Use the Distance Formula to find the distance between each pair of points. Round to the nearest tenth if necessary.
5. P(1, 1), Q(–1, –1)














6. E(1/2,4 1/4),F(5,-1/2)

Answers

Answer 1

Given:

The pair of points.

5. P(1, 1), Q(–1, –1)

6. [tex]E\left(\dfrac{1}{2},4\dfrac{1}{4}\right), F\left(5,-\dfrac{1}{2}\right)[/tex]

To find:

The distance between the pair of points.

Solution:

Distance formula:

[tex]d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

5.

The distance between the pair of points P(1, 1) and Q(–1, –1) is:

[tex]PQ=\sqrt{(-1-1)^2+(-1-1)^2}[/tex]

[tex]PQ=\sqrt{(-2)^2+(-2)^2}[/tex]

[tex]PQ=\sqrt{4+4}[/tex]

[tex]PQ=\sqrt{8}[/tex]

[tex]PQ=2\sqrt{2}[/tex]

Therefore, the distance between P and Q is [tex]2\sqrt{2}[/tex].

6.

The distance between the pair of point [tex]E\left(\dfrac{1}{2},4\dfrac{1}{4}\right), F\left(5,-\dfrac{1}{2}\right)[/tex] is:

[tex]EF=\sqrt{\left(5-\dfrac{1}{2}\right)^2+\left(-\dfrac{1}{2}-4\dfrac{1}{4}\right)^2}[/tex]

[tex]EF=\sqrt{\left(\dfrac{10-1}{2}\right)^2+\left(-\dfrac{1}{2}-\dfrac{17}{4}\right)^2}[/tex]

[tex]EF=\sqrt{\left(\dfrac{9}{2}\right)^2+\left(\dfrac{-2-17}{4}\right)^2}[/tex]

[tex]EF=\sqrt{\dfrac{81}{4}+\left(\dfrac{-19}{4}\right)^2}[/tex]

On further simplification, we get

[tex]EF=\sqrt{\dfrac{81}{4}+\dfrac{361}{16}}[/tex]

[tex]EF=\sqrt{\dfrac{324+361}{16}}[/tex]

[tex]EF=\sqrt{\dfrac{685}{16}}[/tex]

[tex]EF=\sqrt{42.8125 }[/tex]

[tex]EF\approx 6.5[/tex]

Therefore, the distance between E and F is 6.5 units.


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Given

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Required

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Answers

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Step 3 : Caroline doesn't buy fruit but buys cd = 0.18               ( 0.6 x 0.3 )

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Step-by-step explanation:

 

Step 1 : Caroline buys fruit and buys cd ( buys both) = 0.12      ( 0.4 x 0.3)

Step 2 : Caroline buys fruit and not cd =  0.28                          ( 0.4 x 0.7)

Step 3 : Caroline doesn't buy fruit but buys cd = 0.18               ( 0.6 x 0.3 )

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Answers

Answer:

Step-by-step explanation: (15+12)-3^2 power ------> 27-3^2 power ----> 27-9 ----> equals 18

ANSWER:

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0
20
60
80
The box plot shows information about
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40
Weight (grams)
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a) Which of the statements below describes Felipe's statement best?
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C - He is correct because the Median weight is 56 grams.
(1)
b) Work out the range of weights of Felipe's tomatoes.
(1)
c) Work out the interquartile range of weights of Felipe's tomatoes.
(1)

Answers

Answer:

a) c

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Step-by-step explanation:

He is correct because the Median weight is 56 grams.

Option C is the correct answer.

The range of weights of Felipe's tomatoes is 62.

The interquartile range of weights of Felipe's tomatoes is 44 grams.

What is a median?

It is the middle value of the given set of numbers after arranging the given set of numbers in order.

We have,

From the box plot,

Median = 56 grams

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The statement that Felipe describe is correct because the median weight of 56 grams.

The range of the weights of the tomatoes.

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The interquartile range of weights of Felipe's tomatoes.

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Median weight = 56 grams.

Range = 62

Interquartile range = 44 grams.

Learn more about median here:

https://brainly.com/question/28060453

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