prt.3 identify the slope

Answer:

In 5 years I will have $ 1,151.71.

Step-by-step explanation:

To determine, if I put 700 into a savings account that's earns 1% interest compound monthly, how much will I have in 5 years, the following calculation must be performed:

700 x (1 + 0.01 / 12) ^ 12x5 = X

700 x (1 + 0.008333) ^ 60 = X

700 x 1.64530 = X

1,151.71 = X

Therefore, in 5 years I will have $ 1,151.71.

Answer:

A

Step-by-step explanation:

The formula is 5*x=4*10. Then simplify to 5*x=40. Divide both sides by 5. x=8

Answer:

Step-by-step explanation:

736

Step-by-step explanation:

three solutions of the equation:

y = -2x - 1

=>

1) (0, -1)

2) (1, -3)

3) ( -1, 1)

Answer: 28

Step-by-step explanation: 5(4)-4(-2) which is 20+8 and that is 28.

Answer: Graph A

Step-by-step explanation:

Answer:

[tex]x=9.91[/tex]

Step-by-step explanation:

[tex]11x-3=106[/tex]

      [tex]+3[/tex]       [tex]+3[/tex]

[tex]11x=109[/tex]

[tex]/11[/tex]       [tex]/11[/tex]

[tex]x=9.91[/tex]

Answer:my=8x

To find the inverse, flip the x and y variables and then solve for y.

x=8y

x/8=8y/8

x/8=y

Final answer: f^-1(x)=x/8

Answer:ln is called the natural log, or log to the base e. ln can also be written as

So, we can write the given expression as

The property of logs is:

This mean if the number a is raised to log whose base is the same as the number a itself, then the answer will be equal to the argument of the log which is x.

In the given case, the number e and the base of log are the same. So the answer of the expression will be the argument of log which is 6.

so, we can write

Thus, the correct answer is option D

Step-by-step explanation:

Answer:

x = 1, -5.56

Step-by-step explanation:

x^2 = -7x - 8

shift -7x and -8 to the other side . Remember when u shift minus changes into plus.

x^2 + 7x + 8 = 0

using quadratic equation formula

in quadratic equation one value comes positive and other comes in negative

a = 1  , b = 7 and c = 8

taking positive sign

x = (-b + [tex]\sqrt{b^2 - 4*a*c}[/tex]) /2*a

x = (-7 + [tex]\sqrt{7^2 - 4*1*8}[/tex] ) /2*1

x = (-7 + [tex]\sqrt{49 + 32}[/tex] ) /2

x = (-7 + [tex]\sqrt{81}[/tex] )/ 2

x = -7 + 9 / 2

x = 2/2

x = 1

taking negative sign

(-b - [tex]\sqrt{b^2 - 4*a*c}[/tex] ) /2*a

x = (-7 - [tex]\sqrt{7^2 - 4*1*8}[/tex] ) /2*1

x = (-7 - [tex]\sqrt{49 - 32}[/tex] ) /2

x = -7 - [tex]\sqrt{17}[/tex] / 2

x = -7 - 4.12 / 2

x = -11.12/2

x = -5.56

therefore x = 1 , - 5.56

Answer:

[tex]x = \frac{- 7 + \sqrt{17}}{2} \ , \ x = \frac{-7 - \sqrt{17}}{2}[/tex]

Step-by-step explanation:

[tex]x^2 = - 7x - 8\\\\x^2 + 7x + 8 = 0 \\\\[/tex]

[tex]x = \frac{- b \pm \sqrt{b^2 - 4ac}}{2a}\\\\[/tex]               [tex][ \ a = 1 , \ b = 7 , \ c = 8 \ ][/tex]

[tex]x = \frac{-7 \pm \sqrt{49 - (4\times 8)}}{2} \\\\x = \frac{-7 \pm \sqrt{17}}{2} \\\\x = \frac{-7 + \sqrt{17}}{2} , \ , \frac{-7 - \sqrt{17}}{2}[/tex]

Answer:

[tex]m^{\frac{1}{2} }[/tex] . [tex]n^{\frac{1}{2} }[/tex]

Step-by-step explanation:

Using the rules of exponents/ radicals

[tex]\sqrt{a}[/tex] × [tex]\sqrt{b}[/tex] ⇔ [tex]\sqrt{ab}[/tex]

[tex]\sqrt{a}[/tex] = [tex]a^{\frac{1}{2} }[/tex]

Given

[tex]\sqrt{mn}[/tex]

= [tex]\sqrt{m}[/tex] × [tex]\sqrt{n}[/tex]

= [tex]m^{\frac{1}{2} }[/tex] . [tex]n^{\frac{1}{2} }[/tex]

Answer:

[tex] {(mn)}^{ \frac{1}{2} } \\ {m}^{ \frac{1}{2} } {n}^{ \frac{1}{2} } [/tex]

Answer:

B

Step-by-step explanation:

step

Answer:

d) x + 3

Step-by-step explanation:

= x² + 5x + 6

Factorise :-

= x² + 2x + 3x + 6

= x(x + 2) + 3(x + 2)

= (x + 2)(x + 3) [Taking common]

Here we are getting (x + 3) as a factor of x² + 5x + 6 which will be either length or the width

The fundamental counting principle is used to count the total number of possible outcomes that are in a situation.

The fundamental counting principle states that if there are n ways of doing something, as well as m ways of doing another thing, then there are n×m ways to perform both of these actions.

The Fundamental Counting Principle helps when determining the sample space of probability as it figures out the total number of ways the combination of events can occur. Therefore, it is used as a guide when determining the sample space of a probability.

Lastly, the limitation is that the Fundamental Counting Principle is that it assumes that each basic event is equally probable, which does not necessarily have to be true.

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Answer:

The fundamental counting principle is used to count the total number of possible outcomes that are in a situation

Step-by-step explanation:

Answer:

B.

3m - 11 = 2m + 9

Amount Maddie earns = m = $20

Step-by-step explanation:

Let

Amount Maddie earns = m

Amount Lauren earns = 3m - 11

Amount Shannon earns = 2m + 9

If Lauren and Shannon both earned the same amount of money, how much money, m, did Maddie earn?

Amount Lauren earns = Amount Shannon earns

3m - 11 = 2m + 9

Collect like terms

3m - 2m = 9 + 11

m = 20

Amount Maddie earns = m = $20

B.

3m - 11 = 2m + 9

Answer:

[tex]7[/tex]

Solution:

This is a linear function. This means means that r is our rate of change.

To find r recal following formula

[tex]r=\frac{\Delta y}{\Delta x} = \frac{y_2-y_1}{x_2-x_1}[/tex]

Since this is a linear function we can choose any two points. I will choose the first two for simplicity

[tex]\Displaystyle \therefore r = \frac{42-14}{6-2}=\frac{28}{4}=7[/tex]

Answer:

The outcomes produced by A would be greater than B. A further explanation is provided below.

Step-by-step explanation:

Given:

In process A,

Produced units = [tex]32x^{1.5}[/tex]

In process B,

Produced units = [tex]4x^3[/tex]

If the outcomes are equivalent then,

⇒ [tex]32x^{1.5}=4x^3[/tex]

⇒     [tex]x^{1.5} = 8[/tex]

By taking log both  sides, we get

⇒    [tex]log \ 8= 1.5 \ log \ x[/tex]

⇒          [tex]x=3.99[/tex]

The domain is the span of the x-values, and the range is the span of the y-values. In each, we are looking for the smallest and largest values.

Domain: x starts at -7, and goes to infinity (we cannot see an end)

(-7, infinity)

Range: y starts at negative infinity (we cannot see where it would start), and goes to 3

(negative infinity, 3)

Hope this helps!

Answer:

the domain starts at -7 ... only one answer has the domain starting at -7

domain(-7, infinity)

Step-by-step explanation:

the domain starts at -7 ... only one answer has the domain starting at -7

the diagram isn't available.Please fix that

Answer:

Each term is 4 less than the previous term.

Step-by-step explanation:

If this helps you mark as brainlist!

Answer:

B and D are your answers for that whole page

Step-by-step explanation:

Identify the rule that correctly describes each sequence.

12, 8, 4, 0, –4, …

Each term is 4 more than the previous term.

This Is the right one: Each term is 4 less than the previous term.

Each term is 1/2 the previous term.

Each term is 2/3 the previous term.

6, 12, 24, 48, 96, …

Each term is 6 more than the previous term.

Each term is 12 more than the previous term.

Each term is 1/2 the previous term.

This is the right one: Each term is 2 times the previous term.

Answer:

See explanation

Step-by-step explanation:  

(Please Find Diagram in the attachment)⇒Answer Drawing is Given There

According to the question,

Given:

The expression is:

[tex]8x^4-2x[/tex]

To find:

The coefficient and the exponent for each term of the given expression.

Solution:

Coefficients: In the product of s number and a variable, the number is coefficient of the variable.

Exponent: The number in the power is called exponent.

We have,

[tex]8x^4-2x[/tex]

Here, the terms are [tex]8x^4,-2x[/tex].

For the term [tex]8x^4[/tex], the coefficient is 8 and the exponent is 4.

For the term [tex]-2x[/tex], the coefficient is -2 and the exponent is 1.

Therefore, the coefficients are 8 and -2, and the exponent are 4 and 1.

Answer:

reading books (458), science books (957), mathematics books (1054)

Step-by-step explanation:

458 is less than 957 and 1054, while 957 is less than 1054 but more than 458, and 1054 is more than 957 and 458.

458<957<1054

Answer: Choice C

Yes, holidays are a subset and proper subset of the calendar year.

=========================================================

Explanation:

The set of days in the calendar year spans from Jan 1st to Dec 31st.

The set of holidays is a small subset of the previous set mentioned. Any holiday is found on the calendar, but not every day on the calendar is a holiday.

------------

Here's another example of a subset

A = set of all animals

B = set of dogs

Set B is a subset of set A because any dog is an animal. In other words, any individual in set B is also in set A, but not the other way around.

------------

Going back to the calendar example, the set of holidays is a subset and it's also a proper subset of all the days in the year. We say that set B is a proper subset of set A if B has less items in it compared to A.

If we had these two sets

A = {1,2,3,4,5,6}

B = {1,2,3}

We can see that B is a proper subset of set A since everything in B is found in A, and B is smaller than A. The only time we have a subset and not a proper subset is when we talk about the set itself. Any set is a subset of itself (not a proper subset of itself).

The True statement is

Yes, holidays are a subset and proper subset of the calendar year.

Sets are represented as a collection of well-defined objects or elements that are consistent from one person to the next. A capital letter represents a set. The cardinal number of a set is the number of items in a finite set.

The order of a set determines the number of elements in the set. It refers to the size of a set. The order of the set is often referred to as the cardinality.

The set of days in the calendar year spans from Jan 1st to Dec 31st.

The set of holidays is a subset of the previously described set. Any holiday can be found on the calendar, however not every day is a holiday.

let Set B is a Proper subset of set A if it contains fewer elements than A.

So, A = {1,2,3,4,5,6}

B = {1,2,3}

We can see that B is a proper subset of set A since everything in B is found in A, and B is smaller than A.

So, holidays are a subset and proper subset of the calendar year.

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Answer:

The factor is polynomial

Step-by-step explanation:

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