Una persona en la tierra tiene una masa de 70[kg]. Calcule: a) Su fuerza peso en la tierra. b) Su fuerza peso en la luna (considere que la aceleración gravitatoria en la luna es de 1.62 [m/s²]) *

Answers

Answer 1

Answer:

a. El peso = 686 Newton

b. El peso = 113.4 Newton

Explanation:

Dados los siguientes datos;

Masa = 70 kg

Aceleración debida a la gravedad en la luna = 1,62 m/s² una.

a. Para encontrar la fuerza-peso en la Tierra;

Sabemos que la aceleración debida a la gravedad es igual a 9,8 m/s² en el planeta Tierra.

El peso se puede definir como la fuerza que actúa sobre un cuerpo o un objeto como resultado de la gravedad.

Matemáticamente, el peso de un objeto viene dado por la fórmula;

[tex] Peso = mg [/tex]

Dónde;

m es la masa del objeto.

g es la aceleración debida a la gravedad.

Substituting into the formula, we have;

El peso = 70 * 9.8

El peso = 686 Newton

b. To find weight on moon;

Weight = mass * acceleration due to gravity on moon

Weight = 70 * 1.62

Weight = 113.4 Newton


Related Questions

kinetic energy of an object is quadrupled, momentum will change by what factor?

Answers

Answer:

So as KE becomes 4times , Momentum will increase by 2 times.

A ball is hit at an angle of 300. At what point in its trajectory does this

projectile have the least speed?

A. Just after it was launched.

B. At the highest point in its flight.

C. Just before it hits the ground.

D. Midway between the ground and the highest point.


A ball is thrown horizontally with a speed of 4.0 m/s from a height of 60.0

meters. What is the range of the projectile?

A. 4.00 m
B. 14.0 m
C. 24.0 m
D. 34.0 m


Which has constant velocity?
A.Range
B.Trajectory
C.Projectile
D.Vertical or Horizontal Velocity​

Answers

The first one is D. Second one is A.

Answer:

C. At the highest point of flight.

Explanation:

Given data;

[tex]u_{x} = 4 m/s ,u_{y} = 0, h = 60 m[/tex]

Time of flight,

by third equation of motion ,

[tex]h=\frac{1}{2} gt^{2}[/tex]

[tex]t=\sqrt{\frac{2*60}{9.8} }[/tex]

[tex]t = 3.5 Sec[/tex]

so the range ,

by horizontal component of velocity,([tex]u_{x}[/tex])

R = 4X3.5

R = 14 m

Horizontal component of velocity remain constant in the entire motion.

Two skaters, both of mass 75 kg, are on skates on a frictionless ice pond. One skater throws a 0.4-kg ball at 6 m/s to his friend, who catches it and throws it back at 6.0 m/s. When the first skater has caught the returned ball, what is the velocity of each of the two skaters

Answers

Answer:

v = 0.064 m/s

Explanation:

Given that,

The mass of two skaters = 75 kg

The mass of a ball = 0.4 kg

The speed of the ball = 6 m/s

The speed of skater = 6 m/s

We need to find the velocity of each of the two skaters.

Under the values given the moment with respect to the ball and which is subsequently transmitted to people it would be given by:

[tex]P=0.4(6)+0.4(6)\\\\=4.8\ kg-m/s[/tex]

We know that,

P = mv

Where

v is the velocity of each skater.

[tex]v=\dfrac{p}{m}\\\\v=\dfrac{4.8}{75}\\\\=0.064\ m/s[/tex]

So, the velocity of each of the skaters is 0.064 m/s.

44. Water from a fire hose knocks over a wooden shed. Compared with the pressure within the water, the pressure exerted against the shed is

a) less.
b) the same.
c) more.
d) nonexistent.

Answers

b i think sorry if it’s wrong

If ATM is 102 kPa, what force does the atmosphere exert on the palm of your hand which has an area of 0.016 meters?

Answers

Answer:

Force = 1.632 Newton

Explanation:

Given the following data;

Pressure = 102 kPa

Area = 0.016 m²

To find what force the atmosphere exert on the palm of your hand;

Mathematically, pressure is given by the formula;

[tex] Pressure = \frac {Force}{area} [/tex]

Force = 102 * 0.016

Force = 1.632 Newton

plsss help me
thank you very much

Answers

It’s not loading. My bad

CR Physical Science B (GP) 20-21 / 1 Motion
1. A distance-time graph indicates that an object travels 2 m in 2 s and then travels another 80 m during the next 40 s.
What is the average speed of the object?
O 4 m/s
O
2 m/s
O 8 m/s
10 m/s

Answers

Answer:

Average speed = total distance traveled / total time traveled

V = (2 + 80) / (2 + 40) = 82 / 42 = 2 m / s

an object falls freely from rest the total distance covered by it in 2s will be​

Answers

Answer:

Distance, S = 19.6 meters

Explanation:

Given the following data;

Time = 2 seconds

We know that acceleration due to gravity is equal to 9.8 m/s².

Also, the initial velocity of the object is equal to zero because it's starting from rest.

To find the total distance covered by the object, we would use the second equation of motion;

[tex] S = ut + \frac {1}{2}at^{2}[/tex]

Where;

S represents the displacement or height measured in meters. u represents the initial velocity measured in meters per seconds. t represents the time measured in seconds. a represents acceleration measured in meters per seconds square.

Substituting into the equation, we have;

[tex] S = 0*2 + \frac {1}{2}*(9.8)*2^{2}[/tex]

[tex] S = 0 + 4.9*4[/tex]

[tex] S = 4.9*4 [/tex]

Distance, S = 19.6 meters

Therefore, the total distance covered by the object is 19.6 meters.

The first and second coils have the same length, and the third and fourth coils have the same length. They differ only in the cross-sectional area. According to theory, what should be the ratio of the resistance of the second coil to the first coil and the fourth coil to the third

Answers

Answer:

The ratio of the resistances of second coil to the first coil is the ratio of square of radius of the first coil to the square of radius of  second coil.

And

The ratio of the resistances of fourth coil to the third coil is the ratio of square of radius of the third coil to the square of radius of  fourth coil.

Explanation:

The resistance of the coil is directly proportional to the length of the coil and inversely proportional to the area of coil and hence inversely proportional to the square of radius of the coil.

So, the ratio of the resistances of second coil to the first coil is the ratio of square of radius of the first coil to the square of radius of  second coil.

And

The ratio of the resistances of fourth coil to the third coil is the ratio of square of radius of the third coil to the square of radius of  fourth coil.

hoW DO YOU SPELL THIS?

Answers

Answer:

Spell what?

Can u please mention that too?

Answer:

what

Explanation: how do you spell what please include this in your next post

Một ô tô khối lượng một tấn chuyển động trên một đường nằm ngang. Hệ số ma sát giữa bánh ô tô và mặt đường là 0,07. Gia tốc trọng trường g=9,8m/s2
a) vẽ và xác định tên các lực tác động lên vật. Viết phương trình chuyển động của vật.
b) nếu ô tô chuyển động đều, xuống dốc có độ dốc 5%. Tính lực kéo của ô tô.
c) nếu ô tô chuyển động đều. Lên dốc có độ dốc 5%. Tính lực kéo của động cơ ô tô

Answers

Answer: B

Explanation: because B

B

That's my ans thanks me laterr

12) A negatively-charged balloon touching a wooden wall
A) pulls positive charge on the wall surface toward it.
B) pushes negative charge in the wall away from it.
C) polarizes molecules in the wall.
D) all of the above.

Answers

Answer:

D) all of the above.

Explanation:

First polarises it, cahrging and discharging occurs at once.

A negatively charged balloon touching a wooden wall then from the given options option D is correct which is all of the above.

What is a charge?

Charged matter experiences a force when it is exposed to an electromagnetic field due to the physical property of electric charge. Positive or negative charges can exist in an electric field (commonly carried by protons and electrons, respectively).

Contrary charges attract one another, while like charges repel one another. A neutral object is one that carries no net charge. Classical electrodynamics, the name given to an early understanding of how charged particles interact, is still accurate for issues that do not call for taking into account quantum phenomena.

In the first step it polarizes molecules in the wall, then charging and discharging in the wall will take place at once.

To get more information about Charge :

https://brainly.com/question/19886264

#SPJ2

Alex pushes on a 2.0 kg book, resulting in a net force of 6.0 N on the book.
What is the acceleration of the book?
A. 12 m/s2
B. 1.5 m/s2
C. 3.0 m/s2
D. 24 m/s2
HELPPPP

Answers

Answer:

3.0 m/s²

Explanation:

The acceleration of an object given it's mass and the force acting on it can be found by using the formula

[tex]a = \frac{f}{m} \\ [/tex]

From the question we have

[tex]a = \frac{6}{2} \\ [/tex]

We have the final answer as

3.0 m/s²

Hope this helps you

Guys please help me ​

Answers

Answer:

1)[tex]t=2.26\: s[/tex]

2)[tex]S=33.9\: m[/tex]

3)[tex]v=26.77\: m/s[/tex]

4)[tex]\alpha=55.92[/tex]

Explanation:

1)

We can use the following equation:

[tex]y_{f}=y_{0}+v_{iy}t-0.5*g*t^{2}[/tex]

Here, the initial velocity in the y-direction is zero, the final y position is zero and the initial y position is 25 m.

[tex]0=25-0.5*9.81*t^{2}[/tex]

[tex]t=2.26\: s[/tex]

2)

The equation of the motion in the x-direction is:

[tex]v_{ix}=\frac{S}{t}[/tex]

[tex]15=\frac{S}{2.26}[/tex]

[tex]S=33.9\: m[/tex]

3)

The velocity in the y-direction of the stone will be:

[tex]v_{fy}=v_{iy}-gt[/tex]

[tex]v_{fy}=0-(9.81*2.26)[/tex]

[tex]v_{fy}=-22.17\: m/s[/tex]

Now, the velocity in the x-direction is 15 m/s then the velocity will be:

[tex]v=\sqrt{v_{x}^{2}+v_{fy}^{2}}=\sqrt{15^{2}+(-22.17)^{2}}[/tex]

[tex]v=26.77\: m/s[/tex]

4)

The angle of this velocity is:

[tex]tan(\alpha)=\frac{22.17}{15}[/tex]

[tex]\alpha=tan^{-1}(\frac{22.17}{15})[/tex]

[tex]\alpha=55.92[/tex]

Then α=55.92° negative from the x-direction.

I hope it helps you!

A car on the roller coaster begins with 0j of kinetic energy and 12,928j of potential energy and finishes the track with 3,715j of potential energy. How much kinetic energy dose the car finish with????

Answers

Answer:

9213 J

Explanation:

Change in Kinetic energy = Change in Potential energy

= 12,928J - 3715J

=9213 J

For more assistance: +1 (304) 223-3136

While a mason was working concrete into formwork, the formwork collapses. Who is BEST suites to rectify this problem? Mason Carpenter Project Manager O Construction Technician A device made in a workplace had defects. To address this issue the workshop manager should communicate directly with the workshop​

Answers

Answer:

1. Carpenter

2. True

Explanation:

While a mason was working concrete into the formwork, the formwork collapses. The best person to rectify this problem is CARPENTER.

This is because it is the job of the Carpenter to design and build formwork, most especially wooden formwork. Formwork is like casing built to receive concrete and reinforcement during construction. Hence, when formwork collapses either due to stress, tension, or improper construction, it is the job of Carpenter to reconstruct the formwork or rectify the problem.

It is TRUE that when a device made in a workplace had defects. To address this issue the workshop manager should communicate directly with the workshop​. However, this communication will be an instruction on what to do next, and it usually directs those responsible to take action where necessary. For example, a workshop manager communicates to a carpenter about the need to rectify a chair or table that has a defect.

Which of the following situations would violate the second law of
thermodynamics?
O A. A heat engine feeling cold after running for an hour
B. A heat engine using heat to do work
O C. A heat engine losing some energy as heat
D. A heat pump being 80% efficient

Answers

Answer: it’s A.

Explanation: A pex

What is the current in the 30 resistor?
A. 0.0833 A
B. 12 A
C. 2 A
D. 10 A

Answers

Answer:

Explanation:

Step 1) Combine all resistors into an equivalent overall resistor. These are all in series so you just add them up. Req = 10Ω + 20Ω + 30Ω = 60Ω:

Step 2) Using Ohm's Law, I = V/R = 120/60 = 2 A

Now you know how much current is flowing, and that current flows through each resistor the same. So the current in the 30 Ω resistor is 2.00 amps.

ADvantage of friction

Answers

Answer:

1. Friction enables us to walk freely.

2. It helps to support ladder against wall.

3. It becomes possible to transfer one form of energy to another.

4. Objects can be piled up without slipping.

Alcohol consumption slows people's reaction times. In a controlled government test, it takes a certain driver 0.320 s to hit the brakes in a crisis when unimpaired and 1.00 s when drunk. The car is initially traveling at 110.0 km/h. 1) How much farther does the car travel before coming to a stop when the person is drunk compared to sober

Answers

Answer:

[tex]\triangle d=21.726m[/tex]

Explanation:

From the question we are told that:

Unimpaired time to hit break [tex]t_i=0.320s[/tex]

Drunk time [tex]t=1s[/tex]

Initial Velocity [tex]v=110km/h[/tex]

Generally the equation for Average velocity is mathematically given by

[tex]V_{avg}=\frac{\triangle d}{\triangle t}[/tex]

Therefore

[tex]\triangle d=v.dt[/tex]

[tex]\triangle d=31.95*(1-0.32)[/tex]

[tex]\triangle d=21.726m[/tex]

A jet is circling an airport control tower at a distance of 15.8 km. An observer in the tower watches the jet cross in front of the moon. As seen from the tower, the moon subtends an angle of 9.21x10-3 radians. Find the distance traveled (in meters) by the jet as the observer watches the nose of the jet cross from one side of the moon to the other.

Answers

Answer:

The Distance traveled (in meters) by the jet as the observer watches the nose of the jet cross from one side of the moon to the other.

=145.5m

Explanation:

The radius of the circling jet r = 15.8km = 15.8*10^3 m

the angle subtended by moon

θ = 9.21*10^-3 rad

Therefore, the distance traveled by jet is

s = rθ

= (15.8*10^3 m)(9.21*10^-3 )

= (15,800)(0.00921)

=145.5m

A temperature of 200 degrees Fahrenheit is equivalent to approximately A.93.3 degrees Celsius B. 232 degrees Celsius C. 37.8 degrees Celsius D. 840 degrees Celsius

Answers

Answer:

you can use G.oogle for this question.

Answer:

93.3 degrees Celsius.

Explanation:

planet smaller than earth but larger than mercury​

Answers

Answer:

venus......................

The force in a string which is holding up an apple which type of force is it?​

Answers

Gravitational force

An object is 70 micrometer long and 47.66 micrometer wide. How long and wide is the object in km

Answers

Answer:

The length of the object in kilometer (km) is 70 x 10⁻ km

The width of the object in kilometers (km) is 47.66 x 10⁻ km

Explanation:

Given;

length of the object = 70 micrometer = 70 μm

the width of the object = 47.66 micrometer =   47.66  μm

The length of the object in meter:

70 micrometer = 70 μm = 70 x 10⁻⁶ m

The length of the object in kilometer (km):

70 x 10⁻⁶ m = 70 x 10⁻⁹ km

The width of the object in meters:

47.66 micrometer = 47.66 μm = 47.66 x 10⁻⁶ m

The width of the object in kilometers (km):

47.66 x 10⁻⁶ m = 47.66 x 10⁻⁹ km

8 points)Antireflection coating can be used on the eyeglasses to reduce the reflection of light: a) A 100nm thick coating is applied to the lens. What must be the coating’s index of refraction to be most effective at 500nm? (Assume the coating index of refraction is less than that of the lens). b) If the index of refraction of the coating is 1.20, find the necessary thickness of the coating at 500nm.

Answers

Answer:

- the coating’s index of refraction is 1.25

- the required thickness is 104.1667 nm

Explanation:

Given the data in the question;

Thickness of coating t = 100 nm

wavelength λ = 500nm

we know that refractive index is;

t = λ/4n

make n, the subject of formula

t4n = λ

n = λ / 4t

we substitute

n = 500 / ( 4 × 100 )

n = 500 / 400

n = 1.25

Therefore, the coating’s index of refraction is 1.25

2)

given that;

Index of refraction of the coating; n = 1.20

λ = 500 nm

thickness of coating t = ?

t = λ / 4n

we substitute

t = 500 / ( 4 × 1.2 )

t = 500 / 4.8

t = 104.1667 nm

Therefore, the required thickness is 104.1667 nm

PLEASE HELP How does an object move when it is in linear motion?

in a straight line

up and down

in a circle

to the left

Answers

Answer:

In linear motion, the directions of all the vectors describing the system are equal and constant which means the objects move along the same axis and do not change direction. Correct Answer: In a straight line

Explanation:

Answer:

In a straight line. we can also have translational motion which is also a kind of linear motion .

What do we mean by a penetrative pass in the game of football?​

Answers

Answer:

Penetration means forward passes can go through the opposition lines. Once these penetrative passes get through each line, it eliminates the line of players it broke through and leaves the player in possession closer to the opposition goal.

Explanation:

If the temperature stays constant, which change would decrease the amount
of thermal energy in an object?
A. Decreasing its density
B. Increasing its velocity
c. Decreasing its mass
D. Increasing its mass

Answers

Its C. Decreasing its mass

63 km/h is equal to...
O a) 27.5 m/s
b) 18 m/s
c) 1.75 m/s
d) 1.8 m/s
please hurry

Answers

Answer:

17.5 m/s

Explanation:

Refer to the attachment!~

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