. Therefore, we can set up the following proportion (ratio of corresponding sides) to solve for [tex]MK[/tex]:

[tex]\frac{20}{13}=\frac{MK}{57},\\MK=\frac{57\cdot 20}{13}\approx \boxed{87.7}[/tex]

Answer:

87.7

Step-by-step explanation:

Like stated previously similar triangle have side lengths with common ratios

*Create a proportionality to solve for MK*

57/13 = MK / 20

Now solve for MK

Multiply each side by 20

57/13 * 20 = 87.7 ( rounded )

MK/20 * 20 = MK

We're left with MK = 87.7

Answer:

Exact Form: [tex]\frac{17}{6}[/tex]

Decimal Form: 2.83

Mixed Number Form: [tex]2 and 5/6[/tex]

Step-by-step explanation:

Answer:

[tex]1\frac{1}{10}[/tex]

Step-by-step explanation:

[tex]4\frac{1}{3}-2\frac{1}{2}[/tex]

[tex]4\frac{2}{6} -2\frac{3}{6}=1\frac{5}{6}[/tex]

[tex]1\frac{5}{6} =\frac{11}{6}[/tex]

[tex]1\frac{2}{3}=\frac{5}{3}[/tex]

[tex]\frac{11}{6}[/tex] ÷ [tex]\frac{5}{3} =[/tex]

[tex]\frac{11}{6} *\frac{3}{5}=[/tex]

[tex]\frac{11}{2}*\frac{1}{5} =[/tex]

[tex]=\frac{11}{10}[/tex]

[tex]=1\frac{1}{10}[/tex]

Hope this is helpful

Answer:

√20

Or

2√5

Step-by-step explanation:

It is very easy just substitute

It will be:

Answer:

[tex]Correct answer\\y=\frac{1}{2} x-4[/tex]

Step-by-step explanation:

[tex]y-\frac{-5+3}{2} =\frac{-1}{\frac{3-(-5)}{4-8} } (x-\frac{4+8}{2} )\\y+1=\frac{1}{2} (x-6)\\y=\frac{1}{2} x-4[/tex]

Answer:

[tex]cot\theta=-\frac{5}{12}[/tex]

Step-by-step explanation:

We are given that the point (5,-12) lies on the terminal side of an angle theta in standard position.

We have to find the exact value of [tex]cot\theta[/tex].

Let

Point (x,y)=(5,-12)

[tex]r=\sqrt{x^2+y^2}[/tex]

Substitute the values

[tex]r=\sqrt{5^2+(-12)^2}[/tex]

[tex]r=\sqrt{169}=13[/tex]

We know that

[tex]cot\theta=\frac{x}{y}[/tex]

Using values

[tex]cot\theta=-\frac{5}{12}[/tex]

Answer:

yes

Step-by-step explanation:

51 divided by 25

Answer:

The answer is "35.22".

Step-by-step explanation:

Let the given equation:

[tex]\to 130(x-38) +950 \% \times 38=0\\\\\to 130x- 4940+\frac{950}{100} \times 38=0\\\\\to 130x- 4940+9.5\times 38=0\\\\\to 130x- 4940+361=0\\\\\to 130x- 4579=0\\\\\to 130x= 4579\\\\\to x= \frac{4579}{130}\\\\\to x= 35.22[/tex]

Answer: $25

Step-by-step explanation: took the quiz

Answer:

D. f(t) = 192,345(1.04)^t

Step-by-step explanation:

I took the test and it was right.

Also that is the original price and when you look at exponential functions, the starting point or original price is always first the then rate of increase. The table just shows how it increased in year 1 and 2.

Hope this helps. :)

A function assigns the values. The function that best represents the value of the real estate after t years is f(t) = 192,345(1.04)^t. Thus, the correct option is D.

A function assigns the value of each element of one set to the other specific element of another set.

The initial cost of industrial real estate is $192,345, while the cost after one year is $200,038.80. Therefore, the rate of appreciation is,

[tex]\$200,038.80 = \$192,345(1+R)^t\\\\\$200,038.80 = \$192,345(1+R)^1\\\\\dfrac{\$200,038.80}{\$192,345}=(1+R)^t\\\\1.04 = 1 + R\\\\R = 0.04[/tex]

Hence, the function that best represents the value of the real estate after t years is f(t) = 192,345(1.04)^t. Thus, the correct option is D.

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Answer:

its true trust biggie on this one fam

Step-by-step explanation:

its true broski

Part one:

[tex]x^2-8x=-26[/tex]

Rewrite in the form [tex](x+a)^{2} =b[/tex]

[tex]\left(x-4\right)^2=-10[/tex]

[tex]\mathrm{For\:}f^2\left(x\right)=a\mathrm{\:the\:solutions\:are\:}f\left(x\right)=\sqrt{a},\:-\sqrt{a}[/tex]

Solve [tex]x-4=\sqrt{-10} : x=\sqrt{10} i+4[/tex]

Solve [tex]x-4=\sqrt{-10} : x=-\sqrt{10} i+4[/tex]

[tex]x=\sqrt{10}i+4,\:x=-\sqrt{10}i+4[/tex]

Part two:

[tex]x=\frac{-\left(-8\right)\pm \sqrt{\left(-8\right)^2-4\cdot \:1\cdot \:26}}{2\cdot \:1}[/tex]

Simplify [tex]\sqrt{\left(-8\right)^2-4\cdot \:1\cdot \:26}}: 2\sqrt{10} i[/tex]

[tex]=\frac{-\left(-8\right)\pm \:2\sqrt{10}i}{2\cdot \:1}[/tex]

Separate solutions

[tex]x_1=\frac{-\left(-8\right)+2\sqrt{10}i}{2\cdot \:1},\:x_2=\frac{-\left(-8\right)-2\sqrt{10}i}{2\cdot \:1}[/tex]

[tex]\frac{-(-8)+2\sqrt{10}i }{2*1} :4+\sqrt{10}i[/tex]

[tex]\frac{-(-8)+2\sqrt{10}i }{2*1} :4-\sqrt{10}i[/tex]

[tex]x=4+\sqrt{10}i,\:x=4-\sqrt{10}i[/tex]

The solutions are:-

[tex]x=4+\sqrt{10i}\\\\x=4-\sqrt{10i}[/tex]

What is the equation?

The definition of an equation is a mathematical statement that shows that two mathematical expressions are equal.

Here given equation is

[tex]x^2- 8x + 26 = 0\\\\x^2-8x=-26\\\\(x-4)^2=-10\\\\[/tex]

[tex](x-4)=[/tex]±[tex]\sqrt{-10}[/tex]

[tex]x=\sqrt{10}i+4\\\\x=-\sqrt{10}i+4[/tex]

So,

[tex]x=\frac{-b+-\sqrt{b^2-4ac}}{2a}\\\\x=\frac{8+-\sqrt{(-8)^2-4(1)(26)}}{2(1)}\\\\x=\frac{8+-\sqrt{(-8)^2-4(1)(26)}}{2(1)}\\\\x=\frac{8+-\sqrt{64-104}}{2}\\\\x=\frac{8+-2\sqrt{10i}}{2}\\\\x=\frac{2(4+-\sqrt{10i})}{2}\\\\x=4+\sqrt{10i}\\\\x=4-\sqrt{10i}[/tex]

Hence, the solutions are:-

[tex]x=4+\sqrt{10i}\\\\x=4-\sqrt{10i}[/tex]

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Answer:

y = 360 (1.03)^x

Step-by-step explanation:

Amount in account = principle * (1+ rate) ^ time

When the interest is annual

rate is in decimal form and time is in years

y = 360 ( 1+.03) ^x

y = 360 (1.03)^x

Answer:

4/3

Step-by-step explanation:

The formula is (y1-y2) /(x1-x2)

Answer:

slope = [tex]\frac{4}{3}[/tex]

Step-by-step explanation:

Calculate the slope m using the slope formula

m = [tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]

with (x₁, y₁ ) = (2, 2) and (x₂, y₂ ) = (- 1, - 2)

m = [tex]\frac{-2-2}{-1-2}[/tex] = [tex]\frac{-4}{-3}[/tex] = [tex]\frac{4}{3}[/tex]

Answer:

2 and -1

Step-by-step explanation:

sum = 2 + (-1)

= 1

product = 2 × ( -1)

= -2

2 Answers:

=====================================================

Explanation:

Let's go through the answer choices

---------------------------------

A)

The lowest point is y = 1, and the highest point is y = 27. Computing the midpoint gets us (yMin+yMax)/2 = (1+27)/2 = 28/2 = 14.

The midline of [tex]h(\theta)[/tex] is y = 14.

Consider that the parent function [tex]\cos(\theta)[/tex] has a midline of y = 0. The jump from y = 0 to y = 14 must mean [tex]h(\theta)[/tex] has a vertical shift of 14.

Choice A is true

---------------------------------

B)

The period is the length of the cycle. For the function [tex]h(\theta)[/tex], the function starts at [tex]\theta = 0[/tex] and repeats when it gets to [tex]\theta = \frac{\pi}{2}[/tex]. This is a difference of pi/2 units which is the period.

Choice B is false. It contradicts with choice E.

---------------------------------

C)

Choice C is false. The max for [tex]h(\theta)[/tex] is at y = 27

---------------------------------

D)

To figure out the amplitude, we can note the vertical distance from the midline y = 14 to the max is 27-14 = 13 units.

Or we can note the distance from the midline to the min is 14-1 = 13 units.

Or we subtract the min and max, and divide by 2:  (yMax-yMin)/2 = (27-1)/2 = 26/2 = 13

Either way, the amplitude is 13 units

Choice D is false.

---------------------------------

E)

Choice E is true. Refer to choice B to see why this is the case.

---------------------------------

Side note: one possible function is [tex]h(\theta) = 13\cos(4\theta+\pi) + 14[/tex]. The various pieces of that function (in)directly lead to the amplitude, period, and vertical shift.

The correct two options are h(Ф) has vertical shift of 14 and Choice E

The period of a fuction is x/2

A function is defined as the expression that set up the relationship between the dependent variable and independent variable.

Let's go through the answer choices

A)

The lowest point is y = 1, and the highest point is y = 27. Computing the midpoint gets us (yMin+yMax)/2 = (1+27)/2 = 28/2 = 14.

The midline of  is y = 14.

Consider that the parent function  has a midline of y = 0. The jump from y = 0 to y = 14 must mean  has a vertical shift of 14.

Choice A is true

B)

The period is the length of the cycle. For the function , the function starts at  and repeats when it gets to . This is a difference of pi/2 units which is the period.

Choice B is false. It contradicts with choice E.

C)

Choice C is false. The max for  is at y = 27

D)

To figure out the amplitude, we can note the vertical distance from the midline y = 14 to the max is 27-14 = 13 units.

Or we can note the distance from the midline to the min is 14-1 = 13 units.

Or we subtract the min and max, and divide by 2:  (yMax-yMin)/2 = (27-1)/2 = 26/2 = 13

Either way, the amplitude is 13 units

Choice D is false.

E)

Choice E is true. Refer to choice B to see why this is the case.

Side note: one possible function is h(Ф) = 13 Cos(4Ф + π) + 14 . The various pieces of that function (in)directly lead to the amplitude, period, and vertical shift.

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Answer:

82

Step-by-step explanation:

Answer:

82

Step-by-step explanation:

10 times 8.2 would be 82 so you just divide 82 by 10

Answer:

first

2/5m + 8/5

second

22/5

third

11

Answer:

Step-by-step explanation:

20000000000+3000000000+900000000+60000+8000+400+7

Answer:

B

Step-by-step explanation:

we rule out all other 3 by the simple fact that the side is 9

Answer:

A

Step-by-step explanation:

Answer:

A and B, every even number is divisible by two, C is odd

Add all the coins to get total coins:

6 + 8 + 12 + 3 = 29 total coins

Subtract dimes to find total of the coins that are not dimes:

29 -6 = 23

Probability of not picking a dime is the number of coins that aren’t dimes over total coins:

23/29

Answer:

La altura del prisma es 2,4 m.

Step-by-step explanation:

Para calcular el volumen de un prisma rectangular, es necesario multiplicar sus tres dimensiones, esto es, longitud*ancho*altura. El volumen se expresa en unidades cúbicas.

Entonces:

volumen= longitud*ancho*altura

En este caso, los datos conocidos son:

Reemplazando:

24 m³= 2,5 m* 4 m* altura

Resolviendo:

[tex]altura=\frac{24 m^{3} }{2,5 m*4m}[/tex]

[tex]altura=\frac{24 m^{3} }{10 m^{2} }[/tex]

altura= 2,4 m

La altura del prisma es 2,4 m.

Answer:

Mathew will earn $360.72 from his food

Step-by-step explanation:

We know that:

1 bushel of wheat = $5.40

And Matthew produced 66.8 bushels of heat this year

To find how much Matthew will earn from his field, multiply:

5.40 x 66.8 = 360.72

Therefore he will earn $360.72 from his field.

Hope thjs helps!

Answer:

x = 4

Step-by-step explanation:

Corresponding angles are congruent

4x + 44 = 6x + 36

44 = 2x + 36

8 = 2x

x = 4

Answer:

[tex]\rm\displaystyle \theta = \frac{\pi}{4} [/tex]

Step-by-step explanation:

we want to find the acute angle θ (as θ is between (0,π/2)) formed by the line y=-2x+4 and y=3x-3 to do so we can consider the following formula:

[tex] \displaystyle\tan( \theta) = \bigg| \frac{ m_{2} - m_{1} }{1 + m_{1} m_{2} } \bigg | [/tex]

[tex] \rm \displaystyle \implies\theta = \arctan \left( \bigg | \frac{ m_{2} - m_{1} }{1 + m_{1} m_{2} } \bigg | \right)[/tex]

From the first equation we obtain that [tex]m_1[/tex] is -2 and from the second that [tex]m_2[/tex] is 3 therefore substitute:

[tex] \rm\displaystyle \theta = \arctan \left( \bigg | \frac{ 3 - ( - 2) }{1 + ( - 2) (3)} \bigg | \right)[/tex]

simplify multiplication:

[tex] \rm\displaystyle \theta = \arctan \left( \bigg | \frac{ 3 - ( - 2) }{1 + ( - 6)} \bigg | \right)[/tex]

simplify Parentheses:

[tex] \rm\displaystyle \theta = \arctan \left( \bigg | \frac{ 3 + 2 }{1 + ( - 6)} \bigg | \right)[/tex]

simplify addition:

[tex] \rm\displaystyle \theta = \arctan \left( \bigg | \frac{ 5 }{ - 5} \bigg | \right)[/tex]

simplify division:

[tex] \rm\displaystyle \theta = \arctan \left( | - 1| \right)[/tex]

calculate the absolute of -1:

[tex]\rm\displaystyle \theta = \arctan \left( 1\right)[/tex]

calculate the inverse function:

[tex]\rm\displaystyle \theta = \frac{\pi}{4} [/tex]

hence,

the angle θ which is formed by the line y = -2x+4 and y = 3x-3 is π/4

(for more info about the formula refer the attachment thank you!)

Consider two vector-valued functions,

[tex]\vec r(t) = \left\langle t, -2t+4\right\rangle \text{ and } \vec s(t) = \left\langle t, 3t-3\right\rangle[/tex]

Differentiate both to get the corresponding tangent/direction vectors:

[tex]\dfrac{\mathrm d\vec r(t)}{\mathrm dt} = \left\langle1,-2\right\rangle \text{ and } \dfrac{\mathrm d\vec s(t)}{\mathrm dt} = \left\langle1,3\right\rangle[/tex]

Recall the dot product identity: for two vectors [tex]\vec a[/tex] and [tex]\vec b[/tex], we have

[tex]\vec a \cdot \vec b = \|\vec a\| \|\vec b\| \cos(\theta)[/tex]

where [tex]\theta[/tex] is the angle between them.

We have

[tex]\langle1,-2\rangle \cdot \langle1,3\rangle = \|\langle1,-2\rangle\| \|\langle1,3\rangle\| \cos(\theta) \\\\ 1\times1 + (-2)\times3 = \sqrt{1^2 + (-2)^2} \times \sqrt{1^2+3^2} \cos(\theta) \\\\ \cos(\theta) = \dfrac{-5}{\sqrt5\times\sqrt{10}} = -\dfrac1{\sqrt2} \\\\ \implies \theta = \cos^{-1}\left(-\dfrac1{\sqrt2}\right) = \dfrac{3\pi}4[/tex]

Then the acute angle between the lines is π/4.

Answer:

[tex]\displaystyle y=\frac{1}{4}x^2[/tex]

Step-by-step explanation:

Let (x, y) be a point on the parabola.

By definition, any point on the parabola is equidistant from the focus and the directrix

The distance from the focus is given by:

[tex]\begin{aligned} d&=\sqrt{(x-0)^2+(y-1)^2\\\\&=\sqrt{x^2+(y-1)^2}\end{aligned}[/tex]

The distance from the directrix is given by:

[tex]d=|y-(-1)|=|y+1|\text{ or } |-1-y|[/tex]

So:

[tex]\sqrt{x^2+(y-1)^2}=|y+1|^[/tex]

Square both sides. Since anything squared is positive, we can remove the absolute value:

[tex]x^2+(y-1)^2=(y+1)^2[/tex]

Square:

[tex]x^2+(y^2-2y+1)=y^2+2y+1[/tex]

Hence:

[tex]x^2=4y[/tex]

So, our equation is:

[tex]\displaystyle y=\frac{1}{4}x^2[/tex]