Select the correct answer.
mel is teaching travis how to use a compass and a straightedge to construct a square inscribed in a circle. he tells travis to begin by using a
straightedge to draw any chord of the circle and label it wx. next, his instructions are to use the tools to construct a chord that is a
perpendicular bisector of wx and label it yz. finally, he directs travis to use a straightedge to draw the four chords that make up the square: wy
yx, xz, and zw.
what is the first error, if any, mel made in his instructions to travis?
oa mel's instructions contain no errors.
ob. chord wx must be a diameter of the circle,
oc chord yz is found by constructing a segment congruent to wx.
od the four chords that make up the square are the perpendicular bisectors of wx and yz.
ое. chord wx must be congruent to the radius of the circle.

Step-by-step explanation:

inscribed angles subtended by the same arc are equal.

the central angle of a circle is twice any inscribed angle subtended by the same arc.

the first statement tells us that the 53° angle as well as y stay the same size no matter where on their arcs (between the 2 points connected to O) they would be. so, we don't need to bother with any line lengths.

the 2nd statement tells us that x = 2×53 = 106°. the 53° and x angles refer to the short arc on the right of the 2 points connected to O.

and y and x refer to the larger arc on the left of the 2 line connected to O. that means according to the second statement : 360-x (the big angle around O) = 2y

so,

360 - 106 = 2y

254 = 2y

y = 127°

Answer:

5.6

Step-by-step explanation:

4/5 = .8

so ? ÷ 7 = .8|
7 x .8 = 5.6
x= 5.6

x = 5.6

hope it helps...!!!!

Answer:

C. 3000

Step-by-step explanation:

i took the quiz!

also 60 and 3000 line up

Answer:

C 3,000

Step-by-step explanation: It's right on Edge

[tex]\qquad\qquad\huge\underline{{\sf Answer}}♨[/tex]

As we know ~

Area of the circle is :

[tex]\qquad \sf  \dashrightarrow \:\pi {r}^{2} [/tex]

And radius (r) = diameter (d) ÷ 2

[ radius of the circle = half the measure of diameter ]

➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖

[tex]\qquad \sf  \dashrightarrow \:r = d \div 2[/tex]

[tex]\qquad \sf  \dashrightarrow \:r = 4.4\div 2[/tex]

[tex]\qquad \sf  \dashrightarrow \:r = 2.2 \: mm[/tex]

Now find the Area ~

[tex]\qquad \sf  \dashrightarrow \: \pi {r}^{2} [/tex]

[tex]\qquad \sf  \dashrightarrow \:3.14 \times {(2.2)}^{2} [/tex]

[tex]\qquad \sf  \dashrightarrow \:3.14 \times {4.84}^{} [/tex]

[tex]\qquad \sf  \dashrightarrow \:area \approx 15.2 \: \: mm {}^{2} [/tex]

・ ．━━━━━━━†━━━━━━━━━．・

[tex]\qquad \sf  \dashrightarrow \:r = d \div 2[/tex]

[tex]\qquad \sf  \dashrightarrow \:r = 3.7 \div 2[/tex]

[tex]\qquad \sf  \dashrightarrow \:r = 1.85 \: \: cm[/tex]

Bow, calculate the Area ~

[tex]\qquad \sf  \dashrightarrow \: \pi {r}^{2} [/tex]

[tex]\qquad \sf  \dashrightarrow \:3.14 \times (1.85) {}^{2} [/tex]

[tex]\qquad \sf  \dashrightarrow \:3.14 \times 3.4225 {}^{} [/tex]

[tex]\qquad \sf  \dashrightarrow \:area \approx 10.75 \: \: cm {}^{2} [/tex]

・ ．━━━━━━━†━━━━━━━━━．・

[tex]\qquad \sf  \dashrightarrow \:\pi {r}^{2} [/tex]

[tex]\qquad \sf  \dashrightarrow \:3.14 \times (8.3) {}^{2} [/tex]

[tex]\qquad \sf  \dashrightarrow \:3.14 \times 68.89[/tex]

[tex]\qquad \sf  \dashrightarrow \:area \approx216.31 \: \: cm {}^{2} [/tex]

・ ．━━━━━━━†━━━━━━━━━．・

[tex]\qquad \sf  \dashrightarrow \:r = d \div 2[/tex]

[tex]\qquad \sf  \dashrightarrow \:r = 5.8 \div 2[/tex]

[tex]\qquad \sf  \dashrightarrow \:r = 2.9 \: \: yd[/tex]

now, let's calculate area ~

[tex]\qquad \sf  \dashrightarrow \:3.14 \times {(2.9)}^{2} [/tex]

[tex]\qquad \sf  \dashrightarrow \:3.14 \times 8.41 [/tex]

[tex] \qquad \sf  \dashrightarrow \:area \approx26.41 \: \: yd {}^{2} [/tex]

・ ．━━━━━━━†━━━━━━━━━．・

[tex]\qquad \sf  \dashrightarrow \:r = d \div 2[/tex]

[tex]\qquad \sf  \dashrightarrow \:r = 1 \div 2[/tex]

[tex]\qquad \sf  \dashrightarrow \:r = 0.5 \: \: yd[/tex]

Now, let's calculate area ~

[tex]\qquad \sf  \dashrightarrow \:\pi {r}^{2} [/tex]

[tex]\qquad \sf  \dashrightarrow \:3.14 \times (0.5) {}^{2} [/tex]

[tex]\qquad \sf  \dashrightarrow \:3.14 \times 0.25[/tex]

[tex]\qquad \sf  \dashrightarrow \:area \approx0.785 \: \: yd {}^{2} [/tex]

・ ．━━━━━━━†━━━━━━━━━．・

[tex]\qquad \sf  \dashrightarrow \:\pi {r}^{2} [/tex]

[tex]\qquad \sf  \dashrightarrow \:3.14 \times {(8)}^{2} [/tex]

[tex]\qquad \sf  \dashrightarrow \:3.14 \times 64[/tex]

[tex]\qquad \sf  \dashrightarrow \:area = 200.96 \: \: yd {}^{2} [/tex]

➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖

Answer:

the answer is -6.8°

Step-by-step explanation:

-36°+-25°+12°+-3°+18°/5°

-34°÷5°=-6.8°

Make as Braniliest!

[tex]\qquad\qquad\huge\underline{\boxed{\sf Answer}}[/tex]

Let's solve ~ ☂

⧠ Here, I'm using middle term split method :

[tex] \qquad\rightarrowtail \sf {x}^{2} + 6x + 8[/tex]

[tex] \qquad\rightarrowtail \sf {x}^{2} + 4x + 2x+ 8[/tex]

[tex] \qquad\rightarrowtail \sf {x(x}^{} + 4) + 2(x+ 4)[/tex]

[tex] \qquad\rightarrowtail \sf (x + 2)(x+ 4)[/tex]

[tex]\\ \rm\rightarrowtail x^2+6x+8[/tex]

[tex]\\ \rm\rightarrowtail x^2+4x+2x+8[/tex]

[tex]\\ \rm\rightarrowtail x(x+4)+2(x+4)[/tex]

[tex]\\ \rm\rightarrowtail (x+2)(x+4)[/tex]

Done!

Answer:

30.37

Step-by-step explanation:

Answer:

[tex]164 \div 5.40 ={\ 30.3704{}}[/tex]

The answer is 30.3704

Answer:

[tex]\displaystyle 11,3[/tex]

Step-by-step explanation:

Use the Law of Cosines to find the length of the third edge:

Solving for Angles

[tex]\displaystyle \frac{a^2 + b^2 - c^2}{2ab} = cos\angle{C} \\ \frac{a^2 - b^2 + c^2}{2ac} = cos\angle{B} \\ \frac{-a^2 + b^2 + c^2}{2bc} = cos\angle{A}[/tex]

Use [tex]\displaystyle cos^{-1}[/tex]towards the end or you will throw your result off!

Solving for Edges

[tex]\displaystyle b^2 + a^2 - 2ba\:cos\angle{C} = c^2 \\ c^2 + a^2 - 2ca\:cos\angle{B} = b^2 \\ c^2 + b^2 - 2cb\:cos\angle{A} = a^2[/tex]

Take the square root of the final result or it will be thrown off!

Let us get to wourk:

[tex]\displaystyle 10^2 + 7,9^2 - 2[10][7,9]\:cos\:77,5 = a^2 \hookrightarrow 100 + 62,41 - 158\:cos\:77,5 = a^2 \hookrightarrow \sqrt{128,212541} = \sqrt{a^2}; 11,323097677... \\ \\ \boxed{11,3 \approx a}[/tex]

I am joyous to assist you at any time.

Answer:

50%

Step-by-step explanation:

Hope this helped

Maybe mark brainiest

Dime = 10 cents

Nickel = 5 cents

Total value of coins = 3(10) + 4(5) = 30 + 20 = 50

To find the percent, first create a fraction. The fraction will be the amount of money that Benjamin has over the total (one dollar).

50 / 100 = 5 / 10 = 0.5

0.5 x 100 = 50

50%

Answer: 50% of a dollar

Hope this helps!

Answer:

you do not have any numbers, only letters so I cannot answer your question. sorry...

Step-by-step explanation:

Select the correct answer.

Which number is an irrational number?

A.

B.

C.

D.

Answer:

Step-by-step explanation:

you would multiply the fractions

then you would add the hole number

Answer:

2 14/15

Step-by-step explanation:

Answer:

f(-6)= -41 923

Step-by-step explanation:

f(-6)= -( -6)⁶ +5(-6)⁴+8(-6)³+2(-6) -7 you substitute x with -6 the you use a calculator which will then give you - 41923

Answer:

521418

Step-by-step explanation:

Answer:

a

Step-by-step explanation:

7(g-9)+12=26

7(g-9)+12-12=26-12

7(g-9)=14

7(g-9)/7=14/7

g-9=2

g-9+9=2+9

g=11

Answer:

Step-by-step explanation:

26=7(g-9)+12

(take 12 to 26)

so it will be 7(g-9)= 26-12

=> 7(g-9)= 14

(then take 7 to 14)

=> g-9= 14/2

=> g-9= 2

(then take 9 to 2)

g= 2 + 9

hope it is properly explained

STAY SAFE, HAVE A NICE DAY

Answer:

hope it helps

also try to find out what 5power 10 is because I have no calculator with me

Answer:

As per Provided Information

Height of cone h is 3.25 cm

Diameter of cone is 2.2 cm

Radius = 2.2/2

Radius = 1.1 cm

We have been asked to determine the volume of the cone .

Using Formulae

[tex] \boxed{\bf \:Volume_{(Cone)} = \cfrac{1}{3} \pi {r}^{2}h}[/tex]

Substituting the given value and let's solve it

[tex]\sf\longrightarrow \: Volume_{(Cone)} = \cfrac{1}{3} \times 3.14 \times {1.1}^{2} \times 3.25 \\ \\ \\ \sf\longrightarrow \: Volume_{(Cone)} = \cfrac{1}{3} \times 3.14 \times 1.21 \times 3.25 \\ \\ \\ \sf\longrightarrow \: Volume_{(Cone)} = \cfrac{1}{3} \times 3.14 \times 3.9325 \\ \\ \\ \sf\longrightarrow \: Volume_{(Cone)} = \cfrac{1}{3} \times 12.34805 \\ \\ \\ \sf\longrightarrow \: Volume_{(Cone)} = \cfrac{12.34805}{3} \\ \\ \\ \sf\longrightarrow \: Volume_{(Cone)} = 4.11 {cm}^{3} [/tex]

Therefore,

Answer:

4 boxes

Step-by-step explanation:

If she has 4 boxes that hold 5 cookies each, that will total 20 cookies.

4×5=20

20÷5=4

Answer:

[tex]P(A < 84)=\frac{4}{7}[/tex]

Step-by-step explanation:

[tex]Total\ numbers:\ 7\\Numbers\ less\ than\ 84:\ 4\\\\P(A < 84)=\frac{4}{7}[/tex]

Answer:

71.428571%

Step-by-step explanation:

You divide 5 by 7

Answer:

-13

Step-by-step explanation:

Answer:

2929 1/3 [tex]\pi[/tex] in^3

Step-by-step explanation:

The equation for the volume of a sphere is [tex]\frac{4}{3} \pi r^3[/tex].

Insert 13 for r.  Then, simplify.

Answer:

13 C 14 D 15 A 16 B

Step-by-step explanation:

Sorry thats all i know hope you found this helpful

5,278 hope this helps good luck!

Answer:

it is A Scalene Triangle

Answer:

x= 12

Step-by-step explanation:

Hope u understood it

"PLEASE MARK ME THE BRAINLIEST"

Answer:

56

Step-by-step explanation:

Answer:

Pretty sure it's 2:30 P.M.

Step-by-step explanation:

If her track practice started at 12:00 P.M., and and ran relays for one hour, it would already be 1:00 P.M.

Then she practiced the long jump for an hour and thirty minutes. Add another hour to that and it would be 2:00 P.M. Add thirty minutes, and it would be 2:30 P.M.

Hopefully that makes sense to you

5 quarts I think 4 cups per quart has 5 quarts and 2 cups I think

Answer:

1 quart = 4 cups

8 × 4 = 32

32 - 6 = 26

26 - 18 = 8

he has 2 quarts left