Total Assets
Sales
Task 3: Preparing a Cash Flow Statement
Nikea Inc.'s income statement for the year 2013 is shown below:
During the year, the balances for the sales account, cost of goods sold, and gross profit
increased. This information is provided to you. Prepare the cash flow for operating activities,
using both the direct method and the indirect method.
Accounts
Nikea's income statement for the year 2013 is shown below.
Cost of Goods Sold
Gross Profit
Operating Expenses
Deprecation
Styles
Net Income
934,000 Total Liability & Stockholders Equity
Type your response here:
Amount ($)
600,000
14
(400,000)
200,000
(30,000)
(20,000)
150,000
934,000
4
Editin

Answer:

The equation for those inputs and outputs is:
0.25 *input - 151.75 = Output  

Step-by-step explanation:

For this, first search for the Slope of the funtion
THe slope can be found by calculating this :
(y2-y1)/(x2-x1)  or in this case (output2 - output1)/ (input2 - input1)

IT continues as follows:
( -48.5 - 24)  / (-413 - (-703) ) =
= (-72.5) / (290)
= -0.25

The slope is -0.25. If the function is a line then the equation is

-0.25*input + B = output

with any of the choices we can determine B.
  -0.25 * (-703) + B    = 24

   175.75 + B              = 24
175.75 +B - 175.75    = 24 - 175.75

               B                 = - 151.75

The equation for those inputs and outputs is:
0.25 *input - 151.75 = Output  

The perimeter of rectangle M'N'O'P' is given as follows:

54 cm.

A dilation can be defined as a transformation that multiplies the distance between every point in an object and a fixed point, called the center of dilation, by a constant factor called the scale factor.

The ratio between the areas is given as follows:

126/14 = 9.

The area is measure in square units, while the perimeter is measured in units, hence the ratio of the perimeters is the square root of the ratio of the areas, that is:

3.

Hence the perimeter of rectangle M'N'O'P' is given as follows:

3 x 18 = 54 cm.

The complete problem is:

Rectangle MNOP has a perimeter of 18 cm and an area of 14 cm2. After rectangle MNOP is dilated, rectangle M'N'O'P' has an area of 126 cm2. What is the perimeter of rectangle M'N'O'P'?

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The solution is: the amount accumulated after investing a principle P for t years at an interest rate compounded k times per year is $86496.26.

Here, we know,

The whole sum borrowed (or invested), exclusive of interest and dividends.

We have,

The interest that is calculated using both the principal and the interest that has accrued during the previous period is called compound interest. It differs from simple interest in that the principal is not taken into account when determining the interest for the subsequent period with simple interest. Compound interest is commonly abbreviated C.I. in mathematics.

The formula for the amount A accumulated after investing a principle P for t years at an annual interest rate r compounded k times per year is:

A = P * (1+r / k)^kt

given that,

P = $40,500 r = 3.8% t = 20 k = 12

Substituting the given values into this formula, we have:

A = $40,500 * (1 + 0.038 / 12)^12*20

A = $40,500 * 2.1357

A = $86496.2599

A = $86496.26 (rounded to the nearest cent)

Therefore,  the amount accumulated after investing a principle P for t years at an interest rate compounded k times per year is $86496.26.

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Alternate exterior angles are ∠9 and (∠1 + ∠2)

Consecutive interior angles are ∠7 and ∠4

Consecutive exterior angles are ∠9 and ∠∠3

Vertical angles are ∠2 and ∠5

Linear pairs are ∠7 and ∠8

We have,

Alternate exterior angles: Pairs of angles on opposite sides of a transversal line, formed by two parallel lines, and located outside the intersected lines.

Consecutive interior angles: Pairs of angles on the same side of a transversal line, formed by two parallel lines, and located between the intersected lines.

Consecutive exterior angles: Pairs of angles on the same side of a transversal line, formed by two parallel lines, and located outside the intersected lines.

Vertical angles: Pairs of non-adjacent angles formed by the intersection of two lines, sharing the same vertex and having equal measures.

Linear pair: A pair of adjacent angles formed by the intersection of two lines, sharing a common side, and whose measures add up to 180 degrees.

So,

Alternate exterior angles

= ∠9 and (∠1 + ∠2)

Consecutive interior angles

= ∠7 and ∠4

Consecutive exterior angles

= ∠9 and ∠∠3

Vertical angles

= ∠2 and ∠5

Linear pair

= ∠7 and ∠∠8

Thus,

Alternate exterior angles are ∠9 and (∠1 + ∠2)

Consecutive interior angles are ∠7 and ∠4

Consecutive exterior angles are ∠9 and ∠∠3

Vertical angles are ∠2 and ∠5

Linear pairs are ∠7 and ∠8

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The correct description of the shape of the distribution is D. Roughly Symmetric.

Symmetric distribution is an often-referenced term in statistics, representing a type of probability with data segments evenly dispersed around the mean. This denotes the perfect mirror image of the right and left halves when the distribution is split; arriving at an equal size and shape on either side when drawn at the midpoint of the line.

Looking at the distribution of a fire department's response time, we can see that the distribution is roughly symmetric because the values on the left seem to match those on the right.

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Answer:

Since the line is vertical and passes through the point (3, -5), it is a vertical line with undefined slope.

Step-by-step explanation:

The critical values t₀ for a two-sample t-test is ± 2.0.6

To find the critical values t₀ for a two-sample t-test to test the claim that the population means are equal (i.e., µ₁ = µ₂), we need to use the following formula:

t₀ = ± t_(α/2, df)

where t_(α/2, df) is the critical t-value with α/2 area in the right tail and df degrees of freedom.

The degrees of freedom are calculated as:

df = (s₁²/n₁ + s₂²/n₂)² / [(s₁²/n₁)²/(n₁-1) + (s₂²/n₂)²/(n₂-1)]

n₁ = 14, n₂ = 12, X₁ = 6,X₂ = 7, s₁ = 2.5 and s₂ = 2.8

α = 0.05 (two-tailed)

First, we need to calculate the degrees of freedom:

df = (s₁²/n₁ + s₂²/n₂)² / [(s₁²/n₁)²/(n₁-1) + (s₂²/n₂)²/(n₂-1)]

= (2.5²/14 + 2.8²/12)² / [(2.5²/14)²/13 + (2.8²/12)²/11]

= 24.27

Since this is a two-tailed test with α = 0.05, we need to find the t-value with an area of 0.025 in each tail and df = 24.27.

From a t-distribution table, we find:

t_(0.025, 24.27) = 2.0639 (rounded to four decimal places)

Finally, we can calculate the critical values t₀:

t₀ = ± t_(α/2, df) = ± 2.0639

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The correct expression which is not a rational expression,

⇒ (x+3)(2x-1) / (x+3)

We have to given that;

All the expressions are,

⇒ (x+3)(2x-1) / (x+3)

⇒ (3x²+3x) / (4x+5)

⇒ (3x+4√x-7) / (2x+2)

⇒ (2x²-3x³+5) / 5x

Since, A number which can be written in the form of fraction p / q , where q is non zero, are called Rational numbers.

Hence, We can simplify all the expressions as,

⇒ (x+3)(2x-1) / (x+3)

⇒ (2x - 1)

Hence, It is not a rational expression.

⇒ (3x²+3x) / (4x+5)

⇒ 3x (x + 1) / (4x + 5)

Hence, It is a rational expression.

⇒ (3x+4√x-7) / (2x+2)

⇒ (3x + 4√x - 7) / 2 (x + 1)

Hence, It is a rational expression.

⇒ (2x²-3x³+5) / 5x

Hence, It is a rational expression.

Thus, The correct expression which is not a rational expression,

⇒ (x+3)(2x-1) / (x+3)

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The value of side TS is,

⇒ TS = 28

First, we are going to divide the figure and named new points X and Y as:

Now, we know that TS is the sum of TX and XS.

TS = TX + XS

Additionally, TX has the same length of HJ, so:

TX = HJ = 14

Now, we want to know the length of YK, and we can calculate it using the following equation:

LK = LY + YK

LY = HJ,

so, LY = 14

And, 42 = 14 + YK

42 - 14 = YK

28 = YK

Finally, since T and S are midpoints, the length of XS is the half of the length of YK. It means that XS is:

XS = YK/2

XS = 28/2

XS = 14

Therefore, TS is equal to:

TS = TX + XS

TS = 14 + 14

TS = 28

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Example: (2x - 4) x=7 so (2x (x=7) - 4) =18

Answer:

X+2

Hope this helps

According to the information, there are thousands of different lunch options in this restaurant.

To calculate the number of different lunches in the restaurant we must carry out the following mathematical procedure. We must multiply the different options as shown below:

4 green options x 5 protein options x 8 vegetable options x 4 extra options x 6 topping options = 4 x 5 x 8 x 4 x 6 = 4,800 different lunch options.

Based on the above, we can infer that 4,800 different lunch options can be created with the available ingredients.

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The percentage of buyers who paid between 150,000 and 153,300 is approximately 68% + 2.5% = 70.5%.

To solve this problem, we can use the properties of the normal distribution and the empirical rule (also known as the 68-95-99.7 rule) to estimate the percentage of buyers who paid between 150,000 and 153,300.

According to the empirical rule, given a normal distribution:

approximately 68% of the data falls within one standard deviation of the mean approximately 95% of the  three standard deviations of the mean, the data are contained.

In this case, we want to find the percentage of buyers who paid between 150,000 and 153,300, which is one interval of length 3300 above the mean. To use the empirical rule, we need to standardize this interval by subtracting the mean and dividing by the standard deviation:

z1 = (150,000 - 150,000) / 1100 = 0

z2 = (153,300 - 150,000) / 1100 = 3

Here, z1 represents the number of standard deviations between 150,000 and the mean, and z2 represents the number of standard deviations between 153,300 and the mean.

Since the interval we are interested in is within three standard deviations of the mean (z2 <= 3), we can use the empirical rule to estimate the percentage of buyers who paid between 150,000 and 153,300:

Approximately 68% of the buyers paid within one standard deviation of the mean, which is between 149,000 and 151,000 (using z-scores of -1 and 1).

Approximately 95% of the buyers paid within two standard deviations of the mean, which is between 148,000 and 152,000 (using z-scores of -2 and 2).

Therefore, the remaining percentage of buyers who paid between 152,000 and 153,300 is approximately (100% - 95%) / 2 = 2.5%.

So, the percentage of buyers who paid between 150,000 and 153,300 is approximately 68% + 2.5% = 70.5%.

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The area of the sector is: 21) 177.0 cm² 22) 58.6 in.²

The missing sides are: 23) 12     24) 8

The area of the sector of any circle is given as:

Area = ∅/360 * πr², where r is the radius.

21. ∅ = 120°

r = 13 cm

Substitute:

Area = 120/360 * π * 13² = 177.0 cm²

22. ∅ = 105°

r = 8 in.

Substitute:

Area = 105/360 * π * 8² = 58.6 in.²

Since the lines appear tangents in the circles given, then the triangle formed is a right triangle, therefore, we will apply the Pythagorean Theorem in each case:

23. Missing side = √[(9 + 6)² - 9²]

Missing side = 12

24. Let the missing side be x. Therefore, we have:

12 + x = √(16² + 12²)

12 + x = 20

12 + x - 12 = 20 - 12

x = 8

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The absolute error is $1825, the relative error is 2

An absolute error is a determinant of how large an error is. A relative error defines how good or bad an error is.

The formula for determining an absolute error is;

The formula for determining a relative error is:

From the parameters given:

The absolute error can be computed as:

Absolute error = 2559 - (2559 - 1825)

Absolute error = 2559 - 734

Absolute error = $1825

The relative error = 1825 ÷ 734

The relative error = 2.4

The relative error ≅ 2 (as an integer)

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The first cellphone service provider to be established in South Africa was Vodacom. Vodacom was launched on April 1, 1994, and it became the country's first cellular network operator.

The company was a joint venture between Telkom, the national telecommunications company of South Africa, and Vodafone, a global telecommunications giant.

Vodacom introduced the GSM network to South Africa, providing mobile voice and data services to customers across the country. Its launch marked a significant milestone in the telecommunications industry in South Africa, as it brought mobile communication to the masses and revolutionized the way people connect and communicate.

Since its inception, Vodacom has played a pivotal role in the development of the telecommunications sector in South Africa. It has continually expanded its network coverage, introduced innovative services, and played an active role in bridging the digital divide in the country.

Today, Vodacom remains one of the leading mobile network operators in South Africa, providing a wide range of mobile services to millions of customers.

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The probable question may be:

Which cellphone service provider was the first to be established in south africa

The difference of medians is given as follows:

2.

A box and whisker plots shows these five metrics from a data-set, listed and explained as follows:

The median for each day is given as follows:

Hence the difference is given as follows:

8 - 6 = 2.

The box plot is given by the image presented at the end of the answer.

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Answer:

Step-by-step explanation:

Answer:181,250

Step-by-step explanation:

Basically, the cost would go up 5 percent, and you’re asking how much it would go up in 5 years. So 5x5=25, so you’d multiply 145,000 by 25%, which is 36,250. So, you’d add that to 145,000 which would get you 181,250.

Answer:

Step-by-step explanation:

To determine the value of t if the three points A(7, 4), B(-1, -2), and C(3t, 5-4t) are collinear, we can use the concept of slope. If the points are collinear, the slopes between any two pairs of points should be equal.

The slope between points A and B is given by:

m₁ = (y₂ - y₁) / (x₂ - x₁)

= (-2 - 4) / (-1 - 7)

= (-6) / (-8)

= 3/4

Now, let's calculate the slope between points B and C:

m₂ = (y₂ - y₁) / (x₂ - x₁)

= (5 - (-2)) / (3t - (-1))

= (7) / (3t + 1)

Since the points are collinear, the slopes m₁ and m₂ should be equal. Therefore, we can set up the equation:

3/4 = 7 / (3t + 1)

To solve for t, we can cross-multiply and solve the resulting equation:

4(7) = 3(3t + 1)

28 = 9t + 3

25 = 9t

t = 25 / 9

Therefore, the value of t that makes the points A(7, 4), B(-1, -2), and C(3t, 5-4t) collinear is t = 25/9.

Answer:

6/7

Step-by-step explanation:

If the three points are collinear, then the slope of the line passing through any two of the points should be the same as the slope of the line passing through the other two points.

Let's find the slope of the line passing through points A and B:

slope AB = (y2-y1)/(x2-x1)

= (-2-4)/(-1-7)

= -6/-8

= 3/4

Now let's find the slope of the line passing through points B and C:

slope BC = (y2-y1)/(x2-x1)

= (5-4t-(-2))/(3t-(-1))

= (7-4t)/(3t+1)

Since the three points are collinear, slope AB = slope BC:

3/4 = (7-4t)/(3t+1)

Cross-multiplying and simplifying:

12t + 4 = 28-16t

28t = 24

t = 24/28

t = 6/7

Therefore, the value of t is 6/7 if the three points A, B, and C are collinear.

The cruise ship will travel approximately 15 nautical miles in 345 minutes.

Use a proportion to solve this problem. Let "d" be the number of nautical miles the cruise ship will travel in 345 minutes. Then:

19 nautical miles / 437 minutes = d nautical miles / 345 minutes

To solve for "d", cross-multiply:

19 nautical miles x 345 minutes = d nautical miles x 437 minutes

Then, divide both sides by 437 minutes to isolate "d":

d nautical miles = (19 nautical miles x 345 minutes) / 437 minutes

Simplifying this expression, we get:

d nautical miles = 15 nautical miles (rounded to the nearest whole number)

Therefore, the cruise ship will travel approximately 15 nautical miles in 345 minutes.

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The expression that is a factor of both x² - 9 and x² + 8x + 15 is (x + 3).

Given the polynomials in the question:

x² - 9

x² + 8x + 15

To find a factor that is common to both x² - 9 and x² + 8x + 15, we can factorize the two expressions and look for any common factors.

First, factorize x² - 9:

Using the difference of sqaure formula

a² - b² = ( a + b )( a - b )

x² - 9

x² - 3² = (x - 3)(x + 3)

Next, factorize x² + 8x + 15:

Using AC method

( x + 3 )( x + 5 )

From the factorizations, we can see that both expressions have a common factor of (x + 3).

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The initial deposit needed for the account is given as follows:

$19,257.37.

The amount of money earned, in compound interest, after t years, is given by:

[tex]A(t) = P\left(1 + \frac{r}{n}\right)^{nt}[/tex]

In which:

The parameters for this problem are given as follows:

[tex]A = 22000, t = 3, r = 0.0447, n = 4[/tex]

Hence the initial deposit P is obtained as follows:

[tex]A(t) = P\left(1 + \frac{r}{n}\right)^{nt}[/tex]

[tex]22000 = P\left(1 + \frac{0.0447}{4}\right)^{4 \times 3}[/tex]

1.142657P = 22000

P = 22000/1.142657

P = $19,257.37.

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The expected value of the car 7 years after it was purchased is $47,029.12.

To solve this problem, we need to calculate the expected value of the car after 7 years. To do this, we need to use the formula for calculating the value of a depreciating asset:

Value after n years = Initial Value - (Initial Value × (Depreciation Rate/100)×n)

In this case, the initial value of the car is $54792, the depreciation rate is 19%, and n = 7. Thus, the expected value of the car 7 years after it was purchased is:

Value after 7 years = 54792 - (54792 × (19/100)×7)

Value after 7 years = 54792 - (54792 × 0.19×7)

Value after 7 years = 54792 - 7762.88

Value after 7 years = $47,029.12

Therefore, the expected value of the car 7 years after it was purchased is $47,029.12.

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Answer:

9 7/8

Step-by-step explanation:

1. 4 3/8 can be converted into the improper fraction 35/8, and 5 1/2 can be converted into 11/2.

2. Now that we have 35/8 + 11/2, we have to find a common denominator. Since 2 goes into 8 four times, we can turn 11/2 into 44/8 by multiplying the numerator and denominator (the top and the bottom numbers) by 4.

3. Now we have 35/8 + 44/8. At this point, the all we have to do is add the numerators (the top numbers). 35+44=79, so our answer is 79/8, which we can simplify to 9 7/8.

No, I disagree because a good line of fit has to minimize the sum of the squared distance between all the points in the data.

A line of fit is used to mathematically model the relationship between variables in a data. A line of fit is drawn such that the best line would minimize the sum of the squared distances between the plotted points.

This means that, the line of fit should not aim to go through the middle of the data points but minimize the sum of the squared distances between them.

Hence, Alfred's reasoning is Incorrect .

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The value of the home after 5 years would be $194,415.

How to calculate the value of the home after 5 years

First, let's calculate the increase in value for each 3-year period:

After the first 3 years:

Increase = 9% of $150,000 = 0.09 * $150,000 = $13,500

After the second 3 years:

Increase = 9% of ($150,000 + $13,500) = 0.09 * ($150,000 + $13,500) = $14,850

After the third 3 years:

Increase = 9% of ($150,000 + $13,500 + $14,850) = 0.09 * ($150,000 + $13,500 + $14,850) = $16,065

Now, let's add these increases to the initial value of the home to find the value after 5 years:

Value after 5 years = $150,000 + $13,500 + $14,850 + $16,065 = $194,415

Therefore, the value of the home after 5 years would be $194,415.

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The coordinates you would be standing on would be coordinate (-5.71, -3.57).

To discover the arrangement of point "K" that partitions the line section interfacing the beginning point to the coffee shop in a proportion of 5:2, we are able to utilize the concept of the area equation.

We should expect the starting point to be meant as A with orchestrates (- x1, - y1), and the café is implied as B with works with (- x2, - y2). The ratio of 5:2 suggests that segment AB is divided into two parts and five parts, each accounting for 7 percent of the length.

The x-direction of point K can be determined as:

xK = (5 * x2 + 2 * x1)/7

Basically, the y-direction of point K can be determined as:

yK = (5 * y2 + 2 * y1) / 7

Stopping within the arranges of the coffee shop (-8, -5) as (-x2, -y2) and accepting the beginning point as the beginning (0, 0), we have:

xK = (5 * (-8) + 2 * 0) / 7 = -40/7 ≈ -5.71

yK = (5 * (-5) + 2 * 0) / 7 = -25/7 ≈ -3.57

Hence, in case you stood on point K, you'd be around at coordinate (-5.71, -3.57).

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The algebraic equation of the cubic function set on Cartesian plane is f(x) = (x + 6) · (x - 1) · (x - 4). (Correct choice: 3)

In this problem we find the representation of a cubic function set on Cartesian plane, whose definition as algebraic equation is shown below:

f(x) = a · (x - r₁) · (x - r₂) · (x - r₃)

Where:

Graphically speaking, the roots of the polynomials are the points of the curve on x-axis. If we know that a = 1, r₁ = - 6, r₂ = 1 and r₃ = 4, then the algebraic equation of the cubic function is:

f(x) = (x + 6) · (x - 1) · (x - 4)

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Answer:

3)  f(x) = (x - 4)(x - 1)(x + 6)

Step-by-step explanation:

The x-intercepts of a function are the points at which the curve crosses the x-axis, so when f(x) = 0.

From inspection of the given graph, the curve crosses the x-axis at:

According to the Factor Theorem, if f(x) is a polynomial and f(a) = 0, then (x - a) is a factor of f(x).

Therefore, as f(x) = 0 when x = -6, x = 1 and x = 4, then (x + 6) and (x - 1) and (x - 4) are factors of the polynomial.

Therefore, the equation of the function is:

The vendor sold 142 sodas and 91 hotdogs.

According to the question:

The vendor sold 233 sodas and hotdogs combined

The number of hot dogs sold was 51 less number of sodas sold

To find:

Number of sodas sold(S)

Number of hotdogs sold(H)

From the question, it is clear that:

S + H = 233 ...(i)

S - H = 51 ...(ii)

These two are simultaneous linear equations.

Adding equations (i) and (ii):

S + H + S - H = 233 + 51

2S = 284

S = 284/2

S = 142

Substitute this value of S in equation (i):

142 + H = 233

H = 233 - 142

H = 91

Therefore, the vendor sold 142 sodas and 91 hotdogs.

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