Suppose you are collecting money for something.

You need # 200 in all. You ask your parents, uncles

and aunts as well as grandparents. Different people

may give either ` 10, ` 20 or even ` 50. You will collect

till the total becomes 200. Write the algorithm.​

Answer:

The internet allows you to connect with people and information around the world. The internet is more broad and could include searching things up or message-based websites. Emails is more specific, with it being when you send someone a message (called an email) on a mail website (that allows you to get messages from other people, websites, etc.)

Explanation:

In my answer.

Answer:

SELECT TripName

FROM AllTrips

WHERE Trip NOT LIKE ‘NH%'

Explanation:

Required

Fill in the blanks

The table name is not stated; so, I assumed the table name to be AllTrips.

The explanation is as follows:

This select the records in the TripName column

SELECT TripName

This specifies the table where the record is being selected

FROM AllTrips

This states the fetch condition

WHERE Trip NOT LIKE ‘NH%'

Note that:

So, the clause NOT LIKE 'NH%' will return records that do not begin with NH

Answer:

Computers use Zeroes and ones and this system is called

A. BINARY SYSTEM

hope it helps

have a nice day

Answer:

The program in C++ is as follows:

#include <bits/stdc++.h>

using namespace std;

int main(){

string sentence,word="";

getline (cin, sentence);

vector<string> for_reverse;

for (int i = 0; i < sentence.length(); i++){

 if (sentence[i] == ' ')  {

  for_reverse.push_back(word);

  word = "";  }

 else{    word += sentence[i];}  }

for_reverse.push_back(word);

sentence="";

for (int i = for_reverse.size() - 1; i > 0; i--){

 sentence+=for_reverse[i]+" ";}

sentence+=for_reverse[0];

cout<<sentence<<endl;

return 0;

}

Explanation:

This declares sentence and word as strings; word is then initialized to an empty string

string sentence,word="";

This gets input for sentence

getline (cin, sentence);

This creates a string vector to reverse the input sentence

vector<string> for_reverse;

This iterates through the sentence

for (int i = 0; i < sentence.length(); i++){

This pushes each word of the sentence to the vector when space is encountered

 if (sentence[i] == ' ')  {

  for_reverse.push_back(word);

Initialize word to empty string

  word = "";  }

If the encountered character is not a blank space, the character is added to the current word

 else{    word += sentence[i];}  }

This pushes the last word to the vector

for_reverse.push_back(word);  

This initializes sentence to an empty string

sentence="";

This iterates through the vector

for (int i = for_reverse.size() - 1; i > 0; i--){

This generates the reversed sentence

 sentence+=for_reverse[i]+" ";}

This adds the first word to the end of the sentence

sentence+=for_reverse[0];

Print the sentence

cout<<sentence<<endl;

Answer:

Print.. is your answer...

Answer:

a) P(B,A,B), P(x,y,z)

=> P(B,A,B) , P(B,A,B}  

Hence, most general unifier = {x/B , y/A , z/B }.

b. P(x,x), Q(A,A)  

No mgu exists for this expression as any substitution will not make P(x,x), Q(A, A) equal as one function is of P and the other is of Q.

c. Older(Father(y),y), Older(Father(x),John)

Thus , mgu ={ y/x , x/John }.

d) Q(G(y,z),G(z,y)), Q(G(x,x),G(A,B))

=> Q(G(x,x),G(x,x)), Q(G(x,x),G(A,B))  

This is not unifiable as x cannot be bound for both A and B.

e) P(f(x), x, g(x)), P(f(y), A, z)    

=> P(f(A), A, g(A)), P(f(A), A, g(A))  

Thus , mgu = {x/y, z/y , y/A }.

Explanation:  

Unification: Any substitution that makes two expressions equal is called a unifier.  

a) P(B,A,B), P(x,y,z)  

Use { x/B}  

=> P(B,A,B) , P(B,y,z)  

Now use {y/A}  

=> P(B,A,B) , P(B,A,z)  

Now, use {z/B}  

=> P(B,A,B) , P(B,A,B}  

Hence, most general unifier = {x/B , y/A , z/B }  

b. P(x,x), Q(A,A)  

No mgu exists for this expression as any substitution will not make P(x,x), Q(A, A) equal as one function is of P and the other is of Q  

c. Older(Father(y),y), Older(Father(x),John)  

Use {y/x}  

=> Older(Father(x),x), Older(Father(x),John)  

Now use { x/John }  

=> Older(Father(John), John), Older(Father(John), John)  

Thus , mgu ={ y/x , x/John }  

d) Q(G(y,z),G(z,y)), Q(G(x,x),G(A,B))  

Use { y/x }  

=> Q(G(x,z),G(z,x)), Q(G(x,x),G(A,B))

Use {z/x}  

=> Q(G(x,x),G(x,x)), Q(G(x,x),G(A,B))  

This is not unifiable as x cannot be bound for both A and B  

e) P(f(x), x, g(x)), P(f(y), A, z)  

Use {x/y}  

=> P(f(y), y, g(y)), P(f(y), A, z)  

Now use {z/g(y)}  

P(f(y), y, g(y)), P(f(y), A, g(y))  

Now use {y/A}  

=> P(f(A), A, g(A)), P(f(A), A, g(A))  

Thus , mgu = {x/y, z/y , y/A }.

[tex]\sf\purple{Collaborative \:consumption}[/tex] is joining together as a group to use a specific product more efficiently.

[tex]\bold{ \green{ \star{ \orange{Hope\:it\:helps.}}}}⋆[/tex]

1 Account

2 online

3 access

4 password

5 internet

6 email

Answer:

A web browser, or simply "browser," is an application used to access and view websites.

Need a better discription of the question to finalize an answer.

Answer:

Saved In order to be used as a primary key, which of these characteristics must an attribute possess with respect to a single instance of the entity:

There must be a maximum of one attribute instance.

There must be many instances of the attribute.

There must be at most one entity instance that each attribute instance describes.

There must be at least one instance of the attribute.

A singular attribute is also known as a unique attribute. True

Saved Relationship names and types of relationship maxima or minima that each could have are listed below. True

Explanation:

Answer:

VARIABLES

Real temperatura

ALGORITMO

Si temperatura > 20 haga:

Escriba "Temperatura alta"

Fin-Si

Si temperatura > 10 y temperatura <= 20 haga:

Escriba "Temperatura normal"

Fin-Si

Sino:

Escriba "Temperatura baja"

Fin-Si

Explanation:

A continuación, describimos el pseudocódigo para lograr las funcionalidades deseadas:

VARIABLES

Real temperatura

ALGORITMO

Si temperatura > 20 haga:

Escriba "Temperatura alta"

Fin-Si

Si temperatura > 10 y temperatura <= 20 haga:

Escriba "Temperatura normal"

Fin-Si

Sino:

Escriba "Temperatura baja"

Fin-Si

Answer:

false

Explanation:

function should contain more codes

Answer:

Diligence

Explanation:

The computer possess several qualities including tbe ability to be consistent with its task and accuracy of its output. When describing a person or machine that delivers so much over a long periodof time without being weary, bored or tired, such person or machine could be described as being Diligent. Depending on the task a computer is being used to execute, computer machines are usually being used in a non-stop manner. For instance, firms that works on shift basis may have 3 to 4 working shifts per day with each shift making use of the same computer used by the previous shift everyday for several number of days. Example are telecommunications customer service firms who work on a 24 hours basis.

Answer and Explanation:

Deadlock occurs when two operating systems on the same computer are hindering each other's execution, getting blocked, waiting for each one to run first. This can happen when a preemption has not occurred, when a mutual exclusion has occurred, or when one of the systems causes the other to not execute.

File manager is software that allows a computer user to create directories and organize files inside and outside of them.

Process is the term used to determine the functioning of computer software. When a software is started, it uses its own programming code to perform a specific activity.

Multiprogramming is the term used for the moment when an operating system allows the user to run more than one software at the same time. For this to happen, the computer needs to have a high processing capacity, to handle the effort of running several software simultaneously.

Software Classification is the process that determines the composition and different aspects that make up a software. In this way, it is possible to understand the usefulness and programming of this software.

Virtual memory is the use of secondary memory for caching. This allows the user to share files more securely and quickly, in addition to alleviating the problems that limited memory presents.

Answer:

the answer is D. Multi -tester VOM

It is used to measure the resistance on ohms and voltage that flow in the circuit both AC and DC current is D. Multi-tester VOM​.

Ammeter, tool for measuring both direct or alternating electric powered modern, in amperes. An ammeter can degree an extensive variety of modern values due to the fact at excessive values most effective a small part of the modern is directed thru the meter mechanism; a shunt in parallel with the meter consists of the main portion. ammeter.

A multimeter or a multitester additionally referred to as a volt/ohm meter or VOM, is a digital measuring tool that mixes numerous size capabilities in a single unit. A traditional multimeter can also additionally encompass capabilities consisting of the capacity to degree voltage, modern and resistance.

Reda more about the Voltage:

https://brainly.com/question/24858512

#SPJ2

Answer:

2 is the ans

Explanation:

bye bye, gonna go to studyy

Answer:

The pseudo-code describes steps in an algorithm or another system in plain language. Pseudo-Code is often designed for human reading rather than machine reading with structural conventions of a normal language of programming.

Natural languages consist of phrases, usually declarative phrases, with a sequence of information.

Explanation:

Answer:

The program in C++ is as follows

#include <iostream>

using namespace std;

int main(){

   int n1, n2, n3, largest, smallest;

   cin>>n1>>n2>>n3;

   if(n1 >= n2 && n1>=n3){        largest = n1;    }

   else if(n2 >= n1 && n2>=n3){        largest = n2;    }

   else{        largest = n3;    }

   if(n1 <= n2 && n1<=n3){        smallest = n1;    }

   else if(n2 <= n1 && n2<=n3){        smallest = n2;    }

   else{        largest = n3;    }

   cout<<"Smallest: "<<smallest<<endl;

   cout<<"Largest: "<<largest<<endl;

   return 0;

}

Explanation:

Declare all variables

   int n1, n2, n3, largest, smallest;

Get input for the three numbers

   cin>>n1>>n2>>n3;

Check if n1 is the largest

   if(n1 >= n2 && n1>=n3){        largest = n1;    }

Check if n2 is the largest

   else if(n2 >= n1 && n2>=n3){        largest = n2;    }

Otherwise, n3 is the largest

   else{        largest = n3;    }

Check if n1 is the smallest

   if(n1 <= n2 && n1<=n3){        smallest = n1;    }

Check if n2 is the smallest

   else if(n2 <= n1 && n2<=n3){        smallest = n2;    }

Otherwise, n3 is the smallest

  else{        largest = n3;    }

Print the smallest

   cout<<"Smallest: "<<smallest<<endl;

Print the largest

   cout<<"Largest: "<<largest<<endl;

Answer:

The right answer is "Hardware crash".

Explanation:

Thus the above is the right solution.

Answer:

???

Explanation:

???

Answer:

Are you talking about the bruce willis is superman basically? Because if so i don't think so because that is a future event that hasn't happened yet also that film sucks.

Explanation:

Answer:

See Explanation

Explanation:

The function is not given. So, I will provide general explanation.

A function is defined as:

return-type function-name(argument-lists)

For instance, an int function that has 1 argument is:

int Myfunc(int num)

num is the argument of the function Myfunc

So, an example of a function with two arguments is:

int Myfunc(int num, string name)

So, examine the function in the complete question; then count the number of arguments to determine if the answer is true or false.

Answer:

The program in C is as follows:

#include <limits.h>

#include <stdio.h>

int main(){

   int count = 0;

   int number, largest = INT_MIN;

   while(count<10){

       scanf("%d",&number);

       if(number>largest){

           largest = number;        }

       count++;    }

   printf("Largest: %d",largest);

   return 0;

}

Explanation:

This initializes count to 0

   int count = 0;

This declares number and largest; largest is also initialized to the smallest integer

   int number, largest = INT_MIN;

This loop is repeated while count is less than 10

   while(count<10){

Get each number

       scanf("%d",&number);

If current input is greater than the largest integer, largest is updated to the current input

       if(number>largest){

           largest = number;        }

Increase count by 1

       count++;    }

Print the largest

   printf("Largest: %d",largest);

Answer:

d. d1− = 10, d1+ = 0

Explanation:

Given

3X1 + 4X2 +d1− − d1+ = 36

X1 = 6

X2 = 2

Required

Possible values of d1- and d1+

We have:

3X1 + 4X2 +d1− − d1+ = 36

Substitute values for X1 and X2

3 *6 + 4 * 2 + d1- - d1+ = 36

18 + 8 + d1- - d1+ = 36

Collect like terms

d1- - d1+ = 36 - 18 - 8

d1- - d1+ = 10

For the above equation to be true, the following inequality must be true

d1- > d1+

Hence,

(d) is correct

Because:

10 > 0

Answer:

The responsibilities you have are Use characters other than just AZ. If passwords are chosen from the letters AZ, there are only 26 possibilities for each character. Adding digits expands the number of possibilities to 36. Using both uppercase and lowercase letters plus digits expands the number of possible characters to 62

Explanation:

Hoped this helped you :3

Explanation:

Growth – Another important objective of business is to achieve growth. The growth should be in terms of increase in profit, revenue, capacity, number of employees and employee prosperity, etc.

Stability – Stability means continuity of business. An enterprise or business should achieve stability in terms of customer satisfaction, creditworthiness, employee satisfaction etc. A stable organization can easily handle changing dynamics of markets.

Answer:

Explanation:

The following code is written in Java. In order to code this efficiently, I created a class for the trafficLights. The class contains the currentLight, and the streetType as variables and contains a constructore, getter and setter methods, and a method to turn to the next light in the sequence. Then I created 4 objects of TrafficLights for the highways and the streets.

class Brainly {

   public static void main(String[] args) {

       TrafficLights highwaySouth = new TrafficLights("Highway", "green");

       TrafficLights highwayNorth = new TrafficLights("Highway", "green");

       TrafficLights streetEast = new TrafficLights("Street", "yellow");

       TrafficLights streetWest = new TrafficLights("Street", "red");

   }

}

class TrafficLights {

   String streetType, currentLight;

   public TrafficLights(String streetType, String currentLight) {

       this.streetType = streetType;

       this.currentLight = currentLight;

   }

   public void nextLight() {

       if (this.currentLight == "green") {

           this.currentLight = "yellow";

       } else if (this.currentLight == "yellow") {

           this.currentLight = "red";

       } else {

           this.currentLight = "green";

       }

   }

   public String getStreetType() {

       return streetType;

   }

   public void setStreetType(String streetType) {

       this.streetType = streetType;

   }

   public String getCurrentLight() {

       return currentLight;

   }

   public void setCurrentLight(String currentLight) {

       this.currentLight = currentLight;

   }

}