What are the 4 parts of a polygon?

Answer:

El río mide:

300000 metros.

Step-by-step explanation:

1 km = 1000 metros

300 km = 300 * 1000 = 300000 metros

...

Step-by-step explanation:

You already know that we use tn=an²+bn+c for these kinds of sequences:

4, 7, 14, 25, ...

now

7–3=4

So 2a=4===> a=2

[tex] a_{1} = 4 = = > n = 1 \\ 4 = 2 \times {1}^{2} + b + c = = = = > \\ b + c = 2[/tex]

[tex] a_{2} = 7 = = > n = 2 = = = > \\ 7 = 2 \times {2}^{2} + 2 \times b + c = = = > \\ - 1 = 2b + c[/tex]

b=–3, c=5

So the final result is:

[tex] t_{n} = 2 {n}^{2} - 3n + 5[/tex]

Answer:

Step-by-step explanation:

Mabye later

The rate of change is also known as the slope. The formula to find the slope of a line is (y2 - y1) / (x2 - x1).

You can use any two points, as long as both are on the line.

Point 1 = (2, 55)

Point 2 = (8, 220)

slope = (220 - 55) / (8 - 2)

slope = 165 / 6

slope = 55 / 2 = 27.5 / 1

Lavaughn earns $27.50 for working one hour.

Hope this helps!

Answer:

x = 75/4

Step-by-step explanation:

5/8 + 1 1/4 = x/10

5/8 + 5/4 = x/10

15/8 = x/10

8x = 15 × 10

8x/8 = 150/8

x = 150/8

x = 75/4

The work done in lifting the block is 3430 J

From the question, we are to determine the work done in lifting the block

Using the formula,

Work done = mgh

Where m is the mass

g is the acceleration due to gravity

and h is the height

From the question,

m = 50.0 kg

g = 9.81 m/s²

h = 7.00 m

Putting the parameters into the formula,

Work done = 50.0 ×9.8 × 7.00

Work done = 3430 J

Hence, the work done in lifting the block is 3430 J

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Hi! ⋇

               - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -

The first digit of this number is 3², which is 9.

The Number is : 9xx

________

The second digit is: -2·(-4)=8.

The Number is : 98x.

________

The sum of all the digits is 18. This gives us an equation that we can solve in terms of x!

[tex]\multimap\sf{9+8+x=18}[/tex] (x is the digit we are looking for)

Now it takes a little arithmetic to find x :)

[tex]\multimap\sf{17+x=18}[/tex]. Just subtract 17 from both sides to find x!

[tex]\multimap\sf{x=1}[/tex]. And Now, can you see the number!

It's 981, of course :)

Hope this made sense to you!

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[tex]\large\it{\overbrace{Calligrxphy}}[/tex]

The probability that any given car will have a brake failure if it is make a is 0.0065%

The complete question is added as an attachment

From the table in the question, we have:

P(Brake failure|car a) = 0.0065%

The above represents the required conditional probability

Hence, the probability that any given car will have a brake failure if it is make a is 0.0065%

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Answer: The probability that any given car will have a brake failure if it is making A, is 0.0065%.

Step-by-step explanation:

I got it right on Edmentum!

Basic nutrients a 12-year-old needs are:

The following are the nine nutrients that a youngster should consume on a daily basis:

Therefore, basic nutrients a 12-year-old needs are given.

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The correct option is A. (4, 11) and (0, 7).

The solution of the equations y = x + 7 and y = x² – 3x + 7, the solutions are located at points: (4, 11) and (0, 7).

Estimate the y-intercept, slope, and express the equation in the form of the y-intercept (y = mx + b) to find the graphed equation. The slope is the difference between the y- and x-axis values.

A graph equation is an equation in graph theory where the unknown is a graph. Isomorphic ideas are one of the key issues in graph theory.

The equations are; y = x + 7 and y = x² - 3x + 7

At the solution, the u-values are equal, which gives;

y = y

x + 7 = x² - 3·x + 7

x² - 3·x + 7 - (x + 7) = 0

x² - 4·x = 0

x·(x - 4) = 0

x = 4, or x = 0

When x = 4, y = 4 + 7 = 11

When x = 0,

         y = 0 + 7 = 7

Therefore, the solution for the equations  y = x + 7 and y = x² - 3x + 7 are are located at points: (4, 11) and (0, 7).

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The complete question is-

Based on the graphs of the equations y = x + 7 and y = x² – 3x + 7, the solutions are located at points:

A. (4, 11) and (0, 7)

B. (4, 11) and (–7, 0)

C. (–7, 0) and (1.5, 4.75)

D. (1.5, 4.75) and (0, 7)

Answer: B. [tex]12log(x)-4log(y)[/tex]

Step-by-step explanation:

Properties of logs:

[tex]log_{a} (\frac{B}{C} )=log_{A}B-log_{A} C[/tex]

[tex]logA^B = BlogA[/tex]

So, [tex]log\frac{x^{12} }{y^4} =logx^{12} -logy^4 =12log(x)-4log(y)[/tex]

It would be 12 log x - 4 log y (B)

Answer:

Step-by-step explanation:

Assuming that the question is:

12 * (3 + 2^2) : 2 - 10 =       remember PEMDAS

12 * (3 + 4) : 2 - 10 =

12 * 7 : 2 - 10 =

84 : 2 - 10 =

42 - 10 =

32

Answer:

-10.5

Step-by-step explanation:

[tex]\frac{12*(3+2^2)}{2-10}[/tex]

2²= 4

3+4=7

12×7=84

2-10=-8

84÷-8= -10.5

Hope it helped, comment below if you need more assistance! :)

1. The given function is growth.

The percent of growth is 43%.

The initial value is 1500.

2. The rate of decay is 20% per day.

3. a. The exponential equation representing the sales after x months for the given situation is 3500000(0.97ˣ).

b. The monthly sales after 8 months will be $274,310.1758.

4. Between months 5 and 6, the website gains more members. The difference between the two sites for this period is 2700 members.

An exponential function is of the form f(x) = (a)(bˣ), where a is the initial value, and b is the exponential factor.

When b > 1, we have growth, and when b < 1, we have decay or depreciation.

1. Given function, f(x) = 1500(1.43ˣ).

The exponential factor in this function is 1.43, which is greater than 1, thus we have growth.

The percent of growth = (1.43 - 1)*100% = 43%.

The initial value = 1500.

2. Given an equation, y = 75(.8ˣ).

The exponential factor in this function is 0.8, and x signifies the days passed.

Thus, the rate of decay = (1 - 0.8)*100% per day = 20% per day.

3. Initial value = $350,000.

Rate of depreciation = 3% per month.

a. Thus, the equation for the sales after x months can be given as:

f(x) = 350000(1 - 0.03)ˣ = 350000(0.97ˣ).

b. To find the monthly sales after 8 months, we substitute x = 8.

Sales = 350000(0.97⁸) = $274,310.1758.

4. Initial members for both sites = 100.

For site a:-

Members double each month.

This makes an exponential equation, f(x) = 100.(2ˣ), where x is the number of months.

The growth between months 5 and 6 can be calculated as:

f(6) - f(5) = 100.(2⁶) - 100.(2⁵) = 6400 - 3200 = 3200.

For site b:-

500 new members are added each month.

This makes a linear equation, f(x) = 100 + 500x, where x is the number of months.

The growth between months 5 and 6 can be calculated as:

f(6) - f(5) = (100 + 500*6) - (100 + 500*5) = 3100 - 2600 = 500.

Thus, between months 5 and 6, the website a gains more members. The difference between the two sites for this period is 2700 members.

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Answer:The inverse of the function y = 2x^2 –4 is;. y = √(x +4)/2To find the inverse of the function;We must first solve for x in the equation as follows;y = 2x² - 4y + 4 = 2x²x² = (y +4)/2x = √ (y +4)/2By swapping x and y; we then have;y = √(x +4)/2

The interval where the function is negative is (–∞, –6)

The function is given as:

[tex]f(x) = \sqrt[3]{x + 6}[/tex]

Set the radicand to less than 0

x + 6 < 0

Subtract 6 from both sides

x < -6

Rewrite as an interval notation.

(–∞, –6)

Hence, the interval where the function is negative is (–∞, –6)

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Using the properties of logarithms, it is found that the earthquake in Japan in 2011 was 12.92 times more severe.

As given in the problem, the intensities of the earthquakes are given by logarithms of base 10. Then, supposing that the intensities are [tex]R_1, R_2 > 0, R_1 > R_2[/tex], the ratio of the intensities is given by:

[tex]10^{\frac{R_1}{R_2}}[/tex]

The intensities for this problem are [tex]R_1 = 9, R_2 = 8.1[/tex], hence the ratio is:

[tex]10^{\frac{9}{8.1}} = 12.92[/tex]

The earthquake in Japan in 2011 was 12.92 times more severe.

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Answer:

Khan Academy.

Step-by-step explanation:

You can go on khan academy and search up "percentages and numbers." The videos should immediately pop up. there are also lessons if you don't want to risk getting your problem wrong. If you are still confused and do not understand please just comment and I will respond.

The fill up of the missing points are:

Using the image attached, one can see that m<1 and m<2 creates a kind of  linear pair hence one can say they are both supplementary using the law of LINEAR POSTULATE THEOREM.

Based on the fact that the supplementary angles add up to 180 degrees, therefore:

m<1 + m<2 = 180   - will be equation 1

Since the interior angles m<2 and m<3 are known to be equal based on the CONGRUENCE POSTULATE THEOREM. Therefore

m<2 = m<3 ---  will be equation 2

Then place eqn. 2 into eqn. 2

m <1 + m <3 = 180

This connote that m<1 and m<3 are supplementary.

Hence, The fill up of the missing points are:

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Answer:

There are two complex roots:

============

The standard form is:

Compared we can find values of the coefficients and the constant:

Substitute these values into quadratic formula:

     [tex]x=\dfrac{-b\pm\sqrt{b^2-4ac} }{2a}[/tex]

and work out roots:

    [tex]x=\dfrac{-(-6)\pm\sqrt{(-6)^2-4*1*10} }{2*1}=x=\dfrac{6\pm\sqrt{36-40} }{2}=\dfrac{6\pm2\sqrt{-1} }{2}=3 \pm i[/tex]

Figure 1 was translated using the rule (x', y') ⇒ (x -9, y + 2) to produce figure 2.

Transformation is the movement of a point from its initial location to a new location. Types of transformation are translation, reflection, rotation and dilation.

Translation is the movement of a point either up, down, left or right on the coordinate plane.

Figure 1 was translated 9 units left and 2 units up using the rule (x', y') ⇒ (x -9, y + 2) to produce figure 2.

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The new location is in Quadrant IV and The new location has a positive x-coordinate and a negative y-coordinate. Hence, option b and c are correct.

Solution:

If the point were to reflect across the y-axis, it would fall into the fourth quadrant.

Additionally, the coordinates will be positive for the x-axis and negative for the y-axis.

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I hope you are trying to ask the question below:

Question

A point in Quadrant III is reflected across the y-axis. What is true about the new location? Check all that apply.

a. The new location is in Quadrant II.

b. The new location is in Quadrant IV.

c. The new location has a positive x-coordinate and a negative y-coordinate.

d. The new location has a negative x-coordinate and a positive y-coordinate.

e. The new location has negative x- and y-coordinates.

[tex]\huge\text{Hey there!}[/tex]

[tex]\huge\textbf{Equation:}[/tex]

[tex]\text{3x = 120}^\circ[/tex]

[tex]\huge\textbf{Simplifying:}[/tex]

[tex]\text{3x = 120}^\circ[/tex]

[tex]\huge\textbf{Divide \boxed{\bf 3} to both sides:}[/tex]

[tex]\rm{\dfrac{3x}{3} = \dfrac{120}{3}}[/tex]

[tex]\huge\textbf{Simplify it:}[/tex]

[tex]\rm{x = \dfrac{120}{3}}[/tex]

[tex]\rm{x = 40}[/tex]

[tex]\huge\textbf{Therefore, your answer should be:}[/tex]

[tex]\huge\boxed{\mathsf{x =}\frak{40}}\huge\checkmark[/tex]

[tex]\huge\text{Good luck on your assignment \& enjoy your day!}[/tex]

~[tex]\frak{Amphitrite1040:)}[/tex]

Yes we can prove that in the group of more than two people that there are at least two people that have the same number friends given the condition here.

Let us create a variable P. P is an individual called Joe. Now Joes seems to know all at this party. This tells us that all at this party should at least know him.

We have the set  {1,2,...n-1} , given that the minimum number of persons that one person knows is 1.

Let us assume we have Harry. Harry is a party crasher who came to the party. Hence it is possible that someone like Joe that knows all at the party may not even know him. Hence the maximum persons that a person would know is given to be n. The set would then be {0, 1,...,n-2}.

There are n elements in the 2 sets that we have above. Given that n people are at this function, and there are n possibilities for the number that one person can know of the participants, then we can say that at least two people can then know equal number of persons at the party.

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No, The resulting prediction would be more or less reliable than your original one.

Importance:

Prediction is a forecast or a prophecy. An example of a prediction is a psychic telling a couple they will have a child soon, before they know the woman is pregnant. A statement of what will happen in the future.

Predictions provide a reference point for the scientist. If predictions are confirmed, the scientist has supported the hypothesis. If the predictions are not supported, the hypothesis is falsified. Either way, the scientist has increased knowledge of the process being studied.

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Using translation concepts, the graph of g(x) = -|x - 4| is shown at the end of the answer.

A translation is represented by a change in the function graph, according to operations such as multiplication or sum/subtraction in it's definition.

The graph of g(x) = -|x - 4| is the graph of f(x) = |x| with these following changes:

At the end of the answer, the graph shows functions f(x) in red and g(x) in blue.

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Answer:

D (the last choice)

Step-by-step explanation:

Taking the fourth root of each element individually:

49^(1/4) = sqrt(7)

(d^8)^(1/4) = d^2

(e^2)^(1/4) = sqrt(e)

Multiplying them back together:

sqrt(7) * d^2 * sqrt(e) = d^2 * sqrt(7e)

Answer:

The last bubble (that of which is cut from the screen) is simplified.

Step-by-step explanation:

The provided equation is simplified by following these steps:

[tex](49d^{8}e^2)^\frac{1}{4}[/tex]

= [tex](49)^\frac{1}{4}(d)^\frac{8}{4}(e)^\frac{2}{4}[/tex]

[tex](7)^\frac{2}{4}(d)^\frac{8}{4}(e)^\frac{2}{4}[/tex]

=[tex]\sqrt{7} (d^2)(\sqrt{e})[/tex]

Answer:

If every line parallel to two lines intersects both regions in line segments of equal length, then the two regions have equal areas. In the case of your problem, every line parallel to the bases of the two parallelograms will intersect them in lines segments, each with a width of ℓ.

There are infinitely many parallelograms with the same area and base due to the variability of the height.

We have,

There is always more than one parallelogram with the same area and base because the height of the parallelogram can vary while keeping the base and area constant.

The formula to calculate the area of a parallelogram is:

Area = base × height

If the base and area of a parallelogram are fixed, we can rearrange the formula to solve for the height:

height = Area/base

Since the height can be any value as long as it satisfies the above equation, there are infinitely many possible heights for a given base and area.

And for each height, there will be a unique parallelogram with that base and area.

Imagine a rectangle as a special case of a parallelogram where all angles are 90 degrees.

For a given base and area, you can have an infinite number of rectangles by varying the height.

Each rectangle will have different side lengths, but they will all have the same base and area.

Thus,

The variability of the height while keeping the base and area constant allows for the existence of multiple parallelograms with the same area and base.

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It is necessary to imagine the sum of the areas between each z-score and the average.

Given as the ratio of the area under the normal curve between two z-scores, both above average.

The  Z score accurately measures the number of standard deviations above or below the mean of the data points.

The formula for calculating the z-score is

z = (data points – mean) / (standard deviation).

It is also expressed as z = (x-μ) / σ.

Therefore, to find the percentage of the area under the normal curve between two z-scores, both above the mean, you need to look at the sum of the areas between the z-score and the mean.

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The value of the probability P(A∪B) is 39/50

The given parameters are:

P(A)= 9/20

P(B) = 3/5

P(A∩B) = 27/100

To calculate the probability P(A∪B), we make use of the following equation

P(A∪B) = P(A) + P(B) - P(A∩B)

So, we have:

P(A∪B) = 9/20 + 3/5 - 27/100

Evaluate the expression

P(A∪B) = 78/100

Simplify

P(A∪B) = 39/50

Hence, the value of the probability P(A∪B) is 39/50

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The number of ways of arranging 4-digit positive integers with no repeated digits is 4536 ways and number of ways of 4-digit positive integers with repeated digits, but all digits are odd is 625 ways.

In this question,

Positive integers are 0,1,2,3,4,5,6,7,8,9

Total number of integers = 10

This can be solved by permutation concepts.

Case 1: 4-digit positive integers with no repeated digits,

First digit, cannot be zero. So remaining 9 digits.

Second digit, can be any digit other than the first digit. So 9 digits.

Third digit, can be any digits other than first and second. So 8 digits.

Fourth digit, can be any digits other than first, second, third digit. So 7 digits.

Thus, Number of ways of 4-digit positive integers with no repeated digits ⇒ (9)(9)(8)(7)

⇒ 4536 ways.

Case 2:  4-digit positive integers, there may be repeated digits, but all digits are odd

Odd integers are 1,3,5,7,9

Number of digits = 5

In this case, we can repeat the digits. So all places can have 5 possibilities.

Thus number of ways of 4-digit positive integers with repeated digits, but all digits are odd = (5)(5)(5)(5)

⇒ 625 ways.

Hence we can conclude that the number of ways of arranging 4-digit positive integers with no repeated digits is 4536 ways and number of ways of 4-digit positive integers with repeated digits, but all digits are odd is 625 ways.

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