For a rectangular prism, the expression volume is calculated as V = l ⋅ w ⋅ h , where l is the length, w is the width, and h is the height of the rectangular prism.
Volume of Rectangular Prism and Surface AreaIt is much simpler to calculate the surface area and volume of a rectangular prism once it is understood that this type of prism is composed of some sets of identical forms.
The volume of a rectangular prism may be calculated by multiplying its length by its breadth by its height. The surface area of a rectangular prism can be calculated by adding the areas of each of its sides.
If you are familiar with the formulas for the surface area and volume of a rectangular prism, it will be much simpler for you to deal with different geometric shapes.
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The work-energy principle states that the work done by all the __________ forces acting on an object (or system of objects) causes a change in total __________ of the object or system.
The work-energy principle states that the work done by all the non-conservative forces acting on an object (or system of objects) causes a change in the total mechanical energy of the object or system.
What is the work-energy principle?
The work-energy principle states that the total work done on a system is equal to the change in kinetic energy of the system. It is given as:
W.D = ΔK.E
= K.E₁ - K.E₂
where K.E₁ is the initial kinetic energy of the system
K.E₂ is the final kinetic energy of the system
What is meant by non-conservative forces?
Non-conservative forces as the name suggests are not conserved i.e. these forces cause a loss of mechanical energy from the system. A prime example of non-conservative forces is friction.
The total mechanical energy of the system is the sum of the potential energy and kinetic energy that the system contains. This energy is conserved and follows the work-energy theorem.
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what is the best fuse for 1000 w heater?
a)3A
b)4A
c)5A
d)11A
c)5A
Explanation:
As,
[tex]I = \frac{P}{V} = \frac{1000}{220} = 5[/tex]
51. After conducting a search directly above the floor of a fire in a high rise building what is your next priority
After conducting a search directly above the floor of a fire in a high rise building what is your next priority is that their own safety is the first priority.
Life safety is the top consideration at any fire incident. Firefighters practice frequently to be ready to free trapped persons from a burning structure. On some occasions, though, it's the firefighters who require assistance.What are the three incident priorities?
Reviewing the three main responsibilities on the fireground—life safety, incident stabilization, and property preservation—is a good idea. These three concerns must be taken care of at every fire scene to which we react. The circumstances will determine which ones are addressed in what order.Learn more about firebrigade safty rules
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What was Kobe’s attitude toward life and competition?
Answer: Positive
Explanation: Kobe has had an positive attitude on situations and life itself. No matter the competition he still kept a positive attitude regardless. He still wished the best for others even if his enemies thought otherwise. So Kobe was a positive person on the outlook of life and competition.
A 350-g mass is attached to a spring whose spring constant is 64 N/m. Its maximum acceleration is 5.3 m/s2. What is the frequency of its oscillations?
The frequency of oscillation is 2.153 Hz
What is the frequency of spring?
Spring Frequency is the natural frequency of spring with a weight at the lower end. Spring is fixed from the upper end and the lower end is free.
For the mass-spring system in this problem,
The Frequency of spring is calculated with the equation:
[tex]f = \frac{1}{2\pi } \sqrt{\frac{k}{m} }[/tex]
Where,
f = frequency of spring
k = spring constant = 64 N/m
m = mass attached to spring = 350g = 0.350 kg
a = maximum acceleration = 5.3 m/s^2
Substituting the values in the equation,
[tex]f = \frac{1}{2\pi } \sqrt{\frac{64}{0.350} }[/tex]
[tex]f = \frac{1}{2\pi } ( 13.522)[/tex]
[tex]f = 2.1535 Hz[/tex]
Hence,
The frequency of oscillation is 2.153 Hz
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A large box is being pushed across the floor at a constant speed of 4.0 m/s. What can you conclude about the forces acting on the box?
There is no force acting on the large box.
What is the force according to Newton's law?According to Newton's second law of motion, Force is defined as the rate of change of momentum with respect to time.Mathematically, force = mass × accelerationAnd acceleration = velocity/ timeHere, the large box is moving with constant velocity. So its velocity is not changing with time.So velocity / time = zero i.e. acceleration= zeroIt leads to the force to be zero.Thus, we can conclude that the force on the large box is zero.
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The evolutionary cutoff between low- and high-mass stars occurs at approximately:
The evolutionary cutoff between low- and high-mass stars occurs at eight (8) M.
What are high-mass stars?The high-mass stars are celestial bodies that exhibit a high level of luminosity and lived for short periods of time.
Conversely, low-mass stars are small and cool stars that lived for a long period of time.
In conclusion, the evolutionary cutoff between low- and high-mass stars occurs at eight (8) M.
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A 50.0 g stone is attached to the bottom of a vertical spring and set vibrating. If the maximum speed of the stone is 15.0 cm/s and the period is 0.500 s, find the (a) spring constant of the spring, (b) amplitude of the motion, and (c) frequency of oscillation.
Spring constant of the spring, amplitude of the motion, and frequency of oscillation are respectively 8N/m, 1.2 cm and 2Hz.
To find the answer, we need to know about angular frequency, frequency, amplitude of spring mass system.
What's the angular frequency of the spring mass system, if its time period is 0.5 second?Mathematically, w=2π/Tw= 2π/0.5= 12.6 rad/sWhat's the relation between angular frequency and spring constant?Mathematically, w =√(k/m)k= w²mHere, w= 12.6 rad/s, m= 50gm = 0.05kg k= 12.6²× 0.05 = 8 N/mWhat's the relation between amplitude, angular frequency and velocity of mass of a spring mass system?Mathematically, Amplitude= velocity/angular frequencyHere, velocity= 15 cm/s = 0.15m/s, angular frequency= 12.6 rad/sAmplitude= 0.15/12.6= 0.012m = 1.2 cmWhat's the expression of frequency in term of time period?Frequency= 1/time periodHere time period= 0.5 sFrequency= 1/0.5 = 2 HzThus, we can conclude that spring constant of the spring, amplitude of the motion, and frequency of oscillation are respectively 8N/m, 1.2 cm and 2Hz.
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= Sem 2 CR-SS159VGSZE
nating a my ponnesis. I art
Since the investigative question has two variables, you
need to focus on each one separately. Thinking only
about the first part of the question, mass, what might be
a hypothesis that would illustrate the relationship
between mass and kinetic energy? Use the format of
"if...then...because..." when writing your hypothesis.
The relationship between mass and kinetic energy is K.E ∝ m and K.E ∝ v².
What is the relationship between mass and kinetic energy?The kinetic energy of an object exists as the energy that it maintains due to its motion. It is defined as the work required to accelerate a body of a disseminated mass from rest to its stated velocity. Having acquired this energy during its acceleration, the body preserves this kinetic energy unless its speed changes.
The kinetic energy is directly proportional to the mass and also directly proportional to the square of the velocity.If we increase the mass, then kinetic energy will also increase.But if we increase the velocity by n times , then the kinetic energy will increase by [tex]n^{2}[/tex] times.To know more about kinetic energy, refer:
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The following is regarding Momentum Change and Force. help is needed please!
1. A force of 50 N acts on an object of mass 250 kg which is initially at rest, for 10 s. find the distance travelled and the velocity gained at the end of this time.
The distance travelled is 10 m and the velocity gained at the end of this time is 2 m/s.
Velocity of the object at the end of the timeF = mv/t
where;
m is mass of the objectv is velocity of the objectt is timeFt = mv
v = Ft/m
v = (50 x 10)/250
v = 2 m/s
Distance traveled by the objectv² = u² + 2as
where;
u is initial velocity = 0
a is acceleration
a = F/m
a = 50 N/ 250 kg
a = 0.2 m/s²
v² = 0 + 2as
s = v²/2a
s = (2²)/(2 x 0.2)
s = 10 m
Thus, the distance travelled is 10 m and the velocity gained at the end of this time is 2 m/s.
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physical and chemical properties of water
(Not sure how many examples you need so I will put three for each)
Physical:
Chemical:
One of the most significant characteristics of water is its amphoteric tendency. Amphoteric refers to a substance's capacity to function as an acid or base. Water is neither acidic nor basic in its natural form. Its capacity to give and receive protons is the key justification. However, rainfall has a pH between 5.2 and 5.8, making it mildly acidic.Water is referred to be the all-purpose solvent. This is due to its chemical makeup, physical characteristics, high dielectric constant, and other factors that make it the most solvent material. It can attract other compound molecules, disabling their molecular forces and causing them to dissolve since hydrogen and oxygen both have positive and negative charges that are available.Water is a chemical molecule made up of two hydrogen atoms and one oxygen atom. The liquid condition of that substance is often referred to as water, and the solid and gas phases are respectively referred to as ice and steam.An astronomy student, for her PhD, really needs to estimate the age of a cluster of stars. Which of the following would be part of the process she would follow
Plotting what is referred to as an H-R diagram for the stars in the cluster is part of the process in which the astronomy student will follow in this type of scenario.
What is H-R diagram?This is referred to as the Hertzsprung–Russell diagram and is a scatter plot which depicts the relationships between stars' absolute magnitudes versus their effective temperature. It can also be inferred that the higher the luminosity of a star, the higher the temperature and vice versa.
This helps to depict stellar evolution as a result of the features used as parameters such as the life cycle as an older star will be less luminous when properly studied by people hereby making it easier to estimate the age of stars.
This therefore the reason why plotting a Hertzsprung–Russell diagram is very important.
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A hypothetical metal has the bcc crystal structure, a density of 7. 24 g/cm3, and an atomic weight of 48. 9 g/mol. The atomic radius of this metal is.
Atomic radius of this metal is 0.85 x 10^23
Given:
density of metal = 7. 24 g/cm3
metal has the bcc crystal structure
atomic weight = 48. 9 g/mol
To Find:
atomic radius of this metal
Solution: Atomic radius is defined as half the distance between the centers of two neighboring atoms. the atomic radius of a simple cube and hcp is a/2 respectively, whereas it is a√2/4 and a√3/4 for fcc and bcc respectively.
density = Z x M/N• x a^3
a = edge length
Z = 2 atoms = numeber of atoms per unit cell
N• = 6.023 x 10^23 atoms/mol = Avogadro's number
a^3 = density x N•/Z x M
a^3 = 7.24 x 6.023 x 10^23/ 2 x 48. 9
a = 3√0.44 x 10^23
a = 1.98 x 10^23
4R = √3a
R = √3 x 1.98 x 10^23/4
R = 0.85 x 10^23
Atomic radius of this metal is 0.85 x 10^23
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You are singing a song at karaoke and reach a part that requires a louder, more intense sound. What must you do to produce a louder sound
More energy is used in creating a louder sound from the mouth.
What must you do to produce a louder sound?We use more energy in order to produce a louder sound because energy is the thing that helps in the formation of loud sound. Loudness is dependent on the energy that creates loud sound in the mouth. More energy we apply, more loud sound will produce. Energy is the main factor which gives us a loud sound in each and every instruments. Without, we can't imagine loud sound.
So we can conclude that more energy is used in creating a louder sound from the mouth.
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If the Moon takes 27.3 days to complete its orbital path around the Earth, and the orbit has a radius of 3.8 x 108 meters, what is the Earth's Mass
Answer: If the Moon takes 27.3 days to complete its orbital path around the Earth, and the orbit has a radius of 3.8 x 108 meters, then, the Earth's Mass is [tex]6*10^{24}kg[/tex].
Explanation: To find the answer, we have to know more about the Law of periods or the harmonic law.
What is the law of periods or harmonic law?The law of periods states that, the square of the period of revolution of a planet is proportional to the cube of the semi major axis of the elliptical path.We can express it as,[tex]T^2[/tex]∝ [tex]r^3[/tex]
[tex]T^2=\frac{4\pi ^2r^3}{GM}[/tex]
How to solve the problem?From the above given equation, we can reduce mass of earth as,[tex]M=\frac{4\pi ^2r^3}{GT^2}[/tex]
Substituting the values given in the question, we get,[tex]M=\frac{4\pi ^2(3.8*10^8)^3}{6.67*10^-11*(27.3*24*60*60s)^2} =\frac{2.164*10^{27} }{371.08} =5.831*10^{24}=6*10^{24}kg[/tex]
Thus, we can conclude that, the mass of earth is [tex]6*10^{24}kg[/tex] .
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Excessive use of fossil fuels causes an energy crisis
yes, it causes an energy crisis. Burning Fossil Fuels
When we burn oil, coal, and gas, we don't just meet our energy needs, we move the current global warming crisis as well.
Fossil fuels produce large amounts of carbon dioxide when burned. Carbon emissions trap heat in the air and lead to climate change.
What are the major causes of energy crisis?
Most energy crises have been caused by localized shortages, wars and market manipulation. Some have argued that government efforts like tax hikes, nationalization of energy companies, and rule of the energy sector, shift supply and demand of energy away from its economic stability.
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Two parallel wires are separated by 0.36 m. Wire A carries 4.8 A and Wire B carries 8.9 A, both currents in the same direction. The force on 0.53 m of Wire A is:
The force on 0.53 m of Wire A is 1.3×10^(-5) N.
To find the answer, we need to know about the force on a current carrying wire due to another parallel wire.
What's the force experienced by a current carrying wire of length L due to another current carrying parallel wire?The magnetic force experienced by the wire here= μ₀IAIBL/(2πr)IA= current in wire A, IB= current in wire B, L = length of wire and r= separation between themWhat's the force on 0.53 m of Wire A, if IA, IB, L and r are 4.8A, 8.9A, 0.53m and 0.36 m respectively?Force = (4π×10^(-7)×4.8×8.9×0.53)/(2π×0.36)
= 1.3×10^(-5) N
Thus, we can conclude that the force on 0.53 m of Wire A is 1.3×10^(-5) N.
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What is a stream’s discharge rate if it has a width of 10 meters, a depth of 2 meters, and a velocity of 2 meters per second?
A stream’s discharge rate if it has a width of 10 meters, a depth of 2 meters, and a velocity of 2 meters per second will be 40 [tex]m^{3}[/tex]/sec .
Discharge rate = velocity * area
= velocity * depth * width
= 2 * 2 * 10 = 40 [tex]m^{3}[/tex]/sec
A stream’s discharge rate if it has a width of 10 meters, a depth of 2 meters, and a velocity of 2 meters per second will be 40 [tex]m^{3}[/tex]/sec .
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A computer uses 3.5 A at 110 V. What is its resistance in ohms?
Answer:
31.43 Ω
Explanation:
Using Ohm's Law:
[tex]\displaystyle{V=IR}[/tex]
Where V = voltage (V) , I = electric current (A) and R = resistance (ohm)
We know that a computer uses 3.5 ampere at 110 volt, we want to know the resistance. Therefore substitute V = 110 and A = 3.5
[tex]\displaystyle{110=3.5R}\\\\\displaystyle{\dfrac{110}{3.5}=R}\\\\\displaystyle{R=31.43}[/tex]
Therefore, the resistance will be around 31.43 Ohm
Jan is holding an ice cube. What causes the ice to melt?
Thermal energy from the ice is transferred to the air.
Thermal energy from Jan’s hand is transferred to the ice.
The air absorbs thermal energy from Jan’s hand.
Jan’s hand absorbs thermal energy from the ice.
The ice melts because Thermal energy from Jan’s hand is transferred to the ice.
What is thermal energy?Thermal energy is the energy due to temperature difference.
Thermal energy flows from hotter to colder bodies.
The ice Jan is holding melts because heat is transferred from his hands t the ice.
In conclusion, thermal energy flow causes melting.
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Answer:
its b
Explanation:
because the heat from your hand makes the ice melt!
Define mass .Also write the table showing the relation of 'kg' with it's sub- multiples and multiples.
Answer:
the quantity of matter contained in a body is called mass .si unit of mass is kilogram.weight is effected by gravity but mass is not effected by gravity.
Answer:
The quantity of matter contained in a body is called mass .si unit of mass is kilogram.weight is effected by gravity but mass is not effected by gravity.
Explanation:
To correct myopia (nearsightedness) requires ___________ lenses; to correct hyperopia (farsightedness) requires _____________ lenses to correct.
By using concave lens, we can correct Myopia and Hyperopia can be corrected by convex lenses.
To find the answer, we need to know about Myopia and Hyperopia.
What is Myopia and Hyperopia?Myopia is an optical defect, in which a person can see nearby objects clearly and cannot see far off objects clearly.Here the eyeball becomes too longer, and the focal length of eye lens become too short.It can be corrected by using concave lens.For Hyperopia, the person can see far off objects clearly and cannot see nearby objects clearly.This can be corrected by using convex lens.Thus, we can conclude that, by using concave lens, we can correct Myopia and Hyperopia can be corrected by convex lenses.
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Myopia can be corrected using concave lenses, while the Hyperopia is corrected by convex lenses.
We need to be aware of myopia and hyperopia in order to locate the solution.
Myopia and hyperopia: what are they?Myopia is an optical defect in which a person can see clearly up close but not clearly far away.Here, the eyeball lengthens excessively and the eye lens focal length contracts.Concave lenses can be used to rectify it.A person with hyperopia can clearly see distant objects but cannot see nearby objects clearly.Convex lenses can be used to fix this.Thus, we can deduce that myopia and hyperopia can be corrected using concave lenses and convex lenses, respectively.
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Which of the following is an advantage of recorded presentations? A. Start-times and time zones are not a factor. B. Speakers can adapt topic coverage if necessary. C. Audience members have the opportunity to provide feedback D. More visual aids can be used.
The statement describes an advantage of recorded presentations is that the audience members have the opportunity to provide feedback. Thus, the correct option for this question is C.
What do you mean by Recorded presentations?A recorded presentation may be defined as a popular format of multimedia content with a duration of several seconds or minutes that significantly expresses the advantages of a product, service, or any idea with the support of interesting graphic images, concise text, and appropriate narration.
According to the context of this question, a recorded presentation delivers an advantage to the audience to provide feedback. This is because the process of recorded PowerPoint presentation gives the actual sense and understanding to the audience similar to the real event.
Therefore, the correct option for this question is C.
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Astronomers have realized that the surface of ida is older than the surface of gaspra. How do they measure this?
From counting craters on each asteroids , astronomers have realized that the surface of ida is older than the surface of gaspra.
Ida, and Gaspra are three objects located in the asteroid belt between Mars and Jupiter.
Crater counting is a method for estimating the age of a planet's surface based upon the assumptions that when a piece of planetary surface is new, then it has no impact craters; impact craters accumulate after that at a rate that is assumed known.
Counting how many craters of various sizes there are in a given area allows determining how long they have accumulated and consequently, how long ago the surface has formed. Hence , from counting craters on each asteroids ,astronomers have realized that the surface of ida is older than the surface of gaspra.
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How should you plan to excercise if you want to remain healthy past the age of 65
Explanation:
by taking a brisk walking about 150 minutes
2 days a week exercise that strengths muscles
drinking water
Even with the best and largest telescopes, we can’t see all the stars in the milky way galaxy, even though these same telescopes can show us other galaxies. Why is that?
Because starlight cannot pass through black space, we are unable to view all of the stars in the Milky Way galaxy, even with the best and largest telescopes.
In the Milky Way galaxy, the Earth is situated. Part of it can be seen as a broad, opaque ring of stars and dust on a clear night (from sufficiently dark areas). We can see thousands of these stars with our unaided eyes, and a telescope can reveal many more.
However, a large number of the Milky Way's stars are obscured. The supermassive black hole at the centre of the galaxy and the bulge, which is made up of stars, gas, and dust, are to blame for this. The substance in this is opaque to all but the most powerful telescopes.
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An astronomical telescope is designed with over magnification of 35x if the object has a focal length of 100 cm what should be the focal length of the eyepiece and how far should the eyepiece be from the objective
The focal length of eyepiece is 2.85.
It is given that astronomical telescope is designed with over magnification of 35.
The object has a focal length of 100 cm.
We need to determine the focal length of the eyepiece.
The formula to be used here is for astronomical telescope is:
[tex]m=\frac{f_{0} }{f_{e} }[/tex]
Using values here, we get
[tex]35=\frac{100 }{f_{e} }[/tex]
[tex]f_{e}=100/35=2.85[/tex]
Hence, the focal length of eyepiece is 2.85
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What information do we know about the known exoplanets? a. estimates of orbits and masses b. complete composition c. precise masses d. all of the above e. none of the above
The correct option is A. The information we know about the known exoplanets is estimates of orbits and masses.
What is exoplanets?An exoplanet or extrasolar planet is a planet outside the Solar System.
In other words, exoplanet is any planet beyond our solar system.
Characteristics of exoplanetsexoplanets are known for the following characteristics;
they are usually hotthey can orbit their stars so tightly that a “year” lasts only a few daysthey can orbit two suns at onceThus, the information we know about the known exoplanets is estimates of orbits and masses.
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Why stars are shows like twinkling in the sky’s!
Reply please!
Answer:
As light from a star races through our atmosphere, it bounces and bumps through the different layers, bending the light before you see it. Since the hot and cold layers of air keep moving, the bending of the light changes too, which causes the star's appearance to wobble or twinkle.
If you take a given pendulum to the Moon, where the acceleration of gravity is less than on Earth, the resonant frequency of the pendulum will
As the acceleration of gravity is less on the moon than on the Earth, thus the resonant frequency of the pendulum will be less on the moon.
Explanation:
The acceleration due to gravity is less on the moon than the gravitational acceleration on the earth. It is required to examine how the resonant frequency of a pendulum is changed on the moon compared to the earth.
We know that the resonant frequency is dependent on the acceleration of gravity.
[tex]$f=\frac{1}{2 \pi} \sqrt{\frac{g}{l}}$[/tex] where g is the acceleration due to gravity and l is the length of the string.
From the above equation, it is clear that the resonant frequency is directly proportional to the square root of the acceleration due to gravity.
The gravitational acceleration on the moon is less than that on the earth.
Therefore the resonant frequency of the pendulum on the moon is less than that on the earth.
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