What are the key control points within the citric acid cycle?

Answer :By the time thermal equilibrium is attained in the system, ice is completely converted to water.

What is tehrmal equilibrium?

Thermal equilibrium is a situation in which two substances are exactly at the same temperature. That is. Heat is no longer flowing beween the bodies.

Recall that an insulated thermos flask implies that heat does not eneter or leave the system. Heat will flow from the water to the ice untill the both attains the same temperature and the ice is completely converted to water.

Have a good day

The hydrogen ion concentration [H3O+] in an egg white containing 6.3 × 10-⁷M of [OH-] is 1.5 × 10-⁸M.

The hydrogen ion concentration of a solution can be calculated as follows:

pOH = - log [OH-]

pOH = - log [6.3 × 10-⁷M]

pOH = - [-6.2]

pOH = 6.2

Since pOH + pH = 14

pH = 14 - 6.2

pH = 7.8

pH = - log [H3O+]

7.8 = - log [H3O+]

[H3O+] = 10-⁷:⁸

[H3O+] = 1.5 × 10-⁸M

Therefore, the hydrogen ion concentration [H3O+] in an egg white containing 6.3 × 10-⁷M of [OH-] is 1.5 × 10-⁸M.

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Answer:

Opposes the motion

Explanation:

Let's take an example

option A is correct

For a reaction  2Na + 2H2O --> 2NaOH + H2,  The moles of Na needed to produce exactly 5.6 liters of H2 is mathematically given as

moles of H2=0.125mole

Generally, the equation for the  Chemical Reaction is mathematically given as

2Na + 2H2O -> 2NaOH + H2(g)

Therefore, since 2Na gives 1H2

PV=nRT

Hence

n=PV/RT

n=1*5.6/0.0821 *273

n=0.249mols

In conclusion,The moles is

2Na=1H2

moles of H2=0.125mole

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B is your answer

If the ignition temperature of a fuel is lower than the room temperature, then it can catch fire very easily.

Therefore for an ideal fuel, the ignition temperature should be higher than the room temperature.

let's observe one by one

#1

If ignition temperature is below room temperature the fuel can catch fire at once.

#2

Ignition temperature above room temperature is applicable as the fuel won't catch fire easily

#3

It's boiling point of water not fuels

#4

Equal to room temperature is same as first one can cause damage

It gets basic

ie ph>7 for basic solutions

Explanation:

Big C carbon surrounded by He helium

Answer:

I won't say I'm confident with this because I'm not sure if the second one is even correct, but I hope I helped you and didn't make things worse lol.

neutral particles since they do not posses any charge

Answer:

Bakelite

Explanation:

For a liter of a buffer that is 1. 5 m in acetic acid and 0. 70 m in sodium acetate, and with a  result in a buffer pH of 4.01, the moles of HCl required is mathematically given as x=0.313mol

Generally, the equation for the pH   is mathematically given as

pH=pKa+logsalt/acid

Generally, the equation for the Chemical Reaction   is mathematically given as

HCl+CH3CooNa---->NaCl+CH3OOH

Therefore

4.01=4.74+log\frac{0.8-x}{1.3+x}

-0.52=log\frac{0.8-x}{1.3+x}

x=0.313mol

In conclusion, The moles of HCl required is

x=0.313mol

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Buffer is a solution that prevents pH variation in a solution when base or acid is added. In a liter of buffer 0.313 mol of hydrochloric acid must be added.

pH is the potential of hydrogen and is given as,

[tex]\rm pH =\rm pKa + log \dfrac{salt}{acid}[/tex]

The chemical reaction is given as,

[tex]\rm HCl+CH_{3}COONa \rightarrow NaCl+CH_{3}OOH[/tex]

Given,

pH =4.01

pKa = 4.74

Concentration of salt = 0.8 - x

Concentration of acid = 1.3 + x

Substituting values in the pH formula:

[tex]\begin{aligned} 4.01 &= 4.74 + \rm log \dfrac{(0.8 - x)}{ (1.3 + x)}\\\\-0.52 &= \rm log \dfrac{(0.8 - x)}{ (1.3 + x)}\\\\&= 0.313 \;\rm mol\end{aligned}[/tex]

Therefore, 0.313 moles of HCl are needed.

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Answer:

density answer IS ....

Based on the data given, the energy required to remove an electron from a hydrogen atom in the n = 11 state is -0.112 eV

Ionization energy is the energy requiredto remove an electron from a neutral atom or a cation in its gaseous state.

To calculate the energy required to remove the electron from a hydrogen atom in the n = 11 state, the formula below is used:

where

[tex]E_0 \: is \: ground \: state \: energy \: of \: hydrogen \: atom \: = -13.6 eV \\ [/tex]

substituting the values:

[tex]E_n = \frac{ - 13.6 × 1^{2}}{11^{2}} \: = - 0.112 \: eV[/tex]

Therefore, the energy required to remove an electron from a hydrogen atom in the n = 11 state is -0.112 eV

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Methane in fuel cells are not burned and therefore, help to reduce pollutants commonly associated with fossil fuel combustion.

Fossils fuels are fuels wgich are produced from fossils which have decomposed under intense heat and pressure over a long period of time.

Fossils fuels include:

Fossils fuels combustion release pollutants into the atmosphere and have greatly contributed to global warming.

Since methane in fuel cells are not burned, it will help to reduce pollutants commonly associated with fossil fuel combustion.

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Answer:

Disinfecting (or boiling)

Explanation:

They'd want to disinfect everything so that it is germless. Boiling is a possible answer as well because you can boil certain things to rid them of germs.

Answer:

[tex]\huge\boxed{\sf v = 0.017 \ L}[/tex]

Explanation:

Given Data:

Mass = m = 0.08 g

Molar mass of C₂H₂F₄ = (12×2) + (1×2) + (19×4)

= 24 + 2 + 76 = 102 g/mol

Pressure = P = 1.14 atm

Temperature = T = 19.1 °C + 273 = 292.1 K

Gas Constant = R = 0.08206 L atm K⁻¹ mol⁻¹

Required:

Volume = v = ?

Formula:

Pv = nRT

Solution:

Firstly, finding moles (n)

[tex]\displaystyle n = \frac{mass}{molar \ mass} \\\\n = \frac{0.08 }{102} \\\\n =0.0008 \ mol[/tex]

Now, Finding volume (v)

Rearranging formula

[tex]\displaystyle v = \frac{nRT}{P} \\\\v = \frac{(0.0008)(0.08206)(292.1)}{1.14} \\\\v = \frac{0.019}{1.14} \\\\v = 0.017 \ L\\\\\rule[225]{225}{2}[/tex]

Answer:

Ammonium carbonate is a neutral molecule. Charge on NH4 is +1 , so on (NH4)2 is +2 ( +1 * 2) ,lets take the charge on C to be x and O is -2 , so on O3 is -6 (3*-2). Therefore x= + 4. Hope it helps.

Explanation:

The intermolecular forces present in B will be much stronger than the intermolecular forces present in A.

The term intermolecular forces has to do with the forces that hold molecules of a substance together in a particular state of matter. Now, we can see that B must contain dipole - dipole interaction while A has none of these.

It then follows that the intermolecular forces present in B will be much stronger than the intermolecular forces present in A.

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The molar mass of the gas that has a mass of 3.82 g and occupies a volume of 0.854 L is 106.66g/mol.

The molar mass of a substance can be calculated by dividing the mass of the substance by its number of moles.

However, the number of moles of the gas in this question needs to be calculated first using the ideal gas law equation:

PV = nRT

Where;

1.04 × 0.854 = n × 0.0821 × 302

0.888 = 24.79n

n = 0.888/24.79

n = 0.036mol

Molar mass of gas = 3.82g/0.036mol

Molar mass = 106.66g/mol

Therefore, the molar mass of the gas that has a mass of 3.82 g and occupies a volume of 0.854 L is 106.66g/mol.

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Answer:

option C is the correct answer

Explanation:

it belongs to alkanes series

for alkane series the formula is

C n H 2n+2

so the formula of b utane is

C 4 H 10

The correct answer is option C.C4H10

These isomers occur because they can branch off at the carbon chain. For example, butane has two isomers, C4H10. One of them has a "linear" carbon atom and the other has a branched chain.

Butane is a 4-carbon alkane, so its molecular formula is C4H10. There are two isomers. n-Butane and isobutane. Here, n-butane is a linear compound with four carbon atoms connected by a single covalent bond.

\Compounds with the same molecular formula but different arrangements of carbon atoms in the straight or branched chain are called chain isomers. n-Butane and isobutane are chain isomers because they have different carbon atom arrangements

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Answer:

When Chinese researchers first edited the genes of a human embryo in a lab dish in 2015, it sparked global outcry and pleas from scientists not to make a baby using the technology, at least for the present.

When Chinese researchers first edited the genes of a human embryo in a lab dish in 2015, it sparked global outcry and pleas from scientists not to make a baby using the technology, at least for the present.It was the invention of a powerful gene-editing tool, CRISPR, which is cheap and easy to deploy, that made the birth of humans genetically modified in an in vitro fertilization (IVF) center a theoretical possibility

Explanation:

Now, it appears it may already be happening.

According to Chinese medical documents posted online this month (here and here), a team at the Southern University of Science and Technology, in Shenzhen, has been recruiting couples in an effort to create the first gene-edited babies. They planned to eliminate a gene called CCR5 in hopes of rendering the offspring resistant to HIV, smallpox, and cholera.

Answer:

joules per gram per degree (J/goC) or calories per gram per degree (cal/goC).

Explanation:

Answer:

Joules, Kelvin, or calories

Explanation:

The moles of water are used in the given reaction between CO₂ & H₂O is 12 moles.

Mass of any substance will be calculated by using their moles as:

n = W/M , where

W = given or required mass

M = molar mass

Given chemical reaction is:

6CO₂ + 6H₂O → C₆H₁₂O₆ + 6O₂

Moles of 528 g of CO₂ = 528g / 44.01g/mol = 11.99 moles

From the stoichiometry of the reaction, it is clear that:

6 moles of CO₂ = reacts with 6 moles of H₂O

So, 11.99 moles of CO₂ = reacts with 11.99 = 12 moles of H₂O

Hence option (a)is correct i.e. 12 moles.

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Answer:

A

Explanation:

Answer:

an energy level represents the three dimensional space surrounding nucleus where electrons are most likely to be.

Explanation:

39 g H

2

O

 contains

1.3

×

10

24

molecules H

2

O

.

Explanation:

One mole of water has a molar mass of

18.015 g/mol

and

6.022

×

10

23

molecules H

2

O

. Therefore,

1 mol H

2

O

=

18.015 g H

2

O

=

6.022

×

10

23

molecules H

2

1O

Multiply the given mass of water times the conversion factors that cancel grams and moles of water, leaving molecules of water, as demonstrated below.

39

g H

2

O

×

1

mol H

2

O

18.015

g H

2

O

×

6.022

×

10

23

molecules H

2

O

1

mol H

2

O

=

1.3

×

10

24

molecules H

2

O

39 g H

2

O

 contains

1.3

×

10

24

molecules H

2

O

.

Explanation:

One mole of water has a molar mass of

18.015 g/mol

and

6.022

×

10

23

molecules H

2

O

. Therefore,

1 mol H

2

O

=

18.015 g H

2

O

=

6.022

×

10

23

molecules H

2

1O

Multiply the given mass of water times the conversion factors that cancel grams and moles of water, leaving molecules of water, as demonstrated below.

39

g H

2

O

×

1

mol H

2

O

18.015

g H

2

O

×

6.022

×

10

23

molecules H

2

O

1

mol H

2

O

=

1.3

×

10

24

molecules H

2

O

39 g H

2

O

 contains

1.3

×

10

24

molecules H

2

O

.

Explanation:

One mole of water has a molar mass of

18.015 g/mol

and

6.022

×

10

23

molecules H

2

O

. Therefore,

1 mol H

2

O

=

18.015 g H

2

O

=

6.022

×

10

23

molecules H

2

1O

Multiply the given mass of water times the conversion factors that cancel grams and moles of water, leaving molecules of water, as demonstrated below.

39

g H

2

O

×

1

mol H

2

O

18.015

g H

2

O

×

6.022

×

10

23

molecules H

2

O

1

mol H

2

O

=

1.3

×

10

24

molecules H

2

O

Answer/Explanation:

Stars spend the majority of their lifespan medling hydrogen nuclei together to form helium. When the hydrogen that in the core of the star begins to run out, the star will start using hydrogen away from its core and this is what causes the star's outer layer to expand and slowly cool down.

I hope this helps!

-No one

For a buffer is composed of 33. 80 ml of 0. 164 m acetic acid and 31. 63 ml of 0. 189 m sodium acetate,The volume of HCl is mathematically given as

v1=70.1148mL

Generally, the equation for the Chemical reaction is mathematically given as

HCl+CH3Coo-Na---->CH3CooH+NaCl

Therefore

Mole of HCl=34.37*0.204*10^-3

Mole of HCl=7.011*10^-{-3}

In conclusion

M1v1=m2v2

Therefore

[tex]v1=\frac{m2v2}{m1}\\\\v1=\frac{7.011*10^-{-3}}{0.1}[/tex]

v1=70.1148mL

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70.114 ml of 0. 100 m HCl can be added before the buffer capacity is reached

Volume is the space occupied by a three-dimensional object.

The chemical reaction is

[tex]\rm HCl+CH_3Coo-Na---- > CH_3CooH+NaCl[/tex]

step1, calculate the moles of HCl

[tex]34.37 \times0.204\times 10^-3[/tex]

[tex]\rm Moles\; of\; HCL \;7.011\times 10^{-3}[/tex]

The given Volume 1 is 33.80 ml

The given volume 2 is 31.63 ml

By the formula, [tex]M_1V_1=M_2V_2[/tex]

Putting the values in the equation

[tex]0.164 \times 33.80 = 100 \times V_2\\\\V_2 = 70.114 ml.[/tex]

Thus, the final volume is 70.114 ml.

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v1=70.1148mL