There are 120 students in class 7. it is known that 2 3 out of them like maths, out of which 35 are girls. also, out of total students, 3 5 are boys. (3) (a) what is the number of girls in the class? (b) how many students like maths? (c) how many boys like maths?

The exponential likelihood that the next call would occur in more than 21 seconds but less than 26 seconds is 0.1504, which corresponds to option (C) on the multiple-choice list.

We may use an exponential distribution with a mean of 31 seconds to simulate the period between calls.

The exponential distribution's probability density function is given by:

f(x) = λe^(-λx)

where λ is the rate parameter, which is equal to 1/mean in this case.

So, we have λ = 1/31 and we need to find the probability that the time between calls is between 21 and 26 seconds. This can be expressed as:

P(21 < X < 26) = ∫21²⁶ λe^(-λx) dx

Using a calculator or integration software, we can find:

P(21 < X < 26) = 0.1504

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By mathematical induction, the equation 1 + 3 + 5 + ... + (2n - 1) = n² is true for every positive integer n.

Using mathematical induction, we can verify that the equation 1 + 3 + 5 + ... + (2n - 1) = n² is true for every positive integer n.
Base case (n=1): 2(1) - 1 = 1, and 1² = 1, so the equation holds for n=1.
Inductive step: Assume the equation is true for n=k, i.e., 1 + 3 + ... + (2k - 1) = k². We must prove it's true for n=k+1.
Consider the sum 1 + 3 + ... + (2k - 1) + (2(k+1) - 1). By the inductive hypothesis, the sum up to (2k - 1) is equal to k². Thus, the new sum is k² + (2k + 1).
Now, let's examine (k+1)²: (k+1)² = k² + 2k + 1.
Comparing the two expressions, we find that they are equal: k^2 + (2k + 1) = k² + 2k + 1. Therefore, the equation holds for n=k+1.
By mathematical induction, the equation 1 + 3 + 5 + ... + (2n - 1) = n² is true for every positive integer n.

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The best interpretation of Ellen's z-score of -1.9 is that her weight is 1.9 standard deviations below the mean weight. This means that her weight is significantly lower than the average weight for individuals in the population.

The standard deviation is a measure of how much the values in a dataset vary from the mean, and a negative z-score indicates that Ellen's weight is below the mean. The value of -1.9 means that her weight is farther from the mean than about 97.7% of the values in the dataset, as approximately 2.5% of the values fall on each side of the mean in a normal distribution.It is important to note that the z-score only tells us how far away a value is from the mean in terms of standard deviations, and does not provide information about the actual value itself. Therefore, we cannot determine Ellen's actual weight from this z-score alone. Additionally, it is incorrect to interpret the z-score as being in terms of pounds, as the standard deviation is a unit of measurement used to describe variability, and may not necessarily correspond to a specific weight or measurement.

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To evaluate the series Σ(3^n/(141·3²ⁿ) from n=1 to infinity converges or diverges, we can use the ratio test.

The ratio test states that if the limit of the absolute value of the ratio of consecutive terms is less than 1, then the series converges absolutely;

if the limit is greater than 1, then the series diverges; and if the limit is exactly 1, then the test is inconclusive.

Let's first apply the ratio test to this series:

| (3ⁿ+¹/(141·3²ⁿ+¹) * (141·3²ⁿ))/(3ⁿ |

= | 3/141 |

= 1/47

Since the limit of the absolute value of the ratio of consecutive terms is less than 1, the series converges absolutely.

To compute the sum of the series, we can use the formula for the sum of a geometric series:

Σ(3ⁿ/(141·3²ⁿ) = 3/141 Σ(1/9)ⁿ from n=1 to infinity

= (3/141) · (1/(1-(1/9)))

= 27/470

Therefore, the series converges absolutely and its sum is 27/470.

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Answer:

20 bunnies mrs w would have

The answer 44 I took a quiz and that was the answer.

The masses of central black holes in galaxies are correlated with the bulge masses of those galaxies.

This correlation suggests that there is a connection or relationship between growth of a galaxy's central black hole and growth of its bulge.

Specifically, observations have shown that galaxies with more massive bulges tend to have more massive central black holes.

This implies that the growth of the central black hole and the growth of the bulge are linked or influenced by similar processes or mechanisms.

The exact nature of this relationship is still an active area of research in astrophysics.

Various theories and models have been proposed to explain the observed correlation.

Including the idea that the growth of the central black hole and the bulge are regulated by feedback mechanisms.

Involving the accretion of matter onto the black hole and the release of energy in the form of radiation or outflows.

The observed relationship between the masses of central black holes and the bulge masses of galaxies provides,

Valuable insights into the co-evolution of galaxies and their central supermassive black holes.

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Using the Runge-Kutta method of second order, the approximate value of y when x = 0.02 is is 1.0203045100525125.

To apply the Runge-Kutta method of second order to approximate the value of y when x = 0.02, we can follow these steps:

[tex]y' = x^2 + y[/tex]

y(0) = 1

h = 0.01 (step size)

x = 0.02 (desired x-value)

The general formula for the second-order Runge-Kutta method is:

y(i+1) = y(i) + (k1 + k2)/2

where

k1 = h * f(x(i), y(i))

k2 = h * f(x(i) + h, y(i) + k1)

Let's calculate the values step by step:

Set x(0) = 0, y(0) = 1.

k1 = h * f(x(0), y(0))

[tex]= 0.01 * (0^2 + 1)[/tex]

  = 0.01

k2 = h * f(x(0) + h, y(0) + k1)

[tex]= 0.01 * ((0 + 0.01)^2 + 1 + 0.01)[/tex]

  = 0.01 * (0.0001 + 1.01)

  = 0.010101

y(1) = y(0) + (k1 + k2)/2

    = 1 + (0.01 + 0.010101)/2

    = 1 + 0.020101/2

    = 1.0100505

Let's perform the calculations iteratively:

Iteration 1:

x = 0.01

y = 1.0100505 (from Step 4)

Iteration 2:

Now we need to repeat steps 2-4 with the new x and y values:

k1 = h * f(x(1), y(1))

[tex]= 0.01 * (0.01^2 + 1.0100505)[/tex]

  = 0.0102010050025

k2 = h * f(x(1) + h, y(1) + k1)

[tex]= 0.01 * ((0.01 + 0.01)^2 + 1.0100505 + 0.0102010050025)[/tex]

  = 0.010307015102525

y(2) = y(1) + (k1 + k2)/2

    = 1.0100505 + (0.0102010050025 + 0.010307015102525)/2

    = 1.0203045100525125

After the second iteration, when x = 0.02,

we obtain y ≈ 1.0203045100525125.

Therefore, the approximate value of y when x = 0.02 using the Runge-Kutta method of second order is 1.0203045100525125.

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The situation which can be represented by the graph is the relationship between price and supply in economics which have a directly proportional relationship.

In Economics, where all things are equal, the quantity of goods supplied represented by the x-axis increased as the price of the commodities increased.

Note that the price is represented or usually plotted on the Y-axis.

Thus, it is correct to depict such a situation with the above graph.

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If SSR = 47 and SSE = 12, the correlation coefficient R is approximately ±0.8925.

HTo find the coefficient of determination (R-squared or R²) using SSR (Sum of Squares Regression) and SSE (Sum of Squares Error), you'll first need to calculate the total sum of squares (SST), and then use the formula R² = SSR/SST. Here are the steps:

1. Calculate SST: SST = SSR + SSE
  In this case, SST = 47 + 12 = 59
2. Calculate R²: R² = SSR/SST
  For this problem, R² = 47/59 ≈ 0.7966

Since R (correlation coefficient) is the square root of R², you need to take the square root of 0.7966. Keep in mind, R can be either positive or negative depending on the direction of the relationship between the variables. However, since we do not have information about the direction, we'll just provide the absolute value of R:

3. Calculate R: R = √R²
  In this case, R = √0.7966 ≈ 0.8925

So, if SSR = 47 and SSE = 12, the correlation coefficient R is approximately ±0.8925.

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Q1.  Farmer Joe will need approximately 15.71 feet of fence to enclose the rose bush with 1 foot of clearance.

Q2.  the area of the rose bush bed is approximately 7.07 square feet, and the fertilizer bag covers 35 square feet, Farmer Joe will have more than enough fertilizer for the rose bush.

Q1: To calculate the amount of fence Farmer Joe will need for the rose bush, we need to consider the perimeter of the circular fence.

The diameter of the rose bush is 3 feet, so the radius (half of the diameter) is 3/2 = 1.5 feet. Since he needs 1 foot of clearance around the bush, the radius of the circular fence will be 1.5 + 1 = 2.5 feet.

The formula for the circumference (perimeter) of a circle is C = 2πr, where π is a mathematical constant approximately equal to 3.14159. Plugging in the value of the radius, we get:

C = 2 * 3.14159 * 2.5 = 15.70795 feet.

Therefore, Farmer Joe will need approximately 15.71 feet of fence to enclose the rose bush with 1 foot of clearance.

Q2: The fertilizer bag covers an area of 35 square feet. To determine if it will be enough for the rose bush, we need to calculate the area of the circular bed where the rose bush will be planted.

The area of a circle is given by the formula A = πr^2. Plugging in the value of the radius (1.5 feet), we have:

A = 3.14159 * (1.5)^2 = 3.14159 * 2.25 = 7.06858 square feet.

Since the area of the rose bush bed is approximately 7.07 square feet, and the fertilizer bag covers 35 square feet, Farmer Joe will have more than enough fertilizer for the rose bush.

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All angles lying between 0 and 2π satisfying the condition cos x = 1/2 are π/3 and 5π/3. These angles are mainly: π/3, 5π/3 + 2π, and 5π/3 + 4π, and can be simplified to: π/3, 11π/3, and 19π/3.

Given the condition cos x = 1/2, we know that the angle x must be one of the angles for which cos is equal to 1/2, which are π/3 and 5π/3. However, the range of x is 0 ≤ x ≤ 2π. Therefore, we must find all the angles in this range that satisfy the given condition. These angles are: π/3, 5π/3 + 2π, and 5π/3 + 4π, which simplifies to: π/3, 11π/3, 19π/3.

Since 11π/3 and 19π/3 are greater than 2π, we need to subtract 2π from each to get them into the range 0 ≤ x ≤ 2π, which gives: π/3 and 5π/3 as the solutions in this range.

Therefore, all angles between 0 and 2π satisfying the condition, cos x= 1/2 are:π/3 and 5π/3.

We know that cos x is periodic, with a period of 2π, and that its value is equal to 1/2 at two different angles in the interval [0, 2π), which are π/3 and 5π/3. Since we are asked to find all angles that satisfy the condition cos x = 1/2 in this interval, we must add 2π to the second solution, which gives us 11π/3.

However, this is greater than 2π, so we must subtract 2π to get it into the desired range, which gives us 5π/3. Similarly, we must add 4π to the second solution, which gives us 19π/3. However, this is also greater than 2π, so we must subtract 2π to get it into the desired range, which gives us 11π/3.

Therefore, the solutions in the interval [0, 2π) are π/3 and 5π/3. These are the only solutions in this interval since the cosine function has a maximum value of 1 and a minimum value of -1, so it can only equal 1/2 at two angles between 0 and 2π. Thus, all angles between 0 and 2π satisfying the condition cos x = 1/2 are π/3 and 5π/3.

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The answer is ,the best description of the sampling distribution of the sample proportion is the "proportions who approve of the president within all possible samples of this size".

The proportion who approves of the president within all possible samples of this size best describes the sampling distribution of the sample proportion in this situation.

Suppose the true proportion of voters who approve of the president is p.

Then, the distribution of the sample proportions is called a sampling distribution.

The central limit theorem indicates that the sampling distribution will be normally distributed if the sample size is large enough.

In this case, the sample size is 3500 voters, which is considered a large sample size.

Therefore, the sampling distribution of the sample proportion will be normally distributed.

The best description of the sampling distribution of the sample proportion is the "proportions who approve of the president within all possible samples of this size".

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The correct option is "The population is the total number of people who go to the mall, and the sample is the first 300 people at the mall."

The total number of people who visit the mall in this instance constitutes the population, which is the complete group of people we are interested in investigating or drawing conclusions about. The first 300 people to visit the mall were surveyed about their favourite food court restaurant, whereas the sample, on the other hand, refers to a subset of the population chosen to reflect the population and to provide information about it.

It's crucial to keep in mind that the 300-person sample might not accurately reflect the whole population of mall-goers, since some demographic groups might be more inclined to attend the mall at particular times of the day or week. However, the surveyors made an effort to reduce any bias that might have affected the sample by choosing individuals at random from the first 300 persons to enter the mall.

In addition, the study only asks respondents about their favourite restaurant in the food court, thus it might not be able to give a complete picture of their dining preferences. The survey's findings may still be helpful in deciding what kinds of restaurants to include in the food court or in determining the level of popularity of particular eateries.

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Answer:

22,281.73

Step-by-step explanation:

1 kilometer = 1000 Meters

Subtract the 100 meters you already have from 1000.

Multiply 900 times 24.73

Add 22,257 to 24.73

= 22,281.73

The measure of the arc angle JA is 76 degrees.

The sum of angles in a cyclic quadrilateral is 360 degrees. The opposite angles in a cyclic quadrilateral is supplementary.

The measure of an arc intercepted by an angle of a quadrilateral that is inscribed in a circle is equal to two times the measure of the inscribed angle.

Therefore,

26x + 1 = 1 / 2 (18x + 4 + 6 + 32x)

26x + 1 = 1 / 2 (50x + 10)

26x + 1 = 25x + 5

26x - 25x = 5 - 1

x = 4

Therefore,

arc angle JA = 18x + 4

arc angle JA = 18(4) + 4

arc angle JA =72 + 4

arc angle JA = 76 degrees.

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The set S is linearly dependent.

To determine if the set S is linearly independent or dependent, we need to see if any of the vectors in the set can be written as a linear combination of the others.

Let's set up the equation:

a(3/2, 3/4, 5/2) + b(4, 7/2, 3) + c(?, -3/2, 2, 6) = (0,0,0)

To solve for a, b, and c, we can create a system of equations using each component:

3a/2 + 4b + c? = 0
3a/4 + 7b/2 - 3c/2 = 0
5a/2 + 3b + 2c = 0
6c = 0

The last equation tells us that c must be 0, since we can't have a non-zero scalar multiplying the zero vector.

Using the first three equations, we can solve for a and b:

a = (-8/3)c?
b = (5/3)c?

Since c can be any non-zero number, we can see that there are infinitely many solutions to this equation, meaning that the set S is linearly dependent.

Therefore, the answer is option B linearly dependent.

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The area of a regular n-gon with side length s is given by ns2(2 + √3)/4, or ns2tan(π/n)/4 using the trigonometric identity.

Consider a regular n-gon with side length s. We can divide the n-gon into n congruent isosceles triangles, each with base s and equal angles. Let one such triangle be denoted by ABC, where A and B are vertices of the n-gon and C is the midpoint of a side.

The angle at vertex A is equal to 360°/n since the n-gon is regular. The angle at vertex C is equal to half of that angle, or 180°/n, since C is the midpoint of a side. Thus, the angle at vertex B is equal to (360°/n - 180°/n) = 2π/n radians.

We can now use trigonometry to find the area of the triangle ABC: the height of the triangle is given by h = (s/2)tan(π/n), and the area is A = (1/2)sh. Since there are n such triangles in the n-gon, the total area is given by ns2tan(π/n)/4.

Using the fact that tan(π/12) = √6 - √2, we can simplify this expression to ns2(√6 - √2)/4. Multiplying top and bottom by (√6 + √2), we obtain ns2(2 + √3)/4.

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[tex] \sqrt{36 - 25} = \sqrt{11} \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ [/tex]

Given information:Gayle installed a rectangular section of hardwood flooring measuring 12 ft by 12 ft in her family room. She plans on increasing the area of the flooring to 256 ft2 by increasing the width and length by the same amount, x.

Formula for the area of a rectangular is given as follows:Area of a rectangular = Length × WidthLet, the width and length of the rectangular be x.So, the area of the rectangular after increasing the width and length by the same amount will be:(12 + x) × (12 + x)According to the question, the area of the rectangular after increasing the width and length by the same amount is 256.So, the equation that represents the given situation is:256 = (12 + x) × (12 + x)256 = (12 + x)²Answer:Option A: 256 = (12 + x) × (12 + x) is the correct equation to find x.

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Our power series is F(x) = ∑(n=0 to ∞) of (-1)ⁿ × x⁶ⁿ.The interval of convergence for the power series representation of F(x) is -1 < x < 1.

To find the power series representation for the function F(x) = 1/(1 + x⁶), we can use the geometric series formula.

The geometric series formula states that for |r| < 1, the series ∑(n=0 to ∞) of rⁿ converges to 1/(1 - r).

In this case, we can rewrite F(x) as:

F(x) = 1/(1 + x⁶) = (1 - (-x⁶))⁻¹

Now, we can see that this is a geometric series with r = -x⁶. Using the geometric series formula, we can express F(x) as a power series:

F(x) = (1 - (-x⁶)⁻¹) = ∑(n=0 to ∞) of (-x⁶)ⁿ

Expanding this series, we get:

F(x) = ∑(n=0 to ∞) of (-1)ⁿ × x⁶ⁿ)

So, the power series representation for F(x) is:

F(x) = ∑(n=0 to ∞) of (-1ⁿ) × x⁶ⁿ

To determine the interval of convergence for this power series, we need to find the values of x for which the series converges.

The interval of convergence is determined by the radius of convergence, which can be found using the ratio test. The ratio test states that for a power series ∑(n=0 to ∞) of a_n × (x - c)ⁿ, the series converges if the limit of |a_(n+1) / a_n| as n approaches infinity is less than 1.

In this case, our power series is:

F(x) = ∑(n=0 to ∞) of (-1)ⁿ × x⁶ⁿ

Using the ratio test, we have:

|((-1)ⁿ⁺¹ × x⁶[tex]^([/tex]ⁿ⁺¹[tex]^)[/tex]) / ((-1)ⁿ × x⁶ⁿ)| = |(-1) × x⁶| = |x⁶|

The limit of |x⁶| as n approaches infinity is |x⁶|. For the series to converge, |x⁶| must be less than 1. Therefore, the interval of convergence is:

|x⁶| < 1

which implies:

-1 < x⁶ < 1

Taking the sixth root of each inequality, we have:

-1 < x < 1

So, the interval of convergence for the power series representation of F(x) is -1 < x < 1.

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The roots of the equation 2x - 3 = -5x² are x = -1 and x = 3/5. Therefore, the correct options are (B) and (D).

To find the roots of the equation 2x - 3 = -5x², we need to solve the equation and determine the values of x that satisfy it.

Rearranging the equation, we have -5x² - 2x + 3 = 0.

To solve this quadratic equation, we can either factor it or use the quadratic formula. Let's use the quadratic formula:

x = (-b ± √(b² - 4ac)) / (2a)

For the equation -5x² - 2x + 3 = 0, the coefficients are:

a = -5, b = -2, c = 3.

Plugging these values into the quadratic formula, we get:

x = (-(-2) ± √((-2)² - 4(-5)(3))) / (2(-5))

x = (2 ± √(4 + 60)) / (-10)

x = (2 ± √64) / (-10)

x = (2 ± 8) / (-10)

Simplifying further:

x = (2 + 8) / (-10) or x = (2 - 8) / (-10)

x = 10 / (-10) or x = -6 / (-10)

x = -1 or x = 3/5

Therefore, the roots of the equation 2x - 3 = -5x² are x = -1 and x = 3/5.

Among the given options, the correct answers are:

D. x = -1

B. x = 3/5

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Based on the information provided, the demand for a product is given by the function D(x) = √300 - x, where x represents the price in dollars. In this function, the demand is expressed as a relationship between the price and the quantity of the product that consumers are willing to purchase.

To answer your question, let's first understand what demand for a product means. Demand refers to the quantity of a product that consumers are willing to buy at a particular price point. Typically, the higher the price of a product, the lower the demand for it. Now, coming back to your equation, the demand for a product is equal to √300 minus the price in dollars. So, if we put this equation into words, we can say that the demand for the product decreases as the price of the product increases. To put this into numbers, let's assume that the price of the product is 10 dollars. Substituting this value into the equation, we get the demand for the product as √300 - 10, which is equal to approximately 14 units. However, if the price of the product increases to 20 dollars, the demand will decrease to √300 - 20, which is equal to approximately 12 units. Therefore, the higher the price, the lower the demand for the product. In summary, this equation helps us understand the relationship between the price and demand for a product, and we can use it to make informed decisions regarding pricing strategies.

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The best point estimate for the ratio of population variances can be calculated using the F-statistic:

F = s1^2 / s2^2

where s1^2 is the sample variance of the first population, and s2^2 is the sample variance of the second population.

Given the sample statistics:

n1 = 24

n2 = 23

s1^2 = 55.094

s2^2 = 30.271

The F-statistic can be calculated as:

F = s1^2 / s2^2 = 55.094 / 30.271 = 1.8187

The point estimate for the ratio of population variances is therefore 1.8187. Rounded to four decimal places, the answer is 1.8187.

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It seems that you're asking about solving a system of differential equations using the elimination method. Unfortunately, the elimination method is used for solving systems of linear equations, not differential equations. The given system consists of second-order nonlinear differential equations.

To use the elimination method to solve the system:

1. Start by multiplying the first equation by y2 and the second equation by -y1.

2. This gives us:

y′′1y2 = 2y1y2t

-y′′2y1 = -y12y2et

3. Now we can add the two equations together:

y′′1y2 - y′′2y1 = 2y1y2t + y12y2et

4. This simplifies to:

(y1y2)'' = 2y1y2t + y12y2et

5. Finally, we can integrate both sides to get the solution:

y1y2 = ∫(2t + e-t) dt

y1y2 = t2 - e-t + C

where C is a constant of integration.

Therefore, the solution to the system using the elimination method is:

y1y2 = t2 - e-t + C

For such problems, you may want to consider using numerical methods like Euler's method or Runge-Kutta methods to obtain approximate solutions, or consult with a specialist in differential equations to explore other possible techniques for solving the given system.

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Main Answer:To solve this equation, we need an initial condition or boundary condition to determine the specific solution. Once we have the solution for z, we can substitute it back into the first equation (y′′ = 2yzt) to find the solution for y.

Supporting Question and Answer:

How do we solve a system of differential equations using the elimination method?

To solve a system of differential equations using the elimination method, we differentiate the equations and manipulate them to eliminate one variable at a time. This allows us to express one variable in terms of the other variables, reducing the system to a simpler set of equations.

Body of the Solution: To solve the system of differential equations using the elimination method, we will eliminate one variable at a time by differentiating the equations. Let's denote y₁ as y and y₂ as z for simplicity.

Given system:

y′′ = 2yzt z′′ = 2yz - e^t

Step 1: Differentiate the first equation with respect to t. y′′′ = 2(z′t + z) + 2yzt

Step 2: Substitute the value of y′′′ into the second equation. 2(z′t + z) + 2yzt = 2yz - e^t

Simplifying the equation:

2z′t + 2z + 2yzt = 2yz - e^t

Step 3: Rearrange the terms to isolate z′.

2z′t + 2z - 2yz + e^t = 0

Step 4: Divide the equation by 2t to isolate z′.

z′ + z/t - y + e^t/2t = 0

This equation represents a first-order linear differential equation in terms of z.

Final Answer:The single required equation is: z′ + z/t - y + e^t/2t = 0

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the values of x and y that satisfy the given equation are x = 1 and y = -1.

To determine the values of x and y in the equation:

(4+2i)(x+yi) + (3-2i) = 9-4i

We can expand the left side of the equation using the distributive property:

(4x + 2ix + 4yi - 2y) + (3 - 2i) = 9 - 4i

Group the real and imaginary terms together:

(4x - 2y + 3) + (2ix + 4yi - 2i) = 9 - 4i

Now, equating the real parts and imaginary parts on both sides of the equation, we have:

Real Part:

4x - 2y + 3 = 9

Imaginary Part:

2ix + 4yi - 2i = -4i

From the real part equation, we can solve for x and y:

4x - 2y = 9 - 3

4x - 2y = 6

2x - y = 3      (Dividing by 2)

From the imaginary part equation, we can solve for x and y:

2ix + 4yi - 2i = -4i

2ix + 4yi = -4i + 2i

2ix + 4yi = -2i

2x + 4y = -2      (Dividing by i)

Now, we have a system of linear equations:

2x - y = 3

2x + 4y = -2

To solve this system, we can use the method of substitution or elimination. Let's use the elimination method:

Multiply the first equation by 2 to eliminate the x term:

(2)(2x - y) = (2)(3)

4x - 2y = 6

Now, subtract the second equation from the modified first equation:

(4x - 2y) - (2x + 4y) = 6 - (-2)

4x - 2x - 2y - 4y = 6 + 2

2x - 6y = 8

Simplifying further, we get:

2x - 6y = 8    ---(3)

Now, we have two equations:

2x + 4y = -2   ---(2)

2x - 6y = 8    ---(3)

Multiply equation (2) by 3 and equation (3) by 2 to eliminate the x term:

(3)(2x + 4y) = (3)(-2)

(2)(2x - 6y) = (2)(8)

6x + 12y = -6   ---(4)

4x - 12y = 16   ---(5)

Add equations (4) and (5) to eliminate the y term:

(6x + 12y) + (4x - 12y) = -6 + 16

10x = 10

x = 10/10

x = 1

Substitute the value of x back into equation (2):

2(1) + 4y = -2

2 + 4y = -2

4y = -2 - 2

4y = -4

y = -4/4

y = -1

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To find the values of m for each case, we need to analyze the given vectors. For case (a), m can be either 1 or 2. For case (b), m = 1. For case (c), m = 5/4. For case (d), m can be ±1.

In case (a), we determine that A is perpendicular to B by taking their dot product and equating it to zero. This leads to a quadratic equation in terms of m, which we can solve to find two possible values of m. In case (b), we determine that B is parallel to C by cross-checking the ratios of their corresponding components. By equating these ratios, we obtain a linear equation in terms of m, which we can solve to find the value of m. In case (c), we determine if A, B, and C lie in the same plane by checking if their cross product is zero. This leads to a linear equation in terms of m, and solving it provides the value of m. In case (d), we find that D is perpendicular to both N and B by taking their dot products. By solving the resulting equations, we can determine the value of m.

(a) For A to be perpendicular to B, their dot product should be zero: A · B = (2a1 - ma2 - a3) · (ma1 + a2 ? 2a3) = 0

Expanding the dot product and simplifying, we obtain the quadratic equation:

2m - 2m² + 4 = 0

Solving this quadratic equation yields two possible values for m: m = 1 and m = 2.

(b) To determine if B is parallel to C, we compare their corresponding components: ma1 + a2 ? 2a3 = k(a1 + ma2 + 2a3), where k is a constant. By equating the ratios of corresponding components, we get:

m = k

1 = mk

-2 = 2k

From the first two equations, we find m = 1, and substituting this into the third equation, we see that k = -1.

(c) To check if A, B, and C lie in the same plane, we need to determine if their cross product is zero:

(A × B) · C = 0

Expanding and simplifying the cross product, we obtain:

(2a2 + 4a3 + ma1) · (a1 + ma2 + 2a3) = 0

Simplifying further and rearranging terms, we get the linear equation:

4m - 5 = 0

Solving this equation yields m = 5/4.

(d) For D to be perpendicular to both N and B, their dot products should be zero:

D · N = (m²a3 + ma2 + a3) · (N1a1 + N2a2 + N3a3) = 0

D · B = (m²a3 + ma2 + a3) · (ma1 + a2 - 2a3) = 0

Expanding the dot products and simplifying, we obtain two linear equations: m² + 1 - 3m = 0

m² - 1 = 0

Solving these equations, we find m = ±1.

In summary, for case (a), m can be either 1 or 2. For case (b), m = 1. For case (c), m = 5/4. For case (d), m can be ±1.

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Answer:

what is the question at hand?

Step-by-step explanation:

I'll gladly solve if you can provide a question?

The volume of the composite figure of the cylinder and the cone is 485.65 cm³

Given a composite figure.

It consists of a cylinder and a cone.

Volume of cylinder = π r² h, where r is the radius and h is the height of the cylinder.

Here r = 4 cm and h = 7 cm

Volume of cylinder = π (4)² (7)

                                = 112π cm³

Volume of the cone = 1/3 π r² h, where r is the radius and h is the height of the cone.

Here r = 4 cm and h = 8 cm

Volume of cylinder = 1/3 π (4)² (8)

                                = 42.67π cm³

Total volume = 112π cm³ + 42.67π cm³

                      = 154.67π cm³

                      = 485.65 cm³

Hence the volume is 485.65 cm³.

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Answer:

D

Step-by-step explanation:

Answer:

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Find the perimeter of  the triangular base and multiply it by the height.

Find the area of triangular bases:

Add up the two bases to the lateral area to get the total surface area:

Total surface area is 1200 in².