Use Taylor's method of order two to approximate the solution for the following initial-value problem: y =1+(t − y)2, 2 ≤ t ≤ 3, y(2)

Answers

Answer 1

By using Taylor's method of order two, we can approximate the solution for the initial-value problem y = 1 + (t - y)[tex]^2[/tex], 2 ≤ t ≤ 3, y(2).

How can we approximate the solution using Taylor's method of order two for the given initial-value problem?

To approximate the solution for the given initial-value problem using Taylor's method of order two, we need to follow a step-by-step process. Let's break it down:

1. Identify the function and its derivatives

The initial-value problem is defined as: y = 1 + (t - y)[tex]^2[/tex], 2 ≤ t ≤ 3, y(2). Here, y represents the unknown function, and t is the independent variable. We need to find an approximation for y within the given time interval.

2.Express the function as a Taylor series

Using Taylor's method, we express the function y as a Taylor series expansion. In this case, we'll use the second-order expansion, which involves the function's first and second derivatives:

y(t + h) ≈ y(t) + hy'(t) + (h[tex]^2[/tex])/2 * y''(t)

3.Calculate the derivatives

Next, we need to calculate the first and second derivatives of y(t). Taking the derivatives of the given equation, we have:

y'(t) = -2(t - y)

y''(t) = -2

4. Substitute the derivatives into the Taylor series

Now, we substitute the derivatives we calculated into the Taylor series equation from Step 2:

y(t + h) ≈ y(t) + h * (-2(t - y)) + (h[tex]^2[/tex])/2 * (-2)

Simplifying further:

y(t + h) ≈ y(t) - 2h(t - y) - hc[tex]^2[/tex]

5. Set up the iteration process

To obtain an approximation, we iterate the formula from Step 4. Starting with the initial condition y(2) = ?, we substitute t = 2 and y = ? into the formula:

y(2 + h) ≈ y(2) - 2h(2 - y(2)) - h[tex]^2[/tex]

6. Choose a step size and perform iterations

Choose a suitable step size, h, and perform the iterations. In this case, let's choose h = 0.1 and perform iterations from t = 2 to t = 3. We'll calculate the approximate values of y at each step using the formula from Step 5.

7. Perform the calculations and update the values

Starting with the initial condition, substitute the values into the formula and calculate the new approximations iteratively:

For t = 2:

y(2.1) ≈ y(2) - 2h(2 - y(2)) - h[tex]^2[/tex]

For t = 2.1:

y(2.2) ≈ y(2.1) - 2h(2.1 - y(2.1)) - h[tex]^2[/tex]

Repeat this process until you reach t = 3, updating the value of y at each iteration.

By following these steps, you can approximate the solution for the given initial-value problem using Taylor's method of order two. Remember to adjust the step size and number of iterations based on the desired accuracy of the approximation.

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Related Questions

FIND THE DOMAIN AND RANGE!!!!

Answers

For the domain, you would find that all the numbers that go across in the x axis. In this case -3 is less than or equal to x which is less than or equal to 4. Same with the range, different numbers. -3 is less than or equal to y which is less than or equal to 2. Hope this helped!

what r passing marks out of 40​

Answers

Answer:

36/40 - A, 32/40 - B, 28/40 - C, and 24/40 - D

Step-by-step explanation:

Answer:

18 is ur answer

thank you

I need help it's geometry

Answers

Step-by-step explanation:

[tex] \sin(45) = \frac{x}{5} \\ \frac{1}{ \sqrt{2} } = \frac{x}{5} \\ x = \frac{5}{ \sqrt{2} } = 3.535[/tex]

[tex] \sin(45) = \frac{y}{5} \\ y = \frac{5}{ \sqrt{2} } = 3.535[/tex]

Answer:

[tex]\frac{5\sqrt{2} }{2 }[/tex]

Step-by-step explanation:

x=y

45-45-90 equation is x-x- x square root of 2

How many solutions does this system of equations have?

Answers

Answer:

One solution.

A system of linear equations has one solution when the graphs intersect at a point.

I hope it's helpful!

What is the domain of all of these points?
(8, 2), (12,9), (16, 16), (20, 23)

Answers

Answer:

8, 12, 16, 20

Step-by-step explanation:

those are the domains

Which of the following nets is for a pyramid?

Answers

2nd one

hope it helps you

The net of the pyramid is given by figure B

What is the surface area of the pyramid?

The total surface area is the summation of the areas of the base and the three other sides. A = B + ( 1/2 ) ( P x h ), where B is the area of the base of the pyramid, P is the perimeter of the base, and h is the slant height of the pyramid

Surface Area of Pyramid = B + ( 1/2 ) ( P x h )

Given data ,

A net is a two-dimensional representation of a three-dimensional shape that, when folded along the edges, forms the shape of the solid.

In the case of a pyramid, the net consists of a polygonal base and triangular faces that meet at a common vertex.

The number of triangular faces depends on the type of pyramid (triangular, square, pentagonal, etc.).

To learn more about surface area of pyramid click :

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pls help me it is inportant

Answers

Answer:

(5.x)+(5.2)

Step-by-step explanation:

Hope it helps you......

Answer:

nah

Step-by-step explanation:

what is the decimal word form of 120.95?​

Answers

One hundred twenty and ninety-five hundredths ?
One hundred and twenty point nine five

(−3⋅10^3 )⋅(4⋅10^6)=???

Answers

Answer:

-1.19164 x 10^8

Step-by-step explanation:

f(x) = -3x + 3
f(-2) = [?]
Help

Answers

is this the answer you're looking for? I'm sorry I'm confused

HELP I NEED HELP ASAP

Answers

Answer:

C

Step-by-step explanation:

Answer:

exponential;increase

Step-by-step explanation:

answer is C

What number is 40% of 15? Round to the nearest hundredth

Answers

Answer:

6

Step-by-step explanation:

10% of 15 = 1.5x4=6

solve the equation 3(x + 1) + 6 = 33.

Answers

Answer:

155

Step-by-step explanation:

If the mean of 5 numbers is 10 and the mean of other 15 numbers is 20 , what is the combined mean of both 20 numbers​

Answers

9514 1404 393

Answer:

  17.5

Step-by-step explanation:

The sum of the 5 numbers is 5·10 = 50.

The sum of the 15 numbers is 15·20 = 300.

The sum of all 20 numbers is then 50+300 = 350, so their mean is ...

  mean = sum/number = 350/20 = 17.5

The combined mean of the 20 numbers is 17.5.

4k squared = 100 solve for k

Answers

Answer:

k = 5

Step-by-step explanation:

4k^2 = 100

4k^2/4 = 100/4

k^2 = 25

k=5

An account earns simple interest.
$1500 at 4% for 5 years
a. Find the interest earned.
$
b. Find the balance of the account.

Answers

Answer:

a) $300 in interest

b) $1800 account total

Step-by-step explanation:

Interest = Principal x Rate x Time

I = 1500(.04)(5)

I = 300

A = P + I

1800 = 1500 + 300

Find the ratio of 580 ml to 1.12 I to 104 ml

Answers

Answer:

580 : 1120 : 104

Step-by-step explanation:

1.12 ml -> 1120 ml

hence,

580 : 1120 : 104

Plz help me! I need an answer right away

Answers

The answer is G ( 1/9 )

is the answer 84.2??? if not pls explain THANK U ITS GEOMETRY

Answers

The answer is 12.2129

Sin(40)=x/19
*19 *19
12.2129=x

SOMEONE PLEASE HELP


and please explain it so I won't get confused further on ​

Answers

Number 5 is 110 degrees because it is the same angle as m<2.

Now, to find m<7
A straight line is 180 degrees. One side is already given. m<8+m<7 = 180 degrees. So 180-110=70.

Answers:
4. m<7= 70 degrees

5. m<8= 110 degrees

Help Please................

Answers

Answer:

split then d the trinangle with the base and the height and do the rectangle as length times width

Step-by-step explanation:

Answer: 1152

Step-by-step explanation:

Please Help! Ill give brainliest no fakes PLEASE!!

Answers

Answer:

4 and then 15

Step-by-step explanation:

second one: 6:4

last one: 15:10

Select all that apply. Select the formulas that give the amount P in the account after the first period.

Answers

Options :

a.) P=1.005Po

b.) P=1.02Po

c.) P=Po(0.02/4)

d.) P=Po(4.02/4)

e.) P=Po(1+ 0.02/4)

Answer:

a.) P=1.005Po

d.) e.) P=Po(1+ 0.02/4)

Step-by-step explanation:

From the compound interest formula:

P = P0(1 + r/n)^t

Rate = 2% = 2/100 = 0.02

n = Number of compounding times per period, quarterly ; n = (12 /3) months

P = P0(1 + 0.02/4)^1

P = p0(1 + 0.02/4)

Simplifying further :

P = P0(1 + 0.005)

P = p0(1.005)

The tree frog population in your back yard doubles every two weeks. Currently, there are 10 frogs in your back yard. Assuning that there are 4
weeks in a month how many tree frogs will there be in 3 months?

Answers

Answer:

there would be 40,960 tree frogs i think

Step-by-step explanation:

Answer:

640 tree frogs

Step-by-step explanation:

If 1 month = 4 weeks

3 months = 12 weeks (3x4)

After 2 weeks the frogs double to 20

After 4 weeks the frogs double to 40

6 weeks, it doubles to 80

8 weeks, it's 160

10 weeks it's 320

12 weeks, it's 640


please helppppppp

give u 10 pts​

Answers

Answer:

y = x / -4

Step-by-step explanation:

Hope that helps!

Use desmos calculator graphing. Tap the plus. Tap table. Enter x1 on one side and y1 on the other. Enter the data for each side. Make a new equation and Use the following formula: y~ab^x1 = y=0.18(0.74)^x

12 (X + 2) - 4x = 4( 2X + 11 ) -20

Solve for X ​

Answers

Answer:

Step-by-step explanation:

12 (x + 2) - 4x = 4 (2x + 11) - 20

12 + 24 - 4x = 8x + 44 - 20

36 - 4x = 8x + 24

36 - 24 = 8x - 4x

12 = 4x

----   ----

 4     4

3 = x

-x = -3

x = 3

Can someone help w/ this math problem plzz

Answers

Answer:

its C

Step-by-step explanation:

6 tubs hold 125 gallons in all how much does each run hold

Answers

Answer:

125/6= 20.8 gallons

Help fast please. I will give brainliest.

Answers

Answer:

Q5 ) A 80 UNITS²

pls give me brainliest

Pls pls pls pls help

Answers

Step-by-step explanation:

To prove that two lines are perpendicular, when all we have are those two lines, we can use the Linear Pair Perpendicular Theorem - If two straight lines intersect at a point and form a linear pair of equal angles, they are perpendicular.

Our diagonals intersect at point O, so we'd need to show the two linear angles formed at that intersection point are equal, and we can do that with triangle congruency.

A rhombus is a parallelogram, so we will use what we already know about parallelograms - that the diagonals bisect each other.

It is then easy to show that the triangles  ΔAOD and  ΔAOB are congruent using the Side-Side-Side postulate, and from that that ∠AOD ≅ ∠AOB.

And now, since ∠AOD and ∠AOB are a linear pair, we use the Linear Pair Perpendicular Theorem - If two straight lines intersect at a point and form a linear pair of equal angles, they are perpendicular.

PROOF

(1) ABCD is a rhombus //Given

(2) AB=AD                     //definition of rhombus

(3) AO=AO                    //Common side, reflexive property of equality

(4) BO=OD // A rhombus is a parallelogram, a parallelogram's diagonals bisect each other

(5) △AOD≅△AOB   //Side-Side-Side postulate.    

(6) ∠AOD ≅ ∠AOB     //Corresponding angles in congruent triangles (CPCTC)

(7) AC⊥DB     //Linear Pair Perpendicular Theorem

The converse of this is also true: if a parallelogram's diagonals are perpendicular, it is a rhombus.

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