Solve -5(3n + 4) = 40.

The function L= 10 log(I/10^-16) is a logarithmic equation

The loudness of the whisper is 40 decibels

The function of the loudness is given as:

L= 10 log(I/10^-16)

When the intensity is 10^-12, the equation becomes

L= 10 log(10^-12/10^-16)

Evaluate the quotient

L= 10 log(10^4)

Apply the rule of logarithm

L= 10 * 4

Evaluate the product

L = 40

Hence, the loudness of the whisper is 40 decibels

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Answer:

see explanation

Step-by-step explanation:

look photo

[tex]\qquad\qquad\huge\underline{{\sf Answer}}♨[/tex]

The given pair of angles form linear pair, therefore their sum is equal to 180°

that is :

[tex]\qquad \sf  \dashrightarrow \:2(x - 26) + 3x + 2 = 180[/tex]

[tex]\qquad \sf  \dashrightarrow \:2x - 52 + 3x + 2 = 180[/tex]

[tex]\qquad \sf  \dashrightarrow \:5x - 50 = 180[/tex]

[tex]\qquad \sf  \dashrightarrow \:5x = 230[/tex]

[tex]\qquad \sf  \dashrightarrow \:x = 46 \degree[/tex]

Have a great day ~

Answer:

42 in²

Step-by-step explanation:

Total: Shape 1 + Shape 2

Area of a square: l x w, where l is the length and w is the width.

= 6 x 5

= 30

Area of a triangle: 1/2 x b x h, where b is the base and h is the height.

= 1/2 x 4 x 6

= 1/2 x 24

= 12

Total = 30 + 12

= 42 in²

Answer:

Step-by-step explanation:

This figure is trapezium

a and b are the parallel lines.

a = 5 +4 = 9 in  & b = 5 in   and h = 6 in

[tex]\boxed{\text{Area of trapezium =$\dfrac{(a+b)*h}{2}$}}[/tex]

                              [tex]\sf = \dfrac{(9+5)*6}{2}\\\\=\dfrac{14*6}{2}\\\\= 7*6\\\\= 42 \ in^{2}[/tex]

Answer:

sin C = 3/5

Step-by-step explanation:

see image.

It helps to draw a picture. Tan C is the ratio of the OPP/ADJ.

Pythagorean theorem or if you know Pythagorean triples are a shortcut to find the hypotenuse.

Once you know the hypotenuse, use the ratio for sine to solve the question. Sine is OPP/HYP.

see image.

With the frequecy distribution shown in the 50 cities of pakistan,

= highest value - lowest value

= 26.5 - 8.5

= 18

= ∑ f x / ∑ f

= ∑ f x / N

= 905 / 50

= 18.1

median

= lower limit + ( N/2 - C ) * h / ( frequency of the class interval )

C = cumulative frequency preceeding to the median class frequency

h = class interval

= 18.5 + ( 50 / 2 - ( 5 + 12 ) ) * 3 / 18

= 18.5 + 1.3333

= 19.8333

The mode is the value with the highest frequency occurence. This is under class 18 - 20

mode = lower limit + ( ( f1 - f0 ) / (2*f1 - f0 - f2 ) ) * h

f1 = fequency of the modal class

f0 = freqency of the preceeding modal class

f2 = frequency of the next modal class

h = class interval

= 18.5 + ( ( 18 - 12 ) / (2 * 18 - 12 - 8 )  ) * 3

= 18 + ( 0.375 ) * 3

= 19.125

= sqrt ( 1 / N ∑ f ( x - x' )^2 )

= sqrt (1  / 50 * 706.5

= 3.7589

=  standard deviation / mean

= 3.7589 / 3

= 1.2530

= ( standard deviation )^2

= ( 3.7589 )^2

= 14.1293

=  ∑ f ( x - x' )^4 / ( N * ( standard deviation )^4 )

= 27459.405 / ( 50 * 3.7589^4 )

= 2.7509

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Answer:

Because 10 is twice as large as 5.

Step-by-step explanation:

Answer:

v = length x width x hight

The probability of not drawing C in neither draw is P = 0.5

All the cards have the same probability of being drawn, in this case, our set of cards is {F, D, C, G}

The probability of not drawing C is equal to the probability of drawing F, D or G. So we have 3 options out of 4, then the probability is:

p = 3/4.

Now we draw another, this time there are 3 cards, one of these is C, and the other two cards are not C. Then the probability of not drawing C again is equal to 2 over 3.

q = 2/3.

The joint probability (for both of these events to happen) is equal to the product of the individual probabilities:

P = p*q = (3/4)*(2/3) = 0.5

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Answer:

Step-by-step explanation:

The given circle has equation

[tex] \sf \: x^2+y^2=16x[/tex]

The equation of a circle with center (h,k) and radius r units is

[tex] \sf(x-h)^2+(y-k)^2=r^2(x−h) [/tex]

[tex] \sf(x-7)^2+(y-5)^2=4^2(x−7)[/tex]

[tex] \sf(x-7)^2+(y-5)^2=16(x−7) [/tex]

This is the equation that has its center at the origin with radius 4 units.

When this circle is translated seven units to the right and five units up, then the center of the circle will now be at (7,5).

[tex]\sqrt{7^{16}} = 7^n\\\\\implies \left(7^{16}\right)^{\tfrac 12} = 7^n\\\\\implies 7^{\left(\tfrac 12 \times 16\right)}=7^n\\\\\implies 7^8 = 7^n\\\\\implies \ln 7^8 = \ln 7^n\\\\\implies 8\ln 7 = n \ln 7\\\\\implies n =8[/tex]

Answer:

  5 sets

Step-by-step explanation:

The average number of pieces per set is the ratio of the total number of pieces to the total number of sets.

Let x represent the number of 3-piece sets. Then the total number of pieces is ...

  3x +5(5) +10(2) = 3x +45

The total number of sets is ...

  x +5 +2 = x +7

We want the ratio of these numbers to be 5 pieces per set:

  (3x +45)/(x +7) = 5

  3x +45 = 5x +35 . . . . . multiply by (x+7)

  10 = 2x . . . . . . . . . . subtract (3x+35)

  5 = x . . . . . . . . . divide by 2

Divya owns 5 sets with 3 pieces.

_____

Alternate solution

Each 10-piece set has 5 more pieces than average, so the two of them total 10 more pieces than average.

Each 3-piece set has 2 fewer pieces than average. The total number of 3-piece sets must have a total of 10 fewer pieces than average in order to balance the excess of the 10-piece sets. That is, there must be 10/2 = 5 of the 3-piece sets to have a total lof 10 fewer pieces than average.

Altogether, the differences from average must total zero.

Answer:

  840 km

Step-by-step explanation:

The speed expression ...

  840 kilometers per hour

means the plane files 840 kilometers in each hour.

In 1 hour, it will travel 840 km.

Proof -

So, in the first part we'll verify by taking n = 1.

[tex] \implies \: 1 = {1}^{2} = \frac{1(1 + 1)(2 + 1)}{6} [/tex]

[tex] \implies{ \frac{1(2)(3)}{6} }[/tex]

[tex]\implies{ 1}[/tex]

Therefore, it is true for the first part.

In the second part we will assume that,

[tex] \: { {1}^{2} + {2}^{2} + {3}^{2} + ..... + {k}^{2} = \frac{k(k + 1)(2k + 1)}{6} }[/tex]

and we will prove that,

[tex]\sf{ \: { {1}^{2} + {2}^{2} + {3}^{2} + ..... + {k}^{2} + (k + 1)^{2} = \frac{(k + 1)(k + 1 + 1) \{2(k + 1) + 1\}}{6}}}[/tex]

[tex] \: {{1}^{2} + {2}^{2} + {3}^{2} + ..... + {k}^{2} + (k + 1)^{2} = \frac{(k + 1)(k + 2) (2k + 3)}{6}}[/tex]

[tex]{1}^{2} + {2}^{2} + {3}^{2} + ..... + {k}^{2} + (k + 1)^{2} = \frac{k (k + 1) (2k + 1) }{6} + \frac{(k + 1) ^{2} }{6} [/tex]

[tex]{1}^{2} + {2}^{2} + {3}^{2} + ..... + {k}^{2} + (k + 1)^{2} = \frac{k(k+1)(2k+1)+6(k+1)^ 2 }{6} [/tex]

[tex]{1}^{2} + {2}^{2} + {3}^{2} + ..... + {k}^{2} + (k + 1)^{2} = \frac{(k+1)\{k(2k+1)+6(k+1)\} }{6}[/tex]

[tex]{1}^{2} + {2}^{2} + {3}^{2} + ..... + {k}^{2} + (k + 1)^{2} = \frac{(k+1)(2k^2 +k+6k+6) }{6} [/tex]

[tex]{1}^{2} + {2}^{2} + {3}^{2} + ..... + {k}^{2} + (k + 1)^{2} = \frac{(k+1)(2k^2+7k+6) }{6} [/tex]

[tex]{1}^{2} + {2}^{2} + {3}^{2} + ..... + {k}^{2} + (k + 1)^{2} = \frac{(k+1)(k+2)(2k+3) }{6} [/tex]

Henceforth, by using the principle of mathematical induction 1²+2² +3²+....+n² = n(n+1)(2n+1)/ 6 for all positive integers n.

_______________________________

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The fact that the angles in a triangle add up to 180 indicates that it is actually a square). There are also four right triangles, each with a base and a height. The Pythagorean Theorem is reached when a2 + b2 = c2.

Answer:

226

Step-by-step explanation:

Given:

Simplify 6^3+5(4-2)

Note:

I think you meant 6^3 because if you solve 63+5(4-2):

63+5(4-2)

63+5 * 2

63 + 10

73
Solve:

6^3 + 5(4 - 2 )    

6^3 + 5 x 2

6 x 6 x 6 = 216

226 + 5 x 2

5 x 2 = 10

216 + 10 = 226

~Lenvy~

Answer:

Step-by-step explanation:

. Volume: A measure of _space  occupied by a _three dimensional _ figure.

1. Base: The surface on which an object stands on.

1. Height: The _vertical distance from top to bottom, creates a _90° degree angle with the base.

1. Inverse Operation: The opposite of a math operation; the opposite of addition is subtraction and the opposite of multiplication is division.

1. Diameter: A straight line going from one side of a point on a circle to the other through the _center.

1. Radius: The distance from the center to the point of a circle;or half of the diameter.

Volume of a Cylinder

A cylinder is a three dimensional object with a circular base and top.

To find the volume of a cylinder we use the following formula:πr²h

Answer:

a.  up 1 unit

Step-by-step explanation:

f(x) + k will translate the function up k units

f(x) - k will translate the function down k units

f(x-h) will translate the function right h units

f(x+h) will translate the function left h units

k must be greater than or equal to 22.75 to have two different zeros.

Second order polynomials are algebraic expressions that observe the following form:

[tex]p(x) = a\cdot x^2 + b\cdot x + c[/tex]   (1)

Where:

For polynomials of the form p(x) = 0, we can infer the nature of their roots by applying the following discriminant:

d = b² - 4 · a · c   (2)

According to (2), there are three cases:

Now we have the following discriminant case:

-(3 + 2 · k)² - 4 · (1) · (4) ≠ 0

-(9 + 6 · k + 4 · k²) - 16 ≠ 0

-9 - 6 · k - 4 · k² - 16 ≠ 0

4 · k²+ 6 · k +25 ≠ 0

This characteristic polynomial has two conjugated complex roots, then we conclude that all values of k must positive or negative, but never zero. By graphng tools we find that k must be greater than or equal to 22.75 to have two different zeros.

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Answer:

Rs. 32767

Step-by-step explanation:

Because the amount is doubling every day, we can use the expression 1*2^15-1 because there is 1 to start with. Also cool trick! if you need to do 2^1+2^2+2^3+....+2^x, it will be equal to 2^(x+1)-1. So:

2^15-1

32768-1

32767

Answer:

water level is h=6.5 m, compute the time required to drain the tank to a level of h= 0.5m. Use the fourth-order Runge-Kutta method.

Step-by-step explanation:

water level is h=6.5 m, compute the time required to drain the tank to a level of h= 0.5m. Use the fourth-order Runge-Kutta method.

Answer:

draw a square with a side length of 2.5 cm. label it CARL

Draw the circle with center A passing through C

draw SEGMENT CR

draw the straight line d passing through A and perpendicular to CR

Answer:

12 < x < 18

Step-by-step explanation:

Assuming these are 2 sides of a triangle, then

given 2 sides of a triangle , the 3rd side x is in the range

difference of 2 sides < x < sum of 2 sides , that is

15 - 3 < x <  15 + 3

12 < x < 18

Answer:

Step-by-step explanation:

[tex]7 - 1 \frac{3}{5} = 6 \frac{2}{5}[/tex]

It's 8/6

Because 6/8 × 8/6 = 1

Answer:

it's 8/6

I hope it's help u

Answer: 6/8 inch

Step-by-step explanation:

Answer:

See below, please

Step-by-step explanation:

[tex](2x + 9) + (4x - 3) = 90[/tex]

[tex]6x + 6 = 90[/tex]

[tex]6x = 90 - 6 = 84[/tex]

Hence

[tex]x = 14[/tex]

Answer:145

Step-by-step explanation:

if h=33 and g=5 the expression would look like 33-4x5 frist 33-4=29 so now we imes by 5, 29x5=145 so 145 is your answer

Answer:

688.19 inches

Step-by-step explanation:

Answer:

The answer is c on edge or f(x) = 1 sqt x + 6 -2

Step-by-step explanation:

From the given two options, none of them has a function that has the same maximum value as f(x) = -|x+3|-2.

A function is a correspondence between input numbers (x-values) and output numbers (y-values). It is used to describe an equation.

Given that:

Suppose that x = c is a critical point of (x) then,

If f'(x) > 0 to the left of x = c and f'(x) < 0 to the right of x = c;

If f'(x) < 0 to the left of x = c and f'(x) > 0 to the right of x = c;

If f'(x) is the same sign on both sides of x = c;

From the given equation, the critical points: x = -3

If we put the point x = -3 into - |x+3|-2

We can therefore conclude that none of them has a function that has the same maximum value as f(x) = -|x+3|-2.

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