The length of the base of an isosceles triangle is x. The length of a leg is 3x−7. The perimeter of the triangle is 77. Find x.

Answer:

[tex]x-25=7[/tex]

Step-by-step explanation:

First, we must understand the operation occurring. The sentence clearly tells us that we are subtracting. The next important step is finding out the order. In the equation 25 is being taken away from the number; this means that the equation should be [tex]x-25[/tex]. Then, it says that the result is 7. This means the expression should equal 7.

Finally, x=32. This can be solved by adding 25 to both sides.

Answer:

answer is 55° ..........

Answer: 18,27,36

Step-by-step explanation: We have to add all the ratios to get 9 and then divide 81 by 9 and get 9. The multiple 2, 3 and 4 by 9 getting 18, 27 and 36 respectively.

Answer:

Step-by-step explanation:

Area of the rectangular garden is given by the expression,

Area = 6(2x + 5y)

By distributive property,

6(2x + 5y) = 12x + 30y

Therefore, equivalent expression for the area will be,

Area = (12x + 30y)

For x = 3 and y = 4,

Area = 12×(3) + 30×(4)

        = 36 + 120

        = 156

Area of the rectangular garden = 156 square feet.

Answer:

The perimeter of the figure is 114.6

Step-by-step explanation:

If we add all of the numbers given to us, we can find the perimeter's value. So 8+12.3+6.2 etc.

Answer:

114.6

Step-by-step explanation:

just add all the sides together

Answer:

????

Step-by-step explanation:

Where's the equation? diagram?

Answer:

How we supposed to answer with no equation

Step-by-step explanation:

Answer:

Step-by-step explanation:

(-5,-1)  & (-2, -3)

[tex]Slope= \frac{y_{2}-y_{1}}{x_{2}-x_{1}}\\\\= \frac{-3-[-1]}{-2-[-5]}\\\\= \frac{-3+1}{-2+5}\\\\= \frac{-2}{3}[/tex]

m= -2/3  ; (-5,-1)

[tex]y-y_{1}=m(x-x_{1})\\\\y-[-1]= \frac{-2}{3}(x-[-5])\\\\y+1= \frac{-2}{3}(x+5)\\\\y+1=\frac{-2}{3}x+5*\frac{-2}{3}\\\\y+1=\frac{-2}{3}x+\frac{-10}{3}\\\\y=\frac{-2}{3}x+\frac{-10}{3}-1\\\\y=\frac{-2}{3}x+\frac{-10}{3}-\frac{3}{3}\\\\y=\frac{-2}{3}x-\frac{13}{3}[/tex]

The Torque function is T(t) = 3sin((t-5)π/30).

When an engine exerts itself, torque, which is a twisting force, speaks to the rotational force of the engine and quantifies how much of that twisting force is accessible.

Given:

After 5 minutes Thomas ties it on, the torque is zero and increasing.

So, the sine function is shifted right 5 minutes.

and, The maximum value is 3.

Then, the multiplier of the sine function as the period is 60 minutes

Then, the coefficient of t = (2π/60)

                                         = π/30.

Hence, the Torque function is T(t) = 3sin((t-5)π/30).

Learn more about Torque here:

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Answer: None because i dont like cans of paint

Step-by-step explanation: If you dont like cans then you wont like beans. So if d33z + nutz = d33znutz then cans + paint = canspaint

Answer:

see explanation

Step-by-step explanation:

If (x - 1) is a factor then f(1) = 0

Given

f(x) = x³ - 13x² + 32x - 20 , then

f(1) = 1³ - 13(1)² + 32(1) - 20

     = 1 - 13 + 32 - 20

     = 0

Since f(1) = 0 then (x - 1) is a factor

Using Synthetic division

 1  | 1  - 13   32   - 20

      ↓    1   - 12      20    

     -----------------------------

      1    - 12   20     0 ← remainder

quotient = x² - 12x + 20 = (x - 2)(x - 10)

Then

x³ - 13x² + 32x - 20 = (x - 1)(x - 2)(x - 10) ← in factored form

Answer:

4x² - 12x + 9

Step-by-step explanation:

Use the foil method.

(2x - 3) (2x - 3)

= 4x²- 6x - 6x + 9

= 4x² - 12x + 9

Answer:

[tex]Square \ of \ (2x - 3) = 4x^2 - 12x + 9[/tex]

Step-by-step explanation:

[tex](a +b)^2 = a^2 + b^2 + 2ab[/tex]

  [tex](2x + (- 3))^2 = (2x)^2 + ( -3 )^2 + ( 2\times 2x \times - 3)\\\\[/tex]

                    [tex]= 4x^2 + 9 + ( -12x)\\\\=4x^2 - 12 x + 9[/tex]

Answer:

The width is [tex]82m[/tex]

Step-by-step explanation:

------------------------------>>>>

The formula to find the area of a rectangle is [tex]A=lw[/tex]

We already know the area of the rectangular field which is [tex]7626m[/tex]

We already know the length is [tex]93m[/tex]

--------------->>>>

Now let's substitute [tex]7626[/tex] for [tex]A[/tex] because that's the area and substitute [tex]93[/tex] for [tex]l[/tex] because that's the length. After that, let's solve to find the width.

[tex]7626=93w[/tex]

Divide both sides by 93 because that's the opposite of multiplication.

[tex]82=w[/tex]

--------------->>>>

This means that the width of the rectangular field is [tex]82m[/tex]

Hope this is helpful

Answe$12.15

Step-by-step explanation:

She paid 60% of the price...

x + .6x = 32.40

1.6x = 32.40

x=20.25

20.25 * .60 = 12.15

Answer:

x      -2      -1       0      1

y      -1       2        5      8

Step-by-step explanation:

y=3x+5

When x=-2

y=3(-2)+5

y=-6+5

y=-1

when x=-1

y=3(-1)+5

y=-3+5

y=2

whenx=0

y=3(0)+5

y=5

When x=1

y=3(1)+5

y=3+5

y=8

Answer:

Yeah, you can prove with the use of alternate interior angles, alternate exterior angles, and parallel angles. That's why they're similar.

Step-by-step explanation:

Answer:

a) 421mm² = 0.000421 m²

b) 9.3kg²= 9,300,000 g²

c) 25kL²= 25,000,000 L²

d) 1439m²= 0.001439 km²

Answer:

2 days

Step-by-step explanation:

It takes four plumbers five days

total labor needed

4 * 5 = 20 days

How long would it take ten plumbers?

20 / 10 = 2 days

Answer:

x=20, g=100, f=80

Step-by-step explanation:

when ever somthing is suplementary it means the the answer will euqal to 180 degrees. That means your equation is going to be

3x+40+5x-20=180

8x+20=180

8x=160

x=20

Finding g

3(20)+40

60+40

g=100

FInding f

5(20)-20

100-20

f=80

Answer:

4   5

Step-by-step explanation:

I got it right here.

The factored form of (20x² – 12x) + (25x– 15) is (4x+ 5)( 5x- 3).

The process of breaking or decomposing an entity (such as a number, a matrix, or a polynomial) into a product of another entity, or factors, whose multiplication results in the original number, matrix, etc., is known as factorisation or factoring.

Given:

(20x² – 12x) + (25x– 15)

or, 4x(5x – 3) + 5(5x – 3)

or, (4x+ 5)( 5x- 3)

Hence, the factored form of (20x² – 12x) + (25x– 15) is (4x+ 5)( 5x- 3).

Learn more about factorize here:

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Answer:

x = [tex]\frac{2}{3}[/tex]

Step-by-step explanation:

Given

[tex]\sqrt{8x}[/tex] = [tex]\sqrt{4+2x}[/tex] ( square both sides )

8x = 4 + 2x ( subtract 2x from both sides )

6x = 4 ( divide both sides by 6 )

x = [tex]\frac{4}{6}[/tex] = [tex]\frac{2}{3}[/tex]

Answer:

108.56

Step-by-step explanation:

First find the amount of the tip

92 * 18%

92 * .18

16.56

Add this to the amount of the bill

92+16.56

108.56

Answer:

108.56

Step-by-step explanation:

92$ + .18*92 = 108.56$

Hi there!  

»»————-　★　————-««

I believe your answer is:  

[tex]8(y-2)[/tex]

»»————-　★　————-««  

Here’s why:

⸻⸻⸻⸻

[tex]\boxed{\text{Simplifying the Expression:}}\\\\8y-16\\------------------\\\rightarrow 8y-16\\\\\text{8 is a common factor in the terms. Pull out 8 to factor...}}\\\\\rightarrow \boxed{8(y-2)}[/tex]

⸻⸻⸻⸻

»»————-　★　————-««  

Hope this helps you. I apologize if it’s incorrect.  

Answer:

We can not find the answer with with equation since there is no comparison sign. To demonstrate this lets look at a way we could solve this equation.

8y-16=32

8y=48

y=6

Answer:

[tex]a_{n}[/tex] = 6n + 1

Step-by-step explanation:

This is an arithmetic sequence with nth term

[tex]a_{n}[/tex] = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Here a₁ = 13 - 6 = 7 and d = 6 , then

[tex]a_{n}[/tex] = 7 + 6(n - 1) = 7 + 6n - 6 = 6n + 1

Answer:

the first few terms would be

7, 13, 19, 25, 31

nth term = 7 + 6(n+1)

nth term = 7+ 6n + 6

nth term = 6n + 13

Answer:

[tex]\displaystyle x > 6[/tex]

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Equality Properties

Algebra I

Algebra II

Step-by-step explanation:

Step 1: Define

Identify

[tex]\displaystyle 3^{6x + 18} < 27^{3x}[/tex]

Step 2: Solve for x

Answer:

[tex]x>6[/tex]

Step-by-step explanation:

When given the following equation;

[tex]3^(^6^x^+^1^8)<27^(^3^x^)[/tex]

One is asked to solve for ([tex]x[/tex]). The inequality has exponents, hence, it appears daunting at first, however, the easiest way to deal with exponents is to bring them to the same base. This allows for one to have the ability to treat the exponents like an ordinary number. Since ([tex]27=3^3[/tex]) one can rewrite ([tex]27^(^3^x^)[/tex]) as ([tex]3^3^*^(^3^x^)[/tex]). This is possible because raising a number to an exponent when it already has an exponent is the same as multiplying the two exponents. Rewrite the inequality in this format;

[tex]3^(^6^x^+^1^8)<3^3^(^3^x^)[/tex]

Simplify,

[tex]3^(^6^x^+^1^8^)<3^(^9^x^)[/tex]

Since the bases are the same they no longer have any relevance, so one can ignore the bases and only work with the exponents,

[tex]6x+18<9x[/tex]

Now solve this inequality like a  normal inequality. Use inverse operations;

[tex]6x+18<9x[/tex]

[tex]18<3x[/tex]

[tex]6<x[/tex]

Answer:

Step-by-step explanation:

P = 90

r = 40% = 40/100 = 0.4

t = 3 years

It is not clear to me what this means. Is the 40% for each year for 3 years or is the interest rate = 40% period. I know that in some of the poorer countries, this is not an unusual amount to pay for each year he holds the loan.

I will take it as 40% for each year for 3 years.

i = prt = 90 * 0.4 * 3

i = 108

Answer: y= -7

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

(3)(−4)=y−5

−12=y+−5

−12=y−5

Step 2: Flip the equation.

y−5=−12

Step 3: Add 5 to both sides.

y−5+5=−12+5

y=−7

[tex]\huge\text{Hey there!}[/tex]

[tex]\large\textsf{3x = y - 5}\\\\\large\textsf{3(-4) = y - 5}\\\\\large\textsf{3(-4) = \boxed{\bf -12}}\\\\\large\textsf{-12 = y - 5}\\\\\large\textsf{TURN the EQUATION}\\\\\large\textsf{y - 5 = 12}\\\\\large\textsf{ADD 5 to BOTH SIDES}\\\\\large\textsf{y - 5 + 5 = -12 + 5}\\\\\large\textsf{CANCEL out: -5 + 5 because that gives you 0}\\\large\textsf{KEEP: -12 + 5 because that gives you the y-value}\\\\\large\textsf{y = -12 + 5}\\\\\large\textsf{-12 + 5 =\boxed{\bf -7}}[/tex]

[tex]\boxed{\boxed{\large\textsf{Answer: \huge \bf y = -7}}}\huge\checkmark[/tex]

[tex]\large\text{Good luck on your assignment and enjoy your day!}[/tex]

~[tex]\frak{Amphitrite1040:)}[/tex]