Use the relationship shown on this graph.

Answer:

circle

Step-by-step explanation:

any point on the circumference of a circle is equidistant from the centre.

john could be right now 45

What is word problem in math?

A math word problem is a question that is written as one or more sentences and asks students to use their mathematical understanding to solve an issue from "real world."

According to the question:

And

Solution for the above equation:

                                               [tex]x=y-30, y=3 x \quad\\ \quad x=15, y=45[/tex]

steps:

                                                [tex]x=y-30 \\y=3 x[/tex]

Substitute :[tex]$y=3 x$[/tex]

                                               [tex][x=3 x-30][/tex]

                                   [tex]for $$x=3 x-30: \quad x=15[/tex]

For [tex]$y=3 x$[/tex]

Substitute: [tex]$x=15$[/tex]

                                               [tex]y=3 \cdot 15[/tex]

Simplify:

                                               [tex]y=45[/tex]

The solutions to the system of equations are: [tex]$x=15, y=45$[/tex]

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Answer:

-4

Step-by-step explanation:

Slope = y/x

1. y=12 x=-3

  12/-3=-4

2. y=8, x=-2

   8/-2 = -4

3. y=4, x=-1

   4/-1 = -4

4. 0/0 = 0

5. y=-4, x=1

   -4/1 = -4

Hope it helps I had this question last year on Acellus.

Based on the calculations, the true statements are:

A. The angular velocity is 10π rad/sec.

E. The angular velocity is 600π rad/min.

Mathematically, angular velocity can be calculated by using this formula:

ω = θ/t

Where:

Note: 1/2 revolution = 0.5 × 2π = π radians.

Substituting the given parameters into the formula, we have;

ω = θ/t

ω = π/0.1

ω = 10π rad/s.

Next, we would convert the time in seconds to minutes:

ω = 10π × 60

ω = 600π rad/min.

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Complete Question:

A golfer’s arm rotates 1/2 of a revolution in 1/10 of a second. If the angular displacement is measured in radians, which statements are true? Check all that apply.

A. The angular velocity is 10π rad/sec.

B. The angular velocity is 10π rad/min.

C. The angular velocity is 60π rad/min.

D. The angular velocity is 600π rad/sec.

E. The angular velocity is 600π rad/min.

Answer:

A,

Step-by-step explanation:

Edge202

Answer:

The remaining 15 athletes did not participate in any type of flexibility program

The xy-value in the solution to the given system of linear equation shows that x = 2 and y = -4.

Whenever two or more linear equations operate simultaneously, we create a System of Linear Equations. These equations must contain one or more similar variables in order to operate together.

When solving a system of linear equations, our objective is to simplify two equations having two variables to a single equation having one variable. Because each equation in the system includes two variables, substituting an expression for a variable is one technique to minimize the number of variables in an equation.

From the given information:

4x + 5y = -12  --- (1)

-2x + 3y = -16 ----- (2)

From equation (1)

4x+5y+(−5y) = −12 + (−5y)       (Add -5y to both sides)

4x = −5y − 12

Divide both sides by 4

[tex]\mathbf{\dfrac{4x}{4}= \dfrac{-5y-12}{4}}[/tex]

[tex]\mathbf{x= \dfrac{-5}{4}y-3}[/tex]

Replacing the value of x in [tex]\mathbf{ \dfrac{-5}{4}y-3}[/tex] into equation (2); we have:

[tex]=\mathbf{-2(\dfrac{-5}{4}y-3)+3y=-16}[/tex]

[tex]\mathbf{\dfrac{11}{2}y+6 =-16}[/tex]

Simplifying both sides of the equation, we have:

[tex]\mathbf{\dfrac{11}{2}y+6-6 =-16-6}[/tex]

[tex]\mathbf{\dfrac{11}{2}y=-22}[/tex]

Cross multiply

11y = -44

y = -4

Replace the value of y = -4 into [tex]\mathbf{x= \dfrac{-5}{4}y-3}[/tex]

[tex]\mathbf{x= \dfrac{-5}{4}(-4)-3}[/tex]

x = 2

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Since the standard deviation for the population is known, the z-distribution is used as the sampling distribution basis for this hypothesis test.

In this problem, the standard deviation for the population is known, hence the z-distribution is used.

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The equation passing through the point ()8, 2 and parallel to 6x - 9y = -7 is y = 6 / 7x - 2 / 7

The equation of the line passes through the point (8, 2) and it is parallel to 6x  - 7y = -7.

The equation of a line can be represented as follows;

y = mx + b

where

m = slope

b = y-intercept

Therefore, parallel line have the same slope.

6x  - 7y = -7

7y = 6x + 7

y = 6 / 7 x + 1

m = 6 / 7

Hence, using (8, 2)

2 = 6 / 7 (8) + b

2 = 16 / 7 + b

b = 2 - 16 / 7

b =  14 - 16/ 7

b = - 2 / 7

Hence, the equation is y = 6 / 7x - 2 / 7

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The solution to the system of equations is (-1.189, 3.587) and (1.189, 3.587)

The system of equations is given as

y=e^x+e^-x

y=5-x^2

See attachment for the graph of both equations

From the attached graph, the curve intersect at

(-1.189, 3.587) and (1.189, 3.587)

Hence, the solution to the system of equations is (-1.189, 3.587) and (1.189, 3.587)

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The entire interval over which the function, f(x), is positive is (-∞,1).

A mathematical phrase, rule, or law that establishes the link between an independent variable and a dependent variable. In mathematics, functions exist everywhere, and they are crucial for constructing physical links in the sciences.

Each element of X receives exactly one element of Y when a function from one set to the other is used. The set X is referred to as the function's domain, while the set Y is referred to as the function's codomain.

According to the question,

The function has positive values corresponding to the interval from negative infinity to one.

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Answer:

hi play truth and dare to with me in g met

The principal is 1000

SI = PRT/100

Simple interest = 100

Rate = 5%

Time = 2 years.

SI = PRT/100

100 = (P × 5 × 2)/100

10000 = 10P

P = 10000/10

P = 1000

The probability of drawing two yellow balls if they're not replaced exists 1/45.

The probability exists in the analysis of the possibilities of happening of an outcome, which exists accepted by the ratio between favorable cases and possible cases.

Number of yellow marbles be 2

Number of pink marbles be 3

Number of blue marbles be 5

Total number of marbles = 2+3+5 = 10

The probability of removing the first yellow ball = 2/10

Since the ball exists not replaced, that indicates there choice be 9 balls left and 1 yellow ball left.

Probability of drawing the second yellow ball = 1/9.

Probability of drawing two yellow balls if they're not replaced

= 2/10 × 1/9

= 2/90

= 1/45

The probability of drawing two yellow balls if they're not replaced exists 1/45.

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The following pairs of lines should be matched with their descriptions as follows:

Parallel lines can be defined as two (2) lines that are always the same (equal) distance apart and never meet.

In Geometry, two (2) lines are considered to be parallel if their slopes are the same (equal) and they've different y-intercepts.

This ultimately implies that, two (2) lines are parallel under the following conditions:

m₁ = m₂

Note: m is the slope.

Perpendicular lines can be defined as two (2) lines that intersect or meet each other at an angle of 90° (right angles).

In Mathematics, the condition for perpendicularity of two lines is:

m₁ × m₂ = -1

Given the following equations:

y = 2x/3 + 4 and y = -3x/2 + 9; 2/3 × -3/2 = -1.

y = 4x/5 + 8 and y = 5x/4 + 8; neither parallel nor perpendicular lines.

y = 5x/6 + 8 and y = 5x/6 + 2; 5/6 = 5/6.

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The correct answer is all of the above.

Why is the range the most convenient measure of variability?

How do you find the range?

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Answer:

T(1)=1+2(1)+3=6

T(2)=2+2(2)+3=9

T(3)=3+2(3)+3=12

T(100)=100+2(100)+3=303

Answer:

$0.75, which is

75 cents

Step-by-step explanation:

First add the cost of all the items.

1.25 + .50 + 3.95

= 5.70

To find 10% of 5.70, change the percent to a decimal and multiply.

10% is .10

5.70 × .10 = .57

The tax is 57 cents. This can be written as $0.57



The amount of the galleys or the number of galleys.

If given the amount of galleons, you can find the amount of galleys by dividing the number of given galleons by 5.

If given the amount of galleys, you can find the amount of galleons by multiplying the number of given galleys by 5.

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The approximate area of circle A is π · 8² = 64π ≈ 201.062 square inches.

The approximate area of circle B is π · 4² = 16π ≈ 50.265 square inches.

The approximate area of shaded region 1 is 24² - 64π ≈ 374.938 square inches.

The approximate area of shaded region 2 is 64π - 16π = 48π ≈ 150.796 square inches.

In this situation we have a square whose side length is known and two circles whose radii have to be estimated. By direct inspection we find that the diameter of circle A is two thirds of the length of the square side (l), in inches and the diameter of circle B is the half of the diameter of the former. Now we proceed to find the key dimensions of the figure:

Circle A

Diameter: 16 inches

Radius: 8 inches

Circle B

Diameter: 8 inches

Radius: 4 inches

The approximate area of circle A is π · 8² = 64π ≈ 201.062 square inches.

The approximate area of circle B is π · 4² = 16π ≈ 50.265 square inches.

The approximate area of shaded region 1 is 24² - 64π ≈ 374.938 square inches.

The approximate area of shaded region 2 is 64π - 16π = 48π ≈ 150.796 square inches.

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Answer:

√(3 , √(π , 2

Step-by-step explanation:

ascending order

The probability that a student buys coffee OR a muffin before class is 55%

The given parameters are:

P(Coffee) = 30%

P(Muffin) = 40%

P(Tea) = 20%

P(Coffee and Muffin) = 15%

P(Tea and Muffin) = 10%

The probability that a student buys coffee OR a muffin before class is

P(Coffee or Muffin) = P(Coffee) + P(Muffin) - P(Coffee and Muffin)

This gives

P(Coffee or Muffin) = 30% + 40% - 15%

Evaluate

P(Coffee or Muffin) = 55%

Hence, the probability that a student buys coffee OR a muffin before class is 55%

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Answer:

They are parallel.

Step-by-step explanation:

They have the same slope, 7, and different y-intercepts, 4, -1/4, so they are parallel.

Answer:

D. Both factors are positive, so the product will be positive.​

The measure that best describes the data is the median and the measure that might mislead the data is the mode

The mean is calculated as:

[tex]\bar x = \frac{\sum fx}{\sum f}[/tex]

So, we have:

[tex]\bar x = \frac{20* 2 + 50 * 3 + 60 * 6 + 70 * 3 + 80 * 4 + 90 * 4 + 100 * 2 + 130 * 1}{25}[/tex]

This gives

[tex]\bar x = \frac{1770}{25}[/tex]

[tex]\bar x = 70.8[/tex]

So, the mean is 70.8

The median is the middle number, and the position is calculated using

Median = (n + 1)/2 th

This gives

Median = (25 + 1)/2 th

Median = 13th

The 13th element is 70

So, the median is 70

The mode is the data element with the highest frequency.

So, the mode is 60

The line plot has outliers at 20 and 130.

This is so because 20 and 130 are far from other data values

When a dataset has an outlier, the best measure is the median

Hence, the measure that best describes the data is the median.

The measure that might mislead the data is the mode

This is so the highest occurring value does not necessarily represent the dataset

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Answer:

cosF = 0.6

Step-by-step explanation:

cosF = [tex]\frac{adjacent}{hypotenuse}[/tex] = [tex]\frac{EF}{DF}[/tex] = [tex]\frac{6}{10}[/tex] = 0.6

Answer:

Cos F = 0.6

Step-by-step explanation:

    [tex]\sf \boxed{\bf \ Cos \ F = \dfrac{adjacent \ side \ of \ \angle F}{hypotenuse}}[/tex]

                   [tex]\sf =\dfrac{EF}{DF}\\\\=\dfrac{6}{10}\\\\= 0.6[/tex]

Answer: 4:3

Step-by-step explanation:

The side length of the triangle is 48/3 = 16.

The side length of the square is 48/4 = 12.

So, the ratio is 16:12 = 4:3.

The sine, cosine, cosecant, and secant functions have period 2π; the tangent and cotangent functions have period π.

Definition for Period of a Trigonometric Function :

The pause between any function's repetitions is known as the function's period. The duration of one complete cycle is the period of a trigonometric function. Trigonometric functions include three basic types: sin, cos, and tan, which have periods of -2π, 2π, and π respectively.

If a function repeats itself repeatedly at a predetermined frequency, it is said to be periodic. The formula for t is f(x) = f(x + p), where p is a real number that denotes the period of the function. Period is the interval between two occurrences of the wave.

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The recursive formula for the geometric sequence is given as follows:

D.

A geometric sequence is a sequence in which the result of the division of consecutive terms is always the same, called common ratio q.

The nth term of a geometric sequence is given by:

[tex]a_n = a_1q^{n-1}[/tex]

In which [tex]a_1[/tex] is the first term.

With a recursive formula, it is given by:

[tex]a_n = a_{n-1} \times q[/tex]

For this problem, the first term and the common ratio are:

[tex]a_1 = 9, q = -\frac{1}{3}[/tex]

Then the recursive formula is:

D.

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