Use the diagram below to answer the questions.
-17h
119°
с
G
Find m_PCT

Answer: To solve the inequality x^2 + 3x - 4 > 0, we can use the method of factoring.

First, we can factor the quadratic expression:

x^2 + 3x - 4 = (x + 4)(x - 1)

Now we can find the values of x that make the expression greater than zero by looking at the sign of the expression for each factor and applying the sign rules of multiplication:

Using this method, we can create a sign chart:

x x + 4 x - 1 x^2 + 3x - 4

-4 0 -5 +6

-1 + - -

1 + + +

0 + - -

2 + + +

From the sign chart, we can see that the expression is greater than zero for x < -4 or x > 1. Therefore, the solutions to the inequality are all real numbers x such that x < -4 or x > 1. We can write this as:

x < -4 or x > 1

The expression that best reveals the maximum and minimum of the function[tex]f(x) = x^2 - 8x - 4 is (x - 4)^2 - 20.[/tex] Option A

The vertex form of a quadratic function is given by[tex]f(x) = a(x - h)^2 + k[/tex] where (h, k) represents the coordinates of the vertex.

In the given quadratic function [tex]f(x) = x^2 - 8x - 4[/tex], we can rewrite it in the vertex form by completing the square:

[tex]f(x) = (x - 4)^2 - 16 - 4\\f(x) = (x - 4)^2 - 20[/tex]

From this expression, we can see that the vertex of the quadratic function is at the point (4, -20).

The term[tex](x - 4)^2[/tex] tells us that the vertex is at x = 4, and the constant term -20 indicates the y-coordinate of the vertex.

The expression that best reveals the maximum and minimum of the function[tex]f(x) = x^2 - 8x - 4[/tex] is  [tex](x - 4)^2 - 20.[/tex]

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The volume of the pyramid is 18069333.33 units³ and the surface area is 391600 units ²

A pyramid is a three-dimensional figure. It has a flat polygon base. All the other faces are triangles and are called lateral faces.

Surface area of a pyramid is expressed as;

area of 4 lateral face + area of base

area of base = 440²

= 193600 units²

area of a lateral = 1/2 bh

= 1/2 × 440 × 356

= 78320

For four surfaces = 4 × 78320 = 313280

Total surface area = 313280+78320

= 391600 units ²

Volume of a pyramid is expressed as;

V = 1/3base area × height

V = 1/3 × 440² × 280

V = 18069333.33 units³

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Answer:

12 cm

Step-by-step explanation:

By hypotenuse theorem,

x² + 35² = 37²

x² + 35*35 = 37*37

x² + 1225 = 1369

x² = 1369 - 1225

x² = 144

x² = 12*12

x² = 12²

x = 12 cm

The center and radius for each equation are as follows:

40. Center: (3, 2), Radius: 8

41. Center: (-8, 4), Radius: 6

42. Center: (-4, 12), Radius: 2

43. Center: (4, -15), Radius: 3

The standard equations of a circle is given as (x - h)² + (y - k)² = r²

Where the center are (h, k) and the radius of the circle is r.

40. (x - 3)² + (y - 2)² = 64

  Center: (3, 2)

  Radius: √64 = 8

41. (x + 8)² + (y - 4)² = 36

  Center: (-8, 4)

  Radius: √36 = 6

42. (x + 4)² + (y - 12)² = 4

  Center: (-4, 12)

  Radius: √4 = 2

43. (x - 4)² + (y + 15)² = 9

  Center: (4, -15)

  Radius: √9 = 3

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The Free Cash Flow based on the information given will be $115,000

Statement of Cash Flows for Stand Corp for the year ended December 31, 2022

Cash flows from operating activities:

Net income $160,000

Adjustments to reconcile net income to net cash provided by operating activities:

Depreciation expense $17,000

Loss on sale of investments $10,000

Changes in current assets and liabilities:

Increase in accounts receivable ($5,000)

Increase in inventory ($20,000)

Increase in accounts payable $17,000

Increase in accrued expenses $11,000

Net cash provided by operating activities $190,000

Cash flows from investing activities:

Sale of investments $52,000

Purchase of equipment ($75,000)

Net cash used in investing activities ($23,000)

Cash flows from financing activities:

Payment of cash dividends ($25,000)

Net cash used in financing activities ($25,000)

Net increase in cash $142,000

Cash at beginning of year $78,000

Cash at end of year $220,000

Free Cash Flow = Net cash provided by operating activities - Purchase of equipment

Free Cash Flow = $190,000 - $75,000

Free Cash Flow = $115,000

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Using the cosine ratio, the value of the marked side in the image given below is approximately: y = 167.7.

The cosine ratio is defined as the ratio of the length of the hypotenuse of the right triangle over the length of the side that is adjacent to the reference angle. It is given as:

cos ∅ = length of hypotenuse/length of adjacent side.

From the image attached below, we have the following:

Reference angle (∅) = 37°

length of hypotenuse = 210

length of adjacent side = y

Plug in the values:

cos 37 = y/210

210 * cos 37 = y

y = 167.7

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Answer:

∆TSU ~ ∆PJM by SAS since 10/14 = 5/7 and 15/21 = 5/7, and angle S is congruent to angle J.

Answer:

  1460 square inches

Step-by-step explanation:

You want the area of a semicircle with diameter 61 inches.

The area of a circle is given by ...

  A = (π/4)d²

The area of a semicircle is half that, so is ...

  A = (π/8)d²

  A = (3.14/8)(61 in)² ≈ 1460 in²

The area of the semicircular window is about 1460 square inches.

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Donna can expect her total monthly housing expenses to be approximately $842.71 for the first month after purchasing the house, assuming no tax benefits or amortization on the loan.

To calculate Donna's monthly housing expenses, we first need to determine the total amount of the mortgage. Since she puts down $25,000 on a $125,000 house, she will need to take out a mortgage for $100,000.

Next, we can calculate the annual cost of owning the house beyond the 5% cost of mortgage interest, which is given as 4.09% of the value of the house. So, 4.09% of $125,000 is:

0.0409 x $125,000 = $5,112.50

This means that Donna can expect to pay approximately $5,112.50 per year in additional expenses associated with owning the house.

To calculate the monthly cost, we simply divide this by 12:

$5,112.50 / 12 = $426.04

So, Donna can expect to pay approximately $426.04 per month in additional expenses associated with owning the house.

Adding the cost of the mortgage interest, we can calculate her total monthly housing expenses as follows:

Total monthly housing expenses = Mortgage interest + Additional annual costs / 12

Mortgage interest = 5% of $100,000 = $5,000 per year or $416.67 per month

Total monthly housing expenses = $416.67 + ($5,112.50 / 12) = $416.67 + $426.04 = $842.71

Hence, Donna can expect her total monthly housing expenses to be approximately $842.71

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Entonces n is 0,00779 moles,

Los casi 5 sextillones (5 con 21 ceros) de moléculas de HNO3 provocaron la quemadura en la piel del analista.

Para responder a esta pregunta, necesitamos saber la masa molar de HNO3, que es 63,01 g/mol. Usando esta información, podemos calcular el número de moles de HNO3 en los 0,49 g de gotas usando la fórmula: n = m/M, donde n es el número de moles, m es la masa y M es la masa molar.

Como un mol contiene el número de moléculas de Avogadro (6,022 x 10^23), podemos calcular el número de moléculas de HNO3 en las gotas que causaron la quemadura: 0,00779 moles x 6,022 x 10^23 moléculas/mol = 4,69 x 10^21 moléculas .

Es importante recordar que los ácidos concentrados como el HNO3 pueden ser extremadamente peligrosos y pueden causar quemaduras graves, por lo que siempre se deben tomar las precauciones de seguridad adecuadas en un entorno de laboratorio.

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The graph of the logarithmic function is attached below with a vertical asymptote at x = -8 and two integer coordinates at (2, -7) and (1, -10).

The basic logarithmic function is of the form f(x) = logax (r) y = logax, where a > 0. It is the inverse of the exponential function ay = x. Log functions include natural logarithm (ln) or common logarithm (log).

To plot the graph of the given function, we simply need to use a graphing calculator.

The given function is;

f(x) = -3log₃(x + 8) - 4

To find the asymptotes of the graph;

x + 8 > 0

x > -8

The vertical asymptotes is at x = -8

The two points with integer coordinates are (2, -7) and (1, -10)

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a) The area formula for the rectangle is equal to A = r² · sin 2θ.

b) By derivative tests, the maximum possible area of the rectangle is 16 square centimeters.

c) The dimensions of the rectangle are: Width: 5.66 cm, Height: 2.83 cm

In this problem we must determine the maximum possible area of a rectangle inscribed in a semicircle by means of first and second derivative tests. First, derive the area formula of the rectangle:

A = w · h

A = (2 · r · cos θ) · (r · sin θ)

A = 2 · r² · sin θ · cos θ

A = r² · sin 2θ

Where:

Second, perform first derivative test: (r - Constant)

A = 2 · r² · cos 2θ

2 · r² · cos 2θ = 0

cos 2θ = 0

θ = 45°

Third, perform second derivative test: (θ = 45°)

A'' = - 4 · r² · sin 2θ

A'' = - 4 · r² (MAXIMUM)

Fourth, determine the maximum possible area of the rectangle:

A = 4² · sin 90°

A = 16 cm²

Fifth, determine the width and the height of the rectangle: (r = 4, θ = 45°)

w = 2 · r · cos θ

w = 2 · 4 · cos 45°

w = 8 · √2 / 2

w = 4√2 cm

w = 5.66 cm

h = r · sin θ

h = 4 · sin 45°

h = 4 · √2 / 2

h = 2√2 cm

h = 2.83 cm

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When x = 3, y = 2, and z = 4, the value of the expression 5x - 2y + 4z is 27.

The correct answer is (c) 27.

To evaluate the expression 5x - 2y + 4z when x = 3, y = 2, and z = 4, we substitute the given values into the expression and perform the   arithmetic calculations. Here's the step-by-step process:

Step 1: Replace x with 3, y with 2, and z with 4 in the expression:

5(3) - 2(2) + 4(4)Step 2:

Perform the multiplications first:

15 - 4 + 16

Step 3: Perform the additions and subtractions from left to right:

15 - 4 + 16 = 11 + 16 = 27.

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Answer: x=27

Step-by-step explanation:

Assumption the 3's are the bases

[tex]log_{3} 3x +log_{3} 3=5[/tex]              >combine using multiplication log rule (logs with      

                                             same base, that are being added can be  

                                              combined with multiplication)

[tex]log_{3}( 3x)(3) =5\\[/tex]                  >simplify

[tex]log_{3}( 9x) =5\\[/tex]                      >rewrite into exponent form

[tex]3^{5} = 9x[/tex]                             >simplify

243 = 9x

x=27

Answer:

x = 27

Step-by-step explanation:

using the rules of logarithms

• [tex]log_{b}[/tex] b = 1

• [tex]log_{b}[/tex] x = n ⇒ x = [tex]b^{n}[/tex]

then

[tex]log_{3}[/tex] (3x) + [tex]log_{3}[/tex] 3 = 5

[tex]log_{3}[/tex] (3x) + 1 = 5 ( subtract 1 from both sides )

[tex]log_{3}[/tex] (3x) = 4

3x = [tex]3^{4}[/tex] = 81 ( divide both sides by 3 )

x = 27

Answer:

--------------------

If Gauri spends 0.75 of her salary every month, that means she saves 0.25 of her salary:

Divide the total 39000 by her monthly savings:

So it will take Gauri 13 months to save rupees 39000.

Answer:

0.75 can be written as :-

[tex] \frac{75}{100} [/tex]

and in simplest form it is:-

[tex] \frac{3}{4} [/tex]

so the answer is 3/4

The solution to the given composite function is calculated as: 12

Composite functions are defined as when the output of one function is used as the input of another. If we have a function f and another function g, the function  f of g of x is said to be the composition of the two functions.

We are given the functions:

f(x) = 2[tex]x^{\frac{1}{3} }[/tex]

g(x) = -[tex]x^{\frac{4}{3} }[/tex]

Thus:

(f - g)(-8) = 2[tex]x^{\frac{1}{3} }[/tex] + [tex]x^{\frac{4}{3} }[/tex]

= 2∛-8 + (∛-8)⁴

= (2 * -2) + (-2)⁴

= -4 + 16

= 12

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Answer:

SRTZ is not a parallelogram.

Slope of SZ:

[tex]m = \frac{ - 2 - 1}{1 - ( - 2)} = - 1[/tex]

Slope of RT:

[tex]m = \frac{0 - 3}{2 - 1} = - 3[/tex]

Since the slopes of SZ and RT are not equal, SRTZ is not a parallelogram.

The expression (yx + y + px + p) / (5x² + 10x +5) * (10x + 10) / (y² + yp) is simplified to obtain

2/y

The given expression is

(yx + y + px + p) / (5x² + 10x +5) * (10x + 10) / (y² + yp)

The expression is simplified individually, using different each equation in the expression

yx + y + px + p

= y(x + 1) + p(x + 1)

= (y + p)(x + 1)

5x² + 10x +5

= 5(x² + 2x + 1)

= 5(x² + 1)

(10x + 10)

= 10(x + 1)

(y² + yp)

= y(y + p)

bringing the equations together and simplifying further

(y + p)(x + 1) / 5(x² + 1) * 10(x + 1) / y(y + p)

= 10(x + 1)(x + 1) / 5y(x² + 1)

= 10(x² + 1) / 5y(x² + 1)

= 2/y

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Answer:

80.4 square units.

Step-by-step explanation:

solution Given:

apothem(a)=5

no of side(n)= 12

Area(A)-?

The area of a regular polygon can be found using the following formula:

[tex]\boxed{\bold{Area =\frac{1}{2}* n * s * a}}[/tex]

where:

In this case, we have:

First, we need to find S.

We can find the length of one side using the following formula:

[tex]\boxed{\bold{s = 2 * a * tan(\frac{\pi}{n})}}[/tex]

substituting value:

[tex]\bold{s = 2 * 5 * tan(\frac{\pi}{12})=2.679}[/tex]   here π is 180°

To find the area substituting value in the above area's formula:

[tex]\bold{Area = \frac{1}{2}* 12 * 2.679 * 5=80.37\: sqaure\: units}[/tex]

in nearest tenth 80.4 square units.

Therefore, the area of the regular polygon is 80.4 square units.

Answer:

80.4 square units (nearest tenth)

Step-by-step explanation:

The given diagram shows a regular dodecagon (12-sided polygon) with an apothem of 5 units.

The apothem of a regular polygon is the distance from the center of the polygon to the midpoint of one of its sides.

We can calculate the side length of a regular polygon given its apothem using the following formula:

[tex]\boxed{\begin{minipage}{5.5cm}\underline{Apothem of a regular polygon}\\\\$a=\dfrac{s}{2 \tan\left(\dfrac{180^{\circ}}{n}\right)}$\\\\where:\\\phantom{ww}$\bullet$ $s$ is the side length.\\ \phantom{ww}$\bullet$ $n$ is the number of sides.\\\end{minipage}}[/tex]

Substitute n = 12 and a = 5 into the equation to create an expression for s:

[tex]5=\dfrac{s}{2 \tan \left(\dfrac{180^{\circ}}{12}\right)}[/tex]

[tex]s=10\tan \left(15^{\circ}\right)[/tex]

Now we can use the standard formula for an area of a regular polygon:

[tex]\boxed{\begin{minipage}{6cm}\underline{Area of a regular polygon}\\\\$A=\dfrac{n\cdot s\cdot a}{2}$\\\\where:\\\phantom{ww}$\bullet$ $n$ is the number of sides.\\ \phantom{ww}$\bullet$ $s$ is the length of one side.\\ \phantom{ww}$\bullet$ $a$ is the apothem.\\\end{minipage}}[/tex]

Substitute the found expression for s, n = 12 and a = 5 into the formula and solve for A:

[tex]A=\dfrac{12 \cdot 10\tan \left(15^{\circ}\right) \cdot 5}{2}[/tex]

[tex]A=\dfrac{600\tan \left(15^{\circ}\right)}{2}[/tex]

[tex]A=300\tan \left(15^{\circ}\right)[/tex]

[tex]A=80.3847577...[/tex]

[tex]A=80.4\; \sf square\;units\;(nearest\;tenth)[/tex]

Therefore, the area of a regular dodecagon with an apothem of 5 units is 80.4 square units, rounded to the nearest tenth.

The samples are {(H, R), (H, W), (H, B), (T, R), (T, W), (T, B)}. Thus, the correct option is D.

Given that:

A coin is tossed.

A spinner has 3 equal sections: Red, White, and Blue.

The samples are groups of clearly specified components. The number of items in a finite set is denoted by a curly bracket.

The total number of samples is calculated as,

Total samples = 2 x 3

Total samples = 6

The samples are {(H, R), (H, W), (H, B), (T, R), (T, W), (T, B)}.

Thus, the correct option is D.

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The Interquartile range for the given data set is 51.

The interquartile range for a given data set, the values of the first quartile (Q1) and the third quartile (Q3). The interquartile range is the difference between Q3 and Q1.

First, let's arrange the data set in ascending order:

4, 5, 6, 27, 27, 41, 48, 54, 64, 71, 78, 79

To find Q1, which represents the lower quartile, we need to locate the median of the lower half of the data set. Since the data set has 12 values, the lower half consists of the first 6 values:

4, 5, 6, 27, 27, 41

The median of this lower half is the average of the middle two values, which are 6 and 27:

Q1 = (6 + 27) / 2 = 33 / 2 = 16.5

To find Q3, the upper quartile, we need to locate the median of the upper half of the data set. Again, since the data set has 12 values, the upper half consists of the last 6 values:

48, 54, 64, 71, 78, 79

The median of this upper half is the average of the middle two values, which are 64 and 71:

Q3 = (64 + 71) / 2 = 135 / 2 = 67.5

Finally, we can calculate the interquartile range by subtracting Q1 from Q3:

Interquartile range = Q3 - Q1 = 67.5 - 16.5 = 51

Therefore, the interquartile range for the given data set is 51.

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Luis traveled approximately 31,736.8 inches on his bicycle.

We have,

To find the distance that Luis traveled on his bicycle, we need to calculate the circumference of the tires and then multiply it by the number of complete turns.

Given:

Radius of the tires (r) = 20p (2.54) inches

Number of complete turns (n) = 50

The circumference of a circle can be calculated using the formula:

Circumference = 2πr

Substituting the given radius into the formula, we have:

Circumference = 2π * (20p) inches

Now we can calculate the distance traveled (d):

Distance = Circumference x Number of complete turns

Distance = 2π x (20p) x 50 inches

To simplify the calculation, we can approximate π as 3.14:

Distance ≈ 2 x 3.14 x (20 x 2.54) x 50 inches

Calculating this expression, we find:

Distance ≈ 31736.8 inches

Therefore,

Luis traveled approximately 31,736.8 inches on his bicycle.

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The complete question.

What is the distance that Luis traveled on his bicycle rolled 20p (2.54) after the tires gave 50 complete turns

The velocities of the boat and the person relative to the shore are 1.337 m/s and 2.896 m/s, respectively.

We can use the conservation of momentum equation:

(mboat + mperson) * vboat = mperson * vperson

(160 kg + 70 kg) * vboat = 70 kg * (0.80 m/s + vperson)

230 kg * vboat = 56 kg * (0.80 m/s + vperson)

vboat = (56/230) * (0.80 m/s + vperson)

vperson = 0.80 m/s + vboat

vperson = 0.80 m/s + (56/230) * (0.80 m/s + vperson)

(174/115) * vperson = (504/115) * m/s

Dividing both sides by (174/115), we get:

vperson = 2.896 m/s

vboat = (56/230) * (0.80 m/s + vperson)

Substituting the value of vperson, we get:

vboat = 1.337 m/s

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On a 160-kg boat that is at rest with its bow pointed to the shore, a 70-kg person begins to walk from the bow to the stern at 0.80 m/s relative to the boat. What are the velocities of the boat and the person relative to the shore? Neglect the resistance of water to motion.

The equation of the given sine function is y = 4 × sin((π/5)x) + 2.

The equation of the given sine function can be determined based on the given information. We know that the general form of a sine function is:

y = A × sin(Bx - C) + D,

where A represents the amplitude, B represents the frequency, C represents the phase shift, and D represents the vertical shift.

In this case, we are given the following information:

Amplitude (A) = 4: The amplitude is the distance between the maximum and minimum values of the function. Since the function is reflected over the x-axis, the amplitude is positive 4.

Midline (D) = 2: The midline is the horizontal line around which the graph oscillates. In this case, it is y = 2, indicating a vertical shift of 2 units upwards.

Period = 10: The period is the distance between two consecutive peaks (or troughs) of the function.

Given that there is no phase shift, the phase shift (C) is 0.

From the given information, we can deduce the values of A, B, C, and D to construct the equation.

A = 4 (amplitude)

D = 2 (vertical shift)

C = 0 (no phase shift)

To determine B, we use the formula:

B = 2π / Period

Plugging in the value for Period (10), we can calculate B:

B = 2π / 10 = π / 5

Therefore, the equation of the given sine function is:

y = 4 × sin((π/5)x) + 2.

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The conditional value probability is solved and P ( F | E ) = 6/17

Given data ,

P ( E ) = 0.85

P ( F ) = 0.4

P ( E ∩ F ) = 0.3

Now , the formula for conditional probability to calculate P(F|E):

P(F|E) = P(E ∩ F) / P(E)

We are given that P(E) = 0.85 and P(E ∩ F) = 0.3, so we can substitute those values in:

P(F|E) = 0.3 / 0.85

Simplifying this fraction, we get:

P(F|E) = 6/17

Hence , the probability of F given that E has occurred is 6/17 or approximately 0.35.

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The probability of picking a blue marble and then a green marble without replacing the blue one is 4/45.

We have,

We see that there are 10 marbles.

Now,

Number of blue marbles = 2

Number of green marbles = 4

Now,

The probability of picking a blue marble first is 2/10, as there are 2 blue marbles out of 10 in total.

After picking a blue marble, there will be 9 marbles left in the bag.

The probability of picking a green marble second, without replacing the blue one, is 4/9, as there are 4 green marbles remaining out of the 9 marbles in total.

Now,

P(blue marble and green marble) = P(blue marble) x P(green marble)

= (2/10) x (4/9)

= 8/90

= 4/45.

Therefore,

The probability of picking a blue marble and then a green marble without replacing the blue one is 4/45.

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Answer:

10 millimeters

Step-by-step explanation:

The diameter of the button is twice the radius. Therefore, the diameter of Jasmine's pants button is 10 millimeters.