Two years ago, Erin was 35 inches tall. To ride the roller coaster at a theme park, she must be at least 42 inches tall. If she was able to ride the roller coaster this year, how many inches did Erin grow?

Answers

Answer 1

Answer:

In two years erin grew 7 inches

Step-by-step explanation:

42 - 35 = 7

Answer 2

Answer:

atleast 7 inches

Step-by-step explanation:

35 inches - 42 inches = 7 inches

Two years ago, Erin was 35 inches tall.

To ride the roller coaster at a theme park, she must be at least 42 inches tall. So that means she grew atleast 7 inches


Related Questions

A triangular window is above the door to a café. The length of the base of the window is 12 feet, and the height is 10 feet.



What is the area of the window?

Enter your answer in the box.

ft2

Answers

Answer:

60 ft²

Step-by-step explanation:

A = 1/2 × b × h

A = 1/2 × 12ft × 10ft

A = 1/2 × 120 ft

A = 60ft²

PLS HELP!
Which trigonometric function has a range that does not include -0.8?
A.) y=sin x
B.) y=csc x
C.) y=cot x
D.) y=cos x

Answers

Answer:

  B.) y=csc x

Step-by-step explanation:

The cosecant function has a minimum magnitude of 1, so its range excludes any values in the range -1 < y < 1.

  y = csc(x) . . . has a range that does not include -0.8

Are the expressions shown below equivalent?
(3x+9)(x+2)
(3x + 6)(x+3)
Justify/Explain your answer in two different ways.

(Algebra 1) Please help!

Answers

Answer:

Yes, the expressions are equivalent.

Step-by-step explanation:

Expanding (3x + 9)(x + 2) gives us [tex]3x^2 + 15x + 18[/tex] which is the same as when you expand (3x + 6)(x + 3).

Answer:

(3x+9)(x+2)

step:3xx+3x2+9x+9x2

3x2+6x+9x+9x2

answer is 3x2+15x+18

step:3xx+3x3+6x+6x3

3x2+6x+6x3

answer is 3x2+15x+18

Step-by-step explanation:

#Carry on learning#

The first three terms of a sequence are given. Round to the nearest thousandth (if
necessary).
9, 15, 25, ...
Find the 10th term

Answers

Answer:

Step-by-step explanation:

This is a Geometric Sequence  with common ratio 15/9 = 5/3

25/15  is also =  5/3

So the 10th term = ar^(n-1)

= 9*(5/3)^9

= 893.061 to nearest thousandth.

Which of the following describes this?

Answers

Answer:

Step-by-step explanation:

irrational number

Answer:

Irrational number

Step-by-step explanation:

It is a never-ending and non-repeating number.

1.what is a sports car average acceleration if it can go from 0m/s to 27m/s in 6.0 seconds?


2.what is cars acceleration when it slow down from an initial velocity of 4.5m/s to a final velocity of 24.5m/s in 3.2 seconds?



3.a car increases its velocity from 50m/s to 80m/s in 2.0 maintaining its direction.what is acceleration?


4.a turtle moves from a initial velocity of 0.50m/s to 0.80m/s in 6seconds.what is the turtels average acceleration?

Answers

Answer:

1.4.5m/s^2

2.6.25m/s^2

3.15m/s^2

4.0.05m/s^2

Step-by-step explanation:

a=v-u

----

t

27-0

------ = 27/6

6

=4.5m/s^2

u=4.5m/s

v=24.5m/s

t=3.2s

(24.5-4.5)÷3.2

=20/3.2

=6.25m/s^2

v=80m/s

u=50m/s

t=2s

(80-50)÷2

15m/s^2

v=0.80m/s

u=0.50m/s

t=6s

(0.80-0.50)÷6

=0.05m/s^2

what is the answer to the equation 1 1/2 x 3/4 + 1/78 = 9/8 x 5/8

Answers

11/2*3/4+1/78=9/8*5/8

5.5*3/4+1/78=9/8*5/8

16.5/4+1/78=9/8*5/8

4.125+1/78=9/8*5/8

4.125+0.013=9/8*5/8

4.125+0.013=1.125*5/8

4.125+0.013=5.625/8

4.125+0.013=0.703

4.138=0.703

the answer is 4.138=0.703

hope this helps

how many quarters are in 20 dollars?

Answers

4 quarters = 1 dollar
4 x 20 = 80

There is 80 quarters in 20 dollars

Hey there!

4 quarters = 1 dollar

To find how many quarters are in 20 dollars, we multiply 4 by 20

⇒ 4 × 20

⇒ 80

Therefore, 80 quarters are in 20 dollars

please solve WILL MARK BRAINLIES
Solve the question 2 it is necessary but 1 upto you​

Answers

Answer:

See below ↓

Step-by-step explanation:

ii.

(x - iy)(3 + 5i) 3x - 3iy + 5ix - 5i²y3x + 5y + 5ix - 3iyConjugate of -6 - 24i ⇒ -6 + 24iReal part : 3x + 5y = -6Imaginative part : 5x - 3y = 24

Solving

9x + 15y = -18 [Multiplying the real part throughout by 3]25x - 15y = 120 [Multiplying the img part throughout by 5]34x = 102x = 327 + 15y = -1815y = -45y = -3

Answer:

Brainliest please

Step-by-step explanation:

3 more than 1/2 of a number is 10. What is the number (n)?​

Answers

Answer:15

Step-by-step explanation:

3+1/2=3/2

3/2*10=3*5=15

15

Write the point-slope form of the equation of the line through the points (1,-1) and (5,-2)

Answers

Answer:

y + 1 = -1/4 (x - 1) Answer choice C is correct.

Step-by-step explanation:

Point Slope Formula: y - y1 = m (x-x1)

Your points:

(1,-1) and (5,-2)

You need to find the slope first:

Use the formula: y2 - y1 / x2 - x1

Your y2 is -2

y1 is -1

x2 is 5

x1 is 1

-2 - (-1)/5-1

-2 + 1 /4

-1/4 is your slope and the "m" in the formula.

Now we know our y1 is -1 and x1 is 1 you just need to plug them in

y + 1 = -1/4 (x - 1)

Notice that I didn't write y - (-1) this is because the negatives cancel into positives.

Answer choice C is correct.

Answer:

c. [tex]y+1=-\frac{1}{4} (x-1)[/tex]

Step-by-step explanation:

Hi there!

We are given the points (1, -1) and (5, -2)

We want to find the equation of that line using those points, in point-slope form

Point-slope form is written as [tex]y-y_1=m(x-x_1)[/tex], where m is the slope and [tex](x_1, y_1)[/tex] is a point

First, let's find the slope of the line

The formula for the slope (m) calculated from 2 points is [tex]\frac{y_2-y_1}{x_2-x_1}[/tex], where [tex](x_1, y_1)[/tex] and [tex](x_2, y_2)[/tex] are points

We already have everything we need to find the slope, but let's label the values of the points to avoid any confusion when calculating.

[tex]x_1=1\\y_1=-1\\x_2=5\\y_2=-2[/tex]

Now substitute:

m=[tex]\frac{y_2-y_1}{x_2-x_1}[/tex]

m=[tex]\frac{-2--1}{5-1}[/tex]

Subtract

m=[tex]\frac{-2+1}{5-1}[/tex]

m=[tex]\frac{-1}{4}[/tex]

The slope of the line is -1/4

Now substitute this into the formula to find point-slope form (remember that this is [tex]y-y_1=m(x-x_1)[/tex], and that m is the slope value)

Therefore:

[tex]y-y_1=-\frac{1}{4} (x-x_1)[/tex]

Now, let's substitute the values of [tex]x_1[/tex] and [tex]y_1[/tex], which we found earlier (which are 1 and -1 respectively) into the equation

[tex]y--1=-\frac{1}{4} (x-1)[/tex]

Simplify

[tex]y+1=-\frac{1}{4} (x-1)[/tex]

This equation matches option c, which is the answer.
Hope this helps!

Sorry forgot to post pictures of the question on last post (here there are)
For question 4 and 5 You have to find what the equation would look like on a graph. brainly wouldn't let me post all the answer options for those questions sorry!

Answers

Answer:

See below for answers and explanations

Step-by-step explanation:

Problem 1

[tex]x=-3+2cos\theta,\:y=5+2sin\theta\\\\x+3=2cos\theta,\: y-5=2sin\theta\\\\(x+3)^2=4cos^2\theta,\: (y-5)^2=4sin^2\theta\\\\(x+3)^2+(y-5)^2=4cos^2\theta+4sin^2\theta\\\\(x+3)^2+(y-5)^2=4(cos^2\theta+sin^2\theta)\\\\(x+3)^2+(y-5)^2=4(1)\\\\(x+3)^2+(y-5)^2=4[/tex]

Thus, the first option is correct. Trying all the other options will not get you the desired rectangular equation.

Problem 2

[tex]x=3-6cos\theta,\: y=-2+3sin\theta\\\\x-3=-6cos\theta,\: y+2=3sin\theta\\\\\frac{x-3}{-6}=cos\theta,\: \frac{y+2}{3}=sin\theta\\ \\ \frac{(x-3)^2}{36}=cos^2\theta,\: \frac{(y+2)^2}{9}=sin^2\theta\\ \\ \frac{(x-3)^2}{36}+\frac{(y+2)^2}{9}=cos^2\theta+sin^2\theta\\\\ \frac{(x-3)^2}{36}+\frac{(y+2)^2}{9}=1[/tex]

Therefore, the first option is correct. This equation is in the form of an ellipse with a horizontal major axis length of 12 (half is 6) and a vertical minor axis length of 6 (half is 3), with its center at (3,-2).

Problem 3

Not sure which equation needs to be used for this problem

Problem 4

[tex]x=-7cos\theta ,\:y=5sin\theta\\\\-\frac{x}{7}=cos\theta,\: \frac{y}{5}=sin\theta\\ \\ \frac{x^2}{49}=cos^2\theta,\: \frac{y^2}{25}=sin^2\theta\\ \\\frac{x^2}{49}+\frac{y^2}{25}=cos^2\theta+sin^2\theta\\ \\ \frac{x^2}{49}+\frac{y^2}{25}=1[/tex]

This equation is in the form of an ellipse with a horizontal major axis length of 14 (half is 7) and a vertical minor axis length of 10 (half is 5). See attached graph.

Problem 5

Eliminate the parameter:

[tex]x=-t^2-2,\:y=-t^3+4t\\\\x+2=-t^2\\\\-x-2=t^2\\\\\pm\sqrt{-x-2}=t\\\\y=-t^3+4t\\\\y=-(\pm\sqrt{-x-2})^3+4(\pm\sqrt{-x-2})[/tex]

Attached below is the graph of the curve, which corresponds with the first option.

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