please help me
is for my daughter ​

Answer:

D produce energy

Explanation:

Mitochondria are membrane-bound cell organelles (mitochondrion, singular) that generate most of the chemical energy needed to power the cell's biochemical reactions.

Answer:produce energy

Explanation:

Answer:

A. Mass = 61kg, weight on moon = 97.8N

Explanation:

To calculate the weight (force) from Mass of a body, the following formula is used:

W = mg

Where;

W = weight (Newtons)

m = mass (kg)

g = acceleration due to gravity (9.8m/s²)

According to this question, a scale shows that I weigh 600N on Earth, the mass on Earth can be calculated thus:

Using W = mg

m = W/g

m = 600/9.8

m = 61.2

m = 61kg

However, this mass on Earth will weigh differently on the Moon because gravity in the moon is 1.6 N/kg. The weight of the 61kg on the Moon is:

W(moon) = mass × gravity

W = 61 × 1.6

W = 97.6 N

Therefore, Mass = 61kg, weight on moon = 97.8N

Answer:

Explanation:

C

2.00 M is the molarity of a solution made by dissolving 1.25 mol of HCl in enough water to make 625 mL of solution.

A mole is defined as 6.02214076 ×  of some chemical unit, be it atoms, molecules, ions, or others. The mole is a convenient unit to use because of the great number of atoms, molecules, or others in any substance.

[tex]Molality = \frac{Moles \;solute}{Volume \;of \;solution \;in \;litre}[/tex]

[tex]Molality = \frac{1.25}{0.625}[/tex]

Molality = 2.00 M

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Answer:

74.08 atm

Explanation:

We'll begin by converting 91.7 kg to grams (g). This can be obtained as follow:

1 kg = 1000 g

Therefore,

91.7 kg = 91.7 kg × 1000 g / 1 kg

91.7 kg = 91700 g

Next, we shall determine the number of mole present in 91700 g of methane, CH₄. This can be obtained as follow:

Mass of CH₄ = 91700 g

Molar mass of CH₄ = 12 + (4"1)

= 12 + 4

= 16 g/mol

Mole of CH₄ =?

Mole = mass /Molar mass

Mole of CH₄ = 91700 / 16

Mole of CH₄ = 5731.25 moles

Next, we shall convert 497.9 gallon to litres (L). This can be obtained as follow:

1 gallon = 3.785 L

Therefore,

497.9 gallon = 497.9 × 3.785

497.9 gallon = 1884.55 L

Next, we shall convert 23.7 ˚C to Kelvin temperature. This can be obtained as follow:

T(K) = T(˚C) + 273

T(˚C) = 23.7 ˚C

T(K) = 23.7 °C + 273

T(K) = 296.7 K

Finally, we shall determine the pressure in the tank as follow:

Number of mole (n) = 5731.25

Volume = 1884.55 L

Temperature (T) = 296.7 K

Gas constant (R) = 0.0821 atm.L/Kmol

Pressure (P) =?

PV = nRT

P × 1884.55 = 5731.25 × 0.0821 × 296.7

P × 1884.55 = 139607.92

Divide both side by 1884.55

P = 139607.92 / 1884.55

P = 74.08 atm

Therefore the pressure in the tank is 74.08 atm

Answer:

V = 5.97 L

Explanation:

Hello!

In this case, according to the ideal gas law:

[tex]PV=nRT[/tex]

We would need to solve for V as we know the temperature and pressure as the gas it at STP conditions (273 K and 1 atm respectively):

[tex]V=\frac{nRT}{P}[/tex]

Next, we compute the moles in 8 g of NO, given its molar mass of 30.01 g/mol:

[tex]n=\frac{8g}{30.01g/mol}=0.267mol[/tex]

Therefore, we obtain the following volume:

[tex]V=\frac{0.267mol*0.08206\frac{atm*L}{mol*K}*273K}{1atm}\\\\V=5.97 L[/tex]

Best regards!

Answer:

21 Kg of CO.

Explanation:

The balanced equation for the reaction is given below:

Fe₂O₃ + 3CO —> 2Fe + 3CO₂

Next, we shall determine the masses of Fe₂O₃ and CO that reacted from the balanced equation. This can be obtained as illustrated below:

Molar mass of Fe₂O₃ = (56×2) + (16×3)

= 112 + 48

= 160 g/mol

Mass of Fe₂O₃ from the balanced equation = 1 × 160 = 160 g

Molar mass of CO = 12 + 16 = 28 g/mol

Mass of CO from the balanced equation = 3 × 28 = 84 g

SUMMARY:

From the balanced equation above,

160 g Fe₂O₃ required 84 g of CO.

Finally, we shall determine the mass of of CO required for the reduction of 40 kg of Fe₂O₃. This can be obtained as follow:

From the balanced equation above,

160 g Fe₂O₃ required 84 g of CO.

Therefore, 40 Kg of Fe₂O₃ will require = (40 kg × 84 g) / 160 g = 21 Kg of CO.

Thus, 21 Kg of CO is required for the reaction.

Answer:

The mass of 0.063*10⁻⁴ moles of aluminum sulphate  is 2.15*10⁻³ grams.

Explanation:

Aluminum sulfate Al₂(SO₄)₃ has a molar mass of 342.15 g/mol.

Molar mass is the amount of mass that a substance contains in one mole of a substance, which can be an element or a compound.

So in this case you can apply the following rule of three: if 342.15 grams are present in 1 mole of aluminum sulfate, how much mass is present in 0.063*10⁻⁴ moles of the compound?

[tex]mass of aluminum sulphate=\frac{0.063*10^{-4}moles*342.15 grams }{1 mole}[/tex]

mass of aluminum sulphate= 2.15*10⁻³ grams

The mass of 0.063*10⁻⁴ moles of aluminum sulphate  is 2.15*10⁻³ grams.

Answer:

3, 9, 3

Explanation:

The coefficient of 3 tells us that there are three molecules (the chemical unit of NH3). Each molecule of ammonia (NH3) is made up of 1 atom of nitrogen bonded to 3 atoms of hydrogen.

Since there are three molecules, we have three times the amount of atoms there are in one molecule.

3 x 1 = 3 nitrogen

3 x 3 = 9 hydrogen

Answer:

The pressure of  H₂(g) = 741 torr

Explanation:

Given that:

The atmospheric pressure measured in the lab  = 765 torr

The vapor pressure of water = 24 torr

By applying Dalton's Law of Partial Pressure :

Making The Pressure inside the tube due to the H₂(g) the subject of the formula :

we have:

= (765 -24) torr

= 741 torr

According to ideal gas law and Dalton's law of partial pressure, 0.0136 moles of hydrogen are produced in the reaction.

The ideal gas law is a equation which is applicable in a hypothetical state of an ideal gas.It is a combination of Boyle's law, Charle's law,Avogadro's law and Gay-Lussac's law . It is given as, PV=nRT where R= gas constant whose value is 8.314.The law has several limitations.It is applicable to ideal gases which have hypothetical existence.Law was proposed by Benoit Paul Emile Clapeyron.

In the given problem, according to Dalton's law of partial pressure, pressure =765-24=741 torr

Substituting the given values in the ideal gas equation, n=PV/RT

n=741×45.6×10[tex]^-3[/tex]/8.314×298=0.0136 moles.

Thus 0.0136 moles of hydrogen are produced in the reaction.

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Answer:

ok so i did the problem and the answer was 8e+29

Explanation:

i dont really know what the answer is but thats the answer i got

sorry if this didnt help

Answer:

cover A

Explanation:

Answer:

cover sorry if im wrong

Explanation:

the cover makes the kiete float using air resisance

Answer:

32.4 kJ

Explanation:

Given that:

Specific heat capacity fo copper, c = 0.9

Mass of copper, m = 700 g

Temperature change, dθ ;t2 - t1 = (82.1 - 30.7) = 51.4

Energy required, E = mcdθ

E = 700 * 0.9 * 51.4

E = 32382 J

Energy required on kJ

32382 / 1000

= 32.382 kJ

= 32.4 kJ

Answer:

Explanation:what’s the answer

Answer: A. With Earth between the Moon and the Sun.

Explanation:

Answer:

false statements because they are all nonrenewable resources

Answer:

16 electrons in a sulfur atom. Looking at the picture, you can see there are two electrons in shell one, eight in shell two, and six in shell three.

Explanation:

Answer:

pH = 12.90

Explanation:

THe reaction of HNO₃ with KOH is:

HNO₂ + KOH → KNO₂ + H₂O

That means 1 mole of nitrous acid reacts per mole of potassium hydroxide.

To solve this question, we need to find the moles of each reactant:

Moles HNO₂:

0.0179L * (0.458mol / L) = 0.00820 moles

Moles KOH:

0.0334L * (0.368mol / L) = 0.01229 moles

That means KOH is in excess. The moles in excess are:

0.01229 moles - 0.00820 moles = 0.00409 moles KOH = Moles OH⁻

The [OH⁻] is -Total volume = 17.9mL+33.4mL = 51.3mL = 0.0513L-:

0.00409 moles / 0.0513L =

0.0797M =[OH⁻]

pOH = -log[OH⁻] = 1.098

pH = 14 - pOH

Answer:

A=-0.9117kJ.

B= -0.5065kJ

C=-0.8104KJ

Explanation: A s gas expands, it produces works . Therefore

Work done by gas expansion,

W  = P Δ V  

where P =external  pressure,

ΔV = change in volume (final - Initial)

W = -1 atm (10 - 1 ) L

W =  -9L. atm  x  101.3J/  1L. atm

W = 911.7Joules ≈ -0.9117kJ.

1.The work done in the first step is:

W= - 5.00 atm × (2.00 L - 1.00 L) = -5 atm·L ×(101.3J / 1 atm·L)

=506.5J = -0.5065kJ

2.The work done in the second step is:

w = - 1.00 atm × (10.0 L - 2.00 L) = -8atm·L ×(101.3J / 1 atm·L

=810.4J

w=-0.8104KJ

The work done in the whole  process is:

w =-0.5065kJ --0.8104KJ  = -1.3169KJ

Answer:

The answer is D.

Explanation:

I searched it up :)

Answer:

Explanation:

metamorphic

Answer:

give me branlist it is 120nh

Answer:

jbisibjas bhijjoijnc

Explanation:

Answer:

2kcl+ fe= Fecl2+2K

so coefficient required be 2 for kcl and 2 forK

Answer:

0.51 cal/g.°C

Explanation:

Step 1: Given data

Step 2: Calculate the temperature change

ΔT = 12.7 °C - 10.4 °C = 2.3 °C

Step 3: Calculate the specific heat of the liquid (c)

We will use the following expression.

c = Q / m × ΔT

c = 14 cal / 12 g × 2.3 °C = 0.51 cal/g.°C

The pressure is directly proportional to temperature (when the pressure decrease the temperature decrease too). Because the air parcel expands so the molecules will not interact with each other as much.

The energy of the particles does not change but the fact that the particles are more spaced out means the parcel is cooler.

so now, the warmer a parcel of air the more water vapor it can hold. so, if a parcel of air cools it's ability to hold water vapor drops and if it drops to a low enough point that is when the water vapor will condense and turn back into liquid water. This is how clouds and precipitation form on the the windward side of the mountain.

Clouds and precipitation form on the windward side of the mountain due to change in temperature and pressure.

Temperature of any substance is directly proportional to the pressure of that substance.

If the temperature of the wind increases so that winds get warmer and at the same time pressure of gas also increases, due to which particles will go far from each other. After this warm air rises up and cools down will condenses to form clouds, after this precipitate will falls on the windward side of the mountain.

Hence due to temperature and pressure precipitate will form on the windward side of the mountain.​

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Answer:

The amount of the first solution rick needs to mix together to create the love portion is 8.5 mL

Explanation:

So as to make the love potion, we have;

The percentage of carbonated water in the love portion = 40%

The percentage of green tea in the first solution = 65%

The percentage of carbonated water in the first solution = 15%

The percentage of whole milk in the first solution = 20%

The percentage of orange juice in the second solution = 17%

The percentage of lemonade in the second solution = 38%

The percentage of carbonated water in the second solution = 45%

Let 'x' represent the volume in mL of the first solution added to make the love portion, and let 'y' be the volume in mL of the second solution added to make the love portion, we have;

x + y = 51...(1)

0.15·x + 0.45·y = 0.40×51 = 20.4

0.15·x + 0.45·y = 20.4...(2)

Solving the system of simultaneous equation by making 'y' the subject of each of the equation gives;

For equation (1)

y = 51 - x

For equation (2)

y = 20.4/0.45 - (0.15/0.45)·x = 136 - 3·x

y = 136/3 - (1/3)·x

Equating the two equations of 'y', gives;

51 - x = 136/3 - (1/3)·x

51 - 136/3 = x - (1/3)·x

17/3 = (2/3)·x

(2/3)·x = 17/3

x = (3/2) × (17/3) = 17/2 = 8.5

x = 8.5

y = 51 - x = 42.5

y = 42.5

Therefore, the amount of the first solution rick needs to mix together to create the love portion, x = 8.5 mL