The amount of a radioactive substance remaining after t years is given by the function f(t) = m(0.5)", where m is the
initial mass and h is the half-life in years. Cobalt-60 has a half-life of about 5.3 years. Which equation gives the
mass of a 50 mg Cobalt-60 sample remaining after 10 years, and approximately how many milligrams remain?

Answer:

66 (no other answer)

Step-by-step explanation:

The number can be divided by 2 so its even. Its a multiple of 11. It is between 20 and 79. it is a multiple of 3.

Answer:

[tex]\displaystyle y' = \frac{\big( -2 \cos x \sin x - \frac{3}{2\sqrt{x}} \big) \big( \tan^2 x + 5x \big) + \big( \cos^2 x - 3\sqrt{x} + 6 \big) \big( 2 \sec^2 x \tan x + 5 \big)}{ \big( \csc^2 x + 3 \big) \big( \sin^2 x + 6 \big)} + \frac{2 \cot x \csc^2 x \big( \cos^2 x - 3\sqrt{x} + 6 \big) \big( \tan^2 x + 5x \big)}{\big( \csc^2 x + 3 \big)^2 \big( \sin^2x + 6 \big)} - \frac{2 \cos x \sin x \big( \cos^2 x - 3\sqrt{x} + 6 \big) \big( \tan^2 x + 5x \big)}{\big( \csc^2 x + 3 \big) \big( \sin^2 x + 6 \big)^2}[/tex]

General Formulas and Concepts:
Calculus

Differentiation

Derivative Property [Multiplied Constant]:
[tex]\displaystyle (cu)' = cu'[/tex]

Derivative Property [Addition/Subtraction]:
[tex]\displaystyle (u + v)' = u' + v'[/tex]

Derivative Rule [Basic Power Rule]:

Derivative Rule [Product Rule]:
[tex]\displaystyle (uv)' = u'v + uv'[/tex]

Derivative Rule [Quotient Rule]:
[tex]\displaystyle \bigg( \frac{u}{v} \bigg)' = \frac{vu' - uv'}{v^2}[/tex]

Derivative Rule [Chain Rule]:
[tex]\displaystyle [u(v)]' = u'(v)v'[/tex]

Step-by-step explanation:

*Note:

Since the answering box is way too small for this problem, there will be limited explanation.

Step 1: Define

Identify.

[tex]\displaystyle y = \frac{\cos^2 x - 3\sqrt{x} +6}{\sin^2 x + 6} \times \frac{\tan^2 x + 5x}{\csc^2 x + 3}[/tex]

Step 2: Differentiate

We can differentiate this function with the use of the given derivative rules and properties.

Applying Product Rule:

[tex]\displaystyle y' = \bigg( \frac{\cos^2 x - 3\sqrt{x} + 6}{\sin^2 x + 6} \bigg)' \frac{\tan^2 x + 5x}{\csc^2 x + 3} + \frac{\cos^2 x - 3\sqrt{x} +6}{\sin^2 x + 6} \bigg( \frac{\tan^2 x + 5x}{\csc^2 x + 3} \bigg) '[/tex]

Differentiating the first portion using Quotient Rule:

[tex]\displaystyle \bigg( \frac{\cos^2 x - 3\sqrt{x} + 6}{\sin^2 x + 6} \bigg)' = \frac{\big( \cos^2 x - 3\sqrt{x} + 6 \big)' \big( \sin^2 x + 6 \big) - \big( \sin^2 x + 6 \big)' \big( \cos^2 x - 3\sqrt{x} + 6 \big)}{\big( \sin^2 x + 6 \big)^2}[/tex]

Apply Derivative Rules and Properties, namely the Chain Rule:

[tex]\displaystyle \bigg( \frac{\cos^2 x - 3\sqrt{x} + 6}{\sin^2 x + 6} \bigg)' = \frac{\big( -2 \cos x \sin x - \frac{3}{2\sqrt{x}} \big) \big( \sin^2 x + 6 \big) - \big( 2 \sin x \cos x \big) \big( \cos^2 x - 3\sqrt{x} + 6 \big)}{\big( \sin^2 x + 6 \big)^2}[/tex]

Differentiating the second portion using Quotient Rule again:

[tex]\displaystyle \bigg( \frac{\tan^2 x + 5x}{\csc^2 x + 3} \bigg) ' = \frac{\big( \tan^2 x + 5x \big)' \big( \csc^2 x + 3 \big) - \big( \csc^2 x + 3 \big)' \big( \tan^2 x + 5x \big)}{\big( \csc^2 x + 3 \big)^2}[/tex]

Apply Derivative Rules and Properties, namely the Chain Rule again:
[tex]\displaystyle \bigg( \frac{\tan^2 x + 5x}{\csc^2 x + 3} \bigg) ' = \frac{\big( 2 \tan x \sec^2 x + 5 \big) \big( \csc^2 x + 3 \big) - \big( -2 \csc^2 x \cot x \big) \big( \tan^2 x + 5x \big)}{\big( \csc^2 x + 3 \big)^2}[/tex]

Substitute in derivatives:

[tex]\displaystyle y' = \frac{\big( -2 \cos x \sin x - \frac{3}{2\sqrt{x}} \big) \big( \sin^2 x + 6 \big) - \big( 2 \sin x \cos x \big) \big( \cos^2 x - 3\sqrt{x} + 6 \big)}{\big( \sin^2 x + 6 \big)^2} \frac{\tan^2 x + 5x}{\csc^2 x + 3} + \frac{\cos^2 x - 3\sqrt{x} +6}{\sin^2 x + 6} \frac{\big( 2 \tan x \sec^2 x + 5 \big) \big( \csc^2 x + 3 \big) - \big( -2 \csc^2 x \cot x \big) \big( \tan^2 x + 5x \big)}{\big( \csc^2 x + 3 \big)^2}[/tex]

Simplify:

[tex]\displaystyle y' = \frac{\big( \tan^2 x + 5x \big) \bigg[ \big( -2 \cos x \sin x - \frac{3}{2\sqrt{x}} \big) \big( \sin^2 x + 6 \big) - 2 \sin x \cos x \big( \cos^2 x - 3\sqrt{x} + 6 \big) \bigg]}{\big( \sin^2 x + 6 \big)^2 \big( \csc^2 x + 3 \big)} + \frac{\big( \cos^2 x - 3\sqrt{x} +6 \big) \bigg[ \big( 2 \tan x \sec^2 x + 5 \big) \big( \csc^2 x + 3 \big) + 2 \csc^2 x \cot x \big( \tan^2 x + 5x \big) \bigg] }{\big( \csc^2 x + 3 \big)^2 \big( \sin^2 x + 6 \big)}[/tex]

We can rewrite the differential by factoring and common mathematical properties to obtain our final answer:

[tex]\displaystyle y' = \frac{\big( -2 \cos x \sin x - \frac{3}{2\sqrt{x}} \big) \big( \tan^2 x + 5x \big) + \big( \cos^2 x - 3\sqrt{x} + 6 \big) \big( 2 \sec^2 x \tan x + 5 \big)}{ \big( \csc^2 x + 3 \big) \big( \sin^2 x + 6 \big)} + \frac{2 \cot x \csc^2 x \big( \cos^2 x - 3\sqrt{x} + 6 \big) \big( \tan^2 x + 5x \big)}{\big( \csc^2 x + 3 \big)^2 \big( \sin^2x + 6 \big)} - \frac{2 \cos x \sin x \big( \cos^2 x - 3\sqrt{x} + 6 \big) \big( \tan^2 x + 5x \big)}{\big( \csc^2 x + 3 \big) \big( \sin^2 x + 6 \big)^2}[/tex]

∴ we have found our derivative.

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Topic: Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Differentiation

Answer:

-9+x=-20

Step-by-step explanation:

I am not so positive on this one, but if you are not doing inequalities, then this should be correct.

"More than" would insinuate that you are adding. In this class, you would have a number to replace that x, but since no number was given, you place the x in its place. x=-11, because when you "add" -9 with something to get -20, it would have to be -11. Negative numbers can be confusing because when you subtract a negative number by another negative, you end up with a negative. Like in this case. Normally, you would just put -11, so it would look like -9 - 11 = -20. But since this says "more than", unless you are doing inequalities, you add.

If you are doing inequalities, then your answer should be this:

-9 > x = -20

I hope this helps!

-No one

Answer:

6.4

Step-by-step explanation:

she has been riding her bike for 6.4 hours.

I think the radius would be 13.9 ft

calculate the sides of the rectangle in scale factor model

Length: 18 * 1/4 = 4.5 feet

Width: 16 * 1/4 = 4 feet

Rectangle area in scale factor model:

Length * Width

4.5 * 4

18 feet²

Answer:

Given dimensions of a rectangular dining table:

If a scale factor of [tex]\dfrac14[/tex] is used, then we need to multiply each measurement by [tex]\dfrac14[/tex]:

[tex]\implies \textsf{width}=18 \times \dfrac14[/tex]

                [tex]=4.5 \textsf{ units}[/tex]

[tex]\implies \textsf{length}=16 \times \dfrac14[/tex]

                 [tex]=4 \textsf{ units}[/tex]

Therefore, the scale model of the dining room will be 4.5 by 4 units.

Answer:

First Blank: “controlled” Second Blank: "a Different" Third Blank: "the same" Last Blank: "Height of the ramp"

Step-by-step explanation:

Answer:

P = 48in

Step-by-step explanation:

P=4a=4·12=48in

Answer:

11.07~

Step-by-step explanation:

2/7 of 15.5 is 4.42857142857 which we can round to 4.43. We can then just do 15.5-4.43 to get our answer of 11.07.

[tex] \sqrt[3]{ {x}^{5}y } = {x}^{ \frac{5}{3} } {y}^{ \frac{1}{3} } \\ [/tex]

Thus the second option is the correct answer

Answer: 24/5=4.8  36/8=4.5

Step-by-step explanation: First, let's start off by dividing 24 by 5. We can turn this into 24.0 divided by 5 to make it a bit simpler. We know that 240 by 5 = 48, then since there is a decimal 1 digit to the left in 24.0, we apply that decimal 1 digit to the left in 48, making it 4.8! Now let's do 36 by 8. We can do what we did for problem 1 and turn 36 into 36.0, 360 by 8 = 45 and applying the same logic we used before, 360 turns into 36.0, and 45 turns into 4.5! Therefore, Kalel is wrong, and the two equation is not equal.

P.S. Using long division, Kalel is technically kind of right, but there's still that unaccounted for '4' that we still need to divide.

Answer:

1/[tex]\sqrt{2}[/tex] - 1/4

Step-by-step explanation:

We can write 2[tex]\sqrt{8}[/tex] as 2*[tex]\sqrt{4}[/tex]*[tex]\sqrt{2}[/tex]

That becomes 4[tex]\sqrt{2}[/tex], since the square root of 4 is 2 (±2, to be exact)

(4/(4[tex]\sqrt{2}[/tex])  - ( [tex]\sqrt{2}[/tex]/4[tex]\sqrt{2}[/tex])

1/[tex]\sqrt{2}[/tex] - 1/4

Answer:

45 divide by 19 =2 r 7 thanks

[tex]f(x) =2 x+1 \\\\ \text{If x = 2,}\\\\f(2) = 2(2) +1 = 4+1 = 5[/tex]

Answer:

5

Step-by-step explanation:

plug 2 in for x

f(2) = 2(2) + 1

f(2) = 5 [Asnwer]

PLEASE RATE!! I hope this helps!!

If you have any questions comment below

Answer: There are 2 different unit rates here:

The increase of the tree's height per year

The increase of the tree's trunk per year

Rate of tree's height per year

= 33m / 150 years = 0.22m per year.

Rate of tree's trunk per year

= 3m / 150 years = 0.02m per year.

Answer:

Step-by-step explanation: 5.6 would be the add on to 27 so since it included the key word '' left'' you'd substract the two and you'd get your answer, just use calculator. You got this!!!

Go sub to clan fbib !!!!!

Step-by-step explanation:

mean = sum of all data points / number of data points

(22+16+18+14+16+34+20)/7 = 140/7 = 20

median is the number, where half of the data points are smaller, and the other half are larger.

first we need to sort the data points

14, 16, 16, 18, 20, 22, 34

median = 18

mode is the data point occurring most often.

mode = 16 (occurring 2 times, while the others occur only once).

range is the difference between the largest and the smallest data point.

range = 34 - 14 = 20

Answer:

Below,

Step-by-step explanation:

f(x)=-(x+2)^2+4

(a) Vertex form

(b)  a = -1 , h = -2 and k = 4.

     vertex = (-2, 4)

(c) The value of a, -1 will invert it vertically or we can describe it as a reflection in the line y = 4. The graph will change from a U shape to a ∩ shape.

Answer:Compute the variance: 49+25+16+9+1+16+36+648=27.

The variance is a measure of the dispersion and its value is lower for tightly grouped data than for widely spread data. In the example above, the variance is 27. What does it mean to say that tightly grouped data will have a low variance? You can probably already imagine that the size of the variance also depends on the size of the data itself. Below we see ways that mathematicians have tried to standardize the variance.

Step-by-step explanation:

Answer:

A. False

B. True

C. False

D. True

E. False

Answer:

8.28

Step-by-step explanation:

we can express this question as

12.25/1.7=x/1.15

this can be simplified to

x=8.28

The height of Naomi's school building is 8.29 meters

Two triangles are similar if their corresponding angles are equal and their corresponding sides are within the same ratio (or proportion). Similar triangles will have the same shape, but not necessarily the same size.

In the given question and attached figure we have,

Now we have to find the height(AB) of the building,

By the properties of similar triangles, we can write,

AB / BC = DE / CD

Putting all the values we get,

AB / 12.25 = 1.15 / 1.7

Simplifying we get,

AB = (1.15 / 1.7) × 12.25

By further simplifying,

AB = 8.29 meters

Therefore, the height of Naomi's school building is 8.29 meters.

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Answer:

just trust yourself

Step-by-step explanation:

Answer:

72%

Step-by-step explanation:

We have 10 sudents in class 1 and 40 in the other for a total of 50 students.

The 10 in class 1 had a mean of 80 so we do 80x10=800

The mean of the class of 40 is 70, so we do 40x70=2800

we add both of those together to get 3600 then we divide that by 50 because there are 50 students in total.

3600/50=72.

Step-by-step explanation:

let ratio be 4x and 3x

sum : 490$

4x+3x = 490

7x=490

x=490/7

Hence x = 70

first daughter gets = 4x =4 x 70 = 280

second daughter gets =3x = 3x 70 = 210

first daugter gets the larger share

Answer:

Distributive property. When you factor out a GCF, from 12x + 6y, you would get 6(2x+y).

Step-by-step explanation:

12x + 6y is equivalent to 2x + y using the distributive property of multiplication over addition.

A number system is defined as a system of writing to express numbers.

The distributive property states that a(b + c) = ab + ac, where a, b, and c are any real numbers.

We can apply this property to the expression 2x + y by multiplying 2x by 6 and y by 6, giving:

12x + 6y = 6(2x) + 6(y)

Then, we can use the distributive property again to simplify the expression inside the parentheses:

6(2x) + 6(y) = 6(2x + y)

Substituting this expression back into the original equation, we get:

12x + 6y = 6(2x + y)

Simplifying further by dividing both sides by 6, we obtain:

2x + y = 12x/6 + 6y/6

2x + y = 2x + y

Therefore, we have shown that 12x + 6y is equivalent to 2x + y using the distributive property of multiplication over addition.

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Step-by-step explanation:

Let width be x

according to question

length = 2x-4

perimeter = 58

now,

perimeter = 2(length + width)

58 = 2(x+2x-4)

58 = 6x-8

6x = 66

x = 11

putting value of x in length

2x-4

= 2 X 11 -5

= 18

hence the dimensions of the rectangle is 18 and 11

Answer:

d = 7.2

Step-by-step explanation:

12 + d = -4.8

subtract 12 from both sides and you get

d = 7.2

Answer:

  -16.8

Step-by-step explanation:

The equation can be solved by performing the inverse of the operation that is done to the variable. Here, 12 is added to the variable. The inverse of that operation is addition of the "additive inverse", or "opposite" of 12:

  12 + d = -4.8 . . . . . . given equation

  12 -12 +d = -4.8 -12 . . . . . the same operation is done to both sides

  d = -16.8

The value of d that makes the equation true is -16.8.

_____

The addition (subtraction) property of equality tells you that adding (subtracting) the same number from both sides of an equation will not change the value of the variable.

Answer:

the volume should be 9.42