Multiply: (–4 + i)(2 – 3i)
a. –5 – 10i


b. –8 + 11i


c. –5 + 14i


d. –11 + 14i

The measures of missing angles in trapezoids are listed below:

Case 5: m ∠ J = 75°, Case 7: m ∠ T = 118°

In this question we must determine the measures of missing angles in trapezoids. There are two hints to determine the values of the missing angles:

Now we proceed to determine the missing angles in every trapezoid:

Case 5

m ∠ K + m ∠ J = 180°

21 · x + 15 · x = 180°

36 · x = 180°

x = 5

m ∠ J = 15 · x

m ∠ J = 15 · 5

m ∠ J = 75°

Case 7

m ∠ U = m ∠ T

m ∠ T = m ∠ U

m ∠ T = 118°

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The lines FE and GH are parallel to each orther.

What is congruent of the triangle?

The shapes maintain their equality regardless of how they are turned, flipped, or rotated before being cut out and stacked. We'll see that they'll be placed entirely on top of one another and will superimpose one another. Due to their identical radius and ability to be positioned directly on top of one another, the following circles are considered to be congruent.

Any two figures can be perfectly positioned over one another to demonstrate their congruence. The relationship between two figures that are said to be congruent is described using the word "congruence."

Given that

ΔPEI = ΔGHI

here ∠pie = ∠gih

PI =HI

GI=EI

So both triangles are congruent

So the FE║GH.

Hence the lines FE and GH are parallel to each orther.

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Answer:

No it is not an exponential function

Answer:

1.40p+2n=40

Step-by-step explanation:

Answer: x = 4

Step-by-step explanation:

Based on the given distances and angle measures, DE is congruent to XY, DF is congruent to ZX, and EF and ZY are congruent.

This means that:

[tex](4x-1)=15[/tex]

Simplify and solve for x.

[tex]4x-1=15\\4x=16\\x=4[/tex]

So, x = 4

Answer:

[tex]\displaystyle x=\frac{1}{5}y^2[/tex]

Step-by-step explanation:

[tex]\displaystyle r=5\cot(\theta)\csc(\theta)\\\\r=5\biggr(\frac{\cos(\theta)}{\sin(\theta)}\biggr)\biggr(\frac{1}{\sin(\theta)}\biggr)\\\\r=\frac{5\cos(\theta)}{\sin^2(\theta)}\\\\r^2=\frac{5r\cos(\theta)}{\sin^2\theta}\\\\r^2\sin^2(\theta)=5r\cos(\theta)\\\\(r\sin(\theta))^2=5x\\\\y^2=5x\\\\x=\frac{1}{5}y^2[/tex]

Answer:

- 4s - q + r

Step-by-step explanation:

that's right. You do not put the p since 3p and -3p cancel out to give zero. I'll solve the question for you:-

⇒3p-3p+2s-6s+2q-3q+8r-7r

add or subtract the like terms(terms having same variables), then out of the two like terms, put the sign of the greater number, for e.g. 2q-3q = -1q

⇒0 - 4s - 1q + 1r

⇒- 4s - q + r Answer

hope that helps...

Answer:

Step-by-step explanation:

if there is any triangle ABC and a,b,c are sides opposite angles A,B,C respectively , then

[tex]cos~A=\frac{b^2+c^2-a^2}{2bc} \\cos~B=\frac{c^2+a^2-b^2}{2ca} \\cos~C=\frac{a^2+b^2-c^2}{2ab}[/tex]

B=101

a= 3 cm

b=y

c=1 cm

use formula for cos B

cos 101=cos(90+11)=sin 11

[tex]-sin~11=\frac{1^2+3^2-y^2}{2 \times 3 \times 1} \\-6 \times sin~11=1+9-y^2\\y^2=10+6~sin~11\\y^2\approx 10+6\times 0.1908\\y^2 \approx11.1448\\y\approx3.338[/tex]

Answer:

2.16

Step-by-step explanation:

To find the length y:

Since we have an angle with two sides next to it, it is 'cosy', so we can use the cosine rule to find y. Let's make y = a for the formula.

Using the cosine formula:

a^2 = b^2 + c^2 - 2bc cos(A)

where b=1, c=3 and A=101

substitute these values in the formula:

a ^2 = 1^2 + 3^2 - 2(1)(3) × cos(101)

a ^2 = 4.647970...

Square root to find a:

a = √4.647970...

a = 2.16

thus, y = 2.16 to 3sf

Answer:

$26.19

Step-by-step explanation:

9% as a decimal is 0.09.

So, the fee is [tex](291)(0.09)=\$26.19[/tex].

Answer:

$26.19

Step-by-step explanation:

.09 x 291 = 26.19

the blank space must be 2 or x must be zero, I don't know what you mean by one solution

the blank must equal 2 because on the right side the coefficient of x is 2 so it must be same

Answer:

-3

Step-by-step explanation:

Answer: The slope whould be 3

Step-by-step explanation:

Graph the line using the slope and y-intercept, or two points.

Slope: 3

y-intercept:

(0,0)

x|y

----

0|0

1|3

The coordinates of the inflection points are (3, 0) and it concave upwards

From the question, we have the following parameters that can be used in our computation:

g(t) = t^2 - 27/t

Express properly

So, we have

g(t) = t² - 27/t

Calculate the second derivative

So, we have

g''(t) = 2 - 54/t³

Set the differentiated equation to 0

2 - 54/t³ = 0

So, we have

2t³ = 54

Divide by 2

t³ = 27

Take the cube roots

t = 3

Substitute t = 3 in g(t) = t² - 27/t

g(3) = 3² - 27/3

g(3) = 0

This means that the inflection point occurs at t = 3 and the coordinates of the inflection point are (3, 0)

Recall that

g''(t) = 2 - 54/t³

Next, we check if the second derivative exist at t = 0,

g''(0) = 2 - 54/0³

g(0) = undefined

The undefined value implies that the graph has a vertical inflection point at t = 0

And as such, the graph of the function is concave upward

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The solution for the question found using the double angle formula for cosine is -[tex]\frac{7}{25}[/tex].

What are double angle formulae?

There are some trigonometric formulas that are known as double angle formulae because they contain double angles, such as Sin 2x, Cos 2x, and Tan 2x.

The double angle formula for cosine is

Cos 2θ = Cos²θ - Sin²θ

           =2Cos²θ – 1

            = 1 – 2Sin²θ

Given sinθ = [tex]\frac{4}{5}[/tex]

         cos(2θ) = 1-2sin²θ = [tex]1-2[/tex]×( [tex]\frac {4}{5}[/tex])² = [tex]1-[/tex] [tex]\frac{32}{25}[/tex] = [tex]\frac{-7}{25}[/tex]

Therefore Cos(2θ) fund using double angle formula is -[tex]\frac{7}{25}[/tex]

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The solution for the question found using the double angle formula for cosine is -.7/-25

There are some trigonometric formulas that are known as double angle formulae because they contain double angles, such as Sin 2x, Cos 2x, and Tan 2x.

An angle is a measure of the amount of rotation between two rays or lines that share a common endpoint, called the vertex of the angle. The two rays or lines are called the sides of the angle, and the endpoint is called the vertex. The size of an angle is typically measured in degrees or radians, with one full rotation around a point (360 degrees or 2π radians) being equal to a full circle.

The double angle formula for cosine is

Cos 2θ = Cos²θ - Sin²θ

          =2Cos²θ – 1

           = 1 – 2Sin²θ

Given sinθ = 4/5

        cos(2θ) = 1-2sin²θ = 1-2×(4/5 )² =  1-32/25 = -7/25

Therefore Cos(2θ) fund using double angle formula is -

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Answer:

the quotient of g and 25 is g/15.

After simplification we got the above expression in the form 3f + 16m -56

The word "simplify" implies to turn something in a simpler form.

In mathematics, simplify an expression means write an expression in such a way that is comparatively less complicated than before. The main purpose of simplify an expression is to make it easy to solve as well as calculation.

3f + 8(2m-7)

we rearrange the expression by removing the parenthesis.

we remove the parenthesis by multiplying the factors.

3f + 8 × 2m - 8 × 7

3f + 16m -56

the above expression has no like terms to add or subtract so it is kept in this form.

Hence, 3f + 16m -56 is the simpler form.

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Elijah used 24 gigabytes memory on his cell.

Division method is used to distributing a group of things into equal parts. Division is just opposite of multiplications. For example, dividing 20 by 2 means splitting 20 into 2 equal groups of 10.

Given that;

Elijah used 3/4 of the memory on his cell phone memory card.

And, The memory card can hold 32 gigabytes.

Now,

Since, The memory card can hold 32 gigabytes.

And, She used 3/4 of the memory on his cell phone memory card.

Hence. The used memory = 3/4 of 32

                                         = 3/4 × 32

                                         = 3 × 8

                                          = 24 gigabytes

Thus, Elijah used 24 gigabytes memory on his cell.

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Answer:

54

Step-by-step explanation:

Multiply 9 (players per team) and 6 (teams in the league) to find the total players in the league.

9 times 6 = 54

On solving the provided question we can say that - the value of the trignometric function will be -cos(t)+2cosec(t)

The area of mathematics known as trigonometry examines the correlation between triangle side lengths and angles. The area first appeared in the Hellenistic era, around the third century BC. from the use of geometry in astronomical study. The area of mathematics known as exact methods deals with specific trigonometric functions and how they might be used in calculations. There are six popular trigonometric functions in trigonometry. Sine, cosine, tangent, cotangent, secant, and cosecant are their respective names and acronyms (csc). Studying the characteristics of triangles, particularly right triangles, is called trigonometry. The study of geometry, however, is the characteristics of all geometric figures.

here,

(sint(t) + cos(t))[tex]^{2}[/tex] =(sint +cost)(sint - cost)

=|  -cos(t)+2cosec(t) |

= -cos(t)+2cosec(t)

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Answer:

Step-by-Step:5 cars and 14 bikes

Answer:  The answer is SAS

An equation is y = -4x/3 + 10.

A graph of the equation is shown in the image attached below.

In order to write and graphically solve an equation that model this situation, we would assign variables to the number of pound of peaches and number of pounds of apples respectively, and then translate the word problem into algebraic equation as follows:

Next, we would translate the word problem into an algebraic equation as follows;

$2/pound × Pounds of peaches = 2x.

$1.50/pound × pounds of apples = 1.50y

Combining the two expressions above, we have the following:

2x + 1.50y = 15

Making y the subject of formula, we have:

1.50y = 15 - 2x

y = (15 - 2x)/1.50

y = -4x/3 + 10

Therefore, an equation in slope-intercept form that relates the variables is y = -4x/3 + 10.

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The polynomial x⁴ + 3x³ - x - 2 will have a remainder of 1 when divided by x + 1 and the result can be written in the form (x³ + 2x² + 2x - 3) + 1/(x + 1).

Using the long division method will require us to; divide, multiply, subtract, bring down the next number and repeat the process to end at zero or arrive at a remainder

We shall divide the polynomial x⁴ + 3x³ - x - 2 by x + 1. as follows;

x⁴ divided by x equals x³

x + 1 multiplied by x³ equals x⁴ + x³

subtract x⁴ + x³ from x⁴ + 3x³ - x - 2 will result to 2x³ - x - 2

2x³ divided by x equals 2x²

x + 1 multiplied by 2x² equals 2x³ + 2x²

subtract 2x³ + 2x² from 2x³ - x - 2 will result to 2x² - x - 2

2x² divided by x equals 2x

x + 1 multiplied by 2x equals 2x² + 2x

subtract 2x² + 2x from 2x² - x - 2 will result to -3x - 2

-3x divided by x equals -3

x + 1 multiplied by -3 equals -3x - 3

subtract -3x - 3 from -3x - 2 will result to a remainder of 1.

Therefore, the polynomial x⁴ + 3x³ - x - 2 divided by x + 1 gives a quotient x³ + 2x² + 2x - 3 and a remainder of 1 and can be written as (x³ + 2x² + 2x - 3) + 1/(x + 1).

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The numbers which have only two factors either 1 and the number itself are called prime numbers.

Prime number is a natural number greater than 1 that is not a product of two smaller natural numbers while a natural number greater than 1 that is not prime is called a composite number

Therefore a prime number is a whole number greater than 1 whose only factors are 1 and itself. A factor is a whole number that can be divided evenly into another number. The first few prime numbers are 2, 3, 5, 7, 11, 13, 17, 19, 23 and 29

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Answer:

this should help you out

Answer:

  3x -y = 2

Step-by-step explanation:

You want a standard form equation for the line through the points (0, -2) and (2, 4).

The slope of the line is the "rise" divided by the "run". The given point on the right is 3 grid squares above the one on the left. It is one grid square to the right. So, the slope is ...

  m = (squares above)/(squares to the right) = 3/1 = 3

If we consider the actual x- and y-values represented by these grid squares, then the slope is ...

  m = (4 -(-2))/(2 -0) = 6/2 = 3

The point (0, -2) tells you the y-intercept is -2. That is where the line crosses the y-axis.

With this information, we can write the slope-intercept form equation for the line:

  y = mx +b . . . . . . . line with slope m and y-intercept b

  y = 3x -2 . . . . . . . . line with slope 3 and y-intercept -2

The standard form of an equation for a line is ...

  ax +by = c

where a, b, c are generally mutually-prime integers with a ≥ 0. If a=0, then b > 0.

We can rearrange the slope-intercept equation to put it into this form.

  y = 3x -2

  3x -y -2 = 0 . . . . . subtract y

  3x -y = 2 . . . . . . . add 2. This is the standard-form equation of the line.

A line that shows the number of hair barrettes she makes and the total number of beads she uses is y = 75x.

In order to put the equation in y-intercept (y=mx+b) form and determine the equation of a graphed line, you must first determine the slope and y-intercept. The slope is the ratio of the change in y to the change in x. Find two locations on the line, and then draw a sloping triangle joining them.

A line is a perfectly straight, one-dimensional figure that extends infinity in both directions and has no thickness. To stress that a line has no "wiggles" anywhere along its length, it is sometimes referred to as a straight line or, more archaically, a right line.

Two points on the line are (2, 150) and (5, 375)

y - 150 = ( (375-150) / (5-2) )  (x-2)

y - 150 = 75 (x-2)

y = 75x

Equation of line is y = 75x

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The best answer is to simplifying each of the identity separately to get the same expression on both sides. Option C

Trigonometric identities are described mathematically as equalities consisting of trigonometric functions that proves true for all the value of occurring variables for which both sides of equality are defined.

These involve certain functions of one, two or more angles.

They also are different from triangle identities, which involves angles and side lengths of a triangle.

To verify a trigonometric identity, we take the following steps;

Hence, the best option is C

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The quartic equation y = x⁴ - x³ - 5 · x² - x - 6 has x = - 2 and x = 3 as its only real zeros. (Correct choice: C)

Quartic equations are polynomials of grade 4, whose standard form is described below:

y = a · x⁴ + b · x³ + c · x² + d · x + e

Where a, b, c, d, e are real coefficients. A value of x is a zero of a polynomial when the result is equal to zero. The quickest way to find the polynomial is by evaluating each expression at x = - 2 and x = 3:

x = - 2

y = (- 2)⁴ - (- 2)³ - 5 · (- 2)² - (- 2) - 6

y = 16 + 8 - 20 + 2 - 6

y = 0

x = 3

y = 3⁴ - 3³ - 5 · 3² - 3 - 6

y = 81 - 27 - 45 - 3 - 6

y = 0

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