Solve these


[tex] {x}^{2} - 5x + 6[/tex]
[tex] {x}^{2} - 11x + 28[/tex]
​

Answer:

A

Step-by-step explanation:

A

when multiplied out

the highest exponent of x is 2

y = 2x² + x - 6

Answer:

option A

Step-by-step explanation:

A quadratic equation is a single variable polynomial of degree 2.

[tex]A ) y = ( x + 2)(2x-3) = 2x^2 -3x +4x - 6 =2x^2 + x - 6 \ - Yes \\\\B) y = 3(x - 4) \ - No\\\\C) y = \frac{1}{x^2} \ - No\\\\D) y = x(x-4)(x+3) = x(x^2 -x - 12) = x^3 -x^2 - 12x \ - No[/tex]

Answer:

Step-by-step explanation:

This is already factored for us, which is really nice, so now all we need to do is apply the Zero Product Property to the sets of parenthesis and solve for x, which will give us the 2 times that the object is on the ground.

x + 1 = 0 so

x = -1

x - 9 = 0 so

x = 9

We all know that time cannot ever be negative, so the time that the object is on the ground is 9 seconds after it's launched (which was from an initial height of 45 meters).

Answer:

(B). 265 miles

Step-by-step explanation:

She travelled 75 mph for 3 hours and 40 mph for 1 hour.

Therefore, 75 + 75 + 75 + 40 = 265 miles

If this helps you, please mark brainliest!

Answer:

r =v2 /a

Step-by-step explanation:

a=v2/r

ra=v2

r =v2 /a

Answer:

r = [tex]\frac{v^2}{a}[/tex]

Step-by-step explanation:

Given

a = [tex]\frac{v^2}{r}[/tex] ( multiply both sides by r to clear the fraction )

ar = v² ( divide both sides by a )

r = [tex]\frac{v^2}{a}[/tex]

Answer:

$469.80

Step-by-step explanation:

First, let's find out how many fees would be paid exclusively for renting it out for 14 days.

29.00 * 14 = $406

They have to pay 406 dollars just for having the car for 14 days.

Now let's find out how much will need to paid for driving for 320 km.

We can first take away 100 km because the fee only starts afterwards.

320 - 100 = 220

220 * 0.29 = 63.8

63.80 + 406 = 469.80

Answer:

1.04 lbs

Step-by-step explanation:

8.32 lbs / 8 jars=

1.04 lbs per jar

Answer:

x = 32°

Step-by-step explanation:

The two angles form a straight line, so therefore they are supplementary.

The sum of supplementary angles always equal 180°, so we know that:

(3x - 4) + (3x - 8) = 180°

Now you have the equation, solve for x.

3x - 4 + 3x - 8 = 180°

6x - 12 = 180°

6x = 192°

x = 32°

Answer:

3x-4+3x-8=180

3x+3x=180+4+8

6x=192

x=32

check: 3(32)-4+3(32)-8=180

Answer:

son weight = 72

Step-by-step explanation:

D + S = 180

D + 2S = 252

S=252-180

S = 72

D= 108

-pi/4 is the same thing as 7pi/4.

The sine function will get us the y-value we need.

Keep in mind that our y-value will be negative (based on the position of the line), and pi/4 and 3pi/4 will both have positive y-values.

Therefore, the correct expression is sin(7pi/4).

Hope this helps!! :)

Answer:

[tex]{ \tt{q = 60 \degree}} \\ \\ { \tt{w = 180 - 60 = 120 \degree}} \\ \\ { \tt{y = 180 - 60 - 70 = 50 \degree}}[/tex]

Step-by-step explanation:

Here,

y= 2x

and x € (1,2,3)

now,

when x=1 , when x=2 , when x= 3

y=2x y= 2x y=2x

= 2×1 = 2×2 = 2×3

= 2 = 4 = 6

Therefore, y = (2,3,6)

Answer:

(q+p)(r-s)

Step-by-step explanation:

qr-qs+pr-ps

q(r-s) + p(r-s)

(q+p)(r-s)

Answer:

t= r-21

7

Step-by-step explanation:

r = 7(t+3)

expanding the bracket

r = 7t + 21

bringing t to the left hand side

7t = r - 21

divide both sides by seven

t= r-21

7

Answer:

t = (r/7) - 3

Step-by-step explanation:

Given equation,

→ r = 7(t + 3)

Now the value of t will be,

→ r = 7(t + 3)

→ r = 7t + 21

→ r - 21 = 7t

→ 7t = r - 21

→ t = (r - 21)/7

→ t = (r/7) - 3

Hence, value of t is (r/7) - 3.

Answer:

The domain of the function are values of x that respect the following condition: [tex]x \geq 7[/tex]

Step-by-step explanation:

We are given the following function:

[tex]f(x) = \sqrt{x - 7}[/tex]

Domain of the square root function:

The square root does not exist for negative values, so the domain of a square root function:

[tex]g(x) = \sqrt{h(x)}[/tex]

Is [tex]h(x) \geq 0[/tex]

In this question:

[tex]f(x) = \sqrt{x - 7}[/tex]

Then:

[tex]h(x) = x - 7[/tex]

[tex]x - 7 \geq 0[/tex]

[tex]x \geq 7[/tex]

The domain of the function are values of x that respect the following condition: [tex]x \geq 7[/tex]

Answer:

the answer is 8 and x>or equal 7 and the only option greater than 7 is 8

Step-by-step explanation:

Answer:

x = - [tex]\frac{1}{4}[/tex]

Step-by-step explanation:

Given

6 + 4x = 7 ( subtract 6 from both sides )

4x = 1 ( divide both sides by 4 )

x = [tex]\frac{1}{4}[/tex]

Answer:

x = 1/4

Step-by-step explanation:

6 +4x = 7

collect terms

4x = 7 - 6

4x = 1

Divide both sides by 4

x = 1/4

Bye ! :-)

Answer:

The sum of two non-zero even numbers is even and greater than the addends

Step-by-step explanation:

The solution to the whole number equation is sum of two non-zero even numbers is even and greater than the addends

Equations are mathematical statements with two algebraic expressions flanking the equals (=) sign on either side.

It demonstrates the equality of the relationship between the expressions printed on the left and right sides.

Coefficients, variables, operators, constants, terms, expressions, and the equal to sign are some of the components of an equation. The "=" sign and terms on both sides must always be present when writing an equation.

Given data ,

Let the equation be represented as A

Now , the value of A is

Substituting the values in the equation , we get

Let the first number be p

Let the second number be q

Now , the values of p and q are even

So , when p = 2 and q = 4

The sum of two non-zero even numbers is even and greater than the addends

p + q > q   be equation (1)

p + q > p   be equation (2)

2 + 4 > 4

2 + 4 > 2

6 > 4 and 6 > 2

Hence , the equation is true and sum of two non-zero even numbers is even and greater than the addends

To learn more about equations click :

https://brainly.com/question/19297665

#SPJ2

Answer:

m = 3

Step-by-step explanation:

5m + 1 = 3m + 7

2m = 6

m = 3

The value of m in the figure is 3

From the question, line segments GH and HK are congruent.

So, we have:

GH = HK

Substitute known values

5m + 1 = 3m + 7

Collect like terms

5m - 3m = -1 + 7

Evaluate the like terms

2m = 6

Divide both sides by 2

m = 3

Hence, the value of m in the figure is 3

Read more about quadrilaterals at:

https://brainly.com/question/5715879

Answer:

h(3)=19

Step-by-step explanation:

it's saying x=3 so -4×3 is -12 and -12 -7 is 19 so the answer is 19

Answer:

hope this helps

Step-by-step explanation:

Answer:

Step-by-step explanation:

Hope this helps u !!

Answer:

a) [tex]\=x=36.4inches[/tex]

b) [tex]Median=22[/tex]

c) [tex]Mode=18[/tex]

d) [tex]The\ Mean[/tex]

Step-by-step explanation:

From the question we are told that:

Depths:

18 inches,

20 inches

26 inches

22 inches

85 inches

18 inches

24 inches

Sample size [tex]n=7[/tex]

Summation of all depths

 [tex]\sum d=18+20+26+22+85+18+24[/tex]

 [tex]\sum d=255[/tex]

a)

Generally the equation for Mean is mathematically given by

 [tex]\=x=\frac{\sum d}{n}[/tex]

 [tex]\=x=\frac{255}{7}[/tex]

 [tex]\=x=36.4inches[/tex]

b)

Generally the Median is given by the Middle Number which is

 [tex]Median=22[/tex]

c)

Generally the Mode is given by the Highest occurring Number which is

 [tex]Mode=18[/tex]

with two appearances

Therefore

d)

The measure that is the most useful for predicting how deep the snow will be at an 8th lodge is

 [tex]The Mean[/tex]

Answer:

(3 [tex]\frac{1}{3}[/tex] , 5 [tex]\frac{2}{3}[/tex] )

Step-by-step explanation:

x + y = -9    --> y = -x -9  

4x + y = -19 --> y = -4x - 19

Graph accordingly.

Answer:

an = 4n + 3

Step-by-step explanation:

Step-by-step explanation:

BE/BC=BD/BA

tHE TWO SIMILAR TRIANGLES ARE BED AND BC. tHE PROPORTION ABOVE REPRESENTS USE OF THE TWO SIMILAR TRIANGLES.

4/(4 + 10) = 5/(5+X) Cross Multiply

4(5+x) = 5(4+10)m

20 +4x=20 +50 subtract 20 from both sides

4x = 50 divide by 4

x =12.5

Answer:

D.

Step-by-step explanation:

If you look on both triangles, PQ and ST are both and the same spots. (P is in the same spot as S and Q is in the same spot as T.

Answer:

its c trust me. ive seen some stuff like this before