The reading of the scale after 3.6 seconds is 23.79 N.
Velocity of the water
v = √2gh
v = √(2 x 9.8 x 2.2)
v = 6.57 m/s
Rate of change of momentum of the water after impactmv/t = F = 0.4 x 6.57 = 2.628 N
Weight of the bucketWb = 0.72 x 9.8
Wb = 7.056 N
Weight of the accumulated waterWa = (RT)g
Wa = (0.4 x 3.6) x 9.8
Wa = 14.11 N
Reading of the scaleR = Wa + Wb + F
R = 14.11 N + 7.056 N + 2.628 N
R = 23.79 N
Thus, the reading of the scale after 3.6 seconds is 23.79 N.
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A car heading north collides at an intersection with a truck of the same mass as the car heading east. If they lock together and travel at 28 m/s at 46° north of east just after the collision, how fast was the car initially traveling? assume that any other unbalanced forces are negligible.
Answer: A car heading north collides at an intersection with a truck of the same mass as the car heading east. If they lock together and travel at 28 m/s at 46° north of east just after the collision, then the car initially traveling with a velocity of 40.28m/s.
Explanation: To find the answer, we need to know more about the Perfectly inelastic collision.
What is perfectly inelastic collision?Collision is an interaction between two bodies due to which the individual momenta of the colliding bodies are changed, but the total momentum remains constant.If the colliding bodies stick together after collision, then it is called perfectly inelastic collision.here, the coefficient of restitution will be equal to 0.For, inelastic collision, the momentum is conserved, but the energy is not conserved.How to solve the problem?let's write the conservation equation of momentum as,[tex]m_1v_1+0=(m_1+m_2)v_2\\[/tex]
We have to find the value of initial velocity v1,[tex]mv_1=(m+m)28 sin46\\v_1=2*28*0.719=40.28 m/s[/tex]
Thus, we can conclude that, the initial velocity of the car will be 40.28m/s.
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A conducting loop in the form of a circle is placed perpendicular to a magnetic field of 0. 50 t. If the area of the loop decreases at a rate of 3. 0 × 10-3 m2/s, what is the induced emf in the loop?
The induced emf in the loop is -1500 μ V or - 0.0015 V .
According to the question
A conducting loop in the form of a circle is placed perpendicular to a magnetic field of 0. 50 t.
i.e
Magnetic field (B) = 0. 50 T
Area of circle or loop = [tex]\pi r^{2}[/tex]
Now,
The area of the loop decreases at a rate of 3. 0 × 10⁻³ m/s
i.e
dA = 3. 0 × 10⁻³ meter²
dt = 1 sec
As per the formula of Induced e.m.f in the loop
emf is dependent on number of turns of coil, shape of the coil, strength of magnet and speed with which magnet is moved. Emf is independent of resistivity of wire of the coil.
[tex]e=-B*\frac{dA}{dt}[/tex]
where A is the area of the loop.
Now ,
Substituting the values in the formula
[tex]e=-B*\frac{dA}{dt}[/tex]
[tex]e= - 0.50 *\frac{ 3 * 10^{-3}}{1}[/tex]
e = - 0.0015 V
OR
e = -1500 * 10⁻⁶ V
e = -1500 μ V
Negative just signifies emf will such be induced that current induced will oppose change in magnetic field though it
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a 6 amp light bulb dissipates 24j per seconds
calculat the amount of charge passing through the 6 amp light bulb per second
The charge passing through the circuit in one second is 8 C.
What is charge?Charge is property of matter that causes experience of force when kept in electric or magnetic field.
Electric charge exists as the physical property of matter that causes charged matter to experience a force when positioned in an electromagnetic field. Electric charges can be positive or negative. Like charges repulse each other and unlike charges attract each other.
Charge, also understood as electric charge, electrical charge, or electrostatic charge and symbolized by q, exists as a characteristic of a unit of matter that represents the extent to which it has more or fewer electrons than protons.
As we know
I =Q/t
where I is current and Q is charge ,t is time
so put the value in formula
8 = Q/
Q = 8 coulomb.
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An elevator cab and its load have a combined mass of 1600 kg. Find the tension in the supporting cable when the cab, originally moving downward at 12 m/s, is brought to rest with constant acceleration in a distance of 42 m.
The tension in the supporting cable when the cab originally moves downward is 18422.4 N
What is tension?
Tension is described as the pulling force by the means of a three-dimensional object.
Tension might also be described as the action-reaction pair of forces acting at each end of said elements.
Here,
m =combined mass = 1600 kg
s = Displacement of the elevator = 42 m
g = Acceleration due to gravity = 9.81 m/s²
u = Initial velocity = 12 m/s
v = Final velocity = 0
According to the equation of motion:
[tex]v^{2} - u^{2} = 2as[/tex]
0 - 12^2 = 2*a*42
a = - 144 / 84
a = - 1.714 m/s^2
Now let's write the equation of the forces acting on the elevator. Taking upward as positive direction:
T-mg = ma
T = m(g-a)
T = 1600 ( 9.8-(-1.74))
T=18422.4 N
Hence,
The tension in the supporting cable when the cab, originally moving downward is 18422.4 N
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Read the following questions and answer them using complete sentences. Be sure to fully explain your answers.
What can be the challenges of wave power? Is it a reliable source of energy?
Wave power can be regarded as a reliable source of energy because the ocean currents are always moving.
What can be the challenges of wave power?Wave power is a device that can be used to convert the mechanical energy of the ocean waves into electrical energy based on the principle of conservation of energy.
The major challenges that face the use of wave power in electricity generation is the unreliability of the waves which leads to uncertainty in the quantity of power generated Also, the wave direction and direction of ocean currents all limit the amount of power generated by this method. However, in spite of challenges, it can be regarded as a reliable source of energy because the ocean currents are always moving.
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Work is being done in "which of these situations? All motions
are at a constant velocity (including velocity = zero).
O Jessica pushes a 25 kilogram cart a distance of 10 meters.
O
A weightlifter holds a 100 k/fogram barbell over his head.
O Bane carries a 20 kilogram box a distance of 50 meters.
O Ali is trying to push a truck away from the parking lot.
Work is being done when Jessica pushes a 25 kilogram cart a distance of 10 meters and Bane carries a 20 kilogram box a distance of 50 meters.
What is Work ?Work is the product of force and distance in the direction of the force. And the S.I unit of work is Joule
Looking at the given options one by one;
O Jessica pushes a 25 kilogram cart a distance of 10 meters. Work is done by Jessica. The work done = 25 x 10 x 10 = 2500 Joules
O A weightlifter holds a 100 kilogram barbell over his head. The weightlifter does no work.
O Bane carries a 20 kilogram box a distance of 50 meters. Bane does work. The work done = 20 x 10 x 10 = 2000 Joules
O Ali is trying to push a truck away from the parking lot. Since there is no movement, there is no work done.
Therefore, Work is being done when Jessica pushes a 25 kilogram cart a distance of 10 meters and Bane carries a 20 kilogram box a distance of 50 meters.
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Plsss Help!!!!
Complete the following nuclear reaction
a) γ
b) α
c) β–
d) p
Ple can someone help me to answer this question
The length of the uniform meter stick is 50 cm and the mass of the uniform meter stick is 50 g.
A sketch of the uniform stick and the massThe sketch of the uniform stick and the mass will be two based on the given statement.
when the uniform stick balances on knife at 10 cm from one end;-------------------------------------------------------
↓ 10cm Δ (L - 10 cm) ↓
200g M
When the knife edge is moved 5 cm further|---------------15 cm-----------------|
-----------------------------------------------------------------------
↓ 8.75 cm Δ (L - 15 cm) ↓
200g M
From the first diagram, apply principle of moment;
200(10) = M(L - 10) ------- (1)
From the second diagram, apply principle of moment;
200(8.75) = M(L - 15) ------- (2)
From equation (1); M = (2000) / (L - 10)
From equation (2); M = (1750) / (L - 15)
Solve (1) and (2);
(2000) / (L - 10) = (1750) / (L - 15)
1750(L - 10) = 2000(L - 15)
L - 10 = 2000/1750(L - 15)
L - 10 = 1.143(L - 15)
L - 10 = 1.143L - 17.14
17.14 - 10 = 1.143L - L
7.14 = 0.143L
L = 7.14/0.143
L = 50 cm
Mass of the uniform stickM = (2000) / (50 - 10)
M = 50 g
Thus, the length of the uniform meter stick is 50 cm and the mass of the uniform meter stick is 50 g.
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The coefficients of static and kinetic frictions for plastic on wood are 0.50 and 0.40,respectively. How much horizontal force would you need to apply to a 3.0 N plastic calculatorto start it moving from rest?
The horizontal force needed to start the calculator moving from rest is 1.5 N
What is Kinetic friction?
It is defined as a force that acts between moving surfaces.
The magnitude of the force will depend on the coefficient of kinetic friction between the two materials.
Here,
weight of calculator, N = 3 N
The coefficients of static frictions, µ (static) = 0.50
The coefficients of kinetic frictions, µ (kinetic) = 0.40
Now,
The horizontal force required = The static friction force
F = µ (static) * weight of calculator
F = 0.50 * 3.0
F = 1.5 N
Hence,
The horizontal force needed to start the calculator moving from rest is 1.5 N
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The use of fiberglass insulation in the outer walls of a building is intended to minimize heat transfer through the wall by what process?
a) conduction
b) radiation
c) convection
d) vaporization
Answer:
A, conduction.
Explanation:
Thermal conduction, by definition, is "a phenomenon that occurs through the interaction of neighboring atoms and molecules, transferring their energy/heat (partially) to their neighbors". Fiberglass insulation works mainly by preventing thermal conduction, as would a rubber handle of a pot on a hot stove.
Hope this helps!
April stands on a flat surface . If she has a mass of 72 what is the nirmal force acting on her
The normal force acting on April as she stands on a flat surface is 705.6 N.
Normal force of the girl
Fₙ = mg
where;
Fₙ is the normal force of the girlm is mass of the girlg is acceleration due to gravityFₙ = 72 x 9.8
Fₙ = 705.6 N
Thus, the normal force acting on April as she stands on a flat surface is 705.6 N.
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Given: NM 1 XZ
Prove: AXYZ- ANYM
N
Try 11
X
Z
M
We know that side NM is
to side
XZ. If we consider side NY the transversal for these
parallel lines, we create angle pairs. Using the
we can state
that YXZ is congruent to YNM. We know that angle
XYZ is congruent to angle
by the reflexive
property. Therefore, triangle XYZ is similar to triangle
NYM by the
similarity theorem.
F
The prove of Angle XYZ- Angle NYM is given below:
∠XYZ is congruent to ∠NYM - reflexive property. ΔXYZ is the same with Δ NYM,- AA (angle-angle) similarity theorem.What is the triangle about?Note that from the image given;
NM // XZNY = transversal line∠YXZ ≡ ∠YNMSince ∠XYZ is said to be congruent to ∠NYM it can be proven by the use of the reflexive property.
The reflexive property is one that informs that any shape is regarded congruent to itself.
Since ∠NYM has a different way to call ∠XYZ that uses a different vertexes, but the sides are made up of the two angles which are said to be the same.
Therefore , ∠XYZ ≡ ∠NYM are proved by the reflexive property.
Since ΔXYZ is the same with Δ NYM, it can be proven by the AA (angle-angle) similarity theorem.
We have 2 angles Δ XYZ and Δ NYM:
Note that ∠YXZ ≡ ∠YNM
∠XYZ ≡ ∠NYM
So, ΔXYZ is said to be the same to ΔNYM and it is proven by the AA similarity theorem.
Therefore, The prove of Angle XYZ- Angle NYM is given below:
∠XYZ is congruent to ∠NYM - reflexive property. ΔXYZ is the same with Δ NYM,- AA (angle-angle) similarity theorem.Learn more about triangles from
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Answer:
1. parrael
2. corresponding angles theorem
3. NYM
4. AA
Explanation:
just took it
Critical heat flux of forced convective boiling in uniformly heated vertical tubes with special reference to very large length-to-diameter ratios
Critical heat flux of forced convective boiling in uniformly heated vertical tubes with special reference to very large length-to-diameter ratios.
The rate of heat energy moving through a surface is known as heat flux, and the heat flux density is the amount of heat flux per unit area (Wm2).
Temperature measurements are a key component of many industrial systems. Measurements of heat flux and heat transfer provide more details. A heat flow typically occurs in conjunction with a change in temperature. A clearer picture of what's happening can be obtained by measuring both quantities.
The amount of thermal energy emitted over a solid surface is known as heat flux, and its unit is W/m2. There are two methods for measuring heat flux. Either directly utilizing heat flux sensors or indirectly using temperature sensors
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The wavelength of an electromagnetic wave is 600 nm. what is its frequency? (c = 3.0 × 108 m/s)
Answer:
5.0×10^-9
Explanation:
velocity = frequency × wavelength
3.0×10^8=f600×10^-9
divide both sides by 600×10^-9
f=3.0×10^8/600×10-9
f=5.0×10^-9
The wavelength of an electromagnetic wave is 600 nm. The frequency of the electromagnetic wave is 5.0 × 10^14 Hz.
To find the frequency of an electromagnetic wave, we can use the equation:
Frequency (f) = Speed of light (c) / Wavelength (λ)
where:
c = speed of light in a vacuum = 3.0 × 10^8 m/s
λ = wavelength of the electromagnetic wave in meters
First, we need to convert the given wavelength from nanometers (nm) to meters (m). Since 1 nm = 1 × 10^-9 m, the wavelength is:
λ = 600 nm × (1 × 10^-9 m/nm) = 600 × 10^-9 m = 6.0 × 10^-7 m
Now, we can calculate the frequency using the equation:
f = c / λ
f = 3.0 × 10^8 m/s / (6.0 × 10^-7 m)
f = 5 × 10^14 Hz
So, the frequency of the electromagnetic wave is 5 × 10^14 Hz (hertz).
This means that the wave oscillates or completes 5 × 10^14 cycles per second. Higher frequencies correspond to shorter wavelengths and vice versa. Electromagnetic waves with higher frequencies are more energetic, such as X-rays and gamma rays, while waves with lower frequencies, like radio waves, have longer wavelengths and are less energetic.
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A uniform ladder 5.0 m long rests against a frictionless, vertical wall with its lower end 3.0 m from the wall. The ladder weighs 160 N. The coefficient of static friction between the foot of the ladder and the ground is 0.40. A man weighing 740 N climbs slowly up the ladder.
The only vertical forces acting on the wall are the weights of the man and the ladder as well as the normal force because the wall has no friction.
The maximal frictional forces are μsN2=(0.40)(900N)=360N, and N1=w1+wm=160N+740N=900N for the vertical forces to balance. At a height of 4.0 meters above the ground, the ladder makes contact with the wall. about the point of contact with the ground, balancing torques.
N2 = 174.0N because (4.0m)2 = (1.5m)(160N) + (1.0m)(35)(740N) =684N.m. It is necessary for the frictional force to counteract this horizontal force. Setting the frictional fore and n1 to a maximum of 360N and solving for the distance x along the ladder (0.4m)(360N)=(1.50m)(160N)+x(35)(740N) yields x=2.70m
Friction
When two sliding solid surfaces, fluid layers, or material components come into contact with one another, friction acts as a force to stop them from moving in the same direction. Friction comes in several forms:
The relative lateral motion of two solid surfaces in contact is opposed by dry friction. Between moving surfaces, there is kinetic friction, which is different from static friction. With the exception of atomic or molecule friction, asperities on the surface interact to produce dry friction.
When layers of a viscous fluid move in relation to one another, there is friction between them. This is known as fluid friction.
When a lubricant fluid separates two solid surfaces, it is called lubricated friction.
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A lot contains 750 square yards and has a length of 150 feet, what does the frontage measure?
The frontage measure is 45 feet.
FeetThe British imperial and American customary systems of measurement both use the feet (standard symbol: ft) as a unit of length. One foot has exactly 0.3048 meters since the International Yard and Pound Agreement of 1959. One yard equals three feet in both customary and imperial measurements. One foot equals 12 inches.
Throughout history, numerous regional systems of units, including the Greek, Roman, Chinese, French, and English systems, included the concept of "feet." Its length varied from one nation to another, from one city to another, and occasionally from one trade to another. Its length was often divided into 12 inches or 16 digits, however this was not always the case. Its typical length was between 250 mm and 335 mm.
A lot contains 750 square yards and has a length of 150 feet, what does the frontage measure?
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When making segmented bends, the bend radius is the distance from the center point of the circle or object to
When making segmented bends, the bend radius is the distance from the center point of the circle or object to the centerline of conduit.
What is centerline of conduit.Segment bending is a technique for bending conduit in which numerous tiny bends are combined to form a single, bigger bend. Measure from the elbow's center at the bend's CenterPoint to the intersection of the "degrees of bend" lines to determine your centerline radius (see image above). In fact, the CLR may be determined by obtaining this measurement from any point on the elbow. The distance between segments is calculated by dividing the developed length by the number of shots. When making segmented bends, the bend radius is the distance from the center point of the circle or object to the centerline of conduit. To calculate the degrees per shot, divide 90 degrees by the quantity of shots. Regardless of how many lanes a road or highway has, centerline miles are used to quantify their length. Centerline of conduit miles between the two sides of a divided highway might differ slightly due to divergences and curves. Compared to lane miles, centerline miles provide a more understandable indication of a road's overall length.
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The 0.20 kg puck on the frictionless, horizontal table in the figure is connected by a string through a hole in the table to a hanging 1.20 kg block.(Figure 1)
The speed with which the puck must rotate in the circular path is 5.42 m/s.
Speed of the puck in circular pathThe speed of the puck is calculated as follows;
centripetal force = weight of hanging mass
mv²/r = W
where;
W is weight of the hanging massm is mass of the puckr is radius of the circular pathv² = Wr/m
v² = (1.2 x 9.8 x 0.5) / (0.2)
v² = 29.4
v = √29.4
v = 5.42 m/s
Thus, the speed with which the puck must rotate in the circular path is 5.42 m/s.
The complete question is below:
With what speed must the puck rotate in a circle of radius 0.50 m if the block is to remain hanging at rest?
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A colleague proposes using giant vacuum-like strainers to strain all the water in the great pacific garbage patch. do you think this would be an effective way to remove plastic?
No, the use of a giant vacuum-like strainers is not an effective way to remove plastic because the patch tend to be very big and deep that it would need a lot of human effort or strength to filter the trash and the act would lead to disrupt of life in the water column.
What is plastic?Plastic is known to be a term that connote the material that is made up of a key ingredient of an organic substance and it is made up of large molecular weight.
Note that It is also seen as polymers that belongs to long carbon chains. and there are a lot of waste disposal in the ocean which disrupt marine activities.
Hence, No, the use of a giant vacuum-like strainers is not an effective way to remove plastic because the patch tend to be very big and deep that it would need a lot of human effort or strength to filter the trash and the act would lead to disrupt of life in the water column.
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A driver comes to a red light and applies her brakes to decelerate her car to a complete stop. The car’s brakes turned its kinetic energy into __________.
Group of answer choices
a. elastic potential energy
b. gravitational potential energy
c. thermal energy
d. electrical energy
A 58.5 kg wood board is resting on very smooth ice in the middle of a frozen lake. A 41.7 kg boy stands at one end of the board. He walks from one end of the board to the other end with a velocity of 1.27 m/s relative to the ice in the positive direction. What is the velocity of the board relative to the ice?
The velocity of the wood board which is resting on very smooth ice in the middle of a frozen lake relative to this ice is 0.905 m/s
What is conservation of momentum:It states the amount of momentum remains constant
Momentum of a moving body is the product of mass times velocity.
Formula for momentum:
P = m* vWhen the two objects collides, then the initial collision of the two body is equal to the final collision of two bodies by the law of conservation of momentum.
here,
mass of wood, m=58.5 kg
mass of boy, M=41.7 kg
velocity of the boy V=1.27 m/s
Thus,
The conservation of momentum,
m*v = M*V
substituting the value,
(58.5*v) = 1.27* 41.7
v = 52.95 / 58.5
v = 0.905 m/s
Thus, the velocity of the wood board which is resting on very smooth ice in the middle of a frozen lake relative to this ice is 0.905 m/s.
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The fact that voyager 10 continues to speed out of the solar system even though its rockets have no fuel, is an example of:_______
The fact that Voyager 10 continues to speed out of the solar system even though its rockets have no fuel, is an example of Newton's first law.
Sir Isaac Newton is a British mathematician, physicist, astronomer, alchemist, theologist, author, one of the greatest mathematicians and physicists of all time, and one of the most influential scientists. Widely recognized as a person. He was a key figure in the philosophical revolution known as the Enlightenment.
Isaac Newton is best known for his discoveries in optics (composition of white light) and mathematics (calculus). His best known is the formulation of the three laws of motion, which are the basic principles of modern physics.
Newton's first law states that a stationary or uniformly moving object remains straight unless its state is changed by the action of an external force.
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A current of 2.0 A flows through a circuit containing a motor with a resistance of 12 ohm how much energy is converted if the motor runs for a minute
The energy converted is 48 Joules
How to determine the energyWe have the formula for energy in a circuit as
Energy = Power × time
Power = I^2 R
Current, I = 2.0 A
time = 1 minute
Resistance = 12 Ohm
Substitute into the formula
Power = 2 × 2 × 12
Power = 48 Watts
Energy = 48 × 1
Energy = 48 Joules
Thus, the energy converted is 48 Joules
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On your way to work about two hours after sunrise, you notice the moon setting. What phase is it in?
The moon setting on your way to work about two hours after sunrise means it is in the gibbous phase.
What is Gibbous phase?
This phase of the moon involves its side facing the Earth appearing more than half-lit by the Sun, but is less than fully lit.
This phase occurs few hours after sunrise usually in the early morning which is why it is the most appropriate choice.
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A gas is enclosed in a container fitted with a piston of cross-sectional area 0.10 m2 . the pressure of the gas is maintained at 8000 nm-2 . when heat is slowly transferred, the piston is pushed up through a distance of 4 cm. if 42 j heat is transferred to the system during the expansion, what is the change in internal energy of the system?
The change in internal energy is 10 J.
Calculation:Given,
Cross-sectional area, A = 0.10 m²
Pressure of gas, P = 8000 N/m²
Displacement, s = 4 cm = 0.04 m
Heat transferred, H = 42 J
To find,
Change in internal energy =?
We know that, as per Law of thermodynamics,
Change in internal energy = Heat - Work
Force = pressure × area
= 8000 × 0.10
= 800 N
Work = Force × Displacement
= 800 × 0.04
= 32 J
Change in internal energy = Heat - Work
= 42 - 32
= 10 J
Hence, the change in internal energy is 10 J.
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A patient who is lactose intolerant will have a normal glucose curve after ingesting a dose of lactose.
False, A patient who is lactose intolerant will not have a normal glucose curve after ingesting a dose of lactose.
What is lactose intolerant ?
Lactose, the sugar in milk, cannot be fully absorbed by those who have lactose intolerance. They have diarrhea, gas, and bloating as a result of consuming dairy products. Although the illness, which is also known as lactose malabsorption, is typically not harmful, some people may experience uncomfortable symptoms.Types of lactose intolerance -
Primary lactose intolerance (normal result of aging) This is the most common type of lactose intolerance. Secondary lactose intolerance (due to illness or injury)Congenital or developmental lactose intolerance (being born with the condition)Developmental lactose intolerance.The symptoms of lactose intolerance?
Symptoms of lactose intolerance include nausea, cramps, gas, bloating, or diarrhea within 30 minutes to 2 hours after consuming milk or dairy products.
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NEED HELP asap pls
How much thermal energy must be removed from 3.75 kg of
water to freeze it at its melting point? Use Q = mass x latent
heat of fusion.
Melting point
Boiling point
OA. 15.8 kJ
B. 1250 kJ
Cliquid
Latent heat of fusion.
Latent heat of vaporization
C. 3.75 kJ
Properties of water
Property
D. 8480 kJ
0°C
Value
100°C
4.18 kJ/(kg x °C)
333 kJ/kg
2260 kJ/kg
The heat that is required to freeze the water is 1250 kJ. Option B
What is the freezing point?The freezing point of water is the temperature at which liquid water turns to solid. We know that heat is withdrawn from water when it is frozen. This heat is added when the water melts.
The latent heat of fusion = mL
m = 3.75 kg
L = 333kJ/Kg
Hence;
H = 3.75 kg * 333kJ/Kg
H = 1250 kJ
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A geologist finds that a Moon rock whose mass is 8.94 kg has an apparent mass of 6.18 kg when submerged in water. What is the density of the rock
Density of rock = 3.23 Kg/m^3
Given:
mass of Moon rock = 8.94 kg
apparent mass of Moon rock = 6.18 kg
To Find:
density of the rock
Solution: It is a universal fact that mass of an object remains constant whether measured on earth or on moon.
Mass of rock on moon/earth = 8.94 kg
When the block is immersed in water then;
Loss in weight = weight of water displaced
Loss in weight = 8.94 - 6.18 = 2.76 kg
As we know that water has a density of 1g/cm^3 (1000kg/m^3)
Volume of water = volume of the rock = Mass/density = 2.76 kg
density of rock mass/volume = 8.94/2.76 = 3.23 Kg/m^3
Density of rock = 3.23 Kg/m^3
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The spin cycle of a clothes washer extracts the water in clothing by greatly increasing the water's apparent weight so that it is efficiently squeezed
The apparent weight of a 1.1 g drop of water is 4.24084 N.
What is Apparent Weight?According to physics, an object's perceived weight is a characteristic that describes how heavy it is. When the force of gravity acting on an object is not counterbalanced by a force of equal but opposite normality, the apparent weight of the object will differ from the actual weight of the thing.By definition, an object's weight is equal to the strength of the gravitational force pulling on it. It follows that even a "weightless" astronaut in low Earth orbit, with an apparent weight of zero, has almost the same weight that he would have if he were standing on the ground; this is because the gravitational pull of low Earth orbit and the ground are nearly equal.Solution:
N = Speed of rotation = 1250 rpm
D = Diameter = 45 cm
r = Radius = 22.5 cm
M = Mass of drop = 1.1 g
Angular speed of the water = [tex]\omega = \frac{2\pi N}{60}[/tex]
[tex]\omega = \frac{2\pi \times 1250}{60}[/tex]
[tex]\omega = 130.89 rad/s[/tex]
Apparent weight is given by
[tex]W _a = M\omega^{2}R[/tex]
[tex]W_a = 1.1 \times 10^-^3\times (130.89)^2\times 0.225[/tex]
[tex]W_a[/tex] = 4.24084 N
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Question:
The spin cycle of a clothes washer extracts the water in clothing by greatly increasing the water's apparent weight so that it is efficiently squeezed through the clothes and out the holes in the drum. In a top loader's spin cycle, the 45-cm-diameter drum spins at 1250 rpm around a vertical axis. What is the apparent weight of a 1.1 g drop of water?
What should a driver do when he/she gets to a speed hump? a maintain current speed. b accelerate. c brake. d reduce speed to suggested limit.
It is usually best to reduce speed to suggested limit when a driver gets to a speed hump and is denoted as option D.
What is Deceleration?This refers to a situation in which the speed or acceleration of a body is reduced while in the other hand, acceleration refers to the condition in which a body increases its speed or acceleration.
Speed humps are structures which are placed in the road in other to slow vehicles to between 10 to 15 mph. They ensure over speeding is checked due to it being dangerous to other users.
Applying brake or maintaining current speed may lead to the vehicle being tilted towards the front end which may result in collision and other forms of accident.
This therefore the reason why reducing speed to suggested limit is the most appropriate choice.
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