Represent the following situation using Venn diagrams and answer the questions that follow. In a survey of 100 students in the institute language studies at oxford university, the number of students studying various languages in last four years were found to be : Italian 28, German 30,French 42,Italian and French 10, Italian and German 8, German and French 5, all the three languages 3. (1 point each) a. Venn diagram. b. How many students are studying none of the languages? c. How many students had French as their only language? d. How many students are studying at least one of the languages?​

Answer:

The transformation being described is from g(x)=x2 g ( x ) = x 2 to f(x)=x2 f ( x ) = x 2 . The horizontal shift depends on the value of h . The horizontal shift is described as: f(x)=f(x+h) f ( x ) = f ( x + h ) - The graph is shifted to the left h units

Answer: [tex]10^4[/tex]

Step-by-step explanation:

Assuming we are using the common log (base 10),

[tex]\log 3ty=6\\\\\log 3y +\log t=6\\\\2+\log t =6\\\\\log t=4\\\\t=10^4[/tex]

The price of a two-year bond is 101.78 and the correct option is C.

Given that a 9% annual coupon and a yield to maturity of 8%.

Simple yield is the amount of interest received by a bond issuer divided by the current market price of the associated bond.

Implicit Face value, FV=$100

Time, N=2 years

Coupon, C=(9/100)×$100=9

The yield of maturity, r=8%=0.08

Now, we will find the bond price using the formula

Price of bond = C× [1-{1/ (1+r)ⁿ}/r] +M/ (1+r)ⁿ

Substitute the values in this formula, we get

Price of bond=9×[1-{1/(1+0.08)²}/0.08]+100/(1+0.08)²

Price of bond=9×[1-{1/(1.08)²}/0.08]+100/(1.08)²

Price of bond=9×[1-{1/1.1664}/0.08]+100/1.1664

Price of bond=9×[(1-0.857)/0.08]+85.73

Price of bond=9×[0.143/0.08]+85.73

Price of bond=9×1.7875+85.73

Price of bond=16.0875+85.73

Price of bond=101.78

Hence, the price of a two-year bond with a 9% annual coupon and a yield to maturity of 8% is 101.78.

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Answer:

The last option, (x+2)(x-3)(x-1)

Step-by-step explanation:

The completely factored form of f (x) = x³ - 2x² - 5x + 6 is,

⇒ f (x) = (x - 1) (x - 2) (x - 3)

An algebraic equation with the second degree of the variable is called an Quadratic equation.

We have to given that;

Function is,

⇒ f (x) = x³ - 2x² - 5x + 6

Now, We can factor the function as;

Since, 1 is a root of function as it satisfy the function.

So, One factor is,

⇒ (x - 1)

Find another roots as;

(x - 1) ) x³ - 2x² - 5x + 6 ( x² - x - 6

         x³ - x²

        ----------

             - x² - 5x

            - x² + x

            -------------

                    - 6x + 6

                    - 6x + 6

                    ------------

                           0

Hence,

⇒ f (x) = x³ - 2x² - 5x + 6

⇒ f (x) = (x - 1) ( x² - x - 6 )

⇒ f (x) = (x - 1) ( x² - 3x - 2x - 6)

⇒ f (x) = (x - 1) ( x (x - 3) - 2 (x - 3))

⇒ f (x) = (x - 1) (x - 2) (x - 3)

Hence, The completely factored form of f (x) = x³ - 2x² - 5x + 6 is,

⇒ f (x) = (x - 1) (x - 2) (x - 3)

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In Economics, profit can be defined as a measure of the amount of money generated when the selling price is deducted from the cost price of a good or service, which is usually provided by producers.

This ultimately implies that, all producers of any product generally work to maximize their profits and make them as large as possible, in order to enable them break even and successful.

Based on the information provided, we can logically deduce that this function has its roots at x = 0 and x = 26 and its vertex is a minimum. Thus, this quadratic function which describes the relationship between the number of products produced and the overall profit margin is an increasing function:

Therefore, once they hit 26 items they break even again. The worst case scenario is that they produce 13 items, as they will have a profit of -50 dollars because the minimum point is at (18, -35). Also, the first root tells us that the profit will be 0 when 0 products are sold.

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Answer:

Step-by-step explanation:

Shift right

f(x)=√x-4.7

f(x)=√x-25

f(x)=√x-11

Shift left

f(x)=√x+0.8

f(x)=√x+6

area is multiplication

perimiter is adding the numbers on each side, for example, if the right side is 7, the left side will be 7. Add them and it will givey ou 14

1. The solution to the first percent puzzle is as follows:

                              75%         66²/₃         11¹/₉

          33¹/₃%        25%          22¹/₅%      3⁷/₁₀%

         50%         37¹/₂%          33¹/₃%      5¹/₂%

        50%          37¹/₂%          33¹/₃%      5¹/₂%

2. The solution to the second percent puzzle is as follows:

                           10%             90%

         50%           5%              45%

         50%           5%              45%

A percent puzzle is a puzzle that engages students to practice working with percentages.

The percent puzzle involves a matrix format, in which students multiply the column percent by the row percent to find the percent they must put in the missing boxes to complete the puzzle.

The multiplication results for the missing boxes can be either stated in decimals, fractions, or a combination.

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Answer: 4n - 7 = 21, n = 7

Step-by-step explanation:

A difference indicates subtraction of two terms. Four times a number indicates that a number of any value has to be multiplied by 4.

Hence, the equation that is represented by the question is

[tex]4x - 7 = 21[/tex]

We can also solve this equation (i.e., find the value of x that makes this equation true).

Adding 7 to both sides, we get

[tex]4x - 7 + 7 = 21 + 7[/tex]

Since the -7 and 7 add to 0, the equation becomes

[tex]4x = 28[/tex]

To get x by itself, we can divide both sides by 4, making the equation

[tex]x=7[/tex]

Hence, x must be 7 to make the equation true, or 7 is a solution to the equation.

Answer:

[tex]\huge\boxed{\sf n = 49}[/tex]

Step-by-step explanation:

[tex]x^2-14x+n[/tex] ---------------(1)

We need to solve it using the following formula:

[tex]a^2-2ab+b^2=(a-b)^2[/tex]

Writing the middle term in the expression as 2ab

[tex](x)^2-2(x)(7)+n[/tex]

Form the expression, we come to now that

So, the we can write the expression as:

[tex](x)^2-2(x)(7)+(7)^2\\\\x^2-14n+49[/tex]

Comparing expression (1) with the above expression, we get:

[tex]\rule[225]{225}{2}[/tex]

Applying the angles of intersecting secants theorem, the measure of arc XY is: 32°.

According to the angles of intersecting secants theorem, m∠XZY = 1/2(arc VW - arc XY).

Plug in the values:

39 = 1/2(110 - arc XY)

2(39) = 110 - arc XY

78 = 110 - arc XY

78 - 110 = - arc XY

-32 = - arc XY

Arc XY = 32°

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The reason why the expression x² + (p + q)x + pq leads to the need to determine integers that add to b and have a product c is because they follow the FOIL Technique

We want to explain why x² + (p + q)x + pq leads to the need to determine integers that add to b and have a product c.

Now, using the FOIL Technique we can say that the factors are;

(x + p)(x + q)

Expanding this gives;

x² + px + qx + pq

⇒ x² + (p + q)x + pq

Now, applying that to the trinomial; x² + 6x + 8, we can say that;    

p + q = 6, and pq = 8

Thus, solving simultaneously gives;

p = 2 and q = 6.

Thus;

x² + 6x + 8 = (x + 2)(x + 6)

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The probability that the ball Deborah picks is green is; 3/5.

Since the bag initially contains; 3 red balls, 4 green balls, and 2 yellow balls, after Deborah pulls out the 4 balls: red, red, green, yellow.

The balls remaining are; 1 red ball, 3 green and 1 yellow.

Hence, the probability that the final ball she picks is green is; 3/(3+1+1) = 3/5.

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Answer:

Step-by-step explanation:

Therefore, the values of

a

1

and r are 2 and -1, respectively.

The values of a₁ and r of the geometric series are 2 and -1 respectively.

Any term divided by the preceding term is a constant in a geometric series. The common ratio of the sequence is the name given to this constant. Any term in the sequence can be divided by the prior term to determine the common ratio.

We have the series 2, -2, 2, -2, ......

Here, The first term is 2.

and, the Common Ratio = -2 / 2

                                        = 2/(-2)

                                         = -1

So, the first term is 2 and r is -1.

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See below for the response to each question

This is the item that is being surveyed.

The surveyed item is birth weights

Hence, the variable is birth weights

From the question, we have:

Average birth weight is 6 pounds 8 ounces.

Hence, the units of the variable are pounds and ounces

This is the total number of babies in Southeast Asia

Hence, the population of interest is the babies in Southeast Asia

This is the people in the survey

Hence, the individual in the study is the 100 babies that were randomly surveyed

This is the value that gives the required information.

Hence, the parameter of interest is the average birth weight

The statistic is the average

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Answer: The largest he can possibly build is x = 14

Step-by-step explanation:

The multiplication of the expression (x² + 3x + 2) (2x² + 3x + 1) is 2x⁴ + 9x³ + 14x² + 9x + 2

(x² + 3x + 2) (2x² + 3x + 1)

= 2x⁴ + 3x³ + x² + 6x³ + 9x² + 3x + 4x² + 6x + 2

= 2x⁴ + 3x³ + 6x³ + x² + 9x² + 4x² + 3x + 6x + 2

= 2x⁴ + 9x³ + 14x² + 9x + 2

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Answer:

81

Step-by-step explanation:

Considering the definition of an inequality, the inequality that can be used to determine x is 20x + 10≤ 80

An inequality is the existing inequality between two algebraic expressions, connected through the signs:

An inequality contains one or more unknown values ​​called unknowns, in addition to certain known data.

Solving an inequality consists of finding all the values ​​of the unknown for which the inequality relation holds.

A rental car company charges $20 per day to rent a car and $0.10 for every mile driven.

Addison wants to rent a car, knowing that:

On the other hand, x represents the maximum number of days Alyssa can afford to rent for while staying within her budget.

Then, the inequality that can be used to determine x is:

20x + 0.1×100≤ 80

So:

20x + 10≤ 80

In summary, the inequality that can be used to determine x is 20x + 10≤ 80

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Answer: [tex]-3 \leq x < 1[/tex]

Step-by-step explanation:

[tex]\sqrt{x+3} \geq 0 \longrightarrow x \geq -3\\\\\sqrt{1-x} > 0 \longrightarrow 1-x > 0 \longrightarrow x < 1\\\\\therefore -3 \leq x < 1[/tex]

Answer:

B

Step-by-step explanation:

because at origin they are both positive and when it rotates about 270 both will change to negative

The shortest distance from A to B in the diagram is 17 m.

The shortest distance from D to B can be found as follows:

using Pythagoras theorem,

c² = a² + b²

where

Therefore,

DB² = 15² + 8²

DB² = 225 + 64

DB² = 289

DB = √289

DB = 17 m

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Answer:

B, 17 m

Step-by-step explanation:

Founders 23

Answer:

D

Step-by-step explanation:

As the function approaches a certain x-value, it makes a very sharp turn and doesn't touch the axis as you can see in the graph. It does that because if the x-value is applied to the function, it would make it undefined. In this case, the graph is approaching x = -3 and x = +7 since at those points, the lines for the graph change suddenly. You would look for a function that if x is -3 or 7, it makes the y-value undefined.

Another way to easily do this would be to substitute values that are in front of the value that the graph is avoiding like 6 or 8 for 7 and -2 and -4 for -3. You can see if the y-values that would output from substituting those numbers are correct.

Answer:

[tex]\dfrac{3^{13}}{2}[/tex]

Step-by-step explanation:

Given expression:

[tex]\dfrac{3^5 \cdot 2^4 \cdot 2^1 \cdot 3^6 \cdot (3^2)^4}{(2^3)^2 \cdot 3^6}[/tex]

[tex]\textsf{Apply exponent rule} \quad (a^b)^c=a^{bc}:[/tex]

[tex]\implies \dfrac{3^5 \cdot 2^4 \cdot 2^1 \cdot 3^6 \cdot 3^8}{2^6 \cdot 3^6}[/tex]

[tex]\textsf{Apply exponent rule} \quad a^b \cdot a^c=a^{b+c}:[/tex]

[tex]\implies \dfrac{3^{(5+6+8)} \cdot 2^{(4+1)}}{2^6 \cdot 3^6}[/tex]

[tex]\implies \dfrac{3^{19} \cdot 2^{5}}{2^6 \cdot 3^6}[/tex]

[tex]\implies \dfrac{3^{19} \cdot 2^{5}}{3^6 \cdot 2^6}[/tex]

[tex]\textsf{Apply exponent rule} \quad \dfrac{a^b}{a^c}=a^{b-c}:[/tex]

[tex]\implies 3^{(19-6)} \cdot 2^{(5-6)}[/tex]

[tex]\implies 3^{13} \cdot 2^{-1}[/tex]

[tex]\textsf{Apply exponent rule} \quad a^{-n}=\dfrac{1}{a^n}:[/tex]

[tex]\implies \dfrac{3^{13}}{2^1}[/tex]

[tex]\textsf{Apply exponent rule} \quad a^1=a:[/tex]

[tex]\implies \dfrac{3^{13}}{2}[/tex]

Answer:

The result is 3¹³ /2

Step-by-step explanation:

Greetings

Answer:

Given,

1in= 2.54cm

59.69cm=

[tex] \frac{59.69}{2.45} in[/tex]

=23.5 in

Answer:

perpendicular

Step-by-step explanation:

We'll find the slope of both lines and see what it tells us.

If the slopes are the same, the lines are parallel. If the slopes are opposite sign and flipped (negative reciprocals) then they are perpendicular.

The slope is y-Y on top of a fraction and x-X on the bottom.

Slope of AB:

m = 2-1 / -3 -5

= 1/-8 = -1/8

Slope of CD:

m = 7- -1 / 2-1

= 8/1 = 8

Since the slopes are -1/8 and 8, the lines are perpendicular, because they are opposite sign and flipped (negative reciprocals)

The number of ways to forma a square by connecting the ends of some of the line segments is 3, 024 ways

From the given information, we should use the formula for permutation without repetition.

The formula is given as;

Permutation = [tex]\frac{n!}{n -r !}[/tex]

Where n = number of set = 9

r = 4, this is so because, the sides of a square a four

Permutation = [tex]\frac{9!}{9 - 4!}[/tex]

Permutation = [tex]\frac{9!}{5!}[/tex]

Permutation = [tex]\frac{362, 880}{120}[/tex]

Permutation = 3, 024 ways

Thus, the number of ways to forma a square by connecting the ends of some of the line segments is 3, 024 ways

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The value of r If r varies directly with the square of m and inversely with s is 240

Suppose r varies directly with the square of m and inversely with s.

If r varies directly with the square of m and inversely with s, then;

r = km²/s

Given that R = 15 when m = 6 s= 4

15 = k(6)²/4

60 = 36k

k = 60/36

k = 5/3

If the value of m = 24 and s = 4, hence;

r = 5/3*24²/4

r = 240

Hence the value of r If r varies directly with the square of m and inversely with s is 240

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