Suppose a university is divided into three campuses: the Main campus, the Downtown campus, and the Bay Area campus. The Main campus has 60% of the university's students, the Downtown campus has 25%, and the Bay Area has the rest. At the Main campus, 12% of the students are statistics majors. At the Downtown campus, 4% of the students are statistics majors. Finally, at the Bay Area campus, 1% of the students are statistics majors.

Required:
a. What proportion of students at the university are statistics majors?
b. Of all statistics majors at the university, what proportion are at the Main campus?

Answer:

t + 3

Step-by-step explanation:

adding 3 years onto t amount of years

Answer: -5

Step-by-step explanation:

-3x+9y=-57                x=4

-3(4)+9y=-57

-12+9y=-57

             +12

9y=-45

    9y

y=-5

Using the Empirical Rule and the Central Limit Theorem, we have that:

It states that, for a normally distributed random variable:

By the Central Limit Theorem, the sampling distribution of sample means of size n has standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

In this problem, the standard deviation of the distribution of sample means is:

[tex]s = \frac{0.657}{\sqrt{50}} = 0.09[/tex]

68% of the means are within 1 standard deviation of the mean, hence the bounds are:

99.7% of the means are within 3 standard deviations of the mean, hence the bounds are:

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Answer:

About 68% of the sample means fall within the interval $1.64 and $1.82.

About 99.7% of the sample means fall within the interval $1.45 and $2.01.

Step-by-step explanation:

To verify the given intervals, we need to calculate the standard error of the mean (SE) for a sample size of 50 using the population mean and standard deviation provided.

The standard error of the mean (SE) can be calculated as:

SE = population standard deviation / √(sample size)

Given that the population mean is $1.73 and the population standard deviation is $0.657, and the sample size is 50:

SE = $0.657 / √50 ≈ $0.09299 (rounded to 5 decimal places)

Now, we can calculate the intervals:

For the interval where about 68% of the sample means fall:

Interval = (Mean - 1 * SE, Mean + 1 * SE)

Interval = ($1.73 - $0.09299, $1.73 + $0.09299)

Interval ≈ ($1.63701, $1.82299)

So, about 68% of the sample means fall within the interval $1.64 and $1.82, which matches the given statement.

For the interval where about 99.7% of the sample means fall:

Interval = (Mean - 3 * SE, Mean + 3 * SE)

Interval = ($1.73 - 3 * $0.09299, $1.73 + 3 * $0.09299)

Interval ≈ ($1.54703, $1.91297)

So, about 99.7% of the sample means fall within the interval $1.55 and $1.91, which is different from the given statement.

The correct interval for about 99.7% of the sample means, rounded to the nearest hundredth, is $1.55 and $1.91, not $1.45 and $2.01 as mentioned in the statement.

By algebra, if one solution for the second order polynomial b² - 9 = 0 is 3, then the other solution to the expression is - 3.

Herein we have a quadratic equation, that is, a second order polynomial, of the form b² - a² = 0. By algebra we know that the polynomial of such form have the following equivalence:

b² - a² = (b - a) · (b + a), which means that the roots of the interval are x₁ = a and x₂ = - a.

If we know that a² = 9, then the roots of the second order polynomial are:

b² - 9 = (b - 3) · (b + 3)

By algebra, if one solution for the second order polynomial b² - 9 = 0 is 3, then the other solution to the expression is - 3.

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that log4x=2log16x. (ii)Show that log x=3logb³ x. (iii) Show that log₂x=(1+log₂3)logix

Someone may think this graph is misleading because it does not start from the origin

As a general rule, graphs are to begin from the origin

The origin of a graph is

(x, y) = (0, 0)

From the given graph, the origin is

(x, y) = (0, 60)

This means that someone may think this graph is misleading because it does not start from the origin

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The number of mice that didn't get a tumor is 9 mice out of the 25 mice.

Identify the total mice who did not have any effects or the effects did not include a tumor.

Repiratory failure: 9 mice

Based on this, it can be concluded 9 mice did not have a tumor, while 21 mice hat at least a tumor and some of them had a tumor and respiratory failure.

Note: This question is incomplete; here is the missing section:

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After rounding to the nearest tenth, we get:

[tex]\frac{2.1}{1.488} = 1.5[/tex]

We have the quotient:

[tex]\frac{2.1}{1.488}[/tex]

If you multiply the numerator and denominator by 1000, you will get the simpler quotient:

[tex]\frac{2100}{1488}[/tex]

It gives:

[tex]\frac{2100}{1488} = 1.45[/tex]

Now we want to round it to the nearest tenth, which is the first digit after the decimal point.

To do so, we need to look at the number at the right of it.

In this case, we can see a 5, so we should round up, then we have:

[tex]\frac{2100}{1488} = 1.5[/tex]

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The number of people who can go to the game only on Sunday by applying the concept of set theory is equal to 5.

Total number of people for a trip to a baseball game = 15

Number of people planning to go on Saturday = 10

Number of people planning to go Sunday = 12

Let x be the number of people who can go on both Saturday and Sunday.

Then, the number of people who can go only on Saturday is 10 - x.

And the number of people who can go only on Sunday is 12 - x.

Total of 15 people are going to the baseball game.

Using set theory we have,

Number of people going on Saturday only + number of people going on Sunday only + number of people going on both = 15

Substitute the value we have,

⇒(10 - x) + (12 - x) + x = 15

Simplifying the above equation, we get,

⇒22 - x = 15

⇒ x = 7

The number of people who can only go to the game on Sunday is

= 12 - x

= 12 - 7

= 5

Therefore, using set theory number of people can only go to the game on Sunday is equal to 5 .

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One tree is 31.044 m taller than the other one in height.

Given Information and Formula Used:

The distance between the trees, BC (from the figure) = 120 m

Elevation of angles to the top of the trees,

∠AMB = 52°

∠DMC = 36°

In a right angled triangle,

tan x = Perpendicular/Height

Here, x is the angle opposite to the Perpendicular.

Calculating the Height Difference:

Let's compute the height of the taller tree first.

In ΔAMB,

tan 52° = AB / BM

Now, since M is the point halfway between the trees,

BM = CM = BC/2

BM = CM = 60 m

⇒ 1.2799 = AB / 60

AB = 1.2799 × 60

Thus, the height of the taller tree, AB =  76.794 m

Now, we will compute the height of the smaller tree.

In ΔDCM,

tan 36° = DC / CM

⇒ 0.7625 = DC / 60

DC = 0.7625 × 60

Thus, the height of the smaller tree, DC = 45.75 m

The difference in the heights of the trees, AP = AB - DC

AP = (76.794 - 45.75)m

AP = 31.044m

Hence one tree is 31.044m taller in height than the other.

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The missing angle is B = 65° and the missing sides are a ≈ 7.461 and c ≈ 6.762.

In this case, we know two angles (A = 25°, C = 90°) and a side of a triangle (b = 16) and Euclidean properties and the law of the sines must be used to find the rest of variables:

B = 180° - A - C

B = 180° - 25° - 90°

B = 65°

a = 16 × (sin 25°/sin 65°)

a ≈ 7.461

c = 16 × (sin 25°/sin 90°)

c ≈ 6.762

The missing angle is B = 65° and the missing sides are a ≈ 7.461 and c ≈ 6.762.

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The measure of the angle x is 77 degrees if two lines are parallel to each other or p ll q option (A) is correct.

Lines that intersect at a right angle are named perpendicular lines. Lines that are always the same distance apart from each other are known as parallel lines.

The question is incomplete.

The complete question is in the picture, please refer to the attached picture.

We have two lines that are parallel to each other or p ll q

The angle made by transversal t is 136 degrees

The measure of the other angle = 180 - 136 = 44 degrees

Draw a line parallel to p and q and passes through the intersection point of line t and v

The angle made by the transversal and the line drawn is the same as 44 degrees.

The measure of the other angle = 121 - 44 = 77 degrees

Thus, the measure of the angle x is 77 degrees if two lines are parallel to each other or p ll q option (A) is correct.

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The dimensions are 7 inches by 17 inches.

What is the area of rectangle?

Let the length be l inches

Let the breadth be b inches

Area = l*b

We can find dimensions as shown below:

Let the length be x inches

Let the width be y inches

Area = 119 square inches

x=3+2y             (1)

Area = l*w

119 = x*y

Putting value of x

119 = (3+2y) *y

119 = 3y+2y^2

2y^2+3y-119=0

2y^2-14y+17y-119=0

2y(y-7) +17(y-7) =0

(y-7) (2y+17) =0

y=7, -17/2

y cannot be negative

so, y = 7

Putting in equation (1)

x=3+2(7)

= 3+14

= 17

Hence, the dimensions are 7 inches by 17 inches.

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Answer:

v=-7

Step-by-step explanation:

13v-5v=-27-29

8v=-56

v=-56/8=-7

The interval where the function is increasing is (3, ∞)

Given the rational function shown below

g(x) = ∛x-3

For the function to be a positive function, the value in the square root  must be positive such that;

x - 3 = 0

Add 3 to both sides

x = 0 + 3

x = 3

Hence the interval where the function is increasing is (3, ∞)

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The simple annual interest rate for the $ 525 loan is equal to 46.35 %.

In this situation we assume that the loan does not accumulate interests continuously in time. Hence, the interest rate for paying the loan back 75 days later is:

575 = 525 · (1 + r/100)

50 = 525 · r /100

5000 = 525 · r

r = 9.524

The loan has an interest rate of 9.524 % for 75 days. Simple annual interest rate is determine by rule of three:

r' = 9.524 × 365/75

r' = 46.350

The simple annual interest rate for the $ 525 loan is equal to 46.35 %.

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Using the Poisson distribution, it is found that:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by:

[tex]P(X = x) = \frac{e^{-\mu}\mu^{x}}{(x)!}[/tex]

The parameters are:

In this problem, the mean is:

[tex]\mu = 3.2[/tex]

The probability that the company will find 2 or fewer defective products in this batch is:

[tex]P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2)[/tex]

In which:

[tex]P(X = x) = \frac{e^{-\mu}\mu^{x}}{(x)!}[/tex]

[tex]P(X = 0) = \frac{e^{-3.2}3.2^{0}}{(0)!} = 0.0408[/tex]

[tex]P(X = 1) = \frac{e^{-3.2}3.2^{1}}{(1)!} = 0.1304[/tex]

[tex]P(X = 2) = \frac{e^{-3.2}3.2^{2}}{(2)!} = 0.2087[/tex]

Then:

[tex]P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2) = 0.0408 + 0.1304 + 0.2087 = 0.3799[/tex]

There is a 0.3799 = 37.99% probability that the company will find 2 or fewer defective products in this batch.

The probability that 4 or more defective products are found in this batch is:

[tex]P(X \geq 4) = 1 - P(X < 4)[/tex]

In which:

P(X < 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3).

Then:

[tex]P(X = x) = \frac{e^{-\mu}\mu^{x}}{(x)!}[/tex]

[tex]P(X = 0) = \frac{e^{-3.2}3.2^{0}}{(0)!} = 0.0408[/tex]

[tex]P(X = 1) = \frac{e^{-3.2}3.2^{1}}{(1)!} = 0.1304[/tex]

[tex]P(X = 2) = \frac{e^{-3.2}3.2^{2}}{(2)!} = 0.2087[/tex]

[tex]P(X = 3) = \frac{e^{-3.2}3.2^{3}}{(3)!} = 0.2226[/tex]

P(X < 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0.0408 + 0.1304 + 0.2087 + 0.2226 = 0.6025

[tex]P(X \geq 4) = 1 - P(X < 4) = 1 - 0.6025 = 0.3975[/tex]

There is a 0.3975 = 39.75% probability that 4 or more defective products are found in this batch.

For 5 or more, the probability is:

[tex]P(X \geq 5) = 1 - P(X < 5)[/tex]

In which:

P(X < 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4).

Then:

[tex]P(X = x) = \frac{e^{-\mu}\mu^{x}}{(x)!}[/tex]

[tex]P(X = 0) = \frac{e^{-3.2}3.2^{0}}{(0)!} = 0.0408[/tex]

[tex]P(X = 1) = \frac{e^{-3.2}3.2^{1}}{(1)!} = 0.1304[/tex]

[tex]P(X = 2) = \frac{e^{-3.2}3.2^{2}}{(2)!} = 0.2087[/tex]

[tex]P(X = 3) = \frac{e^{-3.2}3.2^{3}}{(3)!} = 0.2226[/tex]

[tex]P(X = 4) = \frac{e^{-3.2}3.2^{4}}{(4)!} = 0.1781[/tex]

P(X < 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) = 0.0408 + 0.1304 + 0.2087 + 0.2226 + 0.1781 = 0.7806

[tex]P(X \geq 5) = 1 - P(X < 5) = 1 - 0.7806 = 0.2194[/tex]

Since [tex]P(X \geq 5) > 0.05[/tex], the company should not stop production it there are 5 defectives in a batch.

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The cost of one ounce of peanuts is $0.20

The cost of one ounce of cashew is $0.35

15p + 5c = 4.75 equation 1

5p + 15c = 6.25 equation 2

Where:

Multiply equation 2 by 3

15p + 45c = 18.75 equation 3

Subtract equation 1 from equation 3

40c = 14

c = 14/40

c = $0.35

Substitute for c in equation 1

15p + (5 x 0.35) = $4.75

15p + 1.75 = 4.75

15p = 4.75 - 1.75

15p = 3

p = 3/15

p = $0.20

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The adjoint of the matrix [tex]\left[\begin{array}{cc}1&0\\2&-1\end{array}\right][/tex] is [tex]\left[\begin{array}{cc}-1&0\\-2&1\end{array}\right][/tex]

The matrix is given as:

[tex]\left[\begin{array}{cc}1&0\\2&-1\end{array}\right][/tex]

For a matrix A be represented as:

[tex]A = \left[\begin{array}{cc}a&b\\c&d\end{array}\right][/tex]

The adjoint is:

[tex]Adj = \left[\begin{array}{cc}d&-b\\-c&a\end{array}\right][/tex]

Using the above format, we have:

[tex]Adj = \left[\begin{array}{cc}-1&0\\-2&1\end{array}\right][/tex]

Hence, the adjoint of the matrix [tex]\left[\begin{array}{cc}1&0\\2&-1\end{array}\right][/tex] is [tex]\left[\begin{array}{cc}-1&0\\-2&1\end{array}\right][/tex]

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The solution to the system of inequalities is (-3.375, 1.75)

The system of inequalities is given as:

3y > 2x+12

2x+y < -5

Next, we plot the graph of the system using a graphing tool

From the graph, both inequalities intersect at

(-3.375, 1.75)

Hence, the solution to the system of inequalities is (-3.375, 1.75)

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Answer:

16.7 degrees

Step-by-step explanation:

The number must be between 20 and 30.

The square of the whole number can be found as follows;

The square of the whole number is between 500 and 900. The number must be between 20 and 30.

The number is an whole number.

Therefore, the number will be between 20 and 30.

20² = 400

30² = 900

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Answer:

80 square units

Step-by-step explanation:

These are rectangles and triangles.

The formula to get the area of a rectangle is its length multiplied by its width.

The formula to get the area triangle is its base multiplied by its height, then divided by 2.

The 3 rectangles all share the width of 6 units, so we can combine the 3 rectangles and consider it as 1 large rectangle.

The lengths of the rectangles are 2, 8, and 2 units.

We can add them together to get a total height of 12 units.

So, the formula to get the area of this rectangle is:
[tex]6\times12= A[/tex]

By solving this, we get:
A = 72 square units

There are 4 triangles remaining.

The base and height of all the triangles are 2 units.

So, by plugging these values into the triangle area formula, as mentioned from the beginning, we get:

[tex](2\times2)\div2=A[/tex]

So, the area of 1 triangle is 2 square units.

But since there are 4 triangles with the same bases and heights, we will multiply the area of 1 triangle by 4.

So, [tex]4 \times 2 = A[/tex]

This means the area of all the triangles together is 8 square units.

By adding the area of the triangles and rectangles together, we will get the answer.

[tex]72+8 = A[/tex]

So, the total area of this box is 80 square units.

Answer:

+5

Step-by-step explanation:

There is a length of 5 between all numbers, meaning that 5 is added to each number to get the next one.

I hope this helps!

Answer:

180°

cuz when a line (I forgot the name) and radius meet at the circumference they from an angle of 90°

Answer: option (2)

Step-by-step explanation:

The slanted line has a negative slope.

Also, the line is shaded below.

This leaves option (2) as the correct answer.

The containers must be spheres of radius = 6.2cm

We know that the shape that minimizes the area for a fixed volume is the sphere.

Here, we want to get spheres of a volume of 1 liter. Where:

1 L = 1000 cm³

And remember that the volume of a sphere of radius R is:

[tex]V = \frac{4}{3}*3.14*R^3[/tex]

Then we must solve:

[tex]V = \frac{4}{3}*3.14*R^3 = 1000cm^3\\\\R =\sqrt[3]{ (1000cm^3*\frac{3}{4*3.14} )} = 6.2cm[/tex]

The containers must be spheres of radius = 6.2cm

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